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  • Using a comma seperated data in MYSQL "IN" clause

    - by Sashi Kant
    I have a column in one of my table where I store multiple ids seperated by comma's. Is there a way in which I can use this column's value in the "IN" clause of a query. The column(city) has values like 6,7,8,16,21,2 I need to use as Select * from table where e_ID in (Select city from locations where e_Id=?) I am satisfied with Crozin's answer, but I am open to suggestions, views and options. Feel free to share your views.

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  • Drop Down list in PHP

    - by ajithperuva
    In my application am submiting my form by using post for a php page. <form method="post"> <select name="txtplace"> <option value="1">ajith</option> </select> </form> here when i am try to get the value of my dropdown its only getting 1.How can i get ajith

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  • How to Solve this Error "Cannot convert lambda expression to type 'string' because it is not a deleg

    - by peace
    . I get this error: "Cannot convert lambda expression to type 'string' because it is not a delegate type" - keyword select become underlined in blue Can you please advice. Employee emp = new Employee(); comHandledBySQt.DataSource = from x in emp.GetDataFromTable("1") select new { x.Id, Name = x.FirstName + " " + x.LastName }; comHandledBySQt.DisplayMember = "Name"; comHandledBySQt.ValueMember = "Id"; Above code should displays drop list of employees first name and last name in a combo box

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  • .NET Extension Objects with XSLT -- how to iterate over a collection?

    - by Pandincus
    Help me, Stackoverflow! I have a simple .NET 3.5 console app that reads some data and sends emails. I'm representing the email format in an XSLT stylesheet so that we can easily change the wording of the email without needing to recompile the app. We're using Extension Objects to pass data to the XSLT when we apply the transformation: <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:msxsl="urn:schemas-microsoft-com:xslt" exclude-result-prefixes="msxsl" xmlns:EmailNotification="ext:EmailNotification"> -- this way, we can have statements like: <p> Dear <xsl:value-of select="EmailNotification:get_FullName()" />: </p> The above works fine. I pass the object via code like this (some irrelevant code omitted for brevity): // purely an example structure public struct EmailNotification { public string FullName { get; set; } } // Somewhere in some method ... var notification = new Notification("John Smith"); // ... XsltArgumentList xslArgs = new XsltArgumentList(); xslArgs.AddExtensionObject("ext:EmailNotification", notification); // ... // The part where it breaks! (This is where we do the transformation) xslt.Transform(fakeXMLDocument.CreateNavigator(), xslArgs, XmlWriter.Create(transformedXMLString)); So, all of the above code works. However, I wanted to get a little fancy (always my downfall) and pass a collection, so that I could do something like this: <p>The following accounts need to be verified:</p> <xsl:for-each select="EmailNotification:get_SomeCollection()"> <ul> <li> <xsl:value-of select="@SomeAttribute" /> </li> </ul> <xsl:for-each> When I pass the collection in the extension object and attempt to transform, I get the following error: "Extension function parameters or return values which have Clr type 'String[]' are not supported." or List, or IEnumerable, or whatever I try to pass in. So, my questions are: How can I pass in a collection to my XSLT? What do I put for the xsl:value-of select="" inside the xsl:for-each ? Is what I am trying to do impossible?

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  • Emacs 23: Selection not highlighted

    - by phimuemue
    I installed Ubuntu 10.04, and with it came Emacs 23. If I want to select text in Emacs, that works perfectly fine except the fact that the region is not highlighted. However, this only happens, if I try to make a region using the keyboard. If I select something with the mouse, it is highlighted as usual. Does anybody know, why the region is not highlighted and how to fix that?

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  • jQuery and PHP suggested answers

    - by Samir Ghobril
    Hey guys, there is a form where the user select some of his friends and I'm curious on how I can implement a list that searches simultaneously while the user is typing a friend's name and when he selects the name the name is written in the text box(jQuery). And if the user wants to select more than one friend, when I'm inserting the names in the database, how can I separate the names that are written in one input field?

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  • More efficient left join of big table

    - by Zeus
    Hello, I have the following (simplified) query select P.peopleID, P.peopleName, ED.DataNumber from peopleTable P left outer join ( select PE.peopleID, PE.DataNumber from formElements FE inner join peopleExtra PE on PE.ElementID = FE.FormElementID where FE.FormComponentID = 42 ) ED on ED.peopleID = P.peopleID Without the sub-query this procedure takes ~7 seconds, but with it, it takes about 3minutes. Given that table peopleExtra is rather large, is there a more efficient way to do that join (short of restructuring the DB) ?

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  • Top 10 unless count is zero

    - by datatoo
    This is probably easy, but eludes me. SQL server2005 I want to show top 100 but if there are not 100 only want to show those and not include zero counts in the result SELECT TOP (100) UserName, FullName_Company, FullName, (SELECT COUNT(*) FROM dbo.Member_Ref WHERE (RefFrom_UserName = dbo.view_Members.UserName) AND (RefDate >= '5/1/2010') AND (RefDate <= '6/1/2010')) AS RefFromCount FROM dbo.view_Members WHERE (MemberStatus = N'Active') ORDER BY RefFromCount DESC I have tried using Group By and HAVING COUNT(*)0 all with the same wrong results

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  • How to update a single table using trigger in MS SQL 2008

    - by Yakob-Jack
    I have a table PeroidicDeduction and the fields are ID(auto-increment),TotalDeduction(e.g.it can be loan),Paid(on which the deduction for each month),RemainingAmount, What I want is when every time I insert or update the table---RemainingAmount will get the value of TotalDeduction-SUM(Paid)....and writ the following trigger...but dosen't work for me CREATE TRIGGER dbo.UpdatePD ON PeroidicDedcution AFTER INSERT,UPDATE AS BEGIN UPDATE PeroidicDedcution SET REmaininAmoubnt=(SELECT TotalDeduction-(SELECT SUM(Paid) FROM PeroidicDeduction) FROM PeroidicDeduction) END NOTE: it is on a Single table

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  • SQL: Get count of rows returned from a left join

    - by Rogue Coder
    I have two tables, one called calendars and one called events. There can be multiple calendars, and multiple events in a calendar. I want to select every calendar, also getting the number of events in the calendar. Right now I have : SELECT C.*, COUNT(*) AS events FROM `calendars` AS C LEFT JOIN `events` E ON C.ID=E.calendar GROUP BY C.ID But that doesn't work. Items with no events still return 1. Any ideas?

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  • SQLAlchemy autocommiting?

    - by muckabout
    I have an issue with SQLAlchemy apparently committing. A rough sketch of my code: trans = self.conn.begin() try: assert not self.conn.execute(my_obj.__table__.select(my_obj.id == id)).first() self.conn.execute(my_obj.__table__.insert().values(id=id)) assert not self.conn.execute(my_obj.__table__.select(my_obj.id == id)).first() except: trans.rollback() raise I don't commit, and the second assert always fails! In other words, it seems the data is getting inserted into the database even though the code is within a transaction! Is this assessment accurate?

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  • how to add a new value to a dropdown list in Rails

    - by LearnRails
    In my item table, I have a itemname column which is currently a dropdown list taking values from DB. <%= select 'item','itemname' , Item.find(:all).collect{|c| [c.itemname]},{:include_blank = 'Select Name'} How can I add a new value to this dropdown list through the application. Is there a provision to directly add value to the list? Thanks

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  • Explain this SQL query in plain English.

    - by Kevinniceguy
    Please explain, in plain English, what question this SQL query answers: SELECT SUM(price) FROM Room r, Hotel h WHERE r.hotelNo = h.hotelNo and hotelName = 'Paris Hilton' and roomNo NOT IN (SELECT roomNo FROM Booking b, Hotel h WHERE (dateFrom <= CURRENT_DATE AND dateTo >= CURRENT_DATE) AND b.hotelNo = h.hotelNo AND hotelName = 'Paris Hilton');

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  • How to replace a region in emacs with yank buffer contents?

    - by Mad Wombat
    When I use VIM or most modeless editors (Eclipse, NetBeans etc.) I frequently do the following. If I have similar text blocks and I need to change them all, I will change one, copy it (or use non-deleting yank), select next block I need and paste the changed version over it. If I do the same thing in emacs (select region and paste with C-y), it doesn't replace the region, it just pastes at the cursor position. What is the way to do this in emacs?

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  • Mysql Avg function for recent 15 records by date (order date desc) in every symbol

    - by venkatesh
    i am trying to create a statement in sql (for a table which holds stock symbols and price on specified date) with avg of 5 day price and avg of 15 days price for each symbol. table description: symbol open high close date the average price is calculated from last 5 days and last 15 days. i tried this for getting 1 symbol: SELECT avg(close), avg(`trd_qty`) FROM (select * from cashmarket WHERE symbol = \'hdil\' order by `M_day` desc limit 0,15 ) s ...but I couldn't get the desired the list for showing avg values for all symbols.

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  • SQL Server: How to get a subitem of sp_helplanguage ?

    - by Quandary
    Question: I can get the SQL Server database language by querying: SELECT @@language And I can get further info via EXEC sp_helplanguage How can I query for a column of sp_helplanguage where name= @@language I do SELECT * FROM sp_helplanguage WHERE name='DEUTSCH' but that obviously doesn't work. What's the correct way to query it ?

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  • How can i get the seed value of an identity column in MySql

    - by mmcdonald
    To get the seed and step values of an identity column in sql server i can use this syntax SELECT ColumnName = name, Seed = seed_value, Step = increment_value FROM sys.identity_columns So far in MySql i have found that if i use this syntax SELECT * FROM INFORMATION_SCHEMA.TABLES WHERE auto_increment IS NOT NULL I can at least find out which columns are an identity... The question being how can i get the SEED and STEP values of the identity column from the MySQL Schema.

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  • Exporting collections

    - by Ruslan
    Hi, have select like select trn_dt,collect(ac_no) from transactions where rownum < 1000 group by trn_dt i'm doing it in SQL Navigator. But i can't export results! Table collect(ac_no) is not exported. Is there any way out?

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  • SQL Timstamp Function

    - by harrison
    Is there any difference between these two queries? select * from tbl where ts < '9999-12-31-24.00.00.000000'; and select * from tbl where ts < timestamp('9999-12-31-24.00.00.000000'); When is the timestamp function required? Is there a difference in performance?

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  • How can you access two identically-named columns in a MySQL LEFT JOIN query?

    - by George Edison
    I have two tables. table_x: id INT(11) tag INT(11) table_tags: id INT(11) name VARCHAR(255) Then I use PHP to perform the following query: SELECT * FROM table_x LEFT JOIN table_tags ON table_x.tag = table_tags.id The only problem is: how do I access table_x.id and table_tags.id in the results? Here is the PHP code: $query = "SELECT * FROM table_x LEFT JOIN table_tags ON table_x.tag = table_tags.id"; $results = mysql_query($query); while($row = mysql_fetch_array($results)) { // how do I now access table_x.id and table_tags.id ??? }

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  • MySQL specifying exact order with WHERE `id` IN (...)

    - by Gray Fox
    Is there an easy way to order MySQL results respectively by WHERE id IN (...) clause? Example: SELECT * FROM articles WHERE articles.id IN (4, 2, 5, 9, 3) to return Article with id = 4 Article with id = 2 Article with id = 5 Article with id = 9 Article with id = 3 and also SELECT * FROM articles WHERE articles.id IN (4, 2, 5, 9, 3) LIMIT 2,2 to return Article with id = 5 Article with id = 9

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  • MYSQL if statement question...

    - by Dennis_M
    Is there any way to get the if statement to evaluate a query? SELECT if(50,'EQ_Type','*') FROM EQUIPMENT; Resulting in: +-----------------------+ | IF(50,'EQ_Type','*') | +-----------------------+ | EQ_Type | | EQ_Type | | EQ_Type | | EQ_Type | | EQ_Type | | EQ_Type | | EQ_Type | | EQ_Type | | EQ_Type | +-----------------------+ 9 rows in set (0.00 sec) I would like the above statement to be equivalent to the following: SELECT 'EQ_Type' FROM EQUIPMENT; And produce: +--------------+ | EQ_Type | +--------------+ | ENGINE | | ENGINE | | ENGINE | | TRAILER | | TRAILER | | TRAILER | | WATER TENDER | | WATER TENDER | | WATER TENDER | +--------------+ Thanks for any help

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