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• How to retrieve Google Appengine Objects by id (Long value) ?

  - by David

  Hi, i have declared an entity the following way: public class MyEntity { @PrimaryKey @Persistent(valueStrategy = IdGeneratorStrategy.IDENTITY) private Long id; @Persistent private String text; //getters and setters } Now I want to retrieve the objects using the id. I tried to manage it from the Google Appengine Data Viewer with "SELECT * FROM MyEntity Where id = 382005" or via a query in a servlet. I get no results returned. But i know for sure that the object with the id exists (i made a jsp which queries all objects in the db and displays them in the db). So what is wrong in my query? Am I querying the wrong field? The Google Appengine Data Viewer names the field "ID/name" and it has the value "id=382005". Do I have to query with this names? I've tried but it didn't work out :(

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• How to get the records using order by and so on

  - by paulrajj

  I have a table categories containing categories id having the records of 1 to 20. when i am doing the search query by using the IN function in mysql i got the results. but i am struggling to get the results using order by. The limit may be vary for every search as this is one of the input value. For example I have tried this query to find out the search results, select * from categories where category in (20,16,12,8) order by rand(), id limit 0,6 this query is executed and the results are in random category_id. the results will be, 8 12 16 20 and following this, another two records must be 8 12 If category_id contains only one record for 8 then, it should follow from 12,16. How can i achieve this ? thanks in advance.

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• How to display how many times each records in a table used by other table

  - by Fredy

  I have a problem with my query, below are two tables that tbl_tag and tbl_tag_usedby. I want to show how much of each record in tbl_tag used by record in tbl_tag_usedby. Here is a query that I use: SELECT t.*, COUNT(u.tagid) AS totale FROM tbl_tag t LEFT JOIN tbl_tag_usedby u ON u.tagid = t.id AND t.status =1 GROUP BY u.tagid and the results are as below: In this case the record id from 2 to 6 do not appear in the query results, I want record id from 2 to 6 are also shown and on the field "totale" its value is 0. Can anyone help me?

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• Retrieve rows where a value exists within a comma separated list

  - by Klaaz

  I like to reverse this query: SELECT * FROM table WHERE status IN ( option,option1,option2 ); in a query like SELECT * FROM table WHERE status contains ( 'option' ); Where field 'status' column contains (by example): 'option,option1'. When I use SELECT * FROM table WHERE status LIKE '%option%' ); It also selects the rows with a 'status' column that only contains 'option1' Is this possible? example data: id,name,status 1,'test1','option,option1' 2,'test2','option,option2' 3,'test3','option2' 4,'test4','option2,option3' 5,'test5','option' SELECT * FROM table WHERE status contains ( 'option' ); This query should select select record 1,2 and 5. 'status' field type is varchar. The problem is that the status fields contains data that is almost alike, exept from the added number to option. Off course this is a made up example but the real thing has this kind of parameters

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• Group by clause return latest row information

  - by I Like PHP

  below is my table structure table_movie_info i_movie_id |movie_actor_id |movie_actress_id |movie_director_id | movie_producer_id 48 | 5 | 9 | 66 | 21 48 | 6 | 15 | 88 | 22 48 | 7 | 12 | 77 | 23 one more table is table_movie movie_id | movie_year | movie_genre_id |movie_rating 1 | 2009 | 6 | 8 2 | 2001 | 5 | 7.5 48 | 2007 | 3 | 6.8 now i need total movie information using both table,i write below query SELECT * FROM table_movie_info LEFT JOIN table_movie ON movie_id = i_movie_id WHERE i_movie_id=48 GROUP BY i_movie_id above query return only one row , but i need such type of information movie_id=48, actors_id list=5,6,7 acttress_id list=9,15,12 etc.. please tell me the optimized query which h return complete information i need. thanks for helping me always.

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• Show parts of the result of an SQL statement using PHP

  - by mouthpiec

  I have an SQL query which returns a set of data (around 40-50 tuples). I would like to display the results 5 at a time on an HTML page using PHP. I already managed to have the right SELECT statement, but i am having problems to display the results 5 by 5 using a "more" button. Can you please help? Note that every time i call the query, the data is being randomized, so it is not possible to set limits and call the query again. I have to find the method to store the results somewhere, and then show them 5 by 5.

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• Querying Same Lookup Table With Multiple Columns

  - by dmaruca

  I'm a bit confused on this. I have a data table structured like this: Table: Data DataID Val 1 Value 1 2 Value 2 3 Value 3 4 Value 4 Then I have another table structured like this: Table: Table1 Col1 Col2 1 2 3 4 4 3 2 1 Both columns from Table1 point to the data in the data table. How can I get this data to show in a query? For example, a query to return this: Query: Query1 Column1 Column2 Value 1 Value 2 Value 3 Value 4 Value 4 Value 3 Value 2 Value 1 I'm familiar enough with SQL to do a join with one column, but lost beyond that. Any help is appreciated. Sample sql or a link to something to read. Thanks! PS: This is in sqlite

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• Joining two select queries and ordering results

  - by user1

  Basically I'm just unsure as to why this query is failing to execute: (SELECT replies.reply_post, replies.reply_content, replies.reply_date AS d, members.username FROM (replies) AS a INNER JOIN members ON replies.reply_by = members.id) UNION (SELECT posts.post_id, posts.post_title, posts.post_date AS d, members.username FROM (posts) as b WHERE posts.post_set = 0 INNER JOIN members ON posts.post_by = members.id) ORDER BY d DESC LIMIT 5 I'm getting this error: #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'a INNER JOIN members ON replies.re' at line 2 All I'm trying to do is select the 5 most recent rows (dates) from these two tables. I've tried Join, union etc and I've seen numerous queries where people have put another query after the FROM statement and that just makes no logical sense to me as to how that works? Am I safe to say that you can join the same table from two different but joined queries? Or am I taking completely the wrong approach, because frankly I can't seem see how this query is failing despite reading the error message. (The two queries on there own work fine)

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• Get the sum by comparing between two tables

  - by Ismail Gunes

  I have to tables ProdBiscuit As tb and StockData As sd , I have to get the sum of the quantity in StockData (quantite) with the condition of if (sd.status0 AND sd.prodid = tb.id AND sd.matcuisine = 3) Here is my sql query SELECT tb.id, tb.nom, tb.proddate, tb.qty, tb.stockrecno FROM ProdBiscuit AS tb JOIN (SELECT id, prodid, matcuisine, status, SUM(quantite) AS rq FROM StockData) AS sd ON (tb.id = sd.prodid AND sd.status > 0 AND sd.matcuisine = 3) LIMIT 25 OFFSET @Myid This gives me no rows at all ? There is only 3 rows in ProdBiscuit and 11 rows in Stockdata and there is only 2 rows in StockData good with the condition. And as shown in the picture there is only two rows which give the condition. What is wrong in my query ? PS: The green lines on the image shows the condition in my query.

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• Problem using Min(field)

  - by Todd

  have these two queries: SELECT classroomid AS crid, startdate AS msd FROM unitTemplates where classroomid = 6 GROUP BY classroomid and: SELECT classroomid AS crid, Min(startdate) AS msd FROM unitTemplates where classroomid = 6 GROUP BY classroomid The second query uses the minimum function. There is only one record in my table with a classroomid of 6. The first query returns msd = 20100505, the second query returns msd = 0 (instead of the expected 20100505). If I change the "Min" to "Max" it returns the highest (and only) startdate (20100505). Why doesn't MySQL like the Min function I'm using?

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• Combining IN and NOT IN in SQL as single result

  - by UltraVi01

  I apologize for the vague title. I am attempting to write a query that returns an alias column with matching values (resulting from an IN) as well as an alias column with values that do not match (using NOT IN). I want the result set to have: userId | matches | nonmatches. I currently have the following query which returns the matches as expected. I am having trouble getting the nonmatches in the result set -- that is, from a NOT IN statement SET @userId = 9; SELECT ug.user_id, COUNT(DISTINCT goal_id) as matches FROM user_goal ug WHERE ug.user_id!=@userId AND goal_id IN (SELECT iug.goal_id FROM user_goal iug WHERE user_id=@userId) GROUP BY user_id ORDER BY matches DESC LIMIT 4 So, the NOT IN would look something like this: goal_id NOT IN(SELECT uggg.goal_id FROM user_goal uggg WHERE user_id=@userId) AS nonmatches I am just not sure how to incorporate the NOT IN statement in my query so I get all the results

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• Mongo: Finding from multiple queries

  - by waxical

  New to Mongo here. I'm using the PHP lib and trying to work out how I can find in a collection from multiple queries. I could do this by repeating the query with a different query, but I wondered if it can be done in one. I.e. $idsToLookFor = array(2124,4241,5553); $query = $db->thisCollection->find(array('id' => $idsToLookFor)); That's what I'd like to do. However it doesn't work. What I'm trying to do is find a set of results for all the id's at one time. Possible or just do a findOne on each with a foreach/for?

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• Preventing SQL injecting in a database class

  - by Josh

  I'm building a database class and thought it'd be a good idea to incorporate some form of SQL injection prevention (duh!). Here's the method that runs a database query: class DB { var $db_host = 'localhost'; var $db_user = 'root'; var $db_passwd = ''; var $db_name = 'whatever'; function query($sql) { $this->result = mysql_query($sql, $this->link); if(!$this->result) { $this->error(mysql_error()); } else { return $this->result; } } } There's more in the class than that but I'm cutting it down just for this. The problem I'm facing is if I just use mysql_real_escape_string($sql, $this->link); then it escapes the entire query and leads to a SQL syntax error. How can I dynamically find the variables that need to be escaped? I want to avoid using mysql_real_escape_string() in my main code blocks, i'd rather have it in a function. Thanks.

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• Pass database data to multiples views-Laravel

  - by user3696018

  I have a database with details of daily sales. To query a database, I have a form in a view with parameters that will query as date of admission, client and others. The result is shown in another view with the daily details of income, and below is a summary of the article do all entered. The summary I wish to transfer to another view, try to view :: composer but only transfer the empty query (I saw it with debug bar). Just appeared an empty view. How I can transfer data from the database without the latter view is empty? The second html view is totaly diferent , only the data is the same.

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• insert into select from other table

  - by user3815079

  I need to add multiple records based on data from another table where the event is the same. I've found on this forum insert into table2(id,name) select "001",first_name from table1 where table1.id="001" as possible solution for my question. So I thought this should be the following syntax: insert into reservations(event,seat) select "99",id from seats where seats.id>0 to add all seats to event 99. However when I run this query mysql gives the message 'MySQL returned an empty resultset (0 rows). (query 0.0028 sec)' and no records were added. I translated the message so could be sligthly different. When I only use the "select "99",id from seats where seats.id0" query, it returns me 1080 rows.

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• MySQL Master-Master w/ multiple read slave cost effective setup in AWS

  - by Ross

  I've been evaluating Amazon Web Services RDS for MySQL and costing out potential scenarios involving a simple multi-AZ deployment read/write setup vs. a multi-AZ deployment mysql master (hot-standby) with additional read-only slaves. the issue I'm trying to cost-optimize includes their reserved instance vs on-demand instances. Situation 1: purchase reserved multi-az setup for Extra-large-hi-mem(17GB RAM) instance for $5200/yr and have my application query the master all the time. the problem is, if I don't need all the resources of the (17GB RAM) all the time and therefore, especially not a hot-standby, what alternatives for savings can a better topology create, like potentially situation 2 below: Situation 2: purchase reserved multi-az setup using smaller master instances than above for the master-master hot-standby to receive the writes only. Then create and load balance several read-only slaves off the master and add/remove and/or scale up/down the read slaves based on demand. This might only cost $1000 + the on-demand usage of the read slaves. My thinking is, if I have a variable read-intensive application load, with low write load, the single level topology in situation 1 means I'm paying for a lot of resources at the write level of topology when I don't need them there. My hope is that situation 2 can yield cost savings from smaller reserved instances on the master-master resource level allowing me to scale up and down and/or out on the read-level according to demand as needed. Does anyone see a downside to doing this or know of some reason this isn't possible with RDS? Any other thoughts or advice always welcome of course. Thanks in advance, R

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• MySQL 5.5 : sortie imminente ? Oracle devrait annoncer la nouvelle version du SGBD open-source mercredi

  MySQL 5.5 : sortie imminente ? Oracle devrait annoncer la nouvelle version du SGBD open-source mercredi Mise à jour du 13/12/10 Ce mercredi, Oracle organise un webinar pour présenter « une mise à jour importante de MySQL ». Tomas Ulin, Vice-Président du développement de MySQL et Rob Young, Senior Product Manager, y dévoileront les dernières avancées du SGBD open-source que le géant des bases de données à récupérée avec le rachat de Sun. Oracle avait annoncé une RC de MySQL 5,5 lors de l'Oracle OpenWorld de septembre (lire ci-avant). Cette fois-ci, les responsables du projets pourraient annoncer sa disponibilité officielle.

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• Non perdere la possibilità di incontrare i membri dell’Oracle Real-Time Decisions Customer Advisory Board!

  - by Silvia Valgoi

  Quest’anno, in via del tutto eccezionale, vengono aperte le porte dell’appuntamento annuale che Oracle dedica ai clienti di alcune specifiche Applicazioni: si incontreranno a Roma il prossimo 20 giugno 2012  i clienti mondiali della soluzione Oracle Real-Time Decisions (RTD). E’ una occasione unica per sentire direttamente da chi ha implementato questa soluzione quali siano stati i reali ritorni sugli investimenti e per parlare direttamente con loro in un contesto internazionale. La testimonianza di  Dell - che presenterà l’utilizzo di RTD  integrato anche a Siebel - la partecipazione di  BT, Deutsch Telecom, United Airlines, Bouygues Telecom, Dell e RoomKe, fanno di questo appuntamento un momento importante per tutti coloro che vedono nel Real-Time Decisions un tassello importante per le loro strategie di Customer Experience Management. Sei interessato? http://www.oracle.com/goto/RealTimeDecisions

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• Raymond James at Oracle OpenWorld: Showcasing Real Time Data Integration.

  - by Christophe Dupupet

  Normal 0 false false false EN-US X-NONE X-NONE MicrosoftInternetExplorer4 /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:11.0pt; font-family:"Calibri","sans-serif"; mso-ascii-font-family:Calibri; mso-ascii-theme-font:minor-latin; mso-fareast-font-family:"Times New Roman"; mso-fareast-theme-font:minor-fareast; mso-hansi-font-family:Calibri; mso-hansi-theme-font:minor-latin; mso-bidi-font-family:"Times New Roman"; mso-bidi-theme-font:minor-bidi;} In today’s always-on, always connected world, integrating data in real-time is a necessity for most companies and most industries. The experts at Raymond James Financials, using Oracle GoldenGate and Oracle Data Integrator, have designed a real-time data integration solution for their operational data store and services that support applications throughout the enterprise . They boast an amazing number of daily executions, while dramatically reducing data latency,  increasing data service performance, and speeding time to market. Normal 0 false false false EN-US X-NONE X-NONE /* Style Definitions */ table.MsoNormalTable {mso-style-name:"Table Normal"; mso-tstyle-rowband-size:0; mso-tstyle-colband-size:0; mso-style-noshow:yes; mso-style-priority:99; mso-style-qformat:yes; mso-style-parent:""; mso-padding-alt:0in 5.4pt 0in 5.4pt; mso-para-margin:0in; mso-para-margin-bottom:.0001pt; mso-pagination:widow-orphan; font-size:10.0pt; font-family:"Times New Roman","serif";} To know more on how they have achieved such results, come listen to Ryan Fonnett and Tim Garrod: they will explain how they implemented their solution, and also illustrate their explanations with a live demonstration of their work. A presentation not to be missed! Real-Time Data Integrationwith Oracle Data Integratorat Raymond James October 1st 2012 at 4:45pm Moscone West, room 3005

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• The Boss Answer: What is a relational database?

  - by kce

  I'm mostly a system administrator and I don't directly work with databases other than installing them, setting up accounts, granting privileges, and so on. I realized that if The Boss walked up to me and asked, "What is a relational database?" I probably couldn't give a satisfactory answer... I'd maybe mumble something about data being stored and organized by categories which you can query with a special programing language (i.e., SQL). So could someone give a good "Boss Answer" for what a relational database is? And maybe how its different than just storing data on a file server? Bonus points for clever but accessible analogies and explaining tables, columns, records and fields. I'd define a "Boss Answer" as a quick one (maybe two) paragraph explanation for non-technical folks... mostly your Boss, on those rare occasions they actually ask you what it is you do all day.

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• Database OR Array

  - by rezoner

  What is the exact point of using external database system if I have simple relations (95% querries are dependant on ID). I am storing users and their stats. Why would I use external database if I can have neat constructions like: db.users[32] = something Array of 500K users is not that big effort for RAM Pros are: no problematic asynchronity (instant results) easy export/import dealing with database like with a native object LITERALLY ps. and considerations: Would it be faster or slower to do collection[3] than db.query("select ... I am going to store it as a file/s There is only ONE application/process accessing this data, and the code is executed line by line - please don't elaborate about locking. Please don't answer with database propositions but why to use external DB over native array/object - I have experience in a few databases - that's not the case. What I am building is a client/gateway/server(s) game. Gateway deals with all users data, processing, authenticating, writing statistics e.t.c No other part of software needs to access directly to this data/database.

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• SharePoint 2010 search crawl not working

  - by J. Hammond

  I have the following set up: 1 x Windows server 2008 R2 running SQL 1 x Windows server 2008 R2 running SharePoint 2010. I have an issue with the search service application, the crawl appears to run for a never ending amount of time with 0 successes and 0 failures. Checking the Search Application Topology, I find that "Query Component 0" is "Not Responding". I have tried the following: I have ensured that the index directory has the right permissions applied to it and the search service account is in the right groups to consume those permissions. I have re-created the search service application. I have restarted the search service manually. I have trawled the net as much as possible to find a solution but as of yet have not come across something that has resolved this issue. Any input will be very much appreciated

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• MySQL port 3306 blocked in csf yet can still telnet to port 3306 from external host

  - by Neek

  We have a Centos 6 VPS that was recently migrated to a new machine within the same web hosting company. It's running WHM/cPanel and has csf/lfd installed. csf is set up with mostly vanilla config. I'm no iptables expert, csf has not let me down before. If a port isn't in the TCP_IN list, it should be blocked on the firewall by iptables. My problem is that I can telnet to port 3306 from an external host, yet I think iptables ought to be blocking 3306 because of csf's rules. We are now failing a security check because of this open port. (this output is obfuscated to protect the innocent: www.ourhost.com is the host with the firewall problem) [root@nickfenwick log]# telnet www.ourhost.com 3306 Trying 158.255.45.107... Connected to www.ourhost.com. Escape character is '^]'. HHost 'nickfenwick.com' is not allowed to connect to this MySQL serverConnection closed by foreign host. So the connection is established, and MySQL refuses the connection due to its configuration. I need the network connection to be refused at the firewall level, before it reaches MySQL. Using WHM's csf web UI I can see 'Firewall Configuration' includes a fairly sensible TCP_IN line: TCP_IN: 20,21,22,25,53,80,110,143,222,443,465,587,993,995,2077,2078,2082,2083,2086,2087,2095,2096,8080 (lets ignore that I could trim that a little for now, my concern is that 3306 is not listed in that list) When csf is restarted it logs the usual slew of output as it sets up iptables rules, for example what looks like it blocking all traffic and then allowing specific ports like SSH on 22: [cut] DROP all opt -- in * out * 0.0.0.0/0 -> 0.0.0.0/0 [cut] ACCEPT tcp opt -- in !lo out * 0.0.0.0/0 -> 0.0.0.0/0 state NEW tcp dpt:22 [cut] I can see that iptables is running, service iptables status returns a long list of firewall rules. Here is my Chain INPUT section from service iptables status, hopefully that's enough to show how the firewall is configured. Table: filter Chain INPUT (policy DROP) num target prot opt source destination 1 acctboth all -- 0.0.0.0/0 0.0.0.0/0 2 ACCEPT tcp -- 217.112.88.10 0.0.0.0/0 tcp dpt:53 3 ACCEPT udp -- 217.112.88.10 0.0.0.0/0 udp dpt:53 4 ACCEPT tcp -- 217.112.88.10 0.0.0.0/0 tcp spt:53 5 ACCEPT udp -- 217.112.88.10 0.0.0.0/0 udp spt:53 6 ACCEPT tcp -- 8.8.4.4 0.0.0.0/0 tcp dpt:53 7 ACCEPT udp -- 8.8.4.4 0.0.0.0/0 udp dpt:53 8 ACCEPT tcp -- 8.8.4.4 0.0.0.0/0 tcp spt:53 9 ACCEPT udp -- 8.8.4.4 0.0.0.0/0 udp spt:53 10 ACCEPT tcp -- 8.8.8.8 0.0.0.0/0 tcp dpt:53 11 ACCEPT udp -- 8.8.8.8 0.0.0.0/0 udp dpt:53 12 ACCEPT tcp -- 8.8.8.8 0.0.0.0/0 tcp spt:53 13 ACCEPT udp -- 8.8.8.8 0.0.0.0/0 udp spt:53 14 LOCALINPUT all -- 0.0.0.0/0 0.0.0.0/0 15 ACCEPT all -- 0.0.0.0/0 0.0.0.0/0 16 INVALID tcp -- 0.0.0.0/0 0.0.0.0/0 17 ACCEPT all -- 0.0.0.0/0 0.0.0.0/0 state RELATED,ESTABLISHED 18 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:20 19 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:21 20 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:22 21 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:25 22 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:53 23 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:80 24 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:110 25 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:143 26 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:222 27 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:443 28 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:465 29 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:587 30 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:993 31 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:995 32 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:2077 33 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:2078 34 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:2082 35 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:2083 36 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:2086 37 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:2087 38 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:2095 39 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:2096 40 ACCEPT tcp -- 0.0.0.0/0 0.0.0.0/0 state NEW tcp dpt:8080 41 ACCEPT udp -- 0.0.0.0/0 0.0.0.0/0 state NEW udp dpt:20 42 ACCEPT udp -- 0.0.0.0/0 0.0.0.0/0 state NEW udp dpt:21 43 ACCEPT udp -- 0.0.0.0/0 0.0.0.0/0 state NEW udp dpt:53 44 ACCEPT udp -- 0.0.0.0/0 0.0.0.0/0 state NEW udp dpt:222 45 ACCEPT udp -- 0.0.0.0/0 0.0.0.0/0 state NEW udp dpt:8080 46 ACCEPT icmp -- 0.0.0.0/0 0.0.0.0/0 icmp type 8 47 ACCEPT icmp -- 0.0.0.0/0 0.0.0.0/0 icmp type 0 48 ACCEPT icmp -- 0.0.0.0/0 0.0.0.0/0 icmp type 11 49 ACCEPT icmp -- 0.0.0.0/0 0.0.0.0/0 icmp type 3 50 LOGDROPIN all -- 0.0.0.0/0 0.0.0.0/0 What's the next thing to check?

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• MySQL se tourne encore plus vers InnoDB, qui sera utilisé pour les tables systèmes pour bénéficier des propriétés ACID

  MySQL se tourne encore plus vers InnoDB qui sera utilisé pour les tables systèmes pour bénéficier des propriétés ACID Depuis le rachat de MySQL par Oracle, le célèbre SGBD a entamé une lente transition de son moteur de base de données, passant du moteur d'origine MyISAM qui est basé sur la méthode ISAM (Indexed Sequential Access Methode) à InnoDB. Cette transition s'est d'ailleurs achevée partiellement par l'intronisation d'InnoDB comme moteur par défaut pour les versions de MySQL 5.5 et plus.Partiellement,...

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• Is there a real name policy in the Ubuntu community?

  - by martin001

  I'm not ashamed to be a part of Ubuntu, but I'm trying to keep the number of web search hits for my real name low, which is kinda impossible if you use a Launchpad account. So, I'm wondering if there is a real name policy in the Ubuntu community, or if it's okay to use a pseudonym/nick name/fake name? While it might be okay to use nick names on IRC and in forums, how about these topics: Adding an OpenPGP key to Launchpad. Signing the Ubuntu Code of Conduct. Becoming an Ubuntu member. Code contributions (e.g., signing the Canonical CLA). Thanks in advance for your answers!

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