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  • Improving the speed of php

    - by cast01
    I'm currently working on a website in PHP, and I'm wondering what the best practices/methods are to reduce the time requests take. I've build the site in a modular way, so a page would consist of a number of modules, and each of these would need to request information. For example, I have a cart module, that (if a cart is set) will fetch the cart with the id (stored in a session variable) from the database and return its contents. I have another module that lists categories and this needs to fetch the categories from the database. My system is built with models, and each model might also make a request, for example a category model will make a request to get products in that category.

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  • Drupal Views pulling Data Fields

    - by askon
    I'm a little new to drupal but have been using things like devel module and theme developer to speed up the learning process. My question, is it possible to theme an entire views BLOCK from a single views tpl.php page OR even a preprocess? When I'm grabbing the $view object I can see results $node-result, it has all of the results, but it doesn't have all my views fields. I'm missing things like, node path, taxonomy titles and paths, etc. From my understanding, Drupal wants you to individually theme EACH output field. It seems rather superfluous to create so many extra templates when I've already got over HALF of my results coming through the $view object Would outputting node over field make this easier? Or am going in the wrong direction with $view-result? Thanks!

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  • i demand you all men to help

    - by Hello you all men
    you all men i demand answer, you say not real question?? many page get big load for long time and now we are suspended and http://stackoverflow.com/questions/2890840/how-can-we-make-our-website-scalable and please you help men very sorry -bern

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  • Modifying my website to allow anonymous comments

    - by David
    I write the code for my own website as an educational/fun exercise. Right now part of the website is a blog (like every other site out there :-/) which supports the usual basic blog features, including commenting on posts. But I only have comments enabled for logged-in users; I want to alter the code to allow anonymous comments - that is, I want to allow people to post comments without first creating a user account on my site, although there will still be some sort of authentication involved to prevent spam. Question: what information should I save for anonymous comments? I'm thinking at least display name and email address (for displaying a Gravatar), and probably website URL because I eventually want to accept OpenID as well, but would anything else make sense? Other question: how should I modify the database to store this information? The schema I have for the comment table is currently comment_id smallint(5) // The unique comment ID post_id smallint(5) // The ID of the post the comment was made on user_id smallint(5) // The ID of the user account who made the comment comment_subject varchar(128) comment_date timestamp comment_text text Should I add additional fields for name, email address, etc. to the comment table? (seems like a bad idea) Create a new "anonymous users" table? (and if so, how to keep anonymous user ids from conflicting with regular user ids) Or create fake user accounts for anonymous users in my existing users table? Part of what's making this tricky is that if someone tries to post an anonymous comment using an email address (or OpenID) that's already associated with an account on my site, I'd like to catch that and prompt them to log in.

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  • Databases design - one link table or multiple link tables?

    - by David
    Hi there, I'm working on a front end for a database where each table essentially has a many to many relationship with all other tables. I'm not a DB admin, just a few basic DB courses. The typical solution in this case, as I understand it, would be multiple link tables to join each 'real' table. Here's what I'm proposing instead: one link table that has foreign key dependencies to all other PKs of the other tables. Is there any reason this could turn out badly in terms of scalability, flexibility, etc down the road?

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  • How to handle multiple openIDs for the same user

    - by Sinan
    For my site I am using a login system much like the one on SO. A user can login with his Facebook, Google (Gmail openID), Twitter account. This question is not about specific oAuth or openID implementations. The question is how to know if the same user logins with different providers. Let me give an example: Bobo comes to site logins to site by clicking on "Login with Facebook". Because this is his first visit we create an account for him. Later Bobo comes to the site. This time he clicks on "Login with Google". So how do I know if this is the same person so I can add this provider to his account instead of creating a new (and duplicate) account. Can I trust solely on email? What is the best way to handle this. How does SO do it? Any ideas?

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  • Audit Table using Triggers

    - by Jose
    DROP TABLE IF EXISTS `actividades`.`act_actividad_audit`; CREATE TABLE `actividades`.`act_actividad_audit` ( `fe_creacion` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP ON UPDATE CURRENT_TIMESTAMP, `usr_digitador` char(10) NOT NULL, `ip_digitador` char(15) NOT NULL, `id_act_actividad` int(10) unsigned NOT NULL, `titulo` char(64) NOT NULL, `act_prioridad_id` int(10) unsigned NOT NULL, `act_motivo_id` int(10) unsigned NOT NULL, `detalle` text, `detalle_tecnico` text, `hostname_id` int(10) unsigned NOT NULL, `hostname_nombre` char(50) NOT NULL, `es_SMOP` tinyint(1) NOT NULL, `url_SMOP` text, `es_tecnico` tinyint(1) NOT NULL ) ENGINE=InnoDB DEFAULT CHARSET=latin1 COMMENT='Auditoria Actividad General'; I want to populate that audit table with a trigger but how can i send or fill the values for usr_digitador or ip_digitador if that values are on client side.? please help

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  • How to display external database data in VBulletin 4 Forums Custom PHP Block?

    - by NJTechGuy
    Hi guys! I want to display data feed from an external database in a sidebar in the forums section. PHP Block Code : $host = 'db.123.net'; $dbUser = 'db49'; $dbPass = 'iReVbY'; $db = 'db6578h8'; mysql_connect("$host", "$dbUser", "$dbPass") or die(mysql_error()); mysql_select_db("$db") or die(mysql_error()); ob_start(); $result = mysql_query("SELECT id, title from abc") or die(mysql_error()); while($row = mysql_fetch_array( $result )) { print"<center>"; print "<a href=\"http://abc.com/?id=" . $row['id'] . "\"></a>"; print "</center>"; } $output .= ob_get_contents(); return $output; ob_end_clean(); How do I return an array to display in a PHP block in the sidebar (forums section)? Please help me out of this! Thank you..

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  • How can "set timestamp" be a slow query?

    - by Peder
    My slow query log is full of entries like the following # Query_time: 1.016361 Lock_time: 0.000000 Rows_sent: 0 Rows_examined: 0 SET timestamp=1273826821; COMMIT; I guess the set timestamp command is issued by replication but I don't understand how set timestamp can take over a second. Any ideas?

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  • Cast integer to real

    - by Dave Jarvis
    Question How do you cast an INTEGER value as a REAL value? Attempts CAST( Y.YEAR AS REAL), but that failed (the documentation indicates you cannot CAST or CONVERT values to REALs. Y.YEAR + 0.0, but that failed, too. Error Message Using udf_slope fails due to: Can't initialize function 'slope'; slope() requires a real as parameter 2 Code SELECT D.AMOUNT, Y.YEAR, slope(D.AMOUNT, Y.YEAR + 0.0) as SLOPE, intercept(D.AMOUNT, Y.YEAR + 0.0) as INTERCEPT FROM YEAR_REF Y, DAILY D Here, D.AMOUNT is a FLOAT and Y.YEAR is an INTEGER. Thank you!

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  • How would I UPDATE these table entries with SQL and PHP?

    - by CT
    I am working on an Asset Database problem. I enter assets into a database. Every object is an asset and has variables within the asset table. An object is also a type of asset. In this example the type is server. Here is the Query to retrieve all necessary data: SELECT asset.id ,asset.company ,asset.location ,asset.purchaseDate ,asset.purchaseOrder ,asset.value ,asset.type ,asset.notes ,server.manufacturer ,server.model ,server.serialNumber ,server.esc ,server.warranty ,server.user ,server.prevUser ,server.cpu ,server.memory ,server.hardDrive FROM asset LEFT JOIN server ON server.id = asset.id WHERE asset.id = '$id' I then assign all results into single php variables. How would I write a query/script to update an asset?

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  • Why does my Doctrine DBAL query return no results when quoted?

    - by braveterry
    I'm using the Doctrine DataBase Abstraction Layer (DBAL) to perform some queries. For some reason, when I quote a parameter before passing it to the query, I get back no rows. When I pass it unquoted, it works fine. Here's the relevant snippet of code I'm using: public function get($game) { load::helper('doctrinehelper'); $conn = doctrinehelper::getconnection(); $statement = $conn->prepare('SELECT games.id as id, games.name as name, games.link_url, games.link_text, services.name as service_name, image_url FROM games, services WHERE games.name = ? AND services.key = games.service_key'); $quotedGame = $conn->quote($game); load::helper('loghelper'); $logger = loghelper::getLogger(); $logger->debug("Quoted Game: $quotedGame"); $logger->debug("Unquoted Game: $game"); $statement->execute(array($quotedGame)); $resultsArray = $statement->fetchAll(); $logger->debug("Number of rows returned: " . count($resultsArray)); return $resultsArray; } Here's what the log shows: 01/01/11 17:00:13,269 [2112] DEBUG root - Quoted Game: 'Diablo II Lord of Destruction' 01/01/11 17:00:13,269 [2112] DEBUG root - Unquoted Game: Diablo II Lord of Destruction 01/01/11 17:00:13,270 [2112] DEBUG root - Number of rows returned: 0 If I change this line: $statement->execute(array($quotedGame)); to this: $statement->execute(array($game)); I get this in the log: 01/01/11 16:51:42,934 [2112] DEBUG root - Quoted Game: 'Diablo II Lord of Destruction' 01/01/11 16:51:42,935 [2112] DEBUG root - Unquoted Game: Diablo II Lord of Destruction 01/01/11 16:51:42,936 [2112] DEBUG root - Number of rows returned: 1 Have I fat-fingered something?

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  • SQL joining 3 tables when 1 table is emty

    - by AdRock
    I am trying to write a query that connects 3 tables. The first table is info about each festival The second table is the number of votes for each festival The third table is reviews for each festival I want to join all 3 tables so i get all the feilds from table1, join table1 with table2 on the festivalid but i also need to count the number of records in table 3 that applys to each festival. The first 2 tables give me a result becuase they both have data in them but table 3 is empty becuase there are no reviews yet so adding that to my query fives me no results SELECT f.*, v.total, v.votes, v.festivalid, r.reviewcount as count FROM festivals f INNER JOIN vote v ON f.festivalid = v.festivalid INNER JOIN (SELECT festivalid, count(*) as reviewcount FROM reviews) GROUP BY festivalid) as r on r.festivalid = v.festivalid

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  • again new query. i am trying to solve this from one hour. please help

    - by Dharmendra
    Query : List the film title and the leading actor for all of 'Julie Andrews' films. there are three tables : movie(id, title, yr, score, votes, director) actor(id, name) casting(movieid, actorid, ord) select movie.title,actor.name as cont from movie join casting on (movie.id=casting.movieid) join actor on (casting.actorid=actor.id) where actor.name='Julie andrews' actually i can' get how to find the leading actor.

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  • Should I include user_id in multiple tables?

    - by Drarok
    I'm at the planning stages of a multi-user application where each user will only have access their own data. There'll be a few tables that relate to each other, so I could use JOINs to ensure they're accessing only their data, but should I include user_id in each table? Would this be faster? It would certainly make some of the queries easier in the long run. Thanks!

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  • SQL Count Query with Grouping by multiple Columns

    - by Christian
    I have a table with three filled columns named "Name", "City" and "Occupation". I want to create a new column in the same table that contains the number of people who have the same occupation. "Name" | "City" | "Occupation" ------------------------------ Amy | Berlin | Plumber Bob | Berlin | Plumber Carol | Berlin | Lawyer David | London | Plumber I want to have a table that contains: "Name" | "City" | "Occupation" | "Number" --------------------------------------- Amy | Berlin | Plumber | 2 Bob | Berlin | Plumber | 2 Carol | Berlin | Lawyer | 1 David | London | Plumber | 1 How does the SQL Query that creates the new columns have to look like? I want to actually create a new column in the database that I can access later.

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  • How to write stored procedures to separate files with mysqldump?

    - by Jader Dias
    The mysqldump option --tab=path writes the creation script of each table in a separate file. But I can't find the stored procedures, except in the screen dump. I need to have the stored procedures also in separate files. The current solution I am working on is to split the screen dump programatically. Is there a easier way? The code I am using so far is: mysqldump -p$PASSWORD --routines --skip-dump-date --no-create-info --no-data --skip-opt $DATABASE > $BACKUP_PATH/$DATABASE.sql mysqldump -p$PASSWORD --tab=$BACKUP_PATH --skip-dump-date --no-data --skip-opt $DATABASE

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  • How can I protect this code from SQL Injection? A bit confused.

    - by Craig Whitley
    I've read various sources but I'm unsure how to implement them into my code. I was wondering if somebody could give me a quick hand with it? Once I've been shown how to do it once in my code I'll be able to pick it up I think! This is from an AJAX autocomplete I found on the net, although I saw something to do with it being vulnerable to SQL Injection due to the '%$queryString%' or something? Any help really appreciated! if ( isset( $_POST['queryString'] ) ) { $queryString = $_POST['queryString']; if ( strlen( $queryString ) > 0 ) { $query = "SELECT game_title, game_id FROM games WHERE game_title LIKE '%$queryString%' || alt LIKE '%$queryString%' LIMIT 10"; $result = mysql_query( $query, $db ) or die( "There is an error in database please contact [email protected]" ); while ( $row = mysql_fetch_array( $result ) ) { $game_id = $row['game_id']; echo '<li onClick="fill(\'' . $row['game_title'] . '\',' . $game_id . ');">' . $row['game_title'] . '</li>'; } } }

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  • Do a query only if there are no results on previous query

    - by yes123
    Hi guys: I do this query(1): (1)SELECT * FROM t1 WHERE title LIKE 'key%' LIMIT 1 I need to do a second(2) query only if this previous query has no results (2)SELECT * FROM t1 WHERE title LIKE '%key%' LIMIT 1 basically i need only 1 row who got the most close title to my key. Atm i am using an UNION query with a custom field to order it and a LIMIT 1. Problem is I don't want to do the others query if already the first made the result. Thanks

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  • Access 2007 file picker, replaces all rows with the same choice.

    - by SqlStruggle
    This code is from an Access 2007 project I've been struggling with. The actual mean part is the part where I should put something like "update only current form" DoCmd.RunSQL "Update Korut Set [PikkuKuva]=('" & varFile & "') ;" Could someone please help me with this?` If I use it now, it updates all the tables with the same file picked. Heres the whole code. ' This requires a reference to the Microsoft Office 11.0 Object Library. Dim fDialog As Office.FileDialog Dim varFile As Variant Dim filePath As String ' Set up the File dialog box. Set fDialog = Application.FileDialog(msoFileDialogFilePicker) With fDialog ' Allow the user to make multiple selections in the dialog box. .AllowMultiSelect = False ' Set the title of the dialog box. .Title = "Valitse Tiedosto" ' Clear out the current filters, and then add your own. .Filters.Clear .Filters.Add "All Files", "*.*" ' user picked at least one file. If the .Show method returns ' False, the user clicked Cancel. If .Show = True Then ' Loop through each file that is selected and then add it to the list box. For Each varFile In .SelectedItems DoCmd.SetWarnings True DoCmd.RunSQL "Update Korut Set [PikkuKuva]=('" & varFile & "') ;" Next Else MsgBox "You clicked Cancel in the file dialog box." End If End With

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  • Make A HTML/PHP Link

    - by Will Evans
    I have the code below: $result = mysql_query("SELECT link, notes FROM links WHERE username='will';"); $html .= "<ul>"; while ($row = mysql_fetch_array($result)) { //loop extract($row); $html .= "<li>{$link} - {$notes}</li>"; } I need the bit where it says {$link} to become a clickable link which opens a new window. How would I do this? When I put tags around it you get this error: The error is: Parse error: syntax error, unexpected '{' in /data/www/vhosts/themacsplash.com/httpdocs/ClipBoy/will.php on line 18 Line 18 is $html .= "{$link} - {$notes}";

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  • Search 2 Columns with 1 Input Field

    - by Norbert
    I have a db with two columns: first name and last name. The first name can have multiple words. Last name can contain hyphenated words. Is there a way to search both columns with only one input box? Database ID `First Name` `Last Name` 1 John Peter Doe 2 John Fubar 3 Michael Doe Search john peter returns id 1 john returns id 1,2 doe returns id 1,3 john doe returns id 1 peter john returns id 1 peter doe returns id 1 doe john returns id 1 I previously tried the following. Searching for John Doe: SELECT * FROM names WHERE ( `first` LIKE '%john%' OR `first` LIKE '%doe%' OR `last` LIKE '%john%' OR `last` LIKE '%doe%' ) which returns both 1 and 3

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  • I need help with creating a data structure in PHP

    - by alex
    What I need to do is have a data structure that shows jobs organised into 14 day periods, but only when an id is the same. I've implemented all sorts of stuff, but they have failed miserably. Ideally, maybe a SQL expert could handle all of this in the query. Here is some of my code. You can assume all library stuff works as expected. $query = 'SELECT date, rig_id, comments FROM dor ORDER BY date DESC'; $dors = Db::query(Database::SELECT, $query)->execute()->as_array(); This will return all jobs, but I need to have them organised by 14 day period with the same rig_id value. $hitches = array(); foreach($dors as $dor) { $rigId = $dor['rig_id']; $date = strtotime($dor['date']); if (empty($hitches)) { $hitches[] = array( 'rigId' => $rigId, 'startDate' => $date, 'dors' => array($dor) ); } else { $found = false; foreach($hitches as $key => $hitch) { $hitchStartDate = $hitch['startDate']; $dateDifference = abs($hitchStartDate - $date); $isSameHitchTimeFrame = $dateDifference < (Date::DAY * 14); if ($rigId == $hitch['rigId'] AND $isSameHitchTimeFrame) { $found = true; $hitches[$key]['dors'][] = $dor; } } if ($found === false) { $hitches[] = array( 'rigId' => $rigId, 'startDate' => $date, 'dors' => array($dor) ); } } } This seems to work OK splitting up by rig_id, but not by date. I also think I'm doing it wrong because I need to check the earliest date. Is it possible at all to do any of this in the database query? To recap, here is my problem I have a list of jobs with all have a rig_id (many jobs can have the same) and a date. I need the data to be organised into hitches. That is, the rig_id must be the same per hitch, and they must span a 14 day period, in which the next 14 days with the same rig_id will be a new hitch. Can someone please point me on the right track? Cheers

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