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  • codeigniter populate form from database

    - by Delirium tremens
    In the controller, I have... function update($id = null) { $this->load->database(); // more code $data = array(); $data = $this->db->get_where( 'users', array( 'id' => $id ) ); $data = $data->result_array(); $data = $data[0]; // more code $this->load->view('update', $data); } In the view, I have... <h5>Username</h5> <input type="text" name="username" value="<?php echo set_value('username'); ?>" size="50" /> <h5>Email</h5> <input type="text" name="email" value="<?php echo set_value('email'); ?>" size="50" /> <h5>Email Confirmation</h5> <input type="text" name="emailconf" value="<?php echo set_value('emailconf'); ?>" size="50" /> <h5>Password</h5> <input type="text" name="password" value="<?php echo set_value('password'); ?>" size="50" /> <h5>Password Confirmation</h5> <input type="text" name="passconf" value="<?php echo set_value('passconf'); ?>" size="50" /> set_value() isn't reading $data search for value="" at http://codeigniter.com/forums/viewthread/103837/ The poster uses only the set_value() function between "" in value="". I'm wondering how to do the same, but I can't get it to work. Help?

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  • Adding new records in Access without wrecking the form

    - by Matt Parker
    I'm working on a simple Access 2003 application to keep track of things that need to be done for clients for some colleagues. Each colleague has a set of clients, and each client has a set of actions that need to be taken by a certain date. I've set up a form that consists of a combobox for client ID (indexed), a drop-down for the person who is handling that client's case, and a button for adding new clients (a standard Access-created Add Record button). The actions are listed in a subform below these three elements. The problem I've run into is that the first person I tested this on clicked the button to add a new record, then didn't fill it out and tried to select another client from the drop-down list. Access interprets this as an attempt to set the selected Client ID as the ID for the new record and rightfully throws an error for duplicate primary keys. I can think of a couple of ways around this problem, but I'd much rather hear your elegant solutions than kludge together some junk in a language I don't know. Let me know if you have any questions. Thank you.

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  • form not showing for empty records

    - by Chris Hodges
    I have a relatively simple PHP page called editcustomers with 3 columns. The problem I'm having is that the form will show when there is a record in the database and the fields will be populated with that info. When no such records exists, the form is not even shown, eliminating the possibility to insert a record. My page layout is as follows: Column 1 shows a form containing customer information, allowing it to be edited. Column 2 allows ordering of products and showing how many products were ordered Column 3 shows the total paid so far, and the total owing. The code for the page I have at present: <html> <?php $id = $_GET['id']; require_once('connect.php'); $sth = $dbh->query("SELECT * FROM users where id = '$id';"); $sth->setFetchMode(PDO::FETCH_ASSOC); $eth = $dbh->query("SELECT * FROM purchases where id = '$id';"); $eth->setFetchMode(PDO::FETCH_ASSOC); ?> <div id="main"> <div id="left"> <form name="custInfo" action ="process.php" method ="post" > <input type = "hidden" name ="formType" value="custInfo"/> <?php while($row = $sth->fetch()){ ?> <p><input type = "hidden" name ="id" value="<?php echo $row["id"] ?>"/> <p><input type = "text" name ="firstName" size ="30" value=" <?php echo $row["firstName"]?>"/> <p><input type = "text" name ="lastName" size ="30" value="<?php echo $row["lastName"]?>"/> <p><input type = "text" name ="country" size ="30" value="<?php echo $row["country"]?>"/> <p></p> <input type="submit" value="Update" /> <?php }?> </div> <div id="mid"> <form name="custCosts" action ="process.php" method ="post" > <input type = "hidden" name ="formType" value="custCosts"/> <?php while($row = $eth->fetch()){ ?> <p><input type = "hidden" name ="id" value="<?php echo $row["id"] ?>"/> <p><input type = "text" name ="amountOwed" size ="30" value=" <?php echo $row["amountOwed"]?>"/> <p><input type = "text" name ="numAaa" size ="30" value="<?php echo $row["numAaa"]?>"/> <p><input type = "text" name ="numBbb" size ="30" value="<?php echo $row["numBbb"]?>"/> <p></p> <input type="submit" value="Update" /> <?php }?> </div> <div id="right"> <b>Total Balance</b> <p> Money owed: </p> <p> aaa total: </p> <p> bbb total: </p> <p> Total: </p> <input type = "text" name ="pay" size ="20" /></p> <input type="submit" value="Make Payment" /> </div> <?php $dbh =null; ?> </body> </html> And the code for all the database trickery: <?php require_once 'connect.php'; $formType = $_POST['formType']; $id = $_POST['id']; $firstName = $_POST['firstName']; $lastName = $_POST['lastName']; $country = $_POST['country']; $amountOwed = $_POST['amountOwed ']; $numAaa = $_POST['numAaa']; $numBbb = $_POST['numBbb']; if(empty($_POST['id'])) { $sth = $dbh->prepare("INSERT INTO customers (firstName, lastName, country) VALUES ('$firstName', '$lastName', '$country')"); $sth->execute(); } elseif(!empty($_POST['id']) && !isset($_POST['stayCost']) && $_POST['formType'] == 'guestInfo'){ $sth = $dbh->prepare("UPDATE customers SET firstName = '$firstName', lastName = '$lastName', country = '$country' WHERE id = '$id'"); $sth->execute(); }elseif(!empty($_POST['id']) && isset($_POST['stayCost']) && $_POST['formType'] == 'guestInfo'){ $sth = $dbh->prepare("INSERT INTO purchases (id, amountOwed, numAaa, numBbb) VALUES ('$id', '$amountOwed', '$numAaa', '$numBbb'"); $sth->execute(); }elseif(!empty($_POST['id']) && $_POST['formType'] == 'guestCosts'){ $sth = $dbh->prepare("UPDATE purchases SET amountOwed= '$amountOwed', numAaa = '$numAaa', numBbb= '$numBbb' WHERE id = '$id'"); $sth->execute(); } $dbh =null; ?> Why does the form not even display if there is no record? An error or something I might understand....but the form is still in the HTML and should still be being output, from what I can see. Why is this not the case?

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  • Cloning whole form elements after clicking button

    - by FreshPro
    I have this following form <form action="" class="form-horizontal"> <div id="wrapper"> <div class="row-fluid"> <div class="span6"> <div class="control-group"> <label class="control-label"><?=$core->l("default_comm_type");?></label> <div class="controls"> <select id="fld_default_comm_type" name="fld_default_comm_type[]" defaultValue="-1" class="m-wrap span10" field="fld_default_comm_type" appEditor="true"> <?=combo_creator::render_default_comm_types()?> </select> </div> </div> </div> <div class="span4 checkerAlign"> <div class="control-group"> <div class="controls"> <?=$core->l("is_active");?> </div> </div> </div> <div class="span2 checkerAlign"><input type="checkbox" name="fld_active[]" id="fld_active" editType="booleanEdit" appEditor="true"/></div> </div> <div><a href="#" id="addMore">Add Row</a></div> </div> The question is when user clicks Add Row button, I need to create a copy of this form elements inside <div id="wrapper"> How can i do that? EDIT: SOLVED <form action="" class="form-horizontal" id="wrapper"> <div class="row-fluid"> <div class="span6"> <div class="control-group"> <label class="control-label"><?=$core->l("default_comm_type");?></label> <div class="controls"> <select id="fld_default_comm_type" name="fld_default_comm_type[]" defaultValue="-1" class="m-wrap span10" field="fld_default_comm_type" appEditor="true"> <?=combo_creator::render_default_comm_types()?> </select> </div> </div> </div> <div class="span4 checkerAlign"> <div class="control-group"> <div class="controls"> <?=$core->l("is_active");?> </div> </div> </div> <div class="span2 checkerAlign"><input type="checkbox" name="fld_active[]" id="fld_active" editType="booleanEdit" appEditor="true"/></div> </div> <a href="#" data-action="add">add</a> <a href="#" data-action="delete">delete</a> </form> In the Js part: jQuery("#addMore").click(function(){ var contents = jQuery("form").html(); jQuery("#test").append(contents); }); When add is clicked it inserts form elements just as I wanted and when delete is clicked it deletes elements. Thank you for the tips guys Problem solved! Thanks guys.

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  • ZF2 Vertical Form

    - by yunhasnawa
    I created a simple form in typical ZF2 application. The form class code is just a modified code provided by Zend's Album example. <?php namespace Admin\Form; use Zend\Form\Form; class CityForm extends Form { public function __construct($name = null) { parent::__construct('city'); $this->setAttribute('method', 'post'); $this->add(array( 'name' => 'id', 'attributes' => array( 'type' => 'hidden', ), )); $this->add(array( 'name' => 'name', 'attributes' => array( 'type' => 'text' ), 'options' => array( 'label' => 'Name', ), )); $this->add(array( 'name' => 'province', 'attributes' => array( 'type' => 'text' ), 'options' => array( 'label' => 'Province', ), )); $this->add(array( 'name' => 'country', 'attributes' => array( 'type' => 'text' ), 'options' => array( 'label' => 'Country', ), )); $this->add(array( 'name' => 'coordinate', 'attributes' => array( 'type' => 'text' ), 'options' => array( 'label' => 'Coordinate', ), )); $this->add(array( 'name' => 'submit', 'attributes' => array( 'type' => 'submit', 'value' => 'Save', 'id' => 'submitButton', ), )); } } And call it like this in CityController, a typical controller extends AbstractActionController: public function addAction() { $form = new CityForm(); $viewData = array( 'form' => $form ); return new ViewModel($viewData); } Finally in view I echo it like this: <?php $title = 'Add New City'; ?> <?php $this->headtitle($title); ?> <h1><?php echo $this->escapehtml($title); ?></h1> <?php $form = $this->form; ?> <?php $form->setAttribute('action', $this->url('city', array('action' => 'add'))); ?> <?php $form->prepare(); ?> <?php echo $this->form()->openTag($form); echo $this->formHidden($form->get('id')); echo $this->formRow($form->get('name')); echo $this->formRow($form->get('province')); echo $this->formRow($form->get('country')); echo $this->formRow($form->get('coordinate')); echo $this->formSubmit($form->get('submit')); echo $this->form()->closeTag(); ?> What I expected to see is a vertical form like this: But what i got is an ugly form like this: What's wrong with my code? Please help. EDIT: When I inspect element, the form generated is strange. The <input> element is inside the <label> element. <form id="city" name="city" method="post" action="/karciscus/public/admin/city/add"> <input type="hidden" value="" name="id"> <label> <span>Name</span><input type="text" value="" name="name"> </label> <label> <span>Province</span><input type="text" value="" name="province"> </label> <label> <span>Country</span><input type="text" value="" name="country"> </label> <label> <span> Coordinate</span><input type="text" value="" name="coordinate"> </label> <input type="submit" value="Save" id="submitButton" name="submit"> </form> I'm pretty sure it is the cause of my ugly rendered form. I think it is not supposedly like that. How to fix it?

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  • django updating m2m field

    - by Marconi
    I have a model service and a ModelForm named Service which I use to add and update the service model. The model looks like this: class Service(models.Model): categories = models.ManyToManyField(Category) The categories field is displayed as a tag with that allows multiple selection. It works well when I'm adding a new record but when I'm updating it, only one service is showing up on the request.POST['categories'] even if I selected multiple categories. I tried dumping the request object and I can see that the categories is showing something like: u'categories': [u'3', u'4', u'2'] I tried calling the request._get_post() and it did return only 1 category, hence the request.POST['categories'] returns only 1. Anybody who knows what's happening and how to fix it?

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  • How would I go about letting a user add and associate a comma separated list of categories while add

    - by Throlkim
    I've been struggling for quite a while to get this feature working: I want my user to be able to select categories when uploading a photograph, but additionally be able to specify a comma-separated list of categories to create/find and associate with the photograph. I've had this working by using an attr_accessor :new_categories on the photographs model, but having that there without the column existing breaks both Paperclip and Exifr. Obviously, image upload and EXIF data retrieval are pretty important for a photography website, but not being able to add categories while uploading a photograph is a pain in the arse. Methods I've tried so far: Using attr_accessor to add a field for new_categories. Breaks gems. Using an Ajax sub-form to add categories. Formtastic can't handle it. Adding a column for new_categories to the photograph model. It works, but it's horrific. I haven't tried using a nested form, but I'd need to intercept it and stop it from processing it as normal. Here's an example of what I'm trying to accomplish: http://imgur.com/rD0PC.png And the function I use to associate the categories: def process_new_categories unless self.new_categories.nil? for title in self.new_categories.split(",") self.categories << Category.find_or_create_by_title(title.strip.capitalize) end end end Has anyone got any ideas as to how to do this?

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  • Getting Undefined index errors when trying to use $_POST

    - by Apoorv Agrawal
    I'm getting the following error messages: Notice: Undefined index: name in C:\xampp\htdocs\ApoorvProject\PostMethod.php on line 7 Notice: Undefined index: email in C:\xampp\htdocs\ApoorvProject\PostMethod.php on line 9 This is what line 7 and line 9 contains: echo $_POST["name"]; echo "<br>"; echo $_POST["email"]; This is the body of my HTML documnent: <form action="PostMethod.php" method="post"> Name: <input type="text" name="name" /> Email: <input type="text" name="email" /> <input type="submit" /> </form> PostMethod.php is the name of my PHP file.

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  • Rails nested form for belongs_to

    - by user1232533
    I'm new to rails and have some troubles with creating a nested form. My models: class User < ActiveRecord::Base belongs_to :company accepts_nested_attributes_for :company, :reject_if => :all_blank end class Company < ActiveRecord::Base has_many :users end Now i would like to create a new company from the user sign_up page (i use Devise btw) by given only a company name. And have a relation between the new User and new Company. In the console i can create a company for a existing User like this: @company = User.first.build_company(:name => "name of company") @company.save That works, but i can't make this happen for a new user, in my new user sign_up form i tried this (i know its wrong by creating a new User fist but im trying to get something working here..): <%= simple_form_for(resource, :as => resource_name, :html => { :class => 'form-horizontal' }, :url => registration_path(resource_name)) do |f| %> <%= f.error_notification %> <div class="inputs"> <% @user = User.new company = @user.build_company() %> <% f.fields_for company do |builder| %> <%= builder.input :name, :required => true, :autofocus => true %> <% end %> <%= f.input :email, :required => true, :autofocus => true %> <%= f.input :password, :required => true %> <%= f.input :password_confirmation, :required => true %> </div> <div class="form-actions"> <%= f.button :submit, :class => 'btn-primary', :value => 'Sign up' %> </div> I did my best to google for a solution/ example.. found some nested form examples but it's just not clear to me how to do this. Really hope somebody can help me with this. Any help on this would be appreciated. Thanks in advance! Greets, Daniel

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  • Why is this jquery dialog window not displaying?

    - by user338413
    I've got a form that is using jquery validation. When the user clicks the submit button, I've got some jquery that intercepts the submit and should display a dialog window asking the user to verify the information they entered on the form. This dialog window should only display if the form has validated. Here is my code: $('#form').submit(function(){ fillVerificationDialog(); /* This loads up the dialog with form data */ if (('#form').valid()){ $('verification_dialog').dialog('open'); return false; } }); My dialog window is not displaying. It just submits the form. And I've verified that the form is valid by using an alert that checks the value of $('#form').valid() If I remove the if statement and just have the line that opens the dialog, the dialog displays. However, it will display even if the form has errors which is what I'm trying to prevent.

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  • Drupal: How to Render Results of Form on Same Page as Form

    - by Aaron
    How would I print the results of a form submission on the same page as the form itself? Relevant hook_menu: $items['admin/content/ncbi_subsites/paths'] = array( 'title' => 'Paths', 'description' => 'Paths for a particular subsite', 'page callback' => 'ncbi_subsites_show_path_page', 'access arguments' => array( 'administer site configuration' ), 'type' => MENU_LOCAL_TASK, ); page callback: function ncbi_subsites_show_path_page() { $f = drupal_get_form('_ncbi_subsites_show_paths_form'); return $f; } Form building function: function _ncbi_subsites_show_paths_form() { // bunch of code here $form['subsite'] = array( '#title' => t('Subsites'), '#type' => 'select', '#description' => 'Choose a subsite to get its paths', '#default_value' => 'Choose a subsite', '#options'=> $tmp, ); $form['showthem'] = array( '#type' => 'submit', '#value' => 'Show paths', '#submit' => array( 'ncbi_subsites_show_paths_submit'), ); return $form; } Submit function (skipped validate function for brevity) function ncbi_subsites_show_paths_submit( &$form, &$form_state ) { //dpm ( $form_state ); $subsite_name = $form_state['values']['subsite']; $subsite = new Subsite( $subsite_name ); //y own class that I use internally in this module $paths = $subsite->normalized_paths; // build list $list = theme_item_list( $paths ); } If I print that $list variable, it is exactly what I want, but I am not sure how to get it into the page with the original form page built from 'ncbi_subsites_show_path_page'. Any help is much appreciated!

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  • Displaying form validation errors in a template (Symfony)

    - by Jay
    Hi, let's say I have a blog with a module "post". now I display a post like this: post/index?id=1 in the index-action i generate a new CommentForm and pass it as $this-form to the template and it is being displayed at the bottom of a post (it's just a textfield, nothing special). form action is set to "post/addcomment". How can I display the validation errors in this form? using setTemplate('index') doesn't work because I would have to pass the id=1 to it... thanks

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  • Setting a form field's value during validation

    - by LaundroMat
    I read about this issue already, but I'm having trouble understanding why I can't change the value of a form's field during validation. I have a form where a user can enter a decimal value. This value has to be higher than the initial value of the item the user is changing. During clean(), the value that was entered is checked against the item's previous value. I would like to be able to re-set the form field's value to the item's initial value when a user enters a lower value. Is this possible from within the clean() method, or am I forced to do this in the view? Somehow, it doesn't feel right to do this in the view... (To make matters more complicated, the form's fields are built up dynamically, meaning I have to override the form's clean() method instead of using the clean_() method).

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  • MYSQL/PHP: Inserting data via HTML form, same "input name"

    - by Camen
    I'm new to MySQL and as a learning project I'd like to make a recipe database. I'd like to the user to be able to enter ingredients through a simple HTML form but I'm stuck in how to label the form so that I can enter several ingredients into the database at once. I'd like to do something like this: <form method="post" action="insert.php"> Ingredient 1: <input type="text" name="ingredient"><br /> Ingredient 2: <input type="text" name="ingredient"><br /> Ingredient 3: <input type="text" name="ingredient"><br /> <input type="submit" value="Submit"> </form> When I do this, I add rows to the table but they're all empty. I know it's got something to do with me using "ingredient" (the table value where I want to add the ingredient name) several times in the form, but I just don't know how to solve it. I would absolutely love some input on how to make it work.

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  • extending spring form tag library attributes

    - by TimmyJ
    I'm using Spring's form tag library in a Spring MVC application that I am developing. The company I am working for has implemented some company-wide policies based on the definition of custom attributes for certain tags. For instance, by default (though the inclusion of a standard javascript file) all tags have their values automatically converted to upper case. In order to disable this one would define their tag with a custom attribute in the following way: <input type="text" uppercase="false" /> The problem is that the addition of these custom attributes to a spring:form tag causes an error at runtime. I've pasted the error below. org.apache.jasper.JasperException: /WEB-INF/jsp/reportCriteria.jsp(45,5) Attribute uppercase invalid for tag input according to TLD My question is: is there any way to extend the TLD to allow for these attributes, or is there any other way add these custom attributes to these spring:form tags?

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  • codeigniter and form action trailing / issue??

    - by alex
    Hi, I am having a bit of an issue with the way CI is dealing with /. In a regular form i notice that the following form action didn't work action="mydomain.com/ci-controller/login/" but this one does work action="mydomain.com/ci-controller/login" Strange but he it worked. But now i need this from a iframe, i the iframe i have a login form which sets the parents url to mydomain.com/ci-controller/login, but i get the same error as it was calling mydomain.com/ci-controller/login/ Could my problem be that the call from the iframe adds a trailing / which is not visible?? Any thoughts

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  • Remembering Form information

    - by Pete Herbert Penito
    Hi everyone! I'm sorry if this has been asked before but I feel my situation is a little different... I have a huge form (like 50 questions involving checkboxes, drop downs, text boxes and textareas) When a user submits a form and the validation page throws an error, is there an easy way to keep the info they entered? My intitial form is on form.php and then the form action is form_posted.php, before anything is run on form_posted.php I have my validation code which sends the user back to form.php with an error number (eg. form.php?error=3) if there was a problem with any in particular. This is done with header("form.php?error=3") so on form.php do the posted variables exist? even tho the page wasn't specifically sent with any posted variables. Also if this is the case, is it completely secure to be making the value of a textbox what it was before? like <input type="text" value="php echo $_POSTED["username"] ?>">

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  • That's all about nuances

    - by user13334359
    When I sent a proposal for session "Managing and Troubleshooting MySQL for Oracle DBAs" to MySQL Connect conference org committee it had not any mention of Oracle in its name, but later I was asked to provide more details for former Oracle DBAs who want to use MySQL. I was fast and I said "yes".So my original aim to teach people to troubleshoot MySQL changed to teaching of how different is MySQL from Oracle in troubleshooting aspects. Although both RDBMs have very much in common they are definitely very different. So what I am going to speak about this time is nuances of how MySQL stores data, how it manages locks, why its high availability solutions: MySQL Cluster and Replication have same names as Oracle's, but work differently and more. And, of course, I will tell how to troubleshoot it all.

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  • How to allow certain HTML tags in a form field in Symfony 1.2

    - by camomileCase
    I'm playing around with Symfony and have encountered a road block. I created a model "CmsPage" which has a field called "content" which is stored as a clob (this is specific to doctrine I believe). When I created the app I set "--escaping-strategy=on" so if I enter any html when editing a CmsPage that gets encoded with html entities or something along those lines. I would like to allow html in this field and a quick googling hasn't helped much. Maybe I'm searching for the wrong terms. Anywho I would like to disable character escaping for this field and possibly only allow a small selection of html tags. What is the correct way to do this in Symfony?

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  • How do I create a polymorphic model with a collection_select?

    - by muxe
    This are my models: class Speaker < ActiveRecord::Base belongs_to :session, :foreign_key => :session_id, :class_name => :Session belongs_to :speakable, :polymorphic => true end class Session < ActiveRecord::Base has_many :speakers accepts_nested_attributes_for :speakers end class Person < ActiveRecord::Base has_many :speakers, :as => :speakable end class Company < ActiveRecord::Base has_many :speakers, :as => :speakable end What I want to do now is something like this: app/views/sessions/edit.html.erb <% f.fields_for :speakers do |sf| %> <p> <%= sf.label :speaker %><br /> <%= sf.collection_select :speakable, Company.all + Person.all, :id, :full_name %> </p> <% end %> But it is not working because of the polymorphic assignment. How do I approach this problem? EDIT: The Error is: undefined method `base_class' for String:Class with params being: "speaker"=>{"speakable"=>"1063885469", "session_id"=>"1007692731"} The value passed to speakable is the id of the Speaker/Company. Yes, this is the value I specified the collection_select to return, but how can I manage to supply both values (speakable_id and speakable_type) ?

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  • Login screen using user custom control

    - by Mocco
    Hi, I have followed some advices I got here today and would need a bit more help now: I have an user control with login logic. In mainForm I am using this: private void Form1_Load(object sender, EventArgs e) { LoginScreen login = new MainMenu(); login.Parent = this; login.Dock = DockStyle.Fill; login.Show(); } But I guess it is not modal and thus does not stop the original Form application. Sure I would need the main Form to do not continue until the login form is closed (and login sucessfull). Would using an event correct? Let login object to raise an event that login was successfull and let the MainForm handle it - run the app?

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  • Javascript: Perform function on form submit

    - by flight643
    Hopefully this is a pretty simple question! I've got the code working in jQuery to listen for a specific form on a page to be submitted and perform an alert when it is.. I.e.: The form itself doesn't have a name so I am targetting the form within a specific form ID. $("#content form").submit(function() { alert("lorem ipsum dolor?"); }); What would be the syntax for performing this in javascript alone without using jquery? For example, I have this code (below) and just am unsure of how to listen for the form to be submitted to perform an action.. var submitform = document.getElementById("content").getElementsByTagName("form"); Thanks!

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  • Changing a Select dropdown with a jquery ui slider

    - by Chris J. Lee
    Trying to set a select dropdown with a slider. You move the jquery ui slider and then it will change the selection of the other two dropdowns. is there a current method in jquery that would set these options? Current dropdown: <select id="alert-options-frequency-opts"> <option value=""></option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> <option value="6">6</option> <option value="7">7</option> <option value="8">8</option> <option value="9">9</option> <option value="10">10</option> </select>

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  • upload form only works in Firefox when uploading ASCII .stl 3D files

    - by NathanPDX
    uploadform.html and upload_file.php (below) works fine in Firefox but fails in Chrome, IE, and Safari when uploading ASCII .stl 3D files. Error message is "Invalid file" and problem occurs with multiple computers and multiple .stl files. When I modify the code to support other file types like JPG and PDF it allows those file types in all three web browsers. Also, Firefox only allows the .stl upload if I include application/octet-stream in the mime types section. Why doesn't this work outside of Firefox? uploadform.html: <!doctype html> <html> <body> <form action="upload_file.php" method="post" enctype="multipart/form-data"> <label for="file">Filename:</label> <input type="file" name="file" id="file" /> <br /> <input type="submit" name="submit" value="Submit" /> </form> </body> </html> upload_file.php: <!doctype html> <html> <body> <?php $allowedExts = array("stl"); $extension = end(explode(".", $_FILES["file"]["name"])); if ( ( ($_FILES["file"]["type"] == "application/sla") || ($_FILES["file"]["type"] == "application/octet-stream") || ($_FILES["file"]["type"] == "text/plain") || ($_FILES["file"]["type"] == "application/unknown") ) && ($_FILES["file"]["size"] < 2000000) && in_array($extension, $allowedExts) ) { if ($_FILES["file"]["error"] > 0) { echo "Return Code: " . $_FILES["file"]["error"] . "<br />"; } else { echo "Upload: " . $_FILES["file"]["name"] . "<br />"; echo "Size: " . ($_FILES["file"]["size"] /1024) . " KB<br />"; if (file_exists("upload/" . $_FILES["file"]["name"])) { echo $_FILES["file"]["name"] . " already exists. "; } else { move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $_FILES["file"]["name"]); echo "successful upload"; } } } else { echo "Invalid file"; } ?> </body> </html>

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