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  • gaema twitter handle error..

    - by zjm1126
    i use gaema for twitter user loggin http://code.google.com/p/gaema/ and my code is : class TwitterAuth(WebappAuth, auth.TwitterMixin): pass class TwitterHandler(BaseHandler): def get(self): twitter_auth = TwitterAuth(self) try: if self.request.GET.get("oauth_token", None): twitter_auth.get_authenticated_user(self._on_auth) self.response.out.write('sss') return twitter_auth.authorize_redirect() except RequestRedirect, e: return self.redirect(e.url, permanent=True) self.render_template('index.html', user=None) def _on_auth(self, user): """This function is called immediatelly after an authentication attempt. Use it to save the login information in a session or secure cookie. :param user: A dictionary with user data if the authentication was successful, or ``None`` if the authentication failed. """ if user: # Authentication was successful. Create a session or secure cookie # to keep the user logged in. #self.response.out.write('logged in as '+user['first_name']+' '+user['last_name']) self.response.out.write(user) return else: # Login failed. Show an error message or do nothing. pass # After cookie is persisted, redirect user to the original URL, using # the home page as fallback. self.redirect(self.request.GET.get('redirect', '/')) and the error is : Traceback (most recent call last): File "D:\Program Files\Google\google_appengine\google\appengine\ext\webapp\__init__.py", line 511, in __call__ handler.get(*groups) File "D:\zjm_code\gaema\demos\webapp\main.py", line 76, in get twitter_auth.authorize_redirect() File "D:\zjm_code\gaema\demos\webapp\gaema\auth.py", line 209, in authorize_redirect http.fetch(self._oauth_request_token_url(), self.async_callback( File "D:\zjm_code\gaema\demos\webapp\gaema\auth.py", line 239, in _oauth_request_token_url consumer_token = self._oauth_consumer_token() File "D:\zjm_code\gaema\demos\webapp\gaema\auth.py", line 441, in _oauth_consumer_token self.require_setting("twitter_consumer_key", "Twitter OAuth") TypeError: require_setting() takes at most 2 arguments (3 given) thanks

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  • best way to find out type

    - by laspal
    hi, I have a dict val_dict - {'val1': 'abcd', 'val': '1234', 'val3': '1234.00', 'val4': '1abcd 2gfff'} All the values to my keys are string. So my question is how to find out type for my values in the dict. I mean if i say`int(val_dict['val1']) will give me error. Basically what I am trying to do is find out if the string is actual string or int or float.` if int( val_dict['val1'): dosomething else if float(val_dict['val1']): dosomething thanks

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  • Checkboxes with pylons

    - by user268746
    Hello, I have been trying to add some check boxes in a pylons mako. However I don't know how to get their values in the controller. It seems that it can only get the first value of the check boxes. I tried using form encode but i got several errors. Is there an easier way to do this? Thanks

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  • How do I make a defaultdict safe for unexpecting clients?

    - by ~miki4242
    Several times (even several in a row) I've been bitten by the defaultdict bug. d = defaultdict(list) ... try: v = d["key"] except KeyError: print "Sorry, no dice!" For those who have been bitten too, the problem is evident: when d has no key 'key', the v = d["key"] magically creates an empty list and assigns it to both d["key"] and v instead of raising an exception. Which can be quite a pain to track down if d comes from some module whose details one doesn't remember very well. I'm looking for a way to take the sting out of this bug. For me, the best solution would be to somehow disable a defaultdict's magic before returning it to the client.

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  • How do I check for Existence of a Record in GAE

    - by VDev
    I am trying to create a simple view in Django & GAE, which will check if the user has a profile entity and prints a different message for each case. I have the program below, but somehow GAE always seem to return a object. My program is below import datetime from django.http import HttpResponse, HttpResponseRedirect from google.appengine.api import users from google.appengine.ext import db from models import Profile import logging #from accounts.views import profile # Create your views here. def login_view(request): user = users.get_current_user() profile = db.GqlQuery("SELECT * FROM Profile WHERE account = :1", users.get_current_user()) logging.info(profile) logging.info(user) if profile: return HttpResponse("Congratulations Your profile is already created.") else: return HttpResponse("Sorry Your profile is NOT created.") My model object is Profile defined as follows: class Profile(db.Model): first_name = db.StringProperty() last_name = db.StringProperty() gender = db.StringProperty(choices=set(["Male", "Female"])) account = db.UserProperty(required = True) friends = db.ListProperty(item_type=users.User) last_login = db.DateTimeProperty(required=True) Thanks for the help.

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  • Pygame's Message-multiple lines?

    - by Jam
    I am using pygame and livewires (though I don't think that part is relevant here) to create a game. I've got the game working, but I'm trying to make something akin to a title screen before the game starts. However, it doesn't recognize when I try to make a new line appear. Here is what I have: begin_message=games.Message(value=""" Destroy the Bricks!\n In this game, you control a paddle,\n controlled by your mouse,\n and attempt to destroy all the rows of bricks.\n Careful though, you only have 1 life.\n Don't mess up! The game will start in\n 5 seconds.""", size=30, x=games.screen.width/2, y=games.screen.height/2, lifetime=500, color=color.white, is_collideable=False) games.screen.add(begin_message) The message appears on the screen, but the newline doesn't happen, so I can only read the first part of the message. Is there a way to make this message actually appear, or can I not use the 'Message' for this?

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  • Amazon S3 permissions

    - by Joe
    Trying to understand S3...How do you limit access to a file you upload to S3? For example, from a web application, each user has files they can upload, but how do you limit access so only that user has access to that file? It seems like the query string authentication requires an expiration date and that won't work for me, is there another way to do this?

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  • Problems installing a package from PyPI: root files not installed

    - by intuited
    After installing the BitTorrent-bencode package, either via easy_install BitTorrent-bencode or pip install BitTorrent-bencode, or by downloading the tarball and installing that via easy_install $tarball, I discover that /usr/local/lib/python2.6/dist-packages/BitTorrent_bencode-5.0.8-py2.6.egg/ contains EGG-INFO/ and test/ directories. Although both of these subdirectories contain files, there are no files in the BitTorr* directory itself. The tarball does contain bencode.py, which is meant to be the actual source for this package, but it's not installed by either of those utils. I'm pretty new to all of this so I'm not sure if this is a problem with the package or with what I'm doing. The package was packaged a while ago (2007), so perhaps it's using some deprecated configuration aspect that I need to supply a command-line flag for. I'm more interested in learning what's wrong with either the package or my procedures than in getting this particular package installed; there is another package called hunnyb that seems to do a decent enough job of decoding bencoded data. Mostly I'd like to know how to deal with such problems in other packages.

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  • Many-to-one relationship in SQLAlchemy

    - by Arrieta
    This is a beginner-level question. I have a catalog of mtypes: mtype_id name 1 'mtype1' 2 'mtype2' [etc] and a catalog of Objects, which must have an associated mtype: obj_id mtype_id name 1 1 'obj1' 2 1 'obj2' 3 2 'obj3' [etc] I am trying to do this in SQLAlchemy by creating the following schemas: mtypes_table = Table('mtypes', metadata, Column('mtype_id', Integer, primary_key=True), Column('name', String(50), nullable=False, unique=True), ) objs_table = Table('objects', metadata, Column('obj_id', Integer, primary_key=True), Column('mtype_id', None, ForeignKey('mtypes.mtype_id')), Column('name', String(50), nullable=False, unique=True), ) mapper(MType, mtypes_table) mapper(MyObject, objs_table, properties={'mtype':Relationship(MType, backref='objs', cascade="all, delete-orphan")} ) When I try to add a simple element like: mtype1 = MType('mtype1') obj1 = MyObject('obj1') obj1.mtype=mtype1 session.add(obj1) I get the error: AttributeError: 'NoneType' object has no attribute 'cascade_iterator' Any ideas?

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  • Remove all user's cookies/sessions when password is reset

    - by Juraj
    I'm interested in improving security of my TurboGears 2.2 application so that when user changes his password, it logs him out from all sessions and he must login again. When user changes password on browser 1, he must relogin on browser 2, too. Experiments show that this is not the case, especially if browser 2 had "remember me" enabled. It's standard quickstarted app using repoze.who. It seems maybe I need to change AuthTktCookiePlugin, but don't see a way to do it without much rewiring.

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  • HttpResponseRedirect question

    - by Hulk
    Cant we send a dictionary variable when using HttpResponseRedirect render_to_response('edited/display.html',context_instance=RequestContext(request,{'newlist': newlist})) //How can the dictionary and the request sent back again //sumthing like this return HttpResponseRedirect('edited/display.html',context_instance=RequestContext(request,{'newlist': newlist}))

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  • Selenium selected option in dropdown not displayed correctly

    - by luckyfool
    I have the following issue with Selenium Webdriver. There are two dropdown menus on a page i am testing "brand" and "items". The options of "items" depend on which brand you choose. I am trying to iterate through all possible choices and print brand-item pairs. I use two possible ways to pick an option from each dropdown menu Using Select(): def retryingSelectOption(name,n): result=False attempts=0 while attempts<5: try: element=Select(driver.find_element_by_name(name)) element.select_by_index(n) print element.all_selected_options[0].text result=True break except StaleElementReferenceException: pass attempts+=1 return result And using .click(): def retryingClickOption(name,n): result=False attempts=0 while attempts<5: try: driver.find_element_by_name(name).find_elements_by_tag_name("option")[n].click() result=True break except StaleElementReferenceException: pass attempts+=1 return result My problem is that at ,what seem to me as random moments (sometimes it works sometimes it does not), even though the above functions return True and printing out the selected option shows me the correct answer, the browser still displays the previous option. So basically Selenium tells me i have picked the right option but the browser displays the previous one.No idea what is wrong.

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  • rename keys in a dictionary

    - by user366660
    i want to rename the keys of a dictionary are which are ints, and i need them to be ints with leading zeros's so that they sort correctly. for example my keys are like: '1','101','11' and i need them to be: '001','101','011' this is what im doing now, but i know there is a better way tmpDict = {} for oldKey in aDict: tmpDict['%04d'%int(oldKey)] = aDict[oldKey] newDict = tmpDict

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  • Default subclass objects in Sqlalchemy?

    - by Timmy
    im using the example from the pylons book orm.mapper(Comment, comment_table) orm.mapper(Tag, tag_table) orm.mapper(Nav, nav_table, polymorphic_on=nav_table.c.type, polymorphic_identity='nav') orm.mapper(Section, section_table, inherits=Nav, polymorphic_identity='section') orm.mapper(Page, page_table, inherits=Nav, polymorphic_identity='page', properties={ 'comments':orm.relation(Comment, backref='page', cascade='all'), 'tags':orm.relation(Tag, secondary=pagetag_table) }) i am mostly copying from this, but is there a simple way have a default Page that gets referenced, but if users requests a change, create a new Page object? thanks i want something similar to this class DefaultPage(Page): __init__(self): self.a = a self.b = b self.c = c orm.mapper(DefaultPage, None, inherits=Nav, yada yada )

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  • Building a user subscription application

    - by Tristan O'Neil
    Hello, I'm trying to come up with the best way to handle user subscription and management for our magazine website. What I want to happen is a user purchases a subscription and they are granted online access of a certain membership role for a certain amount of time depending on how many years they subscribed for. I would also like the system to be able to send out emails when a subscription is almost up. I've seen some third party projects to help accomplish this but I'd prefer to write this from scratch as I want total control over how it works. Any suggestions would be helpful. The main thing I can't figure out is how to have an expiring membership. You must keep track of when the user signed up and how long until they should expire.

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  • Display values and how many times they occured using a Dictionary

    - by user1730056
    I've been told to By using a dictionary (or your solution to Part 4), write a method at_least(a, n) that takes a list, a, and an integer, n, as arguments and returns a list containing only the elements of a that occur at least n times. For complete marks, the list should contain the elements in order of their first occurrence in a. I was able to figure this without using a dictionary, with def at_least2(a, n): return [x for x in a if a.count(x) is n] I was wondering how I can write this using a dictionary? The input is: a = [-6, 8, 7, 3, 2, -9, 1, -3, 2, -4, 4, -8, 7, 8, 2, -2, -7, 0, 1, -9, -3, -7, -3, -5, 6, -3, 6, -3, -10, -8] def at_least(a, 2): and the output: [8, 7, 2, -9, 1, -3, 2, -8, 7, 8, 2, -7, 1, -9, -3, -7, -3, 6, -3, 6, -3, -8] Edit: I don't understand how a dictionary is being used, yet the output isn't in dictionary form? My understanding is that dictionaries have values for each object. I'm not sure if I'm using the right terms.

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  • Partially flattening a list

    - by alj
    This is probably a really silly question but, given the example code at the bottom, how would I get a single list that retain the tuples? (I've looked at the itertools but it flattens everything) What I currently get is: ('id', 20, 'integer') ('companyname', 50, 'text') [('focus', 30, 'text'), ('fiesta', 30, 'text'), ('mondeo', 30, 'text'), ('puma', 30, 'text')] ('contact', 50, 'text') ('email', 50, 'text') what I would like is a single level list like: ('id', 20, 'integer') ('companyname', 50, 'text') ('focus', 30, 'text') ('fiesta', 30, 'text') ('mondeo', 30, 'text') ('puma', 30, 'text') ('contact', 50, 'text') ('email', 50, 'text') def getproducts(): temp_list=[] product_list=['focus','fiesta','mondeo','puma'] #usually this would come from a db for p in product_list: temp_list.append((p,30,'text')) return temp_list def createlist(): column_title_list = ( ("id",20,"integer"), ("companyname",50,"text"), getproducts(), ("contact",50,"text"), ("email",50,"text"), ) return column_title_list for item in createlist(): print item Thanks ALJ

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  • What motivates people to learn a new programming language?

    - by szabgab
    There are plenty of question asking Which Programming Language Should I Learn? but I have not found an answer yet to the question what really motivates people to learn a specific new language?. There are the people who think they should learn a new language every year for educational purpose. How do they decide on the languages to be learned? Then I guess there are people who learn a new language because people around them told it is a fun language and they can build nice things with it. Of course if the current job requires it people would learn a new language but I think if the language seems to have a potential to earn money (e.g. There are plenty of jobs in Java or ObjectiveC can be used to write apps for the iPhone and make money). So why are you learning a new language or why have you learned the languages you know?

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  • Django template context not working with imported class

    - by Andy Hume
    I'm using Django's templating on appengine, and am having a problem whereby a class I'm importing from another package is not correctly being made available to the template context. Broadly speaking, this is the code. The prop1 is not available in the template in the first example below, but is in the second. MyClass is identical in both cases. This does not work: from module import MyClass context = MyClass() self.response.out.write(template.render(path, context)) This does: class MyClass(object): def __init__(self): self.prop1 = "prop1" context = MyClass() self.response.out.write(template.render(path, context)) If I log the context in the above code I get: <module.MyClass object at 0x107b1e450> when it's imported, and: <__main__.MyClass object at 0x103759390> when it's defined in the same file. Any clues as to what might cause this kind of behaviour?

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  • error while storing data in datastore

    - by Rahul99
    for st in Traks : trak = TrakHtml() trak.hawb = st url = 'http://etracking.cevalogistics.com/eTrackResultsMulti.aspx?sv='+st result = urlfetch.fetch(url) trak.htmlData = result.content trak.put() trak.htmlData is a textproparty(). It's giving this error: UnicodeDecodeError: 'ascii' codec can't decode byte 0xc2 in position 29284: ordinal not in range(128)

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