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  • how to submit using link with my current code(php+jquery+ajax)

    - by ruslyrossi
    My current Code : <script type="text/javascript"> $(document).ready(function() { $('#form').ajaxForm( { target: '#preview', success: function() { $('#success_box').addClass('success') setTimeout(function() { $('#success_box').fadeOut('slow'); }, 3100); // <-- time in milliseconds } }); }); </script> <form action="controller/product_edit_update.php" method="post" id="form" name="form" > bla..bla.. <input type="submit" value="Save" /></form> but now i want to add submit link with <a href="" id="submit_with_link" >Save</a>

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  • Why self.view is not available

    - by amok
    I have this code in the main view controller and it is working just fine and as I wanted. loadingActionSheet = [[UIActionSheet alloc] initWithTitle:@"Posting To Twitter..." delegate:nil cancelButtonTitle:@"Cancel" destructiveButtonTitle:nil otherButtonTitles:nil]; [loadingActionSheet showInView:self.view]; I wanted that code to be reusable from different part of the project so I moved it in a separate file (UIView based). The poblem that I am facing is that self.view is not available there and I don't know why because I am learning and I don't know enough to understand what I am missing. What do I have to do/add/change to have the actionsheet shown in my current view even if that code lives somewhere else?

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  • What is the most elegant way to access current_user from the models? or why is it a bad idea?

    - by TheLindyHop
    So, I've implemented some permissions between my users and the objects the users modify.. and I would like to lessen the coupling between the views/controllers with the models (calling said permissions). To do that, I had an idea: Implementing some of the permission functionality in the before_save / before_create / before_destroy callbacks. But since the permissions are tied to users (current_user.can_do_whatever?), I didn't know what to do. This idea may even increase coupling, as current_user is specifically controller-level. The reason why I initially wanted to do this is: All over my controllers, I'm having to check if a user has the ability to save / create / destroy. So, why not just return false upon save / create / destroy like rails' .save already does, and add an error to the model object and return false, just like rails' validations? Idk, is this good or bad? is there a better way to do this?

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  • jQuery ajax() and cakePHP urls

    - by Pickledegg
    I'm trying to call the 'tariff' action of my 'countries' controller using jQuery ajax() and pass it a country name in the following format: /countries/tariff/countryname however, with the following code ( set to GET ), it is calling this with the get '?' added: /countries/tariff/?countryname $(document).ready(function(){ $('#CountriesIndexForm select').change(function(){ $.ajax({ type: "GET", url: "/countries/tariff/", data: escape($(this).val()), success: function(html){ $(this).parent().next('div').html(html); } }); }); }); I understand its because the type: is set to GET, but is there a fix for this?

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  • Creating Html Helper Method - MVC Framework

    - by nettguy
    I am learning MVC from Stephen Walther tutorials on MSDN website. He suggests that we can create Html Helper method. Say Example using System; namespace MvcApplication1.Helpers { public class LabelHelper { public static string Label(string target, string text) { return String.Format("<label for='{0}'>{1}</label>", target, text); } } } My Question under which folder do i need to create these class? View folder or controller folder? or can i place it in App_Code folder?

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  • Simple addView problem

    - by Buyin Brian
    Hi there. I have a simple addView problem that is driving me nuts, I know I am overlooking something simple, perhaps another set of eyes can help. I have a Nib with a view that has a class identity set to TestView In my view controller, I use the following code: CGRect myRect = CGRectMake(0, 0, 320,240); TestView *myTest = [[TestView alloc] initWithFrame:myRect]; [self.view addSubview:myTest]; I have a NSLog in the TestView class's initWithFrame that fires when the above code is executed, but the view doesn't appear in the view controllers view. Thanks for your help.

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  • Grails external Jms broker (active mq)

    - by TheBigS
    I have what will become an 'external' activemq server I'd like grails to be able to talk to. Right now I am just running it on my dev box. Here is what I have setup right now: 1) Run activemq server 2) Run activemq/examples using ant to produce messages 3) View ActiveMQ admin site: http://localhost:8161/admin/queues.jsp verify that messages are in the queue. 4) Follow Mini Tutorial to create the Service and Controller: http://www.grails.org/ActiveMQ+Plugin 5) Configured my Grails resources.groovy file as follows: beans = { jmsConnectionFactory(SingleConnectionFactory){ targetConnectionFactory = { ActiveMQConnectionFactory cf -> brokerURL = 'tcp://localhost:61616' } } } When I run the grails app I get a BindException saying port 61616 is already in use. How do I configure this to use my server that is already running? I've tried changing 'localhost' to '127.0.0.1' and to my LAN ip, but no luck, it keeps trying to setup its own embedded activemq server. Any ideas?

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  • Model class is not found in zend framework project (quickstart) ,please help

    - by Dumindu
    The things I did is zf create project demo1 in command prompt add the lines to application.ini appnamespace = "Application" resources.layout.layoutPath = APPLICATION_PATH "/layouts/scripts" add a layout with header and footer using partial() (They are perfectly worked) create Data.php in models directory and add this simple class <?php class Application_Model_Data{ }//Application for appnamespace then I tried to load this class(by creating instance)from index controller index action $data = new Application_Model_Data(); but when I test it even in this level it gives an error Fatal error: Class 'Application_Model_Data' not found in C:\Zend\...\IndexController.php Question Do I want to add a autoloader to load models in the application( I'm not used modules) if not what was I missed to add please help I'm stuck in the beginning,Thank you

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  • Cakephp, Retreive Data for HABTM Models using conditional find

    - by ion
    There are 2 Models: Project & Category that are bind with HABTM relationship. I would like to perform a search from projects controller that can do the following: FIND all DISTINCT Project.scedule WHERE Category.slug != 'uncategorised' Apologies for the syntax, I'm no sequel expert. What I have managed to do is to retrieve all projects that do not belong to Category uncategorised into an array however I'm not sure as to how to search again the array result for DISTINCT Project.schedule values (needed to fill out a form drop down) I hope I made myself clear.

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  • NavigationBar text colour not changing?

    - by Jeff
    In my tabbar application I am adding Navigation controller in each tab. Suppose the selected index is 0 when I opening the app.In my 3rd tab(selected index=2) I want to change the text colour of navigationbar title.And I am using the code [[UINavigationBar appearance] setTitleTextAttributes: [NSDictionary dictionaryWithObjectsAndKeys: [UIColor greenColor],UITextAttributeTextColor,nil]]; But its not changing the text color of Index 0 and 2.Colour of index 1 will change only if that tab was not clicked before changing the colour by using the above code. I don't know whats is the issue ? Any help/code will be appreciable.

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  • ASP.NET MVC 2 Model object validation

    - by Jimmy
    Hey guys, I'm trying to validate a model object outside of the context of ModelState within a controller, I currently have a parser that creates model objects from an excel file and I want to be able to report how many entries were added to the database and how many failed, is there a way to validate a model object on its data annotations outside of model binding? I'm looking for something similar to the rails model method of model.valid? or a way for me to implement that myself. My current solution is just manually checking if a few key fields are present but this duplicates requirements between my model class and its metadata, there has to be a better way to hook into the model validation checking that is done by mvc 2. Thanks

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  • Best strategy for HTML parcial rendering based on multiple dropdown values

    - by pv2008
    I have a View that renders something like this: "Item 1" and "Item 2" are <tr> elements from a table. After the user change "Value 1" or "Value 2" I would like to call a Controller and put the result (some HTML snippet) in the div marked as "Result of...". I have some vague notions of JQuery. I know how to bind to the onchage event of the Select element, and call the $.ajax() function, for example. But I wonder if this can be achieved in a more efficient way in ASP.NET MVC2.

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  • MVC partial page update

    - by GB
    Hello, I have an MVC project where I have a form with fields a user can enter and save. On that same page I have a table which shows a brief listing of information that the user just saved. The problem I am having is trying to update only the table after a save and not an entire page refresh. Is this possible in jquery or MVC? If so does anyone have an example. Here is what the action in the controller looks like: public ActionResult RefreshList() { string _employeeID = Request.QueryString["empIDSearch"]; this.ViewData["coursehistorylist"] = _service.ListCoursesByEmpID(_employeeID); return View("CourseHistoryList"); } The function in the view: (and this is where I'm confused on how to update only the table) $.ajax({ url: "/Home/RefreshList", type: "POST", success: function(result) { alert("got here"); }, error: function(xhr, ajaxOptions, thrownError) { alert(xhr.status + " " + thrownError + " " + ajaxOptions); } }); Thanks.

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  • Cakephp: Extend search capability to hasMany Relationship

    - by Chris
    I have two models: Car hasMany Passengers Passenger belongsTo Car I want to implement a search using Cake Search. The user should input a number and the searchengine should return all cars that have less than this number passengers. In my search form: echo $form->input('passengers', array('label' => 'Passengers', 'div' => false)); In my Car model: public $filterArgs = array( array('name' => 'passengers', 'type' => 'int'), ); In the controller: public $presetVars = array( array('field' => 'passengers', 'type' => 'int') } I thought of adding a function to the model that returns the number of passengers: function countPassengers(){ return(count($this->Car->Passenger)); //Not sure if this works } And how to I implement this search criteria?: return all Cars where countPassengers()<passenger

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  • Create a link to delete membership in web2py

    - by user1741325
    I'm trying to do something really simple but it's taking me ages to figure out how to do it properly. I want to have a button that simply deletes a member from a group. So in my view I have <div id="del-role">{{=A('Delete Role',_class="btn btn-danger", callback=URL('test'),delete='#del-role')}}</div> However, when I click the button, the only thing I get is a Javascript prompt asking whether I'm sure I want to delete the specified object, yes/no. That's fine but, what I'd really like to do is just auth.del_membership('role') What needs to go in my controller? I do not want any page redirection, I just want to auth.del_membership(role) This seemingly simple thing is taking me forever to understand. Thanks!

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  • How do I reference the other object in django models

    - by UserZero
    Hi, first post here.In Django, I want to have many files be associated with a particular model, so I'm doing a seperate model called files and have model 'A' 'have many' files. But I want my files to be saved in director named by model 'A'. So For example I want something like this: class Show(models.Model): name = models.CharField() showfolder = models.FilePathField() class Episode(models.Model): show = models.ForeignKey(Show) name = models.CharField() files = models.ManyToManyField(mp3) class Mp3(models.Model): file = FileField(upload_to=Episode.show.showfolder) So hopefully that last line expresses what I WANT it to do(get the folder name from Show object associated with the episode). The question is how would I really write that?(besides jumping through hoops in the controller.) Thanks.

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  • In .NET MVC, is there an easy way to check if I'm on the home page?

    - by Hairgami_Master
    I need to take a particular action if a user logs in from the home page. In my LogOnModel, I have a hidden field: @Html.Hidden("returnUrl", Request.Url.AbsoluteUri) In my Controller, I need to check if that value is the Home page or not. In the example below, I'm checking to see if the user is on a particular page ("Account/ResetPassword"). Is there a way to check to see if they're on the home page without resorting to regular expressions? [HttpPost] public ActionResult LogOnInt(LogOnModel model) { if (model.returnUrl.Contains("/Account/ResetPassword")) { return Json(new { redirectToUrl = @Url.Action("Index","Home")}); } Any ideas? A million thanks!

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  • nsfetchedresultscontroller with empty sections

    - by WearyMonkey
    I have a database of People and pets, with a one to many relationship Person Pet Name Name Pet <----- Owner I am using a UITableView backed by Core data and a nsfetchedresultscontroller to display the list of pets, grouped into sections by the owner. NSFetchRequest *fetchRequest = [[NSFetchRequest alloc] init]; fetchRequest.entity = [NSEntityDescription entityFromName:@"Pet" inManagedObjectContext:context] NSSortDescriptor *sortDescriptor = [[NSSortDescriptor alloc] initWithKey:@"Owner.name" ascending:YES]; NSArray *sortDescriptors = [[NSArray alloc] initWithObjects:sortDescriptor, nil]; [fetchRequest setSortDescriptors:sortDescriptors]; NSFetchedResultsController *controller = [[NSFetchedResultsController alloc] initWithFetchRequest:fetchRequest managedObjectContext:context sectionNameKeyPath:@"Owner.name" cacheName:@"Root"]; This works to display all pets under their owners section, however I also want to display the empty sections of People who do not have any pets? Is this possible? Thanks for any help.

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  • ReSharper 5 disable resolve view

    - by Rob
    I just did a fresh installation of Visual Studio 2010 Ultimate and ReSharper 5. But now ran into the following situation; return View("~/Plugin/Plugin.Product.dll/Plugin.Product.Views.CreateProduct.ascx"); From a controller i'm returning a view a shown above. ReSharper 5 is trying to resolve this view, but can't find it. Which is explainable in my situation. What i want is to disable the option for ReSharper to try and resolve the views. Is this possible?

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  • how to request collection of fields in mvc

    - by frosty
    i have the following foreach. Inside you'll see a text box for quantity. At the bottom of the page there is submit button. What is the best practise for saving a collection of fields like this in asp.net MVC. ie how would i get the values in my controller <% foreach(var item in Model.Results) { %> <tr class="RowStyle"> <td><input name="quantity" value="<%= item.Quantity %>" class"input-30" /></td> </tr> <% } %>

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  • Error Handling in Model (MVC)

    - by Andre
    I was wondering what the excepted standard is for handling errors in the Model. Currently I have 'setError' and 'getError' methods that's in use by all my Models. This means I'm only concerned with whether a call to a method in my Model is true or false. If it's false then I would use $this-model-getError() in my Controller. Additionally I'm contemplating setting up a separate file that contains all my errors. One file per model, also wanted to have thoughts on this.

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  • Linking to a file (e.g. PDF) within a CakePHP view.

    - by Hobonium
    I'd like to link to some PDFs in one of my controller views. What's the best practice for accomplishing this? The CakePHP webroot folder contains a ./files/ subfolder, I am confounded by trying to link to it without using "magic" pathnames in my href (e.g. "/path/to/my/webroot/files/myfile.pdf"). What are my options? EDIT: I didn't adequately describe my question. I was attempting to link to files in /app/webroot/files/ in a platform-agnostic (ie. no mod_rewrite) way. I've since worked around this issue by storing such files outside the CakePHP directory structure.

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  • How do I run multiple objects through an IF statement in rails?

    - by codyvbrown
    I am creating an application that highlights user messages from a stream based on whether or not the user has been 'vouched'. It works fine if it's setup for a single author. For example controller: @vouch = Vouch.last.vouched_user_nickname view: <% if tweet.from_user == @vouch %> <div class="flit_message_containerh">.... But I'm having trouble doing it for multiple user nicknames. @vouch = Vouch.find(:all, :select => "vouched_user_nickname", :group => 'vouched_user_nickname' ) Any ideas would be greatly appreciated. I'm a rails noob.

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  • How do I conditionally assign ruby variables to javascript variables?

    - by Tony
    I have a website where I need a javascript version of the "current user" object along with the ruby version. I have been assigning these variables doing something like this... Application Controller: def get_user begin @current_user = User.find(session[:user_id]) if session[:user_id] @current_user_json = @current_user.to_json rescue session.delete(:user_id) @current_user = nil @current_user_json = {} end end Web Page: var current_user = null; current_user_json = '<%= @current_user_json %>'; if(current_user_json != ''){ current_user = current_user_json.user; } Even when there is a current user, I get the current user is undefined. Probably because I am putting the current_user_json assignment around single quotes. However, if I don't put it around single quotes, I'll always get a javascript error when no user is logged in because the syntax is invalid - current_user_json = ; I think I am just looking at this completely wrong and there must be a better way. Given that this is probably a common thing to do, I wanted to get other people's opinion on how to create an object in javascript that is a duplicate of the ruby object.

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  • Want to save data field from form into two columns of two models.

    - by vette982
    I have a Profile model with a hasOne relationship to a Detail model. I have a registration form that saves data into both model's tables, but I want the username field from the profile model to be copied over to the usernamefield in the details model so that each has the same username. function new_account() { if(!empty($this->data)) { $this->Profile->modified = date("Y-m-d H:i:s"); if($this->Profile->save($this->data)) { $this->data['Detail']['profile_id'] = $this->Profile->id; $this->data['Detail']['username'] = $this->Profile->username; $this->Profile->Detail->save($this->data); $this->Session->setFlash('Your registration was successful.'); $this->redirect(array('action'=>'index')); } } } This code in my Profile controller gives me the error: Undefined property: Profile::$username Any ideas?

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