Search Results

Search found 13683 results on 548 pages for 'python sphinx'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 400/548 | < Previous Page | 396 397 398 399 400 401 402 403 404 405 406 407  | Next Page >

  • Cant get the child dir in django hosting (alwaysdata.com) .

    - by zjm1126
    this is my file : mysite templates homepage.html accounts a.html login_view.html i can get the homepage.html and accounts\a.html on 127.0.0.1:8000 but in http://zjm1126.alwaysdata.net , i can only get the homepage.html ,and cant get the account\a.html , this is my code : return render_to_response('accounts/login_view.html') and the accounts/login_view.html is : {% include "accounts\a.html" %} what can i do , thanks ,

    Read the article

  • PyGTK: Radiobuttons are still displayed after removal

    - by canavanin
    Hi everyone! I am using PyGTK and the gtk.assistant. On one page I would like to display two radiobuttons in case the user selected a certain option on a previous page. The labels of the buttons - and whether the buttons are to be present at all - are to depend entirely on that earlier selection. Furthermore, if the user goes back and changes that selection, the page containing the radiobuttons is to be updated accordingly. I have got as far as having the radiobuttons displayed when necessary, and with the correct labels. The trouble is that if I go back and change the determining selection, or if I move one page further than the 'radiobutton page' and then move back, the buttons are not only not removed (in case that would have been required), their number has also doubled. To show you what I'm doing, here's part of my code (I've left out bits that do unrelated things, that's why the function name doesn't fit). The function is called when the "prepare" signal is emitted prior to construction of the 'radiobutten page'. def make_class_skills_treestore(self): print self.trained_by_default_hbox.get_children() # PRINT 1 for child in self.trained_by_default_hbox.get_children(): if type(child) == gtk.RadioButton: self.trained_by_default_hbox.remove(child) #child.destroy() # <-- removed the labels, but not the buttons print self.trained_by_default_hbox.get_children() # PRINT 2 class_skills = self.data.data['classes'][selected_class].class_skills.values() default_trained_count = (class_skills.count([True, True]) , class_skills.count([True, False])) num_default_trained_skills = default_trained_count[1] / 2 # you have to pick one of a pair --> don't # count each as trained by default for i in range(default_trained_count[0]): # those are trained by default --> no choice num_default_trained_skills +=1 selected_class = self.get_classes_key_from_class_selection() if default_trained_count[1]: for skill in self.data.data['classes'][selected_class].class_skills.keys(): if self.data.data['classes'][selected_class].class_skills[skill] == [ True, False ] and not self.default_radio: self.default_radio.append(gtk.RadioButton(group=None, label=skill)) elif self.data.data['classes'][selected_class].class_skills[skill] == [ True, False ] and self.default_radio: self.default_radio.append(gtk.RadioButton(group=self.default_radio[0], label=skill)) if self.default_radio: for radio in self.default_radio: self.trained_by_default_hbox.add(radio) self.trained_by_default_hbox.show_all() self.trained_by_default_hbox and self.trained_by_default_label, as well as self.default_radio stem from the above function's class. I have two print statements (PRINT 1 and PRINT 2) in there for debugging. Here's what they give me: PRINT 1: [<gtk.Label object at 0x8fc4c84 (GtkLabel at 0x90a2f20)>, <gtk.RadioButton object at 0x8fc4d4c (GtkRadioButton at 0x90e4018)>, <gtk.RadioButton object at 0x8fc4cac (GtkRadioButton at 0x90ceec0)>] PRINT 2: [<gtk.Label object at 0x8fc4c84 (GtkLabel at 0x90a2f20)>] So the buttons have indeed been removed, yet they still show up on the page. I know the code requires some refactoring, but first I'd like to get it to work at all... If someone could help me out that would be great! Thanks a lot in advance for your replies - any kind of help is highly appreciated.

    Read the article

  • Type-aware rendering (and editing) of tabular data in pyqt4

    - by pihentagy
    I would like to have a very short / minimal example of how to create some tabular widget with different types of item in it. In the first round let's say I'd like to render [["Hello", 12, True], ["World", 13, False]] (Hello as string, 12 as number (right-align), True as a checkbox for eg.), but it would be nice to have Dates, Colors, and other type of info. Next round: editing (integer with spinbox, maybe sometimes a combobox is handy, but that may not work out of the box). There must be a simple solution, but I couldn't find...

    Read the article

  • default model field attribute in Django

    - by Rosarch
    I have a Django model: @staticmethod def getdefault(): print "getdefault called" return cPickle.dumps(set()) _applies_to = models.TextField(db_index=True, default=getdefault) For some reason, getdefault() is never called, even as I construct instances of this model and save them to the database. This seems to contradict the Django documentation: Field.default The default value for the field. This can be a value or a callable object. If callable it will be called every time a new object is created. Am I doing something wrong? Update: Originally, I had this, but then I switched to the above version to debug: _applies_to = models.TextField(db_index=True, default=cPickle.dumps(set())) I'm not sure why that wouldn't work.

    Read the article

  • Return an object after parsing xml with SAX

    - by sentimental_turtle
    I have some large XML files to parse and have created an object class to contain my relevant data. Unfortunately, I am unsure how to return the object for later processing. Right now I pickle my data and moments later depickle the object for access. This seems wasteful, and there surely must be a way of grabbing my data without hitting the disk. def endElement(self, name): if name == "info": # done collecting this iteration self.data.setX(self.x) self.data.setY(self.y) elif name == "lastTagOfInterest": # done with file # want to return my object from here filehandler = open(self.outputname + ".pi", "w") pickle.dump(self.data, filehandler) filehandler.close() I have tried putting a return statement in my endElement tag, but that does not seem to get passed up the chain to where I call the SAX parser. Thanks for any tips.

    Read the article

  • using dictionary to assign misspelled words to its line number

    - by jad
    This is the code I have so far d = {} counter = 0 for lines in words: counter += 1 for word in text1: if word not in words: d[word] = [counter] else: d[word].append(counter) print(word, d[counter]) words = my text file text1 is my misspelled words But this gives me an error. What I want to do is print the word and the line number e.g. togeher 5 7

    Read the article

  • Why will this for loop not return one field from list rather than the list?

    - by Dick Eshelman
    import csv """sample row = 10/6/2010,73.42,74.43,72.9,74.15,2993500""" filename_in = 'c:/python27/scripts/fiverows.csv' reader = csv.reader(open(filename_in, "rb"), dialect="excel", delimiter="\t", quoting =csv.QUOTE_MINIMAL) for row in reader: for item in row: print 'row = ',row print 'item = ', item When you run this script and print the row you get the sample row returned in [] as a list. When you print the item you get the sample row as an unquoted string. Why do I not get each field ie, (10/6/2010), (73.42), etc. returned as an item? How do I return a single item?

    Read the article

  • Query distinct list of choices for Django form with App Engine Datastore

    - by Brian
    I've been trying to figure this out for hours across a couple of days, and can not get it to work. I've been everywhere. I'll continue trying to figure it out, but was hoping for a quicker solution. I'm using App Engine datastore + Django. Using a query in a view and custom forms, I was able to get a list to the form but then I was not able to post. I have been trying to figure out how to dynamically add the choices as part of the Django form... I've tried various ways with no success. Help! Below are the two models. I'd like to get a distinct list of address_id to show in the location field in InfoForm. This fields could (and maybe should) be named the same, but I thought it'd be easier if they were named different. class Info(db.Model): user = db.UserProperty() location = db.StringProperty() info = db.StringProperty() created = db.DateTimeProperty(auto_now_add=True) modified = db.DateTimeProperty(auto_now=True) class Locations(db.Model): user = db.UserProperty() address_id = db.StringProperty() address = db.StringProperty() class InfoForm(djangoforms.ModelForm): info = forms.ChoiceField(choices=INFO_CHOICES) location = forms.ChoiceField() class Meta: model = Info exclude = ['user','created','modified']

    Read the article

  • Most secure way to generate a random session ID for a cookie?

    - by ensnare
    I'm writing my own sessions controller that issues a unique id to a user once logged in, and then verifies and authenticates that unique id at every page load. What is the most secure way to generate such an id? Should the unique id be completely random? Is there any downside to including the user id as part of the unique id?

    Read the article

  • How do you get SQLAlchemy to override MySQL "on update CURRENT_TIMESTAMP"

    - by nocola
    I've inherited an older database that was setup with a "on update CURRENT_TIMESTAMP" put on a field that should only describe an item's creation. With PHP I have been using "timestamp=timestamp" on UPDATE clauses, but in SQLAlchemy I can't seem to force the system to use the set timestamp. Do I have no choice and need to update the MySQL table (millions of rows)? foo = session.query(f).get(int(1)) ts = foo.timestamp setattr(foo, 'timestamp', ts) setattr(foo, 'bar', bar) www_model.www_Session.commit() I have also tried: foo = session.query(f).get(int(1)) setattr(foo, 'timestamp', foo.timestamp) setattr(foo, 'bar', bar) www_model.www_Session.commit()

    Read the article

  • get the list and input from one function and run them in different function

    - by rookie
    i have a programm that generate the list and then i ask them to tell me what they want to do from the menu and this is where my problem start i was able to get the input form the user to different function but when i try to use the if else condition it doesn't check, below are my code def menu(x,l): print (x) if x == 1: return make_table(l) if x == 2: y= input("enter a row (as a number) or a column (as an uppercase letter") if y in [ "1",'2','3']: print("Minmum is:",minimum(y,l)) if x== 3: print ('bye') def main(): bad_filename = True l =[] while bad_filename == True: try: filename = input("Enter the filename: ") fp = open(filename, "r") for f_line in fp: f_str=f_line.strip() f_str=f_str.split(',') for unit_str in f_str: unit=float(unit_str) l.append(unit) bad_filename = False except IOError: print("Error: The file was not found: ", filename) #print(l) condition=True while condition==True: print('1- open\n','2- maximum') x=input("Enter the choice") menu(x,l) main() from the bottom function i can get list and i can get the user input and i can get the data and move it in second function but it wont work after that.thank you

    Read the article

  • integrate / build 'weather radar' widget

    - by zack
    I'm looking to integrate a 'weather radar' widget into a site I'm building. The only available resource I can find is: http://www.meteoonline.co.uk/gadgets/Europe/Netherlands/135 which basically delivers a flash mov in a iframe ! urrrgh! - and 'permission denied' of course with any javascript interaction on the iframe.. Can anyone suggest an alternative resource / or approach ? I'm happy to work with the raw data if I can get it .. any ideas welcome ! site is like [ html5 + jquery on django ]

    Read the article

  • Django: how to create sites dynamically?

    - by Leandro Ardissone
    Hi, I need to create an application for the company where I can create sites dynamically. For example, I need an admin interface (Django's admin is enough) where I can setup a new site and add some settings to it. Each site must hold a domain (domains can be manually added to apache conf, but if Django can handle it too would be awesome). Each site must be independent of the others, I mean, I shouldn't be able to see the data content of other sites but I can share same applications/models. I've seen the Django's Sites framework, but I'm not sure if it's possible to implement that way. Should I use Sites framework or create a new app that can handle sites better? What do you think?

    Read the article

  • Google App Engine - Is os.environ reset between requests?

    - by Ian Charnas
    Hello I can't think of a way to test this and was hoping someone here knew the answer... I'm storing some request-specific data in os.environ, and was wondering if that data was going to leak to other requests. Does anyone know? Yes I realize that it's normal to use request.environ for this, and usually I do, but I want to store the currently authorized user ID (I'm using custom auth, not GAE auth) inside os.environ so that the models know the currently logged in user (remember, they don't have access to request.environ) without me having to pass the request object to just about every single model method. any help would be greatly appreciated Ian

    Read the article

  • django threadedcomments

    - by Patrick
    Hi folks, I would like to setup a comment systems on my site, using django threadedcomments, and I follow all the steps in the Tutorial, however, I get the following error: No module named newforms.util I am not sure what causing this issue, here is my configuration: #settings.py INSTALLED_APPS = ( 'django.contrib.admin', 'django.contrib.auth', 'django.contrib.contenttypes', 'django.contrib.sessions', 'django.contrib.sites', 'myproject.myapp', 'threadedcomments', ) #urls.py from django.conf import settings from django.conf.urls.defaults import * from django.contrib import admin admin.autodiscover() urlpatterns = patterns('', (r'^admin/', include(admin.site.urls)), (r'^threadedcomments/', include('threadedcomments.urls')), ) Please let me know if there is another better choice for commenting, as long as the comment system is flexible and able to do lot of customization, as well as threadedcomment, of coz, integrating with Rating, I am happy to use the other one. Thanks guys.

    Read the article

  • how to print the linenumber of incorrectwords located in a txt file ?

    - by jad
    i have this piece of code which only prints the line number of the incorrect words. i want it to print the linenumbers of the incorrect words from the txt file. Am i able to modify this code to do that? # text1 is my incorrect words # words is my text file where my incorrect word are in from collections import defaultdict d = defaultdict(list) for lineno, word in enumerate(text1): d[word].append(lineno) print(d)

    Read the article

  • CherryPy always returning HTTP 200 [closed]

    - by DarkArctic
    I'm having a bit of a problem when browsing to a non-existent resource. I get a response code of 200 instead of 404. I'm using the MethodDispatcher and I have a class that overloads the __getattr__ method to instantiate a resource if a child exists or to return AttributeError if one doesn't. My class is always returning the AttributeError correctly, but the data I actually get is always from the last good resource. Here's a simplified (except for __getattr__) version of my class: class BaseResource(object): exposed = True def __init__(self, name): self.children = [] # Pretend this has child resources def __getattr__(self, name): if name in self._children: uuid, application, obj_type, server = self._children[name] try: resource = getattr(app[application], obj_type) except AttributeError as e: raise cherrypy.HTTPError(500, e) return resource(uuid) else: raise AttributeError('Child with name \'{}\' could not be found.'.format(name)) def GET(self): cherrypy.log.error('*** {} not found, raising AttributeError'.format(name)) return 'GET request for {}'.format(self._name) So fetching I get the following when I browse to the following resources: http://localhost:8000/users - This resource exists, so it returns it correctly. http://localhost:8000/users/fake - This returns the "users" resource giving an HTTP 200. http://localhost:8000/users/fake/reallyfake - This returns the "users" resource again. So my question is, where can I start looking to find out why my code isn't returning a 404 for a non-existent resource. I'm sure I've done something wrong, but I'm not sure what. Whatever I did wrong I've undone and I'm now getting a 404 returned correctly. I'm sorry I can't give any detail on what the issue was, but I'm honestly not sure what I did.

    Read the article

  • django file serving issues

    - by tipu
    I have in my url patterns, urlpatterns += patterns('', (r'^(?P<path>.*)$', 'django.views.static.serve', {'document_root': '/home/tipu/Dropbox/dev/workspace/search/images'}) In my template when I do <link rel="stylesheet" type="text/css" href="{{ MEDIA_URL }}style.css" /> It serves the css just fine. But the file logo.png, that's in the same directory as style.css, doesn't show when I do this: <img src = "{{ MEDIA_URL }}logo.png" id = "logo" /> Any idea why?

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 396 397 398 399 400 401 402 403 404 405 406 407  | Next Page >