Get spiral index from location
- by ricick
I'm using Alberto Santini's solution to this question to get a spiral grid reference based on an items index
Algorithm for iterating over an outward spiral on a discrete 2D grid from the origin
It's not the accepted solution, but it's the best for my needs as it avoids using a loop.
It's working well, but what I want now is to do the inverse. Based on a known x and y coordinate return the index of a location.
This is as a precursor to returning the items surrounding a given location.
