error catching exception while System.out.print
- by user1702633
I have 2 classes, one that implements a double lookup( int i);
and one where I use that lookup(int i) in solving a question, or in this case printing the lookup values. This case is for an array.
So I read the exception documentation or google/textbook and come with the following code:
public double lookup(int i) throws Exception
{
if( i > numItems)
throw new Exception("out of bounds");
return items[i];
}
and take it over to my class and try to print my set, where set is a name of the
object type I define in the class above.
public void print()
{
for (int i = 0; i < set.size() - 1; i++)
{
System.out.print(set.lookup(i) + ",");
}
System.out.print(set.lookup(set.size()));
}
I'm using two print()'s to avoid the last "," in the print, but am getting an
unhandled exception Exception (my exception's name was Exception)
I think I have to catch my exception in my print() but cannot find the correct formatting online. Do I have to write
catch exception Exception? because that gives me a syntax error saying invalid type on catch.
Sources like
http://docs.oracle.com/javase/tutorial/essential/exceptions/
are of little help to me, I'm can't seem to grasp what the text is telling me. I'm also having trouble finding sources with multiple examples where I can actually understand the coding in the examples.
so could anybody give me a source/example for the above catch phrase and perhaps a decent source of examples for new Java programmers? my book is horrendous and I cannot seem to find an understandable example for the above catch phrase online.
