Hi,
I need a memory efficient int-int dict in Python that would support the following operations in O(log n) time:
d[k] = v # replace if present
v = d[k] # None or a negative number if not present
I need to hold ~250M pairs, so it really has to be tight.
Do you happen to know a suitable implementation (Python 2.7)?
EDIT Removed impossible requirement and other nonsense. Thanks, Craig and Kylotan!
To rephrase. Here's a trivial int-int dictionary with 1M pairs:
>>> import random, sys
>>> from guppy import hpy
>>> h = hpy()
>>> h.setrelheap()
>>> d = {}
>>> for _ in xrange(1000000):
... d[random.randint(0, sys.maxint)] = random.randint(0, sys.maxint)
...
>>> h.heap()
Partition of a set of 1999530 objects. Total size = 49161112 bytes.
Index Count % Size % Cumulative % Kind (class / dict of class)
0 1 0 25165960 51 25165960 51 dict (no owner)
1 1999521 100 23994252 49 49160212 100 int
On average, a pair of integers uses 49 bytes.
Here's an array of 2M integers:
>>> import array, random, sys
>>> from guppy import hpy
>>> h = hpy()
>>> h.setrelheap()
>>> a = array.array('i')
>>> for _ in xrange(2000000):
... a.append(random.randint(0, sys.maxint))
...
>>> h.heap()
Partition of a set of 14 objects. Total size = 8001108 bytes.
Index Count % Size % Cumulative % Kind (class / dict of class)
0 1 7 8000028 100 8000028 100 array.array
On average, a pair of integers uses 8 bytes.
I accept that 8 bytes/pair in a dictionary is rather hard to achieve in general. Rephrased question: is there a memory-efficient implementation of int-int dictionary that uses considerably less than 49 bytes/pair?
