Search Results

Search found 17149 results on 686 pages for 'python twitter'.

Page 395/686 | < Previous Page | 391 392 393 394 395 396 397 398 399 400 401 402  | Next Page >

• Cleaner way to get user name in pylons with repoze.name

  - by Timmy

  in mako template, i use this ${request.environ['repoze.who.identity']['user']} and the render in controller: render('file.html') can i write this better without passing in parameter everytime?

  Read the article

• SQLAlchemy returns tuple not dictionary

  - by Ivan

  Hi everyone, I've updated SQLAlchemy to 0.6 but it broke everything. I've noticed it returns tuple not a dictionary anymore. Here's a sample query: query = session.query(User.id, User.username, User.email).filter(and_(User.id == id, User.username == username)).limit(1) result = session.execute(query).fetchone() This piece of code used to return a dictionary in 0.5. My question is how can I return a dictionary?

  Read the article

• Django: How do I access the request object or any other variable in a form's clean() method?

  - by nubela

  I am trying to request.user for a form's clean method, but how can I access the request object? Can I modify the clean method to allow variables input? Thanks.

  Read the article

• Splitting a person's name into forename and surname

  - by Nick

  ok so basically I am asking the question of their name I want this to be one input rather than Forename and Surname. Now is there any way of splitting this name? and taking just the last word from the "Sentence" e.g. name = "Thomas Winter" print name.split() and what would be output is just "Winter"

  Read the article

• Should I use fork or threads?

  - by shadyabhi

  In my script, I have a function foo which basically uses pynotify to notify user about something repeatedly after a time interval say 15 minutes. def foo: while True: """Does something""" time.sleep(900) My main script has to interact with user & does all other things so I just cant call the foo() function. directly. Whats the better way of doing it and why? Using fork or threads?

  Read the article

• How do I limit the amount of login retries in Django

  - by RED MONKEY

  I am trying to get a login form I have in django to only allow three login attempts before redirecting to a "login help" page. I am currently using the builtin "django.contrib.auth.views.login" view with a custom template. How do I force it to redirect to another page after n failed login attempts?

  Read the article

• Django and json request

  - by Hulk

  In a template i have the following code <script> var url="/mypjt/my_timer" $.post(url, paramarr, function callbackHandler(dict) { alert('got response back'); if (dict.flag == 2) { alert('1'); $.jGrowl("Data could not be saved"); } else if(dict.ret_status == 1) { alert('2'); $.jGrowl("Data saved successfully"); window.location = "/mypjt/display/" + dict.rid; } }, "json" ); </script> In views i have the following code, def my_timer(request): dict={} try: a= timer.objects.get(pk=1) dict({'flag':1}) return HttpResponse(simplejson.dumps(dict), mimetype='application/javascript') except: dict({'flag':1}) return HttpResponse(simplejson.dumps(dict), mimetype='application/javascript') My question is since we are making a json request and in the try block ,after setting the flag ,cant we return a page directly as return render_to_response('mypjt/display.html',context_instance=RequestContext(request,{'dict': dict})) instead of sending the response, because on success again in the html page we redirect the code Also if there is a exception then only can we return the json request. My only concern is that the interaction between client and server should be minimal. Thanks..

  Read the article

• Django: Determining if a user has voted or not

  - by TheLizardKing

  I have a long list of links that I spit out using the below code, total votes, submitted by, the usual stuff but I am not 100% on how to determine if the currently logged in user has voted on a link or not. I know how to do this from within my view but do I need to alter my below view code or can I make use of the way templates work to determine it? I have read http://stackoverflow.com/questions/1528583/django-vote-up-down-method but I don't quite understand what's going on ( and don't need any ofjavascriptery). Models (snippet): class Link(models.Model): category = models.ForeignKey(Category, blank=False, default=1) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) modified = models.DateTimeField(auto_now=True) url = models.URLField(max_length=1024, unique=True, verify_exists=True) name = models.CharField(max_length=512) def __unicode__(self): return u'%s (%s)' % (self.name, self.url) class Vote(models.Model): link = models.ForeignKey(Link) user = models.ForeignKey(User) created = models.DateTimeField(auto_now_add=True) def __unicode__(self): return u'%s vote for %s' % (self.user, self.link) Views (snippet): links = Link.objects.select_related().annotate(votes=Count('vote')).order_by('-created')

  Read the article

• How to change db in django depending on request.get_host()?

  - by Alexandr

  I am creating multisites platform. Anybody can make simple site, with my platform. I plan to use django multidb support. One db for one site. And i need to change db settings depending on request.get_host(). I think that i's not good idea. Prompt other decisions? How it is realised on various designers of sites?

  Read the article

• Find number of differences in 2 strings

  - by Pirate for Profit

  int n = string.numDifferences("noob", "newb"); // 2 ??

  Read the article

• Django/jQuery - read file and pass to browser as file download prompt

  - by danspants

  I've previously asked a question regarding passing files to the browser so a user receives a download prompt. However these files were really just strings creatd at the end of a function and it was simple to pass them to an iframe's src attribute for the desired effect. Now I have a more ambitious requirement, I need to pass pre existing files of any format to the browser. I have attempted this using the following code: def return_file(request): try: bob=open(urllib.unquote(request.POST["file"]),"rb") response=HttpResponse(content=bob,mimetype="application/x-unknown") response["Content-Disposition"] = "attachment; filename=nothing.xls" return HttpResponse(response) except: return HttpResponse(sys.exc_info()) With my original setup the following jQuery was sufficient to give the desired download prompt: jQuery('#download').attr("src","/return_file/"); However this won't work anymore as I need to pass POST values to the function. my attempt to rectify that is below, but instead of a download prompt I get the file displayed as text. jQuery.get("/return_file/",{"file":"c:/filename.xls"},function(data) { jQuery(thisButton).children("iframe").attr("src",data); }); Any ideas as to where I'm going wrong? Thanks!

  Read the article

• how code a Image button in PyQt?

  - by Alquimista

  Im trying to do simple audio player, but y want use a image(icon) as a pushbutton.

  Read the article

• Overriding Django Admin's main page? - Django

  - by RadiantHex

  Hi folks, I'm trying to add features to Django admin's main page. I've been playing with index.html, but features added to this page affect all app pages. Any ideas on what template I'm supposed to use? Thanks loads!!

  Read the article

• How to replace empty string with zero in comma-separated string?

  - by dsaccount1

  "8,5,,1,4,7,,,,7,,1,9,3,6,,,8,6,3,9,,2,5,4,,,,,3,2,,,7,4,1,1,,4,,6,9,,5,,,,5,,,1,,6,3,,,6,5,,,,7,4,,1,7,6,,,,8,,5,,,7,1,,3,9," I'm doing a programming challenge where i need to parse this sequence into my sudoku script. Need to get the above sequence into 8,5,0,1,4,7,0,0,0,7,0,1,9,3,6,0,0,8......... I tried re but without success, help is appreciated, thanks.

  Read the article

• Refactoring code/consolidating functions (e.g. nested for-loop order)

  - by bmay2

  Just a little background: I'm making a program where a user inputs a skeleton text, two numbers (lower and upper limit), and a list of words. The outputs are a series of modifications on the skeleton text. Sample inputs: text = "Player # likes @." (replace # with inputted integers and @ with words in list) lower = 1 upper = 3 list = "apples, bananas, oranges" The user can choose to iterate over numbers first: Player 1 likes apples. Player 2 likes apples. Player 3 likes apples. Or words first: Player 1 likes apples. Player 1 likes bananas. Player 1 likes oranges. I chose to split these two methods of outputs by creating a different type of dictionary based on either number keys (integers inputted by the user) or word keys (from words in the inputted list) and then later iterating over the values in the dictionary. Here are the two types of dictionary creation: def numkey(dict): # {1: ['Player 1 likes apples', 'Player 1 likes...' ] } text, lower, upper, list = input_sort(dict) d = {} for num in range(lower,upper+1): l = [] for i in list: l.append(text.replace('#', str(num)).replace('@', i)) d[num] = l return d def wordkey(dict): # {'apples': ['Player 1 likes apples', 'Player 2 likes apples'..] } text, lower, upper, list = input_sort(dict) d = {} for i in list: l = [] for num in range(lower,upper+1): l.append(text.replace('#', str(num)).replace('@', i)) d[i] = l return d It's fine that I have two separate functions for creating different types of dictionaries but I see a lot of repetition between the two. Is there any way I could make one dictionary function and pass in different values to it that would change the order of the nested for loops to create the specific {key : value} pairs I'm looking for? I'm not sure how this would be done. Is there anything related to functional programming or other paradigms that might help with this? The question is a little abstract and more stylistic/design-oriented than anything.

  Read the article

• Formwizards for editing in Django

  - by Espen Christensen

  Hi, I am in the process of making a webapp, and this webapp needs to have a form wizard. The wizard consists of 3 ModelForms, and it works flawlessly. But I need the second form to be a "edit form". That is, i need it to be a form that is passed an instance. How can you do this with a form wizard? How do you pass in an instance of a model? I see that the FormWizard class has a get_form method, but isnt there a documented way to use the formwizard for editing/reviewing of data?

  Read the article

• a simple smtp server

  - by fixxxer

  Could you please suggest a simple SMTP server with the very basic APIs(by very basic I mean, to read,write,delete email) that could be run on a linux box? I just need to convert the crux of the email into XML format and FTP it to another machine.

  Read the article

• Trac default language

  - by niez

  Hi, How can I set default language for trac. There's nothing about i18n in trac.ini

  Read the article

• fft and array-to-image / image-to-array-conversion

  - by kame

  Hello! I want to make a fourier-transformation of an image. But how can I change the picture to an array? And after this I think I should use numpy.fft.rfft2 for the transformation. And how to change back from the array to the image? Thanks in advance.

  Read the article

• Finding matching submatrics inside a matrix

  - by DaveO

  I have a 100x200 2D array expressed as a numpy array consisting of black (0) and white (255) cells. It is a bitmap file. I then have 2D shapes (it's easiest to think of them as letters) that are also 2D black and white cells. I know I can naively iterate through the matrix but this is going to be a 'hot' portion of my code so speed is an concern. Is there a fast way to perform this in numpy/scipy? I looked briefly at Scipy's correlate function. I am not interested in 'fuzzy matches', only exact matches. I also looked at some academic papers but they are above my head.

  Read the article

• Trouble with encoding and urllib

  - by Ockonal

  Hello, I'm loading web-page using urllib. Ther eis russian symbols, but page encoding is 'utf-8' 1 pageData = unicode(requestHandler.read()).decode('utf-8') UnicodeDecodeError: 'ascii' codec can't decode byte 0xd0 in position 262: ordinal not in range(128) 2 pageData = requestHandler.read() soupHandler = BeautifulSoup(pageData) print soupHandler.findAll(...) UnicodeEncodeError: 'ascii' codec can't encode characters in position 340-345: ordinal not in range(128)

  Read the article

• basic unique ModelForm field for Google App Engine

  - by Alexander Vasiljev

  I do not care about concurrency issues. It is relatively easy to build unique form field: from django import forms class UniqueUserEmailField(forms.CharField): def clean(self, value): self.check_uniqueness(super(UniqueUserEmailField, self).clean(value)) def check_uniqueness(self, value): same_user = users.User.all().filter('email', value).get() if same_user: raise forms.ValidationError('%s already_registered' % value) so one could add users on-the-fly. Editing existing user is tricky. This field would not allow to save user having other user email. At the same time it would not allow to save a user with the same email. What code do you use to put a field with uniqueness check into ModelForm?

  Read the article

• SQLAlchemy - SQLite for testing and Postgresql for devlopment - How to port?

  - by StackUnderflow

  I want to use sqlite memory database for all my testing and Postgresql for my development/production server. But the SQL syntax is not same in both dbs. for ex: SQLite has autoincrement, and Postgresql has serial Is it easy to port the SQL script from sqlite to postgresql... what are your solutions? If you want me to use standard SQL, how should I go about generating primary key in both the databases?

  Read the article

• List available languages for PyGTK UI strings

  - by detly

  I'm cleaning up some localisation and translation settings in our PyGTK application. The app is only intended to be used under GNU/Linux systems. One of the features we want is for users to select the language used for the applications (some prefer their native language, some prefer English for consistency, some like French because it sounds romantic, etc). For this to work, I need to actually show a combo box with the various languages available. How can I get this list? In fact, I need a list of pairs of the language code ("en", "ru", etc) and the language name in the native language ("English (US)", "???????"). If I had to implement a brute force method, I'd do something like: look in the system locale dir (eg. "/usr/share/locale") for all language code dirs (eg. "en/") containing the relative path "LC_MESSAGES/OurAppName.mo". Is there a more programmatic way?

  Read the article

• Form (or Formset?) to handle multiple table rows in Django

  - by Ben

  Hi, I'm working on my first Django application. In short, what it needs to do is to display a list of film titles, and allow users to give a rating (out of 10) to each film. I've been able to use the {{ form }} and {{ formset }} syntax in a template to produce a form which lets you rate one film at a time, which corresponds to one row in a MySQL table, but how do I produce a form that iterates over all the movie titles in the database and produces a form that lets you rate lots of them at once? At first, I thought this was what formsets were for, but I can't see any way to automatically iterate over the contents of a database table to produce items to go in the form, if you see what I mean. Currently, my views.py has this code: def survey(request): ScoreFormSet = formset_factory(ScoreForm) if request.method == 'POST': formset = ScoreFormSet(request.POST, request.FILES) if formset.is_valid(): return HttpResponseRedirect('/') else: formset = ScoreFormSet() return render_to_response('cf/survey.html', { 'formset':formset, }) And my survey.html has this: <form action="/survey/" method="POST"> <table> {{ formset }} </table> <input type = "submit" value = "Submit"> </form> Oh, and the definition of ScoreForm and Score from models.py are: class Score(models.Model): movie = models.ForeignKey(Movie) score = models.IntegerField() user = models.ForeignKey(User) class ScoreForm(ModelForm): class Meta: model = Score So, in case the above is not clear, what I'm aiming to produce is a form which has one row per movie, and each row shows a title, and has a box to allow the user to enter their score. If anyone can point me at the right sort of approach to this, I'd be most grateful. Thanks, Ben

  Read the article

< Previous Page | 391 392 393 394 395 396 397 398 399 400 401 402  | Next Page >