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  • How to manually set an authenticated user in Spring Security / SpringMVC

    - by David Parks
    After a new user submits a 'New account' form, I want to manually log that user in so they don't have to login on the subsequent page. The normal form login page going through the spring security interceptor works just fine. In the new-account-form controller I am creating a UsernamePasswordAuthenticationToken and setting it in the SecurityContext manually: SecurityContextHolder.getContext().setAuthentication(authentication); On that same page I later check that the user is logged in with: SecurityContextHolder.getContext().getAuthentication().getAuthorities(); This returns the authorities I set earlier in the authentication. All is well. But when this same code is called on the very next page I load, the authentication token is just UserAnonymous. I'm not clear why it did not keep the authentication I set on the previous request. Any thoughts? Could it have to do with session ID's not being set up correctly? Is there something that is possibly overwriting my authentication somehow? Perhaps I just need another step to save the authentication? Or is there something I need to do to declare the authentication across the whole session rather than a single request somehow? Just looking for some thoughts that might help me see what's happening here.

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  • Zend without Database

    - by dbemerlin
    Hi, i googled for an hour now but maybe my Google-Fu is just too weak, i couldn't find a solution. I want to create an application that queries a service via JSON requests (all data and backend/business logic is stored in the service). With plain PHP it's simple enough since i just make a curl request, json_decode the result and get what i need. This already works quite well. A request might look like this: Call http://service-host/userlist with body: {"logintoken": "123456-1234-5678-901234"} Get Result: { "status": "Ok", "userlist":[ {"name": "foo", "id": 1}, {"name": "bar", "id": 2} ] } Now we want to get that into the Zend Framework since it's a hobby project and we want to learn about Zend. The problem is that all information i could find use a Database. Is there even a way to create a Zend Project that does not use a Database? And how can i write a model that represents the actions instead of objects and object-relations?

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  • Conditionally embed ASP.NET MVC2 Views as resources during build in Visual Studio 2010

    - by jslatts
    I have a ASP.NET MVC2 project in VS2010 that can be deployed in two modes: standalone or plugin. In standalone mode, the views should live outside the compiled assembly as .aspx files (the default setup). In plugin mode, the views are switched (currently by hand) to embedded resources and the entire assembly is dropped into a host project folder. Currently, this requires the developer to go through each view and switch it from Build Action: "Content" to "Embedded Resource" and vice versa. I would like to create a new solution configuration to automatically grab all .aspx files and build them as resources. This SO post seems like the solution, but I would prefer not to have to edit the .csproj every single time I add a new view to the project. Is there a way to use a wild cards or some other batch/global conditionally statement to change resources from content to embedded?

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  • asp.net mvc3 return multiple json list

    - by Acid
    Im asp.net mvc3 c# code returns json list like this: return Json(new { name = UserNames, imageUrl = ImageUrls }); UserNames and ImageUrls are both List types And this is my jquery function StartSearch(text) { $.ajax({ url: '/Shared/Search', type: 'POST', data: { SearchText: text }, dataType: 'json', success: function (result) { $.each(result, function (i, item) { alert(result[i].name); }); } }); } How i can get names and umageUrls? Thanks

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  • Use different updatetargetid based on view

    - by Jerrie Pelser
    I have a web page which display a list of items in a HTML table. Above the list is a form which allows the user to add a new item to the list via AJAX (using Ajax.BeginForm). When the data is posted to the controller via AJAX I add the new item to the database backend and generate a new table row via a Partial View which then gets appended to the exisiting table. When the form to add new items however contains errors, I want to render the form back to the web browser and display that. So here is the question: Is it possible to specify the UpdateTargetId from within the controller? At the moment whatever View I return from the controller gets inserted in the same target, but I would like to update a different target (ie. different UpdateTargetId) based on whatever view was returned from the controller. Any help would be appreciated...

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  • Set dropDownList to contain one value only, mvc3

    - by ParPar
    I have this in my controller: ViewBag.PriceListId = new SelectList(m_db.PriceLists, "Id", "Name", us.PriceListId); It contains two values now, but I want to enable the user to choose only the second value, and just if he does something else - allow him choose one of the both values. How do I omit the first value, and add and set him to default after that? Shoud I do it in my controller or use jquery? Thank in advance.

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  • Problem in Saving Multi Level Models in YII

    - by Waqar
    My Table structure for user and his adress detail is as follows CREATE TABLE tbl_users ( id bigint(20) unsigned NOT NULL AUTO_INCREMENT, loginname varchar(128) NOT NULL, enabled enum("True","False"), approved enum("True","False"), password varchar(128) NOT NULL, email varchar(128) NOT NULL, role_id int(20) NOT NULL DEFAULT '2', name varchar(70) NOT NULL, co_type enum("S/O","D/O","W/O") DEFAULT "S/O", co_name varchar(70), gender enum("MALE","FEMALE","OTHER") DEFAULT "MALE", dob date DEFAULT NULL, maritalstatus enum("SINGLE","MARRIED","DIVORCED","WIDOWER") DEFAULT "MARRIED", occupation varchar(100) DEFAULT NULL, occupationtype_id int(20) DEFAULT NULL, occupationindustry_id int(20) DEFAULT NULL, contact_id bigint(20) unsigned DEFAULT NULL, signupreason varchar(500), PRIMARY KEY (id), UNIQUE KEY loginname (loginname), UNIQUE KEY email (email), FOREIGN KEY (role_id) REFERENCES tbl_roles (id), FOREIGN KEY (occupationtype_id) REFERENCES tbl_occupationtypes (id), FOREIGN KEY (occupationindustry_id) REFERENCES tbl_occupationindustries (id), FOREIGN KEY (contact_id) REFERENCES tbl_contacts (id) ) ENGINE=InnoDB; CREATE TABLE tbl_contacts ( id bigint(20) unsigned NOT NULL AUTO_INCREMENT, contact_type enum("cres","pres","coff"), address varchar(300) DEFAULT NULL, landmark varchar(100) DEFAULT NULL, district_id int(11) DEFAULT NULL, city_id int(20) DEFAULT NULL, state_id int(20) DEFAULT NULL, pin_id bigint(20) unsigned DEFAULT NULL, area_id bigint(20) unsigned DEFAULT NULL, po_id bigint(20) unsigned DEFAULT NULL, phone1 varchar(20) DEFAULT NULL, phone2 varchar(20) DEFAULT NULL, mobile1 varchar(20) DEFAULT NULL, mobile2 varchar(20) DEFAULT NULL, PRIMARY KEY (id), FOREIGN KEY (district_id) REFERENCES tbl_districts (id), FOREIGN KEY (city_id) REFERENCES tbl_cities (id), FOREIGN KEY (state_id) REFERENCES tbl_states (id) ) ENGINE=InnoDB; CREATE TABLE tbl_states ( id int(20) NOT NULL AUTO_INCREMENT, name varchar(70) DEFAULT NULL, PRIMARY KEY (id) ) ENGINE=InnoDB; CREATE TABLE tbl_districts ( id int(20) NOT NULL AUTO_INCREMENT, name varchar(70) DEFAULT NULL, state_id int(20) DEFAULT NULL, PRIMARY KEY (id), FOREIGN KEY (state_id) REFERENCES tbl_states (id) ) ENGINE=InnoDB; CREATE TABLE tbl_cities ( id int(20) NOT NULL AUTO_INCREMENT, name varchar(70) DEFAULT NULL, district_id int(20) DEFAULT NULL, state_id int(20) DEFAULT NULL, PRIMARY KEY (id), FOREIGN KEY (district_id) REFERENCES tbl_districts (id), FOREIGN KEY (state_id) REFERENCES tbl_states (id) ) ENGINE=InnoDB; The relationship is as follows User has multiple contacts i.e Permanent Address, Current Address, Office Address. Each Contact has state and City. User-Contact-state like this How to save models of this structure in one go. Please provide a reply ASAP

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  • radiobutton checked on condition in jquery

    - by RememberME
    I have the following fields: <label>Company Type:</label> <label for="primary"><input onclick="javascript: $('#sec').hide('slow');$('#primary_company').find('option:first').attr('selected','selected');" type="radio" runat="server" name="companyType" id="primary" />Primary</label> <label for="secondary"><input onclick="javascript: $('#sec').show('slow');" type="radio" runat="server" name="companyType" id="secondary" />Secondary</label> <div id="sec"> <fieldset> <label for="primary_company">Primary Company:</label> <%= Html.DropDownList("primary_company", Model.SelectPrimaryCompanies, "** Select Primary Company **") %> </fieldset> If there is a primary_company, then the secondary radio button should be selected. If there is no primary_company, then the primary radio button should be selected. Here is my jQuery: $(document).ready(function() { if ($('#primary_company').val().length > 0) { $('#secondary').attr({ checked: true }); } else { $("#primary").attr('checked', true ); $('#sec').hide(); } The sec div hides and shows properly, but a radio button is never selected. I've tried .attr('checked', 'checked') and .attr({ checked: true }) and .attr('checked', true) but nothing is ever selected.

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  • How to implement conditional render in JS?

    - by mare
    Below is the JS (jQuery) code of autocomplete's result function. You can see there's some lines where I print out <li>s containing some data properties (that come in as a result of automcomplete's AJAX call). How could I rewrite this so that <li> would be conditionally rendered based on whether the property contains any value being either int or string (not empty string or whitespace) or something else that can be represented as string? $(".clients-dropdown").result(function (event, data, formatted) { if (data) { // set the hidden input that we need for Client entity rematerialize $(".client-id").val(data.client_id); if (data.ClientName && data.Address1 && data.postalcode && data.postname) { $(".client-address").html( "<li>" + data.ClientName + "</li>" + "<li>" + data.Address1 + "</li>" + "<li>" + data.postalcode + " " + data.postname + "</li>" ); $(".client-details").html( "<li>" + data.PrettyId + "</li>" + "<li>" + data.VatNo + "</li>" + "<li>" + data.Phone + "</li>" + "<li>" + data.Mobile + "</li>" + "<li>" + data.Email1 + "</li>" + "<li>" + data.Contact + "</li>" ); } } Also, for the AJAX call, should my server side action return null when there's a null for a property in the database or empty string?

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  • Url does not change in display when redirecting

    - by zsharp
    action: User/Details View: Details In my 'Details' view, a user can click on an actionlink that goes to the action :User/UserBehavior From which I again return a "Details" View. the url shows http://User/UserBehavior If I return redirectToAction to the Details action, I still get the "UserBehavior" action in the url. how do I redirect and present the new url of the action? isnt that the way its supposed to be? TO CLARIFY: WHEN YOU USE REDIRECTTOACTION, SHOULD THE URL IN THE BROWSER SHOW THE ORIGINAL ACTION OR THE ACTION YOU REDIRECTED TO?

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  • Problem with Models on Master Page View.

    - by user342514
    Have a problem with master page views and models. In the first image, I have a simple view in which I am trying to access the Model properties. None of the model properties are available at this time (this is the problem). If I use a <%= Model.blah % then you can see that the model properties are available. Second photo. In the last photo you will now see that I can access the Model properties that I was trying to access in the first photo. An error will be thrown if viewing this page if you don't first do <%= with the model. CS1061: 'object' does not contain a definition for 'User' and no extension method 'User' accepting a first argument of type 'object' could be found (are you missing a using directive or an assembly reference?) http://yfrog.com/8b43656447p So why is this happening?

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  • some problems with jquery

    - by CoffeeCode
    I'm using AJAX_POSTUP. When i make a request it sends a file to a bowser [offers to download] (the files content are params of the action methods). Does anyone know whats going on and how i can avoid this problem??? i'm not aware of other plugins such as AJAX_POSTUP

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  • 404 with spring 3

    - by markjason72
    hi I am going through my first lessons with spring 3.I created a dynamic web app in eclipse with the following structure. spring3mvc \src\my.spring.HelloWorldController.java \WebContent | |-----WEB-INF\jsp\hello.jsp |-----index.jsp |-----web.xml |-----WEB-INF\spring-servlet.xml |-----WEB-INF\lib\...*.jar files I created the spring-servlet.xml as below <context:component-scan base-package="my.spring" /> <bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView" /> <property name="prefix" value="/WEB-INF/jsp/" /> <property name="suffix" value=".jsp" /> </bean> and coded the controller package my.spring; import org.springframework.stereotype.Controller; import org.springframework.web.bind.annotation.RequestMapping; import org.springframework.web.servlet.ModelAndView; @Controller public class HelloWorldController { @RequestMapping("/hello") public ModelAndView helloWorld() { String message = "Hello World, Spring 3.0!"; return new ModelAndView("hello", "message", message); } } index.jsp has a link to hello view <html> <body> <a href="hello.html">Say Hello</a> </body> </html> finally in hello.jsp I have put <html> <body> ${message} </body> </html> My web.xml has <display-name>Spring3MVC</display-name> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list> <servlet> <servlet-name>spring</servlet-name> <servlet-class> org.springframework.web.servlet.DispatcherServlet </servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>spring</servlet-name> <url-pattern>*.html</url-pattern> </servlet-mapping> When I run the app on Tomcat6 server( thru eclipse),I can see the index page at http://localhost:8080/Spring3MVC/ .It displays the link to hello page.When I click on it(http://localhost:8080/Spring3MVC/hello.html),I get a 404 error. message /Spring3MVC/hello.html description The requested resource (/Spring3MVC/hello.html) is not available. Any idea how I can solve this? thanks mark.

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  • Exception calling UpdateModel - Value cannot be null or empty

    - by James Alexander
    This is probably something silly I'm missing but I'm definitely lost. I'm using .NET 4 RC and VS 2010. This is also my first attempt to use UpdateModel in .NET 4, but every time I call it, I get an exception saying Value cannont be null or empty. I've got a simple ViewModel called LogOnModel: [MetadataType(typeof(LogOnModelMD))] public class LogOnModel { public string Username { get; set; } public string Password { get; set; } public class LogOnModelMD { [StringLength(3), Required] public object Username { get; set; } [StringLength(3), Required] public object Password { get; set; } } } My view uses the new strongly typed helpers in MVC2 to generate a textbox for username and one for the password. When I look at FormCollection in my controller method, I see values for both coming through. And last but not least, here's are post controller methods: // POST: /LogOn/ [HttpPost] public ActionResult Index(FormCollection form) { var lm = new LogOnModel(); UpdateModel(lm, form); var aservice = new AuthenticationService(); if (!aservice.AuthenticateLocal(lm.Username, lm.Password)) { ModelState.AddModelError("User", "The username or password submitted is invalid, please try again."); return View(lm); } return Redirect("~/Home"); } Can someone please lend some insight into why UpdateModel would be throwing this exception? Thanks!

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  • How to handle model state errors in ajax-invoked controller action that returns a PartialView

    - by Robert Koritnik
    I have a POST controller action that returns a partial view. Everything seems really easy. but. I load it using $.ajax(), setting type as html. But when my model validation fails I thought I should just throw an error with model state errors. But my reply always returns 500 Server error. How can I report back model state errors without returning Json with whatever result. I would still like to return partial view that I can directly append to some HTML element. Edit I would also like to avoid returning error partial view. This would look like a success on the client. Having the client parse the result to see whether it's an actual success is prone to errors. Designers may change the partial view output and this alone would break the functionality. So I want to throw an exception, but with the correct error message returned to the ajax client.

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  • Display virtual keyword asp.net for password

    - by Nicole
    Hi! I have a login page with an input of type "password" I would like to have a virtual keyboard to enter the password. I've searched and I found the jquery script for virtual keyboard. The code said to add this to my page $('input[type=password]').keyboard({ layout: "qwerty", customLayout: [["q w e r t y {bksp}", "Q W E R T Y {bksp}"], ["s a m p l e {shift}", "S A M P L E {shift}"], ["{accept} {space} {cancel}", "{accept} {space} {cancel}"]] }); but I cant make it work!!!! nothing happens when y set focus on my password control. Any suggestions?? thank you!! Nicole.

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  • Range annotation between nothing and 100?

    - by aticatac
    Hi I have a [Range] annotation that looks like this: [Range(0, 100)] public int AvailabilityGoal { get; set; } It works as it should, I can only enter values between 0 and 100 but I also want the input box to be optional, the user shouldn't get an validation error if the input box is empty. If the user leaves it empty it should make AvailabilityGoal = 0 but I don't want to force the user to enter a zero. I tried this but it (obviously) didn't work: [Range(typeof(int?), null, "100")] Is it possible to solve this with Data Annotations or in some other way? Thanks in advance. Bobby

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  • validation of form with Jquery within asp.net mvc4 application

    - by slatnia wadii
    I am a beginner with Jquery and asp MVC4 I use the Jquery validate plugin <script src="http://ajax.aspnetcdn.com/ajax/jquery.validate/1.10.0/jquery.validate.js" type="text/javascript"> the code <script> jQuery(document).ready(function() { jQuery("#monFormulaire").validate({ rules: { "reclamation": { "required": true, "minlength": 4, "maxlength": 60000 }, "cause": { "required": true, "minlength": 4, "maxlength": 60000 }, "curative": { "required": true, "minlength": 4, "maxlength": 60000 }, "Closing_date": { "required": true, "minlength": 1, "maxlength": 60000 } }, submitHandler: function (form) { /* envoyer Mail*/ mailJob(); } }); }); <button type="submit" value="Page5" name="btnPage1" style="margin-left:1%" class="backRow" ></button> <table border="1" class="mytab" style="margin: auto;"> formulaire . </table> </form> The validation runs in the right way but the Action in the server side is not invoked anyone have any Idea ???

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  • Bind a ViewModel to a DropDownListFor with a third value besides dataValueField/dataTextField

    - by Elisa
    When I show a list of testplanViewModels in my View and the user selects one the SelectedTestplanId is returned to the Controller post action. What should also be returned is the TemplateId which belongs to the SelectedTestplanId. When the AutoMapper definition is run the Testplan.TestplanId is implicitly copied over to the TestplanViewModel.TestplanId. The same could be done by providing a TemplateId on the TestplanViewModel. When the user selects now a "TestplanViewModel" in the View, how can I attach the TemplateId to the controller action to access it there? The DropDownList does not allow 2 dataValueFields! CreateMap<Testplan, TestplanViewModel>().ForMember(dest => dest.Name, opt => opt.MapFrom(src => string.Format("{0}-{1}-{2}-{3}", src.Release.Name, src.Template.Name, src.CreatedAt, src.CreatedBy))); public ActionResult OpenTestplanViewModels() { IEnumerable<Testplan> testplans = _testplanDataProvider.GetTestplans(); var viewModel = new OpenTestplanViewModel { DisplayList = Mapper.Map<IEnumerable<Testplan>, IEnumerable<TestplanViewModel>>(testplans) }; return PartialView(viewModel); } public class TestplanViewModel { public int TestplanId { get; set; } public string Name { get; set; } } public class OpenTestplanViewModel { [Required(ErrorMessage = "No item selected.")] public int SelectedTestplanId { get; set; } public IEnumerable<TestplanViewModel> DisplayList { get; set; } } OpenTestplanViewModel @using (Html.BeginForm("Open", "Testplan")) { @Html.ValidationSummary(false) @Html.DropDownListFor(x => x.SelectedTestplanId, new SelectList(Model.DisplayList, "TestplanId", "Name"), new { @class = "listviewmodel" }) }

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  • how to refresh mulitple divs when after posting using jquery

    - by oo
    i have a screen with multiple little widgets (all with different divs around them). i have one form and when i post (using jquery) right now it updates the single form using ajax. i want two other divs to refresh as well (that are outside the form). What is the best way to trigger a refresh of multiple different divs on a single jquery ajax post callback?

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