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  • How to set up Atana Studio 3 Themes in Pydev

    - by willy1234x1
    I've installed the Aptana Studio 3 preview and noticed it has support for themes (such as a bespin style or Ruby envy) and I'd love to use the Bespin one in Pydev but so far I've had no luck getting it to work, anyone have a clue as to how to get it to work? Video showing the themes in action.

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  • Editting ForeignKey from "child" table

    - by profuel
    I'm programming on py with django. I have models: class Product(mymodels.Base): title = models.CharField() price = models.ForeignKey(Price) promoPrice = models.ForeignKey(Price, related_name="promo_price") class Price(mymodels.Base): value = models.DecimalField(max_digits=10, decimal_places=3) taxValue = models.DecimalField("Tax Value", max_digits=10, decimal_places=3) valueWithTax = models.DecimalField("Value with Tax", max_digits=10, decimal_places=3) I want to see INPUTs for both prices when editing product, but cannot find any possibility to do that. inlines = [...] works only from Price to Product, which is stupid in this case. Thanx for adnvance.

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  • Problem bounding name to a class in Django

    - by martinthenext
    Hello! I've got a view function that has to decide which form to use depending on some conditions. The two forms look like that: class OpenExtraForm(forms.ModelForm): class Meta: model = Extra def __init__(self, *args, **kwargs): super(OpenExtraForm, self).__init__(*args, **kwargs) self.fields['opening_challenge'].label = "lame translation" def clean_opening_challenge(self): challenge = self.cleaned_data['opening_challenge'] if challenge is None: raise forms.ValidationError('??????? ???, ??????????? ?????? ???. ???????????') return challenge class HiddenExtraForm(forms.ModelForm): class Meta: model = Extra exclude = ('opening_challenge') def __init__(self, *args, **kwargs): super(HiddenExtraForm, self).__init__(*args, **kwargs) The view code goes like that: @login_required def manage_extra(request, extra_id=None, hidden=False): if not_admin(request.user): raise Http404 if extra_id is None: # Adding a new extra extra = Extra() if hidden: FormClass = HiddenExtraForm else: FormClass = OpenExtraForm else: # Editing an extra extra = get_object_or_404(Extra, pk=extra_id) if extra.is_hidden(): FromClass = HiddenExtraForm else: FormClass = OpenExtraForm if request.POST: form = FormClass(request.POST, instance=extra) if form.is_valid(): form.save() return HttpResponseRedirect(reverse(view_extra, args=[extra.id])) else: form = FormClass(instance=extra) return render_to_response('form.html', { 'form' : form, }, context_instance=RequestContext(request) ) The problem is somehow if extra.is_hidden() returns True, the statement FromClass = HiddenExtraForm doesn't work. I mean, in all other conditions that are used in the code it works fine: the correct Form classes are intantiated and it all works. But if extra.is_hidden(), the debugger shows that the condition is passed and it goes to the next line and does nothing! As a result I get a UnboundLocalVar error which says FormClass hasn't been asssigned at all. Any ideas on what's happening?

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  • SelfReferenceProperty vs. ListProperty Google App Engine

    - by John
    Hi All, I am experimenting with the Google App Engine and have a question. For the sake of simplicity, let's say my app is modeling a computer network (a fairly large corporate network with 10,000 nodes). I am trying to model my Node class as follows: class Node(db.Model): name = db.StringProperty() neighbors = db.SelfReferenceProperty() Let's suppose, for a minute, that I cannot use a ListProperty(). Based on my experiments to date, I can assign only a single entity to 'neighbors' - and I cannot use the "virtual" collection (node_set) to access the list of Node neighbors. So... my questions are: Does SelfReferenceProperty limit you to a single entity that you can reference? If I instead use a ListProperty, I believe I am limited to 5,000 keys, which I need to exceed. Thoughts? Thanks, John

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  • How to reset Scrapy parameters? (always running under same parameters)

    - by Jean Ventura
    I've been running my Scrapy project with a couple of accounts (the project scrapes a especific site that requieres login credentials), but no matter the parameters I set, it always runs with the same ones (same credentials). I'm running under virtualenv. Is there a variable or setting I'm missing? Edit: It seems that this problem is Twisted related. Even when I run: scrapy crawl -a user='user' -a password='pass' -o items.json -t json SpiderName I still get an error saying: ERROR: twisted.internet.error.ReactorNotRestartable And all the information I get, is the last 'succesful' run of the spider.

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  • Django and json request

    - by Hulk
    In a template i have the following code <script> var url="/mypjt/my_timer" $.post(url, paramarr, function callbackHandler(dict) { alert('got response back'); if (dict.flag == 2) { alert('1'); $.jGrowl("Data could not be saved"); } else if(dict.ret_status == 1) { alert('2'); $.jGrowl("Data saved successfully"); window.location = "/mypjt/display/" + dict.rid; } }, "json" ); </script> In views i have the following code, def my_timer(request): dict={} try: a= timer.objects.get(pk=1) dict({'flag':1}) return HttpResponse(simplejson.dumps(dict), mimetype='application/javascript') except: dict({'flag':1}) return HttpResponse(simplejson.dumps(dict), mimetype='application/javascript') My question is since we are making a json request and in the try block ,after setting the flag ,cant we return a page directly as return render_to_response('mypjt/display.html',context_instance=RequestContext(request,{'dict': dict})) instead of sending the response, because on success again in the html page we redirect the code Also if there is a exception then only can we return the json request. My only concern is that the interaction between client and server should be minimal. Thanks..

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  • wxPython: Change a buttons text in a wx.FileDialog

    - by Sascha
    Hello I have a wx.FileDialog (with the wx.FD_OPEN flag) & I would like to know if I can (& how) I could change the button in the bottom right of the FileDialog from "Open" to "Create" or "Delete", etc. What I am doing is I have a button with the text "Delete Portfolio", when pressed it opens a FileDialog & allows the user to select a portfolio file(.db) to delete. So instead of the File Dialog's bottom right confirm button displaying "Open" I would like to be able to change the text to "Confirm" or "Delete" or whatever. Is this possible, its a rather superficial thing to do, but if the button says open when the user wants to select a file to delete, it can be a little confusing even if the title of the dialog says "please select a file to delete"

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  • SQLAlchemy returns tuple not dictionary

    - by Ivan
    Hi everyone, I've updated SQLAlchemy to 0.6 but it broke everything. I've noticed it returns tuple not a dictionary anymore. Here's a sample query: query = session.query(User.id, User.username, User.email).filter(and_(User.id == id, User.username == username)).limit(1) result = session.execute(query).fetchone() This piece of code used to return a dictionary in 0.5. My question is how can I return a dictionary?

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  • foreignkey problem

    - by realshadow
    Hey, Imagine you have this model: class Category(models.Model): node_id = models.IntegerField(primary_key = True) type_id = models.IntegerField(max_length = 20) parent_id = models.IntegerField(max_length = 20) sort_order = models.IntegerField(max_length = 20) name = models.CharField(max_length = 45) lft = models.IntegerField(max_length = 20) rgt = models.IntegerField(max_length = 20) depth = models.IntegerField(max_length = 20) added_on = models.DateTimeField(auto_now = True) updated_on = models.DateTimeField(auto_now = True) status = models.IntegerField(max_length = 20) node = models.ForeignKey(Category_info, verbose_name = 'Category_info', to_field = 'node_id' The important part is the foreignkey. When I try: Category.objects.filter(type_id = 15, parent_id = offset, status = 1) I get an error that get returned more than category, which is fine, because it is supposed to return more than one. But I want to filter the results trough another field, which would be type id (from the second Model) Here it is: class Category_info(models.Model): objtree_label_id = models.AutoField(primary_key = True) node_id = models.IntegerField(unique = True) language_id = models.IntegerField() label = models.CharField(max_length = 255) type_id = models.IntegerField() The type_id can be any number from 1 - 5. I am desparately trying to get only one result where the type_id would be number 1. Here is what I want in sql: SELECT c.*, ci.* FROM category c JOIN category_info ci ON (c.node_id = ci.node_id) WHERE c.type_id = 15 AND c.parent_id = 50 AND ci.type_id = 1 Any help is GREATLY appreciated. Regards

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  • Euclidian Distances between points

    - by R S
    I have an array of points in numpy: points = rand(dim, n_points) And I want to: Calculate all the l2 norm (euclidian distance) between a certain point and all other points Calculate all pairwise distances. and preferably all numpy and no for's.

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  • Counting amount of items in Pythons 'for'

    - by Markum
    Kind of hard to explain, but when I run something like this: fruits = ['apple', 'orange', 'banana', 'strawberry', 'kiwi'] for fruit in fruits: print fruit.capitalize() It gives me this, as expected: Apple Orange Banana Strawberry Kiwi How would I edit that code so that it would "count" the amount of times it's performing the for, and print this? 1 Apple 2 Orange 3 Banana 4 Strawberry 5 Kiwi

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  • How to replace empty string with zero in comma-separated string?

    - by dsaccount1
    "8,5,,1,4,7,,,,7,,1,9,3,6,,,8,6,3,9,,2,5,4,,,,,3,2,,,7,4,1,1,,4,,6,9,,5,,,,5,,,1,,6,3,,,6,5,,,,7,4,,1,7,6,,,,8,,5,,,7,1,,3,9," I'm doing a programming challenge where i need to parse this sequence into my sudoku script. Need to get the above sequence into 8,5,0,1,4,7,0,0,0,7,0,1,9,3,6,0,0,8......... I tried re but without success, help is appreciated, thanks.

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  • Simple way to create possible case

    - by bugbug
    I have lists of data such as a = [1,2,3,4] b = ["a","b","c","d","e"] c = ["001","002","003"] And I want to create new another list that was mixed from all possible case of a,b,c like this d = ["1a001","1a002","1a003",...,"4e003"] Is there any module or method to generate d without write many for loop?

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  • Joining different models in Django

    - by Andrew Roberts
    Let's say I have this data model: class Workflow(models.Model): ... class Command(models.Model): workflow = models.ForeignKey(Workflow) ... class Job(models.Model): command = models.ForeignKey(Command) ... Suppose somewhere I want to loop through all the Workflow objects, and for each workflow I want to loop through its Commands, and for each Command I want to loop through each Job. Is there a way to structure this with a single query? That is, I'd like Workflow.objects.all() to join in its dependent models, so I get a collection that has dependent objects already cached, so workflows[0].command_set.get() doesn't produce an additional query. Is this possible?

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  • django: Changing auto_id of ModelForm based form class

    - by Meilo
    Every time I create an instance of the TestForm specified below, I have to overwrite the standard id format with auto_id=True. How can this be done once only in the form class instead? Any hints are very welcome. views.py from django.forms import ModelForm from models import Test class TestForm(ModelForm): class Meta: model = Test def test(request): form = TestForm(auto_id=True)

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  • How to create instances of a class from a static method?

    - by Pierre
    Hello. Here is my problem. I have created a pretty heavy readonly class making many database calls with a static "factory" method. The goal of this method is to avoid killing the database by looking in a pool of already-created objects if an identical instance of the same object (same type, same init parameters) already exists. If something was found, the method will just return it. No problem. But if not, how may I create an instance of the object, in a way that works with inheritance? >>> class A(Object): >>> @classmethod >>> def get_cached_obj(self, some_identifier): >>> # Should do something like `return A(idenfier)`, but in a way that works >>> class B(A): >>> pass >>> A.get_cached_obj('foo') # Should do the same as A('foo') >>> A().get_cached_obj('foo') # Should do the same as A('foo') >>> B.get_cached_obj('bar') # Should do the same as B('bar') >>> B().get_cached_obj('bar') # Should do the same as B('bar') Thanks.

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  • Dropdown sorting in django-admin

    - by Andrey
    I'd like to know how can I sort values in the Django admin dropdowns. For example, I have a model called Article with a foreign key pointing to the Users model, smth like: class Article(models.Model): title = models.CharField(_('Title'), max_length=200) slug = models.SlugField(_('Slug'), unique_for_date='publish') author = models.ForeignKey(User) body = models.TextField(_('Body')) status = models.IntegerField(_('Status')) categories = models.ManyToManyField(Category, blank=True) publish = models.DateTimeField(_('Publish date')) I edit this model in django admin: class ArticleAdmin(admin.ModelAdmin): list_display = ('title', 'publish', 'status') list_filter = ('publish', 'categories', 'status') search_fields = ('title', 'body') prepopulated_fields = {'slug': ('title',)} admin.site.register(Article, ArticleAdmin) and of course it makes the nice user select dropdown for me, but it's not sorted and it takes a lot of time to find a user by username.

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  • Simple XML over http web service

    - by Mark
    I have a simple html service, developed in django. You enter your name - it posts this, and returns a value (male/female). I need to ofer this as a web service. I have no idea where to start. I want to accept a xml request, and provide an xml response - thats it. Can anyone give ma any pointers - Googling it is difficult when you dont know what your searching for.

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  • Should I use fork or threads?

    - by shadyabhi
    In my script, I have a function foo which basically uses pynotify to notify user about something repeatedly after a time interval say 15 minutes. def foo: while True: """Does something""" time.sleep(900) My main script has to interact with user & does all other things so I just cant call the foo() function. directly. Whats the better way of doing it and why? Using fork or threads?

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  • How to classify NN/NNP/NNS obtained from POS tagged document as a product feature

    - by Shweta .......
    I'm planning to perform sentiment analysis on reviews of product features (collected from Amazon dataset). I have extracted review text from the dataset and performed POS tagging on that. I'm able to extract NN/NNP as well. But my doubt is how do I come to know that extracted words classify as features of the products? I know there are classifiers in nltk but I don't know how I should use it for my project. I'm assuming there are 2 ways of finding whether the extracted word is a product feature or not. One is to compare with a bag of words and find out if my word exists in that. Doubt: How do I create/get bag of words? Second way is to implement some kind of apriori algorithm to find out frequently occurring words as features. I would like to know which method is good and how to go about implementing it. Some pointers to available softwares or code snippets would be helpful! Thanks!

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