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  • Trying to re-install ubuntu 11.10on an HP Pavillion G6, screen goes black after the ubuntu logo shows.How do I get it to install normally?

    - by Josh Towers
    Installed Ubuntu 11.1 successfully without my wireless device being recognized. Used sudo apt-get update + upgrade commands to attempt to fix this. Computer crashes after upgrade and now it won't finish re-installing Ubuntu, after it shows the first purple screen with the Ubuntu logo, the screen goes black. Used the Derik's Boot Nuke CD and then attempted re-installment again, and the black screen problem remains consistent, seemingly no matter what I do. It sounds like it's installing but won't let me see anything or go anywhere. heelllppp

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  • File Upload with HttpWebRequest doesn't post the file

    - by Sri Kumar
    Hello All, Here is my code to post the file. I use asp fileupload control to get the file stream. HttpWebRequest requestToSender = (HttpWebRequest)WebRequest.Create("http://localhost:2518/Web/CrossPage.aspx"); requestToSender.Method = "POST"; requestToSender.ContentType = "multipart/form-data"; requestToSender.KeepAlive = true; requestToSender.Credentials = System.Net.CredentialCache.DefaultCredentials; requestToSender.ContentLength = BtnUpload.PostedFile.ContentLength; BinaryReader binaryReader = new BinaryReader(BtnUpload.PostedFile.InputStream); byte[] binData = binaryReader.ReadBytes(BtnUpload.PostedFile.ContentLength); Stream requestStream = requestToSender.GetRequestStream(); requestStream.Write(binData, 0, binData.Length); requestStream.Close(); HttpWebResponse responseFromSender = (HttpWebResponse)requestToSender.GetResponse(); string fromSender = string.Empty; using (StreamReader responseReader = new StreamReader(responseFromSender.GetResponseStream())) { fromSender = responseReader.ReadToEnd(); } XMLString.Text = fromSender; In the page load of CrossPage.aspx i have the following code NameValueCollection postPageCollection = Request.Form; foreach (string name in postPageCollection.AllKeys) { Response.Write(name + " " + postPageCollection[name]); } HttpFileCollection postCollection = Request.Files; foreach (string name in postCollection.AllKeys) { HttpPostedFile aFile = postCollection[name]; aFile.SaveAs(Server.MapPath(".") + "/" + Path.GetFileName(aFile.FileName)); } string strxml = "sample"; Response.Clear(); Response.Write(strxml); I don't get the file in Request.Files. The byte array is created. What was wrong with my HttpWebRequest?

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  • Trouble converting an MP3 file to a WAV file using Naudio

    - by WebDevHobo
    Naudio Library: http://naudio.codeplex.com/ I'm trying to convert an MP3 file to a WAV file, but I've run in to a small error. I know what's going wrong, but I don't really know how to go about fixing it. Here's the piece of code I'm running: private void button1_Click(object sender, EventArgs e) { using(Mp3FileReader reader = new Mp3FileReader(@"path\to\MP3")) { using(WaveFileWriter writer = new WaveFileWriter(@"C:\test.wav", new WaveFormat())) { int counter = 0; while(reader.Read(test, counter, test.Length + counter) != 0) { writer.WriteData(test, counter, test.Length + counter); counter += 512; } } } } reader.Read() goes into the Mp3FileReader class, and the method looks like this: public override int Read(byte[] sampleBuffer, int offset, int numBytes) { if (numBytes % waveFormat.BlockAlign != 0) //throw new ApplicationException("Must read complete blocks"); numBytes -= (numBytes % waveFormat.BlockAlign); return mp3Stream.Read(sampleBuffer, offset, numBytes); } mp3Stream is an object of the Stream class. The problem is: I'm getting an ArgumentException. MSDN says that this is because the sum of offset and numBytes is greater than the length of sampleBuffer. Documentation: http://msdn.microsoft.com/en-us/library/system.io.stream.read.aspx This happens because I increase the counter every time, but the size of the byte array test remains the same. What I've been wondering is: do I need to increase the size of the array dynamically, or do I need to find out the needed size at the beginning and set it right away? And also, instead of 512, the method in Mp3FileReader returns 365 the first time. Which is the size of a whole block. But I'm writing the full 512. I'm basically just using the read to check if I'm not at the end of the file yet. Do I need to catch the return value and do something with that, or am I good here?

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  • IE7 issue - cannot download streamed file when Automatic prompting for file downloads is disabled

    - by Jai ganesh K
    Hi, My application is J2EE (JSP/Servlet) based. I encounter an issue when i try to open a new window (pop-up) from JSP and call a Servlet action (e.g. Streamer.do) which streams a PDF file inside that pop-up. Problem: While IE 7 - Tools - Internet Options - Security - Custom Level - Downloads - Automatic prompting for file downloads is Disabled and while pop-up window get opened, I am unable to download the file (Save/Open prompt is not comming up). In contrast, when I enable this option, I am able to download. But this option sometimes would be disabled in some environments. While testing this in Mozilla Firefox 3.0/3/5/IE6 it is working fine without any settings change. When i check it to enable i then get the Save/Open prompt to work correctly. This should be problem with IE7. Can anybody help us with Javascript or any working settings which doesnt care whether the "Automatic prompting for downloads" option in IE7 is enabled. Any help in this would be much appreciated. Regards! Jai

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  • Pentaho - Reporting Tool - Is the .prpt file (report template file) contains datasource information

    - by Yatendra Goel
    I am new Pentaho Reporting Tool. I have the following question: When I created a report using Pentaho Report Designer, it output a report file having .prpt extension. After that I found an example on internet where the following code were used to display the report in html format:| protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { ResourceManager manager = new ResourceManager(); manager.registerDefaults(); String reportPath = "file:" + this.getServletContext().getRealPath("sampleReport.prpt"); try { Resource res = manager.createDirectly(new URL(reportPath), MasterReport.class); MasterReport report = (MasterReport) res.getResource(); HtmlReportUtil.createStreamHTML(report, response.getOutputStream()); } catch (Exception e) { e.printStackTrace(); } } And the report got printed successfully. So as we haven't specified any datasource information here, I think that the .prpt file contains that information in it. If that's true than Isn't Jasper is better Reporting tool than Pentaho because when we display Jasper reports, we have to provide datasource details also so in that way our report is flexible and is not bound to any particular database.

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  • Need a way to determine if a file is done being written to.

    - by Khorkrak
    The situation I'm in is this - there's a process that's writing to a file, sometimes the file is rather large say 400 - 500MB. I need to know when it's done writing. How can I determine this? If I look in the directory I'll see it there but it might not be done being written. Plus this needs to be done remotely - as in on the same internal LAN but not on the same computer and typically the process that wants to know when the file writing is done is running on a Linux box with a the process that's writing the file and the file itself on a windows box. No samba isn't an option. xmlrpc communication to a service on that windows box is an option as well as using snmp to check if that's viable. Ideally Works on either Linux or Windows - meaning the solution is OS independent. Works for any type of file. Good enough: Works just on windows but can be done through some library or whatever that can be accessed with Python. Works only for PDF files. Current best idea is to periodically open the file in question from some process on the windows box and look at the last bytes checking for the PDF end tag and accounting for the eol differences because the file may have been created on Linux or Windows.

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  • Django/jQuery - read file and pass to browser as file download prompt

    - by danspants
    I've previously asked a question regarding passing files to the browser so a user receives a download prompt. However these files were really just strings creatd at the end of a function and it was simple to pass them to an iframe's src attribute for the desired effect. Now I have a more ambitious requirement, I need to pass pre existing files of any format to the browser. I have attempted this using the following code: def return_file(request): try: bob=open(urllib.unquote(request.POST["file"]),"rb") response=HttpResponse(content=bob,mimetype="application/x-unknown") response["Content-Disposition"] = "attachment; filename=nothing.xls" return HttpResponse(response) except: return HttpResponse(sys.exc_info()) With my original setup the following jQuery was sufficient to give the desired download prompt: jQuery('#download').attr("src","/return_file/"); However this won't work anymore as I need to pass POST values to the function. my attempt to rectify that is below, but instead of a download prompt I get the file displayed as text. jQuery.get("/return_file/",{"file":"c:/filename.xls"},function(data) { jQuery(thisButton).children("iframe").attr("src",data); }); Any ideas as to where I'm going wrong? Thanks!

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  • Deploy an hta file in an exe or msi file

    - by rjmunro
    I've written an HTA file frontend for our web app that allows the web app to run without web browser status bars etc, and allows it to access the local system for certain tasks. I need a way to deploy this to customers. I need an installer to supply an hta file, an ico file, and add a link to them in the start menu and on the users desktop. I looked at building an installer with NSIS, but I couldn't figure out how to assign the icon to the shortcuts - The icon had to be a standard HTA one. Can this be done with NSIS, or should I be using another installer? P.s. I've got no particular preference for NSIS, it's just something I once used a very long time ago. When I download stuff, I think I prefer them to be msi files that launch with windows installer (it feels more like downloading a .rpm or .deb on linux which I am used to) but I know nothing about how those are created. I'm a web/linux guy who knows very little about windows programming.

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  • Reading a binary file in perl: Bad File Descriptor

    - by Magicked
    I'm trying to read a binary file 40 bytes at a time, then check to see if all those bytes are 0x00, and if so ignore them. If not, it will write them back out to another file (basically just cutting out large blocks of null bytes). This may not be the most efficient way to do this, but I'm not worried about that. However, right now I'm getting a "Bad File Descriptor" error and I cannot figure out why. my $comp = "\x00" * 40; my $byte_count = 0; my $infile = "/home/magicked/image1"; my $outfile = "/home/magicked/image1_short"; open IN, "<$infile"; open OUT, ">$outfile"; binmode IN; binmode OUT; my ($buf, $data, $n); while (read (IN, $buf, 40)) { ### Problem is here ### $boo = 1; for ($i = 0; $i < 40; $i++) { if ($comp[$i] != $buf[$i]) { $i = 40; print OUT $buf; $byte_count += 40; } } } die "Problems! $!\n" if $!; close OUT; close IN; I marked with a comment where it is breaking. Thanks for any help!

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  • Saving temporary file name after uploading file with uplodify

    - by mIRU
    I have this script if (!empty($_FILES)) { $tempFile = $_FILES['Filedata']['tmp_name']; $targetPath = dirname(__FILE__).$_POST['folder'] . '/'; $pathinfoFile = pathinfo($_FILES['Filedata']['name']); $targetFile = str_replace('//','/',$targetPath) .uniqid().'.'.$pathinfoFile['extension']; move_uploaded_file($tempFile,$targetFile); } this script is from uplodify , modified for saving the file with unique name , i need after user will upload the file , this unique name and original name , to save temporary , when user will submit the form , this temporary variables i will insert in database , the problem is that in firebug console , i can not see all the actions of this script , and i can not understand the way how to fix it, I tried to save in $_SESSION but i have problems , is not saving , i found why is not working with $_SESSION , http://uploadify.com/forum/viewtopic.php?f=5&t=43 , i tried the solution from forum but without result , exist a more easy way to solve this problem ? , or what is better way to do it ? . Sorry for so silly question , i ran out of ideas . Thanks a lot for helping me , and sorry again for my English

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  • Java - Reading a csv file line by line - stuck with weird non-existent characters being read!

    - by rockit
    hello fellow java developers. I'm having a very strange issue. I'm trying to read a csv file line by line. Im at the point where Im just testing out the reading of the lines. ONly each time that I read a line, the line contains square characters between each character of text. I even saved the file as a txt file in wordpad and notepad with no change. Thus I must be doing something stupid... I have a csv file, standard csv file, yes a text file with commas in it. I try to read a line of text, but the text is all f-ed up and cannot find the phrase within the text. Any advice? code below. //open csv File filReadMe = new File(strRoot + "data2.csv"); BufferedReader brReadMe = new BufferedReader(new InputStreamReader(new FileInputStream(filReadMe))); String strLine = brReadMe.readLine(); //for all lines while (strLine != null){ //if line contains "(see also" if (strLine.toLowerCase().contains("(see also")){ //write line from "(see also" to ")" int iBegin = strLine.toLowerCase().indexOf("(see also"); String strTemp = strLine.substring(iBegin); int iLittleEnd = strTemp.indexOf(")"); System.out.println(strLine.substring(iBegin, iBegin + iLittleEnd)); } //update line strLine = brReadMe.readLine(); } //end for brReadMe.close();

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  • Short file names versus long file names in Windows

    - by normski
    I have some code which gets the short name from a file path, using GetShortNameW(), and then later retrieves the long name view GetLongNameA(). The original file is of the form "C:/ProgramData/My Folder/File.ext" However, following conversion to short, then back to long, the filename becomes "C:/Program Files/My Folder/Filename.ext". The short name is of the form "C:/PROGRA~2/MY_FOL~1/FIL~1.EXT" The short name is being incorrectly resolved. The code compiles using VS 2005 on Windows 7 (I cannot upgrade the project to VS2008) Does anybody have any idea why this might be happening? DWORD pathLengthNeeded = ::GetShortPathNameW(aRef->GetFilePath().c_str(), NULL, 0); if(pathLengthNeeded != 0) { WCHAR* shortPath = new WCHAR[pathLengthNeeded]; DWORD newPathNameLength = ::GetShortPathNameW(aRef->GetFilePath().c_str(), shortPath, pathLengthNeeded); if(newPathNameLength != 0) { UI_STRING unicodePath(shortPath); std::string asciiPath = StringFromUserString(unicodePath); pathLengthNeeded = ::GetLongPathNameA(asciiPath.c_str(),NULL, 0); if(pathLengthNeeded != 0) {// convert it back to a long path if possible. For goodness sake can't we use Unicode throughout?F char* longPath = new char[pathLengthNeeded]; DWORD newPathNameLength = ::GetLongPathNameA(asciiPath.c_str(), longPath, pathLengthNeeded); if(newPathNameLength != 0) { std::string longPathString(longPath, newPathNameLength); asciiPath = longPathString; } delete [] longPath; } SetFullPathName(asciiPath); } delete [] shortPath; }

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  • Unable to delete a file using bash script

    - by user3719091
    I'm having problems removing a file in a bash script. I saw the other post with the same problem but none of those solutions solved my problem. The bash script is an OP5 surveillance check and it calls an Expect process that saves a temporary file to the local drive which the bash script reads from. Once it has read the file and checked its status I would like to remove the temporary file. I'm pretty new to scripting so my script may not be as optimal as it can be. Either way it does the job except removing the file once it's done. I will post the entire code below: #!/bin/bash #GET FLAGS while getopts H:c:w: option do case "${option}" in H) HOSTADDRESS=${OPTARG};; c) CRITICAL=${OPTARG};; w) WARNING=${OPTARG};; esac done ./expect.vpn.check.sh $HOSTADDRESS #VARIABLES VPNCount=$(grep -o '[0-9]\+' $HOSTADDRESS.op5.vpn.results) # Check if the temporary results file exists if [ -f $HOSTADDRESS.op5.vpn.results ] then # If the file exist, Print "File Found" message echo Temporary results file exist. Analyze results. else # If the file does NOT exist, print "File NOT Found" message and send message to OP5 echo Temporary results file does NOT exist. Unable to analyze. # Exit with status Critical (exit code 2) exit 2 fi if [[ "$VPNCount" > $CRITICAL ]] then # If the amount of tunnels exceeds the critical threshold, echo out a warning message and current threshold and send warning to OP5 echo "The amount of VPN tunnels exceeds the critical threshold - ($VPNCount)" # Exit with status Critical (exit code 2) exit 2 elif [[ "$VPNCount" > $WARNING ]] then # If the amount of tunnels exceeds the warning threshold, echo out a warning message and current threshold and send warning to OP5 echo "The amount of VPN tunnels exceeds the warning threshold - ($VPNCount)" # Exit with status Warning (exit code 1) exit 1 else # The amount of tunnels do not exceed the warning threshold. # Print an OK message echo OK - $VPNCount # Exit with status OK exit 0 fi #Clean up temporary files. rm -f $HOSTADDRESS.op5.vpn.results I have tried the following solutions: Create a separate variable called TempFile that specifies the file. And specify that in the rm command. I tried creating another if statement similar to the one I use to verify that file exist and then rm the filename. I tried adding the complete name of the file (no variables, just plain text of the file) I can: Remove the file using the full name in both a separate script and directly in the CLI. Is there something in my script that locks the file that prevents me from removing it? I'm not sure what to try next. Thanks in advance!

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  • High mysql server load, sar output

    - by eric
    I have a MySQL Server that should be performing better than it seems to be. We're running ubuntu on a Amazon Cluster Compute (cc1.4xlarge) Linux ip-10-0-1-60 3.2.0-25-virtual #40-Ubuntu SMP Wed May 23 22:20:17 UTC 2012 x86_64 x86_64 x86_64 GNU/Linux Distributor ID: Ubuntu Description: Ubuntu 12.04 LTS Release: 12.04 Codename: precise I have several output files from sar that i'm not really sure how to interpret. For example, I ran: # Individual block device I/O activities sar -d 1 180 > logs/block_device_io.log & which gave me what looks like really high utilisation of my disk (turns out this block device maps to /dev/xvdh on /var/lib/mysql type ext4 (rw,_netdev) The output from my log: 10:48:59 PM DEV tps rd_sec/s wr_sec/s avgrq-sz avgqu-sz await svctm %util 10:49:00 PM dev202-16 0.00 0.00 0.00 0.00 0.00 0.00 0.00 0.00 10:49:00 PM dev202-32 0.00 0.00 0.00 0.00 0.00 0.00 0.00 0.00 10:49:00 PM dev8-0 0.00 0.00 0.00 0.00 0.00 0.00 0.00 0.00 10:49:00 PM dev202-112 1008.00 31040.00 1416.00 32.20 1.02 1.01 0.89 90.00 10:49:00 PM dev202-80 0.00 0.00 0.00 0.00 0.00 0.00 0.00 0.00 Am I wrong in thinking this is a problem? I have it above 90% almost the entire time we're seeing slowness. Or does this just mean MySQL is doing what it's supposed to do?

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  • Using Virtualbox Bridge Networking fails connection from Guest OS to Oracle XE running on Host

    - by Licheng
    I am trying to make a JDBC connection from a VirtualBox Ubuntu Guest OS to an Oracle XE database running o Host. However, the connection is refused. Here are the details of my environment: VirtualBox: 4.1.4 Host OS: Windows 7 Guest OS: Ubuntu server 11.4 Networking mode: Bridged network Oracle XE database running on Host Issue: WebLogic server runs on the Ubuntu virtualbox. It attempts to connect to an Oracle XE database running on the Host OS (windows 7) with listening port 1521. On the Guest OS (Ubuntu), I am able to ping the Host computer from the Guest OS. However, when I configured a JDBC data source on the WebLogic server on the Guest OS to connect to the Oracle XE, connection took a long time, and eventually I received an "IO Exception: The Network Adapter could not establish the connection". When I tried "telnet host-ip 1521", no connection was established. With Bridge networking, I can make bi-directional connections between the host and the guest OS (e.g. connection through ssh and ftp). Is there anything I missed in the setup of Bridge networking and the guest/host OS? Note that I was able to make the same connection within a normal networking environment (i.e. not using virtual box). I am not sure whether Bridge networking is a good option for the work described above. Should I use host-only networking mode? If so, any specific configurations I need to perform? I read through the Virtual box document on setting up the host-only network, however, it lacks of details. I followed the procedures described in the manual, and couldn't even connect to the host. Could some experts here enlighten me on this issue? Much appreciated. Licheng

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  • How to copy file preserving directory path in Linux?

    - by gasan
    I have Eclipse projects and ".project" file in them, the directory structure looks like 'myProject/.project'. I want to copy these '.project' files to another directory, but I want the enclosing directory name to be preserved. Let's say I have 'a/myProject/.project', I want to copy 'myProject/.project' to 'b', so it be 'b/myProject/.project', but 'b/myProject' doesn't exist. When I try in a: cp -r ./myProject/.project ../b it copies only '.project' file itself, without 'myProject' directory. Please advise.

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  • File association error while trying to browse to a network share in explorer or from run?

    - by ChrisFletcher
    I'm getting the below error message while trying to browse to a local share on a Windows Server 2003 machine: Windows cannot find ### this file does not have a program associated with it for performing this action. Create an Association in the folder options control panel The server is on the network, has an assigned IP address, can access the internet and is otherwise functioning normally. I realise this message can occur when opening a document or file which has no application associated with it, but I'm trying to access a share. What's going on here?

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  • two computers on same network cannot ping eachother nor view NetBios resources

    - by slava
    I'd like to find out the problem of my network configuration I have network configuration is like in this diagram: The problem is between laptop1 and laptop2. At first I thought it was samba server problem. I was configuring samba server on one of the laptops and I wasn't able to access the shares from the second laptop no matter what I was doing. After installing/removing/configuring samba-server a couple of times I realized that the problem resides somewhere else. Laptop configurations: - Laptop1: ubuntu 12.04 - Laptop2: Windows 7/ ubuntu 12.04 ( dual boot ) - Server : ubuntu 12.04 When I do "ping 192.168.0.10" from laptop2, I get "Destination host unreachable". The same situation is when I ping in other direction. When I access Laptop1 shares from Laptop2, having windows 7 loaded, I get the error message: "Error code: 0x80070035 The network path was not found." When I ping "server" or "router" or "wifi router" from any of laptops I get a reply. The same with windows shares, I am able to access "server"s shares from Windows and Ubuntu, from any of my laptops. Netbios can't function correctly, that's obvious, I am unable to access windows shares between laptops. I assume that on "wifi router" is a miss-configuration, but I can't find what specifically. The "Wifi router" works as Hub + wifi, it is connected to "router" not in WAN port but in LAN1. Please, help me correctly configure the router to make them see each-other, or at least make NetBios work correctly, between laptops, to be able to access windows shares. Thanks!

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  • moving plone or recovering data

    - by Atilla Filiz
    I had a simple plone site running on my Ubuntu 8.10 box, setup by following instructions on https://help.ubuntu.com/community/forum/server/Plone Now the computer got an Ubuntu 9.04 install from scratch, and I want to get the site up and running. As far as I understand several python libraries from 9,04 are not compatible with plone. I tried installing plon3-site from ubuntu repos, and I got this: $bin/instance start Traceback (most recent call last): File "bin/instance", line 103, in ? import plone.recipe.zope2instance.ctl File "/media/Robocup2009/robocup2009/eggs/plone.recipe.zope2instance-2.7-py2.4.egg/plone/recipe/zope2instance/__init__.py", line 16, in ? import zc.buildout File "/media/Robocup2009/robocup2009/eggs/zc.recipe.egg-1.1.0-py2.4.egg/zc/__init__.py", line 1, in ? __import__('pkg_resources').declare_namespace(__name__) ImportError: No module named pkg_resources I have python-pkg-resources installed. I actually don't care about plone, I just found it easy to use. My site is just photo and video archive of several users, with low traffic but several gigabytes of data. What would you suggest? Is it easier to get plone working on my box and start my instance(how?), or recover the content from the instance folder(how?) and setup another content management system(which?)

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  • Unzipping archives, preserving folder hierarchy

    - by Hydrangea
    I've got a problem and am not sure what it is, but hope someone can help me think this through because this has me stumped. Backstory: I wrote a Java app (Android) that unzips some zip files downloaded from the network. Until now, this was working great. Then, this week, the archives that I'm creating on my pc (in Ubuntu 12.04) unzip on the Android phone into a flat hierarchy instead of preserving the folders. I'm creating the archives the same way (right-click on folder compress) but even though my old archives (created in 10.04) still unzip as expected, the new ones don't. On Ubuntu, the new zip files look the same to me as the old ones. When unzipped on my pc the folders in these new archives are restored the same as the old ones... it's the Android app that extracts the old ones fine and the new ones flat. What I really want to know, though, is what the difference between the archives is. Question: How could one determine why one zip archive would be extracted with folder hierarchy preserved, when an identical one (to all appearances on Ubuntu 12.04) is extracted with no hierarchy? Are there different ways in which a .zip file can "have" folders, but Ubuntu doesn't distinguish between them?

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  • My rundll32.exe file is corrupt, how do I fix it?

    - by wahle509
    The other day I got a virus on my laptop (Windows XP), but Adaware found it and removed it. Not soon enough though, because it corrupted my rundll32.exe file. Now I can't run almost any application and I have tried to install a couple programs to fix my registry, but I can't even run the install file. What other options do I have besides re-installing my OS?

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  • Error in Apache: /var/run/apache2 not found

    - by Julen
    This is more self-answered question but since it drove me crazy I would like to share with the community and maybe someone can tell me why it happened or what it caused. The thing is I wanted to install in my Ubuntu 10.4 machine a CGI app, one built in the samples that come with the gSOAP toolkit. My intention was to access those from ASP .NET machine. Regular Ubuntu does not come with Apache so I install it from Sypnatic. Pretty easy. I followed this How to Install Apache2 webserver with PHP,CGI and Perl Support in Ubuntu Server. Instead of apache.conf I tweaked httpd.conf since a college here used that file instead of the first to put his Apache running. Besides I was able to access his CGI from my ASP .NET but mysteriously I could not from mine, I was getting always "The request failed with HTTP status 503: Service Temporarily Unavailable". Checking Apache error.log I found these messages: No such file or directory: unable to connect to cgi daemon after multiple tries: /home/julen/htdocs/cgi-bin/calcserver And looking more carefully whenever I restarted Apache I got this other message No such file or directory: Couldn't bind unix domain socket /var/run/apache2/cgisock. cgid daemon failed to initialize I am pretty new with Ubuntu and I could not think that Apache and Synaptic made a mistake in the installation process of the server, but it is true that the /var/run/apache2 was missing whereas in my college's computer was not. I tried to find and "elegant" solution but I found a post from 2006 that had an slight reference to it. Finally I decided to create the folder myself (as root) and then everything worked fine. Hope this helps others if they encounter a similar problem. Still I have the doubt why the folders was not created in the first place. Best, Julen.

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  • Run a batch file before user logs into Windows 2003 R2?

    - by Sid
    I have an Amazon EC2 machine (Windows Server 2003 R2) where I want to run a script (.bat file) when the Windows Server 2003 R2 machine boots up. This need to run BEFORE any user logs in. Ideally I'd like to extend the same work-around on my Windows Server 2008 R2 instances too - but Windows Server 2003 R2 is critical for me as of now. Purely as FYI, the .bat file updates the DDNS records so the EC2 machine doesn't need to consume static IPs.

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