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  • Dynamic evaluation of a table column within an insert before trigger

    - by Tim Garver
    HI All, I have 3 tables, main, types and linked. main has an id column and 32 type columns. types has id, type linked has id, main_id, type_id I want to create an insert before trigger on the main table. It needs to compare its 32 type columns to the values in the types table if the main table column has an 'X' for its value and insert the main_id and types_id into the linked table. i have done a lot of searching, and it looks like a prepared statement would be the way to go, but i wanted to ask the experts. The issue, is i dont want to write 32 IF statements, and even if i did, i need to query the types table to get the ID for that type, seems like a huge waist of resources. Ideally i want to do this inside of my trigger: BEGIN DECLARE @types results_set -- (not sure if this is a valid type); -- (iam sure my loop syntax is all wrong here)... SET @types = (select * from types) for i=0;i<types.records;i++ { IF NEW.[i.type] = 'X' THEN insert into linked (main_id,type_id) values (new.ID, i.id); END IF; } END; Anyway, This is what i was hoping to do, maybe there is a way to dynamically set the field name inside of a results loop, but i cant find a good example of this. Thanks in advance Tim

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  • Currently using View, Should I use a hard table instead?

    - by 1001010101
    I am currently debating whether my table, mapping_uGroups_uProducts, which is a view formed by the following table: CREATE ALGORITHM=UNDEFINED DEFINER=`root`@`localhost` SQL SECURITY DEFINER VIEW `db`.`mapping_uGroups_uProducts` AS select distinct `X`.`upID` AS `upID`,`Z`.`ugID` AS `ugID` from ((`db`.`mapping_uProducts_Products` `X` join `db`.`productsInfo` `Y` on((`X`.`pID` = `Y`.`pID`))) join `db`.`mapping_uGroups_Groups` `Z` on((`Y`.`gID` = `Z`.`gID`))); My current query is: SELECT upID FROM uProductsInfo \ JOIN fs_uProducts USING (upID) column \ JOIN mapping_uGroups_uProducts USING (upID) -- could be faster if we use hard table and index \ JOIN mapping_fs_key USING (fsKeyID) \ WHERE fsName="OVERALL" \ AND ugID=1 \ ORDER BY score DESC \ LIMIT 0,30; which is pretty slow. (for 30 results, it requires about 10 secondes). I think the reason for my query being so slow is definitely due to the fact that that particular query relies on a VIEW which has no index to speed things up. +----+-------------+----------------+--------+----------------+---------+---------+---------------------------------------+-------+---------------------------------+ | id | select_type | table | type | possible_keys | key | key_len | ref | rows | Extra | +----+-------------+----------------+--------+----------------+---------+---------+---------------------------------------+-------+---------------------------------+ | 1 | PRIMARY | mapping_fs_key | const | PRIMARY,fsName | fsName | 386 | const | 1 | Using temporary; Using filesort | | 1 | PRIMARY | <derived2> | ALL | NULL | NULL | NULL | NULL | 19706 | Using where | | 1 | PRIMARY | uProductsInfo | eq_ref | PRIMARY | PRIMARY | 4 | mapping_uGroups_uProducts.upID | 1 | Using index | | 1 | PRIMARY | fs_uProducts | ref | upID | upID | 4 | db.uProductsInfo.upID | 221 | Using where | | 2 | DERIVED | X | ALL | PRIMARY | NULL | NULL | NULL | 40772 | Using temporary | | 2 | DERIVED | Y | eq_ref | PRIMARY | PRIMARY | 4 | db.X.pID | 1 | Distinct | | 2 | DERIVED | Z | ref | PRIMARY | PRIMARY | 4 | db.Y.gID | 2 | Using index; Distinct | +----+-------------+----------------+--------+----------------+---------+---------+---------------------------------------+-------+---------------------------------+ 7 rows in set (0.48 sec) The explain here looks pretty cryptic, and I don't know whether I should drop view and write a script to just insert everything in the view to a hard table. ( obviously, it will lose the flexibility of the view since the mapping changes quite frequently). Does anyone have any idea to how I can optimize my schema better?

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  • self join to select consecutive numbers

    - by shantanuo
    CREATE TABLE `mybug` ( `SEAT_NO` decimal(2,0) NOT NULL, `ROW_NO` decimal(2,0) NOT NULL, `COL_NO` decimal(2,0) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; INSERT INTO `mybug` VALUES ('1','1','1'),('26','7','2'),('31','8','2'),('32','8','1'),('33','9','1'),('34','9','2'),('35','9','5'),('36','9','6'),('37','10','6'),('38','10','5'),('39','10','2'),('40','10','1'),('41','11','1'),('42','11','2'),('43','11','4'),('44','11','5'); +---------+--------+--------+ | SEAT_NO | ROW_NO | COL_NO | +---------+--------+--------+ | 1 | 1 | 1 | | 26 | 7 | 2 | | 31 | 8 | 2 | | 32 | 8 | 1 | | 33 | 9 | 1 | | 34 | 9 | 2 | | 35 | 9 | 5 | | 36 | 9 | 6 | | 37 | 10 | 6 | | 38 | 10 | 5 | | 39 | 10 | 2 | | 40 | 10 | 1 | | 41 | 11 | 1 | | 42 | 11 | 2 | | 43 | 11 | 4 | | 44 | 11 | 5 | +---------+--------+--------+ 16 rows in set (0.00 sec) In the above chart, I need to select 2 seats those are in the same row AND column numbers are next to each other. For e.g. Seat Numbers 38 & 39 can not be issued even if both the seats are from the same row because the column numbers 2 & 5 are not adjacent. The expected results are as follows: 31 33 35 37 39 41 43 These are the starting numbers and the next seat will be automatically booked as well. for e.g. 31 & 32

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  • Having a problem inserting into database

    - by neo skosana
    I have a stored procedure: CREATE PROCEDURE busi_reg(IN instruc VARCHAR(10), IN tble VARCHAR(20), IN busName VARCHAR(50), IN busCateg VARCHAR(100), IN busType VARCHAR(50), IN phne VARCHAR(20), IN addrs VARCHAR(200), IN cty VARCHAR(50), IN prvnce VARCHAR(50), IN pstCde VARCHAR(10), IN nm VARCHAR(20), IN surname VARCHAR(20), IN eml VARCHAR(50), IN pswd VARCHAR(20), IN srce VARCHAR(50), IN refr VARCHAR(50), IN sess VARCHAR(50)) BEGIN INSERT INTO b_register SET business_name = busName, business_category = busCateg, business_type = busType, phone = phne, address = addrs, city = cty, province = prvnce, postal_code = pstCde, firstname = nm, lastname = surname, email = eml, password = pswd, source = srce, ref_no = refr; END; This is my php script: $busName = $_POST['bus_name']; $busCateg = $_POST['bus_cat']; $busType = $_POST['bus_type']; $phne = $_POST['phone']; $addrs = $_POST['address']; $cty = $_POST['city']; $prvnce = $_POST['province']; $pstCde = $_POST['postCode']; $nm = $_POST['name']; $surname = $_POST['lname']; $eml = $_POST['email']; $srce = $_POST['source']; $ref = $_POST['ref_no']; $result2 = $db->query("CALL busi_reg('$instruc', '$tble', '$busName', '$busCateg', '$busType', '$phne', '$addrs', '$cty', '$prvnce', '$pstCde', '$nm', '$surname', '$eml', '$pswd', '$srce', '$refr', '')"); if($result) { echo "Data has been saved"; } else { printf("Error: %s\n",$db->error); } Now the error that I get: Commands out of sync; you can't run this command now

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  • PHP While loop seperating unique categories from multiple 'Joined' tables

    - by Hob
    I'm pretty new to Joins so hope this all makes sense. I'm joining 4 tables and want to create a while loop that spits out results nested under different categories. My Tables categories id | category_name pages id | page_name | category *page_content* id | page_id | image_id images id | thumb_path My current SQL join <?php $all_photos = mysql_query(" SELECT * FROM categories JOIN pages ON pages.category = categories.id JOIN image_pages ON image_pages.page_id = pages.id JOIN images ON images.id = image_pages.image_id ");?> The result I want from a while loop I would like to get something like this.... Category 1 page 1 Image 1, image 2, image 3 page 2 Image 2, image 4 Category 2 page 3 image 1 page 4 image 1, image 2, image 3 I hope that makes sense. Each image can fall under multiple pages and each page can fall under multiple categories. at the moment I have 2 solutions, one which lists each category several times according to the the amount of pages inside them: eg. category 1, page 1, image 1 - category 1, page 1, image 2 etc One that uses a while loop inside another while loop inside another while loop, resulting in 3 sql queries. <?php while($all_page = mysql_fetch_array($all_pages)) { ?> <p><?=$all_page['page_name']?></p> <?php $all_images = mysql_query("SELECT * FROM images JOIN image_pages ON image_pages.page_id = " . $all_page['id'] . " AND image_pages.image_id = images.id"); ?> <div class="admin-images-block clearfix"> <?php while($all_image = mysql_fetch_array($all_images)) { ?> <img src="<?=$all_image['thumb_path']?>" alt="<?=$all_image['title']?>"/> <?php } ?> </div> <?php } } ?

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  • How much does an InnoDB table benefit from having fixed-length rows?

    - by Philip Eve
    I know that dependent on the database storage engine in use, a performance benefit can be found if all of the rows in the table can be guaranteed to be the same length (by avoiding nullable columns and not using any VARCHAR, TEXT or BLOB columns). I'm not clear on how far this applies to InnoDB, with its funny table arrangements. Let's give an example: I have the following table CREATE TABLE `PlayerGameRcd` ( `User` SMALLINT UNSIGNED NOT NULL, `Game` MEDIUMINT UNSIGNED NOT NULL, `GameResult` ENUM('Quit', 'Kicked by Vote', 'Kicked by Admin', 'Kicked by System', 'Finished 5th', 'Finished 4th', 'Finished 3rd', 'Finished 2nd', 'Finished 1st', 'Game Aborted', 'Playing', 'Hide' ) NOT NULL DEFAULT 'Playing', `Inherited` TINYINT NOT NULL, `GameCounts` TINYINT NOT NULL, `Colour` TINYINT UNSIGNED NOT NULL, `Score` SMALLINT UNSIGNED NOT NULL DEFAULT 0, `NumLongTurns` TINYINT UNSIGNED NOT NULL DEFAULT 0, `Notes` MEDIUMTEXT, `CurrentOccupant` TINYINT UNSIGNED NOT NULL DEFAULT 0, PRIMARY KEY (`Game`, `User`), UNIQUE KEY `PGR_multi_uk` (`Game`, `CurrentOccupant`, `Colour`), INDEX `Stats_ind_PGR` (`GameCounts`, `GameResult`, `Score`, `User`), INDEX `GameList_ind_PGR` (`User`, `CurrentOccupant`, `Game`, `Colour`), CONSTRAINT `Constr_PlayerGameRcd_User_fk` FOREIGN KEY `User_fk` (`User`) REFERENCES `User` (`UserID`) ON DELETE CASCADE ON UPDATE CASCADE, CONSTRAINT `Constr_PlayerGameRcd_Game_fk` FOREIGN KEY `Game_fk` (`Game`) REFERENCES `Game` (`GameID`) ON DELETE CASCADE ON UPDATE CASCADE ) ENGINE=INNODB CHARACTER SET utf8 COLLATE utf8_general_ci The only column that is nullable is Notes, which is MEDIUMTEXT. This table presently has 33097 rows (which I appreciate is small as yet). Of these rows, only 61 have values in Notes. How much of an improvement might I see from, say, adding a new table to store the Notes column in and performing LEFT JOINs when necessary?

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  • Echoing users by group name in PHP

    - by BobSapp
    What I want to do is click a name of a group(every group what I create other than poweruser and admin groups) and that will echo all of the users in that group from the database. I have figured out the code so far but now my problem is how will I print it all out when clicking the name of the group? My code so far is: <h3>Groups</h3> <?php include('db.php'); if (isset($_GET["groupID"])) { $sql="SELECT `group`.*, `user`.* FROM `user` inner join `group` on group.groupID=user.groupID where group.groupID= " . mysql_real_escape_string($_GET["groupID"]) ; } else { $sql="SELECT * FROM `group` WHERE groupName <> 'admin' AND groupName <> 'poweruser'" ; } $result=mysql_query($sql,$connection); while($line=mysql_fetch_array($result)){ echo "<a href='index.php?page=groups&group=".$line['groupID']."'>".$line['groupName'].'</a><br />'; } mysql_free_result($result); mysql_close($connection); ?>

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  • Multiple/nested "select where" with Zend_Db_Select

    - by DJRayon
    Hi there I need to create something like this: select name from table where active = 1 AND (name LIKE 'bla' OR description LIKE 'bla') The first part is easy: $sqlcmd = $db->select() ->from("table", "name") ->where("active = ?", 1) Now comes the tricky part. How can I nest? I know that I can just write ->orWhere("name LIKE ? OR description LIKE ?", "bla") But thats wron, because I need to dynamically change all the parts. The query will be built all the time the script runs. Some parts get deleted, some altered. In this example I need to add those OR-s because sometimes I need to search wider. "My Zend Logic" tells me that the correct way is like this: $sqlcmd = $db->select() ->from("table", "name") ->where("active = ?", 1) ->where(array( $db->select->where("name LIKE ?", "bla"), $db->select->orWhere("description LIKE ?", "bla") )) But that doesn't work (atleast I dont remember it working). Please. Can someone help me to find a object oriented way for nesting "where"-s

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  • How to convert a list object to bigdecimal in prepared statement?

    - by user1103504
    I am using prepared statement for bulk insertion of records. Iam iterating a list which contains values and their dataTypes differ. One of the data type is BigDecimal and when i try to set calling preparedstatement, it is throwing null pointer exception. My code int count = 1; for (int j = 0; j < list.size(); j++) { if(list.get(j) instanceof Timestamp) { ps.setTimestamp(count, (Timestamp) list.get(j)); } else if(list.get(j) instanceof java.lang.Character) { ps.setString(count, String.valueOf(list.get(j))); } else if(list.get(j) instanceof java.math.BigDecimal) { ps.setBigDecimal(count, (java.math.BigDecimal)list.get(j)); } else { ps.setObject(count, list.get(j)); } count++; } I tried 2 ways to convert, casting the object and tried to create a new object of type BigDecimal ps.setBigDecimal(count, new BigDecimal(list.get(j).toString)); both donot solve my problem. It is throwing null pointer exception. help is appreciated. Thanks

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  • INSERT..ON DUPLICATE KEY UPDATE - but NOT using the duplicate key to compare.

    - by calumbrodie
    I am trying to solve a problem I have inherited with poor treatment of different data sources. I have a user table that contains BOTH good and evil users. create table `users`( `user_id` int(13) NOT NULL AUTO_INCREMENT , `email` varchar(255) , `name` varchar(255) , PRIMARY KEY (`user_id`) ); In this table the primary key is currently set to be user_id. I have another table ('users_evil') which contains ONLY the evil users (all the users from this table are included in the first table) - the user_id's on this table do NOT correspond to those in the first table. I want to have all my users in one table, and simply flag which are good and which are evil. What I want to do is alter the user table and add a column ('evil') which defaults to 0. I then want to dump the data from my 'users_evil') table and then run an INSERT..ON DUPLICATE KEY UPDATE with this data into the first table (setting 'evil'=1 where the emails match) The problem is that the 'PK' is set to the user_id and not the 'email'. Any suggestions, or even another strategy to successfully achive this. Can I run this statement but treat another column as PK only for the duration of the statement.

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  • Application logic for invoicing and subscriptions?

    - by Industrial
    Hi everyone, We're just in the planning stage of a web app that offers subscriptions to our customers. The subscription periods varies and can be prolonged indefinitely by our customers, but are always at least one month (30 days). When a customer signs up, the customer information (billing address, phone number and so on) are stored in a customers table and a subscription is created in the subscriptions table: id | start_date | end_date | customer_id -------------------------------------------------------- 1 | 2010-12-31 | 2011-01-31 | 1 Every month we'll loop through the subscriptions table (cronjob preferably) and create invoices for the past subscription period, which are housed in their own table - invoices. Depending on the customer, invoices are manually printed out and sent by mail, or just emailed to the customer. Due to the nature of our customers and the product, we need to offer a variety of different payment alternatives including wire transfer and card payments, hence some invoices may need to be manually handled and registered as paid by our staff. The 15th every month, the invoices table are looped through and if no payment has been marked for the actual invoice, the according subscription will be removed. If there's a payment registered, the end_date in the subscriptions table is incremented by another 30 days (or what now our period our customer has chosen). Are we looking at headaches by incrementing dates forwards and backwards to handle non-paying customers and extending subscriptions? Would it be a better idea to add new subscriptions as customers extends their subscription?

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  • Symfony2 same form, different entities NOT related

    - by user1381537
    I'm trying to write one form for submitting against MySQL DB, but I can't get it working, I've tried a lot of things (separate forms, create an ->add('foo', new foo()) to a field, and trying to parse plain SQL with a normal HTML form is my only solution, which is obviously not the best. This is my DB structure: As you can see I need to insert the comments textarea to ticketcomments among the user who wrote it, etc. On crmentity the description field. Then on ticketcf the fields that I need to submit from form, are this (because you wont know if I don't tell you because of the field names): tcf.cf594 AS Type, tcf.cf675 AS Suscription, tcf.cf770 AS ID_PRODUCT, tcf.cf746 AS NotificationDate, tcf.cf747 AS ResponseDate, tcf.cf748 AS ResolutionDate, And, of course, every table needs to have the same ticketid id for the submitted form, so we can retrieve it with one simple query. It will be easy to do with plain SQL instead of using DQL and Symfony2 forms, but is not a good way to do it. Also, here's my "Ticket list" query, if you need it to have it more clear... SELECT t.ticketNo AS Ticket, t.title AS Asunto, t.status AS Estado, t.updateLog AS LOG, t.hours AS Horas, t.solution AS Solucion, t.priority AS Prioridad, tcf.cf594 AS Tipo, tcf.cf675 AS Suscripcion, tcf.cf770 AS IDPROD, tcf.cf746 AS F_Noti, tcf.cf747 AS F_Resp, tcf.cf748 AS F_Reso, CONCAT (cd.firstname, cd.lastname) AS Contacto, crm.description AS Descripcion, crm.crmid AS id FROM WbsGoclientsBundle:VtigerTroubletickets t INNER JOIN WbsGoclientsBundle:VtigerTicketcf tcf WITH t.ticketid = tcf.ticketid INNER JOIN WbsGoclientsBundle:VtigerContactdetails cd WITH t.parentId = cd.contactid INNER JOIN WbsGoclientsBundle:VtigerCrmentity crm WITH t.ticketid = crm.crmid WHERE t.parentId IN ( SELECT cd1.contactid FROM WbsGoclientsBundle:VtigerContactdetails cd1 WHERE cd1.accountid = ( SELECT cd2.accountid FROM WbsGoclientsBundle:VtigerContactdetails cd2 WHERE cd2.contactid = :contactid)) AND t.status <> \'Closed\' And also "Ticket details" query (which is not in DQL format yet, only SQL) is so simple, it only retrieve the comments field and createdtime from ticketcomments appended to this query so we have all the fields... Thank you. This is a test form, using troubletickets and ticketcomments, it's returning errores because I can't set a comments field because troubletickets doesn't has it, but I need that field to be submitted to ticketcomments ... VtigerTicketcommentsType <?php namespace WbsGo\clientsBundle\Form\Type; use Symfony\Component\Form\AbstractType, Symfony\Component\Form\FormBuilderInterface; use Symfony\Component\OptionsResolver\OptionsResolverInterface; class VtigerTicketcommentsType extends AbstractType { public function buildForm(FormBuilderInterface $builder, array $options) { $builder ->add('ticketid') ->add('comments') ->add('ownerid') ->add('ownertype') ->add('createdtype') ; } public function setDefaultOptions(OptionsResolverInterface $resolver) { $resolver->setDefaults(array( 'data_class' => 'WbsGo\clientsBundle\Entity\VtigerTicketcomments' )); } public function getName() { return 'comments'; } } OpenTicketType.php <?php namespace WbsGo\clientsBundle\Form; use Symfony\Component\Form\AbstractType, Symfony\Component\Form\FormBuilderInterface ; use WbsGo\clientsBundle\Form\Type\VtigerTicketcommentsType; use Symfony\Component\OptionsResolver\OptionsResolverInterface; class OpenTicketType extends AbstractType { public function buildForm(FormBuilderInterface $builder, array $options) { $builder ->add('title') ->add('priority') ->add('solution') ->add('comments', 'collection', array( 'type' => new VtigerTicketcommentsType() )) ; } public function setDefaultOptions(OptionsResolverInterface $resolver) { $resolver->setDefaults(array( 'data_class' => 'WbsGo\clientsBundle\Entity\VtigerTroubletickets' )); } public function getName() { return 'ticket'; } } TicketController.php <?php namespace WbsGo\clientsBundle\Controller; use Symfony\Bundle\FrameworkBundle\Controller\Controller; use WbsGo\clientsBundle\Entity\VtigerTroubletickets; use WbsGo\clientsBundle\Entity\VtigerTicketcomments; use WbsGo\clientsBundle\Form\OpenTicketType; use Symfony\Component\HttpFoundation\Request; class TicketController extends Controller { public function indexAction() { $em = $this->getDoctrine()->getManager(); $tickets = $em ->getRepository('WbsGoclientsBundle:VtigerTroubletickets') ->findAllOpenByCustomerId($this->getUser()->getId()); $userdata = $this->getDoctrine()->getManager() ->getRepository('WbsGoclientsBundle:VtigerContactdetails') ->findContact($this->getUser()->getId()); return $this ->render('WbsGoclientsBundle:Ticket:index.html.twig', array('tickets' => $tickets, 'userdata' => $userdata)); } public function addAction() { $assets = $this->getDoctrine()->getManager() ->getRepository('WbsGoclientsBundle:VtigerAssets') ->findAssetByAccountId($this->getUser()->getId()); $assetlist = array(); foreach ($assets as $key => $v) { $assetlist[$key] = $key; } $form = $this->createForm(new OpenTicketType(), new VtigerTroubletickets()); return $this ->render('WbsGoclientsBundle:Ticket:add.html.twig', array('form' => $form->createView(), 'assets' => $assets,)); } } This is the error Symfony2 is returning Neither the property "comments" nor one of the methods "getComments()", "isComments()", "hasComments()", "_get()" or "_call()" exist and have public access in class "WbsGo\clientsBundle\Entity\VtigerTroubletickets". EDIT 2 This code is actually rendering my forms, but I need help in order to submit each XXXType form to its corresponding table. public function buildForm(FormBuilderInterface $builder, array $options) { $builder ->add('descripcion') ->add('prioridad') ->add('solucion') ->add('comment', new VtigerTicketcommentsType() ) ->add('contacto') ->add('suscripcion') ->add('producto', 'entity', array( 'class' => 'WbsGo\clientsBundle\Entity\VtigerAssets', 'property' => 'assetname', 'empty_value' => '--SELECT--', 'query_builder' => function(\WbsGo\clientsBundle\Entity\VtigerAssetsRepository $repository) { //return $repository->findAssetByAccountId($this->customerId); return $repository->createQueryBuilder('a') ->select('a') ->where('a.account = (SELECT cd.accountid FROM WbsGoclientsBundle:VtigerContactdetails cd WHERE cd.contactid = ?1)') ->setParameter(1, $this->customerId); } ) ) ->add('hardware') ->add('backup') ->add('web') ->add('restore') ->add('customerId') ; } I also removed ->add('ticketid') from VtigerTicketcommentsType.php because it has relationship and is not needed. it's auto_incremental and must be generated once everything is submitted.

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  • Best way to run multiple queries per second on database, performance wise?

    - by Michael Joell
    I am currently using Java to insert and update data multiple times per second. Never having used databases with Java, I am not sure what is required, and how to get the best performance. I currently have a method for each type of query I need to do (for example, update a row in a database). I also have a method to create the database connection. Below is my simplified code. public static void addOneForUserInChannel(String channel, String username) throws SQLException { Connection dbConnection = null; PreparedStatement ps = null; String updateSQL = "UPDATE " + channel + "_count SET messages = messages + 1 WHERE username = ?"; try { dbConnection = getDBConnection(); ps = dbConnection.prepareStatement(updateSQL); ps.setString(1, username); ps.executeUpdate(); } catch(SQLException e) { System.out.println(e.getMessage()); } finally { if(ps != null) { ps.close(); } if(dbConnection != null) { dbConnection.close(); } } } And my DB connection private static Connection getDBConnection() { Connection dbConnection = null; try { Class.forName(DB_DRIVER); } catch (ClassNotFoundException e) { System.out.println(e.getMessage()); } try { dbConnection = DriverManager.getConnection(DB_CONNECTION, DB_USER,DB_PASSWORD); return dbConnection; } catch (SQLException e) { System.out.println(e.getMessage()); } return dbConnection; } This seems to be working fine for now, with about 1-2 queries per second, but I am worried that once I expand and it is running many more, I might have some issues. My questions: Is there a way to have a persistent database connection throughout the entire run time of the process? If so, should I do this? Are there any other optimizations that I should do to help with performance? Thanks

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  • Storing "binary" data type in C program

    - by puchu
    I need to create a program that converts one number system to other number systems. I used itoa in Windows (Dev C++) and my only problem is that I do not know how to convert binary numbers to other number systems. All the other number systems conversion work accordingly. Does this involve something like storing the input to be converted using %? Here is a snippet of my work: case 2: { printf("\nEnter a binary number: "); scanf("%d", &num); itoa(num,buffer,8); printf("\nOctal %s",buffer); itoa(num,buffer,10); printf("\nDecimal %s",buffer); itoa(num,buffer,16); printf("\nHexadecimal %s \n",buffer); break; } For decimal I used %d, for octal I used %o and for hexadecimal I used %x. What could be the correct one for binary? Thanks for future answers!

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  • Beginner having difficulty with SQL query

    - by Vulcanizer
    Hi, I've been studying SQL for 2 weeks now and I'm preparing for an SQL test. Anyway I'm trying to do this question: For the table: 1 create table data { 2 id int, 3 n1 int not null, 4 n2 int not null, 5 n3 int not null, 6 n4 int not null, 7 primary key (id) 8 } I need to return the relation with tuples (n1, n2, n3) where all the corresponding values for n4 are 0. The problem asks me to solve it WITHOUT using subqueries(nested selects/views) It also gives me an example table and the expected output from my query: 01 insert into data (id, n1, n2, n3, n4) 02 values (1, 2,4,7,0), 03 (2, 2,4,7,0), 04 (3, 3,6,9,8), 05 (4, 1,1,2,1), 06 (5, 1,1,2,0), 07 (6, 1,1,2,0), 08 (7, 5,3,8,0), 09 (8, 5,3,8,0), 10 (9, 5,3,8,0); expects (2,4,7) (5,3,8) and not (1,1,2) since that has a 1 in n4 in one of the cases. The best I could come up with was: 1 SELECT DISTINCT n1, n2, n3 2 FROM data a, data b 3 WHERE a.ID <> b.ID 4 AND a.n1 = b.n1 5 AND a.n2 = b.n2 6 AND a.n3 = b.n3 7 AND a.n4 = b.n4 8 AND a.n4 = 0 but I found out that also prints (1,1,2) since in the example (1,1,2,0) happens twice from IDs 5 and 6. Any suggestions would be really appreciated.

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  • Zip multiple database PDF blob files

    - by Michael
    I have a database table that contains numerous PDF blob files. I am attempting to combine all of the files into a single ZIP file that I can download and then print. Please help! <?php include '../config.php'; include '../connect.php'; $session = $_GET['session']; $query = "SELECT $tbl_uploads.username, $tbl_uploads.description, $tbl_uploads.type, $tbl_uploads.size, $tbl_uploads.content, $tbl_members.session FROM $tbl_uploads LEFT JOIN $tbl_members ON $tbl_uploads.username = $tbl_members.username WHERE $tbl_members.session = '$session'"; $result = mysql_query($query) or die('Error, query failed'); $files = array(); while(list($username, $description, $type, $size, $content) = mysql_fetch_array($result)) { $files[] = "$username-$description.pdf"; } $zip = new ZipArchive; $zip->open('file.zip', ZipArchive::CREATE); foreach ($files as $file) { $zip->addFile($file); } $zip->close(); header('Content-Type: application/zip'); header('Content-disposition: attachment; filename=filename.zip'); header('Content-Length: ' . filesize($zipfilename)); readfile($zipname); exit(); ?>

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  • How to find intersect rows when condition depend on some columns in one table

    - by user3695637
    Table subscribe subscriber | subscribeto (columns) 1 | 5 1 | 6 1 | 7 1 | 8 1 | 9 1 | 10 2 | 5 2 | 6 2 | 7 There are two users that have id 1 and 2. They subscribe to various user and I inserted these data to table subscribe. Column subscriber indicates who is subscriber and column subscribeto indicates who they've subscribe to. From the above table can conclude that; user id=1 subscribed to 6 users user id=2 subscribed to 3 users I want to find manual of subscription (like Facebook is manual friends) user 1 subscribe to user 5,6,7,8,9,10 user 2 subscribe to user 5,6,7 So, Manual subscription of user 1 and 2 are: 5,6,7 And I'm trying to create SQL statement.. I give you user table for my SQL statement and I think we can use only subscribe table but I can't figure out. Table user userid (columns) 1 2 3 ... ... SQL "select * from user where (select count( 1 ) from subscribe where subscriber = '1' and subscribeto = user.userid) and (select count( 1 ) from subscribe where subscriber = '2' and subscribeto = user.userid);" This SQL can work correctly, but it very slow for thousands of columns. Please provide better SQL for me, Thanks.

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  • update entire table with pdo

    - by MephDaddy
    I am working on a simple gaming ladder script. I am having little to no luck trying to find an effective way to reset my ladder information while leaving my table id and name fields intact. I am trying to get create a loop to update my entire table, similar to the way I draw my table. Shown below. ...... //Start displaying ladder with with team with most wins at the top echo "<TABLE border=1 width=500 align=center><TR>"; foreach($db->query('SELECT * FROM test ORDER BY win DESC , name ASC') as $row) { echo "<TR><TD>" . $row['name'] . "</TD><TD>" . $row['win'] . "</TD><TD>"; echo $row['loss'] . "</TD><TD>" . $row['battles'] . "</TD><TD>"; echo $row['score'] . "</TD></TR>"; } ...... I currently have a table with 6 fields(id,name,win,loss,battles,score). I want to reset the values of win,loss,battles, and score back to 0. While leaving id and name alone. Effective reseting my ladder for a new season to begin. The only way I have been able to complete this is to find out how many rows there are and run a for loop. It seems vary inefficient. Was hoping I could get some better insight as to how to go about this.

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  • Problems while trying to make a query with variables in the conditions (stored procedure)

    - by pablo89
    Hi!! Im having a problem, Im trying to do a query... I remember that in the past I did something like this but today this query is returning nothing, no error, no data, just nothing... the query is something like this: SELECT field1, @variableX:=field2 FROM table WHERE (SELECT COUNT(fieldA) FROM table2 WHERE fieldB=@variableX AND fieldC=0)0 AND (SELECT COUNT(fieldA) FROM table2 WHERE fieldB=@variableX AND fieldC=4)=0; I also tried this query but it didnt work (also it gaves no error): SELECT field1, @variableX:=field2, @variableY:=(SELECT COUNT(fieldA) FROM table2 WHERE fieldB=@variableX AND fieldC=0), @variableZ:=(SELECT COUNT(fieldA) FROM table2 WHERE fieldB=@variableX AND fieldC=4) FROM table WHERE @variableY0 AND @variableZ=0; As you can see, what Im trying to do in the 1st query is use a variable in the conditions; in the 2nd query Im trying to create some variables and evaluate them in the conditions. At the end in the 2nd query the @variableY=1 AND @variableZ=0 but I dont know what the query returns an empty data What could be wrong here??? Any comment or suggest is welcome!!! thanks!!! Bye!!!

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  • Auto-creating a "link" table between 2 main tables (ex table EmployeeProject from Employee and Project tables)

    - by user573382
    Hello! I have these 2 tables, Medication containing: IDMedication, IDCategory, Name, and Supplier, containing: IDSupplier, Name. I want to automatically create a relationship table, MedicationSupplier, containing: IDMedication and IDSupplier as keys, Price, and Quantity. My idea was to have a main page where i request the following data: (Medication)Name, IDCAtegory, (Supplier)Name, Price, Quantity. I'm not sure if i'm doing the right thing here. So this is what i'm receiveing in the .php where i do the insert: $Denumire=$_POST['Denumire']; //Medication Name $IDCategorie=$_POST['IDCategorie']; //IDCategory $Nume=$_POST['Nume']; //Supplier Name $Pret=$_POST['Pret']; //Price $Stoc=$_POST['Stoc']; //Quantity And this is my insert: $q_produse = "INSERT INTO produse VALUES ('','$IDCategorie','$Denumire')"; $q_prodfurniz = "INSERT INTO produsfurnizor VALUES ('','$IDFurnizor','$Pret','$Stoc')"; mysql_query($q_produse) or die($error); mysql_query($q_prodfurniz) or die($error); mysql_close(); My main problem at the moment is that i don't know how to insert IDMedication in the relationship table. Any help / suggestions of improving my code would be greatly appreciated. Thanks!

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  • How do I Delete a View? How do I Create a View?

    - by Paula DiTallo
    Before I create views, I generally work out what I want to retrieve in my SELECT statement ahead of time so I'll just  have to cut and  paste the query. The example below is done  in T-SQL/Sybase format, however for Oracle and MySQL, just  place a semi-colon ';' at the end of your statement and remove the  'GO' command.          To drop (delete) an existing view: DROP VIEW vw_rpt_metroBestCustomers GO To create a view: CREATE VIEW vw_rpt_metroBestCustomers ( CustomerName,    OfficeNum,    City,    StateOrProv,    Country,    ZipCode   ) AS SELECT a.FirstName + ', ' + a.LastName,           b.OfficePhoneNum,           c.City,           c.StateOrProvAbbr,           c.Country,           c.PostalCode     FROM Customer a,          CustLocAssoc x,          CustContactAssoc y,          Location c,          Contact b     WHERE a.CustID = x.CustID       AND a.CustID = y.CustID       AND y.ContactID = b.ContactID       AND x.LocID = c.LocID       AND a.LoyaltyMedian > 85.5 GO        I frequently rename columns when developing views to makeit easier for simple, text-based reporting--however, renamingthe columns isn't necessary.The create view statement above could have been writtenas follows:CREATE VIEW vw_rpt_metroBestCustomersAS (SELECT a.FirstName + ', ' + a.LastName, b.OfficePhoneNum, c.City, c.StateOrProvAbbr, c.Country, c.PostalCode FROM Customer a, CustLocAssoc x, CustContactAssoc y, Location c, Contact b WHERE a.CustID = x.CustID AND a.CustID = y.CustID AND y.ContactID = b.ContactID AND x.LocID = c.LocID AND a.LoyaltyMedian > 85.5 )GO

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  • How can I create an SPF record on my 1and1.com hosted domain?

    - by tnorthcutt
    Emails from my domain (hosted at 1and1, and using Google Apps Premier edition) have sporadically been going to recipients' spam folders lately. I did some research, tested, and found out that I do not have an SPF record for my domain. According to this Google Support page, I need to create one. Following the steps on that page is easy, until I get to #3: Create a TXT record containing this text: v=spf1 include:_spf.google.com ~all I see no way to create a "TXT record". Here is a screenshot of the admin panel:

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  • How do I create a game that runs on Windows, iOS and Android?

    - by AspaApps
    I use C++ to create windows games and now I want to step into another other OS like Android or iOS. I'm totally familiar with C++ so I tried to create app for iOS using objective C it was working awesome. However, I also want to publish games for Android but not by using Java. I don't want to create a single game 5-6 times for other platforms. Is their any way that if I create game for Windows then it will work in Android and iOS ? Or should I use Action Script 3.0? If I use action script 3.0, will it require Flash player to run the game in Windows, Android, iOS?

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  • migrating simple rails database to mysql

    - by joseph-misiti
    i am interested in creating a rails app with a mysql database. i am new to rails and am just trying to start creating something simple: rails -d mysql MyMoviesSQL cd MyMoviesSQL script/generate scaffold Movies title:string rating:integer rake db:migrate i am seeing the following error: rake aborted! NoMethodError: undefined method `ord' for 0:Fixnum: SET NAMES 'utf8' if i do a trace: ** Invoke db:migrate (first_time) ** Invoke environment (first_time) ** Execute environment ** Execute db:migrate rake aborted! NoMethodError: undefined method ord' for 0:Fixnum: SET NAMES 'utf8' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract_adapter.rb:219:inlog' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/mysql_adapter.rb:323:in execute' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/mysql_adapter.rb:599:inconfigure_connection' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/mysql_adapter.rb:594:in connect' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/mysql_adapter.rb:203:ininitialize' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/mysql_adapter.rb:75:in new' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/mysql_adapter.rb:75:inmysql_connection' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract/connection_pool.rb:223:in send' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract/connection_pool.rb:223:innew_connection' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract/connection_pool.rb:245:in checkout_new_connection' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract/connection_pool.rb:188:incheckout' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract/connection_pool.rb:184:in loop' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract/connection_pool.rb:184:incheckout' /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/monitor.rb:242:in synchronize' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract/connection_pool.rb:183:incheckout' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract/connection_pool.rb:98:in connection' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract/connection_pool.rb:326:inretrieve_connection' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract/connection_specification.rb:123:in retrieve_connection' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/connection_adapters/abstract/connection_specification.rb:115:inconnection' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/migration.rb:435:in initialize' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/migration.rb:400:innew' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/migration.rb:400:in up' /Library/Ruby/Gems/1.8/gems/activerecord-2.3.5/lib/active_record/migration.rb:383:inmigrate' /Library/Ruby/Gems/1.8/gems/rails-2.3.5/lib/tasks/databases.rake:116 /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:636:in call' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:636:inexecute' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:631:in each' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:631:inexecute' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:597:in invoke_with_call_chain' /System/Library/Frameworks/Ruby.framework/Versions/1.8/usr/lib/ruby/1.8/monitor.rb:242:insynchronize' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:590:in invoke_with_call_chain' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:583:ininvoke' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2051:in invoke_task' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2029:intop_level' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2029:in each' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2029:intop_level' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2068:in standard_exception_handling' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2023:intop_level' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2001:in run' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:2068:instandard_exception_handling' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/lib/rake.rb:1998:in run' /Library/Ruby/Gems/1.8/gems/rake-0.8.7/bin/rake:31 /usr/bin/rake:19:inload' /usr/bin/rake:19 here are my versions: rails - 2.3.5 ruby - 1.8.6 gem list * LOCAL GEMS * actionmailer (2.3.5, 1.3.6) actionpack (2.3.5, 1.13.6) actionwebservice (1.2.6) activerecord (2.3.5, 1.15.6) activeresource (2.3.5) activesupport (2.3.5, 1.4.4) acts_as_ferret (0.4.1) capistrano (2.0.0) cgi_multipart_eof_fix (2.5.0) daemons (1.0.9) dbi (0.4.3) deprecated (2.0.1) dnssd (0.6.0) fastthread (1.0.1) fcgi (0.8.7) ferret (0.11.4) gem_plugin (0.2.3) highline (1.2.9) hpricot (0.6) libxml-ruby (0.9.5, 0.3.8.4) mongrel (1.1.4) needle (1.3.0) net-sftp (1.1.0) net-ssh (1.1.2) rack (1.0.1) rails (2.3.5) rake (0.8.7, 0.7.3) RedCloth (3.0.4) ruby-openid (1.1.4) ruby-yadis (0.3.4) rubygems-update (1.3.6) rubynode (0.1.3) sqlite3-ruby (1.2.1) termios (0.9.4) also, if i need to add a patch to FixNum, can someone please tell which file to add the patch to. thanks for your help

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