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• how to get latest entry from a table for an item and do arithmatic operation on it?

  - by I Like PHP

  i have below tables tbl_rcv_items st_id | item_id |stock_opening_qnty |stock_received_qnty |stock_rcvd_date 14 1 0 70 2010-05-18 15 16 0 100 2010-05-06 16 10 0 59 2010-05-20 17 14 0 34 2010-05-20 20 1 70 5 2010-05-12 tbl_issu_items issue_id refer_issue_id item_id item_qntt item_updated 51 1 1 5 2010-05-18 19:34:29 52 1 16 6 2010-05-18 19:34:29 53 1 10 7 2010-05-18 19:34:29 54 1 14 8 2010-05-18 19:34:29 75 7 1 12 2010-05-18 19:40:52 76 7 16 1 2010-05-18 19:40:52 77 7 10 1 2010-05-18 19:40:52 78 7 14 1 2010-05-18 19:40:52 79 8 1 3 2010-05-19 11:28:50 80 8 16 5 2010-05-19 11:28:50 81 8 10 6 2010-05-19 11:28:50 82 8 14 7 2010-05-19 11:28:51 87 10 1 2 2010-05-19 12:51:03 88 10 16 0 2010-05-19 12:51:03 89 10 10 0 2010-05-19 12:51:03 90 10 14 0 2010-05-19 12:51:03 91 14 1 1 2010-05-19 18:43:58 92 14 14 3 2010-05-19 18:43:58 tbl_item_detail item_id item_name 1 shirt 2 belt 10 ball pen 14 vim powder 16 pant NOW if i want total available quantity for each item till today using both table total available quantity for an item =stock_opening_qnty+stock_received_qnty(LATEST ENTRY FROM (tbl_rcv_item) for that item id according to stock_rcvd_date) - SUM(item_qntt) for eg: if i want to know the available quantity for item_id=1 till today(25-05-2010) then it shoud be 70+5(latest entry for item_id till 25/5/2010)-23( issued till 25/5/2010)=52 i write below query , SELECT tri.item_id, tid.item_name, (tri.stock_opening_qnty + tri.stock_received_qnty) AS totalRcvQntt, SUM( tii.item_qntt ) AS totalIsudQntt FROM tbl_rcv_items tri JOIN tbl_issu_items tii ON tii.item_id = tri.item_id JOIN tbl_item_detail tid ON tid.item_id=tri.item_id WHERE tri.stock_rcvd_date <= CURDATE() GROUP BY (tri.item_id) which results Array ( [0] => Array ( [item_id] => 1 [item_name] => shirt [totalRcvQntt] => 70 [totalIsudQntt] => 46 ) [1] => Array ( [item_id] => 10 [item_name] => ball pen [totalRcvQntt] => 59 [totalIsudQntt] => 16 ) [2] => Array ( [item_id] => 14 [item_name] => vim powder [totalRcvQntt] => 34 [totalIsudQntt] => 20 ) [3] => Array ( [item_id] => 16 [item_name] => pant [totalRcvQntt] => 100 [totalIsudQntt] => 17 ) ) in above result total isuse quantity for shirt(item_id=1) shoube be 23 whereas results reflects 46 bcoz there are two row regrading item_id=1 in tbl_rcv_items, i only need the latest one(means which stock_rcvd_date is less than tommorow) please tell me where i doing mistake?? or rewrite the best query. thanks a lot!

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• How can I replace/speed up a text search query which uses LIKE ?

  - by Jules

  I'm trying to speed up my query... select PadID from Pads WHERE (keywords like '%$search%' or ProgramName like '%$search%' or English45 like '%$search%') AND RemovemeDate = '2001-01-01 00:00:00' ORDER BY VersionAddDate DESC I've done some work already, I have a keywords table so I can add ... PadID IN (SELECT PadID FROM Keywords WHERE word = '$search') ... However its going to be a nightmare to split up the words from English45 and ProgramName into a word table. Any ideas ? EDIT : (also provided actual table names)

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• Echo autoincrement id doubt

  - by Marcelo

  Hi, can I print the id, even if it's autoincrement ? Because the way I'm doing I'm using an empty variable for id. $id= ""; mysql_connect(localhost,$username,$password); @mysql_select_db($database) or die ("Não conectou com a base $database"); mysql_query("INSERT INTO table1(id,...) VALUES ('".$id."',....)") or die(mysql_error()); mysql_close(); echo "Your id is :"; echo "".$id; I'm trying to print the id, but it's coming blank. I checked the table and there's an id number there. How can I print it then at? Thanks for the attention

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• Sql query listing Fathers and childs with joins, how to distinct them?

  - by DaNieL

  Having those tables: table_n1: | t1_id | t1_name | | 1 | foo | table_n2: | t2_id | t1_id | t2_name | | 1 | 1 | bar | I need a query that gives me two result: | names | | foo | | foo / bar | But i cant figure out the right way. I wrote this one: SELECT CONCAT_WS(' / ', table_n1.t1_name, table_n2.t2_name) AS names FROM table_n1 LEFT JOIN table_n2 ON table_n2.t1_id = table_n1.t1_id that works for an half: this only return the 2° row (in the example above): | names | | foo - bar | This query return the 'father' (table_n1) name only when it doesnt have 'childs' (table_n2). How can i fix it?

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• need a web browser in my desktop application

  - by javadahut

  part of the specification of this desktop application is to have a mini browser built in, so that you can enter URL, and navigate the site as you would on a normal browser. Access to the browser page's DOM is required, should let me programmatically change the rendering view of a page, should be cross-platform, renders javascript JDIC seems outdated and I've heard Mozswing doesn't run on Mac.... Jxbrowser license costs a grand and up. Is Java the wrong platform to be creating such app? Are there any other solutions out there for building an application like this ? Thank you.

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• Advice on a DB that can be uploaded to a website by a smart client for collecting survey feedback

  - by absfabs

  Hello, I'm hoping you can help. I'm looking for a zero config multi-user datbase that my winforms application can easily upload to a webserver folder (together with 1 or 2 classic asp pages) and am looking for some suggestions/recommendations. The idea is that the database will be used to collect feedback entered by people filling in the asp pages. The pages will write to the database using javascript. The database will subsequently be downloaded again for processing once the responses are in. In Summary: It will mostly run in MS Windows environments. I have a modest budget for this and do not mind paying for such a database. No runtime licensing costs. Should be xcopy - Once uploaded to a website folder it should be operational. It should not have a dotnet CLR dependency. It should support a resonable level of concurrent access. Average respondent count would be around 20-30 but one never knows. Should be a reasonable size so that uploads/downloads to and from the site will be reasonably fast. Would appreciate your suggestions/comments Many thanks Abz To clarify - this is a desktop commercial application for feedback management in a vertical market. It uses SQL Server as the backing store. The application currently provides feedback management from email and paper feedback. I now want to add web feedback capability. Getting users to to make their SQL servers accessible to a website is not at option at this time as I am want to make getting up and running as painless as possible. I intend to release a web based implementation of the software in the near future but for now am looking at the above as a pragmatic way to provide web based feedback collection.

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• Select * from 'many to many' SQL relationship

  - by Rampant Creative Group

  I'm still learning SQL and my brain is having a hard time with this one. Say I have 3 tables: teams players and teams_players as my link table All I want to do is run a query to get each team and the players on them. I tried this: SELECT * FROM teams INNER JOIN teams_players ON teams.id = teams_players.team_id INNER JOIN players ON teams_players.player_id = players.id But it returned a separate row for each player on each team. Is JOIN the right way to do it or should I be doing something else? ----------------------------------------- Edit Ok, so from what I'm hearing, this isn't necessarily a bad way to do it. I'll just have to group the data by team while I'm doing my loop. I have not yet tried the modified SQL statements provided, but I will today and get back to you. To answer the question about structure - I guess I wasn't thinking about the returned row structure which is part of what lead to my confusion. In this particular case, each team is limited to 4 players (or less) so I guess the structure that would be helpful to me is something like the following: teams.id, teams.name, players.id, players.name, players.id, players.name, players.id, players.name, players.id, players.name, 1 Team ABC 1 Jim 2 Bob 3 Ned 4 Roy 2 Team XYZ 2 Bob 3 Ned 5 Ralph 6 Tom

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• Checking inherited attributes in an 'ancestry' based SQL table

  - by Brendon Muir

  I'm using the ancestry gem to help organise my app's tree structure in the database. It basically writes a childs ancestor information to a special column called 'ancestry'. The ancestry column for a particular child might look like '1/34/87' where the parent of this child is 87, and then 87's parent is 34 and 34's is 1. It seems possible that we could select rows from this table each with a subquery that checks all the ancestors to see if a certain attribute it set. E.g. in my app you can hide an item and its children just by setting the parent element's visibility column to 0. I want to be able to find all the items where none of their ancestors are hidden. I tried converting the slashes to comma's with the REPLACE command but IN required a set of comma separated integers rather than one string with comma separated string numbers. It's funny, because I can do this query in two steps, e.g. retrieve the row, then take its ancestry column, split out the id's and make another query that checks that the id is IN that set of id's and that visibility isn't ever 0 and whala! But joining these into one query seems to be quite a task. Much searching has shown a few answers but none really do what I want. SELECT * FROM t1 WHERE id = 99; 99's ancestry column reads '1/34/87' SELECT * FROM t1 WHERE visibility = 0 AND id IN (1,34,87); kind of backwards, but if this returns no rows then the item is visible. Has anyone come across this before and come up with a solution. I don't really want to go the stored procedure route. It's for a rails app.

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• how can join a query result set with an existing table?

  - by Yang

  is there any way to avoid using tmp table?

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• Basic join query understanding

  - by OM The Eternity

  I know this very silly, but can anybody help me in understanding what does this join query is doing in elabortive description? SELECT j1.* FROM jos_audittrail j1 LEFT OUTER JOIN jos_audittrail j2 ON (j1.trackid = j2.trackid AND j1.field = j2.field AND j1.changedone < j2.changedone) WHERE j1.operation = 'UPDATE' AND j1.trackid=$t_ids[$n] AND j2.id IS NULL I know its very silly, but i need to go ahead with my further need... Pls do help me...

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• PHP is not called properly in IE using set interval function in Javascript

  - by Hemant

  Hi all, I am trying to show the message updated in DB using the following code var showtime = setInterval('redirect()',5000); ////Redirecting to DB Status ///// function redirect() { xmlhttp = GetXmlHttpObject(); if (xmlhttp==null) { alert ("Browser does not support HTTP Request"); return; } var url="isResultexist.php" xmlhttp.onreadystatechange=stateChanged; xmlhttp.open("GET",url,true); xmlhttp.send(null); } I am collecting the response from PHP here and using it to update the Messages on UI Problem here is it works fine 1st time when it called after 5sec but there after return the Same result even DB is updated, This works fine with Mozilla and google chrome browser regards hemant

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• PHP Post Count in Forum

  - by Chris

  I'm currently desiging a forum application, I considered using a premade but decided against it as it's useful for me to learn some of the techniques. So I've written a fairly full featured forum... great. One of the problems I want to solve is to include user data for each post, at the minute the post table includes the poster ID (obviously) and I added the poster's username at a later date so I didn't have to query the User DB for X number of posts in a thread. However, it's become apparent I now want to do this, usernames don't need to update retrospectively, however avatars, sigs, and especially post counts need to update actively, so data in some form needs keeping up to date somewhere... What would be a good way of implementing this? I obviously don't want to include any more user data on the Posts DB table than necessary, but I'm struggling to find an easy way to do this short of querying the DB for each post in a thread, which is potentially going to create a lot of traffic. How have other people solved this, I've been examining the code on some other open source apps but I can't find what I'm looking for. Is it possible to select multiple records in one query? In which case I could build an array dynamically on each page request (eg 'SQL blah blah' then a for each loop to insert the ID's). Could I join the tables each time? Do I submit a query for each post? Hmm.

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• For SQL, when did it start to be desirable to always use the words "Inner Join" instead of implicitl

  - by Jian Lin

  For SQL, when did it start to be desirable to always use the words "Inner Join" instead of implicitly joining by: select * from t1, t2 where t1.ID = t2.ID; ? Is it just for style or to distinguish between outer join or are there other reasons for it?

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• Creating a Variable that is the Sum of Two Other Variables

  - by John

  Hello, For the code below, I would like to make a new variable called totalScore2 that equals days + totalScore. How can I do this? Thanks in advance, John $sqlStr = "SELECT l.loginid, l.username, l.created, DATEDIFF(NOW(), l.created) AS days, COALESCE(s.total, 0) AS countSubmissions, COALESCE(c.total, 0) AS countComments, COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore

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• Using * in SELECT Query

  - by libregeek

  I am currently porting an application written in MySQL3 and PHP4 to MySQL5 and PHP5. On analysis I found several SQL queries which uses "select * from tablename" even if only one column(field) is processed in PHP. The table has almost 60 columns and it has a primary key. In most cases, the only column used is id which is the primary key. Will there be any performance boost if I use queries in which the column names are explicitly mentioned instead of * ? (In this application there is only one method which we need all the columns and all other methods return only a subset of the columns)

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• Auto deployment of PHP applications

  - by Christopher McCann

  My team currently has a development web/database server and a live deployment web server and a live database server. We use SVN with the repository stored on the development server but the problem is our deployment process. Currently when we need to deploy an update to the live application we simply use SFTP to transfer from the repository to the live web server and then amend the database on the live server to reflect the development database. This is a really slow process as we also minify all javascript and CSS files. I have used Capistrano for Ruby and Cruise Control for java but I have never used anything for PHP. I'd rather not have to build our own if something already existed. Does anyone know of anything?

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• PHP replace string help...

  - by MILESMIBALERR

  i am designing a site with a comment system and i would like a twitter like reply system. The if the user puts @a_registered_username i would like it to become a link to the user's profile. i think preg_replace is the function needed for this. $ALL_USERS_ROW *['USERNAME'] is the database query array for all the users and ['USERNAME'] is the username row. $content is the comment containing the @username i think this should not be very hard to solve for someone who is good at php. Does anybody have any idea how to do it?

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• LAMP stack on home computer as a public web server

  - by Scott

  So I'm using this website: http://www.howtoforge.com/ubuntu_debian_lamp_server to setup LAMP on my Ubuntu Virtual Machine. Here is my question though, This will enable me to program and test through localhost. How can I set this up so anyone on the web can access my .php pages from any Internet capable device, and they will still interact with my local database, etc?

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• Creating search functionality with Laravel 4

  - by Mitch Glenn

  I am trying to create a way for users to search through all the products on a website. When they search for "burton snowboards", I only want the snowboards with the brand burton to appear in the results. But if they searched only "burton", then all products with the brand burton should appear. This is what I have attempted to write but isn't working for multiple reasons. Controller: public function search(){ $input = Input::all(); $v= Validator::make($input, Product::$rules); if($v->passes()) { $searchTerms = explode(' ', $input); $searchTermBits = array(); foreach ($searchTerms as $term) { $term = trim($term); if (!empty($term)){ $searchTermBits[] = "search LIKE '%$term%'"; } } $result = DB::table('products') ->select('*') ->whereRaw(". implode(' AND ', $searchTermBits) . ") ->get(); return View::make('layouts/search', compact('result')); } return Redirect::route('/'); } I am trying to recreate the first solution given for this stackoverflow.com problem The first problem I have identified is that i'm trying to explode the $input, but it's already an array. So i'm not sure how to go about fixing that. And the way I have written the ->whereRaw(". implode(' AND ', $searchTermBits) . "), i'm sure isn't correct. I'm not sure how to fix these problems though, any insights or solutions will be greatly appreciated.

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• How to access stdClass variables stdClass Object([max(id)])=>64)

  - by Theopile

  I need the very last valid entry in a database table which would be the row with the greatest primary key. So using mysqli, my query is "SELECT MAX(id) FROM table LIMIT 1". This query returns the correct number(using print_r()) but I cannot figure out how to access it. Here is the main code. Note that the $this-link refers to class with a mysqli connection. $q="select max(id) from stones limit 1"; $qed=$this->link->query($q) or die(mysqli_error()); if($qed){ $row=$qed->fetch_object(); print_r($row); echo $lastid=$row;//here is the problem } The valid line print_r($row) echos out "stdClass Object ( [max(id)] = 68 )"

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• SQL select statement

  - by kwokwai

  Hi all, I got a Table which has two fields: Point, and Level, with some sample data as follows: ----------------------- Point | Level ----------------------- 10 | Level 1 20 | Level 2 30 | Level 3 40 | Level 4 Suppose that there is a user who has 25 points, to find the Level in which this user is in, the Select statement I used was: Select Level from Table where Point < 30 AND Point > 20; But the Select SQL ststament is a hard-copy one where you can see the ponts 30 and 20 are fixed. I want to alter the Select statement so that the new SQL Select statement can be applied to all users with different points, but I don't know how to do it.

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• Using memtables in sql. When is it reasonable and is it safe?

  - by Spiros

  I was just reading an update from a friend's project, mentioning the use of memtables to store data temporatily and then flush to a table on disk. Up to now, I have never faced a situation where I would use a memtable, or a situation where I would think the use of a mem table would be beneficial; so I wonder, when would someone use mem tables? what makes a memtable (appart from access speed) a reasonable choice? and how safe is it, even for temp data? there is always the limitation of available physical memory.

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• Sql query - selecting top 5 rows and further selecting rows only if User is present

  - by Gublooo

  Hello, I kind of stuck on how to implement this query - this is pretty similar to the query I posted earlier but I'm not able to crack it. I have a shopping table where everytime a user buys anything, a record is inserted. Some of the fields are * shopping_id (primary key) * store_id * user_id Now what I need is to pull only the list of those stores where he's among the top 5 visitors: When I break it down - this is what I want to accomplish: * Find all stores where this UserA has visited * For each of these stores - see who the top 5 visitors are. * Select the store only if UserA is among the top 5 visitors. The corresponding queries would be: select store_id from shopping where user_id = xxx select user_id,count(*) as 'visits' from shopping where store_id in (select store_id from shopping where user_id = xxx) group by user_id order by visits desc limit 5 Now I need to check in this resultset if UserA is present and select that store only if he's present. For example if he has visited a store 5 times - but if there are 5 or more people who have visited that store more than 5 times - then that store should not be selected. So I'm kind of lost here. Thanks for your help

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• how to make secure sign up form

  - by klox

  i want my sign up form to be secure from hacker..i want all secret information can't easily open by wrong people.. i wan't some data become encrypted.. how to make it??

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• IF expression in SQL

  - by chupinette

  INSERT INTO item_quotation (item_id, quotation_id,name_searched,item_name,other_name,selling_price,discounted_price) SELECT DISTINCT I.item_id," . $quotation_id . ",T.item_name, I.name,I.other_name, INV.selling_price, I.discounted_price FROM temp_quotations T, item I, inventory INV<br/> WHERE ( I.name LIKE CONCAT( '%', T.item_name, '%' ) OR I.other_name LIKE CONCAT( '%', T.item_name, '%' )) AND INV.item_id = I.item_id; I have a table called temp_quotations(temp_item_id,item_name)having values (1,grinder), (2,drill), (3,kit) I have another table called item(item_id,name,other_name,discounted_price) having values (1,grinder A,100),(2,kit A,200) When I execute this sql, it insert values in table item_quotation(item_id, quotation_id,name_searched,item_name,other_name,selling_price,discounted_price) for example in this case it will insert (1,1,grinder,grinder A,150,100) (2,1,kit,kit A, 250,200) Since the item drill is not found in table item, it wont display it in table item_quotations. I want to write an if statement within that sql so that when the item_name from temp_quotation does not match the name from item, it displays not found in the place of item_name. This is what i tried but it does not display "not found": INSERT INTO item_quotation (item_id, quotation_id,name_searched,item_name,other_name,selling_price,discounted_price) SELECT DISTINCT I.item_id," . $quotation_id . ",T.item_name, IF(I.name LIKE CONCAT( '%', T.item_name, '%' ),I.name,'not found'),I.other_name, INV.selling_price, I.discounted_price FROM temp_quotations T, item I, inventory INV WHERE ( I.name LIKE CONCAT( '%', T.item_name, '%' ) OR I.other_name LIKE CONCAT( '%', T.item_name, '%' )) AND INV.item_id = I.item_id;

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