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  • Help needed to construct a SQL query

    - by song202y
    Need your help to get the list of suggested friends (who aren't friends of the current user but are friends of 2 or more of the current user's friends). The primary ordering should put people at the same school at the top, and the secondary ordering should put people with more common friends (that is, the number of people who are friends of that person and the current user) near the top. Users: user_id PK, user_name Profiles: user_id PK, school_name, ... Friendships: id PK, user_id FK, friend_id FK Thank you in advance. Joe

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  • self join to select consecutive numbers

    - by shantanuo
    CREATE TABLE `mybug` ( `SEAT_NO` decimal(2,0) NOT NULL, `ROW_NO` decimal(2,0) NOT NULL, `COL_NO` decimal(2,0) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; INSERT INTO `mybug` VALUES ('1','1','1'),('26','7','2'),('31','8','2'),('32','8','1'),('33','9','1'),('34','9','2'),('35','9','5'),('36','9','6'),('37','10','6'),('38','10','5'),('39','10','2'),('40','10','1'),('41','11','1'),('42','11','2'),('43','11','4'),('44','11','5'); +---------+--------+--------+ | SEAT_NO | ROW_NO | COL_NO | +---------+--------+--------+ | 1 | 1 | 1 | | 26 | 7 | 2 | | 31 | 8 | 2 | | 32 | 8 | 1 | | 33 | 9 | 1 | | 34 | 9 | 2 | | 35 | 9 | 5 | | 36 | 9 | 6 | | 37 | 10 | 6 | | 38 | 10 | 5 | | 39 | 10 | 2 | | 40 | 10 | 1 | | 41 | 11 | 1 | | 42 | 11 | 2 | | 43 | 11 | 4 | | 44 | 11 | 5 | +---------+--------+--------+ 16 rows in set (0.00 sec) In the above chart, I need to select 2 seats those are in the same row AND column numbers are next to each other. For e.g. Seat Numbers 38 & 39 can not be issued even if both the seats are from the same row because the column numbers 2 & 5 are not adjacent. The expected results are as follows: 31 33 35 37 39 41 43 These are the starting numbers and the next seat will be automatically booked as well. for e.g. 31 & 32

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  • Having a problem inserting into database

    - by neo skosana
    I have a stored procedure: CREATE PROCEDURE busi_reg(IN instruc VARCHAR(10), IN tble VARCHAR(20), IN busName VARCHAR(50), IN busCateg VARCHAR(100), IN busType VARCHAR(50), IN phne VARCHAR(20), IN addrs VARCHAR(200), IN cty VARCHAR(50), IN prvnce VARCHAR(50), IN pstCde VARCHAR(10), IN nm VARCHAR(20), IN surname VARCHAR(20), IN eml VARCHAR(50), IN pswd VARCHAR(20), IN srce VARCHAR(50), IN refr VARCHAR(50), IN sess VARCHAR(50)) BEGIN INSERT INTO b_register SET business_name = busName, business_category = busCateg, business_type = busType, phone = phne, address = addrs, city = cty, province = prvnce, postal_code = pstCde, firstname = nm, lastname = surname, email = eml, password = pswd, source = srce, ref_no = refr; END; This is my php script: $busName = $_POST['bus_name']; $busCateg = $_POST['bus_cat']; $busType = $_POST['bus_type']; $phne = $_POST['phone']; $addrs = $_POST['address']; $cty = $_POST['city']; $prvnce = $_POST['province']; $pstCde = $_POST['postCode']; $nm = $_POST['name']; $surname = $_POST['lname']; $eml = $_POST['email']; $srce = $_POST['source']; $ref = $_POST['ref_no']; $result2 = $db->query("CALL busi_reg('$instruc', '$tble', '$busName', '$busCateg', '$busType', '$phne', '$addrs', '$cty', '$prvnce', '$pstCde', '$nm', '$surname', '$eml', '$pswd', '$srce', '$refr', '')"); if($result) { echo "Data has been saved"; } else { printf("Error: %s\n",$db->error); } Now the error that I get: Commands out of sync; you can't run this command now

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  • mysql_query where statment help

    - by Anders Kitson
    I am retrieving values from the url with the GET method and then using a if statement to determine of they are there then query them against the database to only show those items that match them, i get an unknown error with your request. here is my code $province = $_GET['province']; $city = $_GET['city']; if(isset($province) && isset($city) ) { $results3 = mysql_query("SELECT * FROM generalinfo WHERE province = $province AND city = $city ") or die( "An unknown error occurred with your request"); } else { $results3 = mysql_query("SELECT * FROM generalinfo"); } /*if statement ends*/

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  • Duplicate Blob field with foreach

    - by JGSilva
    I have some fields (blob) where I have uploaded some images. The images display correctly and I can open it without problem in Photoshop for example. I created a button where user can duplicate the product and everything works fine, but when it comes to duplicate the image entry I got some errors, like 1064 and others ones that I can't remember cause I am working 3 days inside this. Because de original product have 3 or more images I select then and gave an foreach. What I notice when a print de blob is that in the end it eats the next array, like if don't have an end. In other words, the next item got inside that utf-8 character in the print. That gave me some clue. The next approach was to save it in somewhere, and reupload it. The problem is that only the first one works. When I download the image saved, it opens normally so, it is not a saving in disk problem. When I gave a print in the $result, the same happens, is like the image is hungry and ate the next one. Here is the code. Notice = I created the [$count] to see if was not an rewrite in array error. Even tried to , in beging of the foreach, kind of clean the vars… $count=0; foreach ($original_image as $key => $val) { $count++; //$arquivo = ''; //$image = ''; //$file = ''; //$this->image = ''; //$return = ''; $arquivo[$count] = $val['pi_id'].'.'.$val['pi_type']; $image[$count] = $caminho_url.$arquivo[$count]; if (file_exists($image[$count])) { $this->image = Image::factory($image[$count]); $this->image->save($image[$count]); $file[$count]=mysql_real_escape_string(addslashes(fread(fopen($image[$count], "r"), filesize($image[$count])))); $return[$count] = Product::add_image($id_prod, $file[$count], $val['pi_type'],$val['pi_main']); }else { die('no'); } }

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  • COUNT issue across multiple tables

    - by Kim
    I am trying to count across 2 tables and I dont see whats wrong with my query yet I get a wrong result. User 2 does not exist in table_two, so the zero is correct. SELECT t1.creator_user_id, COUNT(t1.creator_user_id), COUNT(t2.user_id) FROM table_one AS t1 LEFT JOIN table_two AS t2 ON t2.user_id = t1.creator_user_id GROUP BY t1.creator_user_id, t2.user_id Actual result 1 192 192 2 9 0 Expected result 1 16 12 2 9 0 The result indicate a missing group by condition, but I already got both fields used. Where am I wrong ? Also, can I sum up all users that doesnt exist in table_two for t1 ? Like user 3 exists 21 times in t1, then the results would be: 1 16 12 (users with > 0 in t2 will need their own row) 2 30 0 (user 2=9 + user 3=21 => 30) Its okay for the user Id to be wrong for sum of t1 for all users with 0 in t2. If not possible, then I'll just do two queries.

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  • How can I get columns name from select query in php?

    - by Farshad Mehrvarzan
    I want to execute a SELECT query but I don't how many columns to select. Like: select name, family from persons; How can I know which columns to select? "I am currently designing a site for the execute query by users. So when the user executes this query, I won't know which columns selected. But when I want to show the results and draw a table for the user I should know which columns selected."

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  • How do I workaround this error ? You can't specify target table my table for update in FROM clause

    - by Jules
    I'm struggling to convert my select query into a update query, it has aliases.. Update pads set RemoveMeDate = '1999-01-01 00:00:00' where padid in ( SELECT old_table.padid FROM `jules-fix-reasons`.`pads` AS old_table JOIN `jules`.`pads` AS new_table ON old_table.padid = new_table.`PadID` WHERE new_table.RemoveMeDate <> '2001-01-01 00:00:00' AND old_table.RemoveMeDate = '2001-01-01 00:00:00') I've tried removing the aliases, but that doesn't help :(

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  • How can I figure out a users postal code if I have their latitude / longitude location? Need help w

    - by mike
    I'm using HTML5 geolocation to collect the users lat / long and I need to figure out what their postal code is as well. I have a database of all the lat / long for each postal code in the US & Canada. How can I write a query to find out what their postal code is? Below, is an example of how the data is structured in the 'zips' table. Country PostalCode Latitude Longitude USA 0051 40.813078 -73.046388 USA 00616 18.426456 -66.673779 I can't do a 'SELECT PostalCode FROM zips WHERE Latitude = user.lat AND Longitude = user.long'. I believe I need to find the nearest lat / long. Any suggestions on how I can write this?

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  • Understanding Nested If.. Else statements

    - by user1174762
    For some reason my PHP login script keeps returning "invalid email/password combination", yet i know I am entering the correct email and password. Does anyone see what I might be doing wrong? <?php $email= $_POST['email']; $password= $_POST['password']; if (!empty($email) && !empty($password)) { $connect= mysqli_connect("localhost", "root", "", "si") or die('error connecting with the database'); $query= "SELECT user_id, email, password FROM users WHERE email='$email' AND password='$password'"; $result= mysqli_query($connect, $query) or die('error with query'); if (mysqli_num_rows($result) == 1) { $row= mysqli_fetch_array($result); setcookie('user_id', $row['user_id']); echo "you are now logged in"; } else { echo "invalid username/password combination"; } } else { echo" you must fill out both username and password"; } ?>

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  • Stop invalid data in a attribute with foreign key constraint using triggers?

    - by Eternal Learner
    How to specify a trigger which checks if the data inserted into a tables foreign key attribute, actually exists in the references table. If it exist no action should be performed , else the trigger should delete the inserted tuple. Eg: Consider have 2 tables R(A int Primary Key) and S(B int Primary Key , A int Foreign Key References R(A) ) . I have written a trigger like this : Create Trigger DelS BEFORE INSERT ON S FOR EACH ROW BEGIN Delete FROM S where New.A <> ( Select * from R;) ); End; I am sure I am making a mistake while specifying the inner sub query within the Begin and end Blocks of the trigger. My question is how do I make such a trigger ?

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  • What might be causing this Rails method error?

    - by Trip
    My error: Notice the undefined method '-@' . This is for a sort by. All sorts on one page break, but all the sorts on other pages use the same helper and do not break. Does it allude to something obvious? Processing OrganizationsController#search (for ::1 at 2010-05-13 15:42:01) [GET] Parameters: {"action"=>"search", "controller"=>"organizations", "direction"=>"desc", "_"=>"1273779721464", "order_by"=>"published_at"} SQL (0.5ms) SHOW TABLES Organization Columns (2.2ms) SHOW FIELDS FROM `organizations` NoMethodError (undefined method `-@' for #<Array:0x2f88cc8>): app/controllers/organizations_controller.rb:190:in `search' sunspot (1.0.5) lib/sunspot/util.rb:84:in `call' sunspot (1.0.5) lib/sunspot/util.rb:84:in `instance_eval_or_call' sunspot (1.0.5) lib/sunspot/search.rb:200:in `build' sunspot (1.0.5) lib/sunspot/session.rb:45:in `new_search' sunspot (1.0.5) lib/sunspot/session.rb:53:in `search' sunspot (1.0.5) lib/sunspot/session_proxy/abstract_session_proxy.rb:11:in `search' sunspot (1.0.5) lib/sunspot.rb:323:in `search' app/controllers/organizations_controller.rb:183:in `search' haml (2.2.2) [v] rails/./lib/sass/plugin/rails.rb:19:in `process' lib/flash_session_cookie_middleware.rb:14:in `call' vendor/gems/hoptoad_notifier-2.2.2/lib/hoptoad_notifier/rack.rb:27:in `call' /usr/local/lib/ruby/1.8/webrick/httpserver.rb:104:in `service' /usr/local/lib/ruby/1.8/webrick/httpserver.rb:65:in `run' /usr/local/lib/ruby/1.8/webrick/server.rb:173:in `start_thread' /usr/local/lib/ruby/1.8/webrick/server.rb:162:in `start' /usr/local/lib/ruby/1.8/webrick/server.rb:162:in `start_thread' /usr/local/lib/ruby/1.8/webrick/server.rb:95:in `start' /usr/local/lib/ruby/1.8/webrick/server.rb:92:in `each' /usr/local/lib/ruby/1.8/webrick/server.rb:92:in `start' /usr/local/lib/ruby/1.8/webrick/server.rb:23:in `start' /usr/local/lib/ruby/1.8/webrick/server.rb:82:in `start' Rendered rescues/_trace (68.5ms) Rendered rescues/_request_and_response (0.6ms) Rendering rescues/layout (internal_server_error)

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  • How do I create a user history?

    - by ggfan
    I want to create a user history function that allows shows users what they done. ex: commented on an ad, posted an ad, voted on an ad, etc. How exactly do I do this? I was thinking about... in my site, when they log in it stores their user_id ($_SESSION['user_id']) so I guess whenever an user posts an ad(postad.php), comments(comment.php), I would just store in a database table "userhistory" what they did based on whenever or not their user_id was activate. When they comment, I store the user_id in the comment dbc table, so I'll also store it in the "userhistory" table. And then I would just queries all the rows in the dbc for the user to show it Any steps/improvements I can make? :)

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  • Select 2 Rows from Table when COUNT of another table

    - by Marcus
    Here is the code that I currently have: SELECT `A`.* FROM `A` LEFT JOIN `B` ON `A`.`A_id` = `B`.`value_1` WHERE `B`.`value_2` IS NULL AND `B`.`userid` IS NULL ORDER BY RAND() LIMIT 2 What it currently is supposed to do is select 2 rows from A when the 2 rows A_id being selected are not in value_1 or value_2 in B. And the rows in B are specific to individual users with userid. What I need to do is make it also so that also checks if there are already N rows in B matching a A_id (either in value_1, or value_2) and userid, and if there are more than N rows, it doesn't select the A row.

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  • sql UPDATE, a calculation is used multiple times, can it just be calculated once?

    - by Zachery Delafosse
    UPDATE `play` SET `counter1` = `counter1` + LEAST(`maxchange`, FLOOR(`x` / `y`) ), `counter2` = `counter2` - LEAST(`maxchange`, FLOOR(`x` / `y`) ), `x` = MOD(`x`, `y`) WHERE `x` `y` AND `maxchange` 0 As you can see, " LEAST(`maxchange`, FLOOR(`x` / `y`) ) " is used multiple times, but it should always have the same value. Is there a way to optimize this, to only calculate once? I'm coding this in PHP, for the record.

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  • Query returning related assets

    - by GMo
    I have 2 tables, one is an assets table which holds digital assets (e.g. article, images etc), the 2nd table is an asset_links table which maps 1-1 relationships between assets contained within the assets table. Here are the table definitions: Asset +---------------+--------------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +---------------+--------------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | source | varchar(255) | YES | | NULL | | | title | varchar(255) | YES | | NULL | | | date_created | datetime | YES | | NULL | | | date_embargo | datetime | YES | | NULL | | | date_expires | datetime | YES | | NULL | | | date_updated | datetime | YES | | NULL | | | keywords | varchar(255) | YES | | NULL | | | status | int(11) | YES | | NULL | | | priority | int(11) | YES | | NULL | | | fk_site | int(11) | YES | MUL | NULL | | | resource_type | varchar(255) | YES | | NULL | | | resource_id | int(11) | YES | | NULL | | | fk_user | int(11) | YES | MUL | NULL | | +---------------+--------------+------+-----+---------+----------------+ Asset_links +-----------+---------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +-----------+---------+------+-----+---------+----------------+ | id | int(11) | NO | PRI | NULL | auto_increment | | asset_id1 | int(11) | YES | | NULL | | | asset_id2 | int(11) | YES | | NULL | | +-----------+---------+------+-----+---------+----------------+ In the asset_links table there are the following rows: 1 - 3, 1 - 4, 2 - 10, 2 - 56 I am looking to write one query which will return all assets which satisfy any asset search criteria and within the same query return all of the linked asset data for linked assets for that asset. e.g. The query returning assets 1 and 2 would return : Asset 1 attributes - Asset 3 attributes - Asset 4 attributes Asset 2 attributes - Asset 10 attributes - Asset 56 attributes What is the best way to write the query?

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  • Very simple shopping cart, remove button

    - by Kynian
    Im writing sales software that will be walking through a set of pages and on certain pages there are items listed to sell and when you click buy it basically just passes a hidden variable to the next page to be set as a session variable, and then when you get to the end it call gets reported to a database. However my employer wanted me to include a shopping cart, and this shopping cart should display the item name, sku, and price of whatever you're buying, as well as a remove button so the person doing the script doesnt need to go back through the entire thing to remove one item. At the moment I have the cart set to display everything, which was fairly simple. but I cant figure out how to get the remove button to work. Here is the code for the shopping cart: $total = 0; //TEST CODE: $_SESSION['itemname-addon'] = "Test addon"; $_SESSION ['price-addon'] = 10.00; $_SESSION ['sku-addon'] = "1234h"; $_SESSION['itemname-addon1'] = "Test addon1"; $_SESSION ['price-addon1'] = 99.90; $_SESSION ['sku-addon1'] = "1111"; $_SESSION['itemname-addon2'] = "Test addon2"; $_SESSION ['price-addon2'] = 19.10; $_SESSION ['sku-addon2'] = "123"; //end test code $items = Array ( "0"=> Array ( "name" => $_SESSION['itemname-mo'], "price" => $_SESSION ['price-mo'], "sku" => $_SESSION ['sku-mo'] ), "1" => Array ( "name" => $_SESSION['itemname-addon'], "price" => $_SESSION ['price-addon'], "sku" => $_SESSION ['sku-addon'] ), "2" => Array ( "name" => $_SESSION['itemname-addon1'], "price" => $_SESSION ['price-addon1'], "sku" => $_SESSION ['sku-addon1'] ), "3" => Array ( "name" => $_SESSION['itemname-addon2'], "price" => $_SESSION ['price-addon2'], "sku" => $_SESSION ['sku-addon2'] ) ); $a_length = count($items); for($x = 0; $x<$a_length; $x++){ $total +=$items[$x]['price']; } $formattedtotal = number_format($total,2,'.',''); for($i = 0; $i < $a_length; $i++){ $name = $items[$i]['name']; $price = $items[$i]['price']; $sku = $items[$i]['sku']; displaycart($name,$price,$sku); } echo "<br /> <b>Sub Total:</b> $$formattedtotal"; function displaycart($name,$price,$sku){ if($name != null || $price != null || $sku != null){ if ($name == "no sale" || $price == "no sale" || $sku == "no sale"){ echo ""; } else{ $formattedprice = number_format($price,2,'.',''); echo "$name: $$formattedprice ($sku)"; echo "<form action=\"\" method=\"post\">"; echo "<button type=\"submit\" />Remove</button><br />"; echo "</form>"; } } } So at this point Im not sure where to go from here for the remove button. Any suggestions would be appreciated.

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