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  • How to combine these three sql queries into one?

    - by lam3r4370
    How to combine these two sql queries into one? SELECT DISTINCT * FROM rss WHERE MATCH(content,title) AGAINST ('$filter') SELECT COUNT(content) FROM rss WHERE MATCH(content,title) AGAINST ('$filters') And if the result is 0 from the above query - SELECT DISTINCT * FROM rss WHERE content LIKE '%$filters%' OR title LIKE '%$filters%'; $filter .= $row['filter']; $filters = $row['filter']; $filters may be more than one keyword

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  • How to get a list of unrepeatable date from my db in PHP?

    - by SzamDev
    Hi in my db there are 5 fields (id, list_date, amount, total, m_from) and contain data, for example : 1 - 1/1/2010 - 10 - 50 - 'example111' 1 - 1/1/2010 - 10 - 50 - 'example111' 1 - 1/4/2010 - 10 - 50 - 'example154 1 - 1/1/2010 - 10 - 50 - 'example111' 1 - 1/5/2010 - 10 - 50 - 'test' I need to know how I can get dates from list_date but without repeatable dates like '1/1/2010, 1/5/2010, 1/4/2010' Thanks in Advance.

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  • Send multi message using jquery plugin in multi-row data?

    - by Agus Puryanto
    i use jquery.form to send a form, but in may case below how use this jquery plugin $('#htmlForm').ajaxForm({ target: '#htmlExampleTarget', success: function() { $('#htmlExampleTarget').fadeIn('slow'); $('#htmlForm').hide(); } }); for($i=1;$i<= 10;$i++){ //form $1 form name="form$i" action="blabla.php" input type="text" name="name$i" / input type="text" name="name$i" / input type="submit" name="submit" / }

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  • How do I assign a rotating category to database entries in the order the records come in?

    - by Stomped
    I have a table which gets entries from a website, and as those entries go into the database, they need to be assigned the next category on a list of categories that may be changed at any time. Because of this reason I can't do something simple like for mapping the first category of 5 to IDs 1, 6, 11, 16. I've considered reading in the list of currently possibly categories, and checking the value of the last one inserted, and then giving the new record the next category, but I imagine if two requests come in at the same moment, I could potentially assign them both the same category rather then in sequence. So, my current round of thinking is the following: lock the tables ( categories and records ) insert the newest row into records get the newest row's ID select the row previous to the insertl ( by using order by auto_inc_name desc 0, 1 ) take the previous row's category, and grab the next one from the cat list update the new inserted row unlock the table I'm not 100% sure this will work right, and there's possibly a much easier way to do it, so I'm asking: A. Will this work as I described in the original problem? B. Do you have a better/easier way to do this? Thanks ~

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  • Separating Variables Inside an Array

    - by Jake Avila Talledo
    Hey i have an array an I need to separate each value so it would be something like this $arry = array(a,b,c,d,e,f) $point1 = (SELECT distance FROM Table WHERE Origin = a AND Destination = b); $point2 = (SELECT distance FROM Table WHERE Origin = b AND Destination = c); $point3 = (SELECT distance FROM Table WHERE Origin = c AND Destination = d); $point4 = (SELECT distance FROM Table WHERE Origin = d AND Destination = e); $point5 = (SELECT distance FROM Table WHERE Origin = e AND Destination = f); $point6 = (SELECT distance FROM Table WHERE Origin = f AND Destination = g); $point7 = (SELECT distance FROM Table WHERE Origin = g AND Destination = f); $total_trav = $point1+$point2+$point3+$point4+$point5+$point6+$point7

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  • Finding comma separated values with a colon delimiter

    - by iconMatrix
    I am setting values in my database for tourneyID,Selected,Paid,Entered,date then separating each selection with a colon So I have a string that may look like this 187,S,,,09-21-2013:141,S,,,06-21-2013:144,S,,,05-24-2013 but it also could look like this 145,S,,,07-12-2013:142,S,,,05-24-2013:187,S,,,09-21-2013 and some times is looks like this 87,S,,,07-11-2013:125,S,,,06-14-2013 I am trying to find this sequence: 187,S,,,09-21-2013 I have data stored like that because I paid a programmer to code it for me. Now, as I learn, I see it was not the best solution, but it is what I have till I learn more and it is working. My problem is when using LIKE it returns both the 187 and 87 values $getTeams = mysql_query("SELECT * FROM teams WHERE (team_tourney_vector LIKE '%$tid,S,P,,$tourney_start_date%' OR team_tourney_vector LIKE '%$tid,S,,,$tourney_start_date%') AND division='$division'"); I tried this using FIND_IN_SET() but it would only return the the team id for this string 187,S,,,09-21-2013:141,S,,,06-21-2013:144,S,,,05-24-2013 and does not find the team id for this string 145,S,,,07-12-2013:142,S,,,05-24-2013:187,S,,,09-21-2013 SELECT * FROM teams WHERE FIND_IN_SET('187',team_tourney_vector) AND (team_tourney_vector LIKE '%S,,,09-21-2013%') Any thoughts on how to achieve this?

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  • A better understanding of the relations beetween database tables

    - by Nistor Alexandru
    Hi I am trying to get a better understanding of relational databases and there is something that I keep bumping into and don't understand.Let's take this two tables: In this case Login.ID is the primary key with auto_increment set and Profile.ID_LOGIN is the Foreign KEY.When a user is created and it's username and password is stored in the login database does the ID coresponding to the curesnt username and password get automaticly added into ID_LOGIN or do I have to create an SQL statement to do this? If I have to create a SQL statement how should I aproach adding the ID_LOGIN to make sure I am adding it corectly?

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  • SQL query joining rows with same value

    - by user1285737
    I need to write a query that creates a view that calculates the total cost of each sale, by considering quantity and price of each bought item. The view should return the debit and total cost. In the answer each debit-number should only occur once. Thanks in advance Table ITEM: ID NAME PRICE 118 Jeans 100 120 Towel 20 127 Shirt 55 Table DEBIT: DEBIT ITEM Quantity 100581 118 5 100581 120 1 100586 127 5

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  • Locking DB w/ Large Reads (Ruby-on-Rails/Heroku)

    - by Splashlin
    Currently I have a Web API running on Heroku that is constantly writing information we're collecting from other data sources (currently theres about half a GB of data and it's growing very quickly). We're looking to add a reporting system on top of the current database that we can use to extract useful information out of the DB. The problem is that when we're running reports we're locking the DB and any other sites communicating with the DB are timing out. Does anyone have any solutions on how to solve this type of issue? Amazon RDS seems to have some interesting stuff with database replication but I don't know if that will solve my problems. Any advice would be greatly appreciated. Thanks

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  • Can i use a parameter multiple times in the qame query?

    - by djerry
    Hey guys, i was wondering, can a parameter be used more then once in the same query, like this : MySqlParameter oPar0 = new MySqlParameter("e164", MySqlDbType.String); oPar0.Value = user.E164; string sSQL0 = "Delete from callmone.call where (caller=?e164 or called=?e164);"; clsDatabase.ExecuteSQL(sSQL0, oPar0); Is this possible or should i write 2 parameters?

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  • why is ADODB inserting NULL values on update?

    - by every_answer_gets_a_point
    i have: With rs .AddNew ' create a new record ' add values to each field in the record .Fields("datapath") = dpath .Fields("analysistime") = "atime" .Fields("reporttime") = "rtime" .Fields("lastcalib") = "lcalib" .Fields("analystname") = "aname" .Fields("reportname") = "rname" .Fields("batchstate") = "bstate" .Fields("instrument") = "NA" .Update ' stores the new record End With when i check the database, it looks like it ONLY inserted the last field! has anyone encountered this problem?

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  • Inventory count in CakePHP

    - by metrobalderas
    We are developing an inventory tracking system. Basically we've got an order table in which orders are placed. When an order is payed, the status changes from 0 to 1. This table has multiple children in another table order_items. This is the main structure. CREATE TABLE order( id INT UNSIGNED AUTO_INCREMENT PRIMARY KEY, user_id INT UNSIGNED, status INT(1), total INT UNSIGNED ); CREATE TABLE order_items( id INT UNSIGNED AUTO_INCREMENT PRIMARY KEY, order_id INT UNSIGNED, article_id INT UNSIGNED, size enum('s', 'm', 'l', 'xl'), quantity INT UNSIGNED ); Now, we've got a stocks table with similar architecture for the acquisitions. This is the structure. CREATE TABLE stock( id INT UNSIGNED AUTO_INCREMENT PRIMARY KEY, article_id INT UNSIGNED ); CREATE TABLE stock_items( id INT UNSIGNED AUTO_INCREMENT PRIMARY KEY, stock_id INT UNSIGNED, size enum('s', 'm', 'l', 'xl'), quantity INT(2) ); The main difference is that stocks has no status field. What we are looking for is a way to sum each article size from stock_items, then sum each article size from order_items where Order.status = 1 and substract both these items to find our current inventory. This is the table we want to get from a single query: Size | Stocks | Sales | Available s | 10 | 3 | 7 m | 15 | 13 | 2 l | 7 | 4 | 3 Initially we thought abouth using complex find conditions, but perhaps that's the wrong approach. Also, since it's not a direct join, it turns out to be quite hard. This is the code we have to retrieve the stock's total for each item. function stocks_total($id){ $find = $this->StockItem->find('all', array( 'conditions' => array( 'StockItem.stock_id' => $this->find('list', array('conditions' => array('Stock.article_id' => $id))) ), 'fields' => array_merge( array( 'SUM(StockItem.cantidad) as total' ), array_keys($this->StockItem->_schema) ), 'group' => 'StockItem.size', 'order' => 'FIELD(StockItem.size, \'s\', \'m\' ,\'l\' ,\'xl\') ASC' )); return $find; } Thanks.

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  • problems with inserting data in database

    - by jannes braet
    $message=$_POST['answer']; $message=nl2br($message); $message=strip_tags($message, '<p><a><b><i><strong><em><code><sub><sup><img><ul><ol><li>'); $message = mysql_real_escape_string($message); $user=$_SESSION['SESS_MEMBER_ID']; $qry="INSERT INTO forum_rules (message,author,date) VALUES ($message,$user,'".date("Y-m-d H:i:s")."')"; $result=mysql_query($qry) or die(mysql_error()); if (!$result) { echo "error inserting data into database"; } else { ... } this codes always outputs error inserting data into database and i don't see what i'm doing wrong. i hav also tried to do it without the date part but that didn't work tho. can someone please tell me what i'm doing wrong here

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  • Fetch last item in a category that fits specific criteria

    - by Franz
    Let's assume I have a database with two tables: categories and articles. Every article belongs to a category. Now, let's assume I want to fetch the latest article of each category that fits a specific criteria (read: the article does). If it weren't for that extra criteria, I could just add a column called last_article_id or something similar to the categories table - even though that wouldn't be properly normalized. How can I do this though? I assume there's something using GROUP BY and HAVING?

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  • if specific row = null, execute query

    - by fusion
    how do i check if the value of a column is null, and only then execute the query? for example: col1 col2 col3 01 abc i run a query which first checks if the record exists or not; if it exists, it should execute the update query and if it doesn't exist, it executes the insert query. how do i check if col3 is null and if it is null, it should execute the update query. . $sql = "SELECT uid FROM `users` WHERE uid = '" . $user_id . "'"; $result = mysql_query($sql,$conn) or die('Error:' .mysql_error()); $totalrows = mysql_num_rows($result); if($totalrows < 1) { insertUser($user_id,$sk, $conn); } else { updateSessionKey($user_id,$sk,$conn); }

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  • php session_start() error

    - by tooepic
    Hi, i've used a sample found on online and applied it to my code: <?php session_start(); if (isset($_REQUEST["email"])) { $_SESSION["name"] = true; $host = $_SERVER["HTTP_HOST"]; $path = dirname($_SERVER["PHP_SELF"]); $sid = session_name() . "=" . session_id(); header("Location: index.php?$sid"); exit; } ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> ... ... and rest of the html code When I open this page, I got an error: Warning: session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started at /data/server/user/directory/sub-directory/login.php:1) in /data/server/user/directory/sub-directory/login.php on line 2 Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at /data/server/user/directory/sub-directory/login.php:1) in /data/server/user/directory/sub-directory/login.php on line 2 I looked around to resolve this issue and saw few posts about this in this site also, but I just can't get a good grip on this...can't find the answer. Please help. Thanks.

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  • problem with logout script in php

    - by user225269
    I'm a beginner in php, and I am trying to create a login and logout. But I am having problems in logging out. My logout just calls for the login form which is this: <? session_start(); session_destroy(); ?> <table width="300" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC"> <tr> <form name="form1" method="post" action="checklogin.php"> <td> <table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF"> <tr> <td colspan="3"><strong>Member Login </strong></td> </tr> <tr> <td width="78">Username</td> <td width="6">:</td> <td width="294"><input name="myusername" type="text" id="myusername"></td> </tr> <tr> <td>Password</td> <td>:</td> <td><input name="mypassword" type="text" id="mypassword"></td> </tr> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login"></td> </tr> </table> </td> </form> </tr> </table> My problem is, when I try to press the back button in the browser. Whoever user is using it can still access what is not supposed to be accessed when a user hasn't logged in. Do I need to add a code on the user page? I have this code on the user page: <? session_start(); if(!session_is_registered(myusername)){ header("location:main_login.php"); } ?> What can you recommend that I would do so that a script will prompt to enter the username and password again when a user clicks on the back button.

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  • Unknown column '' in 'field list'

    - by Rixius
    I am running a sql in PHP query that is dieing with the mysql_error() of Unknown column '' in 'field list' The query: SELECT `standard` AS fee FROM `corporation_state_fee` WHERE `stateid` = '8' LIMIT 1 when I run the query in PHPmyadmin, it return the information without flagging the error

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  • how to filter an id for subcategory in sql

    - by Naim Nsco
    i have create one table with A is 1,2,3 and B is 3,5,5,9,10,10 For example, i want to change from this table NP A B C 1 1 3 why not 1 1 5 weigh 1 1 5 hello 1 1 9 no way 1 1 10 now or never 1 1 10 float the boat, capt ain 1 1 12 no nelp 2 2 4 why 2 2 6 way too much 2 2 11 help 3 3 1 not now 3 3 2 not 3 3 7 milky way 3 3 7 this is stupid 3 3 8 one way To be like this:- A B C ---------- -- -------- 1 3 why not 5 weigh 5 hello 9 no way 10 now or never 10 float the boat, capt ain 12 no nelp 2 4 why 6 way too much 11 help 3 1 not now 2 not 7 milky way 7 this is stupid 8 one way How to do like that?. Anyone know about this?.

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  • my sql insert query not working

    - by Piyush
    I am inserting userId.It is displaying correct but inserting 0 in spite of actual userId. mycode- If(! empty($userIDToCheck) || $userIDToCheck != '' ) { echo $userIDToCheck; $sql = "INSERT INTOpnpdb.ruser(userid) VALUES ('$userIDToCheck');"; mysql_query($sql)or die(mysql_error()); echo "Done"; } Output : pi203713 Done But is database it is inserting "0"???

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  • How would i output a message that says "values inserted to table" ?

    - by ranlo
    <?php error_reporting(0); $con=mysql_connect("localhost","root",""); if (!$con) { die('could not connect:'.mysql_error()); } mysql_select_db("final?orgdocs",$con); $org_name = $_POST["org_name"]; $org_type = $_POST["org_type"]; $org_code = $_POST["org_code"]; $description = $_POST["description"]; $stmt = "INSERT INTO organization VALUES('".$org_name."','".$org_type."','".$org_code."','".$description."')"; $result = mysql_query("SELECT * FROM organization WHERE org_name = '$org_name' "); echo '<TABLE BORDER = "1">'; $result1 = $result; while ($row = mysql_fetch_array($result1)){ echo '<TR>'.'<TD>'.'Organization Name'.'</TD>'.'<TD>'.'Organization Type'.'</TD>'.'<TD>'.'Organization Code'.'</TD>'.'<TD>'.'Description'.'</TD>'.'<TD>'.'Constitution'.'</TD>'; echo '</TR>'; echo '<TR>'.'<TD>'.$row['org_name'].'</TD>'.'<TD>'.$row['org_type'].'</TD>'; echo '<TD>'.$row['org_code'].'</TD>'.'<TD>'.$row['description'].'</TD>'.'<TD>'; echo '</TR>'; } echo '</TABLE>'; ?>

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  • fetch some data from two tables

    - by user1753971
    i have site like imdb and we provide movie information sin site..and our website have option to rate all movies for every users. I have two tables 1 . imdb (its for store movie details) id,name,actors,vote 2. ratings (its for store users rating details) id,rating_id(its same as id from first table),rating_num,IP now what am doing is..when anyone rating a movie take the avg of that movie rating by using rating tables (total ratings/number of ratings) and insert that value into "vote" column in first table..my demands this..thats why done like this.. Now my problem is..i want to fetch top rated movies..i mean in vote column which movie have top rating which want to list and one more condition is that that movie should rated by 10 users(use ratings table for that) thanks in advance

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