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  • How Can I Join Two DB Tables and Return Lowest Price From Joined Table

    - by Jason
    I have two tables, the first table has the product and the second table the prices. The price table could have more than one price per product but I only want to display the lowest. But I keep getting all the prices returned and I'm having trouble figuring out how to do it. this is what I get returned in my query: SELECT * FROM products AS pr JOIN prices AS p ON pr.id = p.product_id WHERE pr.live = 1 AND p.live = 1 id product1 name description £100 id product1 name description £300 id product1 name description £200 id product2 name description £50 id product2 name description £80 id product2 name description £60 id product3 name description £222 id product3 name description £234 id product3 name description £235 but I'm after: id product1 name description £100 id product2 name description £50 id product3 name description £222 Any help would be appreciated

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  • Echoing users by group name in PHP

    - by BobSapp
    What I want to do is click a name of a group(every group what I create other than poweruser and admin groups) and that will echo all of the users in that group from the database. I have figured out the code so far but now my problem is how will I print it all out when clicking the name of the group? My code so far is: <h3>Groups</h3> <?php include('db.php'); if (isset($_GET["groupID"])) { $sql="SELECT `group`.*, `user`.* FROM `user` inner join `group` on group.groupID=user.groupID where group.groupID= " . mysql_real_escape_string($_GET["groupID"]) ; } else { $sql="SELECT * FROM `group` WHERE groupName <> 'admin' AND groupName <> 'poweruser'" ; } $result=mysql_query($sql,$connection); while($line=mysql_fetch_array($result)){ echo "<a href='index.php?page=groups&group=".$line['groupID']."'>".$line['groupName'].'</a><br />'; } mysql_free_result($result); mysql_close($connection); ?>

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  • sql query need a help.

    - by benjamin button
    If i have a table with two fields.customer id and order. let's say i have in total order ID 1,2,3,4 all the customer can have all the four orders.like below 1234 1 1234 2 1234 3 1234 4 3245 3 3245 4 5436 2 5436 4 you can see above that 3245 customer doesnt have order id 1 and 2. how could i print in the query output like 3245 1 3245 2 5436 1 5436 3 EDIT: i dont order table but i have list of order's like we can hard code it in the query(1,2,3,4) i dont have an orders table.

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  • Average over a timeframe with missing data

    - by BHare
    Assuming a table such as: UID Name Datetime Users 4 Room 4 2012-08-03 14:00:00 3 2 Room 2 2012-08-03 14:00:00 3 3 Room 3 2012-08-03 14:00:00 1 1 Room 1 2012-08-03 14:00:00 2 3 Room 3 2012-08-03 14:15:00 1 2 Room 2 2012-08-03 14:15:00 4 1 Room 1 2012-08-03 14:15:00 3 1 Room 1 2012-08-03 14:30:00 6 1 Room 1 2012-08-03 14:45:00 3 2 Room 2 2012-08-03 14:45:00 7 3 Room 3 2012-08-03 14:45:00 8 4 Room 4 2012-08-03 14:45:00 4 I wanted to get the average user count of each room (1,2,3,4) from the time 2PM to 3PM. The problem is that sometimes the room may not "check in" at the 15 minute interval time, so the assumption has to be made that the previous last known user count is still valid. For example the check-in's for 2012-08-03 14:15:00 room 4 never checked in, so it must be assumed that room 4 had 3 users at 2012-08-03 14:15:00 because that is what it had at 2012-08-03 14:00:00 This follows on through so that the average user count I am looking for is as follows: Room 1: (2 + 3 + 6 + 3) / 4 = 3.5 Room 2: (3 + 4 + 4 + 7) / 4 = 4.5 Room 3: (1 + 1 + 1 + 8) / 4 = 2.75 Room 4: (3 + 3 + 3 + 4) / 4 = 3.25 where # is the assumed number based on the previous known check-in. I am wondering if it's possible to so this with SQL alone? if not I am curious of a ingenious PHP solution that isn't just bruteforce math, as such as my quick inaccurate pseudo code: foreach ($rooms_id_array as $room_id) { $SQL = "SELECT * FROM `table` WHERE (`UID` == $room_id && `Datetime` >= 2012-08-03 14:00:00 && `Datetime` <= 2012-08-03 15:00:00)"; $result = query($SQL); if ( count($result) < 4 ) { // go through each date and find what is missing, and then go to previous date and use that instead } else { foreach ($result) $sum += $result; $avg = $sum / 4; } }

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  • Pagination links do not work after first page

    - by TheStack
    Hello, I am trying to fix this pagination script. It seems when I click on the pagination links [1][2][3][4]or[5] , it doesn't work. It just shows the first page and when clicking on the next numbers nothing happens. I hoping someone can see something in the script that I can not see. The main page looks like this (pagination.php): <?php include_once('generate_pagination.php'); ?> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script> <script type="text/javascript" src="jquery_pagination.js"></script> <div id="loading" ></div> <div id="content" data-page="1"></div> <ul id="pagination"> <?php generate_pagination() ?> </ul> <br /> <br /> <a href="#" class="category" id="marketing">Marketing</a> <a href="#" class="category" id="automotive">Automotive</a> <a href="#" class="category" id="sports">Sports</a> Then, generate_pagination.php: <?php function generate_pagination($sql) { include_once('config.php'); $per_page = 3; //Calculating no of pages $result = mysql_query($sql); $count = mysql_fetch_row($result); $pages = ceil($count[0]/$per_page); //Pagination Numbers for($i=1; $i<=$pages; $i++) { echo '<li class="page_numbers" id="'.$i.'">'.$i.'</li>'; } } $ids=$_GET['ids']; generate_pagination("SELECT COUNT(*) FROM explore WHERE category='$ids'"); ?> Here is the jquery file (jquery_pagination.js): $(document).ready(function(){ //Display Loading Image function Display_Load() { $("#loading").fadeIn(900,0); $("#loading").html("<img src='bigLoader.gif' />"); } //Hide Loading Image function Hide_Load() { $("#loading").fadeOut('slow'); }; //Default Starting Page Results $("#pagination li:first").css({'color' : '#FF0084'}).css({'border' : 'none'}); Display_Load(); $("#content").load("pagination_data.php?page=1", Hide_Load()); //Pagination Click $("#pagination li").click(function(){ Display_Load(); //CSS Styles $("#pagination li") .css({'border' : 'solid #dddddd 1px'}) .css({'color' : '#0063DC'}); $(this) .css({'color' : '#FF0084'}) .css({'border' : 'none'}); //Loading Data var pageNum = this.id; $("#content").load("pagination_data.php?page=" + pageNum, function(){ Hide_Load(); $(this).attr('data-page', pageNum); }); }); // Editing below. // Sort content Marketing $("a.category").click(function() { Display_Load(); var this_id = $(this).attr('id'); $.get("pagination.php", { category: this.id }, function(data){ //Load your results into the page var pageNum = $('#content').attr('data-page'); $("#pagination").load('generate_pagination.php?category=' + pageNum +'&ids='+ this_id ); $("#content").load("filter_marketing.php?page=" + pageNum +'&id='+ this_id, Hide_Load()); }); }); }); Lastly, filter_marketing.php (when a user clicks the filter link buttons): <?php include('config.php'); $per_page = 3; if(count($_GET)>0) { if($_GET['page']!=''){ $page=$_GET['page']; } if($_GET['id']!=''){ $id=$_GET['id']; } } $page= ($_GET['page']!='') ? $_GET['page']: false; $id= ($_GET['id']!='') ? $_GET['id']: false; $start = ($page-1)*$per_page; if($page && $id){ $sql = "SELECT * FROM explore WHERE category='$id' ORDER BY category LIMIT $start,$per_page"; } else { die('Error: missing parameters. Id= '.$id.' and page= '.$page); } $result = mysql_query($sql); ?> <table width="800px"> <?php while($row = mysql_fetch_array($result)) { $msg_id=$row['id']; $message=$row['site_description']; $site_price=$row['site_price']; ?> <tr> <td><?php echo $msg_id; ?></td> <td><?php echo $message; ?></td> <td><?php echo $site_price; ?></td> </tr> <?php } ?> </table> So, if anyone sees where the problem is occurring and can help rid of the problem, that would be great, Thank you.

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  • Want to calculate the sum of the count rendered by group by option..

    - by Vijay
    i have a table with the columns such id, tid, companyid, ttype etc.. the id may be same for many companyid but unique within the companyid and tid is always unique and i want to calculate the total no of transactions entered in the table, a single transaction may be inserted in more than one row, for example, id tid companyid ttype 1 1 1 xxx 1 2 1 may be null 2 3 1 yyy 2 4 1 may be null 2 5 1 may be null the above entries should be counted as only 2 transactions .. it may be repeated for many companyids.. so how do i calculate the total no of transactions entered in the table i tried select sum(count(*)) from transaction group by id,companyId; but doesn't work select count(*) from transaction group by id; wont work because the id may be repeated for different companyids.

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  • php database image show problem

    - by Termedi
    here is the code <?php session_start(); if(!isset($_SESSION['user_name'])) { header('Location: login.php'); } $conn = mysql_connect("localhost", "root", "") or die("Can no connect to Database Server"); ?> <html> <head> </head> <body> <center> <div id="ser"> <form action="" method="post"> <label for="file">Card No:</label> <input type="text" name="card_no" id="card_no" class="fil" onKeyUp="CardNoLength()" onKeyDown="CardNoLength()" onKeyPress="CardNoLength()"/> <input type="submit" name="search" value="Search" class="btn" onClick="return CardNoLengthMIN()"/> </form> </div> </center> <br/><hr style="border: 1px solid #606060 ;" /> <center><a href="index.php">Home</a></center> <br/> <center> <?php if(isset($_POST['card_no'])) { if($conn) { if(mysql_select_db("img_mgmt", $conn)) { $sql = "select * from temp_images where card_no='".trim($_POST['card_no'])."'"; $result = mysql_query($sql); $image = mysql_fetch_array($result); if(isset($image['card_no'])) { //echo "<img src=\"".$image['file_path']."\" alt=\"".$image['card_no']."\" width=\"250\" height=\"280\"/>"; header("Content-type: image/jpeg"); echo $image['img_content']; } else { echo "<p style=\"color:red;\">Sorry, Your search came with no results ! <br/> Try with different card number"; } } else { echo "Database selection error: ".mysql_error(); } } else { echo "Could not connect: ".mysql_error(); } } ?> </center> </body> </html> But it after executing the script it shows: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\img\search.php:61) in C:\xampp\htdocs\img\search.php on line 77

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  • How do I create a user history?

    - by ggfan
    I want to create a user history function that allows shows users what they done. ex: commented on an ad, posted an ad, voted on an ad, etc. How exactly do I do this? I was thinking about... in my site, when they log in it stores their user_id ($_SESSION['user_id']) so I guess whenever an user posts an ad(postad.php), comments(comment.php), I would just store in a database table "userhistory" what they did based on whenever or not their user_id was activate. When they comment, I store the user_id in the comment dbc table, so I'll also store it in the "userhistory" table. And then I would just queries all the rows in the dbc for the user to show it Any steps/improvements I can make? :)

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  • Database normalization and duplicate values

    - by bretddog
    Consider a Parent / Child / GrandChild structure in a database table schema, or even a deeper hierarchy. These being in the same aggregate. One table DAYS keeps a single row per day, and has a "Date" field. This is the root table, or maybe a child of the root. No row can ever be deleted in this table. In this case, however complex my table schema looks like, however far away in the hierarchy any other table is, is there any reason why any other table would hold a Date value? Can't it instead just have a FK to the DAYS table. I obviously assume that the creation of these date fields happen not before such datefield exist in the DAYS table. I'm now thinking just about the date part to be relevant, not the time part. Not sure if all databases can store these individually. That's maybe relevant, but not really the focus of the question.

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  • Explain this SQL query in plain English.

    - by Kevinniceguy
    Please explain, in plain English, what question this SQL query answers: SELECT SUM(price) FROM Room r, Hotel h WHERE r.hotelNo = h.hotelNo and hotelName = 'Paris Hilton' and roomNo NOT IN (SELECT roomNo FROM Booking b, Hotel h WHERE (dateFrom <= CURRENT_DATE AND dateTo >= CURRENT_DATE) AND b.hotelNo = h.hotelNo AND hotelName = 'Paris Hilton');

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  • Get category count for a category where only the child categories have products

    - by Matthew
    I'm having problems getting a count for a category collection that will include products in any of that categories children. However I don't want just a full count I want to filter that count by a product collection (so only include products in the count that appear in the product collection)... Any suggestions? Code to get a filtered product collection (filtered by a multiselect attribute) /** @var $attribute Mage_Eav_Model_Entity_Attribute */ $valuesCollection = Mage::getResourceModel('eav/entity_attribute_option_collection') ->setAttributeFilter($attribute->getId()) ->addFieldToFilter('value', array ('like' => $make)) ->addFieldToSelect('option_id') ->setStoreFilter(0, false); $set = array(); foreach($valuesCollection as $option){ $set[] = $option->getData('option_id'); } $_productCollection = Mage::getResourceModel('catalog/product_collection') ->addAttributeToFilter('sparex_makemodel', array('in' => $set ) ) ->addAttributeToSelect('*'); I'm getting the child categories for a given category like thus.. $childCats = Mage::getModel('catalog/category')->load(2)->getChildrenCategories(); Now none of these categories have products assigned to them, however their children (or children of children) do. I want to produce a count for these categories that includes the child categories but only where the products are in my filtered collection.

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  • Best datastructure for this relationship...

    - by Travis
    I have a question about database 'style'. I need a method of storing user accounts. Some users "own" other user accounts (sub-accounts). However not all user accounts are owned, just some. Is it best to represent this using a table structure like so... TABLE accounts ( ID ownerID -> ID name ) ...even though there will be some NULL values in the ownerID column for accounts that do not have an owner. Or would it be stylistically preferable to have two tables, like so. TABLE accounts ( ID name ) TABLE ownedAccounts ( accountID -> accounts(ID) ownerID -> accounts(ID) ) Thanks for the advice.

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  • Select multi-select form from array

    - by Budove
    Here's the issue. I have a database column called pymnt_meth_pref, which contains a comma separated string of payment methods chosen from a multiselect form. <td>Payment Methods Used:<br /> <input type="checkbox" name="pyment_meth_pref[]" value="Cash">I can pay with cash.<br /> <input type="checkbox" name="pyment_meth_pref[]" value="Check">I can pay by check.<br /> <input type="checkbox" name="pyment_meth_pref[]" value="Credit Card">I can pay by credit card.<br /> <input type="checkbox" name="pyment_meth_pref[]" value="Paypal">I can pay with Paypal.<br /> </td> This array is posted to a variable and turned into a comma separated string if (isset($_POST['pyment_meth_pref'])) $pymntmethpref = implode(", ", $_POST['pyment_meth_pref']); if (isset($_POST['pyment_meth_acc'])) $pymntmethacc = implode(", ", $_POST['pyment_meth_acc']); This is then inserted into the database as a comma separated string. What I would like to do, is take this string and apply the values to the original form when the user goes back to the form as 'pre-selected' checkboxes, indicated that the user has already selected those values previously, and keeping those values in the database if they choose to edit any other information in the form. I'm assuming this would need to be done with javascript but if there is a way to do it with PHP I'd rather do it that way.

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  • server performance: multiple external connections and performance

    - by websiteguru
    I am creating a php script that requires the server to make several cURL requests per run. I'll be running this script through cron every 3 minutes. Im looking to maximize the amount of cURL requests I can make in a 24 hr period. What I am wondering is if it would be better from a performance standpoint to get a dedicated server, or several small shared hosting accounts. With the problem being number of external connections and not system resources I'm wondering which is the best approach.

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  • Select 2 Rows from Table when COUNT of another table

    - by Marcus
    Here is the code that I currently have: SELECT `A`.* FROM `A` LEFT JOIN `B` ON `A`.`A_id` = `B`.`value_1` WHERE `B`.`value_2` IS NULL AND `B`.`userid` IS NULL ORDER BY RAND() LIMIT 2 What it currently is supposed to do is select 2 rows from A when the 2 rows A_id being selected are not in value_1 or value_2 in B. And the rows in B are specific to individual users with userid. What I need to do is make it also so that also checks if there are already N rows in B matching a A_id (either in value_1, or value_2) and userid, and if there are more than N rows, it doesn't select the A row.

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  • Get the count of A -> B and B->A without duplicates

    - by TomGasson
    I have a table like so: index|from | to ------------------ 1 | ABC | DEF 2 | ABC | GHI 3 | ABC | GHI 4 | ABC | JKL 5 | ABC | JKL 6 | ABC | JKL 7 | DEF | ABC 8 | DEF | GHI 9 | DEF | JKL 10 | GHI | ABC 11 | GHI | ABC 12 | GHI | ABC 13 | JKL | DEF And I need to count how the total times between the points (regardless of direction) to get the result: A | B | count ----------------- ABC | DEF | 2 ABC | GHI | 5 ABC | JKL | 3 DEF | GHI | 1 DEF | JKL | 2 So far I can get: SELECT `a`.`from` as `A`, `a`.`to` as `B`, (`a`.`count` + `b`.`count`) as `count` FROM (SELECT `from`, `to`, count(*) as `count` FROM `table` GROUP BY 1,2) `a` LEFT OUTER JOIN (SELECT `from`,`to`, count(*) as `count` FROM `table` GROUP BY 1,2) `b` ON `a`.`from` = `b`.`to` AND `a`.`to` = `b`.`from` But I'm unsure how to remove the A/B swapped duplicates.

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  • LIMIT amount of rows fetched by JOIN

    - by user892134
    How do i LIMIT the child rows fetched to only 5? Here is the SQLfiddle http://sqlfiddle.com/#!2/bd96a/2. Right now it fetches all rows with parentid='4' and parentid='14'. It should only fetch 5 of each parentid. Assuming i have hundreds of rows, it should only fetch a max of 5 for each parentid. "SELECT child.* FROM mytable as parent LEFT JOIN mytable as child on child.parentid=parent.id WHERE parent.pageid IN ( 1, 2) AND parent.submittype='1' ORDER BY child.id ASC"; How do i solve this?

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  • Connecting PHP Server and Android?

    - by user3439988
    I am trying to create a simple test application to transfer data back and forth between my server and Android device. The following are the things I aim for: Ability to upload data and files to the server. To be able to view my files on the server. To be able to download the files from the server to my android device. Ability of the server to send me updates on the files or notifications to my phone. I need a safe and secure way to do these things. I have tried these: HTTPPost requests onto the server and echoing the output accordingly and capturing the HTTPresponse and parsing it. For files I have tried using MultipartEntity, but I think that has been deprecated.

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  • How to refresh site if $_SESSION variable has changed

    - by 4ndro1d
    I'm writing in my $_SESSION variable from a database, when i clicked a link. public function getProjectById($id){ $query="SELECT * FROM projects WHERE id=\"$id\""; $result=mysql_query($query); $num=mysql_numrows($result); while ($row = mysql_fetch_object($result)) { $_SESSION['projectid'] = $row->id; $_SESSION['projecttitle'] = $row->title; $_SESSION['projectinfo'] = $row->info; $_SESSION['projecttext'] = $row->text; $_SESSION['projectcategory'] = $row->category; } } Now my variable is overwritten and I want to show these variables in my index.php like this: <div id="textContent"> <?php if(isset($_SESSION['projecttext']) && !empty($_SESSION['projecttext'])) { echo $_SESSION['projecttext']; }else { echo 'No text'; } ?></div> But of course, my page will not refresh automatically. How can I do that?

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