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  • Frequency Table by user in SQL

    - by Roberto
    Very basic SQL question (DB is MySQL): I want a table of number of transactions by users. User ID Transaction count 1 43 2 213 3 0 4 23 5 0 In a table I have the two relevant records (user_id and buy_count). How could I get the table I want? Thanks, Roberto

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  • Adding STI to Existing Table...

    - by keruilin
    I want to add STI to an existing table using a custom type column. Let's call this taste_type whose corresponding model is Fruit. In the Fruit model I have: set_inheritance_column :taste_type In my migration to add STI I have: class AddSTI < ActiveRecord::Migration def self.up add_column :fruits, :taste_type, :string, :limit => 100, :null => false Fruit.reset_column_information Fruit.find_by_id(1).update_attributes({:taste_type => 'Sour'}) end def self.down remove_column :fruits, :taste_type end end When I run the migration, I get the following error: Mysql::Error: Column 'taste_type' cannot be null: ... Any idea what's going? I can get the migration to run if I comment the set_inheritance_column in the Fruit model, then uncomment it after I run the migration. Obviously, I don't want to do this, however.

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  • deploying WAMP -> live site - any random tips?

    - by Haroldo
    In the next few weeks I'll be taking my site from the localhost (WAMP) and puting it on a new server. This will be the first site, on my first server, so basically...i'm a noob! This must be an important moment for any independent web developer / small business so i'd love to hear about some experiences, mistakes and system default security holes that one should fix straight away... I'm using php, mysql, cpanel and WHM, and looking for tips like "Turn off error reporting in PHP"

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  • how escape quotes when inserting into database in PHP

    - by Mauro74
    Hi all, I'm quite new to PHP so sorry if sounds such an easy problem... :) I'm having an error message when inserting content which contains quotes into my db. here's what I tried trying to escape the quotes but didn't work: $con = mysql_connect("localhost","xxxx","xxxxx"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("test", $con); $nowdate = date('d-m-Y') $title = sprintf($_POST[title], mysql_real_escape_string($_POST[title])); $body = sprintf($_POST[body], mysql_real_escape_string($_POST[body])); $sql="INSERT INTO articles (title, body, date) VALUES ('$title','$body','$nowdate'),"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } header('Location: index.php'); Could you provide any solution please? Thanks in advance. Mauro

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  • Password Validation

    - by Humpton
    Hi there. Using mysql and php Is there any reason / value when checking a password to query the database using the user name and password (after sanitizing, of course) and recording a failed attempt when no rows are returned vs querying the database using the user name and then comparing the return password string? EDIT: To those who mentioned it below, yes the password is hashed up in the database.

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  • PHP vs Phpmyadmin

    - by user330306
    Hi there, I've got this code which i execute on phpmyadmin which works 100% Create Temporary Table Searches ( id int, dt datetime); Create Temporary Table Searches1 ( id int, dt datetime, count int); insert into Searches(id, dt) select a.id, now() from tblSavedSearches a; insert into Searches1(id, dt, count) select b.savedSearchesId, (select c.dt from tblSavedSearchesDetails c where b.savedSearchesId = c.savedSearchesId order by c.dt desc limit 1) as 'dt', count(b.savedSearchesId) as 'cnt' from tblSavedSearchesDetails b group by b.savedSearchesId; insert into tblSavedSearchResults(savedSearchId,DtSearched,isEnabled) select id,now(),0 from Searches where not id in (select savedSearchId from tblSavedSearchResults); update tblSavedSearchResults inner join Searches1 on tblSavedSearchResults.savedSearchId = Searches1.id Set tblSavedSearchResults.DtSearched = Searches1.dt, tblSavedSearchResults.isEnabled = 1; However when i put the same code in php as below it generates an error $dba = DbConnect::CreateDbaInstance(); $query = ""; $query.="Create Temporary Table Searches ( id int, dt datetime); "; $query.="Create Temporary Table Searches1 ( id int, dt datetime, count int); "; $query.="insert into Searches(id, dt) select a.id, now() from tblSavedSearches a; "; $query.="insert into Searches1(id, dt, count) "; $query.="select "; $query.=" b.savedSearchesId, "; $query.=" (select c.dt from tblSavedSearchesDetails c where b.savedSearchesId = c.savedSearchesId order by c.dt desc limit 1) as 'dt', "; $query.=" count(b.savedSearchesId) as 'cnt' "; $query.="from tblSavedSearchesDetails b "; $query.="group by b.savedSearchesId; "; $query.="insert into tblSavedSearchResults(savedSearchId,DtSearched,isEnabled) "; $query.="select id,now(),0 from Searches where not id in (select savedSearchId from tblSavedSearchResults); "; $query.="update tblSavedSearchResults "; $query.="inner join Searches1 on tblSavedSearchResults.savedSearchId = Searches1.id "; $query.="Set tblSavedSearchResults.DtSearched = Searches1.dt, tblSavedSearchResults.isEnabled = 1; "; $dba->DbQuery($query) or die(mysql_error()); I get the following error You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'Create Temporary Table Searches1 ( id int, dt datetime, count int) insert into S' at line 1 Please if someone could assist me with this ... Thanks

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  • why this left join query failed to load all the data in left table ?

    - by lzyy
    users table +-----+-----------+ | id | username | +-----+-----------+ | 1 | tom | | 2 | jelly | | 3 | foo | | 4 | bar | +-----+-----------+ groups table +----+---------+-----------------------------+ | id | user_id | title | +----+---------+-----------------------------+ | 2 | 1 | title 1 | | 4 | 1 | title 2 | +----+---------+-----------------------------+ the query SELECT users.username,users.id,count(groups.title) as group_count FROM users LEFT JOIN groups ON users.id = groups.user_id result +----------+----+-------------+ | username | id | group_count | +----------+----+-------------+ | tom | 1 | 2 | +----------+----+-------------+ where is the rest users' info? the result is the same as inner join , shouldn't left join return all left table's data? PS:I'm using mysql

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  • How to recognize what indexes are not used?

    - by tomaszs
    I have a table in MySQL with 7 indexes, most of them are on more than one column. I think here is too much indexes. Is there any way to get statistics of what indexes are used more by all thousands of queries to this database and what are less worthy so I know what index to consider to remove in first place?

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  • PHP URL Security Question

    - by TaG
    I want to have users store the url in my database I'm using php mysql and htmlpurifier I was wondering if the following code was good way to filter out bad data? Here is the Partial PHP code. $url = mysqli_real_escape_string($mysqli, $purifier->purify(htmlspecialchars(strip_tags($_POST['url'])));

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  • SQL GUI Programs

    - by jake
    Are there any programs with a gui which let you create a SQL database, create tables, define the primary and foreign keys and insert data? I am tired of having to use the mysql command line client, very tedious.

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  • Pound symbol not displaying on web page

    - by Gublooo
    Hello I have a mysql database table to store country name and currency symbol - the CHARSET has correctly set to UTF8. This is example data inserted into the table insert into country ( country_name, currency_name, currency_code, currency_symbol) values ('UK','Pounds','GBP','£'); When I look in the database - the pound symbol appears fine - but when I retrieve it from the database and display it on the website - a weird square symbol shows up with a question mark inside instead of the pound symbol. You can look at it here - http://www.didyouswipe.com/profile/view-profile/user_id/181 Please advice Thanks

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  • date() is showing December 1969

    - by Doug
    $sql = "SELECT * FROM news ORDER BY `news_id` DESC LIMIT 1"; $result = mysql_query($sql) or die(mysql_error()); $row = mysql_fetch_assoc($result); $date = $row['time_posted']; echo "<i> " .date("Y/m/d", $date) . "</i>: "; I used timestamp in mysql. So, what's the problem?

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  • How to get UTF-8 working in java webapps?

    - by kosoant
    I need to get UTF-8 working in my Java webapp (servlets + JSP, no framework used) to support äöå etc. for regular Finnish text and Cyrillic alphabets like ??? for special cases. My setup is the following: Development encironment: Windows XP Production encironment: Debian Database used: MySQL 5.x Users mainly use Firefox2 but also Opera 9.x, FF3, IE7 and Google Chrome are used to access the site. How to achieve this?

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  • ORDER BY letters and not numbers of a field

    - by Jon
    Is there a way to order mysql results by the first letter and ignore numbers? For example, I have a list of addresses: 123 Main Street 456 Second Street 234 Third Street and I want to order by the street name and ignore the street number. Is there an easy way to do this?

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  • What happens if you kill a long-running alter query?

    - by B T
    What happens if you kill a long-running alter query? Will the alter query simply revert? How long could that take (as a proportion of the time it has already been running)? What if that query is being replicated onto another server? Will killing the process on the other server revert the original server's alter query? We're running mysql

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  • creating a primary key format

    - by ryn6
    how do i create a primary key for an account with a format like this: ABC-123 ABC-124 ABC-125 another example: BCA-111 BCA-112 BCA-113 and so on. by the way im using mysql.is it possible to do auto increment when using this format?

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  • Making Browser Auto-Scroll to Most Recently Submitted Comment.

    - by John
    Hello, I made a comment on a Wordpress blog and I noticed that after I submitted the comment, the top of the browser was flush with the top of my comment. In other words, the web page was auto-scrolled down to the top of my comment. How can I do this? I am using a comment system with PHP / MySQL. Thanks in advance, John

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  • How does Wordpress link posts to categories in its database?

    - by bcmcfc
    At present I am displaying a list of the last 5 posts in a site's blog in its footer using this mysql query: SELECT post_title, guid, post_date FROM wp_posts WHERE post_type = 'post' AND post_status = 'Publish' ORDER BY post_date DESC LIMIT 5 How can I edit this query to restrict the search to a particular category id? I thought it would be as simple as looking for a category field in the posts table but it isn't!

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