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  • Object directing to a property when accessed as an iterable

    - by ThE_JacO
    I'm trying to figure out if there's an elegant and concise way to have a class accessing one of its own properties when "used" as a dictionary, basically redirecting all the methods that'd be implemented in an ordered dictionary to one of its properties. Currently I'm inheriting from IterableUserDict and explicitly setting its data to another property, and it seems to be working, but I know that UserDict is considered sort of old, and I'm concerned I might be overlooking something. What I have: class ConnectionInterface(IterableUserDict): def __init__(self, hostObject): self._hostObject= hostObject self.ports= odict.OrderedDict() self.inputPorts= odict.OrderedDict() self.outputPorts= odict.OrderedDict() self.data= self.ports This way I expect the object to behave and respond (and be used) the way I mean it to, except I want to get a freebie ordered dictionary behaviour on its property "ports" when it's iterated, items are gotten by key, something is looked up ala if this in myObject, and so on. Any advice welcome, the above seems to be working fine, but I have an odd itch that I might be missing something. Thanks in advance.

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  • form.has_errors tag not working

    - by John
    Hello, Im using Django 1.2.3. I have login functionality in my site using django.contrib.auth.views.login. The user is able to login after entering correct username and password. But, form.has_errors is not working i.e. if the login credentials entered are incorrect i dont see the error message. My login.html in templates/registration is as follows : <html> <head> <title>Login</title> </head> <body> <h1>User Login</h1> {% if form.has_errors %} <p>Your username and password didn't match. Please try again.</p> {% endif %} <form method="post" action="."> {% csrf_token %} <p><label for="id_username">Username:</label> {{ form.username }}</p> <p><label for="id_password">Password:</label> {{ form.password }}</p> <input type="hidden" name="next" value="/" /> <input type="submit" value="login" /> </form> </body> </html> Any way to fix this problem? Please Help Thank You.

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  • Django: Converting an entire Model into a single dictionary

    - by LarrikJ
    Is there a good way in Django to convert an entire model to a dictionary? I mean, like this: class DictModel(models.Model): key = models.CharField(20) value = models.CharField(200) DictModel.objects.all().to_dict() ... with the result being a dictionary with the key/value pairs made up of records in the Model? Has anyone else seen this as being useful for them? Thanks. Update I just wanted to add is that my ultimate goal is to be able to do a simple variable lookup inside a Template. Something like: {{ DictModel.exampleKey }} With a result of DictModel.objects.get(key__exact=exampleKey).value Overall, though, you guys have really surprised me with how helpful allof your responses are, and how different the ways to approach it can be. Thanks a lot.

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  • Why doesn't this work?

    - by Kyle W
    take = raw_input('Please enter the string of numbers that compose code\n\n\t') y = str(take) l = [] for i in xrange(0, len(y), 3):         l.append(str(y[i:i+3])) b = len(l) a = 0 while(a!=b):         c = l[a].replace('444', ' ')         c = l[a].replace('111', 'a')         c = l[a].replace('112', 'b')         c = l[a].replace('113', 'c')         c = l[a].replace('114', 'd')         c = l[a].replace('115', 'e')         etc...         a = a + 1 filename = 'decmes.txt' file = open(filename, 'w') file.write(c) file.close() I can enter anything, just 111 for example and it gives me back the same thing I put in. Maybe it's something dumb, but I can't figure it out.

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  • Permission to view, but not to change! - Django

    - by RadiantHex
    Hi folks, is it possible to give users the permission to view, but not to change or delete. currently in the only permissions I see are "add", "change" and "delete"... but there is no "read/view" in there. I really need this as some users will only be able to consult the admin panel, in order to see what has been added in. Help would be amazing!

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  • Matching Strings: a biological perspective

    - by sun
    Write a function, called constrainedMatchPair which takes three arguments: a tuple representing starting points for the first substring, a tuple representing starting points for the second substring, and the length of the first substring. The function should return a tuple of all members (call it n) of the first tuple for which there is an element in the second tuple (call it k) such that n+m+1 = k, where m is the length of the first substring. Complete the definition def constrainedMatchPair(firstMatch,secondMatch,length):

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  • printing only the last 8 entries in a .csv file

    - by user2341103
    I have an input csv file as below,I want to print only the most recent 8 entries..can anyone provide inputs on how to do this? INPUT:- trend.csv ['2013-06-25 20:01', '10'] ['2013-06-25 20:06', '9'] ['2013-06-25 20:06', '8'] ['2013-06-26 20:06', '7'] ['2013-06-26 20:06', '6'] ['2013-06-26 20:06', '5'] ['2013-06-26 20:06', '4'] ['2013-06-26 20:06', '3'] ['2013-06-26 20:06', '2'] ['2013-06-26 20:08', '1'] OUTPUT:- ['2013-06-25 20:06', '8'] ['2013-06-26 20:06', '7'] ['2013-06-26 20:06', '6'] ['2013-06-26 20:06', '5'] ['2013-06-26 20:06', '4'] ['2013-06-26 20:06', '3'] ['2013-06-26 20:06', '2'] ['2013-06-26 20:08', '1'] import csv #Now read the recent 8 entries and print cr = csv.reader(open("trend.csv","rb")) for row in cr: #print only the recent most 8 entries print row

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  • JavaScript: Is there any "python's Generator" equivalent in JavaScript?

    - by JackSMTV
    Is there any "python's Generator" equivalent in JavaScript? PS: Python's Generator is very memory efficient when we need to do one time iterate through a big array, hash... "Generators are iterables, but you can only read them once. It's because they do not store all the values in memory, they generate the values on the fly" (Python's Generator explained in this thread: The Python yield keyword explained )

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  • speeding up parsing of files

    - by user248237
    the following function parses a CSV file into a list of dictionaries, where each element in the list is a dictionary where the values are indexed by the header of the file (assumed to be the first line.) this function is very very slow, taking ~6 seconds for a file that's relatively small (less than 30,000 lines.) how can I speed it up? def csv2dictlist_raw(filename, delimiter='\t'): f = open(filename) header_line = f.readline().strip() header_fields = header_line.split(delimiter) dictlist = [] # convert data to list of dictionaries for line in f: values = map(tryEval, line.strip().split(delimiter)) dictline = dict(zip(header_fields, values)) dictlist.append(dictline) return (dictlist, header_fields) thanks.

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  • Utilizing a third party application for GitHub in a django project

    - by Smock
    I'm trying to use a third party application located here: git://github.com/Star2Billing/django-audiofield.git I'm using Aptana Studio as my IDE. I created my project and then I clicked on the project and imported the app from the github location. It looked like it imported. I wanted to check that it imported properly before beginning any real coding so I performed manage.py validate. I got a message that stated: "No module named audiofield". I added the app to my Installed Apps settings and followed the installation instructions. I'm not sure if I'm importing it incorrectly. Also, I'm using virtualenv in Aptana. I'm not sure if this may have added to the problem. Please help.

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  • Run a shell command from Django

    - by Badifunky
    Hello, I'm developing a web page in Django (using apache server) that needs to call a shell command to enable/dissable some daemons. I'm try to do it with os.system(service httpd restart 1>$HOME/out 2>$HOME/error) and this command doesn't return anything. Any idea how can i fix this?

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  • Python3k parse string re help

    - by dsaccount1
    "8,5,,1,4,7,,,,7,,1,9,3,6,,,8,6,3,9,,2,5,4,,,,,3,2,,,7,4,1,1,,4,,6,9,,5,,,,5,,,1,,6,3,,,6,5,,,,7,4,,1,7,6,,,,8,,5,,,7,1,,3,9," I'm doing a programming challenge where i need to parse this sequence into my sudoku script. Need to get the above sequence into 8,5,0,1,4,7,0,0,0,7,0,1,9,3,6,0,0,8......... I tried re but without success, help is appreciated, thanks.

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  • Dividing a string into list according to the format given

    - by user506710
    Hello all , I have a string like "SAB_bARGS_D" . What I want is that the string gets divided into list of characters but whenever there is a _ sign the next character gets appended to the previous one. So the answer to above should be ['S','A','B_b','A','R','G','S_D'] It can be done by using a for loop traversing through the list but is there an inbuilt function that I can use..... Thanks a lot

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  • Partially fattening a list

    - by alj
    This is probably a really silly question but, given the example code at the bottom, how would I get a single list that retain the tuples? (I've looked at the itertools but it flattens everything) What I currently get is: ('id', 20, 'integer') ('companyname', 50, 'text') [('focus', 30, 'text'), ('fiesta', 30, 'text'), ('mondeo', 30, 'text'), ('puma', 30, 'text')] ('contact', 50, 'text') ('email', 50, 'text') what I would like is a single level list like: ('id', 20, 'integer') ('companyname', 50, 'text') ('focus', 30, 'text') ('fiesta', 30, 'text') ('mondeo', 30, 'text') ('puma', 30, 'text') ('contact', 50, 'text') ('email', 50, 'text') def getproducts(): temp_list=[] product_list=['focus','fiesta','mondeo','puma'] #usually this would come from a db for p in product_list: temp_list.append((p,30,'text')) return temp_list def createlist(): column_title_list = ( ("id",20,"integer"), ("companyname",50,"text"), getproducts(), ("contact",50,"text"), ("email",50,"text"), ) return column_title_list for item in createlist(): print item Thanks ALJ

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