Search Results

Search found 14310 results on 573 pages for 'mysql sock'.

Page 364/573 | < Previous Page | 360 361 362 363 364 365 366 367 368 369 370 371  | Next Page >

  • how to join 3 relational tables

    - by orioncabbar
    Hello there, how to join 3 relational tables with the structure: t1 | id t2 | id | rating t3 | source_id | relation t3 stores the data of a field which t1 and t2 uses both. so source_id field can be t1's id or t2's id. input : t1 id output : t2 rating an example: **t1** id | --------- 42 | **t2** id | rating ------------- 37 | 9.2 **t3** id | source_id -------------- 42 | 1 37 | 1 26 | 2 23 | 1 what i want is to get 9.2 output with 42 input. can you do that in one sql query?

    Read the article

  • Is it necessary to write ROLLBACK if queries fail?

    - by Donator
    I write mysql_query("SET AUTOCOMMIT=0"); mysql_query("START TRANSACTION"); before I write all queries. Then check if all of them are true and then write: mysql_query("COMMIT"); But if one of query fails, I just pass COMMIT query. So do I really need ROLLBACK function if one of the queries fail? Because without ROLLBACK it also works. Thanks.

    Read the article

  • How Can I Join Two DB Tables and Return Lowest Price From Joined Table

    - by Jason
    I have two tables, the first table has the product and the second table the prices. The price table could have more than one price per product but I only want to display the lowest. But I keep getting all the prices returned and I'm having trouble figuring out how to do it. this is what I get returned in my query: SELECT * FROM products AS pr JOIN prices AS p ON pr.id = p.product_id WHERE pr.live = 1 AND p.live = 1 id product1 name description £100 id product1 name description £300 id product1 name description £200 id product2 name description £50 id product2 name description £80 id product2 name description £60 id product3 name description £222 id product3 name description £234 id product3 name description £235 but I'm after: id product1 name description £100 id product2 name description £50 id product3 name description £222 Any help would be appreciated

    Read the article

  • php database image show problem

    - by Termedi
    here is the code <?php session_start(); if(!isset($_SESSION['user_name'])) { header('Location: login.php'); } $conn = mysql_connect("localhost", "root", "") or die("Can no connect to Database Server"); ?> <html> <head> </head> <body> <center> <div id="ser"> <form action="" method="post"> <label for="file">Card No:</label> <input type="text" name="card_no" id="card_no" class="fil" onKeyUp="CardNoLength()" onKeyDown="CardNoLength()" onKeyPress="CardNoLength()"/> <input type="submit" name="search" value="Search" class="btn" onClick="return CardNoLengthMIN()"/> </form> </div> </center> <br/><hr style="border: 1px solid #606060 ;" /> <center><a href="index.php">Home</a></center> <br/> <center> <?php if(isset($_POST['card_no'])) { if($conn) { if(mysql_select_db("img_mgmt", $conn)) { $sql = "select * from temp_images where card_no='".trim($_POST['card_no'])."'"; $result = mysql_query($sql); $image = mysql_fetch_array($result); if(isset($image['card_no'])) { //echo "<img src=\"".$image['file_path']."\" alt=\"".$image['card_no']."\" width=\"250\" height=\"280\"/>"; header("Content-type: image/jpeg"); echo $image['img_content']; } else { echo "<p style=\"color:red;\">Sorry, Your search came with no results ! <br/> Try with different card number"; } } else { echo "Database selection error: ".mysql_error(); } } else { echo "Could not connect: ".mysql_error(); } } ?> </center> </body> </html> But it after executing the script it shows: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\img\search.php:61) in C:\xampp\htdocs\img\search.php on line 77

    Read the article

  • Activetopics - Get max 5 topics per category

    - by Arjen
    Hey, I want to get the 5 latest active topics within several category's. Each topic has a subcatid and this subcatid relates to a catid. What I want is to get the 5 active topics within each catid. I'm trying to use the query below, but this isn't working at all: set @num := 0, @catid := 0; SELECT forum_posts.topicid, forum_topics.titel, forum_topics.sticky, forum_topics.gesloten, MAX(forum_cats.id) AS catid, MAX(forum_cats.titel) AS cattitel, MAX(forum_subcats.id) AS subcatid, MAX(forum_posts.id) AS maxid, DATE_FORMAT(MAX(forum_posts.datum), '%d-%m-%Y om %H:%i uur') AS datum, UNIX_TIMESTAMP(MAX(forum_posts.datum)) AS laatstereactieunix, (COUNT(forum_posts.id) - 1) AS reactieaantal, @num := IF(@catid = MAX(forum_cats.id), @num + 1, 1) AS row_number, @catid := MAX(forum_cats.id) AS dummy FROM forum_posts INNER JOIN forum_topics ON forum_topics.id = forum_posts.topicid INNER JOIN forum_subcats ON forum_subcats.id = forum_topics.subcat INNER JOIN forum_cats ON forum_cats.id = forum_subcats.cat WHERE forum_cats.id IN (1) AND forum_topics.gesloten != '1' GROUP BY forum_posts.topicid, forum_topics.titel, forum_topics.sticky, forum_topics.gesloten HAVING row_number <= 5 ORDER BY forum_cats.id ASC, MAX(forum_posts.datum) DESC When executing this code I get always the same number (1) for row_number, so this is not the result I want. Does anyone know how I can get this work? Thanks!

    Read the article

  • Possible to sort via two time stamps and display same row twice.

    - by jamiethompson90
    I'm looking at creating a time table solution. I have a task sheet that looks like Area 1 item 1 startTime endTime Area 1 item1 startTime endTime I wish to create a display where I can view what even is happening next, either endTime or startTime i.e. Newcastle reel 16:45 18:45 Newcastle reel2 17:45 19:45 would output Newcastle reel 16:45 Newcastle reel 17:45 Newcastle reel 18:45 Newcastle reel 19:45 More so, I would like to detect if the time is a startTime or an endTime would I have to enter two rows for each activity (time,area,item, start|end). I can make the interface to the creation of two rows. I just wondered if there was a better solution. Any input is appreciated, Thanks, Jamie

    Read the article

  • Sql Query to get total rows and total rows matching specific condition

    - by mrNepal
    OK, Here is what my table looks like ------------------------------------------------ id type ----------------------------------------------- 1 a 2 b 3 a 4 c 5 c 7 a 8 a ------------------------------------------------ Now, I need a query that can give me this output... ----------------------------------------------------------------- count(*) | count(type=a) | count(type=b) | count(type=c) ----------------------------------------------------------------- 8 4 1 3 ------------------------------------------------------------------ I only know to get the total set using count(*), but how to do the remaining

    Read the article

  • Sort database entries via a dropdown list

    - by Lin
    Hello! I'm curious if anyone could possibly help me, because I can't find anything exactly related to it anywhere, and it's driving me nuts. I'd like to have a dropdown list on a page, that will give the visitor the option to sort all entries by year. I have entries from i.e. 2001, 2005, 2009, 2010. The years should be displayed in the dropdown, so the visitor can easily just select all entries dated 2001 if they want. The year for each entry is located in the one database table I have. In other words, I simply want a "sort by" dropdown that you can see on pretty much any shopping site nowadays. But with set years. Thanks in advance for any replies!

    Read the article

  • Deleting rows from different tables

    - by Ross
    Here is what i'm trying to do: Delete the project from projects table and all the images associated with that project in the images table Lets say $del_id = 10 DELETE FROM projects, images WHERE projects.p_id = '$del_id' AND images.p_id = '$del_id' What is wrong with this query

    Read the article

  • PHP - Drilling down Data and Looping with Loops

    - by stogdilla
    I'm currently having difficulty finding a way of making my loops work. I have a table of data with 15 minute values. I need the data to pull up in a few different increments $filters=Array('Yrs','Qtr','Day','60','30','15'); I think I have a way of finding out what I need to be able to drill down to but the issue I'm having is after the first loop to cycle through all the Outter most values (ex: the user says they want to display by Hours, each hour should be able to have a "+" that will then add a new div to display the half hour data, then each half hour data have a "+" to display the 15 minute data upon request. Now I can just program the number of outputs for each value (6 different outputs) just in-case... but isn't there a way I can make it do the drill down for each one in a loop? so I only have to code one output once and have it just check if there are any more intervals after it and check for those? I'm sure I'm just overlooking some very simple way of doing this but my brain isn't being clever today. Sorry in advance if this is a simple solution. I guess the best way I could think of it as a reply on a form. How you would check to see if it's a reply of a reply, and then if that reply has any replys...etc for output. Can anyone help or at least point me in the right direction? Or am I stuck coding each possible check? Thanks in advance!

    Read the article

  • Optimize innodb table

    - by ming yeow
    When i run optimize table on a innodb table, i get this message instead. does it mean that the table has already been optimized, but in a different manner? "table | optimize | note | Table does not support optimize, doing recreate + analyze instead |"

    Read the article

  • How can I perform this query between related tables without using UNION?

    - by jeremy
    Suppose I have two separate tables that I watch to query. Both of these tables has a relation with a third table. How can I query both tables with a single, non UNION based query? I want the result of the search to rank the results by comparing a field on each table. Here's a theoretical example. I have a User table. That User can have both CDs and books. I want to find all of that user's books and CDs with a single query matching a string ("awesome" in this example). A UNION based query might look like this: SELECT "book" AS model, name, ranking FROM book WHERE name LIKE 'Awesome%' UNION SELECT "cd" AS model, name, ranking FROM cd WHERE name LIKE 'Awesome%' ORDER BY ranking DESC How can I perform a query like this without the UNION? If I do a simple left join from User to Books and CDs, we end up with a total number of results equal to the number of matching cds timse the number of matching books. Is there a GROUP BY or some other way of writing the query to fix this?

    Read the article

  • Perl daemon script for message queue hanging for 20 seconds after each process. Why?

    - by Mike Diena
    I have daemon script written in Perl that checks a database tables for rows, pulls them in one by one, sends the contents via HTTP post to another service, then logs the result and repeats (only a single child). When there are rows present, the first one is posted and logged immediately, but every subsequent one is delayed for around 20 seconds. There are no sleep()'s running, and I can't find any other obvious delays. Any ideas?

    Read the article

  • What might be causing this Rails method error?

    - by Trip
    My error: Notice the undefined method '-@' . This is for a sort by. All sorts on one page break, but all the sorts on other pages use the same helper and do not break. Does it allude to something obvious? Processing OrganizationsController#search (for ::1 at 2010-05-13 15:42:01) [GET] Parameters: {"action"=>"search", "controller"=>"organizations", "direction"=>"desc", "_"=>"1273779721464", "order_by"=>"published_at"} SQL (0.5ms) SHOW TABLES Organization Columns (2.2ms) SHOW FIELDS FROM `organizations` NoMethodError (undefined method `-@' for #<Array:0x2f88cc8>): app/controllers/organizations_controller.rb:190:in `search' sunspot (1.0.5) lib/sunspot/util.rb:84:in `call' sunspot (1.0.5) lib/sunspot/util.rb:84:in `instance_eval_or_call' sunspot (1.0.5) lib/sunspot/search.rb:200:in `build' sunspot (1.0.5) lib/sunspot/session.rb:45:in `new_search' sunspot (1.0.5) lib/sunspot/session.rb:53:in `search' sunspot (1.0.5) lib/sunspot/session_proxy/abstract_session_proxy.rb:11:in `search' sunspot (1.0.5) lib/sunspot.rb:323:in `search' app/controllers/organizations_controller.rb:183:in `search' haml (2.2.2) [v] rails/./lib/sass/plugin/rails.rb:19:in `process' lib/flash_session_cookie_middleware.rb:14:in `call' vendor/gems/hoptoad_notifier-2.2.2/lib/hoptoad_notifier/rack.rb:27:in `call' /usr/local/lib/ruby/1.8/webrick/httpserver.rb:104:in `service' /usr/local/lib/ruby/1.8/webrick/httpserver.rb:65:in `run' /usr/local/lib/ruby/1.8/webrick/server.rb:173:in `start_thread' /usr/local/lib/ruby/1.8/webrick/server.rb:162:in `start' /usr/local/lib/ruby/1.8/webrick/server.rb:162:in `start_thread' /usr/local/lib/ruby/1.8/webrick/server.rb:95:in `start' /usr/local/lib/ruby/1.8/webrick/server.rb:92:in `each' /usr/local/lib/ruby/1.8/webrick/server.rb:92:in `start' /usr/local/lib/ruby/1.8/webrick/server.rb:23:in `start' /usr/local/lib/ruby/1.8/webrick/server.rb:82:in `start' Rendered rescues/_trace (68.5ms) Rendered rescues/_request_and_response (0.6ms) Rendering rescues/layout (internal_server_error)

    Read the article

  • Zend Framework multiple databases

    - by Uffo
    I'm currently using only one database with Zend Framework, but now I have to add ONE MORE. I'm using this code right now: public static function setupDatabase() { $config = self::$registry->configuration; $db = Zend_Db::factory($config->db->adapter, $config->db->toArray()); $db->query("SET NAMES 'utf8'"); self::$registry->database = $db; Zend_Db_Table::setDefaultAdapter($db); } What code do I need to write in order to use ONE MORE database; and how I will reference it, when I need to make some queries or so.. Best Regards!

    Read the article

  • mysqli_query SELECT FROM WHERE [ partial match ] ?

    - by user296516
    Hi guys, I have a database that a time filed that is stored in this format "2010.06.04. | 18:53 01". What I need is to select rows that have a specific date, for example "2010.06.04." Right now I am doing it my first selecting all rows and then looping through them and adding ones with the specified date to a new array. Maybe there is an easier way to do it and I somehow can select it using mysqli_query? Thanks!

    Read the article

  • PHP Framework Benefits / Downfalls

    - by Lizard
    I have been a PHP developer for about 10 years now and until about a month ago I have never used a framework. The framework I am now using due to an existing codebase is cakePHP 1.2 I can see certain benefits of the frameworks with the basic helpers like default layouts. I can deffinately seen the benefits of MVC keeping the logic sperate etc. But the query building just seems to be bloated. Is this expected? Am I likely to be able to build better queries than the framework could build? I just feel I could get my apps running better without a framework. What are your thoughts?

    Read the article

  • Help needed to construct a SQL query

    - by song202y
    Need your help to get the list of suggested friends (who aren't friends of the current user but are friends of 2 or more of the current user's friends). The primary ordering should put people at the same school at the top, and the secondary ordering should put people with more common friends (that is, the number of people who are friends of that person and the current user) near the top. Users: user_id PK, user_name Profiles: user_id PK, school_name, ... Friendships: id PK, user_id FK, friend_id FK Thank you in advance. Joe

    Read the article

  • How can I figure out a users postal code if I have their latitude / longitude location? Need help w

    - by mike
    I'm using HTML5 geolocation to collect the users lat / long and I need to figure out what their postal code is as well. I have a database of all the lat / long for each postal code in the US & Canada. How can I write a query to find out what their postal code is? Below, is an example of how the data is structured in the 'zips' table. Country PostalCode Latitude Longitude USA 0051 40.813078 -73.046388 USA 00616 18.426456 -66.673779 I can't do a 'SELECT PostalCode FROM zips WHERE Latitude = user.lat AND Longitude = user.long'. I believe I need to find the nearest lat / long. Any suggestions on how I can write this?

    Read the article

< Previous Page | 360 361 362 363 364 365 366 367 368 369 370 371  | Next Page >