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  • How to draw the "trail" in a maze solving application

    - by snow-spur
    Hello i have designed a maze and i want to draw a path between the cells as the 'person' moves from one cell to the next. So each time i move the cell a line is drawn Also i am using the graphics module The graphics module is an object oriented library Im importing from graphics import* from maze import* my circle which is my cell center = Point(15, 15) c = Circle(center, 12) c.setFill('blue') c.setOutline('yellow') c.draw(win) p1 = Point(c.getCenter().getX(), c.getCenter().getY()) this is my loop if mazez.blockedCount(cloc)> 2: mazez.addDecoration(cloc, "grey") mazez[cloc].deadend = True c.move(-25, 0) p2 = Point(getX(), getY()) line = graphics.Line(p1, p2) cloc.col = cloc.col - 1 Now it says getX not defined every time i press a key is this because of p2???

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  • How to access non-first matches with xpath in Selenium RC ?

    - by Gj
    I have 20 labels in my page: In [85]: sel.get_xpath_count("//label") Out[85]: u'20' And I can get the first one be default: In [86]: sel.get_text("xpath=//label") Out[86]: u'First label:' But, unlike the xpath docs I've found, I'm getting an error trying to subscript the xpath to get to the second label's text: In [87]: sel.get_text("xpath=//label[2]") ERROR: An unexpected error occurred while tokenizing input The following traceback may be corrupted or invalid The error message is: ('EOF in multi-line statement', (216, 0)) ERROR: An unexpected error occurred while tokenizing input The following traceback may be corrupted or invalid The error message is: ('EOF in multi-line statement', (1186, 0)) --------------------------------------------------------------------------- Exception Traceback (most recent call last) /Users/me/<ipython console> in <module>() /Users/me/selenium.pyc in get_text(self, locator) 1187 'locator' is an element locator 1188 """ -> 1189 return self.get_string("getText", [locator,]) 1190 1191 /Users/me/selenium.pyc in get_string(self, verb, args) 217 218 def get_string(self, verb, args): --> 219 result = self.do_command(verb, args) 220 return result[3:] 221 /Users/me/selenium.pyc in do_command(self, verb, args) 213 #print "Selenium Result: " + repr(data) + "\n\n" 214 if (not data.startswith('OK')): --> 215 raise Exception, data 216 return data 217 Exception: ERROR: Element xpath=//label[2] not found What gives?

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  • A web framework where AJAX was not an after thought

    - by Pirate for Profit
    AJAX is a pain in the ass because it essentially means you'll have to write two sets of similarish code: one for browsers with JavaScript enabled and those without. Not only this, but you have to connect JavaScript events to hook into your models and display the results. And if all that weren't bad enough, you need to send an address change with the request, otherwise the user won't be able to "click back" correctly (if confused look at what happens to the address bar when you click links in GMail). We're searching for something that had the foresight and design goals with all these concerns in mind. Performance and security are also obvious major concerns. We love config-based systems as well, where you don't have to write a lot of code you just drop it into an easily read config format. It's like asking for the holy grail right?

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  • Catch PyGTK TreeView reorder

    - by mkotechno
    I have a simple gtk.TreeView with a gtk.ListStore model and set_reorderable(True), I want to catch the signal/event emited when the user reorder through drag&drop the list, but the documentation does not help much: "The application can listen to these changes by connecting to the model's signals" So I tried to connect the model (ListStore) signals... but surprise! ListStore has no signals, so you are dispatched to TreeModel signals, then I tried to connect with the TreeModel "rows-reordered" signal with no lucky. How should I catch the list reorder performed by the user?

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  • Pygame program that can get keyboard input with caps

    - by None
    I have a Pygame program that needs text input. The way it does this is to get keyboard input and when a key is pressed it renders that key so it is added to the screen. Essentially it acts like a text field. The problem is, when you hold shift it doesn't do anything. I relize this is because the program ignores shift input and instead writes the text if it's number is under 128. I have thought of setting a variable when shift is pressed then capitalizing if it was true, but string capitalization only woks on letters, not things like numbers or semicolons. Is there maybe a number I can add to the ascii number typed to modify it if shift is pressed, or something else?

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  • Sort by an object's type

    - by Richard Levasseur
    Hi all, I have code that statically registers (type, handler_function) pairs at module load time, resulting in a dict like this: HANDLERS = { str: HandleStr, int: HandleInt, ParentClass: HandleCustomParent, ChildClass: HandleCustomChild } def HandleObject(obj): for data_type in sorted(HANDLERS.keys(), ???): if isinstance(obj, data_type): HANDLERS[data_type](obj) Where ChildClass inherits from ParentClass. The problem is that, since its a dict, the order isn't defined - but how do I introspect type objects to figure out a sort key? The resulting order should be child classes follow by super classes (most specific types first). E.g. str comes before basestring, and ChildClass comes before ParentClass. If types are unrelated, it doesn't matter where they go relative to each other.

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  • scoping problem in recursive closure

    - by wiso
    why this work: def function1(): a = 10 def function2(): print a function2() but this not: def function1(): a = 10 def function2(): print a a -= 1 if a>0: function2() function2() error: UnboundLocalError: local variable 'a' referenced before assignment

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  • how to count all distinct records in many-to-many relations in django ORM?

    - by marduk-pl
    hi, i have two models: class Project(models.Model): categories = models.ManyToManyField(Category) class Category(models.Model): name = models.CharField() now, i make some queryset: query = Project.objects.filter(id__in=[1,2,3,4]) and i like to get list of all distinct categories in this queryset with count of projects with refering to these categories - exactly i would like to get that results: category1 - 10 projects category2 - 5 projects that is opposite to this query: query2 = query.annotate(Count('categories')) what return me: project1 - 2categories project2 - 7categories how can i make it in django ORM?

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  • How to get the original variable name of variable passed to a function

    - by Acorn
    Is it possible to get the original variable name of a variable passed to a function? E.g. foobar = "foo" def func(var): print var.origname So that: func(foobar) Returns: >>foobar EDIT: All I was trying to do was make a function like: def log(soup): f = open(varname+'.html', 'w') print >>f, soup.prettify() f.close() .. and have the function generate the filename from the name of the variable passed to it. I suppose if it's not possible I'll just have to pass the variable and the variable's name as a string each time.

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  • django - variable declared in base project does not appear in app

    - by unsorted
    I have a variable called STATIC_URL, declared in settings.py in my base project: STATIC_URL = '/site_media/static/' This is used, for example, in my site_base.html, which links to CSS files as follows: <link rel="stylesheet" href="{{ STATIC_URL }}css/site_tabs.css" /> I have a bunch of templates related to different apps which extend site_base.html, and when I look at them in my browser the CSS is linked correctly as <link rel="stylesheet" href="/site_media/static/css/site_tabs.css" /> (These came with a default pinax distribution.) I created a new app called 'courses' which lives in the ...../apps/courses folder. I have a view for one of the pages in courses called courseinstance.html which extends site_base.html just like the other ones. However, when this one renders in my browser it comes out as <link rel="stylesheet" href="css/site_tabs.css" /> as if STATIC_URL were equal to "" for this app. Do I have to make some sort of declaration to get my app to take on the same variable values as the project? I don't have a settings.py file for the app. by the way, the app is listed in my list of INSTALLED_APPS and it gets served up fine, just without the link to the CSS file (so the page looks funny). Thanks in advance for your help.

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  • pyplot: really slow creating heatmaps

    - by cvondrick
    I have a loop that executes the body about 200 times. In each loop iteration, it does a sophisticated calculation, and then as debugging, I wish to produce a heatmap of a NxM matrix. But, generating this heatmap is unbearably slow and significantly slow downs an already slow algorithm. My code is along the lines: import numpy import matplotlib.pyplot as plt for i in range(200): matrix = complex_calculation() plt.set_cmap("gray") plt.imshow(matrix) plt.savefig("frame{0}.png".format(i)) The matrix, from numpy, is not huge --- 300 x 600 of doubles. Even if I do not save the figure and instead update an on-screen plot, it's even slower. Surely I must be abusing pyplot. (Matlab can do this, no problem.) How do I speed this up?

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  • lxml unicode entity parse problems

    - by Jon Hadley
    I'm using lxml as follows to parse an exported XML file from another system: xmldoc = open(filename) etree.parse(xmldoc) But im getting: lxml.etree.XMLSyntaxError: Entity 'eacute' not defined, line 4495, column 46 Obviously it's having problems with unicode entity names - but how would i get round this? Via open() or parse()?

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  • how to import a 'zip' file to my .py ..

    - by zjm1126
    when i use http://github.com/joshthecoder/tweepy-examples , i find : import tweepy in the appengine\oauth_example\handlers.py but i can't find a tweepy file or tweepy's 'py' file, except a tweepy.zip file, i don't think this is right,cauz i never import a zip file, i find this in app.py: import sys sys.path.insert(0, 'tweepy.zip') why ? how to import a zip file.. thanks

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  • Scrapy Could not find spider Error

    - by Nacari
    I have been trying to get a simple spider to run with scrapy, but keep getting the error: Could not find spider for domain:stackexchange.com when I run the code with the expression scrapy-ctl.py crawl stackexchange.com. The spider is as follow: from scrapy.spider import BaseSpider from __future__ import absolute_import class StackExchangeSpider(BaseSpider): domain_name = "stackexchange.com" start_urls = [ "http://www.stackexchange.com/", ] def parse(self, response): filename = response.url.split("/")[-2] open(filename, 'wb').write(response.body) SPIDER = StackExchangeSpider()` Another person posted almost the exact same problem months ago but did not say how they fixed it, http://stackoverflow.com/questions/1806990/scrapy-spider-is-not-working I have been following the turtorial exactly at http://doc.scrapy.org/intro/tutorial.html, and cannot figure out why it is not working.

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  • How to add a context processor from a Django app

    - by Edan Maor
    Say I'm writing a Django app, and all the templates in the app require a certain variable. The "classic" way to deal with this, afaik, is to write a context processor and add it to TEMPLATE_CONTEXT_PROCESSORS in the settings.py. My question is, is this the right way to do it, considering that apps are supposed to be "independent" from the actual project using them? In other words, when deploying that app to a new project, is there any way to avoid the project having to explicitly mess around with its settings?

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  • Is there a simple way to make lists behave as files (with ftplib)

    - by Brent.Longborough
    I'd like to use ftplib to upload program-generated data as lists. The nearest method I can see for doing this is ftp.storlines, but this requires a file object with a readlines() method. Obviously I could create a file, but this seems like overkill as the data isn't persistent. Is there anything that could do this?: session = ftp.new(...) upload = convertListToFileObject(mylist) session.storlines("STOR SOMETHING",upload) session.quit

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  • Technique to remove common words(and their plural versions) from a string

    - by Jake M
    I am attempting to find tags(keywords) for a recipe by parsing a long string of text. The text contains the recipe ingredients, directions and a short blurb. What do you think would be the most efficient way to remove common words from the tag list? By common words, I mean words like: 'the', 'at', 'there', 'their' etc. I have 2 methodologies I can use, which do you think is more efficient in terms of speed and do you know of a more efficient way I could do this? Methodology 1: - Determine the number of times each word occurs(using the library Collections) - Have a list of common words and remove all 'Common Words' from the Collection object by attempting to delete that key from the Collection object if it exists. - Therefore the speed will be determined by the length of the variable delims import collections from Counter delim = ['there','there\'s','theres','they','they\'re'] # the above will end up being a really long list! word_freq = Counter(recipe_str.lower().split()) for delim in set(delims): del word_freq[delim] return freq.most_common() Methodology 2: - For common words that can be plural, look at each word in the recipe string, and check if it partially contains the non-plural version of a common word. Eg; For the string "There's a test" check each word to see if it contains "there" and delete it if it does. delim = ['this','at','them'] # words that cant be plural partial_delim = ['there','they',] # words that could occur in many forms word_freq = Counter(recipe_str.lower().split()) for delim in set(delims): del word_freq[delim] # really slow for delim in set(partial_delims): for word in word_freq: if word.find(delim) != -1: del word_freq[delim] return freq.most_common()

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  • In Django : How to serialize dict object to json ?

    - by Rohit
    I have this very basic problem, >>> serializers.serialize("json", {'a':1}) Traceback (most recent call last): File "<console>", line 1, in <module> File "/usr/lib/pymodules/python2.6/django/core/serializers/__init__.py", line 87, in serialize s.serialize(queryset, **options) File "/usr/lib/pymodules/python2.6/django/core/serializers/base.py", line 40, in serialize for field in obj._meta.local_fields: AttributeError: 'str' object has no attribute '_meta' >>> How can this be done ? Thanks in advance !

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  • Can PyAMF support service deployment by way of the filesystem?

    - by Chris R
    I'm evaluating PyAMF to replace our current PHP (ugh) AMF services framework, and I'm unable to find the one crucial piece of information that would allow me to provide a compelling use case for changing over: Right now, new PHP AMF services are deployed simply by putting the .php files in the filesystem; the next time they're accessed, the new service is in play. Removal of a service is as simple as deleting the .php file that provided it, and updating it is correspondingly simple. I need that same ease-of-deployment from PyAMF. If we have to rewrite our installers to deploy these services, it'll be a nonstarter. So, what I need to know is, can PyAMF support new service discovery by way of the filesystem, can it support service upgrading and removal by way of same, and if so, what is the best way to set it up to do this? I'm open to any of the various server options; I can easily have cherrypy, django, whatever installed and running on its own, and even -- with a bit more sturm nd drang -- have mod_python or mod_wsgi made available.

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