Search Results

Search found 16355 results on 655 pages for 'lua c connection'.

Page 382/655 | < Previous Page | 378 379 380 381 382 383 384 385 386 387 388 389  | Next Page >

  • How can I split mySQL query logs by database?

    - by barnaby
    I've been trying to implement a mySQL Proxy solution that can separate out the queries into per-database logs. Everything I've Googled has pointed to mySQL Proxy but I can only seem to capture the database a connection was opened to, not which the current query is being issued against. Is it even possible? Is there a different tool to use? Thanks for any suggestions.

    Read the article

  • asp.net ajax calls stop browsing of sites page

    - by Ashian
    Hi, I have an ajax web application(asp.net). some of users report the a problemt that when they work sometimes by system ( and pages who have ajax calls) their connection to server will intrupt and just a blank page they will see. they can't browse any other page on my site while they close all open browsers and reopen site. Is there any idea about this and how can I fix it? thanks Mehdi

    Read the article

  • Invalid authorization specification error with Classic ASP accessing MSSQL DB

    - by Scott
    Hi, I am getting the following error: Invalid authorization specification I've narrowed down the error to my connection string. I have verified the server name, database, user & password are correct. Here is the string: "Provider=SQLOLEDB;Server=xxxxx.db.12345.hostedresource.com;Database=foo;UID=fooUser;PWD=fooPW" The SQL server is hosted on Godaddy so I don't have access to its settings. Please help, I've scoured the internet for a solution!

    Read the article

  • Why are these two sql statements deadlocking? (Deadlock graph + details included).

    - by Pure.Krome
    Hi folks, I've got the following deadlock graph that describes two sql statements that are deadlocking each other. I'm just not sure how to analyse this and then fix up my sql code to prevent this from happening. Main deadlock graph Click here for a bigger image. Left side, details Click here for a bigger image. Right side, details Click here for a bigger image. What is the code doing? I'm reading in a number of files (eg. lets say 3, for this example). Each file contains different data BUT the same type of data. I then insert data into LogEntries table and then (if required) I insert or delete something from the ConnectedClients table. Here's my sql code. using (TransactionScope transactionScope = new TransactionScope()) { _logEntryRepository.InsertOrUpdate(logEntry); // Now, if this log entry was a NewConnection or an LostConnection, then we need to make sure we update the ConnectedClients. if (logEntry.EventType == EventType.NewConnection) { _connectedClientRepository.Insert(new ConnectedClient { LogEntryId = logEntry.LogEntryId }); } // A (PB) BanKick does _NOT_ register a lost connection .. so we need to make sure we handle those scenario's as a LostConnection. if (logEntry.EventType == EventType.LostConnection || logEntry.EventType == EventType.BanKick) { _connectedClientRepository.Delete(logEntry.ClientName, logEntry.ClientIpAndPort); } _unitOfWork.Commit(); transactionScope.Complete(); } Now each file has it's own UnitOfWork instance (which means it has it's own database connection, transaction and repository context). So i'm assuming this means there's 3 different connections to the db all happening at the same time. Finally, this is using Entity Framework as the repository, but please don't let that stop you from having a think about this problem. Using a profiling tool, the Isolation Level is Serializable. I've also tried ReadCommited and ReadUncommited, but they both error :- ReadCommited: same as above. Deadlock. ReadUncommited: different error. EF exception that says it expected some result back, but got nothing. I'm guessing this is the LogEntryId Identity (scope_identity) value that is expected but not retrieve because of the dirty read. Please help! PS. It's Sql Server 2008, btw.

    Read the article

  • iphone sqlite app startup issues

    - by Futur
    Hi All, I have 4 database catalogues in my app, i will be switching the four catalogues. When i start the app, i read the NSUserDefaults and try to load the default catalogue in the memory, but in the first time this doesnt happen. Instead i get null values returned first time just because the DB connection is not successful for some unknown reason, the debugger is unable to go there too. But the app starts up the next time, the values are fetched successfully. Please help

    Read the article

  • QueryTables error

    - by ktm5124
    I have the following VBA code inside an Excel macro: With ActiveSheet.QueryTables.Add( _ Connection:=ConnStr, _ Destination:=ActiveSheet.Range("A1"), _ Sql:=SqlStr) .Refresh End With And yet I am getting the error: "Run-time error '1004': Application-defined or object-defined error." The debugger points to this code as the source of error. Assuming that my ConnStr and SqlStr are correct, why am I getting this error? I am using Excel 2007 and I am querying an Oracle database.

    Read the article

  • .NET datetime issue with SQL stored procedure

    - by DanO
    I am getting the below error when executing my application on a Windows XP machine with .NET 2.0 installed. On my computer Windows 7 .NET 2.0 - 3.5 I am not having any issues. The target SQL server version is 2005. This error started occurring when I added the datetime to the stored procedure. I have been reading alot about using .NET datetime with SQL datetime and I still have not figured this out. If someone can point me in the right direction I would appreciate it. Here is the where I believe the error is coming from. private static void InsertRecon(string computerName, int EncryptState, TimeSpan FindTime, Int64 EncryptSize, DateTime timeWritten) { SqlConnection DBC = new SqlConnection("server=server;UID=InventoryServer;Password=pass;database=Inventory;connection timeout=30"); SqlCommand CMD = new SqlCommand(); try { CMD.Connection = DBC; CMD.CommandType = CommandType.StoredProcedure; CMD.CommandText = "InsertReconData"; CMD.Parameters.Add("@CNAME", SqlDbType.NVarChar); CMD.Parameters.Add("@ENCRYPTEXIST", SqlDbType.Int); CMD.Parameters.Add("@RUNTIME", SqlDbType.Time); CMD.Parameters.Add("@ENCRYPTSIZE", SqlDbType.BigInt); CMD.Parameters.Add("@TIMEWRITTEN", SqlDbType.DateTime); CMD.Parameters["@CNAME"].Value = computerName; CMD.Parameters["@ENCRYPTEXIST"].Value = EncryptState; CMD.Parameters["@RUNTIME"].Value = FindTime; CMD.Parameters["@ENCRYPTSIZE"].Value = EncryptSize; CMD.Parameters["@TIMEWRITTEN"].Value = timeWritten; DBC.Open(); CMD.ExecuteNonQuery(); } catch (System.Data.SqlClient.SqlException e) { PostMessage(e.Message); } finally { DBC.Close(); CMD.Dispose(); DBC.Dispose(); } } Unhandled Exception: System.ArgumentOutOfRangeException: The SqlDbType enumeration value, 32, is invalid. Parameter name: SqlDbType at System.Data.SqlClient.MetaType.GetMetaTypeFromSqlDbType(SqlDbType target) at System.Data.SqlClient.SqlParameter.set_SqlDbType(SqlDbType value) at System.Data.SqlClient.SqlParameter..ctor(String parameterName, SqlDbType dbType) at System.Data.SqlClient.SqlParameterCollection.Add(String parameterName, SqlDbType sqlDbType) at ReconHelper.getFilesInfo.InsertRecon(String computerName, Int32 EncryptState, TimeSpan FindTime, Int64 EncryptSize, DateTime timeWritten) at ReconHelper.getFilesInfo.Main(String[] args)

    Read the article

  • How to connect laptop with telephone using WI-FI? (ethernet)

    - by rmaster
    What I did: 1)added new wireless network in wireless network settings and gave it SSID 2)gave laptop the IP like 192.168.0.1, mask: 255.255.255.0, gateway: 192.168.0.2 3)gave the telephone with wifi the same mask but IP and gateway rewersed But telephone can not find my new wireless network(it can find all other networks), computer also can not find it. where is error? how to make it visible and working? if my steps are wrong tell me correct way to establish this connection via wi-fi

    Read the article

  • Default MVC Web Application Database

    - by wows
    When setting up a new ASP.NET MVC Web Application, the default connection string inside Web.Config is something like this: connectionString="data source=.\SQLEXPRESS;Integrated Security=SSPI;AttachDBFilename=|DataDirectory|aspnetdb.mdf;User Instance=true" I'm just wanting to play around with logging in and registering, etc but when I run the app it obviously can't find a SQL database. What database with what tables do I need to setup to do this? I have SQL Server 2005 Standard installed on my system, is that enough? Thanks.

    Read the article

  • I cnn't use Database in SQL Azure!

    - by Nahid
    Hi, I am trying to use a Database in SQL AZURE. I have installed SQL Server 2008. I can Login SQL Azure and can use master Database. But I can't use other Database and I can't see any things in my object explorer. Its Show Error: "USE statement is not supported to switch between databases. Use a new connection to connect to a different Database." How can I use other database?

    Read the article

  • Why the parent page get refreshed when I click the link to open thickbox-styled form?

    - by user333205
    Hi, all: I'm using Thickbox 3.1 to show signup form. The form content comes from jquery ajax post. The jquery lib is of version 1.4.2. I placed a "signup" link into a div area, which is a part of my other large pages, and the whole content of that div area is ajax+posted from my server. To make thickbox can work in my above arangement, I have modified the thickbox code a little like that: //add thickbox to href & area elements that have a class of .thickbox function tb_init(domChunk){ $(domChunk).live('click', function(){ var t = this.title || this.name || null; var a = this.href || this.alt; var g = this.rel || false; tb_show(t,a,g); this.blur(); return false; });} This modification is the only change against the original version. Beacause the "signup" link is placed in ajaxed content, so I Use live instead of binding the click event directly. When I tested on my pc, the thickbox works well. I can see the signup form quickly, without feeling the content of the parent page(here, is the other large pages) get refreshed. But after transmiting my site files into VHost, when I click the "signup" link, the signup form get presented very slowly. The large pages get refreshed evidently, because the borwser(ie6) are reloading images from server incessantly. These images are set as background images in CSS files. I think that's because the slow connection of network. But why the parent pages get refreshed? and why the browser reloads those images one more time? Havn't those images been placed in local computer's disk? Is there one way to stop that reloadding? Because the signup form can't get displayed sometimes due to slow connection of network. To verified the question, you can access http://www.juliantec.info/track-the-source.html and click the second link in left grey area, that is the "signup" link mentioned above. Thinks!

    Read the article

  • timeout stringwithcontentsofurl

    - by sergiobuj
    Hi, I have this call to stringwithcontentsofurl: [NSString stringWithContentsOfURL:url usedEncoding:NSASCIIStringEncoding error:nil]; How can I give that a simple timeout? I don't want to use threads or operation queues (the content of the url is about 100 characters), I just don't want to wait too long when the connection is slow.

    Read the article

  • cannot access sql server after publishing site in iis7

    - by vinu
    I am created a website using visual studio 2010. On the time of the development of website I am able to access the database.. but after publishing the site using IIS7..i was unable to access the database..the exception occured during that time was "the connection is in the closed state".in IIS7 When I changed the application pool identity to localsystem, it worked. Data base is installed in the same machine. and server is SQL SERVER 2008 R2

    Read the article

  • PHP syntax error “unexpected $end”

    - by Jacksta
    I have 3 files 1) show_createtable.html 2) do_showfielddef.php 3) do_showtble.php 1) First file is for creating a new table for a data base, it is a fom with 2 inputs, Table Name and Number of Fields. THIS WORKS FINE! <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <h1>Step 1: Name and Number</h1> <form method="post" action="do_showfielddef.php" /> <p><strong>Table Name:</strong><br /> <input type="text" name="table_name" size="30" /></p> <p><strong>Number of fields:</strong><br /> <input type="text" name="num_fields" size="30" /></p> <p><input type="submit" name="submit" value="go to step2" /></p> </form> </body> </html> 2) this script validates fields and createa another form to enter all the table rows. This for also WORKS FINE! <?php //validate important input if ((!$_POST[table_name]) || (!$_POST[num_fields])) { header( "location: show_createtable.html"); exit; } //begin creating form for display $form_block = " <form action=\"do_createtable.php\" method=\"post\"> <input name=\"table_name\" type=\"hidden\" value=\"$_POST[table_name]\"> <table cellspacing=\"5\" cellpadding=\"5\"> <tr> <th>Field Name</th><th>Field Type</th><th>Table Length</th> </tr>"; //count from 0 until you reach the number fo fields for ($i = 0; $i <$_POST[num_fields]; $i++) { $form_block .=" <tr> <td align=center><input type=\"texr\" name=\"field name[]\" size=\"30\"></td> <td align=center> <select name=\"field_type[]\"> <option value=\"char\">char</option> <option value=\"date\">date</option> <option value=\"float\">float</option> <option value=\"int\">int</option> <option value=\"text\">text</option> <option value=\"varchar\">varchar</option> </select> </td> <td align=center><input type=\"text\" name=\"field_length[]\" size=\"5\"> </td> </tr>"; } //finish up the form $form_block .= " <tr> <td align=center colspan=3><input type =\"submit\" value=\"create table\"> </td> </tr> </table> </form>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create a database table: Step 2</title> </head> <body> <h1>defnie fields for <? echo "$_POST[table_name]"; ?> </h1> <? echo "$form_block"; ?> </body> </html> Problem is here 3) this form creates the tables and enteres them into the database. I am getting an error on line 37 "Parse error: syntax error, unexpected $end in /home/admin/domains/domaina.com.au/public_html/do_createtable.php on line 37" <? $db_name = "testDB"; $connection = @mysql_connect("localhost", "admin_user", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "CREATE TABLE $_POST[table_name]("; for ($i = 0; $i < count($_POST[field_name]); $i++) { $sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i]; if ($_POST[field_length][$i] !="") { $sql .=" (".$_POST[field_length][$i]."),"; } else { $sql .=","; } $sql = substr($sql, 0, -1); $sql .= ")"; $result = mysql_query($sql, $connection) or die(mysql_error()); if ($result) { $msg = "<p>" .$_POST[table_name]." has been created!</p>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create A Database Table: Step 3</title> </head> <body> <h1>Adding table to <? echo "$db_name"; ?>...</h1> <? echo "$msg"; ?> </body> </html>

    Read the article

  • Script to create a table and fields in SQL wont work

    - by Jacksta
    Warning this is lenghty! attack if you knowledagble. well at least more then a newb beginner like me. This script uses three files as detailed below. It is suppoed to create the database and fields from the form input. It gets to the end and shows my_contacts has been created!. But when i go into phpMyadmin the table has not been created. I have a file named show_createtable.html which is used to create a table in MySQL <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <h1>Step 1: Name and Number</h1> <form method="post" action="do_showfielddef.php" /> <p><strong>Table Name:</strong><br /> <input type="text" name="table_name" size="30" /></p> <p><strong>Number of fields:</strong><br /> <input type="text" name="num_fields" size="30" /></p> <p><input type="submit" name="submit" value="go to step2" /></p> </form> </body> </html> This Form Posts to do_showfielddef.php <?php //validate important input if ((!$_POST[table_name]) || (!$_POST[num_fields])) { header( "location: show_createtable.html"); exit; } //begin creating form for display $form_block = " <form action=\"do_createtable.php\" method=\"post\"> <input name=\"table_name\" type=\"hidden\" value=\"$_POST[table_name]\"> <table cellspacing=\"5\" cellpadding=\"5\"> <tr> <th>Field Name</th><th>Field Type</th><th>Table Length</th><th>Primary Key?</th><th>Auto-Increment?</th> </tr>"; //count from 0 until you reach the number fo fields for ($i = 0; $i <$_POST[num_fields]; $i++) { $form_block .=" <tr> <td align=center><input type=\"texr\" name=\"field name[]\" size=\"30\"></td> <td align=center> <select name=\"field_type[]\"> <option value=\"char\">char</option> <option value=\"date\">date</option> <option value=\"float\">float</option> <option value=\"int\">int</option> <option value=\"text\">text</option> <option value=\"varchar\">varchar</option> </select> </td> <td align=center><input type=\"text\" name=\"field_length[]\" size=\"5\"></td> <td aligh=center><input type=\"checkbox\" name=\"primary[]\" value=\"Y\"></td> <td aligh=center><input type=\"checkbox\" name=\"auto_increment[]\" value=\"Y\"></td> </tr>"; } //finish up the form $form_block .= " <tr> <td align=center colspan=3><input type =\"submit\" value=\"create table\"> </td> </tr> </table> </form>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create a database table: Step 2</title> </head> <body> <h1>defnie fields for <? echo "$_POST[table_name]"; ?> </h1> <? echo "$form_block"; ?> </body> </html> Which in turn creates the table and fields with this file do_showfielddef.php //connect to database $connection = @mysql_connect("localhost", "user", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); //start creating the SQL statement $sql = "CREATE TABLE $_POST[table_name]("; //continue the SQL statement for each new field for ($i = 0; $i < count($_POST[field_name]); $i++) { $sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i]; if ($_POST[auto_increment][$i] =="Y") { $additional = "NOT NULL auto_increment"; } else { $additional = ""; } if ($_POST[primary][$i] =="Y") { $additional .= ", primary key (".$_POST[field_name][$i].")"; } else { $additional = ""; } if ($_POST[field_length][$i] !="") { $sql .= " (".$_POST[field_length][$i].") $additional ,"; } else { $sql .=" $additional ,"; } } //clean up the end of the string $sql = substr($sql, 0, -1); $sql .= ")"; //execute the query $result = mysql_query($sql, $connection) or die(mysql_error()); //get a giid message for display upon success if ($result) { $msg = "<p>" .$_POST[table_name]." has been created!</p>"; } ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create A Database Table: Step 3</title> </head> <body> <h1>Adding table to <? echo "$db_name"; ?>...</h1> <? echo "$msg"; ?> </body> </html>

    Read the article

  • Add subview to another view

    - by Martol1ni
    With two ViewControllers, MyView 1 and MyView 2, is there possible to add a subview to MyView2 from MyView1.m? I have tried: MyView2 * screen = [[MyView2 alloc]initWithNibName:nil bundle:nil]; [screen.view addSubView:mySubView]; But my new instance of MyView 2 has no connection to the 'visible' ViewController on MyView2, right? To clarify, the ViewController that is showing, is MyView1. I want MyView1 to be able to add a subview to the MyView2 view. Thanks

    Read the article

  • Integration Services Throws an Error Reading Access 2007 Table

    - by Eric Flamm
    [Participant Table [1994]] Error: SSIS Error Code DTS_E_CANNOTACQUIRECONNECTIONFROMCONNECTIONMANAGER. The AcquireConnection method call to the connection manager "I:\My Documents\Flamm Consulting\Migrations.accdb" failed with error code 0xC0209303. There may be error messages posted before this with more information on why the AcquireConnection method call failed. Frankly, I'm confused about how SSIS should connect to Access 2007 - the UI just isn't very friendly - there's no file browser, for example. I'm wondering if there's something wrong with my install - missing drivers, etc.

    Read the article

  • PHP apache_request_headers() diagrees with reality (as confirmed by Firebug): why?

    - by Peter Howe
    I have written a web app in PHP which makes use of Ajax requests (made using YUI.util.Connect.asyncRequest). Most of the time, this works fine. The request is sent with an X-Requested-With value of XMLHttpRequest. My PHP controller code uses apache_request_headers() to check whether an incoming request is Ajax or not and all works well. But not always. Intermittently, I'm getting a situation where the Ajax request is sent (and Firebug confirms for me that the headers on the request include an X-Requested-With of XMLHttpRequest) but apache_request_headers() is not returning that header in its list. The output from when I var_dump the apache_request_headers() is as follows (note the lack of X- 'Host' => string 'peterh.labs.example.com' (length=26) 'User-Agent' => string 'Mozilla/5.0 (X11; U; Linux i686; en-GB; rv:1.9.0.3) Gecko/2008101315 Ubuntu/8.10 (intrepid) Firefox/3.0.3' (length=105) 'Accept' => string 'text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8' (length=63) 'Accept-Language' => string 'en-gb,en;q=0.5' (length=14) 'Accept-Encoding' => string 'gzip,deflate' (length=12) 'Accept-Charset' => string 'ISO-8859-1,utf-8;q=0.7,*;q=0.7' (length=30) 'Keep-Alive' => string '300' (length=3) 'Connection' => string 'keep-alive' (length=10) 'Referer' => string 'http://peterh.labs.example.com/qmail/' (length=40) 'Cookie' => string 'WORKFLOW_SESSION=55f9aff2051746851de453c1f776ad10745354f6' (length=57) 'Pragma' => string 'no-cache' (length=8) 'Cache-Control' => string 'no-cache' (length=8) But Firebug tells me: Request Headers: Host peterh.labs.example.com User-Agent Mozilla/5.0 (X11; U; Linux i686; en-GB; rv:1.9.0.3) Gecko/2008101315 Ubuntu/8.10 (intrepid) Firefox/3.0.3 Accept text/html,application/xhtml+xml,application/xml;q=0.9,**;q=0.8 Accept-Language en-gb,en;q=0.5 Accept-Encoding gzip,deflate Accept-Charset ISO-8859-1,utf-8;q=0.7,*;q=0.7 Keep-Alive 300 Connection keep-alive X-Requested-With XMLHttpRequest Referer http://peterh.labs.example.com/qmail/ Cookie WORKFLOW_SESSION=55f9aff2051746851de453c1f776ad10745354f6 This mismatch is (apparently) intermittent when executing the same code. But I don't believe in "intermittent" when it comes to software! Help!

    Read the article

  • NHibernate unable to create SessionFactory

    - by Tyler
    I'm having a bit of trouble setting up NHibernate, and I'm not too sure what the problem is exactly. I'm attempting to save a domain object to the database (Oracle 10g XE). However, I'm getting a TypeInitializationException while trying to create the ISessionFactory. Here is what my hibernate.cfg.xml looks like: <?xml version="1.0" encoding="utf-8"?> <hibernate-configuration xmlns="urn:nhibernate-configuration-2.2" > <session-factory name="MyProject.DataAccess"> <property name="connection.driver_class">NHibernate.Driver.OracleClientDriver</property> <property name="connection.connection_string"> User ID=myid;Password=mypassword;Data Source=localhost </property> <property name="show_sql">true</property> <property name="dialect">NHibernate.Dialect.OracleDialect</property> <property name="proxyfactory.factory_class">NHibernate.ByteCode.LinFu.ProxyFactoryFactory, NHibernate.ByteCode.LinFu</property> <mapping resource="MyProject/Domain/User.hbm.xml"/> </session-factory> </hibernate-configuration> I created a DAO which I will use to persist domain objects to the database. The DAO uses a HibernateUtil class that creates the SessionFactory. Both classes are in the DataAccess namespace along with the Hibernate configuration. This is where the exception is occuring. Here's that class: public class HibernateUtil { private static ISessionFactory SessionFactory = BuildSessionFactory(); private static ISessionFactory BuildSessionFactory() { try { // This seems to be where the problem occurs return new Configuration().Configure().BuildSessionFactory(); } catch (TypeInitializationException ex) { Console.WriteLine("Initial SessionFactory creation failed." + ex); throw new Exception("Unable to create SessionFactory."); } } public static ISessionFactory GetSessionFactory() { return SessionFactory; } } The DataAccess namespace references the NHibernate DLLs. This is virtually the same setup I've used with Hibernate in Java, so I'm not entirely sure what I'm doing wrong here. Any ideas? Edit The innermost exception is the following: "Could not find file 'C:\Users\Tyler\Documents\Visual Studio 2010\Projects\MyProject\MyProject\ConsoleApplication\bin\Debug\hibernate.cfg.xml'." ConsoleApplication contains the entry point where I've created a User object and am trying to persist it with my DAO. Why is it looking for the configuration file there? The actual persisting takes place in the DAO, which is in DataAccess. Also, when I add the configuration file to ConsoleApplication, it still does not find it.

    Read the article

< Previous Page | 378 379 380 381 382 383 384 385 386 387 388 389  | Next Page >