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  • filter queryset based on list, including None

    - by jujule
    Hi all I dont know if its a django bug or a feature but i have a strange ORM behaviour with MySQL. class Status(models.Model): name = models.CharField(max_length = 50) class Article(models.Model) status = models.ForeignKey(status, blank = True, null=True) filters = Q(status__in =[0, 1,2] ) | Q(status=None) items = Article.objects.filter(filters) this returns Article items but some have other status than requested [0,1,2,None] looking at the sql query : SELECT [..] FROM `app_article` LEFT OUTER JOIN `app_status` ON (`app_article`.`status_id` = `app_status`.`id`) WHERE (`app_article`.`status_id` IN (1, 2) OR `app_status`.`id` IS NULL) ORDER BY [...] the OR app_status.id IS NULL part seems to be the cause. if i change it to OR app_article.status_id IS NULL it works correctly. How to deal with this ? Thanx.

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  • File mode for creating+reading+appending+binary

    - by MihaiD
    I need to open a file for reading and writing. If the file is not found, it should be created. It should also be treated as a binary for Windows. Can you tell me the file mode sequence I need to use for this? I tried 'r+ab' but that doesn't create the files if they are not found. Thanks

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  • Psycopg2 doesn't like table names that start with a lower case letter

    - by Count Boxer
    I am running ActiveState's ActivePython 2.6.5.12 and PostgreSQL 9.0 Beta 1 under Windows XP. If I create a table with an upper case first letter (i.e. Books), psycopg2 returns the "Programming Error: relation "books" does not exist" error message when I run the select statement: execute("SELECT * FROM Books"). The same error is returned if I run: execute("SELECT * FROM books"). However, if I change the table to a lower case first name (i.e. books), then either of the above statements works. Are tables name supposed to have a lower case first name? Is this a setting or a feature or a bug? Am I missing something obvious?

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  • Writing a unique identifier to script?

    - by dannycab
    I'd like to write a subscript that adds a unique identifier (machine time) to a script everytime that it runs. However, each time I edit the script (in IDLE) the indetifiers are over-written. Is there a elegant way of doing this. The script that I wrote appears below. import os, time f = open('sys_time_append.py','r') lines = f.readlines() f.close() fout = open('sys_time_append.py','w') for thisline in lines: fout.write(thisline) fout.write('\n#'+str(time.time())+' s r\n') fout.close() Thanks for any help.

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  • "UserWarning: Unbuilt egg for setuptools" - What does this actually mean?

    - by Wolo
    Hiya. When I install things into a virtualenv using pip I often see the message "UserWarning: Unbuilt egg for setuptools". I always safely ignore it and go about my business and it doesn't seem to cause me any problems. But I've suddenly been smacked in the face with curiosity, and wondered if someone could explain what it means, exactly? Also, does the new virtualenv option to use distribute instead fit into all this somewhere? Should I be using that instead, or just ignoring it until distutils2 comes out? (apologies if that's totally unrelated - maybe it should be a new question?) Thanks!

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  • Can I override a query in DJango?

    - by stinkypyper
    I know you can override delete and save methods in DJango models, but can you override a select query somehow to intercept and change a parameter slightly. I have a hashed value I want to check for, and would like to keep the hashing internal to the model.

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  • How can I retrieve all the returned variables from a function?

    - by user1447941
    import random def some_function(): example = random.randint(0, 1) if example == 1: other_example = 2 else: return False return example, other_example With this example, there is a chance that either one or two variables will be returned. Usually, for one variable I'd use var = some_function() while for two, var, var2 = some_function(). How can I tell how many variables are being returned by the function?

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  • Mechanize Submit Form Error: Insufficient items with name '10427'

    - by maneh
    I'm trying to submit a form with Mechanize, I have tried different ways, but the problem persists. Can anyone help me on this. Thank you in advance! This is the form I want to submit: http://www.stpairways.st/ This is the code that I'm using: def stp_airways(url): import re import mechanize br = mechanize.Browser() br.open(url) print br.title() br.select_form(name = "frmbook") br.form['TypeTrajet'] = ["1"] br.form['id_depart'] = ["11967"] br.form['id_arrivee'] = ["10427"] br.form['txtDateAller'] = "5/7/2014" br.form['txtDateRetour'] = "12/7/2014" br.form['TypePassager1u1000r0b1'] = ["1"] br.form['TypePassager2u1000r0b1'] = ["0"] br.form['TypePassager3u1000r0b1'] = ["0"] br.form['CodeIsoDeviseClient'] = ["17,20,23,24,25,26,27,28,29,30,31,33,34,36,37,64,65,67,68,70,73,80,81,95,96,103,147,151,152,159,160,162,169,170TP1TPF"] br.form['CodeIsoDeviseClient'] = ["EUR"] # submit response1 = br.submit() print response1.read()

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  • Praw (Redditt API) How to retrieve replies to a comment past 10 levels deep

    - by jpreed00
    Ok, so I've written some code that, for all intents and purposes, should work: def checkComments(comments): for comment in comments: print comment.body checkComments(comment.replies) def processSub(sub): sub.replace_more_comments(limit=None, threshold=0) checkComments(sub.comments) #login and subreddit init stuff here subs = mysubreddit.get_hot(limit=50) for sub in subs: processSub(sub) However, given a submission that has 50 nested replies like so: root comment -> 1st reply -> 2nd reply -> 3rd reply ... -> 50th reply The above code only prints: root comment 1st reply 2nd reply 3rd reply 4th reply 5th reply 6th reply 7th reply 8th reply 9th reply Any idea how I can get the remaining 41 levels of replies? Or is this a praw limitation?

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  • Problem with validating ModelForm

    - by user561640
    I use ModelForm to create my form. All works fine except 1 thing - validating the unique field. Code: class Article(models.Model): ... title = models.CharField(max_length=255, unique=True, error_messages={'max_length' : 'max translation', 'unique' : 'unique translation', 'required' : 'req translation',}) ... class ArticleForm(ModelForm): ... title = forms.CharField(max_length=255, min_length=3, error_messages={'required' : 'req translation', 'min_length' : 'min translation', 'max_length' : 'max translation', 'unique' : 'unique translation',}) But when I save my form with non-unique title I don't get my custom translated error but I get default error. How to fix it, that my unique field error is displayed?

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  • Stopping long-running requests in Pylons

    - by Jack
    I'm working on an application using Pylons and I was wondering if there was a way to make sure it doesn't spend way too much time handling one request. That is, I would like to find a way to put a timer on each request such that when too much time elapses, the request just stops (and possibly returns some kind of error). The application is supposed to allow users to run some complex calculations but I would like to make sure that if a calculation starts taking too much time, we stop it to allow other calculations to take place.

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  • Pygame's Message-multiple lines?

    - by Jam
    I am using pygame and livewires (though I don't think that part is relevant here) to create a game. I've got the game working, but I'm trying to make something akin to a title screen before the game starts. However, it doesn't recognize when I try to make a new line appear. Here is what I have: begin_message=games.Message(value=""" Destroy the Bricks!\n In this game, you control a paddle,\n controlled by your mouse,\n and attempt to destroy all the rows of bricks.\n Careful though, you only have 1 life.\n Don't mess up! The game will start in\n 5 seconds.""", size=30, x=games.screen.width/2, y=games.screen.height/2, lifetime=500, color=color.white, is_collideable=False) games.screen.add(begin_message) The message appears on the screen, but the newline doesn't happen, so I can only read the first part of the message. Is there a way to make this message actually appear, or can I not use the 'Message' for this?

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  • Amazon S3 permissions

    - by Joe
    Trying to understand S3...How do you limit access to a file you upload to S3? For example, from a web application, each user has files they can upload, but how do you limit access so only that user has access to that file? It seems like the query string authentication requires an expiration date and that won't work for me, is there another way to do this?

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  • How do I make a defaultdict safe for unexpecting clients?

    - by ~miki4242
    Several times (even several in a row) I've been bitten by the defaultdict bug. d = defaultdict(list) ... try: v = d["key"] except KeyError: print "Sorry, no dice!" For those who have been bitten too, the problem is evident: when d has no key 'key', the v = d["key"] magically creates an empty list and assigns it to both d["key"] and v instead of raising an exception. Which can be quite a pain to track down if d comes from some module whose details one doesn't remember very well. I'm looking for a way to take the sting out of this bug. For me, the best solution would be to somehow disable a defaultdict's magic before returning it to the client.

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  • index error:list out of range

    - by kaushik
    from string import Template from string import Formatter import pickle f=open("C:/begpython/text2.txt",'r') p='C:/begpython/text2.txt' f1=open("C:/begpython/text3.txt",'w') m=[] i=0 k='a' while k is not '': k=f.readline() mi=k.split(' ') m=m+[mi] i=i+1 print m[1] f1.write(str(m[3])) f1.write(str(m[4])) x=[] j=0 while j<i: k=j-1 l=j+1 if j==0 or j==i: j=j+1 else: xj=[] xj=xj+[j] xj=xj+[m[j][2]] xj=xj+[m[k][2]] xj=xj+[m[l][2]] xj=xj+[p] x=x+[xj] j=j+1 f1.write(','.join(x)) f.close() f1.close() It say line 33,xj=xj+m[l][2] has index error,list out of range please help thanks in advance

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  • How to detect a sign change for elements in a numpy array

    - by cb160
    I have a numpy array with positive and negative values in. a = array([1,1,-1,-2,-3,4,5]) I want to create another array which contains a value at each index where a sign change occurs (For example, if the current element is positive and the previous element is negative and vice versa). For the array above, I would expect to get the following result array([0,0,1,0,0,1,0]) Alternatively, a list of the positions in the array where the sign changes occur or list of booleans instead of 0's and 1's is fine.

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  • why my code show messy code ..

    - by zjm1126
    class sss(webapp.RequestHandler): def get(self): url = "http://www.google.com/" result = urlfetch.fetch(url) if result.status_code == 200: self.response.out.write(result.content) and this view show : when i change code to this: if result.status_code == 200: self.response.out.write(result.content.decode('utf-8').encode('gb2312')) it show : so ,what i should do ? thanks

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  • Sqlalchemy: Many to Many relationship error

    - by 1001010101
    Dear everyone, I am following the Many to many relationship described on http://www.sqlalchemy.org/docs/mappers.html#many-to-many #This is actually a VIEW tb_mapping_uGroups_uProducts = Table( 'mapping_uGroups_uProducts', metadata, Column('upID', Integer, ForeignKey('uProductsInfo.upID')), Column('ugID', Integer, ForeignKey('uGroupsInfo.ugID')) ) tb_uProducts = Table( 'uProductsInfo', metadata, Column('upID', Integer, primary_key=True) ) mapper( UnifiedProduct, tb_uProducts) tb_uGroupsInfo = Table( 'uGroupsInfo', metadata, Column('ugID', Integer, primary_key=True) ) mapper( UnifiedGroup, tb_uGroupsInfo, properties={ 'unifiedProducts': relation(UnifiedProduct, secondary=tb_mapping_uGroups_uProducts, backref="unifiedGroups") }) where the relationship between uProduct and uGroup are N:M. When I run the following sess.query(UnifiedProduct).join(UnifiedGroup).distinct()[:10] I am getting the error: sqlalchemy.exc.ArgumentError: Can't find any foreign key relationships between 'uProductsInfo' and 'uGroupsInfo' What am I doing wrong?

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  • Updating a module level shared dictionary

    - by Vishal
    Hi, A module level dictionary 'd' and is accessed by different threads/requests in a django web application. I need to update 'd' every minute with a new data and the process takes about 5 seconds. What could be best solution where I want the users to get either the old value or the new value of d and nothing in between. I can think of a solution where a temp dictionary is constructed with a new data and assigned to 'd' but not sure how this works! Appreciate your ideas. Thanks

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  • Checkboxes with pylons

    - by user268746
    Hello, I have been trying to add some check boxes in a pylons mako. However I don't know how to get their values in the controller. It seems that it can only get the first value of the check boxes. I tried using form encode but i got several errors. Is there an easier way to do this? Thanks

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  • Returning all "positions" of a list

    - by Daymor
    I Have a list with "a" and "b" and the "b"'s are somewhat of a path and "a"'s are walls. Im writing a program to make a graph of all the possible moves. I got the code running to check the first "b" for possible moves, but i have NO Idea how im going to find all "b"'s , even less check them all without repeating. Major issue im having is getting the tuple coordinates of the "b"'s out of the list. Any pointers/tips?

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