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  • Writing a blocking wrapper around twisted's IRC client

    - by Andrey Fedorov
    I'm trying to write a dead-simple interface for an IRC library, like so: import simpleirc connection = simpleirc.Connect('irc.freenode.net', 6667) channel = connection.join('foo') find_command = re.compile(r'google ([a-z]+)').findall for msg in channel: for t in find_command(msg): channel.say("http://google.com/search?q=%s" % t) Working from their example, I'm running into trouble (code is a bit lengthy, so I pasted it here). Since the call to channel.__next__ needs to be returned when the callback <IRCClient instance>.privmsg is called, there doesn't seem to be a clean option. Using exceptions or threads seems like the wrong thing here, is there a simpler (blocking?) way of using twisted that would make this possible?

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  • Django: Serving Media Behind Custom URL

    - by TheLizardKing
    So I of course know that serving static files through Django will send you straight to hell but I am confused on how to use a custom url to mask the true location of the file using Django. http://stackoverflow.com/questions/2681338/django-serving-a-download-in-a-generic-view but the answer I accepted seems to be the "wrong" way of doing things. urls.py: url(r'^song/(?P<song_id>\d+)/download/$', song_download, name='song_download'), views.py: def song_download(request, song_id): song = Song.objects.get(id=song_id) fsock = open(os.path.join(song.path, song.filename)) response = HttpResponse(fsock, mimetype='audio/mpeg') response['Content-Disposition'] = "attachment; filename=%s - %s.mp3" % (song.artist, song.title) return response This solution works perfectly but not perfectly enough it turns out. How can I avoid having a direct link to the mp3 while still serving through nginx/apache? EDIT 1 - ADDITIONAL INFO Currently I can get my files by using an address such as: http://www.example.com/music/song/1692/download/ But the above mentioned method is the devil's work. How can I accomplished what I get above while still making nginx/apache serve the media? Is this something that should be done at the webserver level? Some crazy mod_rewrite? http://static.example.com/music/Aphex%20Twin%20-%20Richard%20D.%20James%20(V0)/10%20Logon-Rock%20Witch.mp3

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  • Reliable and fast way to convert a zillion ODT files in PDF?

    - by Marco Mariani
    I need to pre-produce a million or two PDF files from a simple template (a few pages and tables) with embedded fonts. Usually, I would stay low level in a case like this, and compose everything with a library like ReportLab, but I joined late in the project. Currently, I have a template.odt and use markers in the content.xml files to fill with data from a DB. I can smoothly create the ODT files, they always look rigth. For the ODT to PDF conversion, I'm using openoffice in server mode (and PyODConverter w/ named pipe), but it's not very reliable: in a batch of documents, there is eventually a point after which all the processed files are converted into garbage (wrong fonts and letters sprawled all over the page). Problem is not predictably reproducible (does not depend on the data), happens in OOo 2.3 and 3.2, in Ubuntu, XP, Server 2003 and Windows 7. My Heisenbug detector is ticking. I tried to reduce the size of batches and restarting OOo after each one; still, a small percentage of the documents are messed up. Of course I'll write about this on the Ooo mailing lists, but in the meanwhile, I have a delivery and lost too much time already. Where do I go? Completely avoid the ODT format and go for another template system. Suggestions? Anything that takes a few seconds to run is way too slow. OOo takes around a second and it sums to 15 days of processing time. I had to write a program for clustering the jobs over several clients. Keep the format but go for another tool/program for the conversion. Which one? There are many apps in the shareware or commercial repositories for windows, but trying each one is a daunting task. Some are too slow, some cannot be run in batch without buying it first, some cannot work from command line, etc. Open source tools tend not to reinvent the wheel and often depend on openoffice. Converting to an intermediate .DOC format could help to avoid the OOo bug, but it would double the processing time and complicate a task that is already too hairy. Try to produce the PDFs twice and compare them, discarding the whole batch if there's something wrong. Although the documents look equal, I know of no way to compare the binary content. Restart OOo after processing each document. it would take a lot more time to produce them it would lower the percentage of the wrong files, and make it very hard to identify them. Go for ReportLab and recreate the pages programmatically. This is the approach I'm going to try in a few minutes. Learn to properly format bulleted lists Thanks a lot.

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  • Rewriting Live TCP Streams

    - by user213060
    I want to rewrite TCP/IP streams. Ettercap's etterfilter command lets you perform simple live replacements of TCP/IP data based on fixed strings or regexes. Example: http://ettercap.sourceforge.net/forum/viewtopic.php?t=2833 I would like to rewrite streams based on my own filter program instead of just simple string replacements. Anyone have an idea of how to do this? Is there anything other than Ettercap that can do live replacement like this, maybe as a plugin to a VPN software or something? Thanks!

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  • installing simplejson on the google appengine

    - by user266564
    Super nub question time! I am trying to use simplejson on the google appengine. In a terminal on my machine I have simplejson installed and working. But my when I try to import it in a script running on the appengine I get an error saying no such library exists. If open the interactive console on my machine (from the link on http://localhost:8080/_ah/admin) and type "import simplejson" I get: Traceback (most recent call last): File "/home/chris/google_appengine/google/appengine/ext/admin/init.py", line 210, in post exec(compiled_code, globals()) File "", line 1, in ImportError: No module named simplejson Any thoughts?

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  • wx Menu disappears from frame when shown as a popup

    - by Adam Fraser
    I'm trying to create a wx.Menu that will be shared between a popup (called on right-click), and a sub menu accessible from the frame menubar. The following code demonstrates the problem. If you open the "MENUsubmenu" from the menubar the item "asdf" is visible. If you right click on the frame content area, "asdf" will be visible from there as well... however, returning to the menubar, you will find that "MENUsubmenu" is vacant. Why is this happening and how can I fix it? import wx app = wx.PySimpleApp() m = wx.Menu() m.Append(-1, 'asdf') def show_popup(evt): ''' R-click callback ''' f.PopupMenu(m, (evt.X, evt.Y)) f = wx.Frame(None) f.SetMenuBar(wx.MenuBar()) frame_menu = wx.Menu() f.MenuBar.Append(frame_menu, 'MENU') frame_menu.AppendMenu(-1,'submenu', m) f.Show() f.Bind(wx.EVT_RIGHT_DOWN, show_popup) app.MainLoop() Interestingly, appending the menu to MenuBar works, but is not the behavior I want: import wx app = wx.PySimpleApp() m = wx.Menu() m.Append(-1, 'asdf') def show_popup(evt): f.PopupMenu(m, (evt.X, evt.Y)) f = wx.Frame(None) f.SetMenuBar(wx.MenuBar()) f.MenuBar.Append(m, 'MENU') f.Show() f.Bind(wx.EVT_RIGHT_DOWN, show_popup) app.MainLoop()

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  • import webkit fails with an ImportError

    - by Stuart K
    When I import webkit on Ubuntu 10.04 I get the following error: Traceback (most recent call last): File "test.py", line 1, in <module> import webkit File "/usr/lib/pymodules/python2.6/webkit/__init__.py", line 19, in <module> import webkit ImportError: /usr/lib/pymodules/python2.6/webkit/webkit.so: undefined symbol: webkit_web_frame_get_global_context I think all the packages I need are installed. Does anyone have an idea of why this is failing?

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  • Start PyGTK cellrenderer edit from code

    - by mkotechno
    I have a treeview with an editable CellRendererText: self.renderer = gtk.CellRendererText() self.renderer.set_property('editable', True) But now I need to launch the edition from code instead from user, this is to focus the user attention in the fact he just created a new row and needs to be named. I tried this but does not work: self.renderer.start_editing( gtk.gdk.Event(gtk.gdk.NOTHING), self.treeview, str(index), gtk.gdk.Rectangle(), gtk.gdk.Rectangle(), 0) Neither does not throw errors, but the documentation about for what is each argument is not clear, in fact I really don't know if start_editing method is for this. All suggestions are welcome, thanks.

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  • What is going on with the "return fibonacci( number-1 ) + fibonacci( number-2 )"?

    - by user1478598
    I have problem understanding what the return fibonacci( number-1 ) + fibonacci( number-2 ) does in the following program: import sys def fibonacci( number ): if( number <= 2 ): return 1 else: return fibonacci( number-1 ) + fibonacci( number-2 ) The problem is that I can't imagine how this line works: return fibonacci( number-1 ) + fibonacci( number-2 ) Does the both of the "fibonacci( number-1 )" and "fibonacci( number-2 )" being processed at the same time? or the "fibonacci( number-1 )" is the first to be processed and then the second one? I only see that processing both of them would eventually return '1' so the last result I expect to see it is a '1 + 1' = '2' I would appreciate a lot, If someone can elaborately explain the process of its calculation. I think this is a very newb question but I can't really get a picture of its process.

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  • Loading Files in AppEngine

    - by Chris M
    I've got a tiny bit of code to display a file in app.yaml - url: /(.*\.(gif|png|jpg)) static_files: static/\1 upload: static/(.*\.(gif|png|jpg)) in main.py ... class ShowImage(webapp.RequestHandler): def get(self): rootpath = os.path.dirname(__file__) file = rootpath + "/static/tracker.gif"; fh=open(file, 'r') self.response.out.write(fh.read()) fh.close ... I can see the files gone up by going to my *.appspot.com/tracker.gif (as per the app.yaml) But using *.appspot.com/showimage returns Traceback (most recent call last): File "/base/python_lib/versions/1/google/appengine/ext/webapp/__init__.py", line 510, in __call__ handler.get(*groups) File "/base/data/home/apps/APPNAME/2.341131266814384624/main.py", line 170, in get fh=open(file, 'r') IOError: [Errno 2] No such file or directory: '/base/data/home/apps/APPNAME/2.341131266814384624/static/tracker.gif'

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  • [Gdata] GetAuthSubToken returns None

    - by Matt
    Hey guys, I am a little lost on how to get the auth token. Here is the code I am using on the return from authorizing my app: client = gdata.service.GDataService() gdata.alt.appengine.run_on_appengine(client) sessionToken = gdata.auth.extract_auth_sub_token_from_url(self.request.uri) client.UpgradeToSessionToken(sessionToken) logging.info(client.GetAuthSubToken()) what gets logged is "None" so that does seem right :-( if I use this: temp = client.upgrade_to_session_token(sessionToken) logging.info(dump(temp)) I get this: {'scopes': ['http://www.google.com/calendar/feeds/'], 'auth_header': 'AuthSub token=CNKe7drpFRDzp8uVARjD-s-wAg'} so I can see that I am getting a AuthSub Token and I guess I could just parse that and grab the token but that doesn't seem like the way things should work. If I try to use AuthSubTokenInfo I get this: Traceback (most recent call last): File "/Applications/GoogleAppEngineLauncher.app/Contents/Resources/GoogleAppEngine-default.bundle/Contents/Resources/google_appengine/google/appengine/ext/webapp/__init__.py", line 507, in __call__ handler.get(*groups) File "controllers/indexController.py", line 47, in get logging.info(client.AuthSubTokenInfo()) File "/Users/matthusby/Dropbox/appengine/projects/FBCal/gdata/service.py", line 938, in AuthSubTokenInfo token = self.token_store.find_token(scopes[0]) TypeError: 'NoneType' object is unsubscriptable so it looks like my token_store is not getting filled in correctly, is that something I should be doing? Also I am using gdata 2.0.9 Thanks Matt

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  • Django: How to create a model dynamically just for testing

    - by muhuk
    I have a Django app that requires a settings attribute in the form of: RELATED_MODELS = ('appname1.modelname1.attribute1', 'appname1.modelname2.attribute2', 'appname2.modelname3.attribute3', ...) Then hooks their post_save signal to update some other fixed model depending on the attributeN defined. I would like to test this behaviour and tests should work even if this app is the only one in the project (except for its own dependencies, no other wrapper app need to be installed). How can I create and attach/register/activate mock models just for the test database? (or is it possible at all?) Solutions that allow me to use test fixtures would be great.

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  • How to share memory buffer across sessions in Django?

    - by afriza
    I want to have one party (or more) sends a stream of data via HTTP request(s). Other parties will be able to receive the same stream of data in almost real-time. The data stream should be accessible across sessions (according to access control list). How can I do this in Django? If possible I would like to avoid database access and use in memory buffer (along with some synchronization mechanism)

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  • cannot output a json encoded dict containing accents (noob inside)

    - by user296546
    Hi all, here is a fairly simple example wich is driving me nuts since a couple of days. Considering the following script: # -*- coding: utf-8 -* from json import dumps as json_dumps machaine = u"une personne émérite" print(machaine) output = {} output[1] = machaine jsonoutput = json_dumps(output) print(jsonoutput) The result of this from cli: une personne émérite {"1": "une personne \u00e9m\u00e9rite"} I don't understand why their such a difference between the two strings. i have been trying all sorts of encode, decode etc but i can't seem to be able to find the right way to do it. Does anybody has an idea ? Thanks in advance. Matthieu

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  • stdout and stderr anomalies

    - by momo
    from the interactive prompt: >>> import sys >>> sys.stdout.write('is the') is the6 what is '6' doing there? another example: >>> for i in range(3): ... sys.stderr.write('new black') ... 9 9 9 new blacknew blacknew black where are the numbers coming from?

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  • PDB: exception when in console - full stack trace

    - by EoghanM
    When at the pdb console, entering a statement which causes an exception results in just a single line stack trace, e.g. (Pdb) someFunc() *** TypeError: __init__() takes exactly 2 arguments (1 given) However I'd like to figure out where exactly in someFunc the error originates. i.e. in this case, which class __init__ is attached to. Is there a way to get a full stack trace in Pdb?

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  • Assignment to None

    - by Joel
    Hello, I have a function which returns 3 numbers, e.g.: def numbers(): return 1,2,3 usually I call this function to receive all three returned numbers e.g.: a,b,c=numbers() However, I have one case in which I only need the first returned number. I tried using: a, None None = numbers() But I receive "SyntaxError: assignment to None". I know, of course, that i can use the first option I mentioned and then not use "b" and "c", but only "a". However, this seems like a "waste" of two vars and feels like wrong programming. Any ideas? Thanks, Joek

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  • do I need to use partial?

    - by wiso
    I've a general function, for example (only a simplified example): def do_operation(operation, a, b, name): print name do_something_more(a,b,name, operation(a,b)) def operation_x(a,b): return a**2 + b def operation_y(a,b): return a**10 - b/2. and some data: data = {"first": {"name": "first summation", "a": 10, "b": 20, "operation": operation_x}, "second": {"name": "second summation", "a": 20, "b": 50, "operation": operation_y}, "third": {"name": "third summation", "a": 20, "b": 50, "operation": operation_x}, # <-- operation_x again } now I can do: what_to_do = ("first", "third") # this comes from command line for sum_id in what_to_do: do_operation(data["operation"], data["a"], data["b"], data["name"]) or maybe it's better if I use functools.partial? from functools import partial do_operation_one = do_operation(name=data["first"]["name"], operation=data["first"]["operation"], a=data["first"]["a"], b=data["first"]["b"]) do_operation_two = do_operation(name=data["second"]["name"], operation=data["second"]["operation"] a=data["second"]["a"], b=data["second"]["b"]) do_operation_three = do_operation(name=data["third"]["name"], operation=data["third"]["operation"] a=data["third"]["a"], b=data["third"]["b"]) do_dictionary = { "first": do_operation_one, "second": do_operation_two, "third": do_operation_three } for what in what_to_do: do_dictionary[what]()

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  • How to "signal" interested child processes (without signals)?

    - by Teddy
    I'm trying to find a good and simple method to signal child processes (created through SocketServer with ForkingMixIn) from the parent process. While Unix signals could be used, I want to avoid them since only children who are interested should receive the signal, and it would be overkill and complicated to require some kind of registration mechanism to identify to the parent process who is interested. (Please don't suggest threads, as this particular program won't work with threads, and thus has to use forks.)

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  • Polynomial fitting with log log plot

    - by viral parekh
    I have a simple problem to fit a straight line on log-log scale. My code is, data=loadtxt(filename) xdata=data[:,0] ydata=data[:,1] polycoeffs = scipy.polyfit(xdata, ydata, 1) yfit = scipy.polyval(polycoeffs, xdata) pylab.plot(xdata, ydata, 'k.') pylab.plot(xdata, yfit, 'r-') Now I need to plot fit line on log scale so I just change x and y axis, ax.set_yscale('log') ax.set_xscale('log') then its not plotting correct fit line. So how can I change fit function (in log scale) so that it can plot fit line on log-log scale? Thanks -Viral

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  • Infrastructure for a "news-feed"

    - by ensnare
    I'd like to offer a news-feed like feature for users of our website. When the user logs in, he is shown a list of the latest updates across various areas of the site. I'm afraid that this is going to be difficult to scale. What are some networking / database topologies that can support a scalable infrastructure without having lots of copies of the same data? (I'd like to make it so if a piece of data is updated, each user's feed is also updated live). Thanks for the assistance and advice.

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  • Displaying Google Calendar event data on FullCalendar

    - by aurealus
    I am using Google Calendar as a storage engine for a calendar system I am building, however, I am using a single Google user account with multiple calendars, i.e. each user on my system has their own calendar within the one user account. I'm able to create a calendar per user just fine, but I would like to have FullCalendar retrieve the events for display purposes, without manually getting the magic cookie url from Google Calendar settings. I would like to be able to retrieve it programmatically or 'proxy' the feed via an authenticated call to get event data that I'm doing in Django. $('#calendar').fullCalendar({ events: $.fullCalendar.gcalFeed( "http://www.google.com/calendar_url/" <-- or /my/event/feed/url ) });

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  • Google App Engine + Form Validation

    - by Iwona
    Hi, I would like to do google app engine form validation but I dont know how to do it? I tried like this: from google.appengine.ext.db import djangoforms from django import newforms as forms class SurveyForm(forms.Form): occupations_choices = ( ('1', ""), ('2', "Undergraduate student"), ('3', "Postgraduate student (MSc)"), ('4', "Postgraduate student (PhD)"), ('5', "Lab assistant"), ('6', "Technician"), ('7', "Lecturer"), ('8', "Other" ) ) howreach_choices = ( ('1', ""), ('2', "Typed the URL directly"), ('3', "Site is bookmarked"), ('4', "A search engine"), ('5', "A link from another site"), ('6', "From a book"), ('7', "Other") ) boxes_choices = ( ("des", "Website Design"), ("svr", "Web Server Administration"), ("com", "Electronic Commerce"), ("mkt", "Web Marketing/Advertising"), ("edu", "Web-Related Education") ) name = forms.CharField(label='Name', max_length=100, required=True) email = forms.EmailField(label='Your Email Address:') occupations = forms.ChoiceField(choices=occupations_choices, label='What is your occupation?') howreach = forms.ChoiceField(choices=howreach_choices, label='How did you reach this site?') # radio buttons 1-5 rating = forms.ChoiceField(choices=range(1,6), label='What is your occupation?', widget=forms.RadioSelect) boxes = forms.ChoiceField(choices=boxes_choices, label='Are you involved in any of the following? (check all that apply):', widget=forms.CheckboxInput) comment = forms.CharField(widget=forms.Textarea, required=False) And I wanted to display it like this: template_values = { 'url' : url, 'url_linktext' : url_linktext, 'userName' : userName, 'item1' : SurveyForm() } And I have this error message: Traceback (most recent call last): File "C:\Program Files\Google\google_appengine\google\appengine\ext\webapp_init_.py", line 515, in call handler.get(*groups) File "C:\Program Files\Google\google_appengine\demos\b00213576\main.py", line 144, in get self.response.out.write(template.render(path, template_values)) File "C:\Program Files\Google\google_appengine\google\appengine\ext\webapp\template.py", line 143, in render return t.render(Context(template_dict)) File "C:\Program Files\Google\google_appengine\google\appengine\ext\webapp\template.py", line 183, in wrap_render return orig_render(context) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 168, in render return self.nodelist.render(context) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 705, in render bits.append(self.render_node(node, context)) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 718, in render_node return(node.render(context)) File "C:\Program Files\Google\google_appengine\lib\django\django\template\defaulttags.py", line 209, in render return self.nodelist_true.render(context) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 705, in render bits.append(self.render_node(node, context)) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 718, in render_node return(node.render(context)) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 768, in render return self.encode_output(output) File "C:\Program Files\Google\google_appengine\lib\django\django\template_init_.py", line 757, in encode_output return str(output) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\util.py", line 26, in str return self.unicode().encode(settings.DEFAULT_CHARSET) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\forms.py", line 73, in unicode return self.as_table() File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\forms.py", line 144, in as_table return self._html_output(u'%(label)s%(errors)s%(field)s%(help_text)s', u'%s', '', u'%s', False) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\forms.py", line 129, in _html_output output.append(normal_row % {'errors': bf_errors, 'label': label, 'field': unicode(bf), 'help_text': help_text}) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\forms.py", line 232, in unicode value = value.str() File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\util.py", line 26, in str return self.unicode().encode(settings.DEFAULT_CHARSET) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\widgets.py", line 246, in unicode return u'\n%s\n' % u'\n'.join([u'%s' % w for w in self]) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\widgets.py", line 238, in iter yield RadioInput(self.name, self.value, self.attrs.copy(), choice, i) File "C:\Program Files\Google\google_appengine\lib\django\django\newforms\widgets.py", line 212, in init self.choice_value = smart_unicode(choice[0]) TypeError: 'int' object is unsubscriptable Do You have any idea how I can do this validation in different case? I have tried to do it using this kind of: class ItemUserAnswer(djangoforms.ModelForm): class Meta: model = UserAnswer But I dont know how to add extra labels to this form and it is displayed in one line. Do You have any suggestions? Thanks a lot as it making me crazy why it is still not working:/

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