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  • Invalid parameter number: number of bound variables does not match number of tokens

    - by Alex
    I have a table: 'objects' with few columns: object_id:int, object_type:int, object_status:int, object_lati:float, object_long:float My query is : $stmt = $db->query('SELECT o.object_id, o.object_type, o.object_status, o.object_lati, o.object_long FROM objects o WHERE o.object_id = 1'); $res = $stmt->fetch(); Pdo throw error: SQLSTATE[HY093]: Invalid parameter number: number of bound variables does not match number of tokens When i remove column object_lati or object_long query is work fine.

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  • Python and MySQLdb

    - by rohanbk
    I have the following query that I'm executing using a Python script (by using the MySQLdb module). conn=MySQLdb.connect (host = "localhost", user = "root",passwd = "<password>",db = "test") cursor = conn.cursor () preamble='set @radius=%s; set @o_lat=%s; set @o_lon=%s; '%(radius,latitude,longitude) query='SELECT *, 6371*1000 * acos(cos(radians(@o_lat)) * cos(radians(lat)) * cos(radians(lon) - radians(@o_lon)) + sin(radians(@o_lat)) * sin(radians(lat))) as distance FROM poi_table HAVING distance < @radius ORDER BY distance ASC LIMIT 0, 50' complete_query=preamble+query results=cursor.execute (complete_query) print results The values of radius, latitude, and longitude are not important, but they are being defined when the script executes. What bothers me is that the snippet of code above returns no results; essentially meaning that the way that the query is being executed is wonky. I executed the SQL query (including the set variables with actual values, and it returned the correct number of results). If I modify the query to just be a simple SELECT FROM query (SELECT * FROM poi_table) it returns results. What is going on here?

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  • Problem with SQL, ResultSet in java

    - by aphex
    How can I iterate ResultSet ? I've tried with the following code, but i get the error java.sql.SQLException: Illegal operation on empty result set. while ( !rs.isLast()) { rs.next(); int id = rs.getInt("person_id"); SQL.getInstance().getSt().execute("INSERT ref_person_pub(person_id) VALUES(" + id + ")"); }

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  • Looking for a good database structure to achieve Facebook/SO like notifications

    - by user156814
    I want to be able to have notifications on my site, similar to the way SO does it. I have looked for a good table structure to do this, but I cant seem to figure it out. I was thinking something like this. Notifications id, notification_type_id, user_id, type_id Notification Types id, notification_text Where the notification type would relate to either a new post, a new comment, or whatever features I add later down the line... User Id would relate to whoever the notification is for. Type_id and notification type would go hand in hand, so if the notification_type was a new comment, the type_id would be the comment_id to go to. This seems good to me, but i want to be able to notify ALL users when something changes.. like on facebook when you comment on something, you get a notification that someone else has also commented on the same thing after you. I cant seem to figure this out... Help wanted Thanks

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  • ON DELETE RESTRICT Causing Error 150

    - by Levi Hackwith
    CREATE TABLE project ( id INTEGER NOT NULL AUTO_INCREMENT, created_at DATETIME NOT NULL, name VARCHAR(75) NOT NULL, description LONGTEXT NOT NULL, is_active TINYINT NOT NULL DEFAULT '1', PRIMARY KEY (id), INDEX(name, created_at) ) ENGINE = INNODB; CREATE TABLE role ( id INTEGER NOT NULL, name VARCHAR(50) NOT NULL, description LONGTEXT NOT NULL, PRIMARY KEY (id) ) ENGINE = INNODB; CREATE TABLE organization ( id INTEGER NOT NULL AUTO_INCREMENT, created_at DATETIME NOT NULL, name VARCHAR(100) NOT NULL, is_active TINYINT NOT NULL DEFAULT '1', PRIMARY KEY (id) ) ENGINE = INNODB; CREATE TABLE user ( id INTEGER NOT NULL AUTO_INCREMENT, created_at DATETIME NOT NULL, role_id INTEGER NOT NULL, organization_id INTEGER NOT NULL, last_login_at DATETIME NOT NULL, last_ip_address VARCHAR(25) NOT NULL, username VARCHAR(45) NOT NULL, password CHAR(32) NOT NULL, email_address VARCHAR(255) NOT NULL, first_name VARCHAR(45) NOT NULL, last_name VARCHAR(45) NOT NULL, address_1 VARCHAR(100) NOT NULL, address_2 VARCHAR(25) NULL, city VARCHAR(25) NOT NULL, state CHAR(2) NOT NULL, zip_code VARCHAR(10) NOT NULL, primary_phone_number VARCHAR(10) NOT NULL, secondary_phone_number VARCHAR(10) NOT NULL, is_primary_organization_contact TINYINT NOT NULL DEFAULT '0', is_active TINYINT NOT NULL DEFAULT '1', PRIMARY KEY (id), CONSTRAINT fk_user_role_id FOREIGN KEY (role_id) REFERENCES role (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_user_organization_id FOREIGN KEY (organization_id) REFERENCES organization (id) ON UPDATE RESTRICT ON DELETE RESTRICT ) ENGINE = INNODB; CREATE TABLE project_user ( user_id INTEGER NOT NULL, project_id INTEGER NOT NULL, PRIMARY KEY (user_id, project_id), CONSTRAINT fk_project_user_user_id FOREIGN KEY (user_id) REFERENCES user (id) ON UPDATE RESTRICT ON DELETE CASCADE, CONSTRAINT fk_project_user_project_id FOREIGN KEY (project_id) REFERENCES project (id) ON UPDATE RESTRICT ON DELETE RESTRICT ) ENGINE = INNODB; CREATE TABLE ticket_category ( id INTEGER NOT NULL AUTO_INCREMENT, name VARCHAR(20) NOT NULL, description LONGTEXT NOT NULL, PRIMARY KEY (id) ) ENGINE = INNODB; CREATE TABLE ticket_type ( id INTEGER NOT NULL AUTO_INCREMENT, name VARCHAR(20) NOT NULL, description LONGTEXT NOT NULL, PRIMARY KEY (id) ) ENGINE = INNODB; CREATE TABLE ticket_status ( id INTEGER NOT NULL AUTO_INCREMENT, name VARCHAR(20) NOT NULL, description LONGTEXT NOT NULL, PRIMARY KEY (id) ) ENGINE = INNODB; CREATE TABLE ticket ( id INTEGER NOT NULL AUTO_INCREMENT, created_at DATETIME NOT NULL, project_id INTEGER NOT NULL, created_by INTEGER NOT NULL, submitted_by INTEGER NOT NULL, assigned_to INTEGER NULL, category_id INTEGER NOT NULL, type_id INTEGER NOT NULL, title VARCHAR(75) NOT NULL, description LONGTEXT NOT NULL, contact_type_id TINYINT NOT NULL, affects_all_clients TINYINT NOT NULL DEFAULT '0', is_billable TINYINT NOT NULL DEFAULT '1', esimated_hours DECIMAL(4, 1) NOT NULL DEFAULT '0', hours_worked DECIMAL (4, 1) NOT NULL DEFAULT '0', status_id TINYINT NOT NULL, PRIMARY KEY (id), CONSTRAINT fk_ticket_project_id FOREIGN KEY (project_id) REFERENCES project (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_created_by FOREIGN KEY (created_by) REFERENCES user (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_submitted_by FOREIGN KEY (submitted_by) REFERENCES user (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_assigned_to FOREIGN KEY (assigned_to) REFERENCES user (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_category_id FOREIGN KEY (category_id) REFERENCES ticket_category (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_type_id FOREIGN KEY (type_id) REFERENCES ticket_type (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_status_id FOREIGN KEY (status_id) REFERENCES ticket_status (id) ON UPDATE RESTRICT ON DELETE RESTRICT ) ENGINE = INNODB; CREATE TABLE ticket_time_entry ( id INTEGER NOT NULL AUTO_INCREMENT, user_id INTEGER NOT NULL, ticket_id INTEGER NOT NULL, started_at DATETIME NOT NULL, ended_at DATETIME NOT NULL, PRIMARY KEY (id), CONSTRAINT fk_ticket_time_entry_user_id FOREIGN KEY (user_id) REFERENCES user (id) ON UPDATE RESTRICT ON DELETE RESTRICT, CONSTRAINT fk_ticket_time_entry_ticket_id FOREIGN KEY (ticket_id) REFERENCES ticket (id) ON UPDATE RESTRICT ON DELETE RESTRICT ) ENGINE = INNODB; The ticket table's create statement causes an error 150. I have no clue why. When I remove the ON DELETE RESTRICT statements from the table declaration, it works. Why is that?

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  • In SQL, if we rename INNER JOIN as INTERSECT JOIN, LEFT OUTER JOIN as LEFT UNION JOIN, and FULL OUTE

    - by Jian Lin
    In SQL, the name Join gives an idea of "merging" or a sense of "union", making something bigger. But in fact, as in the other post http://stackoverflow.com/questions/2706051/in-sql-a-join-is-actually-an-intersection-and-it-is-also-a-linkage-or-a-sidew it turns out that a Join (Inner Join) is actually an Intersection. So if we think of Join = Inner Join = Intersect Join Left Outer Join = Left Union Join Full Outer Join = Full Union Join = Union Join then we always get a feel of what's happening, and maybe never forget what they are easily. In a way, we can think of Intersect as "making it less", therefore it is excluding something. That's why the name "Join" won't go with the idea of "Intersect". But in fact, both Intersect and Union can be thought of as: Union: bringing something together and merge them unconditionally. Intersect: bringing something together and merge them based on some condition. so the "bringing something together" is probably what "Join" is all about. It is like, Intersection is a "half glass of water" -- we can thinking of it as "excluding something" or as "bringing something together and accepting the common ones". So if the word "Intersect Join" is used, maybe a clear picture is there, and "Union Join" can be a clear picture too. Maybe the word "Inner Join" and "Outer Join" is very clear when we use SQL a lot. Somehow, the word "Outer" tends to give a feeling that it is "outside" and excluding something rather than a "Union".

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  • Non Working Relationship

    - by Dominik K.
    Hello everyone, I got a problem with cake's model architecture. I got a Users-Model and a Metas-Model. Here are the model codes: Users: <?php class User extends AppModel { var $name = 'User'; var $validate = array( 'username' => array('notempty'), 'email' => array('email'), 'password' => array('notempty') ); var $displayField = 'username'; var $hasMany = array( 'Meta' => array( 'className' => 'Meta', 'foreignKey' => 'user_id' ) ); } ?> and the Metas Model: <?php class Meta extends AppModel { var $name = 'Meta'; //The Associations below have been created with all possible keys, those that are not needed can be removed var $belongsTo = array( 'User' => array( 'className' => 'User', 'foreignKey' => 'user_id', 'required' => true ) ); } ?> So now the question is why do I not get the Meta data into the User array? Should I get it in the Auth object? Or where can I work with the meta data? hope you can help me! Have a nice Day! Dom

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  • Is it dangerous to keep an admin page to administer your database?

    - by Scarface
    Hey guys I have an admin page that checks if you are admin before submitting any queries, and contains a header to the index page if you are not admin, but I am worried about protecting the page. I am concerned someone may be able to destroy my database with it. Does anyone have any recommendation into protecting a page like this, if not, should I just manually admin my database through phpmyadmin and delete the page all together?

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  • does php mysql_fetch_array works with html input box?

    - by dexter
    this is my entire PHP code: <?php if(empty($_POST['selid'])) {echo "no value selected"; } else { $con = mysql_connect("localhost","root",""); if(mysql_select_db("cdcol", $con)) { $sql= "SELECT * FROM products where Id = '$_POST[selid]'"; if($result=mysql_query($sql)) { echo "<form name=\"updaterow\" method=\"post\" action=\"dbtest.php\">"; while($row = mysql_fetch_array($result)) { echo "Id :<input type=\"text\" name=\"ppId\" value=".$row['Id']." READONLY></input></br>"; echo "Name :<input type=\"text\" name=\"pName\" value=".$row['Name']."></input></br>"; echo "Description :<input type=\"text\" name=\"pDesc\" value=".$row['Description']."></input></br>"; echo "Unit Price :<input type=\"text\" name=\"pUP\" value=".$row['UnitPrice']."></input></br>"; echo "<input type=\"hidden\" name=\"mode\" value=\"Update\"/>"; } echo "<input type=\"submit\" value=\"Update\">"; echo "</form>"; } else {echo "Query ERROR";} } } ?> PROBLEM here is, ....if the value i am getting from database using mysql_fetch_array($result) is like:(say Description is:) "my product" then; in input box it shows only "my" the word(or digit) after "SPACE"(ie blank space) doesn't get displayed? can input box like above can display the data with two or more words(separated by blank spaces)?

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  • Linq for java

    - by Milhous
    Would a LINQ for java be a useful tool? I have been working on a tool that will allow a java object to map to a row in a database. Would this be useful for java programmers? What features would be useful?

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  • Join Query returns empty result, unexpected result

    - by Abs
    Hello all, Can anyone explain why this query returns an empty result. SELECT * FROM (`bookmarks`) JOIN `tags` ON `tags`.`bookmark_id` = `bookmarks`.`id` WHERE `tag` = 'clean' AND `tag` = 'simple' In my bookmarks table, I have a bookmark with an id of 70 and in my tags table i have two tags 'clean' and 'simple' both that have the column bookmark_id as 70. I would of thought a result would have been returned? How can I remedy this so that I have the bookmark returned when it has a tag of 'clean' and 'simple'? Thanks all for any explanation and solution to this.

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  • Why can't I get a TRUE return in this prepared statement?

    - by Cortopasta
    I can't seem to get this to do anything but return false. My best guess is that the prepared statement isn't executing, but I have no idea why. private function check_credentials($plain_username, $md5_password) { global $dbcon; $ac = new ac(); $ac->dbconnect(); $userid = $dbcon->prepare('SELECT id FROM users WHERE username = :username AND password = :password LIMIT 1'); $userid->bindParam(':username', $plain_username); $userid->bindParam(':password', $md5_password); $userid->execute(); $id = $userid->fetch(); Return $id; } *EDIT:*I've even tried hard coding the username and password into the function itself to try and isolate the problem like this: private function check_credentials($plain_username, $md5_password) { global $dbcon; $plain_username = "jim"; $md5_username = "waffles"; $ac = new ac(); $ac->dbconnect(); $userid = $dbcon->prepare('SELECT id FROM users WHERE username = :username AND password = :password LIMIT 1'); $userid->bindParam(':username', $plain_username); $userid->bindParam(':password', $md5_password); $userid->execute(); print_r($dbcon->errorInfo()); $id = $userid->fetch(); Return $id; } Still nothing :-/

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  • How do I delete a foreign key in SQLAlchemy?

    - by Travis
    I'm using SQLAlchemy Migrate to keep track of database changes and I'm running into an issue with removing a foreign key. I have two tables, t_new is a new table, and t_exists is an existing table. I need to add t_new, then add a foreign key to t_exists. Then I need to be able to reverse the operation (which is where I'm having trouble). t_new = sa.Table("new", meta.metadata, sa.Column("new_id", sa.types.Integer, primary_key=True) ) t_exists = sa.Table("exists", meta.metadata, sa.Column("exists_id", sa.types.Integer, primary_key=True), sa.Column( "new_id", sa.types.Integer, sa.ForeignKey("new.new_id", onupdate="CASCADE", ondelete="CASCADE"), nullable=False ) ) This works fine: t_new.create() t_exists.c.new_id.create() But this does not: t_exists.c.new_id.drop() t_new.drop() Trying to drop the foreign key column gives an error: 1025, "Error on rename of '.\my_db_name\#sql-1b0_2e6' to '.\my_db_name\exists' (errno: 150)" If I do this with raw SQL, i can remove the foreign key manually then remove the column, but I haven't been able to figure out how to remove the foreign key with SQLAlchemy? How can I remove the foreign key, and then the column?

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  • PHP Variable with Array

    - by Crays
    Hi guys, i'm trying to make a "update user's power" page. It is something similar to those you can find in say, invisionfree forums. I need it to generate a list of members with checkbox [done] Add an option for it [done] What i don't know how to do is to update, to say, give all the selected users the selected power. Then i went searching for something and found most of them uses array to do this, but i never found one that actually explains how it works. The example i took (with my own modification) was this: while($row = mysql_fetch_array($result)) { echo '<tr>'.$id[]=$rows['id'].''; echo '<td width="50px" align="center" class="TableFormCell"><input type="checkbox" name="option[]" /></td>'; echo '<td width="170px" align="center" class="TableFormCell">'.$row['uname'].'</td>'; echo '</tr>'; } I'm not sure what exactly $id[]=$rows['id'] does I know after the row, my option[] would become an array of option[1], option[2], option[3] for what power should be given, i've got no problem with that but on how to update the database i'm got no clue... for($i=0;$i<$count;$i++){ $sql1="UPDATE ninos SET power='$power' WHERE id='$option[$i]'"; $result1=mysql_query($sql1); } So Say i have 5 users, Aye, Bee, Cee, Dee, Eee with IDs of 1,2,3,4,5 how can i make it so that my script would run like $sql1="UPDATE ninos SET power = '$power' Where id='1','2','3','4','5'"; Please help, thanks.

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  • How to design tag database structure?

    - by liuxingruo
    I have a subjects database, and I want to create a new tag database to tag the subjects, but I have no idea how to design the new tag database structure. I'm assuming the new database looks like this: tag_id tag_name tagged_subject_ids 1 tag1 1, 2, 3, 5, 10 2 tag2 2, 4, 5, 6, 10, 12 so, if I want to select the tags belong to subject 1: SELECT tag_name FROM tag_database WHERE tagged_subject_ids LIKE '1'; I think the way that I select tag may be very slow, so please help me. Thanks!

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  • Mysqli query only works on localhost, not webserver

    - by whamo
    Hello. I have changed some of my old queries to the Mysqli framework to improve performance. Everything works fine on localhost but when i upload it to the webserver it outputs nothing. After connecting I check for errors and there are none. I also checked the php modules installed and mysqli is enabled. I am certain that it creates a connection to the database as no errors are displayed. (when i changed the database name string it gave the error) There is no output from the query on the webserver, which looks like this: $mysqli = new mysqli("server", "user", "password"); if (mysqli_connect_errno()) { printf("Can't connect Errorcode: %s\n", mysqli_connect_error()); exit; } // Query used $query = "SELECT name FROM users WHERE id = ?"; if ($stmt = $mysqli->prepare("$query")) { // Specify parameters to replace '?' $stmt->bind_param("d", $id); $stmt->execute(); // bind variables to prepared statement $stmt->bind_result($_userName); while ($stmt->fetch()) { echo $_userName; } $stmt-close(); } } //close connection $mysqli-close(); As I said this code works perfectly on my localserver just not online. Checked the error logs and there is nothing so everything points to a good connection. All the tables exists as well etc. Anyone any ideas because this one has me stuck! Also, if i get this working, will all my other queries still work? Or will i need to make them use the mysqli framework as well? Thanks in advance.

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  • SubSonic: MySqlDataReader closes connection.

    - by SchlaWiener
    I am using SubSonic 2.1 and entcountered a problem while executing a Transaction with SharedDbConnectionScope and TransactionScope. The problem is that in the obj.Save() method I get an "The connection must be valid and open" exception I tracked down the problem to this line: // Loads a SubSonic ActiveRecord object User user = new User(User.Columns.Username, "John Doe"); in this Constructor of the User class a method "LoadParam" is called which eventually does if (rdr != null) rdr.Close(); It looks like the rdr.Close() implicitly closes my connection which is fine when using the AutomaticConnection. But during a transaction it is usally not a good idea to close the connection :-) My Question is if this is by design or if it's an error in the MySqlDataReader.

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  • Google Maps - user to pinpoint a location

    - by JohnB
    Hi, Is it possible to allow users of my website to mark places on a map I display using Google Maps API? I need to then save that location coordinates to a db. I've been looking through the google maps API, I found that I can use the web service to do searches like this: http://maps.google.com/maps/geo?q=Maine,+United+States&output=json&oe=utf8\&sensor=false&key=my_key But I am not sure it's working on a house number level (which I need it to) and I'm not sure how to display a 'did you mean?' to the user when he misspells the address.. Anyone have an idea? Thanks,

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  • Grouping a query with php

    - by Tom Hoad
    Basic question! I have 2 tables FRUIT id | fruit_name ------------------- 1 | Apple 2 | Banana 3 | Carrot VARIETIES id | fk_fruit_id | variety_name --------------------------------------- 1 1 Cox 2 1 Braeburn 3 2 Chester 4 3 Kotaka 5 3 Imperial 6 3 Oneal I'd like to output a list of varieties per fruit e.g. APPLE - Cox, Braeburn BANANA - Chester CARROT - Kotaka, Imperial, Oneal My current code is $query = "SELECT * FROM produce, varieties WHERE produce.id = varieties.fk_fruit_id"; $result = mysql_query($query) or die('Error : ' . mysql_error()); while ($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $produce_fruit_code = $row['fruit_code']; $variety_name = $row['variety_name']; echo $produce_fruit_code.' - '.$variety_name.'<br/>'; } which outputs: Apple - Cox Apple - Braeburn Banana - Chester Carrot - Kotaka Carrot - Imperial Carrot - Oneal Not a million miles away, but still not there. Any help is much appreciated, thanks!

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  • What is the proper PHP syntax to post a file that exists in a directory that's on the server?

    - by ggg
    This is a basic post form in PHP that loads from the client PC. What is the proper syntax to load from a directory on the server? <form enctype="multipart/form-data" action="index.php?option=com_productionparse" method="POST"> <input type="hidden" name="MAX_FILE_SIZE" value="90000000000" /><br /> Choose a file to upload: <input name="file" size=120 type="file" /><br /> <input type="submit" value="Upload File" /> </form>

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  • Select number of rows for each group where two column values makes one group

    - by Fábio Antunes
    I have a two select statements joined by UNION ALL. In the first statement a where clause gathers only rows that have been shown previously to the user. The second statement gathers all rows that haven't been shown to the user, therefore I end up with the viewed results first and non-viewed results after. Of course this could simply be achieved with the same select statement using a simple ORDER BY, however the reason for two separate selects is simple after you realize what I hope to accomplish. Consider the following structure and data. +----+------+-----+--------+------+ | id | from | to | viewed | data | +----+------+-----+--------+------+ | 1 | 1 | 10 | true | .... | | 2 | 10 | 1 | true | .... | | 3 | 1 | 10 | true | .... | | 4 | 6 | 8 | true | .... | | 5 | 1 | 10 | true | .... | | 6 | 10 | 1 | true | .... | | 7 | 8 | 6 | true | .... | | 8 | 10 | 1 | true | .... | | 9 | 6 | 8 | true | .... | | 10 | 2 | 3 | true | .... | | 11 | 1 | 10 | true | .... | | 12 | 8 | 6 | true | .... | | 13 | 10 | 1 | false | .... | | 14 | 1 | 10 | false | .... | | 15 | 6 | 8 | false | .... | | 16 | 10 | 1 | false | .... | | 17 | 8 | 6 | false | .... | | 18 | 3 | 2 | false | .... | +----+------+-----+--------+------+ Basically I wish all non viewed rows to be selected by the statement, that is accomplished by checking weather the viewed column is true or false, pretty simple and straightforward, nothing to worry here. However when it comes to the rows already viewed, meaning the column viewed is TRUE, for those records I only want 3 rows to be returned for each group. The appropriate result in this instance should be the 3 most recent rows of each group. +----+------+-----+--------+------+ | id | from | to | viewed | data | +----+------+-----+--------+------+ | 6 | 10 | 1 | true | .... | | 7 | 8 | 6 | true | .... | | 8 | 10 | 1 | true | .... | | 9 | 6 | 8 | true | .... | | 10 | 2 | 3 | true | .... | | 11 | 1 | 10 | true | .... | | 12 | 8 | 6 | true | .... | +----+------+-----+--------+------+ As you see from the ideal result set we have three groups. Therefore the desired query for the viewed results should show a maximum of 3 rows for each grouping it finds. In this case these groupings were 10 with 1 and 8 with 6, both which had three rows to be shown, while the other group 2 with 3 only had one row to be shown. Please note that where from = x and to = y, makes the same grouping as if it was from = y and to = x. Therefore considering the first grouping (10 with 1), from = 10 and to = 1 is the same group if it was from = 1 and to = 10. However there are plenty of groups in the whole table that I only wish the 3 most recent of each to be returned in the select statement, and thats my problem, I not sure how that can be accomplished in the most efficient way possible considering the table will have hundreds if not thousands of records at some point. Thanks for your help. Note: The columns id, from, to and viewed are indexed, that should help with performance. PS: I'm unsure on how to name this question exactly, if you have a better idea, be my guest and edit the title.

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  • One table, need multiple values from different rows/tuples

    - by WmasterJ
    I have tables like: 'profile_values' userID | fid | value -------+---------+------- 1 | 3 | [email protected] 1 | 45 | 203-234-2345 3 | 3 | [email protected] 1 | 45 | 123-456-7890 And: 'users' userID | name -------+------- 1 | joe 2 | jane 3 | jake I want to join them and have one row with two of the values like: 'profile_values' userID | name | email | phone -------+-------+----------------+-------------- 1 | joe | [email protected] | 203-234-2345 2 | jane | [email protected] | 123-456-7890 I have solved it but it feels clumsy and I want to know if there is a better way to do it. Meaning solutions that are either more readable or faster(optimized) or simply best-practice. Current solution: multiple tables selected, many conditional statements: SELECT u.userID AS memberid, u.name AS first_name, pv1.value AS fname, pv2.value as lname FROM users AS u, profile_values AS pv1, profile_values AS pv2, WHERE u.userID = pv1.userID AND pv1.fid = 3 AND u.userID = pv2.userID AND pv2.fid = 45; Thanks for the help!

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  • useing my own db info to replace parts of a url and open in a iframe

    - by Morpheus Lucid
    print ("http://maps.google.com/maps/api/staticmap?center=");echo $City;print (",");echo $City;print (","); echo $State;print ("&zoom=14&size=500x500&maptype=roadmap&markers=color:blue|label:S|"); echo $Latitude;print (",");echo $Longitude;print ("&sensor=false")"); when page is loaded it prints right but would like to take the results from this and put into a iframe so when page loads it shows the map of the entry

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