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  • Codeigniter - Is it ok to add functionality to the constructor in controllers?

    - by Irro
    I'm making a project where I want the user to search for shops in different cities and would like the url to be like this: domain/shop/city/name. So I created a controller in codeigniter called Shop. But I cant create a city function since the city part of the url changes dependent on city name. One easy way to do it would be to add a function called "search" and add the functionality there but then I get url's like: domain/shop/search/city/name which I really would like to avoid. So my question is if it's ok to add my functionality directly into the constructor to avoid that extra "search" part in the url? I'm afraid that there might be some performance tricks involved that potentially keeps the class in memory so the constructor will not be called every time.

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  • Rails Rspec testing not saving a transactional model

    - by NolanDC
    I'm currently testing my Rails controllers using RSpec. In one controller, I have a model that uses transactions, so that it will not be saved unless another nested model (whose data is filled in using fields_for) is also saved correctly. The tests hit a snag when they reach the transaction. Some debugging output proves that the model is valid and ready to save. However, upon entering the transaction block, the model does not save. Even stranger, the code never reaches the else clause of "if model.save" (It does, however, enter the transaction block). I can only assume this is a problem with my testing a transactional model. Any ideas/hints/solutions?

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  • How do I completely disable caching in Cakephp?

    - by James Lamiell
    So I opened the cache floodgates in my Cakephp app and now I want to close them... I've done pretty everything I can: delete all files in the tmp folder (but not the folders), turned 'Cache.disable' on in the core.php file in my app, have tried clearing the cache from within some controllers with clearCache() and Cache::clear() (but I suspect this doesn't work because it's not loading the controller -- due to caching). I've pretty much effectively halted my development process just because caching won't turn off. Anyone have some ideas that I could try? I'm starting to think it may be within the browser or maybe my hosting service, but it's probably just Cakephp messing with me.

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  • How to change the toolbar button's Bitmap in win32 ?

    - by Morpheus
    Hi all! I have created a toolbar with some controls on it using ReBar within a window. Can anyone please tell me, How to get the HWND of a buttons/combobox/etc (not normal buttons in a window) if I know (only) the Id of it ? How to obtain the HBITMAP if I know the id of the resource ? How to set the bitmap to the controller ? SendDlgItemMessageW(hWnd, nId, BM_SETIMAGE, IMAGE_BITMAP, (LPARAM)hBitmap); This isn't working for toolbars, isn't it ? I couldn't find a way to do it, please help me. Thank you... Regards EDIT: Anyone please ? :( EDIT: Ok. it seems everyone is busy these days. :( Btw, is it a wrong question ?

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  • how to request collection of fields in mvc

    - by frosty
    i have the following foreach. Inside you'll see a text box for quantity. At the bottom of the page there is submit button. What is the best practise for saving a collection of fields like this in asp.net MVC. ie how would i get the values in my controller <% foreach(var item in Model.Results) { %> <tr class="RowStyle"> <td><input name="quantity" value="<%= item.Quantity %>" class"input-30" /></td> </tr> <% } %>

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  • Dismissing the keyboard in a UIScrollView

    - by Nicholas1024
    Alright, I have a couple of UITextFields and UITextViews inside a UIScrollView, and I'd like to set the keyboard to disappear whenever the scrollview is touched or scrolled (except when you touch down inside the text field/view, of course). My current attempt at doing this is replacing the UIScrollView with a subclass, and setting it to call a removeKeyboard function (defined inside the main view controller) inside the touchesBegan method. However, this only removes the keyboard for a normal touch, not when the view is simply scrolled. So, what's the best way to remove the keyboard inside a UIScrollView? Thanks in advance for your help.

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  • How to integrate yahoo user interface with cakePHP

    - by ygmehboob
    Hi all I am very new to cakePHP, I want to add YUI accordion in the default layout of my application. A simple explanation could be like this - I have a table 'lecturers' in my database. I have baked the model lecturer (file) I have baked the controller lecturers_controller (file) I have baked the view lecturers (folder) I need to override the default layout but I want to add YUI 3 accordion sothat the table name lecturers will be on top, after clicking on the top division it will slidedown and will show me the column name of lecturer table. Is there anyone who could suggest me how to integrate the YUI 3 accordion - Do I have to write a helper for this or simply after copying the YUI 3 library I could code this in the default.ctp file. I am really confused as I could hardly get a full tutorial on this topic. Thank you in advance ................

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  • Should I separate RESTful API controllers from "regular" controllers?

    - by keithjgrant
    This seems like an elementary question, but after a lot of searching around I can't seem to find a straightforward explanation: If I'm building a web application that is going to be accessed largely through a web browser, but that will also support some API requests in a RESTful way, should there be a large degree of separation between the two? On one hand, it seems a large amount of the functionality is the same, with identical data presented in different views (HTML vs. XML/JSON). But on the other hand, there are certain things I need to present to the browser that doesn't quite fit a RESTful approach: how to get an empty form to create a new instance of a resource and how to get a pre-populated form to edit an existing resource. Should these two different methods of accessing the system by funneled through different controllers? Different methods in the same controller? The exact same methods with a switch for view type?

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  • How to handle ViewData type casting in MVC

    - by Wondering
    Hi All, I am new to MVC and facing one issue. I have a xml file and i am retrieving its value using Linq to xml and assigning it to ViewData. Controller.cs var res=from x in doc.Descendants("person") select new { Fname=x.Element("fname").Value, Lname=x.Element("lname").Value }; ViewData["Persons"]=res; in View I am trying <% foreach (var item in ViewData["Persons"]) { %> <li> <%= item.Fname %> </li> <% } %> but foreach (var item in ViewData["Persons"] is giving type casting error..what should be the exact type csting so that i can retrive values in the format item.Fname. Thanks.

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  • grails mail connection refused

    - by mkoryak
    it seems i have tried the mail config in the way that its docs said, but still i get: Error 500: Executing action [x] of controller [x] caused exception: Mail server connection failed; nested exception is javax.mail.MessagingException: Could not connect to SMTP I am using google apps for my email so [email protected] is using gmail. i cannot get grails to send out a test message on my dev box (win 7). my config is: host = "smtp.gmail.com" port = 465 username = "[email protected]" password = "x" props = ["mail.smtp.auth":"true", "mail.smtp.debug":"true", "mail.smtp.starttls.enable":"true", "mail.smtp.socketFactory.port":"465", "mail.smtp.socketFactory.class":"javax.net.ssl.SSLSocketFactory", "mail.smtp.socketFactory.fallback":"false"]

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  • How do I conditionally assign ruby variables to javascript variables?

    - by Tony
    I have a website where I need a javascript version of the "current user" object along with the ruby version. I have been assigning these variables doing something like this... Application Controller: def get_user begin @current_user = User.find(session[:user_id]) if session[:user_id] @current_user_json = @current_user.to_json rescue session.delete(:user_id) @current_user = nil @current_user_json = {} end end Web Page: var current_user = null; current_user_json = '<%= @current_user_json %>'; if(current_user_json != ''){ current_user = current_user_json.user; } Even when there is a current user, I get the current user is undefined. Probably because I am putting the current_user_json assignment around single quotes. However, if I don't put it around single quotes, I'll always get a javascript error when no user is logged in because the syntax is invalid - current_user_json = ; I think I am just looking at this completely wrong and there must be a better way. Given that this is probably a common thing to do, I wanted to get other people's opinion on how to create an object in javascript that is a duplicate of the ruby object.

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  • How to update two f.select from 2 different tables on ruby on rails

    - by Zerosoul13
    Hello, I just started working on a Ruby On Rails project and i got to the point where i need to see the contacts of a company. They should appear once the company is selected.. <%= observe_field :empresa_id, :url={:action = "get_contactos", :controller= :contactos, :updatewith =:empresa_id} % but nothing happens, i don't see even a error on the script/server. Can someone point me in the right direction? http://nealenssle.com/blog/2007/04/12/how-to-dynamically-update-form-elements-in-rails-using-ajax/ I see on the link that a guy did the exact same thing i need but did not post any info. Cheers.

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  • PHP/codeigniter - use of exit()

    - by Patrick
    I have a few pages that require login, so all controllers that link to these pages start with $this->checkSession(); //...rest of the code CheckSession should verify the session is still live, otherwise display a message and stop the execution of the rest of the code in the controller: function checkSession() { if (!$this->session->userdata('is_logged_in')) { //the session has expired! $data['main'] = 'confirmation_message'; $data['title'] = "Session expired"; $this->load->vars($data); $this->load->view('template'); exit(); } } . I was expecting these instructions to happen in sequence, but I only get a blank page. How can I make sure exit() gets executed only after all views are loaded?

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  • Rails routes looking for show action

    - by user1334345
    I am pretty new to rails and basically I want to make a user registration form. I am currently using rails 3.2.3 Basically I want to make basic routes like user/register on top of basic REST route for user. Here are my routes.rb resources :user do collection do get 'register' end end And here are my rake routes: register_user_index GET /user/register(.:format) user#register user_index GET /user(.:format) user#index POST /user(.:format) user#create new_user GET /user/new(.:format) user#new edit_user GET /user/:id/edit(.:format) user#edit user GET /user/:id(.:format) user#show PUT /user/:id(.:format) user#update DELETE /user/:id(.:format) user#destroy From my understanding, since register user is on top of show, it should match with register first before going to show. However, when I try to do localhost:3000/user/register, it gives me this error: No route matches {:action="show", :controller="user"} Can somebody help me with this? Thanks!!

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  • Model's method not being recognized when called

    - by Brian Roisentul
    I'm using ruby on rails 2.3.2 and also using the acts_as_taggable_on puglin. That generated me two db tables: tags and taggings. As I didn't need anything more from those, I didn't create a Tag model, for example. Now the project is more mature, I need to create some methods for tags, so I created a Tag model with some methods in it. The model looks something like this: class Tag < ActiveRecord::Base def self.get_parent parent = Tag.find(self.parent_id) return parent end end When I call it from a controller, it won't find the method. This is the code: tag = Tag.find(tag_id) the_parent = tag.get_parent This will throw an error saying: undefined method `get_parent' for #<Tag id: 13, name: "Historia", parent_id: 12> I don't know what's wrong. Any help will be appreciated.

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  • PrivateFontCollection fails on appharbor

    - by grennis
    I am trying to load a custom font (ttf file) and draw into an image with the Graphics object. This code runs fine locally: PrivateFontCollection fonts = new PrivateFontCollection(); string path = context.Server.MapPath("~/App_Data/Futura LT Bold.ttf"); if (!System.IO.File.Exists(path)) { throw new InvalidOperationException("Font file is not deployed: " + path); } fonts.AddFontFile(path); However when run on appharbor, the call to AddFontFile fails with the exception: System.ArgumentException: Font 'Futura LT Book' does not support style 'Regular'. at System.Drawing.Font.CreateNativeFont() at System.Drawing.Font.Initialize(FontFamily family, Single emSize, FontStyle style, GraphicsUnit unit, Byte gdiCharSet, Boolean gdiVerticalFont) at System.Drawing.Font..ctor(FontFamily family, Single emSize) at LumenboxWeb.Controllers.GalleryController.FontTest() in d:\temp\h5oqslma.udd\input\src\LumenboxWeb\Controllers\GalleryController.cs:line 59 at lambda_method(Closure , ControllerBase , Object[] ) at System.Web.Mvc.ActionMethodDispatcher.Execute(ControllerBase controller, Object[] parameters) at System.Web.Mvc.ReflectedActionDescriptor.Execute(ControllerContext controllerContext, IDictionary`2 parameters) I have tried different fonts, and they all work locally, but none work on appharbor. Is it possible to load fonts dynamically on appharbor?

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  • Navigating between 2 ViewControllers

    - by Kobe.o4
    Im using Navigation Controller for my ViewControllers,I set my importantViewController as something like this to be its RootView: UINavigationController *navControl = [[UINavigationController alloc] initWithRootViewController: vc]; [self presentModalViewController: navControl animated: YES]; Then, I pushView anotherView the FrontViewController like this: [self.navigationController pushViewController:vc animated:YES]; After a button is pressed in FrontViewController another view will be pushed ViewA but it is connected with another ViewController ViewB the same way as this AGAIN: [self.navigationController pushViewController:vc animated:YES]; (Which I think Im doing wrong when dismissing either of them with [self.navigationController popViewControllerAnimated:YES];) This is an illustration: My problem is, I need to navigate between View A and View B then when I dismiss either of them it will got back to FrontViewController. Like a child of a child View. Thanks.

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  • Should a service layer return view models for an MVC application?

    - by erg39
    Say you have an ASP.NET MVC project and are using a service layer, such as in this contact manager tutorial on the asp.net site: http://www.asp.net/mvc/tutorials/iteration-4-make-the-application-loosely-coupled-cs If you have viewmodels for your views, is the service layer the appropriate place to provide each viewmodel? For instance, in the service layer code sample there is a method public IEnumerable<Contact> ListContacts() { return _repository.ListContacts(); } If instead you wanted a IEnumerable, should it go in the service layer, or is there somewhere else that is the "correct" place? Perhaps more appropriately, if you have a separate viewmodel for each view associated with ContactController, should ContactManagerService have a separate method to return each viewmodel? If the service layer is not the proper place, where should viewmodel objects be initialized for use by the controller?

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  • Simple addView problem

    - by Buyin Brian
    Hi there. I have a simple addView problem that is driving me nuts, I know I am overlooking something simple, perhaps another set of eyes can help. I have a Nib with a view that has a class identity set to TestView In my view controller, I use the following code: CGRect myRect = CGRectMake(0, 0, 320,240); TestView *myTest = [[TestView alloc] initWithFrame:myRect]; [self.view addSubview:myTest]; I have a NSLog in the TestView class's initWithFrame that fires when the above code is executed, but the view doesn't appear in the view controllers view. Thanks for your help.

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  • ASP.NET MVC 2 Model object validation

    - by Jimmy
    Hey guys, I'm trying to validate a model object outside of the context of ModelState within a controller, I currently have a parser that creates model objects from an excel file and I want to be able to report how many entries were added to the database and how many failed, is there a way to validate a model object on its data annotations outside of model binding? I'm looking for something similar to the rails model method of model.valid? or a way for me to implement that myself. My current solution is just manually checking if a few key fields are present but this duplicates requirements between my model class and its metadata, there has to be a better way to hook into the model validation checking that is done by mvc 2. Thanks

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  • Grails external Jms broker (active mq)

    - by TheBigS
    I have what will become an 'external' activemq server I'd like grails to be able to talk to. Right now I am just running it on my dev box. Here is what I have setup right now: 1) Run activemq server 2) Run activemq/examples using ant to produce messages 3) View ActiveMQ admin site: http://localhost:8161/admin/queues.jsp verify that messages are in the queue. 4) Follow Mini Tutorial to create the Service and Controller: http://www.grails.org/ActiveMQ+Plugin 5) Configured my Grails resources.groovy file as follows: beans = { jmsConnectionFactory(SingleConnectionFactory){ targetConnectionFactory = { ActiveMQConnectionFactory cf -> brokerURL = 'tcp://localhost:61616' } } } When I run the grails app I get a BindException saying port 61616 is already in use. How do I configure this to use my server that is already running? I've tried changing 'localhost' to '127.0.0.1' and to my LAN ip, but no luck, it keeps trying to setup its own embedded activemq server. Any ideas?

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  • What do I need to change to get this 'acts_as_rateable' Rails plugin working with this code from the

    - by tepidsam
    Hello! I'm working my way through the 'Foundation Rails 2' book. In Chapter 9, we are building a little "plugins" app. In the book, he installs the acts_as_rateable plugin found at http://juixe.com/svn/acts_as_rateable. This plugin doesn't appear to exist in 2010 (the page for this "old" plugin seems to be working again...it was down when I tried it earlier), so I found another acts_as_rateable plugin at http://github.com/azabaj/acts_as_rateable. These plugins are different and I'm trying to get the "new" plugin working with the code/project/app from the Foudations 2 book. I was able to use the migration generator included with the "new" plugin and it worked. Now,though, I'm a bit confused. In the book, he has us create a new controller to work with the plugin (the old plugin). Here's the code for that: class RatingsController < ApplicationController def create @plugin = Plugin.find(params[:plugin_id]) rating = Rating.new(:rating => params[:rating]) @plugin.ratings << average_rating redirect_to @plugin end end Then he had us change the routing: map.resources :plugins, :has_many => :ratings map.resources :categories map.root :controller => 'plugins' Next, we modified the following to the 'show' template so that it looks like this: <div id="rate_plugin"> <h2>Rate this plugin</h2> <ul class="star-rating"> <li> <%= link_to "1", @plugin.rate_it(1), :method => :post, :title => "1 star out of 5", :class => "one-star" %> </li> <li> <%= link_to "2", plugin_ratings_path(@plugin, :rating => 2), :method => :post, :title => "2 stars out of 5", :class => "two-stars" %> </li> <li> <%= link_to "3", plugin_ratings_path(@plugin, :rating => 3), :method => :post, :title => "3 stars out of 5", :class => "three-stars" %> </li> <li> <%= link_to "4", plugin_ratings_path(@plugin, :rating => 4), :method => :post, :title => "4 stars out of 5", :class => "four-stars" %> </li> <li> <%= link_to "5", plugin_ratings_path(@plugin, :rating => 5), :method => :post, :title => "5 stars out of 5", :class => "five-stars" %> </li> </ul> </div> The problem is that we're using code for a different plugin. When I try to actually "rate" one of the plugins, I get an "unknown attribute" error. That makes sense. I'm using attribute names for the "old" plugin, but I should be using attributes names for the "new" plugin. The problem is...I've tried using a variety of different attribute names and I keep getting the same error. From the README for the "new" plugin, I think I should be using some of these but I haven't been able to get them working: Install the plugin into your vendor/plugins directory, insert 'acts_as_rateable' into your model, then restart your application. class Post < ActiveRecord::Base acts_as_rateable end Now your model is extended by the plugin, you can rate it ( 1-# )or calculate the average rating. @plugin.rate_it( 4, current_user.id ) @plugin.average_rating #=> 4.0 @plugin.average_rating_round #=> 4 @plugin.average_rating_percent #=> 80 @plugin.rated_by?( current_user ) #=> rating || false Plugin.find_average_of( 4 ) #=> array of posts See acts_as_rateable.rb for further details! I'm guessing that I might have to make some "bigger" changes to get this plugin working. I'm asking this question to learn and only learn. The book gives code to get things working with the old plugin, but if one were actually building this app today it would be necessary to use this "new" plugin, so I would like to see how it could be used. Cheers! Any ideas on what I could change to get the "new" plugin working?

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  • Making a zend routes default paramaters display in the URL

    - by NaNuk
    I have a route defined as below. $route['manage-vehicles'] = new Zend_Controller_Router_Route( 'vehicles/manage/page/:page', array( 'controller' => 'vehicles', 'action' => 'manage', 'page' => '1' ) ); When the 'page' parameter is not specifically defined (e.g. in a menu constructed using the navigation component), the resultant URL is /vehicles/manage/page I would much prefer or the URL not to to display the default paramater key in this scenario i.e. /vehicles/manage Any ideas how to accomplish this would be appreciated? Thanks.

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  • Want to save data field from form into two columns of two models.

    - by vette982
    I have a Profile model with a hasOne relationship to a Detail model. I have a registration form that saves data into both model's tables, but I want the username field from the profile model to be copied over to the usernamefield in the details model so that each has the same username. function new_account() { if(!empty($this->data)) { $this->Profile->modified = date("Y-m-d H:i:s"); if($this->Profile->save($this->data)) { $this->data['Detail']['profile_id'] = $this->Profile->id; $this->data['Detail']['username'] = $this->Profile->username; $this->Profile->Detail->save($this->data); $this->Session->setFlash('Your registration was successful.'); $this->redirect(array('action'=>'index')); } } } This code in my Profile controller gives me the error: Undefined property: Profile::$username Any ideas?

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  • findBy(x) Using Zend_Navigation with custom route

    - by Stephen
    I am creating my navigation from a db generated array and defining which route to use for some of the uris. when I set the route i am no longer able to use findByUri() as the uri seems to be moved under the properties key example array being used: [id] => 7 [label] => Legal [controller] => index [uri] => /legal [route] => cmsPage [visible] => 1 [params] => Array ( [first] => legal ) snippet of the output: [_properties:protected] => Array ( [uri] => /legal [created] => 2012-10-20 10:23:23 ) When I don't define the route I am able to use findByUri() successfully. currently I am looping through each to find the property that matches the request but it seems a long / wrong approach Is there a way to search by the nested param - or am i doing something wrong with the setup (everything else behaves as expected)

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