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  • In Node.js, how can I load my modules once and then use them throughout the app?

    - by TIMEX
    I want to create one global module file, and then have all my files require that global module file. Inside that file, I would load all the modules once and export a dictionary of loaded modules. How can I do that? I actually tried creating this file...and every time I require('global_modules'), all the modules kept reloading. It's O(n). I want the file to be something like this (but it doesn't work): //global_modules.js - only load these one time var modules = { account_controller: '/account/controller.js', account_middleware: '/account/middleware.js', products_controller: '/products/controller.js', ... } exports.modules = modules;

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  • Can't unwrap Optional.None tableviewcell

    - by Mathew Padley
    I've a table view that has a custom table view cell in it. My problem is that when i try and assign a value to a variable in the custom table view cell I get the stated error. Now, I think its because the said variable is not initialised, but its got me completely stumped. This is the custom table cell: import Foundation import UIKit class LocationGeographyTableViewCell: UITableViewCell { //@IBOutlet var Map : MKMapView; @IBOutlet var AddressLine1 : UILabel; @IBOutlet var AddressLine2 : UILabel; @IBOutlet var County : UILabel; @IBOutlet var Postcode : UILabel; @IBOutlet var Telephone : UILabel; var location = VisitedLocation(); func Build(location:VisitedLocation) -> Void { self.location = location; AddressLine1.text = "test"; } } My cell for row at index path is: override func tableView(tableView: UITableView!, cellForRowAtIndexPath indexPath: NSIndexPath!) -> UITableViewCell! { var addressCell = tableView.dequeueReusableCellWithIdentifier("ContactDetail") as? LocationGeographyTableViewCell; if !addressCell { addressCell = LocationGeographyTableViewCell(style: UITableViewCellStyle.Value1, reuseIdentifier: "ContactDetail"); } addressCell!.Build(Location); return addressCell; } As I say I'm completely baffled, the Build function calls the correct function in the tableviewcell. Any help will be gratefully appreciated. Ta

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  • Using OAuth along with spring security, grails

    - by GroovyUser
    I have grails app which runs on the spring security plugin. It works with no problem. I wish I could give the users the way to connect with Facebook and social networking site. So I decided to use Spring Security OAuth plugin. I have configured the plugin. Now I want user can access both via normal local account and also the OAuth authentication. More precisely I have a controller like this: @Secured(['IS_AUTHENTICATED_FULLY']) def test() { render "Home page!!!" } Now I want this controller to be accessed with OAuth authentication too. Is that possible to do so?

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  • Apache and linux file permissions can't browse file or directories

    - by dardub
    I just copied my magento site over to a local server running CentOS 5.4. The browser said it can't locate the location of the stylesheets. The stylesheets are within /skin/frontend/my_new_interface/design2/css. I tried to view in the browser and I can't view any of the files within the css directory. I verified a million times that I'm typing in the correct location. I can view files within /skin/frontend/my_new_interface/design2. Can't browse directories within browser however. I typed in ls -l css and get: -rwxr-xr-x 1 apache apache listed for all the files I tried chmod -R 755 and the directories I changed the apache conf Options Indexes But still when I browse the directories I get Forbidden. However, in another fresh installation of magento in the same www dir, I am able to browse directories. As far as I can tell both installations have same ownership and permissions. I also tried find . -type f -exec chmod 644 {} \; find . -type d -exec chmod 755 {} \; which was recommended in the magento wiki I've just run out of ideas.

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  • UIAlertView Will not show

    - by John
    I have a program that is requesting a JSON string. I have created a class that contains the connect method below. When the root view is coming up, it does a request to this class and method to load up some data for the root view. When I test the error code (by changing the URL host to 127.0.0.1), I expect the Alert to show. Behavior is that the root view just goes black, and the app aborts with no alert. No errors in debug mode on the console, either. Any thoughts as to this behavior? I've been looking around for hints to this for hours to no avail. Thanks in advance for your help. Note: the conditional for (error) is called, as well as the UIAlertView code. - (NSString *)connect:(NSString *)urlString { NSString *jsonString; UIApplication *app = [UIApplication sharedApplication]; app.networkActivityIndicatorVisible = YES; NSError *error = nil; NSURLResponse *response = nil; NSURL *url = [[NSURL alloc] initWithString:urlString]; NSURLRequest *req = [NSURLRequest requestWithURL:url cachePolicy:NSURLRequestReloadIgnoringCacheData timeoutInterval:10]; NSData *_response = [NSURLConnection sendSynchronousRequest: req returningResponse: &response error: &error]; if (error) { /* inform the user that the connection failed */ //AlertWithMessage(@"Connection Failed!", message); UIAlertView *alert = [[UIAlertView alloc] initWithTitle:@"Oopsie!" message:@"Unable to connect! Try later, thanks." delegate:nil cancelButtonTitle:@"OK" otherButtonTitles: nil]; [alert show]; [alert release]; } else { jsonString = [[[NSString alloc] initWithData:_response encoding:NSUTF8StringEncoding] autorelease]; } app.networkActivityIndicatorVisible = NO; [url release]; return jsonString; }

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  • Make user object available to all Controllers in Zend?

    - by Sled
    Hey guys, I'm using Zend_Auth to identify a user in my application. This creates a session with the userobject. My question is how do I make this object available to every Controller and action, so I don't have to pull it out of the session every time I need data from this object? I'm guessing this should be done in bootstrap.php or index.php but I don't really know how to makte it available to every controller.. so any code examples would be appreciated! Thanks!

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  • [NHibernate and ASP.NET MVC] How can I implement a robust session-per-request pattern in my project,

    - by Guillaume Gervais
    I'm currently building an ASP.NET MVC project, with NHibernate as its persistance layer. For now, some functionnalities have been implemented, but only use local NHibernate sessions: each method that accessed the database (read or write) needs to instanciate its own NHibernate session, with the "using()" directive. The problem is that I want to leverage NHibernate's Lazy-Loading capabilities to improve the performance of my project. This implies an open NHibernate session per request until the view is rendered. Furthermore, simultaneous request must be supported (multiple Sessions at the same time). How can I achieve that as cleanly as possible? I searched the Web a little bit and learned about the session-per-request pattern. Most of the implementations I saw used some sort of Http* (HttpContext, etc.) object to store the session. Also, using the Application_BeginRequest/Application_EndRequest functions is complicated, since they get fired for each HTTP request (aspx files, css files, js files, etc.), when I only want to instanciate a session once per request. The concern that I have is that I don't want my views or controllers to have access to NHibernate sessions (or, more generally, NHibernate namespaces and code). That means that I do not want to handle sessions at the controller level nor the view one. I have a few options in mind. Which one seems the best ? Use interceptors (like in GRAILS) that get triggered before and after the controller action. These would open and close sessions/transactions. Is it possible in the ASP.NET MVC world? Use the CurrentSessionContext Singleton provided by NHibernate in a Web context. Using this page as an example, I think this is quite promising, but that still requires filters at the controller level. Use the HttpContext.Current.Items to store the request session. This, coupled with a few lines of code in Global.asax.cs, can easily provide me with a session on the request level. However, it means that dependencies will be injected between NHibernate and my views (HttpContext). Thank you very much!

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  • Searching for the right pattern to handle login data

    - by stevebot
    Hi all, I'm working on a controller that handles logins for a Web app. These logins will come from multiple clients but will all contain the same data. However, depending on the client, this data will be interpreted into common entities for our webapp differently. For instance, we have a user code that gets sent in, and in one case we may use the first four digits of the code, and in another case 12 digits of the code to map to a field on a User entity. Instead of handling this all in the controller and having big nasty if blocks of logic, I would like to use a pattern to handle how this information gets ingested into our application. What are your opinions?

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  • Can't call method in model table class using Doctrine with Zend Framework

    - by Jeremy Hicks
    I'm using Doctrine with Zend Framework. For my model, I'm using a base class, the regular class (which extends the base class), and a table class. In my table class, I've created a method which does a query for records with a specific value for one of the fields in my model. When I try and call this method from my controller, I get an error message saying, "Message: Unknown method Doctrine_Table::getCreditPurchases". Is there something else I need to do to call functions in my table class? Here is my code: class Model_CreditTable extends Doctrine_Table { /** * Returns an instance of this class. * * @return object Model_CreditTable */ public static function getInstance() { return Doctrine_Core::getTable('Model_Credit'); } public function getCreditPurchases($id) { $q = $this->createQuery('c') ->where('c.buyer_id = ?', $id); return $q->fetchArray(); } } // And then in my controller method I have... $this->view->credits = Doctrine_Core::getTable('Model_Credit')->getCreditPurchases($ns->id);

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  • rails link path and routing error

    - by Nick5a1
    <%= link_to t('.new', :default => t("helpers.links.new")), new_equipment_path, :class => 'btn btn-primary' %> I have the above code in a view, but am getting the following error when clicking the link: No route matches {:action=>"show", :controller=>"equipment"} My routes file contains: devise_for :users ActiveAdmin.routes(self) devise_for :admin_users, ActiveAdmin::Devise.config resources :equipment resources :workouts root :to => "home#index" match 'workouts/random', :to => 'workouts#random' match ':controller(/:action(/:id))(.:format)' Why is it trying to access the show action?

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  • Creating an Attribute to check for Exceptions

    - by BiffBaffBoff
    I'm creating an attribute so that whenever an exception occurs on my site, I'll receive an email detailing the exception. I've got so far but my Attribute code doesn't seem to fire if an exception occurs: public class ReportingAttribute : FilterAttribute, IExceptionFilter { public void OnException(ExceptionContext filterContext) { // This will generate an email to me ErrorReporting.GenerateEmail(filterContext.Exception); } } Then above my Controller I'm doing: [ReportingAttribute] public class AccountController : Controller The other way to do it is ofcourse putting ErrorReporting.GenerateEmail(ex) inside my catch blocks? There must be a simpler way? Thats why I thought of creating the Attribute to handle this

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  • jquery $.ajax not working in firefox against rails (406 response) (works in chrome & IE)

    - by phil swenson
    I have a rails backend and am testing the following jquery code against it: var content = $("#notification_content").val(); var data = new Object(); data.content = content; $.ajax({ url: "/notifications/detect_type.json", type:"POST", data: data, success: function(result ){updateTypeDropDown(result)}}); This code works fine in Chrome and IE. However in Firefox (using Firebug), I see this: http://localhost:3000/notifications/detect_type.json 406 Not Acceptable here is a chrome request in the log: Processing NotificationsController#detect_type (for 127.0.0.1 at 2010-12-21 17:05:59) [POST] Parameters: {"action"="detect_type", "content"="226 south emerson denver co 80209", "controller"="notifications"} User Columns (2.0ms) SHOW FIELDS FROM users User Load (37.4ms) SELECT * FROM users WHERE (users.id = '1') LIMIT 1 Completed in 58ms (View: 1, DB: 40) | 406 Not Acceptable [http://localhost/notifications/detect_type.json] here is a firefox request in the log: Processing NotificationsController#detect_type (for 127.0.0.1 at 2010-12-21 17:06:41) [POST] Parameters: {"action"="detect_type", "content"="226 south emerson 80209", "controller"="notifications"} User Columns (2.1ms) SHOW FIELDS FROM users User Load (30.4ms) SELECT * FROM users WHERE (users.id = '1') LIMIT 1 Completed in 100ms (View: 1, DB: 33) | 200 OK [http://localhost/notifications/detect_type.json] I'm stumped. Ideas?

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  • How to save checkbox checked values in Database

    - by user1298215
    How to save checkbox values in database. Below is my view code. @foreach (var item in Model) { @Html.CheckBox("statecheck", (IEnumerable<SelectListItem>)ViewData["StatesList"]) @Html.DisplayFor(modelItem => item.state_name) </br> } <input class="ASPbutton" type="submit" value="submit"/> Below is My controller. public ActionResult States() { ViewData["StatesList"] = new SelectList(am.FindUpcomingStates().ToList(), "state_id", "state_Name"); return View(); } My model is public IQueryable<state> FindUpcomingStates() { return from state in Adm.states orderby state.state_name select state; } After clicking submit button checked item state_id will be saved into database. I wrote like below in Controller, but i got true or false values, i want state_id [AcceptVerbs(HttpVerbs.Post)] public ActionResult States(string _stateName, char[] statecheck, FormCollection formvalues) { statecheck = Request.Form["statecheck"].ToArray(); ViewData["StatesList"] = new SelectList(am.FindUpcomingStates222().ToList(), "state_id", "state_id", _stateName); }

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  • Read from plist insted of Code array

    - by BoSoud
    Hi Guys am Using [URL="http://www.iphonesdkarticles.com/2009/01/uitableview-searching-table-view.html"]UITableView - Searching table view[/URL] its really nice easy tutorial but i really have bad time try to read from plist that what i did change - (void)viewDidLoad { [super viewDidLoad]; //Initialize the array. listOfItems = [[NSMutableArray alloc] init]; TableViewAppDelegate *AppDelegate = (TableViewAppDelegate *)[[UIApplication sharedApplication] delegate]; listOfItems = [AppDelegate.data objectForKey:@"Countries"]; //Initialize the copy array. copyListOfItems = [[NSMutableArray alloc] init]; //Set the title self.navigationItem.title = @"Countries"; //Add the search bar self.tableView.tableHeaderView = searchBar; searchBar.autocorrectionType = UITextAutocorrectionTypeNo; searching = NO; letUserSelectRow = YES; } and This How i read plist from My AppDelegate.m - (void)applicationDidFinishLaunching:(UIApplication *)application { NSString *Path = [[NSBundle mainBundle] bundlePath]; NSString *DataPath = [Path stringByAppendingPathComponent:@"Data.plist"]; NSDictionary *tempDict = [[NSDictionary alloc] initWithContentsOfFile:DataPath]; self.data = tempDict; [tempDict release]; // Configure and show the window [window addSubview:[navigationController view]]; [window makeKeyAndVisible]; } and this my plist <plist version="1.0"> <dict> <key>Countries</key> <array> <array> <string>USA</string> </array> <dict/> </array> </dict> </plist> and i get this error *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '*** -[NSCFArray objectForKey:]: unrecognized selector sent to instance 0x1809dc0' help please am stock with this

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  • Are @property's necessary for Interface Builder?

    - by Rits
    In my UIViewController subclass, I have 3 UIView's with each a @property as an IBOutlet. I do not use these properties at all in my code. The views get instantiated as soon as the view controller is created and they are deallocated when the view controller is deallocated. I was thinking; can't I just remove the @property's? I did, and I could still connect my instance variables (with IBOutlet) in Interface Builder. So my question now is; is there any use for properties in combination with Interface Builder, or is it OK to leave them out? Is it required for some memory management or something? Or are they really just for use in your own code? And if I do leave them out, do I still need to release them in dealloc?

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  • Play 2.0 javaToDo tutorial doesn't compile

    - by chsn
    I'm trying to follow the Play2.0 JavaToDO tutorial and for some reason it just doesn't want to work. Have looked through stackoverflow and other online resources, but haven't find an answer to this and it's driving me crazy. Attached code of the Application.java package controllers; import models.Task; import play.data.Form; import play.mvc.Controller; import play.mvc.Result; public class Application extends Controller { static Form<Task> taskForm = form(Task.class); public static Result index() { return redirect(routes.Application.tasks()); } public static Result tasks() { return ok( views.html.index.render(Task.all(), taskForm)); } public static Result newTask() { return TODO; } public static Result deleteTask(Long id) { return TODO; } } Attached code of the Task java package models; import java.util.List; import javax.persistence.Entity; import play.data.Form; import play.data.validation.Constraints.Required; import play.db.ebean.Model.Finder; import play.mvc.Result; import controllers.routes; @Entity public class Task { public Long id; @Required public String label; // search public static Finder<Long,Task> find = new Finder( Long.class, Task.class); // display tasks public static List<Task> all() { return find.all(); } // create task public static void create(Task task) { task.create(task); } // delete task public static void delete(Long id) { find.ref(id).delete(id); // find.ref(id).delete(); } // create new task public static Result newTask() { Form<Task> filledForm = taskForm.bindFromRequest(); if(filledForm.hasErrors()) { return badRequest( views.html.index.render(Task.all(), filledForm) ); } else { Task.create(filledForm.get()); return redirect(routes.Application.tasks()); } } } I get a compile error on Task.java on the line static Form<Task> taskForm = form(Task.class); As I'm working on eclipse (the project is eclipsified before import), it's telling me that taskForm cannot be resolved and it also underlines every play 2 command e.g. "render(), redirect(), bindFromRequest()" asking me to create a method for it. Any ideas how to solve the compilations error and also how to get Eclipse to recognize the play2 commands? EDIT: updated Application.java package controllers; import models.Task; import play.data.Form; import play.mvc.Controller; import play.mvc.Result; public class Application extends Controller { // create new task public static Result newTask() { Form<Task> filledForm = form(Task.class).bindFromRequest(); if(filledForm.hasErrors()) { return badRequest( views.html.index.render(Task.all(), filledForm) ); } else { Task.newTask(filledForm.get()); return redirect(routes.Application.tasks()); } } public static Result index() { return redirect(routes.Application.tasks()); } public static Result tasks() { return ok( views.html.index.render(Task.all(), taskForm)); } public static Result deleteTask(Long id) { return TODO; } } Updated task.java package models; import java.util.List; import javax.persistence.Entity; import play.data.Form; import play.data.validation.Constraints.Required; import play.db.ebean.Model; import play.db.ebean.Model.Finder; import play.mvc.Result; import controllers.routes; @Entity public class Task extends Model { public Long id; @Required public String label; // Define a taskForm static Form<Task> taskForm = form(Task.class); // search public static Finder<Long,Task> find = new Finder( Long.class, Task.class); // display tasks public static List<Task> all() { return find.all(); } // create new task public static Result newTask(Task newTask) { save(task); } // delete task public static void delete(Long id) { find.ref(id).delete(id); // find.ref(id).delete(); } }

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  • twitter streaming api instead of search api

    - by user1711576
    I am using twitters search API to view all the tweets that use a particular hashtag I want to view. However, I want to use the stream function, so, I only get recent ones, and so, I can then store them. <?php global $total, $hashtag; $hashtag = $_POST['hash']; $total = 0; function getTweets($hash_tag, $page) { global $total, $hashtag; $url = 'http://search.twitter.com/search.json?q='.urlencode($hash_tag).'&'; $url .= 'page='.$page; $ch = curl_init($url); curl_setopt ($ch, CURLOPT_RETURNTRANSFER, TRUE); $json = curl_exec ($ch); curl_close ($ch); echo "<pre>"; $json_decode = json_decode($json); print_r($json_decode->results); $json_decode = json_decode($json); $total += count($json_decode->results); if($json_decode->next_page){ $temp = explode("&",$json_decode->next_page); $p = explode("=",$temp[0]); getTweets($hashtag,$p[1]); } } getTweets($hashtag,1); echo $total; ?> The above code is what I have been using to search for the tweets I want. What do I need to do to change it so I can stream the tweets instead? I know I would have to use the stream url https://api.twitter.com/1.1/search/tweets.json , but what do I need to change after that is where I don't know what to do. Obviously, I know I'll need to write the database sql but I want to just capture the stream first and view it. How would I do this? Is the code I have been using not any good for just capturing the stream?

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  • In CakePHP, how to leave all prefixes?

    - by Victor Piousbox
    I have a link that goes like this: $this->Html->link('Welcome', array('controller' => 'users', 'action' => 'add')); I suspect it doesn't work (Firefox says the redirect will never complete), so I did this: $this->Html->link('Welcome', array('controller' => 'users', 'action' => 'add', 'my'=>false)); 'my' is a prefix. I also have 'admin', 'ajax', and 'rss'. So now instead of pointing to /users/add or /my/users/add, the link points to /rss/users/add. The link is in a header, in a layout so I don't know which prefix it will be invoked from. I want to go to /users/add, that is, leave all prefixes altogether. How do I do that in CakePHP? I'm using 1.3 version.

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  • Refreshing a MKMapView when the user location is updated or using default values

    - by koichirose
    I'm trying to refresh my map view and load new data from the server when the device acquires the user location. Here's what I'm doing: - (void)viewDidLoad { CGRect bounds = self.view.bounds; mapView = [[MKMapView alloc] initWithFrame:bounds]; mapView.showsUserLocation=YES; mapView.delegate=self; [self.view insertSubview:mapView atIndex:0]; [self refreshMap]; } - (void)mapView:(MKMapView *)theMapView didUpdateUserLocation:(MKUserLocation *)userLocation { //this is to avoid frequent updates, I just need one position and don't need to continuously track the user's location if (userLocation.location.horizontalAccuracy > self.myUserLocation.location.horizontalAccuracy) { self.myUserLocation = userLocation; CLLocationCoordinate2D centerCoord = { userLocation.location.coordinate.latitude, userLocation.location.coordinate.longitude }; [theMapView setCenterCoordinate:centerCoord zoomLevel:10 animated:YES]; [self refreshMap]; } } - (void)refreshMap { [[UIApplication sharedApplication] setNetworkActivityIndicatorVisible:YES]; [self.mapView removeAnnotations:self.mapView.annotations]; //default position NSString *lat = @"45.464161"; NSString *lon = @"9.190336"; if (self.myUserLocation != nil) { lat = [[NSNumber numberWithDouble:myUserLocation.coordinate.latitude] stringValue]; lon = [[NSNumber numberWithDouble:myUserLocation.coordinate.longitude] stringValue]; } NSString *url = [[NSString alloc] initWithFormat:@"http://myserver/geo_search.json?lat=%@&lon=%@", lat, lon]; NSURLRequest *theRequest=[NSURLRequest requestWithURL:[NSURL URLWithString:url] cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:60.0]; [[NSURLConnection alloc] initWithRequest:theRequest delegate:self]; [url release]; [[UIApplication sharedApplication] setNetworkActivityIndicatorVisible:NO]; } I also have a - (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data, to create and add the annotations. Here's what happens: sometimes I get the location after a while, so I already loaded data close to the default location. Then I get the location and it should remove the old annotations and add the new ones, instead I keep seeing the old annotations and the new ones are added anyway (let's say I receive 10 annotations each time, so it means that I have 20 on my map when I should have 10). What am I doing wrong?

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  • How to send exceptions to exceptionController?

    - by ivar
    <bean class="org.springframework.web.servlet.handler.SimpleMappingExceptionResolver"> <property name="mappedHandlers"> <set> <ref bean="exceptionController" /> </set> </property> <property name="defaultErrorView" value="tiles/content/error" /> </bean> I'm trying to send exceptions to a controller so I can create a redirect. If I comment out the mappedHandlers part then the error tile is displayed but it is only a tile. The rest of the tiles load normally. I need to make a redirect in the controller so I can show an error page not just an error tile. I can't find enough information or an example how the exception invokes some method in exceptionController.

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  • Rails routing issue

    - by Brob
    Hi I've just started learning rails and been going through some tutorials from learning rails (http://www.buildingwebapps.com/podcasts/79335-putting-the-page-contents-into-the) The tutorials appear to be Rails v2 and I'm on Rails v3 There is a line in the routes file which appears to be causing a problem map.view_page ':name', :controller => 'viewer', :action => 'show' The line works for the front end view i.e. my viewer controller but not for the back end I get the error NoMethodError in Viewer#show I think this has something to do with the view I am using and the line <%= @page.body %> I know it's difficult without the full code but if anyone can help that would be awesome

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  • Custom android preference type loses focus when typing

    - by Brian
    I created a simple preference class that shows an AutoCompleteTextView control and it displays properly but when i focus on the AutoCompleteTextView and start typing it brings up the keyboard but then immediately loses focus on the control. Any idea why this loses focus? Here's what i did to create the view. the inflated layout is just a basic linear layout with a title textview in it. I could change it to a dialog preference instead I guess but it'd be smoother if it could be part of the base view. @Override protected View onCreateView(ViewGroup parent) { LayoutInflater inflater = (LayoutInflater) getContext().getSystemService(Context.LAYOUT_INFLATER_SERVICE); LinearLayout layout = (LinearLayout) inflater.inflate(R.layout.base_preference, null); if (mHint != null) { TextView hintView = (TextView) layout.findViewById(R.id.PreferenceHintTextView); hintView.setText(mHint); } TextView titleView = (TextView) layout.findViewById(R.id.PreferenceTitleTextView); titleView.setText(getTitle()); AutoCompleteTextView inputView = new AutoCompleteTextView(getContext()); inputView.setGravity(Gravity.FILL_HORIZONTAL); ArrayAdapter<CharSequence> adapter = new ArrayAdapter<CharSequence>(getContext(), R.layout.auto_complete_text_list_item, getEntries()); inputView.setAdapter(adapter); inputView.setThreshold(1); inputView.setOnItemSelectedListener(this); layout.addView(inputView); return layout; }

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  • How to manage lifecycle in a ViewGroup-derived class?

    - by Scott Smith
    I had a bunch of code in an activity that displays a running graph of some external data. As the activity code was getting kind of cluttered, I decided to extract this code and create a GraphView class: public class GraphView extends LinearLayout { public GraphView(Context context, AttributeSet attrs) { super(context, attrs); LayoutInflater inflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE); inflater.inflate(R.layout.graph_view, this, true); } public void start() { // Perform initialization (bindings, timers, etc) here } public void stop() { // Unbind, destroy timers, yadda yadda } . . . } Moving stuff into this new LinearLayout-derived class was simple. But there was some lifecycle management code associated with creating and destroying timers and event listeners used by this graph (I didn't want this thing polling in the background if the activity was paused, for example). Coming from a MS Windows background, I kind of expected to find overridable onCreate() and onDestroy() methods or something similar, but I haven't found anything of the sort in LinearLayout (or any of its inherited members). Having to leave all of this initialization code in the Activity, and then having to pass it into the view seemed like it defeated the original purpose of encapsulating all of this code into a reusable view. I ended up adding two additional public methods to my view: start() and stop(). I make these calls from the activity's onResume() and onPause() methods respectively. This seems to work, but it feels like I'm using duct tape here. Does anyone know how this is typically done? I feel like I'm missing something...

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  • Perl: How do I extract certain bits from a byte and then covert these bits to a hex value?

    - by Siegfried Hepp
    I need to extract certain bits of a byte and covert the extract bits back to a hex value. Example (the value of the byte is 0xD2) : 76543210 bit position 11010010 is 0xD2 Bit 0-3 defines the channel which is 0010b is 0x2 Bit 4-5 defines the controller which is 01b is 0x1 Bit 6-7 defines the port which is 11b is 0x3 I somehow need to get from the byte is 0xD2 to channel is 0x2, controller is 0x1, port is 0x3 I googled allot and found the functions pack/unpack, vec and sprintf. But I'm scratching by head how to use the functions to achieve this. Any idea how to achieve this in Perl ?

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  • How do I (or should I?) access the service layer from a SiteMesh template (views/layouts/main.gsp) in Grails?

    - by knorv
    I need to create a toplist in the page footer on a site that I'm building. The footer is created in the default SiteMesh layout template (views/layouts/main.gsp). In order to create the toplist access to the database is needed, so I've encapsulated all logic needed for the toplist creation in a service class (services/FooService). Please note that while services are usually accessed from the controller layer, in this case the default layout template (views/layouts/main.gsp) is not generated from a controller. Can the layout view (views/layouts/main.gsp) access a service class? How? Is this the correct design decision? If not, what is a better encapsulation and how do I interact with said encapsulation from the layout view (views/layouts/main.gsp)?

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