XSLT multiple string replacement with recursion
- by John Terry
I have been attempting to perform multiple (different) string replacement with recursion and I have hit a roadblock. I have sucessfully gotten the first replacement to work, but the subsequent replacements never fire. I know this has to do with the recursion and how the with-param string is passed back into the call-template. I see my error and why the next xsl:when never fires, but I just cant seem to figure out exactly how to pass the complete modified string from the first xsl:when to the second xsl:when. Any help is greatly appreciated.
<xsl:template name="replace">
<xsl:param name="string" select="." />
<xsl:choose>
<xsl:when test="contains($string, ' ')">
<xsl:value-of select="substring-before($string, ' ')" />
<br/>
<xsl:call-template name="replace">
<xsl:with-param name="string" select="substring-after($string, ' ')"/>
</xsl:call-template>
</xsl:when>
<xsl:when test="contains($string, 'TXT')">
<xsl:value-of select="substring-before($string, ' TXT')" />
<xsl:call-template name="replace">
<xsl:with-param name="string" select="substring-after($string, ' ')" />
</xsl:call-template>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$string"/>
</xsl:otherwise>
</xsl:choose>
</xsl:template>
