Search Results

Search found 4900 results on 196 pages for 'upload'.

Page 39/196 | < Previous Page | 35 36 37 38 39 40 41 42 43 44 45 46  | Next Page >

  • iPhone Development: Use POST to submit a form

    - by Mario
    I've got the following html form: <form method="post" action="http://shk.ecomd.de/up.php" enctype="multipart/form-data"> <input type="hidden" name="id" value="12345" /> <input type="file" name="pic" /> <input type="submit" /> </form> And the following iPhone SDK Submit method: - (void)sendfile { UIImage *tempImage = [UIImage imageNamed:@"image.jpg"]; NSMutableURLRequest *request = [[NSMutableURLRequest alloc] init]; [request setHTTPMethod:@"POST"]; [request setURL:[NSURL URLWithString:@"http://url..../form.php"]]; NSString *boundary = @"------------0xKhTmLbOuNdArY"; NSString *contentType = [NSString stringWithFormat:@"multipart/form-data; boundary=%@",boundary]; [request addValue:contentType forHTTPHeaderField: @"Content-Type"]; NSMutableData *body = [NSMutableData data]; [body appendData:[[NSString stringWithFormat:@"\r\n%@\r\n",boundary] dataUsingEncoding:NSASCIIStringEncoding]]; [body appendData:[@"Content-Disposition: form-data; name=\"id\"\r\n\r\n" dataUsingEncoding:NSASCIIStringEncoding]]; [body appendData:[@"12345" dataUsingEncoding:NSUTF8StringEncoding]]; [body appendData:[[NSString stringWithFormat:@"\r\n%@\r\n",boundary] dataUsingEncoding:NSASCIIStringEncoding]]; [body appendData:[@"Content-Disposition: form-data; name=\"pic\"; filename=\"photo.png\"\r\n" dataUsingEncoding:NSASCIIStringEncoding]]; [body appendData:[@"Content-Type: application/octet-stream\r\n\r\n" dataUsingEncoding:NSASCIIStringEncoding]]; [body appendData:[NSData dataWithData:UIImageJPEGRepresentation(tempImage, 90)]]; [body appendData:[[NSString stringWithFormat:@"\r\n%@",boundary] dataUsingEncoding:NSASCIIStringEncoding]]; // setting the body of the post to the reqeust [request setHTTPBody:body]; NSError *error; NSURLResponse *response; NSData* result = [NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error]; NSString* aStr = [[[NSString alloc] initWithData:result encoding:NSASCIIStringEncoding] autorelease]; NSLog(@"Result: %@", aStr); [request release]; } This does not work, but I have no clue why. Can you please help me?!! What am I doing wrong?

    Read the article

  • How we Can post Video and Image in ASIHTTPRequest ?

    - by GhostRider
    I want to post one image to my webservice and one video too , but problem is that when it go to video part it give me Excess-bad Error NSString *url = [NSString stringWithFormat:@"http://example.com/add_videoxml.php"]; networkQueue = [[ASINetworkQueue alloc] init]; [networkQueue cancelAllOperations]; [networkQueue setShowAccurateProgress:YES]; //[networkQueue setUploadProgressDelegate:progressBar]; [networkQueue setDelegate:self]; [networkQueue setRequestDidFinishSelector:@selector(requestFinished:)]; [networkQueue setRequestDidFailSelector: @selector(requestFailed:)]; request= [[ASIFormDataRequest alloc] initWithURL:[NSURL URLWithString:url]] ; [request setPostValue:@"284" forKey:@"id"]; [request setPostValue:@"show" forKey:@"show"]; [request addRequestHeader:@"Content-Type" value:@"multipart/form-data;boundary=---------------------------1842378953296356978857151853"]; NSData *imgData=UIImageJPEGRepresentation(userImage, 0.9); if(imgData != nil){ [request setFile:imgData withFileName:@"Loveatnight" andContentType:@"image/jpeg" forKey:@"image"]; } //[request addRequestHeader:@"Content-Type" // value:@"multipart/form-data;boundary=---------------------------1842378953296356978857151853"]; if(videoData != nil){ [request setFile:videoData withFileName:@"Loveishard" andContentType:@"image/jpeg" forKey:@"uploadfile"]; }// error is come on that line [request setTimeOutSeconds:500]; //NSLog(@"%@",request); [networkQueue addOperation:request]; [networkQueue go]; Added by the OP [request setFile:videoData withFileName:@"Loveishard" andContentType:@"video/quicktime" forKey:@"uploadfile"]; i use this becuase my video formate is mov , but it again give error

    Read the article

  • PHP file upload

    - by Develman
    I have big trouble with file uploads with php. My own tests are successful but my colleague is telling me that he cannot update "larger" (ca. 5mb) files. Phpinfo says: - max_execution_time 30 - memory_limit 32 Mb - post_max_size 8 Mb - upload_max_filesize 10 Mb Is it better to use FTP? The problem is that I cannot change these settings at my webhoster.

    Read the article

  • PHP upload file using PUT instead of POST

    - by Marco Demaio
    I read something about this on PHP docs, but it's not celar to me: Do the most widely used browsers (IE, FF, Chrome, Safari, Opera, ...) support this PUT method to uplaod files? What HTML should I write to make the browser call the server via PUT request. I mean do I need to write a FORM with an INPUT file field and just replace the attribute method="POST" with the method="PUT"? On the PHP docs (link above) they say a PUT request is much simplier than a POST request when uploading file, along with this advantage, what other advantages/disadvanatges do the PUT has comapred to teh POST? Thanks!

    Read the article

  • Uploading videos to Twitter using OAuth

    - by deepa
    Hi, I am developing an iPhone app that uses Twitvid library for uploading videos to TwitVid. This library first authenticates the app using the user-name and password input parameters. Then it uploads the video. But, recently I switched to OAuth mechanism of authentication which leads to a web-page where user can enter the user-name and password. So, I cannot provide the input fields for user-name and password in my app for uploading video. Can someone help me out to solve this problem. Thanks and Regards, Deepa

    Read the article

  • Get Path of Uploaded File using Python

    - by Ali
    Is it possible to get the full path of the file on the user's computer being uploaded to my site? Using os.path.abspath(fileitem.filename) simply gets me the address of where my script is executing from on my shared hosting server. FYI: fileitem = form['file'] and form = cgi.FieldStorage()

    Read the article

  • Flash uploader that can handle >2GB files?

    - by Alvin SMith
    Is there an open source Flash uploader that can handle files larger than 2 GB? ASP.net implementations like SlickUpload are not an option, and SWFUpload (and others that I've seen) do not handle files larger than 2 GB. Nor is requiring the user to have Java installed to run applets. This would be for both IE and Firefox. I've seen a couple "large file transfer" sites that have a Flash uploader and claim to go past the 2GB limit (which is the limit for http uploads for most browsers) so I know it is technically possible.

    Read the article

  • Cloning input type file and set the value

    - by jribeiro
    I know that it isn't possible to set the value of an input type="file" for security reasons... My problem is: I needed to style an input type="file" so what I did was have a button and hide the file input. like: <a href="#" onclick="$('input[name=&quot;photo1&quot;]').click(); return false;" id="photo1-link"></a> <input type="file" name="photo1" class="fileInput jqtranformdone validate[required]" id="photo1" /> These works great in all browsers except IE which gives me an access denied error on submitting through ajax. I'm using the ajaxSubmit jquery plugin (malsup.com/jquery/form/) So after reading for a while I tried to do: var photo1Val = $('#photo1').val(); var clone1 = $('#photo1').clone().val(photo1Val); $('#photo1').remove(); clone1.appendTo('form'); console.log(photo1Val) //prints the right value C:/fakepath/blablabla.jpg $('form').ajaxSubmit(options); The problem is that after this the value of $('#photo1') is empty... Any ideas how to work around this? Thanks

    Read the article

  • Locating file path from a <InMemoryUploadedFile> Djnago object

    - by PirosB3
    Hi all I have a Django app which, submitting a package, should return values that are inside it.. Submitted the form to a view called "insert": request.FILES['file'] returns the file objects, but it is of kind < InMemoryUploadedFile. What i need is a way to get the absolute path of the uploaded file, so that i can feed it to a method that will return the values needed Anyone know how i can accomplish this? Thanks

    Read the article

  • rails paperclip multi upload

    - by mattherick
    hello! has somebody from you followed this tutorial? link text I really don´t now why, but I got following fault, when I went through the tutorial word by word: @album[photo_attributes]‘ is not allowed as an instance variable name somebody an idea why?

    Read the article

  • [grails] attaching multiple files to a domain class

    - by Emyr
    I've seen various Grails plugins which allow easier handling of file uploads, however these tend only to support a single file per form-submit. I'd like a multi-attach form where as soon as you pick one file, an extra field and button is added using JS (various sites do it like this). Do you know of any good plugins which provide elegant uploading of multiple files without excessive coding? A progress bar either per-file of for the whole process would also be very nice. I don't know to what extent I can allow GORM to handle a java.io.File field (or in this case a Collection<File>).

    Read the article

  • Problem with images in upload directory after upgrading WordPress to 3.0

    - by Volmar
    I've developed a WordPress plugin and it wordked well from WP 2.0 and up to WP 3.0rc1 (haven't tried rc2) but now with rc3 and milestone 3.0 a strange and irritating error appeared. If you check out my demo page you will se that none of the cover-images is working. they are in the same place as before but they can not be hotlinked or show up when i enter the correct url. if i move the img-directory from /wp-content/uploads/my-record-collection/ to /wp-content/uploads/ the images show up if i enter the url, but not if i move it back inside my "my-record-collection"-folder. anyone know what change in rc3(or maybe rc2) that made this bug appear and what can be done to fix it?

    Read the article

  • has any tools easy to download or uploaed data from gae ..

    - by zjm1126
    i find this: http://aralbalkan.com/1784 but it is : Gaebar is an easy-to-use, standalone Django application that you can plug in to your existing Google App Engine Django or app-engine-patch-based Django applications on Google App Engine to give them datastore backup and restore functionality. my app is not based on django,so did you know any tools esay to do this . thanks

    Read the article

  • Please Find the error :

    - by jagdeep
    using System; using System.Collections; using System.Configuration; using System.Data; using System.Linq; using System.Web; using System.Web.Security; using System.Web.UI; using System.Web.UI.HtmlControls; using System.Web.UI.WebControls; using System.Web.UI.WebControls.WebParts; using System.Xml.Linq; public partial class Expt : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { } protected void Bttnadd_Click(object sender, EventArgs e) { FileUpload1.SaveAs(MapPath("~/img//"+DateTime.Now.ToString()+FileUpload1.FileName)); } } Exception Details: System.Web.HttpException: ~/img//1/1/2011 1:47:52 PMWinter.jpg is not a valid virtual path.

    Read the article

  • file upload in JSF using myfaces component

    - by prt
    Hi, all i am creating a JSF application where file uploading functionality is required.I have added all the required jar files in my /WEB-INF/lib folder. jsf-api.jar jsf-impl.jar jstl.jar standard.jar myfaces-extensions.jar commons-collections.jar commons-digester.jar commons-beanutils.jar commons-logging.jar commons-fileupload-1.0.jar but still when trying to deploy the application on apache 6.0.29 i am getting the following error. org.apache.catalina.core.StandardContext addApplicationListener INFO: The listener "com.sun.faces.config.ConfigureListener" is already configured for this context. The duplicate definition has been ignored. org.apache.catalina.core.StandardContext start SEVERE: Error listenerStart PM org.apache.catalina.core.StandardContext start SEVERE: Context [/jsfApplication] startup failed due to previous errors org.apache.catalina.loader.WebappClassLoader clearReferencesJdbc The web application [/jsfApplication] registered the JBDC driver [com.mysql.jdbc.Driver] but failed to unregister it when the web application was stopped. To prevent a memory leak, the JDBC Driver has been forcibly unregistered. org.apache.catalina.loader.WebappClassLoader clearReferencesThreads SEVERE: The web application [/jsfApplication] appears to have started a thread named [Timer-0] but has failed to stop it. This is very likely to create a memory leak. org.apache.catalina.loader.WebappClassLoader clearReferencesThreads SEVERE: The web application [/jsfApplication] appears to have started a thread named [MySQL Statement Cancellation Timer] but has failed to stop it. This is very likely to create a memory leak. log4j:ERROR LogMananger.repositorySelector was null likely due to error in class reloading, using NOPLoggerRepository. i am using also using hibernate and spring framework for this application. please help. thanks,

    Read the article

  • file upload with php

    - by Rajanikant shukla
    Hi every body I am uploading file with php every thing is fine but move_uploded_file is not working every variable displayed record and all permission for file is set function uploadfile($filename) { $filetype=$filename["type"]; $filename=$filename['name']; $filetempname=$filename['tmp_name']; if($filetype=="application/msword") { move_uploaded_file($filetempname,"resume/".$filename); } }

    Read the article

  • PHP: How to get creation date from uploaded file?

    - by Haemp
    Problem: I want to determine the original file creation time from a file uploaded to my server via PHP. My understanding is that the file is copied from the client to a temporary file on my server, which then is referenced in the $_FILES var. The temporary file is of course of no use because it was just created. Is there any way I could get the creation date from the clients original file? Thanks

    Read the article

  • Curl (*nix) upload file to ASP.NET

    - by WedTM
    I have an old redhat 8 box that I need to pragmatically send files to my webserver from. Disregarding the security issues with this, I've come up with the following way. curl -F file=@<filename> http://webhost/reciever.aspx The problem is, no matter what I try, the ASP.NET page is not accepting the file. What am I doing wrong?

    Read the article

  • Symfony and uploadify

    - by Thomas
    Hi! I want to use uploadify with Symfony 1.4, but so far I couldn't. Uploadify loads correctly, I choose my files, it says that the files were successfully uploaded, but the are nowhere. (I'm doing this on localhost) Is there anybody who met this problem before? Thanks, Tom $file = $request->getParameter('file'); $filename = sha1($file->getOriginalName()).$file->getExtension($file->getOriginalExtension()); $file->save(sfConfig::get('sf_upload_dir').'/'.$filename);

    Read the article

  • How to get file path using FileUpload to be read by FileStream?

    - by john ryan
    I have a Method that open excel file and read it through exceldatareaderClass that i have downloaded in codeplex by using filestream. Currently I just declared the exact directory where the filestream open an excel file.And it works fine. Stream stream = new FileStream("C:\\" + FileUpload.PostedFile.FileName, FileMode.Open, FileAccess.Read, FileShare.Read); Now i need to read the excel file wherever location the user place it like on windows forms fileupload.FileStream needs the exact location where the file is located. How to do this.? Example: Sample.xls is located on My Documents the file path should be like : C:\Documents and Settings\user\My Documents\ string openpath ="" ;//filepath Stream stream = new FileStream(openpath+ FileUpload.PostedFile.FileName, FileMode.Open, FileAccess.Read, FileShare.Read); Thanks in Regards

    Read the article

< Previous Page | 35 36 37 38 39 40 41 42 43 44 45 46  | Next Page >