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  • scripting a google docs form submission

    - by justSteve
    I'm trying to create a bookmarklet that parses a page and sends the results to a googledocs spreadsheet via a form that I've defined. The relevent bit of the script is: var form = document.createElement("form"); form.action = "http://spreadsheets.google.com/formResponse?formkey=Fd0SHgwQ3YwSFd5UHZpM1QxMlNOdlE6MA&ifq"; form.method = "POST"; form.id="ss-form"; form.innerHTML = ["<input id='entry_0' name = 'entry.0.single' value = '" + orderDate + "'/>", "<input name = 'entry.2.single' value = '" + email + "'/>", "<input name = 'entry.3.single' value = '" + customerID + "'/>", ].join(""); form.submit(); alert(form.innerHTML); // returns: Nothing is being saved to the form via the bookmarklet - any way to capture google's response in my bookmarklet's code? (fwiw, i've injected jQuery via jQueryify) EDIT: Firebug's Net panel isn't hearing any of the activity triggered by the bookmarklet - How about i approach this from goolgle's viewform method instead of formresponse. The form i'm trying to submit is located at: http://spreadsheets.google.com/viewform?hl=en&formkey=dFd0SHgwQ3YwSFd5UHZpM1QxMlNOdlE6MA How can I go about injecting the script values into that form and then submitting that - again...via script within the bookmarklet that would have been triggered while on the page being parsed?

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  • JQuery Validation Plugin: Prevent validation issue on nested form

    - by Majid
    I have a form on which I use validation. This form has a section for photo upload. Initially this section contains six elements with the following code: <img class="photo_upload" src="image/app/photo_upload.jpg"> I have bound a function to the click event for the class of photo_upload. This function replaces the image with a minimal form with this code: Copy code <form onsubmit="startUploadImage();" target="control_target" enctype="multipart/form-data" method="post" action="index.php"> <input type="hidden" value="add_image" name="service"> <input type="hidden" value="1000000" name="MAX_FILE_SIZE"> <input type="file" size="10" name="photo" id="photo_file_upload"><br> <button onclick="javascript:cancel_photo_upload();return false;">Cancel</button> </form> So, essentially, after the image is clicked, I'd have a new form nested in my original, validated form. Now, when I use this new form and upload an image, I receive an error (repeated three times) saying: validator is undefined http://host.com/path/index.php Line 286 What is going on here? My guess is this Submit event bubbles up to the outer form As we have validation on that form, validation is triggered, Validation tries to find the form triggering it, Since we have not bound validation to the inner form it returns 'undefined' Now, is my assessment correct? Whether it is or not, how can I solve this issue?

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  • How to return id of a submitted form using Prototype?

    - by pstinnett
    I have a page that has several ajax submission forms. Each form has a dynamic id assigned to it when it's written to the page. Does anyone know if there is an easy way to return the id of the form that is being submitted? I'm basically looking to click "submit" and alert the id of the submitted form. From there I can use it in the ajax onSuccess function.

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  • How to finish a broken data upload to the production Google App Engine server?

    - by WooYek
    I was uploading the data to App Engine (not dev server) through loader class and remote api, and I hit the quota in the middle of a CSV file. Based on logs and progress sqllite db, how can I select remaining portion of data to be uploaded? Going through tens of records to determine which was and which was not transfered, is not appealing task, so I look for some way to limit the number of record I need to check. Here's relevant (IMO) log portion, how to interpret work item numbers? [DEBUG 2010-03-30 03:22:51,757 bulkloader.py] [Thread-2] [1041-1050] Transferred 10 entities in 3.9 seconds [DEBUG 2010-03-30 03:22:51,757 adaptive_thread_pool.py] [Thread-2] Got work item [1071-1080] <cut> [DEBUG 2010-03-30 03:23:09,194 bulkloader.py] [Thread-1] [1141-1150] Transferred 10 entities in 4.6 seconds [DEBUG 2010-03-30 03:23:09,194 adaptive_thread_pool.py] [Thread-1] Got work item [1161-1170] <cut> [DEBUG 2010-03-30 03:23:09,226 bulkloader.py] [Thread-3] [1151-1160] Transferred 10 entities in 4.2 seconds [DEBUG 2010-03-30 03:23:09,226 adaptive_thread_pool.py] [Thread-3] Got work item [1171-1180] [ERROR 2010-03-30 03:23:10,174 bulkloader.py] Retrying on non-fatal HTTP error: 503 Service Unavailable

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  • Basic File upload in GWT

    - by Maksim
    I'm trying to figure out how to upload one file using GWTs FileUpload widget. I'm using GWT and Google AppEngine with Java but I would like to upload file to my own Linux server. I have the following code already but now I can't figure out how to submit my file to the Google AppServer server and save it to another server: public class FileUploader{ private ControlPanel cp; private FormPanel form = new FormPanel(); private FileUpload fu = new FileUpload(); public FileUploader(ControlPanel cp) { this.cp = cp; this.cp.setPrimaryArea(getFileUploaderWidget()); } @SuppressWarnings("deprecation") public Widget getFileUploaderWidget() { form.setEncoding(FormPanel.ENCODING_MULTIPART); form.setMethod(FormPanel.METHOD_POST); // form.setAction(/* WHAT SHOULD I PUT HERE */); VerticalPanel holder = new VerticalPanel(); fu.setName("upload"); holder.add(fu); holder.add(new Button("Submit", new ClickHandler() { public void onClick(ClickEvent event) { GWT.log("You selected: " + fu.getFilename(), null); form.submit(); } })); form.addSubmitHandler(new FormPanel.SubmitHandler() { public void onSubmit(SubmitEvent event) { if (!"".equalsIgnoreCase(fu.getFilename())) { GWT.log("UPLOADING FILE????", null); // NOW WHAT???? } else{ event.cancel(); // cancel the event } } }); form.addSubmitCompleteHandler(new FormPanel.SubmitCompleteHandler() { public void onSubmitComplete(SubmitCompleteEvent event) { Window.alert(event.getResults()); } }); form.add(holder); return form; } } Now, what do I need to do next? What do i need to put in web.xml and how do I write my servlet so i can store file and return url of that object (if possible)

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  • I can't upload mp3 files using Codeigniter

    - by Drew
    There are lots of suggested fixes for this but none of them work for me. I have tried making the upload class (using the following methods: http://codeigniter.com/forums/viewthread/148605/ and http://codeigniter.com/forums/viewthread/125441/). When i try to upload an mp3 i get the error message "The filetype you are attempting to upload is not allowed". Below is my code for my model and my form (i've got a very skinny controller). If someone could help me out with this I would be eternally grateful. --Model-- function do_upload() { $soundfig['upload_path'] = './uploads/nav'; $soundfig['allowed_types'] = 'mp3'; $this->load->library('upload', $soundfig); if ( ! $this->upload->do_upload()) { $error = array('error' => $this->upload->display_errors()); return $error; } else { /* $data = $this->upload->data('userfile'); */ $sound = $this->upload->data(); /* $full_path = 'uploads/nav/' . $data['file_name']; */ $sound_path = 'uploads/nav/' . $sound['file_name']; if($this->input->post('active') == '1'){ $active = '1'; }else{ $active = '0'; } $spam = array( /* 'image_url' => $full_path, */ 'sound' => $sound_path, 'active' => $active, 'url' => $this->input->post('url') ); $id = $this->input->post('id'); $this->db->where('id', $id); $this->db->update('NavItemData', $spam); return true; } } --View - Form-- <?php echo form_open_multipart('upload/do_upload');?> <?php if(isset($buttons)) : foreach($buttons as $row) : ?> <h2><?php echo $row->name; ?></h2> <!-- <input type="file" name="userfile" size="20" /><br /> --> <input type="file" name="userfile" size="20" /> <input type="hidden" name="oldfile" value="<?php echo $row->image_url; ?>" /> <input type="hidden" name="id" value="<?php echo $row->id; ?>" /> <br /><br /> <label>Url: </label><input type="text" name="url" value="<?php echo $row->url; ?>" /><br /> <input type="checkbox" name="active" value="1" <?php if($row->active == '1') { echo 'checked'; } ?> /><br /><br /> <input type="submit" value="submit" /> </form> <?php endforeach; ?> <?php endif; ?>

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  • upload an m4a file in flex, saving it as a blob in oracle, and retrieving metadata info from it

    - by Angus
    Hi, I currently have a FileUpload.mxml component that uploads a .m4a to an oracle database, retrieves metadata from the file and saves the metadata info in the database. to acheive this I use FileReference() and set up, amoung others, the dispatcher.addEventListener(DataEvent.UPLOAD_COMPLETE_DATA, completeHandler); So the file is posted to a php file which saves it as a blob. Once the blob is saved, the script sends a message back to flex to dispatch the upload_complete_data event. In the complete handler, the metadata is then retreived by reading the value back from the database into a custom made meta data reader. The metadata info is then saved via flex. This seems a little long winded. Has anyone else successfully achieved this using a different way?

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  • Retrieving models from form with ModelMultipleChoiceField

    - by colinjameswebb
    I am having difficulties with forms, specifically ModelMultipleChoiceField. I've pieced together this code from various examples, but it sadly doesn't work. I would like to be able to: Search for some Works on work_search.html Display the results of the search, with checkboxes next to each result Select the Works I want, via the checkboxes After pressing Add, display which works were selected. I believe everything is okay except the last part. The page simply displays "works" :( Here is the code - sorry about the length. Models.py class Work(models.Model): title = models.CharField(max_length=200) artist = models.CharField(max_length=200) writers = models.CharField(max_length=200) def __unicode__(self): return self.title + ' - ' + self.artist forms.py class WorkSelectForm(forms.Form): def __init__(self, queryset, *args, **kwargs): super(WorkSelectForm, self).__init__(*args, **kwargs) self.fields['works'] = forms.ModelMultipleChoiceField(queryset=queryset, widget=forms.CheckboxSelectMultiple()) views.py def work_search(request): query = request.GET.get('q', '') if query: qset = ( Q(title__icontains=query) | Q(artist__icontains=query) | Q(writers__icontains=query) ) results = Work.objects.filter(qset).distinct() form = WorkSelectForm(results) return render_to_response("work_search.html", {"form": form, "query": query }) else: results = [] return render_to_response("work_search.html", {"query": query }) def add_works(request): #if request.method == POST: form = WorkSelectForm(request.POST) #if form.isvalid(): items = form.fields['works'].queryset return render_to_response("add_works.html", {"items":items}) work_search.html {% extends "base.html" %} {% block content %} <h1>Search</h1> <form action="." method="GET"> <label for="q">Search: </label> <input type="text" name="q" value="{{ query|escape }}"> <input type="submit" value="Search"> </form> {% if query %} <h2>Results for "{{ query|escape }}":</h2> <form action="add_works" method="post"> <ul> {% if form %} {{ form.as_ul }} {% endif %} </ul> <input type="submit" value="Add"> </form> {% endif %} {% endblock %} add_works.html {% extends "base.html" %} {% block content %} {% if items %} {% for item in items %} {{ item }} {% endfor %} {% else %} <p>Nothing selected</p> {% endif %} {% endblock %}

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  • Resumable upload from Java client to Grails web application?

    - by dersteps
    After almost 2 workdays of Googling and trying several different possibilities I found throughout the web, I'm asking this question here, hoping that I might finally get an answer. First of all, here's what I want to do: I'm developing a client and a server application with the purpose of exchanging a lot of large files between multiple clients on a single server. The client is developed in pure Java (JDK 1.6), while the web application is done in Grails (2.0.0). As the purpose of the client is to allow users to exchange a lot of large files (usually about 2GB each), I have to implement it in a way, so that the uploads are resumable, i.e. the users are able to stop and resume uploads at any time. Here's what I did so far: I actually managed to do what I wanted to do and stream large files to the server while still being able to pause and resume uploads using raw sockets. I would send a regular request to the server (using Apache's HttpClient library) to get the server to send me a port that was free for me to use, then open a ServerSocket on the server and connect to that particular socket from the client. Here's the problem with that: Actually, there are at least two problems with that: I open those ports myself, so I have to manage open and used ports myself. This is quite error-prone. I actually circumvent Grails' ability to manage a huge amount of (concurrent) connections. Finally, here's what I'm supposed to do now and the problem: As the problems I mentioned above are unacceptable, I am now supposed to use Java's URLConnection/HttpURLConnection classes, while still sticking to Grails. Connecting to the server and sending simple requests is no problem at all, everything worked fine. The problems started when I tried to use the streams (the connection's OutputStream in the client and the request's InputStream in the server). Opening the client's OutputStream and writing data to it is as easy as it gets. But reading from the request's InputStream seems impossible to me, as that stream is always empty, as it seems. Example Code Here's an example of the server side (Groovy controller): def test() { InputStream inStream = request.inputStream if(inStream != null) { int read = 0; byte[] buffer = new byte[4096]; long total = 0; println "Start reading" while((read = inStream.read(buffer)) != -1) { println "Read " + read + " bytes from input stream buffer" //<-- this is NEVER called } println "Reading finished" println "Read a total of " + total + " bytes" // <-- 'total' will always be 0 (zero) } else { println "Input Stream is null" // <-- This is NEVER called } } This is what I did on the client side (Java class): public void connect() { final URL url = new URL("myserveraddress"); final byte[] message = "someMessage".getBytes(); // Any byte[] - will be a file one day HttpURLConnection connection = url.openConnection(); connection.setRequestMethod("GET"); // other methods - same result // Write message DataOutputStream out = new DataOutputStream(connection.getOutputStream()); out.writeBytes(message); out.flush(); out.close(); // Actually connect connection.connect(); // is this placed correctly? // Get response BufferedReader in = new BufferedReader(new InputStreamReader(connection.getInputStream())); String line = null; while((line = in.readLine()) != null) { System.out.println(line); // Prints the whole server response as expected } in.close(); } As I mentioned, the problem is that request.inputStream always yields an empty InputStream, so I am never able to read anything from it (of course). But as that is exactly what I'm trying to do (so I can stream the file to be uploaded to the server, read from the InputStream and save it to a file), this is rather disappointing. I tried different HTTP methods, different data payloads, and also rearranged the code over and over again, but did not seem to be able to solve the problem. What I hope to find I hope to find a solution to my problem, of course. Anything is highly appreciated: hints, code snippets, library suggestions and so on. Maybe I'm even having it all wrong and need to go in a totally different direction. So, how can I implement resumable file uploads for rather large (binary) files from a Java client to a Grails web application without manually opening ports on the server side?

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  • How to redirect to the current page with form in php?

    - by garcon1986
    Hello, I tried to redirect to the current page with form in my php application. Now i have met a problem. <form name="myform" action="?page=matching" method="GET"> <input id="match_button" type="submit" name="button" value="button" onClick="func_load3()" /> </form> action="?page=matching" means the current page, because i use the single entry in my php application. With the code upon, When i click the button, it redirects to the homepage. And I tried to use: <form name="myform" action="<?php echo $_SERVER['PHP_SELF']; ?>" method="GET"> but it still doesn't work. So i have to ask for help from you. Do you have any ideas about that? How to fix it? Thanks in advance.

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  • How can I retrieve the values of controls in the form that posted?

    - by Mike at KBS
    I know this has got to be the simplest-sounding question ever asked about ASP.Net but I'm baffled. I have a form wherein my visitor will enter name, address, etc. Then I am POSTing that form via the PostBackUrl property of my Submit button to another page, where the fields are supposed to be all re-formed into new hidden fields, then POSTed again to Paypal. My problem is I cannot get at the values entered by the visitor in the original page. Any time I put in "runat='server'", ASP.Net completely changes the ID of the control, making it impossible to figure out how to access. In the POSTed form I tried Request.Form["_txtFirstName"] and that turned up null. Then I tried ((TextBox)PreviousPage.FindControl("_txtFirstName")).Text and that was null, too. I've tried variations on those. I cannot figure out how I'm supposed to get at these controls. Why does this stuff need to be so difficult?

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  • Serializing form data with field names that have dots in them.

    - by Dave
    Does the serialize function in jQuery replace dots ('.') with underscores? For example, I have a form field such as: <input id="Project.name" name="Project.name" type="text"> When the form is POSTed, I'm serializing the form data and sending it to another PHP file to save. The dots seem to be converted to underscores. Is this normal behavior?

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  • How do I add descriptive text to form link .gif ?

    - by erynion
    I want to make the descriptive text around a form link also open the form. I want to make it so you can click on "Some Text Here" (below) and open the form on somesomite.com just as if you clicked on the image below this text (somebut.gif, below) <DIV style="position: absolute; top:10px; right:10px; width:70px; height:25px"> <font color="white"><b>Some Text Here<b></font> </div> <DIV style="position: absolute; top:50px; right:10px; width:70px; height:25px"> <form action="https://www.somesite.com/cgi-bin/something" method="post"> <input type="hidden" name="cmd" value="_s-xclick"> <input type="image" src="https://www.somesite.com/somebut.gif" border="0" name="submit"> <input type="hidden" name="encrypted" value="-----BEGIN PKCS7-----LONG_KEY...> </form> </div> Thanks

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  • Why is my form triggering the wrong controller action?

    - by COCoach
    This form has multiple submit buttons, when clicked, it calls a simple JavaScript function to change the value of a hidden input (function is called "setHidden". This worked before, after some other not relevant code, it has ceased working. Essentially, the action it is supposed to call is never called, instead it seems to default back to a previous URL. The Form: <form action="/League/RemoveOwner" method="post"> <input type="hidden" value="1007" name="lid"/> <input type="hidden" value="0" id="index" name="index"/> <input type="image" src="../../Resources/Images/Delete.png" height="12" alt="Remove Owner" title="Remove Owner" onclick="setHidden('index', '1031')"/></a> coach<br /> </form> The Controller: [HttpPost] public ActionResult RemoveOwner(int id, string index) { //yada return PartialView(); } When clicking the image, it should call the remove owner controller, instead it calls the "View" controller: public ActionResult View(int id) { //yada return View(); }

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  • How to upload an image to imageshark using curl?

    - by cinek1lol
    Hello: I wrote a program using curl.exe that sends pictures to imageshark and receives a link to the pictures. The problem that I have to specify the path to the image on the disk, and the rest of my so constructed that I have uploaded these pictures to a binary char array And I mean, I can send these pictures to char variable, and not giving the file path (you know what I mean?) Not too much know how to use it to save the library directly to curl. I'll be very grateful for any help sorry I know little English. wants to send a file loaded POST method to the variable char binary. Programs that are written above, send the file to disk. Do you understand what's going on? This is look like I would like to send the file in char variable, rather than on the hard disk I found the program, but he sends the entire file, and I would like to have it sent to the variable char dz

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  • How to send data after form has been validated using jQuery?

    - by Keith Donegan
    I have a simple email address sign up form as follows: <form action="" id="newsletterform" method="get"> <input type="text" name="email" class="required email" id="textnewsletter" /> <input type="submit" id="signup" /> </form> Here's what I want to be able to do: Validate the form to look for an empty string or a incorrectly filled out email address one the user clicks submit or hits enter. If one of the above happens (empty string etc), I would like to generate an error to let the user know. Then once the user fills out a correctly formed email address and hits submit (or enter) I want the form to send the email address to wherever I specify in the jQuery code and then generate a little "Thank you for signing up notice", all without reloading the browser. I have looked at too many tutorials and my eyes are pretty much aching at this stage, so please don't point me to any urls (I most likely have been there). If someone could provide a barebone outline of what to do It would be so much appreciated.

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  • File upload fails when user is authenticated. Using IIS7 Integrated mode.

    - by Nikkelmann
    These are the user identities my website tells me that it uses: Logged on: NT AUTHORITY\NETWORK SERVICE (Can not write any files at all) and Not logged on: WSW32\IUSR_77 (Can write files to any folder) I have a ASP.NET 4.0 website on a shared hosting IIS7 web server running in Integrated mode with 32-bit applications support enabled and MSSQL 2008. Using classic mode is not an option since I need to secure some static files and I use Routing. In my web.config file I have set the following: <system.webServer> <modules runAllManagedModulesForAllRequests="true" /> </system.webServer> My hosting company says that Impersonation is enabled by default on machine level, so this is not something I can change. I asked their support and they referred me to this article: http://www.codinghub.net/2010/08/differences-between-integrated-mode-and.html Citing this part: Different windows identity in Forms authentication When Forms Authentication is used by an application and anonymous access is allowed, the Integrated mode identity differs from the Classic mode identity in the following ways: * ServerVariables["LOGON_USER"] is filled. * Request.LogognUserIdentity uses the credentials of the [NT AUTHORITY\NETWORK SERVICE] account instead of the [NT AUTHORITY\INTERNET USER] account. This behavior occurs because authentication is performed in a single stage in Integrated mode. Conversely, in Classic mode, authentication occurs first with IIS 7.0 using anonymous access, and then with ASP.NET using Forms authentication. Thus, the result of the authentication is always a single user-- the Forms authentication user. AUTH_USER/LOGON_USER returns this same user because the Forms authentication user credentials are synchronized between IIS 7.0 and ASP.NET. A side effect is that LOGON_USER, HttpRequest.LogonUserIdentity, and impersonation no longer can access the Anonymous user credentials that IIS 7.0 would have authenticated by using Classic mode. How do I set up my website so that it can use the proper identity with the proper permissions? I've looked high and low for any answers regarding this specific problem, but found nil so far... I hope you can help!

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  • How to display records below form on submission in php without the use of database?

    - by OM The Eternity
    I have a form with multiple fields in it along with a image input field, just below the form i have a list to be displayed on every submit of this form... this has to be done without the use of DB.. I think this can be achieved by using session but its not working with me, as evrytime page gets refreshed and session gets recreated/reset.. Please help me in resolving this issue

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  • How to Create the Upload File for Application Loader?

    - by Ohad Regev
    When I use Application Loader, I get to the point where it asks me to "Choose..." the file to be uploaded. If I understand correctly, it supposes to be the appName.app file I see under "Products" on my app bundle (I right click it and select "Show in Finder" to get to the specific file in library; then I'm supposed to ZIP it and the ZIP file is what I will choose in Application Loader). First, am I correct with this assumption? if yes... What should I define different in XCode than the way I used to build the application for testing (on simulator and on my personal iPhone)? Should I change the Info---Command-line build use from Debug to Release? How should I define the Build Settings---Code Signing section (in which field should I select the "iPhone Developer" option and in which should it be "iPhone Distribution")? Are there any other important Info/Build Settings/p.list/etc... fields I should relate to? any help will be appreciated...

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  • Can you set a form field value with PHP?

    - by dcp3450
    I use the $_GET function to pull a value with php from the url (http:..../index.html?variable=value), basic stuff. However, I need to use that value in my form. Typically, I would set <?php echo 'value="'.$variable.'"' ; ?> or something to that effect. However, I can't use php inside my form using the editor I'm working with. Can I set a value in the form without using PHP in my form? If so, how?

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