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  • OSMDroid simple example required

    - by Bex
    Hi! I am trying to create an app that uses offline maps and custom tiles. For this I have decided to use OSMDroid and have included the jar within my project. I will create my custom tiles using MOBAC. I have been directed to these examples: http://code.google.com/p/osmdroid/source/browse/#svn%2Ftrunk%2FOpenStreetMapViewer%2Fsrc%2Forg%2Fosmdroid%2Fsamples but I am struggling to follow them as I am new to both java and android. I have created a class file called test (which I have created following an example!): public class test extends Activity { /** Called when the activity is first created. */ protected static final String PROVIDER_NAME = LocationManager.GPS_PROVIDER; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); MapView map = (MapView) findViewById(R.id.map); map.setTileSource(TileSourceFactory.MAPQUESTOSM); map.setBuiltInZoomControls(true); map.setMultiTouchControls(true); map.getController().setZoom(16); map.getController().setCenter(new GeoPoint(30266000, -97739000)); } } with a layout file: <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent"> <org.osmdroid.views.MapView android:id="@+id/map" android:layout_width="fill_parent" android:layout_height="fill_parent" tilesource="MapquestOSM" android:layout_weight="1" /> </LinearLayout> When I run this I see no map, just an empty grid. I think this is due to my tilesource but I'm not sure what I need to change it to. Can anyone help? Bex

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  • Problem with XML encoding of database contents with Latin characters

    - by user89691
    I have an ASP Access database that contains strings in various European languages. The database was populated prior by agents in the respective countries. It contains entries with accented etc characters as you would expect. If I open the database with MS Access these characters show up fine. For example the the German equivalent of "Open" shows as "Öffnen" (hopefully you can see an "O" with 2 dots above it!). I have ASP code that reads the database and returns records in XML. The text is passed to XMLEncode to construct the XML, but that only seems to deal with the 5 specials like "<", "&", etc. If I dump the XML the accented characters are unchanged. <English>Open</English> <German>Öffnen</German> If I look at the raw packets with Wireshark I see that the "Ö" byte is hex D6, which appears to be it's decimal Unicode and ISO 8859-1 value. The problem starts when I try to parse the XML in client-side JS. I get: "An invalid character was found in text content" from IE. FF and Chrome happily accept the XML without hiccup but the browser shows the "Ö" character as a diamond with a question mark inside. http://www.validome.org/xml/validate/ reports "encoding error." http://www.w3schools.com/dom/dom_validate.asp thinks it is fine. The XML is UTF-8 encoded. What do I need to do to have IE accept my XML without complaint? What do I need to do to have browsers display the stuff correctly?

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  • EAV Database Sheme

    - by GLO
    Hello Stackoverflow comunity! I believe that my question has to do with all db guru here! Do you know the EAV DB Scheme ( http://en.wikipedia.org/wiki/Entity-attribute-value_model ) and what they say about the performing of this model. I wonder, If I break this model into smaller tables what the result is? Let's talk about it. I have a db with more that 100K records. A lot of categories and many items ( with different properties per category ) Everything is stored in a EAV. If I try to break this scheme and create for any category a unique table is something that will I have to avoid? Yes, I know that probably I'll have a lot of tables and I'll need to ALTER them if I want to add an extra field, BUT is this so wrong? I have also read that as many tables I have, the db will be populate with more files and this isn't good for any filesystem. Any suggestion? Thank you!

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  • Binding WPF ComboBox in XAML - Why is it Empty?

    - by mdiehl13
    I am trying to learn how to bind my simple database (.sdf) to a combobox. I created a dataset with my tables in it. I then dragged a table from the DataSource onto my control. There are no build warnings/errors, and when it runs, the ComboBox is empty. <UserControl x:Class="OurFamilyFinances.TabItems.TransactionTab" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" xmlns:mc="http://schemas.openxmlformats.org/markup-compatibility/2006" xmlns:d="http://schemas.microsoft.com/expression/blend/2008" mc:Ignorable="d" d:DesignHeight="414" d:DesignWidth="578" xmlns:my="clr-namespace:OurFamilyFinances" Loaded="UserControl_Loaded_1"> <UserControl.Resources> <my:FinancesDataDataSet x:Key="financesDataDataSet" /> <CollectionViewSource x:Key="accountViewSource" Source="{Binding Path=Account, Source={StaticResource financesDataDataSet}}" /> </UserControl.Resources> <Grid> <ComboBox DisplayMemberPath="Name" Height="23" HorizontalAlignment="Left" ItemsSource="{Binding Source={StaticResource accountViewSource}}" Margin="3,141,0,0" Name="accountComboBox" SelectedValuePath="ID" VerticalAlignment="Top" Width="120"> <ComboBox.ItemsPanel> <ItemsPanelTemplate> <VirtualizingStackPanel /> </ItemsPanelTemplate> </ComboBox.ItemsPanel> </ComboBox> </Grid> The paths that is shows are correct, the selectedPath is "ID" and the displaypath is "Name". If I do this in Linq to Sql, the combo box does populate: this.accountComboBox.ItemsSource = from o in db.Account select new { o.ID, o.Name }; But I would like to learn how to do this in XAML. I have dragged datagrids from the DataSource as well, but they are not populated either. Any idea?

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  • Map enum in JPA with fixed values ?

    - by Kartoch
    I'm looking for the different ways to map an enum using JPA. I especially want to set the integer value of each enum entry and to save only the integer value. @Entity @Table(name = "AUTHORITY_") public class Authority implements Serializable { public enum Right { READ(100), WRITE(200), EDITOR (300); private int value; Right(int value) { this.value = value; } public int getValue() { return value; } }; @Id @GeneratedValue(strategy = GenerationType.AUTO) @Column(name = "AUTHORITY_ID") private Long id; // the enum to map : private Right right; } A simple solution is to use the Enumerated annotation with EnumType.ORDINAL: @Column(name = "RIGHT") @Enumerated(EnumType.ORDINAL) private Right right; But in this case JPA maps the enum index (0,1,2) and not the value I want (100,200,300). Th two solutions I found do not seem simple... First Solution A solution, proposed here, uses @PrePersist and @PostLoad to convert the enum to an other field and mark the enum field as transient: @Basic private int intValueForAnEnum; @PrePersist void populateDBFields() { intValueForAnEnum = right.getValue(); } @PostLoad void populateTransientFields() { right = Right.valueOf(intValueForAnEnum); } Second Solution The second solution proposed here proposed a generic conversion object, but still seems heavy and hibernate-oriented (@Type doesn't seem to exist in JEE): @Type( type = "org.appfuse.tutorial.commons.hibernate.GenericEnumUserType", parameters = { @Parameter( name = "enumClass", value = "Authority$Right"), @Parameter( name = "identifierMethod", value = "toInt"), @Parameter( name = "valueOfMethod", value = "fromInt") } ) Is there any other solutions ? I've several ideas in mind but I don't know if they exist in JPA: use the setter and getter methods of right member of Authority Class when loading and saving the Authority object an equivalent idea would be to tell JPA what are the methods of Right enum to convert enum to int and int to enum Because I'm using Spring, is there any way to tell JPA to use a specific converter (RightEditor) ?

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  • Can't send client certificate via SslStream

    - by Jonathan
    I am doing an SSL3 handshake using an SslStream, but, in spite of my best efforts, the SslStream never sends a client certificate on my behalf. Here is the code: SSLConnection = new System.Net.Security.SslStream(SSLInOutStream, false, new System.Net.Security.RemoteCertificateValidationCallback(AlwaysValidRemoteCertificate), new System.Net.Security.LocalCertificateSelectionCallback(ChooseLocalCertificate)); X509CertificateCollection CC = new X509CertificateCollection(); CC.Add(Org.BouncyCastle.Security.DotNetUtilities.ToX509Certificate(MyLocalCertificate)); SSLConnection.AuthenticateAsClient("test", CC, System.Security.Authentication.SslProtocols.Ssl3, false); and then I have AlwaysValidRemoteCertificate just returning true, and ChooseLocalCertificate returning the zeroth element of the array. The code probably looks a little weird because the project is a little weird, but I think that is beside the point here. The SSL handshake completes. The issue is that instead of sending a certificate message on my behalf (in the handshake process), with the ASN.1 encoded certificate (MyLocalCertificate), the SslStream sends an SSL alert number 41 (no certificate) and then carries on. I know this from packet sniffing. After the handshake is completed, the SslStream marks IsAuthenticated as true, IsMutuallyAuthenticated as false, and its LocalCertificate member is null. I feel like I'm probably missing something pretty obvious here, so any ideas would be appreciated. I am a novice with SSL, and this project is off the beaten path, so I am kind of at a loss. P.S. 1: My ChooseLocalCertificate routine is called twice during the handshake, and returns a valid (as far as I can tell), non-null certificate both times. P.S. 2: SSLInOutStream is my own class, not a NetworkStream. Like I said, though, the handshake proceeds mostly normally, so I doubt this is the culprit... but who knows?

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  • Custom SSL handling stopped working on Android 2.2 FroYo

    - by Eric
    For my app, Transdroid, I am connecting to remote servers via HTTP and optionally securely via HTTPS. For these HTTPS connections with the HttpClient I am using a custom SSL socket factory implementation to make sure self-signed certificates are working. Basically, I accept everything and ignore every checking of any certificate. This has been working fine for some time now, but it no longer work for Android 2.2 FroYo. When trying to connect, it will return an exception: java.io.IOException: SSL handshake failure: I/O error during system call, Broken pipe Here is how I initialize the HttpClient: SchemeRegistry registry = new SchemeRegistry(); registry.register(new Scheme("http", new PlainSocketFactory(), 80)); registry.register(new Scheme("https", (trustAll ? new FakeSocketFactory() : SSLSocketFactory.getSocketFactory()), 443)); client = new DefaultHttpClient(new ThreadSafeClientConnManager(httpParams, registry), httpParams); I make use of a FakeSocketFactory and FakeTrustManager, of which the source can be found here: http://code.google.com/p/transdroid/source/browse/#svn/trunk/src/org/transdroid/util Again, I don't understand why it suddenly stopped work, or even what the error 'Broken pipe' means. I have seen messages on Twitter that Seesmic and Twidroid fail with SSL enabled on FroYo as well, but am unsure if it's related. Thanks for any directions/help!

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  • GXT Performance Issues

    - by pearl
    Hi All, We are working on a rather complex system using GXT. While everything works great on FF, IE (especially IE6) is a different story (looking at more than 10 seconds until the browser renders the page). I understand that one of the main reasons is DOM manipulation which is a disaster under IE6 (See http://www.quirksmode.org/dom/innerhtml.html). This can be thought to be a generic problem of a front-end Javascript framework (i.e. GWT) but a simple code (see below) that executes the same functionality proofs otherwise. In fact, under IE6 - getSomeGWT() takes 400ms while getSomeGXT() takes 4 seconds. That's a x10 factor which makes a huge different for the user experience !!! private HorizontalPanel getSomeGWT() { HorizontalPanel pointsLogoPanel = new HorizontalPanel(); for (int i=0; i<350; i++) { HorizontalPanel innerContainer = new HorizontalPanel(); innerContainer.add(new Label("some GWT text")); pointsLogoPanel.add(innerContainer); } return pointsLogoPanel; } private LayoutContainer getSomeGXT() { LayoutContainer pointsLogoPanel = new LayoutContainer(); pointsLogoPanel.setLayoutOnChange(true); for (int i=0; i<350; i++) { LayoutContainer innerContainer = new LayoutContainer(); innerContainer.add(new Text("just some text")); pointsLogoPanel.add(innerContainer); } return pointsLogoPanel; } So to solve/mitigate the issue one would need to - a. Reduce the number of DOM manipulations; or b. Replace them with innerHTML. AFAIK, (a) is simply a side effect of using GXT and (b) is only possible with UiBinder which isn't supported yet by GXT. Any ideas? Thanks in advance!

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  • C# file write permission issue under "Program Files" folder

    - by George2
    Hello everyone, I am using inno setup to make a installation package for my application, and my application is written by C# + .Net 2.0 + VSTS 2008. Inno setup = http://www.jrsoftware.org/isinfo.php and I install my application under Program Files/Foo folder (Foo is my application name). My application is targeting to Windows Vista. The issue I found is my program cannot write to the folder Program Files/Foo. And I need the permission of write to this folder in order to save some configuration files. The strange thing I notice is the folder Program Files/Foo is marked as readonly and I have checked all folders under Program Files are marked with read only, such as Office. My questions are, Why all folders are marked as read only under Program Files? It means we should not write to individual application folders under Program Files? If not, where should we write information to disk like user last selected configuration information of an individual application? If we could write to individual application folders under Program Files, what is the solution? I do not want my application to Run As administrator to solve this issue, and if there are solution to write to this folder, I want to require minimal permission if possible. thanks in advance, George

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  • How can I transform XML to invalid XML using XSLT?

    - by Damovisa
    I need to transform a valid XML document to the OFX v1.0.2 format. This format is more or less XML, but it's technically invalid and therefore cannot be parsed as XML. I'm having trouble getting my Xml transformation working because the .Net XslCompiledTransform object insists on interpreting the XSL as an XML document (which is fair enough). If I escape the xml-ish tags using &lt; and &gt, they get removed when I download the file. Here's the start of my XSLT: <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="text"></xsl:output> <xsl:param name="currentdate"></xsl:param> <xsl:template match="Transactions"> OFXHEADER:100 DATA:OFXSGML VERSION:102 SECURITY:NONE ENCODING:USASCII CHARSET:1252 COMPRESSION:NONE OLDFILEUID:NONE NEWFILEUID:NONE <OFX> <SIGNONMSGSRSV1> <SONRS> <STATUS> <CODE>0 <SEVERITY>INFO </STATUS> <DTSERVER><xsl:value-of select="$currentdate" /> <LANGUAGE>ENG Any suggestions?

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  • XMLBeans - xsi:type stripped using Axis2 and Tomcat?

    - by Matthew Gamble
    I’m new to XMLBeans and have been trying to use it to create an XML document as part of an axis2 web service. When I run my code as a standard Java application or as a standard servlet, the XML is correctly generated: <?xml version="1.0" encoding="UTF-8"?> <c:BroadsoftDocument protocol="OCI" xmlns:c="C"> <sessionId>000000001</sessionId> <command xsi:type="AuthenticationRequest" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"> <userId>admin</userId></command> </c:BroadsoftDocument> However, when the exact same code is run under Axis2 & Tomcat in a servlet I get: <?xml version="1.0" encoding="UTF-8"?> <c:BroadsoftDocument protocol="OCI" xmlns:c="C"> <sessionId>000000001</sessionId> <command> <userId>admin</userId></command> </c:BroadsoftDocument> This of course isn’t valid – the xsi:type of the “command” element is stripped when the code is run under Tomcat. Does anyone have any suggestions of what I could be doing wrong that would cause this type of issue only when running under Axis2? At first I thought it was a Tomcat issue, but after creating a generic servlet and running the exact same code I don't have any issues. I've tried playing with the XMLOptions for XMLBeans, but couldn't seem to resolve the problem. The options I'm currently using are: xmlOptions = new XmlOptions(); xmlOptions.setCharacterEncoding("UTF-8"); xmlOptions.setUseDefaultNamespace(); xmlOptions.setSaveAggressiveNamespaces(); xmlOptions.setSavePrettyPrint();

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  • Encoding issue - 2nd band of ISO-8859-1 values do not get encoded?

    - by bstack
    Hello, I want to send the pound sign character i.e. '£' encoded as ISO-8859-1 across the wire. I perform this by doing the following: var _encoding = Encoding.GetEncoding("iso-8859-1"); var _requestContent = _encoding.GetBytes(requestContent); var _request = (HttpWebRequest)WebRequest.Create(target); _request.Headers[HttpRequestHeader.ContentEncoding] = _encoding.WebName; _request.Method = "POST"; _request.ContentType = "application/x-www-form-urlencoded; charset=iso-8859-1"; _request.ContentLength = _requestContent.Length; _requestStream = _request.GetRequestStream(); _requestStream.Write(_requestContent, 0, _requestContent.Length); _requestStream.Flush(); _requestStream.Close(); When I put a breakpoint at the target, I expect to receive the following: '%a3', however I receive '%u00a3' instead. ISO-8859-1 is divided into 2 groups of characters: (ref: http://en.wikipedia.org/wiki/ISO_8859-1) The lower range 20 to 7E - is where all characters seem to be encoded correctly The higher range A0 to FF - is where all characters seem to encode to their Unicode equivalent value As '£' is in higher range A0 to FF, it gets encoded to %u00a3. In fact when I use the first few characters of the higher range A0 to FF i.e. '¡¢£¤¥¦§¨©ª«¬®', I get '%u00a1%u00a2%u00a3%u00a4%u00a5%u00a6%u00a7%u00a8%u00a9%u00aa%u00ab%u00ac%u00ae'. This behaviour is consistent. The question I have is why do characters in the higher range A0 to FF get encoded to their unicode value - and not to their equivalent ISO-8859-1 value? Help would be greatly appreciated... Billy

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  • facebook connect button not producing pop-up

    - by bigmac
    This is a really simple question, but I can't seem to find the answer. I am just getting started with Facebook Connect. I would like to use it only for user authentication, so there is no need for my users to create another account. I used a very basic example from wiki.developers.facebook.com : <html xmlns="http://www.w3.org/1999/xhtml" xmlns:fb="http://www.facebook.com/2008/fbml"> <head></head> <body> <fb:login-button></fb:login-button> <script src="http://static.ak.connect.facebook.com/js/api_lib/v0.4/FeatureLoader.js.php/en_US" type="text/javascript"></script> <script type="text/javascript"> FB.init("***api-key***", "xd_receiver.htm"); </script> </body> </html> Very straight forward. It seems to work fine. However, if I am currently already logged in to Facebook, the pop-up window doesn't come up when I click the login button. Why is that?

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  • what is the best way to stream a audio file to website users/listners

    - by Naveen Chamikara Gamage
    I'm developing a music site which will stream audio files stored in a server to users, audio files will be played through flash player placed in a webpage.. As I heard I need to use a streaming media server for streaming audio files ( like 2mb to 3mb in size).. Do I need to use one? I found some streaming media server softwares like http://www.icecast.org - but as in their documentation, It is used for streaming radio stations and live streaming purposes, but I just need to stream audio files faster and in low size (low bandwidth) with good quality.. I heard I need to encode the audio files first and then send them to listeners and in their end audio files need to be decoded again. Is that true? How can I do that? if I need to use a special web server, where should I host my files? Any good hosting providers? if I host audio files in a normal web server, they will use HTTP or TCP to deliver my audio files to users/ listners but I found that HTTP and TCP are not good ways to use for multi media purposes like streaming audio and video files, and they are used for delivering HTML and stuff. I found I should use RSTP or UDP for streaming audio files.. What should I use? I know that .MP3 files has much better quality than the other formats but it also gives huge size to the audio files.. which format should I use for audio files? Most of the best quality audio files are more than 7mb so I'm planning to convert them my self using a software so I could get low size files with some level of good quality. If I'm converting my audio files what is the good BITRATE I should use for my files? Any known best softwares for converting audio files while keeping quality in a good level? Note** - I know that I will not need complex requirements at the beginning of the site but I wanted to what are the best ways like they are using for soundcloud.com

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  • Insert video clip in a lyx presentation and play it in GNU/Linux.

    - by Orjanp
    How can I insert a video clip into a presentation created in Lyx? Have seen http://www.latex-community.org/forum/viewtopic.php?f=19&t=48. It works, but there the video starts in the background in an external player. I would prefer it to be played in the presentation itself. If an external player is used it it should at least start in the foreground. But the presentation takes the foreground. Using evince in GNU/linux as pdf viewer. Beamer is used as a presentation template. Is it possible to play a video file in an embedded player in the presentation itself? Created an example presentation. The code is found below. \documentclass[english]{beamer} \usepackage{mathptmx} \usepackage[T1]{fontenc} \usepackage[latin9]{inputenc} \usepackage{amsmath} \usepackage{amssymb} \makeatletter %%%%%%%%%%%%%%%%%%%%%%%%%%%%%% Textclass specific LaTeX commands. % this default might be overridden by plain title style \newcommand\makebeamertitle{\frame{\maketitle}}% \AtBeginDocument{ \let\origtableofcontents=\tableofcontents \def\tableofcontents{\@ifnextchar[{\origtableofcontents}{\gobbletableofcontents}} \def\gobbletableofcontents#1{\origtableofcontents} } \makeatletter \long\def\lyxframe#1{\@lyxframe#1\@lyxframestop}% \def\@lyxframe{\@ifnextchar<{\@@lyxframe}{\@@lyxframe<*>}}% \def\@@lyxframe<#1>{\@ifnextchar[{\@@@lyxframe<#1>}{\@@@lyxframe<#1>[]}} \def\@@@lyxframe<#1>[{\@ifnextchar<{\@@@@@lyxframe<#1>[}{\@@@@lyxframe<#1>[<*>][}} \def\@@@@@lyxframe<#1>[#2]{\@ifnextchar[{\@@@@lyxframe<#1>[#2]}{\@@@@lyxframe<#1>[#2][]}} \long\def\@@@@lyxframe<#1>[#2][#3]#4\@lyxframestop#5\lyxframeend{% \frame<#1>[#2][#3]{\frametitle{#4}#5}} \makeatother \def\lyxframeend{} % In case there is a superfluous frame end %%%%%%%%%%%%%%%%%%%%%%%%%%%%%% User specified LaTeX commands. \usetheme{Warsaw} \usepackage{hyperref} \makeatother \usepackage{babel} \begin{document} \title{Testing video} \makebeamertitle \lyxframeend{}\section{Testing video} \lyxframeend{}\subsection{Testing video} \lyxframeend{}\lyxframe{Testing video} \href{run:video.wmv}{Movie} \appendix \lyxframeend{} \end{document}

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  • how to solve the error in GWT ?

    - by megala
    I created one GWT project in eclipse.It contained the following codings Program 1:Creategroup package com.crimson.creategroup; import javax.persistence.Basic; import javax.persistence.Entity; import javax.persistence.GeneratedValue; import javax.persistence.GenerationType; import javax.persistence.Id; import com.google.appengine.api.datastore.Key; import com.google.appengine.api.users.User; @Entity(name="CreateGroup") public class Creategroup { @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private Key key; @Basic private User author; @Basic private String groupname; @Basic private String groupid; @Basic private String groupdesc; @Basic private String emailper; public Key getKey() { return key; } public void setAuthor(User author) { this.author = author; } public User getAuthor() { return author; } public void setGroupname(String groupname) { this.groupname = groupname; } public String getGroupname() { return groupname; } public void setGroupid(String groupid) { this.groupid = groupid; } public String getGroupid() { return groupid; } public void setGroupdesc(String groupdesc) { this.groupdesc = groupdesc; } public String getGroupdesc() { return groupdesc; } public void setEmailper(String emailper) { this.emailper = emailper; } public String getEmailper() { return emailper; } public Creategroup(String groupname,String groupid,String groupdesc ,String emailper) { this.groupname = groupname; this.groupid = groupid; this.groupdesc = groupdesc; this.emailper=emailper; } } Program 2:Creategroupservlet package com.crimson.creategroup; import java.io.IOException; import javax.persistence.EntityManager; import javax.servlet.http.HttpServlet; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import com.google.appengine.api.users.User; import com.google.appengine.api.users.UserService; import com.google.appengine.api.users.UserServiceFactory; import java.util.logging.Logger; public class Creategroupservlet extends HttpServlet{ private static final long serialVersionUID = 1L; private static final Logger log = Logger.getLogger(Creategroupservlet.class.getName()); public void doPost(HttpServletRequest req, HttpServletResponse resp) throws IOException { UserService userService = UserServiceFactory.getUserService(); User user = userService.getCurrentUser(); String groupname=req.getParameter("gname"); String groupid=req.getParameter("groupdesc"); String groupdesc=req.getParameter("gdesc"); String email=req.getParameter("eperm"); if (groupname == null) { System.out.println("Complete all the details"); } if (user != null) { log.info("Greeting posted by user " + user.getNickname() + "\n " + groupname+"\n" + groupid + "\n" + groupdesc + "\n" + email); final EntityManager em = EMF.get(); try { Creategroup group = new Creategroup(groupname,groupid,groupdesc,email); em.persist(group); } finally { em.close(); } } else { throw new IllegalArgumentException("anonymous posts not permitted!"); } resp.sendRedirect("/group.jsp"); } } Program 3:EMF package com.crimson.creategroup; import javax.persistence.EntityManager; import javax.persistence.EntityManagerFactory; import javax.persistence.Persistence; public class EMF { private static final EntityManagerFactory emfInstance = Persistence.createEntityManagerFactory("transactions-optional"); private EMF() { } public static EntityManager get() { return emfInstance.createEntityManager(); } } Program 4:index.jsp <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <%@ page contentType="text/html;charset=UTF-8" language="java" %> <%@ page import="com.google.appengine.api.users.User" %> <%@ page import="com.google.appengine.api.users.UserService" %> <%@ page import="com.google.appengine.api.users.UserServiceFactory" %> <html> <head> <meta http-equiv="content-type" content="text/html; charset=UTF-8"> <link type="text/css" rel="stylesheet" href="Group.css"> <title>Add Group into DataStore</title> </head> <body> <div id="nav"> <% UserService userService = UserServiceFactory.getUserService(); User user = userService.getCurrentUser(); if (user != null) { response.sendRedirect("/group.jsp"); %> <% } else { %> <a href="<%= userService.createLoginURL(request.getRequestURI()) %>">Sign in</a> <% } %> </div> <h1>Create Group</h1> <table> <tr> <td colspan="2" style="font-weight:bold;"> This demo uses secured resources, so you need to be logged into your Gmail account.</td> </tr> </table> </body> </html> program 5:group.jsp <%@ page contentType="text/html;charset=UTF-8" language="java" %> <%@ page import="java.util.List" %> <%@ page import="javax.persistence.EntityManager" %> <%@ page import="com.google.appengine.api.users.User" %> <%@ page import="com.google.appengine.api.users.UserService" %> <%@ page import="com.google.appengine.api.users.UserServiceFactory" %> <%@ page import="com.crimson.creategroup.Creategroup" %> <%@ page import="com.crimson.creategroup.EMF" %> <html> <body> <% UserService userService = UserServiceFactory.getUserService(); User user = userService.getCurrentUser(); if (user != null) { %> <p>Hello, <%= user.getNickname() %>! (You can <a href="<%= userService.createLogoutURL(request.getRequestURI()) %>">sign out</a>.)</p> <% } else { response.sendRedirect("/index.jsp"); } %> <% final EntityManager em = EMF.get(); try { String query = "select from " + Creategroup.class.getName(); List<Creategroup> groups = (List<Creategroup>) em.createQuery(query).getResultList(); if (groups.isEmpty()) { %> <p>This table not having any group</p> <% } else { for (Creategroup g : groups) { %> <p><b><%= g.getAuthor().getNickname() %></b> wrote:</p> <blockquote><%= g. getGroupname() %></blockquote> <blockquote><%= g. getGroupid() %></blockquote> <blockquote><%= g. getGroupdesc() %></blockquote> <blockquote><%= g. getEmailper() %></blockquote> <% } } } finally { em.close(); } %> <form action="/sign" method="post"> <input type="text" name="Groupname" size="25"> <input type="text" name="Groupid" size="25"> <input type="text" name="Groupdesc" size="250"> <input type="text" name="Emaildesc" size="25"> <div><input type="submit" value="CREATE GROUP" /></div> </form> </body> </html> Program 6:Web.xml <?xml version="1.0" encoding="UTF-8"?> <!DOCTYPE web-app PUBLIC "-//Sun Microsystems, Inc.//DTD Web Application 2.3//EN" "http://java.sun.com/dtd/web-app_2_3.dtd"> <web-app> <!-- Servlets --> <servlet> <servlet-name>Creategroupservlet</servlet-name> <servlet-class>com.crimson.creategroup.Creategroupservlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>Creategroupservlet</servlet-name> <url-pattern>sign in</url-pattern> </servlet-mapping> <!-- Default page to serve --> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list> </web-app> Program 7:persistence.xml <?xml version="1.0" encoding="UTF-8" ?> <persistence xmlns="http://java.sun.com/xml/ns/persistence" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/persistence http://java.sun.com/xml/ns/persistence/persistence_1_0.xsd" version="1.0"> <persistence-unit name="transactions-optional"> <provider>org.datanucleus.store.appengine.jpa.DatastorePersistenceProvider</provider> <properties> <property name="datanucleus.NontransactionalRead" value="true"/> <property name="datanucleus.NontransactionalWrite" value="true"/> <property name="datanucleus.ConnectionURL" value="appengine"/> </properties> </persistence-unit> </persistence but is shows the following error Missing required argument 'module[s]' Google Web Toolkit 2.0.0 DevMode [-noserver] [-port port-number | "auto"] [-whitelist whitelist-string] [-blacklist blacklist-string] [-logdir directory] [-logLevel level] [-gen dir] [-codeServerPort port-number | "auto"] [-server servletContainerLauncher] [-startupUrl url] [-war dir] [-extra dir] [-workDir dir] module[s] How to solve this thanks in advance?

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  • Twitter4J throws exception in TwitterFactory

    - by Philipp Andre
    Hello Guys, i'm trying to access twitter via oauth. Therefore, i registered my app, downloaded Twitter4j, added the jars in my Eclipse-Project, and then tried to execute the following code: Twitter twitter = new TwitterFactory().getOAuthAuthorizedInstance("[key]","[secretKey]); RequestToken requestToken = twitter.getOAuthRequestToken(); System.out.println(requestToken.getAuthorizationURL()); But it raises the following exception: [Sat May 29 11:19:11 CEST 2010]Using class twitter4j.internal.logging.StdOutLoggerFactory as logging factory. [Sat May 29 11:19:11 CEST 2010]Use twitter4j.internal.http.alternative.HttpClientImpl as HttpClient implementation. Exception in thread "main" java.lang.AssertionError: java.lang.reflect.InvocationTargetException at twitter4j.internal.http.HttpClientFactory.getInstance(HttpClientFactory.java:71) at twitter4j.internal.http.HttpClientWrapper.<init>(HttpClientWrapper.java:59) at twitter4j.http.OAuthAuthorization.init(OAuthAuthorization.java:83) at twitter4j.http.OAuthAuthorization.<init>(OAuthAuthorization.java:74) at twitter4j.TwitterFactory.getOAuthAuthorizedInstance(TwitterFactory.java:112) at MainProgram.main(MainProgram.java:18) Caused by: java.lang.reflect.InvocationTargetException at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) at sun.reflect.NativeConstructorAccessorImpl.newInstance(Unknown Source) at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(Unknown Source) at java.lang.reflect.Constructor.newInstance(Unknown Source) at twitter4j.internal.http.HttpClientFactory.getInstance(HttpClientFactory.java:65) ... 5 more Caused by: java.lang.NoClassDefFoundError: org/apache/http/impl/client/DefaultHttpClient at twitter4j.internal.http.alternative.HttpClientImpl.<init>(HttpClientImpl.java:63) ... 10 more I currently can't figure out why ... can you please give me some suggestions? Best regards Philipp

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  • Intern working for Indian NGO - Help with PHP 4, advising staff

    - by Kevin Burke
    Hello, For the past three months I've been working for an Indian NGO (http://sevamandir.org), doing some volunteer work in the field but also trying to improve their website, which needs a ton of work. Recently I've been trying to fix the "subscribe to newsletter" button, which is broken. I used filter_var to filter the email input, but when I tried to test this out I got an error. Then I learned that the web host is still using php version 4.3.2 and register_globals is turned on. I've mentioned that they should upgrade their web host before (they are paying around $50 per year for Rediff Web Hosting, complete with 100MB storage and 1 MySQL database). That would add a lot of complexity for the IT staff of 3, who would have to update everyone's email information (I assume? this is a 250-person organization), and have me find a new web host and teach them about it. The staff isn't that sophisticated about web usage - the head guy still uses IE6, and the website's laid out in tables (they use Dreamweaver WYSIWYG to lay out pages). So I've got two options - use regular expressions to filter the email, which I'm not that skilled at doing (and would be more vulnerable to exploitation after I leave), turn off register globals and then try to teach the staff what I'm doing, or try to get them to upgrade their versions of PHP and MySQL and/or change web host. I'd appreciate some advice. Thanks for your help, Kevin

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  • A problem happened during install the ruby

    - by Alex
    I’m a freshman on Ruby and now trying to install ruby on my machine according to the Tutorial on http://wiki.openqa.org/display/WTR/Tutorial However, after I installed the ruby186-26, and run the command “gem update --system”, the following error occurred: C:\Documents and Settings\e482090\Desktopgem update --system c:/ruby/lib/ruby/site_ruby/1.8/rubygems/config_file.rb:51:in initialize': Inval id argument - <Not Set>/.gemrc (Errno::EINVAL) from c:/ruby/lib/ruby/site_ruby/1.8/rubygems/config_file.rb:51:inopen' from c:/ruby/lib/ruby/site_ruby/1.8/rubygems/config_file.rb:51:in initi alize' from c:/ruby/lib/ruby/site_ruby/1.8/rubygems/gem_runner.rb:36:innew' from c:/ruby/lib/ruby/site_ruby/1.8/rubygems/gem_runner.rb:36:in do_con figuration' from c:/ruby/lib/ruby/site_ruby/1.8/rubygems/gem_runner.rb:25:inrun' from c:/ruby/bin/gem:23 C:\Documents and Settings\e482090\Desktopgem install watir c:/ruby/lib/ruby/site_ruby/1.8/rubygems/config_file.rb:51:in initialize': Inval id argument - <Not Set>/.gemrc (Errno::EINVAL) from c:/ruby/lib/ruby/site_ruby/1.8/rubygems/config_file.rb:51:inopen' from c:/ruby/lib/ruby/site_ruby/1.8/rubygems/config_file.rb:51:in initi alize' from c:/ruby/lib/ruby/site_ruby/1.8/rubygems/gem_runner.rb:36:innew' from c:/ruby/lib/ruby/site_ruby/1.8/rubygems/gem_runner.rb:36:in do_con figuration' from c:/ruby/lib/ruby/site_ruby/1.8/rubygems/gem_runner.rb:25:inrun' from c:/ruby/bin/gem:23 Meanwhile, we have tried this on other machines and the result turned out ok. Thus, my question is why the error happened on my pc? Have you met this kind of error before?

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  • Bitbucket API authentication with Python's HTTPBasicAuthHandler

    - by jbochi
    I'm trying to get the list of issues on a private repository using bitbucket's API. I have confirmed that HTTP Basic authentication works with hurl, but I am unable to authenticate in Python. Adapting the code from this tutorial, I have written the following script. import cookielib import urllib2 class API(): api_url = 'http://api.bitbucket.org/1.0/' def __init__(self, username, password): self._opener = self._create_opener(username, password) def _create_opener(self, username, password): cj = cookielib.LWPCookieJar() cookie_handler = urllib2.HTTPCookieProcessor(cj) password_manager = urllib2.HTTPPasswordMgrWithDefaultRealm() password_manager.add_password(None, self.api_url, username, password) auth_handler = urllib2.HTTPBasicAuthHandler(password_manager) opener = urllib2.build_opener(cookie_handler, auth_handler) return opener def get_issues(self, username, repository): query_url = self.api_url + 'repositories/%s/%s/issues/' % (username, repository) try: handler = self._opener.open(query_url) except urllib2.HTTPError, e: print e.headers raise e return handler.read() api = API(username='my_username', password='XXXXXXXX') api.get_issues('my_username', 'my_repository') results in: >>> Server: nginx/0.7.62 Date: Mon, 19 Apr 2010 16:15:06 GMT Content-Type: text/plain Connection: close Vary: Authorization,Cookie Content-Length: 9 Traceback (most recent call last): File "C:/USERS/personal/bitbucket-burndown/bitbucket-api.py", line 29, in <module> print api.get_issues('my_username', 'my_repository') File "C:/USERS/personal/bitbucket-burndown/bitbucket-api.py", line 25, in get_issues raise e HTTPError: HTTP Error 401: UNAUTHORIZED api.get_issues('jespern', 'bitbucket') works like a charm. What's wrong with my code?

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  • More issues with IntelliJ 9.0.1 "Hello World" in Scala - Predef version 5.0 vs 4.1

    - by Alex R
    Any ideas what could cause this? Scala signature Predef has wrong version Expected 5.0 found: 4.1 in .... scala-library.jar I tried both versions 2.7.6 and 2.8 RC1 of scala-*.jar, the result was the same. JDK is 1.6.u20. UPDATE Today uninstalled IntelliJ 9.0.1, and installed 9.0.2 Early Availability, with the 4/14 stable version of the Scala plug-in. Then I setup a project from scratch through the wizards: new project from scratch JDK is 1.6.u20 accept the default (project) instead of global / module accept the download of Scala 2.8.0beta1 into project's lib folder Created a new class: object hello { def main(args: Array[String]) { println("hello: " + args); } } For my efforts, I now have a brand-new error :) Here it is: Scalac internal error: class java.lang.ClassNotFoundException [java.net.URLClassLoader$1.run(URLClassLoader.java:202), java.security.AccessController.doPrivileged(Native Method), java.net.URLClassLoader.findClass(URLClassLoader.java:190), java.lang.ClassLoader.loadClass(ClassLoader.java:307), sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:301), java.lang.ClassLoader.loadClass(ClassLoader.java:248), java.lang.Class.forName0(Native Method), java.lang.Class.forName(Class.java:169), org.jetbrains.plugins.scala.compiler.rt.ScalacRunner.main(ScalacRunner.java:72)] Thanks

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  • How to draw line inside a scatter plot

    - by ruffy
    I can't believe that this is so complicated but I tried and googled for a while now. I just want to analyse my scatter plot with a few graphical features. For starters, I want to add simply a line. So, I have a few (4) points and like in this plot [1] I want to add a line to it. http://en.wikipedia.org/wiki/File:ROC_space-2.png [1] Now, this won't work. And frankly, the documentation-examples-gallery combo and content of matplotlib is a bad source for information. My code is based upon a simple scatter plot from the gallery: # definitions for the axes left, width = 0.1, 0.85 #0.65 bottom, height = 0.1, 0.85 #0.65 bottom_h = left_h = left+width+0.02 rect_scatter = [left, bottom, width, height] # start with a rectangular Figure fig = plt.figure(1, figsize=(8,8)) axScatter = plt.axes(rect_scatter) # the scatter plot: p1 = axScatter.scatter(x[0], y[0], c='blue', s = 70) p2 = axScatter.scatter(x[1], y[1], c='green', s = 70) p3 = axScatter.scatter(x[2], y[2], c='red', s = 70) p4 = axScatter.scatter(x[3], y[3], c='yellow', s = 70) p5 = axScatter.plot([1,2,3], "r--") plt.legend([p1, p2, p3, p4, p5], [names[0], names[1], names[2], names[3], "Random guess"], loc = 2) # now determine nice limits by hand: binwidth = 0.25 xymax = np.max( [np.max(np.fabs(x)), np.max(np.fabs(y))] ) lim = ( int(xymax/binwidth) + 1) * binwidth axScatter.set_xlim( (-lim, lim) ) axScatter.set_ylim( (-lim, lim) ) xText = axScatter.set_xlabel('FPR / Specificity') yText = axScatter.set_ylabel('TPR / Sensitivity') bins = np.arange(-lim, lim + binwidth, binwidth) plt.show() Everything works, except the p5 which is a line. Now how is this supposed to work? What's good practice here?

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  • Rails, RSpec and Webrat: Expected output matches rendered output but still getting error in view spe

    - by Anthony Burns
    Hello all, I've just gotten started using BDD with RSpec/Cucumber/Webrat and Rails and I've run into some frustration trying to get my view spec to pass. First of all, I am running Ruby 1.9.1p129 with Rails 2.3.2, RSpec and RSpec-Rails 1.2.6, Cucumber 0.3.11, and Webrat 0.4.4. Here is the code relevant to my question config/routes.rb: map.b_posts 'backend/posts', :controller => 'backend/posts', :action => 'backend_index', :conditions => { :method => :get } map.connect 'backend/posts', :controller => 'backend/posts', :action => 'create', :conditions => { :method => :post } views/backend/posts/create.html.erb: <% form_tag do %> <% end %> *spec/views/backend/posts/create.html.erb_spec.rb:* describe "backend/posts/create.html.erb" do it "should render a form to create a post" do render "backend/posts/create.html.erb" response.should have_selector("form", :method => 'post', :action => b_posts_path) do |form| # Nothing here yet. end end end Here is the relevant part of the output when I run script/spec: 'backend/posts/create.html.erb should render a form to create a post' FAILED expected following output to contain a <form method='post' action='/backend/posts'/> tag: <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.0 Transitional//EN" "http://www.w3.org/TR/REC-html40/loose.dtd"> <html><body><form action="/backend/posts" method="post"> </form></body></html> It would appear to me that what have_selector is looking for is exactly what the template generates, yet the example still fails. I am very much looking forward to seeing my error (because I have a feeling it is my error). Any help is much appreciated!

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  • Debugging MinGW program with gdb on Windows, not terminating at assert failure

    - by devil
    How do I set up gdb on window so that it does not allow a program with assertion failure to terminate? I intend to check the stack trace and variables in the program. For example, running this test.cpp program compiled with MinGW 'g++ -g test.cpp -o test' in gdb: #include <cassert> int main(int argc, char ** argv) { assert(1==2); return 0; } Gives: $ gdb test.exe GNU gdb 6.8 Copyright (C) 2008 Free Software Foundation, Inc. License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html> This is free software: you are free to change and redistribute it. There is NO WARRANTY, to the extent permitted by law. Type "show copying" and "show warranty" for details. This GDB was configured as "i686-pc-mingw32"... (gdb) r Starting program: f:\code/test.exe [New thread 4616.0x1200] Error: dll starting at 0x77030000 not found. Error: dll starting at 0x75f80000 not found. Error: dll starting at 0x77030000 not found. Error: dll starting at 0x76f30000 not found. Assertion failed: 1==2, file test.cpp, line 2 This application has requested the Runtime to terminate it in an unusual way. Please contact the application's support team for more information. Program exited with code 03. (gdb) I would like to be able to stop the program from terminating immediately, like how Visual Studio's debugger and gdb on Linux does it. I have done a search and found some stuff on trapping signals but I can't seem to find a good post on how to set up gdb to do this.

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  • Setting Access-Control-Allow-Origin in Dreamhost possible?

    - by Kaushik Gopal
    Just wanted a confirmation for this: Firefox currently doesn't play well for picking custom fonts through a sub-domain via the font-face tag. Other browsers do this without any problems. A little research showed up saying that i am required to set the Access-Control-Allow-Origin as is shown in the link here: http://pastie.org/653265 Essentially i have my blog at kaushikgopal.com/blog and i was trying to access fonts that within this blog that are available at font.kaushikgopal.com. I tried changing the same in my .htaccess file but couldn't resolve the issue.(I placed a .htaccess file within the font sub-domain folder and directly pasted code from the above pastie link). I submitted a ticket to dreamhost asking for assistance and they were helpful in clearly stating "We do not support Access-Control-Allow-Origin on shared hosting servers". So i didn't go the sub-domain route for fonts. But i'm a little curious, has anyone tried this (with a dreamhost hosting account would be helpful)? Just want to confirm what the tech-support guy suggested is accurate and there's no other way. Thanks. Another nice link clearly stating the problem : http://www.stevesouders.com/tests/font-face/xdomain.php

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