Explain this C# code: byte* p = (byte*) (void*) Scan0;
- by qulzam
I found the code from the net in which i cant understand this line:-
byte* p = (byte*)(void*)Scan0;
There Scan0 is System.IntPtr.
It is code of C#.Net. Plz Explain the above line.
The complete code is given below. this is code to convert a image in grayscale.
public static Image GrayScale(Bitmap b)
{
BitmapData bmData = b.LockBits(new Rectangle(0, 0, b.Width, b.Height), ImageLockMode.ReadWrite, PixelFormat.Format24bppRgb);
int stride = bmData.Stride;
System.IntPtr Scan0 = bmData.Scan0;
unsafe
{
byte* p = (byte*)(void*)Scan0;
int nOffset = stride - b.Width * 3;
byte red, green, blue;
for (int y = 0; y < b.Height; ++y)
{
for (int x = 0; x < b.Width; ++x)
{
blue = p[0];
green = p[1];
red = p[2];
p[0] = p[1] = p[2] = (byte)(.299 * red + .587 * green + .114 * blue);
p += 3;
}
p += nOffset;
}
}
b.UnlockBits(bmData);
return (Image)b;
}
I understand all the code but only have the problem on this line.
byte* p = (byte*)(void*)Scan0;
