Partially fattening a list
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            by alj
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        Published on 2010-05-29T13:44:50Z
        Indexed on 
            2010/05/29
            13:52 UTC
        
        
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python
This is probably a really silly question but, given the example code at the bottom, how would I get a single list that retain the tuples?
(I've looked at the itertools but it flattens everything)
What I currently get is:
('id', 20, 'integer')
('companyname', 50, 'text')
[('focus', 30, 'text'), ('fiesta', 30, 'text'), ('mondeo', 30, 'text'), ('puma', 30, 'text')]
('contact', 50, 'text')
('email', 50, 'text')
what I would like is a single level list like:
('id', 20, 'integer')
('companyname', 50, 'text')
('focus', 30, 'text')
('fiesta', 30, 'text')
('mondeo', 30, 'text')
('puma', 30, 'text')
('contact', 50, 'text')
('email', 50, 'text')
def getproducts():
    temp_list=[]
    product_list=['focus','fiesta','mondeo','puma'] #usually this would come from a db
    for p in product_list:
        temp_list.append((p,30,'text'))
    return temp_list
def createlist():    
    column_title_list = (
                                    ("id",20,"integer"),
                                    ("companyname",50,"text"),
                                    getproducts(), 
                                    ("contact",50,"text"),
                                    ("email",50,"text"),
                                ) 
    return column_title_list
for item in createlist():
    print item
Thanks
ALJ
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