planet mysql - Page 368

How can I figure out a users postal code if I have their latitude / longitude location? Need help w

- by mike

I'm using HTML5 geolocation to collect the users lat / long and I need to figure out what their postal code is as well. I have a database of all the lat / long for each postal code in the US & Canada. How can I write a query to find out what their postal code is? Below, is an example of how the data is structured in the 'zips' table. Country PostalCode Latitude Longitude USA 0051 40.813078 -73.046388 USA 00616 18.426456 -66.673779 I can't do a 'SELECT PostalCode FROM zips WHERE Latitude = user.lat AND Longitude = user.long'. I believe I need to find the nearest lat / long. Any suggestions on how I can write this?

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CakePHP Form Helper Database Interaction

- by xtine

Currently I am developing a CakePHP that will list various businesses. In the database, there is a table for businesses that lists them like so: id | name | address | city | state | state_id | zip | url The state column are abbreviations of states (for listing purposes) CA, AK, FL, etc and the state_id matches up with the ids in the states table: id | name | state_abbr I have an admin_add.ctp template with form helpers for inserting new businesses. For entering a state for a business I am going to have a pull down that lists all the states. However, how do I make the database insert so it will know how to add the state abbreviation and state id when I submit the form to add the business?

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storing numbers as varchar

- by Yeti

Is it ok to store numbers as varchar? What's the difference between int 123456789012 and varchar 123456789012 ?

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Connection Pool Strategy: Good, Bad or Ugly?

- by Drew

I'm in charge of developing and maintaining a group of Web Applications that are centered around similar data. The architecture I decided on at the time was that each application would have their own database and web-root application. Each application maintains a connection pool to its own database and a central database for shared data (logins, etc.) A co-worker has been positing that this strategy will not scale because having so many different connection pools will not be scalable and that we should refactor the database so that all of the different applications use a single central database and that any modifications that may be unique to a system will need to be reflected from that one database and then use a single pool powered by Tomcat. He has posited that there is a lot of "meta data" that goes back and forth across the network to maintain a connection pool. My understanding is that with proper tuning to use only as many connections as necessary across the different pools (low volume apps getting less connections, high volume apps getting more, etc.) that the number of pools doesn't matter compared to the number of connections or more formally that the difference in overhead required to maintain 3 pools of 10 connections is negligible compared to 1 pool of 30 connections. The reasoning behind initially breaking the systems into a one-app-one-database design was that there are likely going to be differences between the apps and that each system could make modifications on the schema as needed. Similarly, it eliminated the possibility of system data bleeding through to other apps. Unfortunately there is not strong leadership in the company to make a hard decision. Although my co-worker is backing up his worries only with vagueness, I want to make sure I understand the ramifications of multiple small databases/connections versus one large database/connection pool.

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How to get multiple counts with one SQL query?

- by Crobzilla

I am wondering how to write this query. I know this actual syntax is bogus, but it will help you understand what I am wanting. I need it in this format, because it is part of a much bigger query. SELECT distributor_id, COUNT(*) AS TOTAL, COUNT(*) WHERE level = 'exec', COUNT(*) WHERE level = 'personal' I need this all returned in one query. Also, it need to be in one row, so the following won't work: 'SELECT distributor_id, COUNT(*) GROUP BY distributor_id'

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Strange data swapping error occurs when I attempt to update rows in my table from another table in m

- by Wesley

So I have a table of data that is 10,000 lines long. Several of the columns in the table simply describe information about one of the columns, meaning, that only one column has the content, and the rest of the columns describe the location of the content (its for a book). Right now, only 6,000 of the 10,000 rows' content column is filled with its content. Rows 6-10,000's content column simply says null. I have another table in the db that has the content for rows 6,000-10,000, with the correct corresponding primary key which would (seemingly) make it easy to update the 10,000 row table. I have been trying an update query such as the following: UPDATE table(10,000) SET content_column = (SELECT content FROM table(6,000-10,000) WHERE table(10,000).id = table(6-10,000.id) Which kind of works, the only problem is that it pulls in the data from the second table just fine, but it replaces the existing content column with null. So rows 1-6,000's content column become null, and rows 6-10,000's content column have the correct values...Pretty strange I thought anyway. Does anybody have any thoughts about where I am going wrong? If you could show me a better sql query, I would appreciate it! Thanks

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Multiple left joins, how to output in php

- by Dan

I have 3 tables I need to join. The contracts table is the main table, the 'jobs' and 'companies' table are extra info that can be associated to the contracts table. so, since I want all entries from my 'contracts' table, and the 'jobs' and 'companies' data only if it exists, I wrote the query like this.... $sql = "SELECT * FROM contracts LEFT JOIN jobs ON contracts.job_id = jobs.id LEFT JOIN companies ON contracts.company_id = companies.id ORDER BY contracts.end_date"; Now how would I output this in PHP? I tried this but kept getting an undefined error "Notice: Undefined index: contracts.id"... $sql_result = mysql_query($sql,$connection) or die ("Fail."); if(mysql_num_rows($sql_result) > 0){ while($row = mysql_fetch_array($sql_result)) { $contract_id = stripslashes($row['contracts.id']); $job_number = stripslashes($row['jobs.job_number']); $company_name = stripslashes($row['companies.name']); ?> <tr id="<?=$contract_id?>"> <td><?=$job_number?></td> <td><?=$company_name?></td> </tr> <? } }else{ echo "No records found"; } Any help is appreciated.

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PHP Ajax not working

- by Kostis

I have 3 buttons on my page and depending on which one the user is clickingi want to run through ajax call a delete query in my database. When the user clicks on a button the javascript function seems to work but it doesn't run the query in php script. The html page: <?php session_start(); ?> <!DOCTYPE HTML> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=iso-8859-7"> <script> function myFunction(name) { var r=confirm("Are you sure? This action cannot be undone!"); if (r==true) { alert(name); // check if is getting in if statement and confirm the parameter's value var xmlhttp; if (str.length==0) { document.getElementById("clearMessage").innerHTML=""; return; } if (window.XMLHttpRequest) {// code for IE7+, Firefox, Chrome, Opera, Safari xmlhttp=new XMLHttpRequest(); } else {// code for IE6, IE5 xmlhttp=new ActiveXObject("Microsoft.XMLHTTP"); } xmlhttp.onreadystatechange=function() { if (xmlhttp.readyState==4 && xmlhttp.status==200) { document.getElementById("clearMessage").innerHTML= responseText; } } xmlhttp.open("GET","clearDatabase.php?q="+name,true); xmlhttp.send(); } else alert('pff'); } </script> </head> <body> <div id="wrapper"> <div id="header"></div> <div id="main"> <?php if (session_is_registered("username")){ ?>  <input type="button" value="???a????s? pa?a??? µ???µ?t??" onclick="myFunction('messages')" /> <input type="button" value="???a????s? pa?a??? s??ed????" onclick="myFunction('conferences')" /> <input type="button" value="???a????s? push notifications" onclick="myFunction('notifications')" /> <div id="clearMessage"></div> <?php } else echo "Login first."; ?> </div> <div id="footer"></div> </div> </body> </html> and the php script: <?php if (isset($_GET["q"])) $q=$_GET["q"]; $host = "localhost"; $database = "dbname"; $user = "dbuser"; $pass = "dbpass"; $con = mysql_connect($host,$user,$pass) or die(mysql_error()); mysql_select_db($database,$con) or die(mysql_error()); if ($q=="messages") $query = "DELETE FROM push_message WHERE time_sent IS NOT NULL"; else if ($q=="conferences") $query = "DELETE FROM push_message WHERE time_sent IS NOT NULL"; else if ($q=="notifications") { $query = "DELETE FROM push_friend WHERE time_sent IS NOT NULL"; } $res = mysql_query($query,$con) or die(mysql_error()); if ($res) echo "success"; else echo "failed"; mysql_close($con); ?>

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Query returning related assets

- by GMo

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WHERE id IN doesn't work in UPDATE

- by Donator

UPDATE statistics' SET money = money + '$money' WHERE member_id IN ((SELECT member_id FROM races WHERE l_id = '$mem_id'), $other_id) What's wrong with that? I want to retrieve all member_ids from races and also include to member_id $other_id. Without $other_id it works. By the way, it gives me "Subquery returns more than 1 row" error.

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WHERE id IN doesn't work in UPDATE

- by Donator

UPDATE static SET money = money + '100' WHERE member_id IN (SELECT member_id FROM race WHERE race_id = '$race_id')" I want to retrieve member_ids and give for all of them +100 money. What's wrong?

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form not showing for empty records

- by Chris Hodges

I have a relatively simple PHP page called editcustomers with 3 columns. The problem I'm having is that the form will show when there is a record in the database and the fields will be populated with that info. When no such records exists, the form is not even shown, eliminating the possibility to insert a record. My page layout is as follows: Column 1 shows a form containing customer information, allowing it to be edited. Column 2 allows ordering of products and showing how many products were ordered Column 3 shows the total paid so far, and the total owing. The code for the page I have at present: <html> <?php $id = $_GET['id']; require_once('connect.php'); $sth = $dbh->query("SELECT * FROM users where id = '$id';"); $sth->setFetchMode(PDO::FETCH_ASSOC); $eth = $dbh->query("SELECT * FROM purchases where id = '$id';"); $eth->setFetchMode(PDO::FETCH_ASSOC); ?> <div id="main"> <div id="left"> <form name="custInfo" action ="process.php" method ="post" > <input type = "hidden" name ="formType" value="custInfo"/> <?php while($row = $sth->fetch()){ ?> <p><input type = "hidden" name ="id" value="<?php echo $row["id"] ?>"/> <p><input type = "text" name ="firstName" size ="30" value=" <?php echo $row["firstName"]?>"/> <p><input type = "text" name ="lastName" size ="30" value="<?php echo $row["lastName"]?>"/> <p><input type = "text" name ="country" size ="30" value="<?php echo $row["country"]?>"/> <p></p> <input type="submit" value="Update" /> <?php }?> </div> <div id="mid"> <form name="custCosts" action ="process.php" method ="post" > <input type = "hidden" name ="formType" value="custCosts"/> <?php while($row = $eth->fetch()){ ?> <p><input type = "hidden" name ="id" value="<?php echo $row["id"] ?>"/> <p><input type = "text" name ="amountOwed" size ="30" value=" <?php echo $row["amountOwed"]?>"/> <p><input type = "text" name ="numAaa" size ="30" value="<?php echo $row["numAaa"]?>"/> <p><input type = "text" name ="numBbb" size ="30" value="<?php echo $row["numBbb"]?>"/> <p></p> <input type="submit" value="Update" /> <?php }?> </div> <div id="right"> <b>Total Balance</b> <p> Money owed: </p> <p> aaa total: </p> <p> bbb total: </p> <p> Total: </p> <input type = "text" name ="pay" size ="20" /></p> <input type="submit" value="Make Payment" /> </div> <?php $dbh =null; ?> </body> </html> And the code for all the database trickery: <?php require_once 'connect.php'; $formType = $_POST['formType']; $id = $_POST['id']; $firstName = $_POST['firstName']; $lastName = $_POST['lastName']; $country = $_POST['country']; $amountOwed = $_POST['amountOwed ']; $numAaa = $_POST['numAaa']; $numBbb = $_POST['numBbb']; if(empty($_POST['id'])) { $sth = $dbh->prepare("INSERT INTO customers (firstName, lastName, country) VALUES ('$firstName', '$lastName', '$country')"); $sth->execute(); } elseif(!empty($_POST['id']) && !isset($_POST['stayCost']) && $_POST['formType'] == 'guestInfo'){ $sth = $dbh->prepare("UPDATE customers SET firstName = '$firstName', lastName = '$lastName', country = '$country' WHERE id = '$id'"); $sth->execute(); }elseif(!empty($_POST['id']) && isset($_POST['stayCost']) && $_POST['formType'] == 'guestInfo'){ $sth = $dbh->prepare("INSERT INTO purchases (id, amountOwed, numAaa, numBbb) VALUES ('$id', '$amountOwed', '$numAaa', '$numBbb'"); $sth->execute(); }elseif(!empty($_POST['id']) && $_POST['formType'] == 'guestCosts'){ $sth = $dbh->prepare("UPDATE purchases SET amountOwed= '$amountOwed', numAaa = '$numAaa', numBbb= '$numBbb' WHERE id = '$id'"); $sth->execute(); } $dbh =null; ?> Why does the form not even display if there is no record? An error or something I might understand....but the form is still in the HTML and should still be being output, from what I can see. Why is this not the case?

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How trasmit a Dictionary in a jsons form

- by xRobot

I have a dictionary in jsons form like this: $user = "{ name: Mary , born: 1963, money: 213 }"; I need to pass it throught this field: <input type="hidden" name="custom" value="" > and then insert it in the db: INSERT INTO user ( name, born, money ) VALUE ( $name, $born, $money ) How can I do that ?

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Wrong logic in If Statement?

- by Charles

$repeat_times = mysql_real_escape_string($repeat_times); $result = mysql_query("SELECT `code`,`datetime` FROM `fc` ORDER by datetime desc LIMIT 25") or die(mysql_error()); $output .=""; $seconds = time() - strtotime($fetch_array["datetime"]); if($seconds < 60) $interval = "$seconds seconds"; else if($seconds < 3600) $interval = floor($seconds / 60) . " minutes"; else if($seconds < 86400) $interval = floor($seconds / 3600) . " hours"; else $interval = floor($seconds / 86400) . " days"; while ($fetch_array = mysql_fetch_array($result)) { $fetch_array["code"] = htmlentities($fetch_array["code"]); $output .= "<li><a href=\"http://www.***.com/code=" . htmlspecialchars(urlencode($fetch_array["code"])) . "\" target=\"_blank\">" . htmlspecialchars($fetch_array["code"]) . "</a> (" . $interval . ") ago.</li>"; } $output .=""; return $output; Why is this returning janice (14461 days) instead of janice (15 minutes ago) The datetime function table has the DATETIME type in my table so it's returning a full string for the date.

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Efficient way to combine results of two database queries.

- by ensnare

I have two tables on different servers, and I'd like some help finding an efficient way to combine and match the datasets. Here's an example: From server 1, which holds our stories, I perform a query like: query = """SELECT author_id, title, text FROM stories ORDER BY timestamp_created DESC LIMIT 10 """ results = DB.getAll(query) for i in range(len(results)): #Build a string of author_ids, e.g. '1314,4134,2624,2342' But, I'd like to fetch some info about each author_id from server 2: query = """SELECT id, avatar_url FROM members WHERE id IN (%s) """ values = (uid_list) results = DB.getAll(query, values) Now I need some way to combine these two queries so I have a dict that has the story as well as avatar_url and member_id. If this data were on one server, it would be a simple join that would look like: SELECT * FROM members, stories WHERE members.id = stories.author_id But since we store the data on multiple servers, this is not possible. What is the most efficient way to do this? Thanks.

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Wrong intrepretation of some columns in ireport

- by Purushotham

Hi, I got a strange problem. I am using iReport 3.7.1 tool to create some reports. The Query Editor has one query. It shows all the data types of the fields in that query exactly same as the data types shown when I execute it using SQLYOG editor. The problem is here: One field data type is mismatched. I don't know the reason. SQLYOG says it is INTEGER whereas iReport Query Editor says its a long value. BTW The value that assigned to that filed is zero. Can anyone help ? I want to zero-in on this issue.

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mysqli_query SELECT FROM WHERE [ partial match ] ?

- by user296516

Hi guys, I have a database that a time filed that is stored in this format "2010.06.04. | 18:53 01". What I need is to select rows that have a specific date, for example "2010.06.04." Right now I am doing it my first selecting all rows and then looping through them and adding ones with the specified date to a new array. Maybe there is an easier way to do it and I somehow can select it using mysqli_query? Thanks!

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What logic can be applied to create the Insert query from given Audit table?

- by Parth

i need to create a PHP script to create the insert query to insert in a table, The table from which I need to fetch out the data to create insert query is given below.. The query has to be like this INSERT INTO table_name (field1,field2, field3...) values('newvalue','newvalue','newvalue',....) Please Help... Thanks

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Which is best and easy way to program and show many to many relationship in databse

- by Mirage

I have two quantities Cat A , CatB Now the items in Cat A can belong to many items in CatB. and CatB will also have many Items from Cat A. I thinking of having Table1 for Cat A , Table2 for CatB and Table C for relation ship. with PK-A , PK-B Is that correct. How should i make my form in html so that user can select multiple values. Currently i am using select box Any ideas

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client computer name

- by Anup Prakash

After getting the client(Website user) IP address. Now i want to go one step ahead by knowing the Computer name of the user. So, agian i need help from my question viewer to help me regarding computer name of the client(website user). I tried it by myself using google. But at last i thought it is better to ask to all of you who have better and best answers. Thanx again to see my query. And much much thanx for them who are answering this question.

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How to UNION ALL two SELECT statements?

- by Lisa

I have 2 tables, one looks like this: TABLE ONE id | Last Name | First Name | Username | Password | Secret Question and another that looks like this: TABLE TWO id | Hobby | Country | I want to combine a Select statement that grabs data from both tables and output the results. The following code: $select = mysql_query(" SELECT * FROM table_one WHERE Username = 'Bob' UNION ALL SELECT * FROM table_two WHERE Hobby = 'Baseball' "); while ($return = mysql_fetch_assoc($select)) { $userName = $return['Username']; $hobby = $return['Hobby']; } echo "$userName likes $hobby"; results in a The used SELECT statements have a different number of columns error, what am I doing wrong?

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Unique constraint not created in JPA

- by homaxto

I have created the following entity bean, and specified two columns as being unique. Now my problem is that the table is created without the unique constraint, and no errors in the log. Does anyone have an idea? @Entity @Table(name = "cm_blockList", uniqueConstraints = @UniqueConstraint(columnNames = {"terminal", "blockType"})) public class BlockList { @Id @GeneratedValue(strategy = GenerationType.AUTO) private int id; @ManyToOne(cascade = CascadeType.PERSIST) @JoinColumn(name="terminal") private Terminal terminal; @Enumerated(EnumType.STRING) private BlockType blockType; private String regEx; }

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PHP reporting error. DB verify how to?

- by iamfab

Error reporting Notice: Undefined variable: random_chars in wamp\www\php_sandbox\idgen.php on line 21 Call Stack: # Time Memory Function Location 1 0.0045 678928 {main}( ) ..\idgen.php:0 GPB7446 How do I fix this error? Using this code like an automatic unique id generator. How do I connect to DB to verify code is truly unique before allowing it to be assigned to a user creating a new account? Thanks <?php $characters = array( "A","B","E","F","G","H","J","K","M","N","P","R","S","T","W","X","Y","Z"); $keys = array(); while(count($keys) < 3) { $x = mt_rand(0, count($characters)-1); if(!in_array($x, $keys)) { $keys[] = $x; } } foreach($keys as $key){ $random_chars .= $characters[$key];} $randNum = rand(2327,9987); $randLet = rand(2327,9987); echo $random_chars . $randNum; ?>

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How to join 2 tables & display them correctly?

- by steven

http://img293.imageshack.us/img293/857/tablez.jpg Here is a picture of the 2 tables. The mybb_users table is the table that has the users that signed up for the forum. The mybb_userfields is the table that contain custom profile field data that they are able to customize & change in their profile. Now, all I want to do is display all users in rows with the custom profile field data that they provided in their profile(which is in the mybb_userfields table) How can I display these fields correctly together? For instance, p0gz is a male,lives in AZ,he owns a 360,does not know his bandwidth & Flip Side Phoenix is his team. How can it just be like "p0gz-male-az-360-dont know-flipside phoenix" in a row~???

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Best way to run multiple queries per second on database, performance wise?

- by Michael Joell

I am currently using Java to insert and update data multiple times per second. Never having used databases with Java, I am not sure what is required, and how to get the best performance. I currently have a method for each type of query I need to do (for example, update a row in a database). I also have a method to create the database connection. Below is my simplified code. public static void addOneForUserInChannel(String channel, String username) throws SQLException { Connection dbConnection = null; PreparedStatement ps = null; String updateSQL = "UPDATE " + channel + "_count SET messages = messages + 1 WHERE username = ?"; try { dbConnection = getDBConnection(); ps = dbConnection.prepareStatement(updateSQL); ps.setString(1, username); ps.executeUpdate(); } catch(SQLException e) { System.out.println(e.getMessage()); } finally { if(ps != null) { ps.close(); } if(dbConnection != null) { dbConnection.close(); } } } And my DB connection private static Connection getDBConnection() { Connection dbConnection = null; try { Class.forName(DB_DRIVER); } catch (ClassNotFoundException e) { System.out.println(e.getMessage()); } try { dbConnection = DriverManager.getConnection(DB_CONNECTION, DB_USER,DB_PASSWORD); return dbConnection; } catch (SQLException e) { System.out.println(e.getMessage()); } return dbConnection; } This seems to be working fine for now, with about 1-2 queries per second, but I am worried that once I expand and it is running many more, I might have some issues. My questions: Is there a way to have a persistent database connection throughout the entire run time of the process? If so, should I do this? Are there any other optimizations that I should do to help with performance? Thanks

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Search found 14348 results on 574 pages for 'planet mysql'.

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- by mike

- by xtine

- by Yeti

- by Drew

- by Crobzilla

- by Wesley

- by Dan

- by Kostis

- by GMo

- by Donator

- by Donator

- by Chris Hodges

- by xRobot

- by Charles

- by ensnare

- by Purushotham

- by user296516

- by Parth

- by Mirage

- by Anup Prakash

- by Lisa

- by homaxto

- by iamfab

- by steven

- by Michael Joell

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