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  • java url connection, wait for data being sent through the outputstream

    - by Mateu
    I'm writting a java class that tests uploading speed connection to a server. I want to check how many data can be send in 5 seconds. I've written a class which creates a URL, creates a connection, and sends data trough the outPutStream. There is a loop where I writte data to the stream for 5 seconds. However I'm not able to see when data has been send (I writte data to the output stream, but data is not send yet). How can I wait untill data is really sent to the server? Here goes my code (which does not work): URL u = new URL(url) HttpURLConnection uc = (HttpURLConnection) u.openConnection(); uc.setDoOutput(true); uc.setDoInput(true); uc.setUseCaches(false); uc.setDefaultUseCaches(false); uc.setRequestMethod("POST"); uc.setRequestProperty("Content-Type", "application/octet-stream"); uc.connect(); st.start(); // Send the request OutputStream os = uc.getOutputStream(); //This while is incorrect cause it does not wait for data beeing sent while (st.getElapsedTime() < miliSeconds) { os.write(buffer); os.flush(); st.addSize(buffer.length); } os.close(); Thanks

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  • Restrict allowed file upload types PHP

    - by clang1234
    Right now I have a function which takes my uploaded file, checks the extension, and if it matches an array of valid extensions it's processed. It's a contact list importer. What I need to figure out is how to be sure that file (in this case a .csv) is actually what it says it is (ex. not an excel file that just got renamed as a .csv). Our servers run PHP 5.2.13 Here's the current validation function I have public static function validateExtension($file_name,$ext_array) { $extension = strtolower(strrchr($file_name,".")); $valid_extension="FALSE"; if (!$file_name) { return false; } else { if (!$ext_array) { return true; } else { foreach ($ext_array as $value) { $first_char = substr($value,0,1); if ($first_char <> ".") { $extensions[] = ".".strtolower($value); } else { $extensions[] = strtolower($value); } } foreach ($extensions as $value) { if ($value == $extension) { $valid_extension = "TRUE"; } } if ($valid_extension==="TRUE") { return true; } else { return false; } } } }

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  • How can I save a directory tree to an array in PHP?

    - by Greg
    I'm trying to take a directory with the structure: top folder1 file1 folder2 file1 file2 And save it into an array like: array ( 'folder1' => array('file1'), 'folder2' => array('file1', 'file2') ) This way, I can easily resuse the tree throughout my site. I've been playing around with this code but it's still not doing what I want: private function get_tree() { $uploads = __RELPATH__ . DS . 'public' . DS . 'uploads'; $iterator = new RecursiveIteratorIterator(new RecursiveDirectoryIterator($uploads), RecursiveIteratorIterator::SELF_FIRST); $output = array(); foreach($iterator as $file) { $relativePath = str_replace($uploads . DS, '', $file); if ($file->isDir()) { if (!in_array($relativePath, $output)) $output[$relativePath] = array(); } } return $output; }

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  • Browser download file prompt using javascript

    - by aix
    hi, I was wondering if there was any method to implement browser's download file prompt using javascript. My reason - well users will be uploading files to a local fileserver which cannot be accessed from the webserver. In other words, both will be on different domains! e.g. let’s say websites hosted on www.xyz.com, but files would reside on local file server with address like \10.10.10.01\Files\file.txt. How am I uploading/transferring file to local fileserver... using ACTIVEX(yikes) & VBscript!!!! (don’t ask :-) so i am storing local file path in my database and binding that data to a grid. So when the user clicks on that link, the file opens in a window (using javascript). Problem is certain file types like text, jpg, pdf, etc open inside browser window. How would i be able to implement content-type or content-disposition using client side scripting? Is that even possible? hoping my description was clear. Any ideas? EDIT: the local file server has a window's shared folder on which the files are saved.

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  • csv file upload and update mysql db

    - by Indra
    I am very to new to php. i am using the following code to open a csv file and update my database. i need to check the value of first row-first column of the csv file. if it is matching "some text 1", then i need to run code1, if it is "some text 2", run code2, else code3. I can use if else condition but since i am using while loop It fails. Can anyone help me. $handle = fopen($file_tmp,"r"); while(($fileop = fgetcsv($handle,",")) !== false) { // I need to check here $companycode = mysql_real_escape_string($fileop[0]); $Item = mysql_real_escape_string($fileop[3]); $pack = preg_replace('/[^A-Za-z0-9\. -]/', '', $fileop[4]); $lastmonth = mysql_real_escape_string($fileop[5]); $ltlmonth = mysql_real_escape_string($fileop[6]); $op = mysql_real_escape_string($fileop[9]); $pur = mysql_real_escape_string($fileop[10]); $sale = mysql_real_escape_string($fileop[12]); $bal = mysql_real_escape_string($fileop[17]); $bval = mysql_real_escape_string($fileop[18]); $sval = mysql_real_escape_string($fileop[19]); $sq1 = mysql_query("INSERT INTO `sas` (companycode,Item,pack,lastmonth,ltlmonth,op,pur,sale,bal,bval,sval) VALUES ('$companycode','$Item','$pack','$lastmonth','$ltlmonth','$op','$pur','$sale','$bal','$bval','$sval')"); }

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  • How can I check the MIME type of an uploaded file using Perl CGI?

    - by FOOM
    I'm trying to get the MIME type of an <input type="file" /> element using Perl, but without actually examining the contents of the file itself, In other words, just using the HTTP headers. I have only been able to get the "multipart/form-type" Content-Type value, but my understanding is that each element will get its own MIME Type? How can I see the sub-MIME types using Perl?

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  • Multiple file selection for an upload control

    - by Abel Morelos
    Hi, I was trying to do something like this: http://www.element-it.com/Examples/MultiPowUpload/AdvancedHTMLinterface.html But in my search for information I found that is not possible to perform multiple file selection with simple HTML and JavaScript (and JSP in the server side). There is a way to do this without using Flash? A third party component you could recommend? Thanks.

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  • Reading file data during form's clean method

    - by Dominic Rodger
    So, I'm working on implementing the answer to my previous question. Here's my model: class Talk(models.Model): title = models.CharField(max_length=200) mp3 = models.FileField(upload_to = u'talks/', max_length=200) Here's my form: class TalkForm(forms.ModelForm): def clean(self): super(TalkForm, self).clean() cleaned_data = self.cleaned_data if u'mp3' in self.files: from mutagen.mp3 import MP3 if hasattr(self.files['mp3'], 'temporary_file_path'): audio = MP3(self.files['mp3'].temporary_file_path()) else: # What goes here? audio = None # setting to None for now ... return cleaned_data class Meta: model = Talk Mutagen needs file-like objects - the first case (where the uploaded file is larger than the size of file handled in memory) works fine, but I don't know how to handle InMemoryUploadedFile that I get otherwise. I've tried: # TypeError (coercing to Unicode: need string or buffer, InMemoryUploadedFile found) audio = MP3(self.files['mp3']) # TypeError (coercing to Unicode: need string or buffer, cStringIO.StringO found) audio = MP3(self.files['mp3'].file) # Hangs seemingly indefinitely audio = MP3(self.files['mp3'].file.read()) Is there something wrong with mutagen, or am I doing it wrong?

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  • PHP resizing PNGs results in corrupted files

    - by Robert
    I have a PHP script that resizes .jpg, .gif, and .png files to a bounding box. $max_width = 500; $max_height = 600; $filetype = $_FILES["file"]["type"]; $source_pic = "img/" . $idnum; if($filetype == "image/jpeg") { $src = imagecreatefromjpeg($source_pic); } else if($filetype == "image/png") { $src = imagecreatefrompng($source_pic); } else if($filetype == "image/gif") { $src = imagecreatefromgif($source_pic); } list($width,$height)=getimagesize($source_pic); $x_ratio = $max_width / $width; $y_ratio = $max_height / $height; if( ($width <= $max_width) && ($height <= $max_height) ) { $tn_width = $width; $tn_height = $height; } else if (($x_ratio * $height) < $max_height) { $tn_height = ceil($x_ratio * $height); $tn_width = $max_width; } else { $tn_width = ceil($y_ratio * $width); $tn_height = $max_height; } $tmp = imagecreatetruecolor($tn_width,$tn_height); imagecopyresampled($tmp,$src,0,0,0,0,$tn_width, $tn_height,$width,$height); $destination_pic = "img/thumbs/" . $idnum . "thumb"; if($filetype == "image/jpeg") { imagejpeg($tmp,$destination_pic,80); } else if($filetype == "image/png") { imagepng($tmp,$destination_pic,80); } else if($filetype == "image/gif") { imagegif($tmp,$destination_pic,80); } imagedestroy($src); imagedestroy($tmp); The script works fine with jpeg and gif but when running on a png the file will be corrupted. Is there anything special I need to use when working with a png? I have never worked with this sort of thing in PHP so I'm not very familiar with it.

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  • Standard upload web control alternatives

    - by Roy
    Hi all, I'm developing a ASP.NET MVC application. There is little space for me to put two standard file uploading web controls in a page. So I'm seeking for some succinct alternatives. A checkbox-look button pops up a file open dialog is ideal. Is there any kind of stuff? Thanks in advance!

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  • How does this script work for the ImageShack.us API?

    - by vette982
    I'm looking into using the ImageShack.us API for uploading images from my website. I found this tutorial for using it with the XML return http://elliottback.com/wp/using-the-imageshack-xml-api/, but I'm not sure about what to do with it. Where do I enter my API key for this script? Furthermore, he shows the use of two PHP files - should these be combined into one file? Any help with this would be appreciated (examples would be even better).

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  • Large Video Uploads via a website

    - by Andrew
    Some of the problems that can happen are timeouts, disconnections, and not being able to resume a file and having to start from the beginning. Assuming these files are up to around 5gigs in size, what is the best solution for dealing with this problem? I'm using a Drupal 6 install for the website. Some of my constraints due to the server setup I have to deal with: Shared hosting with max 200 connections at a time (unlimited disk space) Shared hosting. Unable to create users through an API (so can't automatically generate ftp accounts) I do have the ability to run cron-type scripts via a Drupal module. My initial thought was to create ftp users based off of Drupal accounts and requiring them to download an ftp client for their OS of choice. But the lack of API to auto-create ftp accounts and the inability to do it from command line kind of hinder that solution. If there's a workaround someone can think of, let me know! Thanks

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  • How can I write a file on an sftp-server with PHP?

    - by Daniel
    Hi, I hope someone here could help me, because I couldn't find any solution with Google. What I have to do is to generate a XML-string (that works) an save that directly into a file on an sftp-server. So far, so good... I used the following code with ftp and it works to, but not with ftps. So I either need another options-configuration for the stream or a different way to solve that task. Here my current code: $host = 'ftp.example.com'; $port = 22; $user = 'xxxxxx'; $pass = 'xxxxxx'; $file = 'test_' . time() . '.txt'; $ftpPath = sprintf('ftp://%s:%s@%s:%d/%s', $user, $pass, $host, $port, $file); $context = stream_context_create(array('ftp' = array('overwrite' = true))); file_put_contents($ftpPath, 'test', 0, $context);

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  • Html file upload preview by Javascript

    - by openidsujoy
    I want to show a PREVIEW kind of thing for an post , so took details by JS but problem comes when it comes to <input type="file" , it's not giving full path to the file Ex: if I do $("#image").val(); it only give "Sunset.jpg" not C:\Documents and Settings\All Users....\Sunset.jpg any idea how to get that detail value?

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  • looking to scan documents directly to be uploaded to a webpage

    - by Tom
    I was hoping to do this from a flash plugin, kind of how flash accesses the microphone or webcam but it doesn't seem possible. Is this going to be possible using Java, or ActiveX, or some other strategy that I haven't looked at yet? The idea is to do it without a client install, or at least something lightweight and browser and platform independent, (and possibly the moon on a stick as welll ;-))

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  • even small file upload stops activity on apache/rails

    - by Pavel K.
    on my rails(2.3.5) app(currently 50-70rpm, maximum response time around 0.7s), uploading even 700k file(using paperclip plugin) locks up the server for web requests for everyone for 2 minutes! (other apps on same server work normally) does anyone have a clue why that might be happening? i am using some mysql transactions which lock the database also if that might be an issue i read http://www.therailsway.com/2009/4/23/uploading-files but it couldn't be locking server for 2 minutes for a small file, could it?!

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  • One table for uploads for multiple resources in CakePHP

    - by Mef
    Hi, I have CakePHP app in which I'd like to attach gallery to multiple resources. Let's say I've got artists, each one has own gallery. I've got articles, every article has some images attached to it and so on. Now I set up tables like this: Artists hasMany Artistimages, fields in artistimages table are: id, artist_id, filename, filetype, filesize etc. Articles hasMany Articleimages, fields in articleimages table are: id, article_id, filename, filetype, filesize etc. ...but this is not how it should be, I think. Is there possibility to have one table called for example uploads which will contain all images with foreign key pointing to resource its reffering to? How to tell CakePHP which image is coming from which resource?

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  • .net Drawing.Graphics.FromImage() returns blank black image

    - by joox
    I'm trying to rescale uploaded jpeg in asp.net So I go: Image original = Image.FromStream(myPostedFile.InputStream); int w=original.Width, h=original.Height; using(Graphics g = Graphics.FromImage(original)) { g.ScaleTransform(0.5f, 0.5f); ... // e.g. using (Bitmap done = new Bitmap(w, h, g)) { done.Save( Server.MapPath(saveas), ImageFormat.Jpeg ); //saves blank black, though with correct width and height } } this saves a virgin black jpeg whatever file i give it. Though if i take input image stream immediately into done bitmap, it does recompress and save it fine, like: Image original = Image.FromStream(myPostedFile.InputStream); using (Bitmap done = new Bitmap(original)) { done.Save( Server.MapPath(saveas), ImageFormat.Jpeg ); } Do i have to make some magic with g? upd: i tried: Image original = Image.FromStream(fstream); int w=original.Width, h=original.Height; using(Bitmap b = new Bitmap(original)) //also tried new Bitmap(w,h) using (Graphics g = Graphics.FromImage(b)) { g.DrawImage(original, 0, 0, w, h); //also tried g.DrawImage(b, 0, 0, w, h) using (Bitmap done = new Bitmap(w, h, g)) { done.Save( Server.MapPath(saveas), ImageFormat.Jpeg ); } } same story - pure black of correct dimensions

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  • fastest way to upload an xls file into a database

    - by shmichael
    I have an xls file with ~60 sheets of data. I would like to move them into a database (postgres) such that each sheet's data is stored in a different table. What is the fastest way of creating these tables? I don't care about naming or proper typing of columns. The columns could all be strings for that matter. I don't want to run 60 different csv uploads.

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