Search Results

Search found 28223 results on 1129 pages for 'view controller'.

Page 406/1129 | < Previous Page | 402 403 404 405 406 407 408 409 410 411 412 413  | Next Page >

  • Changing the title of a MFMailComposeViewController

    - by Badescu Alexandru
    Although i know changing MFMailComposeViewController is fround upon, i'm taking a risk. I found some ideas such as [self presentModalViewController:controller animated:YES]; // Existing line [[[[controller viewControllers] lastObject] navigationItem] setTitle:@"SomethingElse"]; and [[[[(MFMailComposeViewController*)vc navigationBar] items] objectAtIndex:0] setTitle:@" SomethingElse"]; but the odd thing is that the title is "SomethingElse" for like 2 seconds and after that it returns to the subject that is set. I've tried other solutions as well but the same output. I am using SHK (ShareKit) to connect to social. Here is the code from showViewController : if ([vc respondsToSelector:@selector(modalPresentationStyle)]) vc.modalPresentationStyle = [SHK modalPresentationStyle]; if ([vc respondsToSelector:@selector(modalTransitionStyle)]) vc.modalTransitionStyle = [SHK modalTransitionStyle]; [topViewController presentModalViewController:vc animated:YES]; [[[[(MFMailComposeViewController*)vc navigationBar] items] objectAtIndex:0] setTitle:@" "]; [(UINavigationController *)vc navigationBar].barStyle = [(UINavigationController *)vc toolbar].barStyle = [SHK barStyle]; self.currentView = vc;

    Read the article

  • PHP Cookie Warning...

    - by Nano HE
    Hi,I am new to PHP, I practised PHP setcookie() just now and failed. http://localhost/test/index.php <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8"> <title></title> </head> <body> <?php $value = 'something from somewhere'; setcookie("TestCookie", $value); ?> </body> </html> http://localhost/test/view.php <?php // I plan to view the cookie value via view.php echo $_COOKIE["TestCookie"]; ?> But I failed to run index.php, IE warning like this. Warning: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\test\index.php:9) in C:\xampp\htdocs\test\index.php on line 12 I enabled my IE 6 cookie no doubt. Is there anything wrong on my procedure above? Thank you. WinXP OS and XAMPP 1.7.3 used.

    Read the article

  • iphone: Accessing Code for Elements Created in Interface Builder

    - by user362685
    I am attempting to create a basic tab-bar application using interface builder. I create a new project in Xcode selecting tab bar application. My question is how can I access the code that instantiates and pushes each of the views when the tab bar buttons are pressed? I would imagine that would be done by the tab bar controller, however when I write the class file from interface builder (filewrite class files), it just creates a blank generic TabBarController.h/TabBarController.m without the methods for pushing each of the views associated with the tab bar elements. I ask this because I would like to pass each view controller a reference to the data model when they are instantiated. Any help would be greatly appreciated, thanks.

    Read the article

  • Searching in Ruby on Rails - How do I search on each word entered and not the exact string?

    - by bgadoci
    I have built a blog application w/ ruby on rails and I am trying to implement a search feature. The blog application allows for users to tag posts. The tags are created in their own table and belong_to :post. When a tag is created, so is a record in the tag table where the name of the tag is tag_name and associated by post_id. Tags are strings. I am trying to allow a user to search for any word tag_name in any order. Here is what I mean. Lets say a particular post has a tag that is 'ruby code controller'. In my current search feature, that tag will be found if the user searches for 'ruby', 'ruby code', or 'ruby code controller'. It will not be found if the user types in 'ruby controller'. Essentially what I am saying is that I would like each word entered in the search to be searched for, not necessarily the 'string' that is entered into the search. I have been experimenting with providing multiple textfields to allow the user to type in multiple words, and also have been playing around with the code below, but can't seem to accomplish the above. I am new to ruby and rails so sorry if this is an obvious question and prior to installing a gem or plugin I thought I would check to see if there was a simple fix. Here is my code: View: /views/tags/index.html.erb <% form_tag tags_path, :method => 'get' do %> <p> <%= text_field_tag :search, params[:search], :class => "textfield-search" %> <%= submit_tag "Search", :name => nil, :class => "search-button" %> </p> <% end %> TagsController def index @tags = Tag.search(params[:search]).paginate :page => params[:page], :per_page => 5 @tagsearch = Tag.search(params[:search]) @tag_counts = Tag.count(:group => :tag_name, :order => 'count_all DESC', :limit => 100) respond_to do |format| format.html # index.html.erb format.xml { render :xml => @tags } end end Tag Model class Tag < ActiveRecord::Base belongs_to :post validates_length_of :tag_name, :maximum=>42 validates_presence_of :tag_name def self.search(search) if search find(:all, :order => "created_at DESC", :conditions => ['tag_name LIKE ?', "%#{search}%"]) else find(:all, :order => "created_at DESC") end end end

    Read the article

  • How can I diff against a revision of a single file using only the default Git GUI tools?

    - by Rich
    I want to view the history of a single file, and then compare a single revision from that history against the current version. On the command line, this is easy: Run: git log -- <filename> Locate the version you want to compare, Run: git diff <commitid> -- <filename> But how can this be done using only the default Git gui tools, git gui and gitk? I know of two methods using gitk, but they're both horribly clunky: Either: Select the New View option from the View menu, Type in the full path to your file into the box labelled Enter files and directories to include, one per line, Locate the version you want to compare by looking at the highlighted items in the top pane, and click on it to select it, Right-click on the current version and select Diff selected - this, Or: Select Tree in the bottom right-hand pane, Locate the file you want to look at, right-click on it, and select Highlight this only, Locate the version you want to compare by looking at the highlighted items in the top pane, and click on it to select it, Right-click on the current version and select Diff selected - this, Click on the file in the bottom right-hand pane to jump to it in the diff output, or scroll manually. Is a better method than this?

    Read the article

  • spring json writes more json then i want

    - by mkoryak
    I am using the json spring view in order to return a simple JSON object from my controller. The problem is that its returning more data then i want. it is returning the validation errors and things inside of my model when all i am doing is this in the controller: Map model = new HashMap() model.put("success", "true"); return new ModelAndView("jsonView", model); If you look at the bottom of this page in the docs it looks like i am getting back data that POST would return. i am not doing a post, i am doing a GET by going directly to the URL with params. How do i get this lib to return just the data in my model?

    Read the article

  • Identity.Name is disposed in a IIS7 Asp.NET MVC application Thread

    - by vIceBerg
    I have made the smallest demo project to illustrate my problem. You can download the sources Here Visual Studio 2008, .NET 3.5, IIS7, Windows 7 Ultimate 32 bits. The IIS Website is configured ONLY for Windows Authentication in an Integreated pipeline app pool (DefaultAppPool). Here's the problem. I have an Asp.NET MVC 2 application. In an action, I start a thread. The View returns. The thread is doing it's job... but it needs to access Thread.CurrentPrincipal.Identity.Name BANG The worker process of IIS7 stops. I have a window that says: "Visual Studio Just-In-Time Debugger An unhandled exception ('System.Object.DisposedException') occured in w3wp.exe [5524]" I checked with the debugger and the Thread.CurrentPrincipal.Identity is valid, but the Name property is disposed. If I put a long wait in the action before it returns the view, then the Thread can do it's job and the Identity.Name is not disposed. So I think the Name gets disposed when the view is returned. For the sake of the discussion, here's the code that the thread runs (but you can also download the demo project. The link is on top of this post): private void Run() { const int SECTOWAIT = 3; //wait SECTOWAIT seconds long end = DateTime.Now.Ticks + (TimeSpan.TicksPerSecond * SECTOWAIT); while (DateTime.Now.Ticks <= end) continue; //Check the currentprincipal. BANG!!!!!!!!!!!!! var userName = Thread.CurrentPrincipal.Identity.Name; } Here's the code that starts the thread public void Start() { Thread thread = new Thread(new ParameterizedThreadStart(ThreadProc)); thread.SetApartmentState(ApartmentState.MTA); thread.Name = "TestThread"; thread.Start(this); } static void ThreadProc(object o) { try { Builder builder = (Builder)o; builder.Run(); } catch (Exception ex) { throw; } } So... what am i doing wrong? Thanks

    Read the article

  • Does to_json require parameters? what about within rails?

    - by Harry Wood
    Does to_json require parameters? what about within rails? I started getting the error "wrong number of arguments (0 for 1)" when doing myhash.to_json Unfortunately I'm not sure when this error started happening, but I guess it relates to some versions of either rails or the json gem. I suppose my code (in a rails controller) is using the ActiveSupport::JSON version of to_json, rather than the to_josn method supported by the json gem. ActiveSupport::JSON vs JSON In environment.rb I have RAILS_GEM_VERSION = '2.3.2' and also config.gem "json", :version=> '1.1.7' It's just a simple hash structure containing primitives which I want to convert in my controller, and it was working, but now I can't seem to run to_json without passing parameters.

    Read the article

  • How to show ModelState.AddModelError when the Model is Empty in MVC4

    - by kk1076
    I am displaying a shopping cart. I need to check for empty values in Shopping cart and display a message like "The Shopping Cart is empty". When I use ModelState.AddModelError in myAction, it throws an exception as there is null reference in Model. How to display the ErrorMessage. My Action public ActionResult Index() { string id = Request.QueryString["UserID"]; IList<CartModel> objshop = new List<CartModel>(); objshop = GetCartDetails(id); if (objshop.Count > 0) { return View(objshop.ToList()); } else { ModelState.AddModelError("", "Your Shopping Cart is empty!"); } return View(); } My View @{ @Html.ValidationSummary(true) } <th > @Html.DisplayNameFor(model => model.ProductName) </th> <th > @Html.DisplayNameFor(model => model.Quantity) </th> <th > @Html.DisplayNameFor(model => model.Rate) </th> <th > @Html.DisplayNameFor(model => model.Price) </th> @foreach (var item in Model) { <td> @Html.DisplayFor(modelItem => item.ProductName)</td> <td> @Html.DisplayFor(modelItem => item.Quantity)</td> <td> @Html.DisplayFor(modelItem => item.Rate) </td> <td> @Html.DisplayFor(modelItem => item.Price) </td> } Any suggestions.

    Read the article

  • Asp.Net MVC - Binding of parameter to model value!

    - by Pino
    This seems like the model binding is causing me issues. Essentially I have a model called ProductOption and for the purpose of this question it has 2 fields ID (Int) PK ProductID (Int) FK I have a standard route set-up context.MapRoute( "Product_default", "Product/{controller}/{action}/{id}", new { controller = "Product", action = "Index", id = UrlParameter.Optional } ); and if the user wants to add an option the URL is, /Product/Options/Add/1 in the above URL 1 is the ProductID, I have the following code to return a blank model the the view, [HttpGet] public ActionResult Add(int id) { return View("Manage", new ProductOptionModel() { ProductID = id }); } Now in my view I keep a hidden field <%= Html.HiddenFor(x=>x.ID) %> This is used to determine (on submit) if we are editing or adding a new option. However the Model binder in .net seems to replace .ID (Which was 0 when leaving the above get actionresult) with 1 (or the value of the id parameter in the URL) How can I stop or work around this? ViewModel public class ProductExtraModel { //Database public int ID { get; set; } public string Name { get; set; } public int ProductID { get; set; } public ProductModel Product { get; set; } }

    Read the article

  • Using the same code in different (partial) views

    - by Danny Chen
    Maybe this question is quite simple because I'm new to MVC2. I have a simple demo MVC project. (1) A weak-typed view: Index.aspx <% Html.RenderPartial("ArticalList", ViewData["AllArticals"] as List<Artical>); %> (2) A strong-typed partical view: ArticalList.ascx <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<List<Artical>>" %> <% foreach (Artical a in Model) { %> <%= Html.ActionLink(a.Title, "About", new { id = a.ID })%><br /> <%} %> (3) Here is the HomeController.cs public ActionResult Index() { ViewData["AllArticals"] = Artical.GetArticals(); return View(); } public ActionResult ArticalList() { return PartialView(Artical.GetArticals()); } Sorry I'm using a Web-Form "angle", because if I'm using a Web-Form, when I visit Index.aspx, rendering ArticalList.ascx will call public ActionResult ArticalList(). But here I need to write Artical.GetArticals() twice in two actions. How can I put them in one?

    Read the article

  • Combined sign in and registration page?

    - by Ryan
    This is somewhat against rails convention but I am trying to have one controller that manages both user session authentication and user registration. I am having troubles figuring out how to go about this. So far I am merging the User Controller and the Sessions Controller and having the 'new' method deliver both a new usersession and a new user instance. With the new routes in rails 3 though, I am having trouble figuring out how to generate forms for these items. Below is the code: user_controller.rb class UserController < ApplicationController def new @user_session = UserSession.new @user = User.new end def create_user @user = User.new(params[:user]) if @user.save flash[:notice] = "Account Successfully Registered" redirect_back_or_default signup_path else render :action => new end end def create_session @user_session = UserSession.new(params[:user_session]) if @user_session.save flash[:notice] = "Login successful!" redirect_back_or_default login_path else render :action => new end end end views/user/new.html.erb <div id="login_section"> <% form_for @user_session do |f| -%> <%= f.label :email_address, "Email Address" %> <%= f.text_field :email %> <%= f.label :password, "Password" %> <%= f.text_field :password %> <%= f.submit "Login", :disable_with => 'Logining...' %> <% end -%> </div> <div id="registration_section"> <% form_for @user do |f| -%> <%= f.label :email_address, "Email Address" %> <%= f.text_field :email %> <%= f.label :password, "Password" %> <%= f.text_field :password %> <%= f.label :password_confirmation, "Password Confirmation" %> <%= f.text_field :password_confirmation %> <%= f.submit "Register", :disable_with => 'Logining...' %> <% end -%> </div> I imagine I will need to use :url = something for those forms, but I am unsure how to specify. Within routes.rb I have yet to specify either Usersor UserSessions as resources (not convinced that this is the best way to do it... but I could be). I would like, however, the registration and login on the same page and have implemented this by doing the following: routes.rb match 'signup' => 'user#new' match 'login' => 'user#new' What's the best way to go about solving this?

    Read the article

  • Sorting and Pagination does not work after I build a custom keyword search that is build using relat

    - by Roland
    I recently started to build a custom keyword search using Yii 1.1.x The search works 100%. But as soon as I sort the columns and use pagination in the admin view the search gets lost and all results are shown. So with otherwords it's not filtering so that only the search results show. Somehow it resets it. In my controller my code looks as follows $builder=Messages::model()->getCommandBuilder(); //Table1 Columns $columns1=array('0'=>'id','1'=>'to','2'=>'from','3'=>'message','4'=>'error_code','5'=>'date_send'); //Table 2 Columns $columns2=array('0'=>'username'); //building the Keywords $keywords = explode(' ',$_REQUEST['search']); $count=0; foreach($keywords as $key){ $kw[$count]=$key; ++$count; } $keywords=$kw; $condition1=$builder->createSearchCondition(Messages::model()->tableName(),$columns1,$keywords,$prefix='t.'); $condition2=$builder->createSearchCondition(Users::model()->tableName(),$columns2,$keywords); $condition = substr($condition1,0,-1) . " OR ".substr($condition2,1); $condition = str_replace('AND','OR',$condition); $dataProvider=new CActiveDataProvider('Messages', array( 'pagination'=>array( 'pageSize'=>self::PAGE_SIZE, ), 'criteria'=>array( 'with'=>'users', 'together'=>true, 'joinType'=>'LEFT JOIN', 'condition'=>$condition, ), 'sort'=>$sort, )); $this->render('admin',array( 'dataProvider'=>$dataProvider,'keywords'=>implode(' ',$keywords),'sort'=>$sort )); and my view looks like this $this->widget('zii.widgets.grid.CGridView', array( 'dataProvider'=>$dataProvider, 'columns'=>array( 'id', array( 'name'=>'user_id', 'value'=>'CHtml::encode(Users::model()->getReseller($data->user_id))', 'visible'=>Yii::app()->user->checkAccess('poweradministrator') ), 'to', 'from', 'message', /* 'date_send', */ array( 'name'=>'error_code', 'value'=>'CHtml::encode($data->status($data->error_code))', ), array( 'class'=>'CButtonColumn', 'template'=>'{view} {delete}', ), ), )); I really do not know what do do anymore since I'm terribly lost, any help will be hihsly appreciated

    Read the article

  • Android: onListItemClick not opening up the .xml file

    - by Capsud
    Hi, public void onListItemClick(ListView l, View v, int position, long id) { if(position == 0){ setContentView(R.layout.cuisine); } } I have an array of Strings and i'm using the above method to try and open up a new xml file called 'cuisine' when it is clicked. but it keeps failing! Have I done this right, or what am I doing wrong? Thanks. Ok from looking at similar problems on the web, people have said to get the onListItemClick() to start a new activity and using that new activity to then open up the new view? So what i've done is this... protected void onListItemClick(ListView l, View v, int position, long id) { Intent dundrumIntent = new Intent(v.getContext(), DundrumSelector.class); dundrumIntent.putExtra("position", position); startActivityForResult(dundrumIntent, 0); } and then import android.app.Activity; import android.os.Bundle; public class DundrumSelector extends Activity { @Override public void onCreate(Bundle savedInstanceState){ super.onCreate(savedInstanceState); int position = getIntent().getExtras().getInt("position"); if(position == 0){ setContentView(R.layout.cuisine); } } } Yet i'm still getting the same problem. The program crashes when I click on an item in the listView. And yes i've added the activity to the manifest. Does anyone have a resolution to this as alot of people seem to be having the same problem. Thanks alot.

    Read the article

  • How to solve the leaks when allocating the NSMutableArray in Objective-C

    - by Madan Mohan
    Hi Guys, I am getting leaks in Master view controller of iPhone. When I call this method, I am inserting them into filteredListCount array, because when I search I need to show the list from filteredListCount array otherwise customerArray. This functionality is working fine but I am getting leaks in the method below at allocation: filteredListCount = [[NSMutableArray alloc] initWithCapacity: [customerArray count]]; This is the first view controller of my application, I am showing the list and I am also allowing to search from a list. - (void)parser:(CustomerListLibXmlParser *)parser addCustomerObject:(Customer *)customerObj1 { [UIApplication sharedApplication].networkActivityIndicatorVisible = YES; [customerArray addObject:customerObj1]; filteredListCount = [[NSMutableArray alloc] initWithCapacity: [customerArray count]]; [filteredListCount addObjectsFromArray: customerArray]; [theTableView reloadData]; } - (void)parser:(CustomerListLibXmlParser *)parser encounteredError:(NSError *)error { } - (void)parserFinished:(CustomerListLibXmlParser *)parser { [UIApplication sharedApplication].networkActivityIndicatorVisible = NO; self.title=@"Customers"; }

    Read the article

  • MVC without ORM is not real MVC?

    - by ajsie
    at the moment im integrating ORM (doctrine) into a MVC framework (codeigniter). then it hit me that this was the obvious way of setting up a MVC: the controller calls the models that are representing database tables. look at this picture: MVC + ORM then i wondered, how can a MVC without ORM be real MVC? cause then the models are not real objects, rather aggregations of different functions that perform CRUD, then returning the result to the controller. and there is no need for a state (object properties) i guess so the functions would be all static? correct me if im wrong on this one. i guess a lot of people are using models without ORM. please share your thoughts. how do your models look like?

    Read the article

  • 404 with spring 3

    - by markjason72
    hi I am going through my first lessons with spring 3.I created a dynamic web app in eclipse with the following structure. spring3mvc \src\my.spring.HelloWorldController.java \WebContent | |-----WEB-INF\jsp\hello.jsp |-----index.jsp |-----web.xml |-----WEB-INF\spring-servlet.xml |-----WEB-INF\lib\...*.jar files I created the spring-servlet.xml as below <context:component-scan base-package="my.spring" /> <bean id="viewResolver" class="org.springframework.web.servlet.view.UrlBasedViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView" /> <property name="prefix" value="/WEB-INF/jsp/" /> <property name="suffix" value=".jsp" /> </bean> and coded the controller package my.spring; import org.springframework.stereotype.Controller; import org.springframework.web.bind.annotation.RequestMapping; import org.springframework.web.servlet.ModelAndView; @Controller public class HelloWorldController { @RequestMapping("/hello") public ModelAndView helloWorld() { String message = "Hello World, Spring 3.0!"; return new ModelAndView("hello", "message", message); } } index.jsp has a link to hello view <html> <body> <a href="hello.html">Say Hello</a> </body> </html> finally in hello.jsp I have put <html> <body> ${message} </body> </html> My web.xml has <display-name>Spring3MVC</display-name> <welcome-file-list> <welcome-file>index.jsp</welcome-file> </welcome-file-list> <servlet> <servlet-name>spring</servlet-name> <servlet-class> org.springframework.web.servlet.DispatcherServlet </servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>spring</servlet-name> <url-pattern>*.html</url-pattern> </servlet-mapping> When I run the app on Tomcat6 server( thru eclipse),I can see the index page at http://localhost:8080/Spring3MVC/ .It displays the link to hello page.When I click on it(http://localhost:8080/Spring3MVC/hello.html),I get a 404 error. message /Spring3MVC/hello.html description The requested resource (/Spring3MVC/hello.html) is not available. Any idea how I can solve this? thanks mark.

    Read the article

  • Error using MVCContrib TestHelper

    - by Brian McCord
    While trying to implement the second answer to a previous question, I am receiving an error. I have implemented the methods just as the post shows, and the first three work properly. The fourth one (HomeController_Delete_Action_Handler_Should_Redirect_If_Model_Successfully_Delete) gives this error: Could not find a parameter named 'controller' in the result's Values collection. If I change the code to: actual .AssertActionRedirect() .ToAction("Index"); it works properly, but I don't like the "magic string" in there and prefer to use the lambda method that the other poster used. My controller method looks like this: [HttpPost] public ActionResult Delete(State model) { try { if( model == null ) { return View( model ); } _stateService.Delete( model ); return RedirectToAction("Index"); } catch { return View( model ); } } What am I doing wrong?

    Read the article

  • Eliminating static properties - What patterns do I have at my disposal?

    - by Jamie Dixon
    I currently have a type that I inject into my controllers that's used for getting and setting session data. I use this so that I can obtain relevant session information as _sessionData.Username rather than using Session["username"]. I'd like to use this session information across all of my views and would previously have done this by making the SessionData members static instead of injecting the SessionData class into my controller. I want to avoid using static members as well as having to pass the object to the view in each controller. What patterns best suit this type of scenario? What do you do to solve this same problem?

    Read the article

  • Android: ProgressDialog doesn't show

    - by Select0r
    Hi, I'm trying to create a ProgressDialog for an Android-App (just a simple one showing the user that stuff is happening, no buttons or anything) but I can't get it right. I've been through forums and tutorials as well as the Sample-Code that comes with the SDK, but to no avail. This is what I got: btnSubmit.setOnClickListener(new View.OnClickListener() { public void onClick(View view) { (...) ProgressDialog pd = new ProgressDialog(MyApp.this); pd.setProgressStyle(ProgressDialog.STYLE_HORIZONTAL); pd.setMessage("Working..."); pd.setIndeterminate(true); pd.setCancelable(false); // now fetch the results (...long time calculations here...) // remove progress dialog pd.dismiss(); I've also tried adding pd.show(); and messed around with the parameter in new ProgressDialog resulting in nothing at all (except errors that the chosen parameter won't work), meaning: the ProgressDialog won't ever show up. The app just keeps running as if I never added the dialog. I don't know if I'm creating the dialog at the right place, I moved it around a bit but that, too, didnt't help. Maybe I'm in the wrong context? The above code is inside private ViewGroup _createInputForm() in MyApp. Any hint is appreciated, Greetings, Select0r

    Read the article

  • Printing elements of array using ERB

    - by Keva161
    I'm trying to print a simple array defined in my controller into my view with a new line for each element. But what it's doing is printing the whole array on one line. Here's my controller: class TodosController < ApplicationController def index @todo_array = [ "Buy Milk", "Buy Soap", "Pay bill", "Draw Money" ] end end Here's my view: <%= @todo_array.each do |t| %> <%= puts t %><\br> <% end %> Here's the result: <\br> <\br> <\br> <\br> ["Buy Milk", "Buy Soap", "Pay bill", "Draw Money"]

    Read the article

  • Accessing a parent scope from a child directive

    - by zok
    The following code does not work. Apparently I cannot access someFunction() from child-dir. Is it a matter of accessing a parent scope from a child directive? How to do it, when the child directive comes from an external library? Angular/HTML: <parent-dir ng-controller="parentCtrl"> <child-dir ng-click="someFunction()"> </child-dir> </parent-dir> JS: .controller('parentCtrl', function($scope) { $scope.someFunction() { console.log('hello'); } }

    Read the article

  • PyQt QAbstractListModel seems to ignore tristate flags

    - by mcieslak
    I've been trying for a couple days to figure out why my QAbstractLisModel won't allow a user to toggle a checkable item in three states. The model returns the Qt.IsTristate and Qt.ItemIsUserCheckable in the flags() method, but when the program runs only Qt.Checked and Qt.Unchecked are toggled on edit. class cboxModel(QtCore.QAbstractListModel): def __init__(self, parent=None): super(cboxModel, self).__init__(parent) self.cboxes = [ ['a',0], ['b',1], ['c',2], ['d',0] ] def rowCount(self,index=QtCore.QModelIndex()): return len(self.cboxes) def data(self,index,role): if not index.isValid: return QtCore.QVariant() myname,mystate = self.cboxes[index.row()] if role == QtCore.Qt.DisplayRole: return QtCore.QVariant(myname) if role == QtCore.Qt.CheckStateRole: if mystate == 0: return QtCore.QVariant(QtCore.Qt.Unchecked) elif mystate == 1: return QtCore.QVariant(QtCore.Qt.PartiallyChecked) elif mystate == 2: return QtCore.QVariant(QtCore.Qt.Checked) return QtCore.QVariant() def setData(self,index,value,role=QtCore.Qt.EditRole): if index.isValid(): self.cboxes[index.row()][1] = value.toInt()[0] self.emit(QtCore.SIGNAL("dataChanged(QModelIndex,QModelIndex)"), index, index) print self.cboxes return True return False def flags(self,index): if not index.isValid(): return QtCore.Qt.ItemIsEditable return QtCore.Qt.ItemIsEnabled | QtCore.Qt.ItemIsEditable | QtCore.Qt.ItemIsUserCheckable | QtCore.Qt.ItemIsTristate You can test it with this, class MainForm(QtGui.QMainWindow): def __init__(self, parent=None): super(MainForm, self).__init__(parent) model = cboxModel(self) self.view = QtGui.QListView() self.view.setModel(model) self.setCentralWidget(self.view) app = QtGui.QApplication(sys.argv) form = MainForm() form.show() app.exec_() and see that only 2 states are available. I'm assuming there's something simple I'm missing. Any ideas? Thanks!

    Read the article

  • Android: CustomListAdapter

    - by primal
    Hi, I have implemented a custom list view which looks like the twitter timeline. adapter = new MyClickableListAdapter(this, R.layout.timeline, mObjectList); setListAdapter(adapter); The constructor for MyClickableListAdapter is as follows private class MyClickableListAdapter extends ClickableListAdapter{ public MyClickableListAdapter(Context context, int viewId, List objects) { super(context, viewId, objects); } ClickableListAdapter extends BaseAdapter and implements the necessary methods. The xml code for the list view is as follows <ListView android:id="@+id/android:list" android:layout_width="fill_parent" android:layout_height="wrap_content" /> This is what it looks like. I have 3 questions 1) I tried registering a context menu for the list view by adding the line after setting the list adapter registerforContextMenu(getListView()); But on long-click the menu doesnt get displayed. I cannot understand what I am doing wrong! 2) Is it possible to display a textview above the listview? I tried it by adding the code for textview above the listview. But then, only the textview gets displayed. 3) I have seen in many twitter clients that on clicking post a window pops up from the top covering only some portion of the screen and rest of the timeline is visible. How can this be done possibly without starting a new activity? Any help would be much appreciated..

    Read the article

  • Should Factories Persist Entities?

    - by mxmissile
    Should factories persist entities they build? Or is that the job of the caller? Pseudo Example Incoming: public class OrderFactory { public Order Build() { var order = new Order(); .... return order; } } public class OrderController : Controller { public OrderController(IRepository repository) { this.repository = repository; } public ActionResult MyAction() { var order = factory.Build(); repository.Insert(order); ... } } or public class OrderFactory { public OrderFactory(IRepository repository) { this.repository = repository; } public Order Build() { var order = new Order(); ... repository.Insert(order); return order; } } public class OrderController : Controller { public ActionResult MyAction() { var order = factory.Build(); ... } } Is there a recommended practice here?

    Read the article

< Previous Page | 402 403 404 405 406 407 408 409 410 411 412 413  | Next Page >