Search Results

Search found 15449 results on 618 pages for 'python signal'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 419/618 | < Previous Page | 415 416 417 418 419 420 421 422 423 424 425 426  | Next Page >

  • Display graph without saving using pydot

    - by user506710
    Hello all I am trying to display a simple graph using pydot. My question is that is there any way to display the graph without writing it to a file as currently I use write function to first draw and then have to use the Image module to show the files. However is there any way that the graph directly gets printed on the screen without being saved ?? Also as an update I would like to ask in this same question that I observe that while the image gets saved very quickly when I use the show command of the Image module it takes noticeable time for the image to be seen .... Also sometimes I get the error that the image could'nt be opened because it was either deleted or saved in unavailable location which is not correct as I am saving it at my Desktop..... Does anyone know what's happening and is there a faster way to get the image loaded..... Thanks a lot....

    Read the article

  • Converting time period strings to value/unit pair

    - by randomtoor
    I need to parse the contents of a string that represents a time period. The format of the string is value/unit, e.g.: 1s, 60min, 24h. I would separate the actual value (an int) and unit (a str) to separated variables. At the moment I do it like this: def validate_time(time): binsize = time.strip() unit = re.sub('[0-9]','',binsize) if unit not in ['s','m','min','h','l']: print "Error: unit {0} is not valid".format(unit) sys.exit(2) tmp = re.sub('[^0-9]','',binsize) try: value = int(tmp) except ValueError: print "Error: {0} is not valid".format(time) sys.exit(2) return value,unit However, it is not ideal as things like 1m0 are also (wrongly) validated (value=10,unit=m). What is the best way to validate/parse this input?

    Read the article

  • Creating tables with pylons and SQLAlchemy

    - by Sid
    I'm using SQLAlchemy and I can create tables that I have defined in /model/__init__.py but I have defined my classes, tables and their mappings in other files found in the /model directory. For example I have a profile class and a profile table which are defined and mapped in /model/profile.py To create the tables I run: paster setup-app development.ini But my problem is that the tables that I have defined in /model/__init__.py are created properly but the table definitions found in /model/profile.py are not created. How can I execute the table definitions found in the /model/profile.py so that all my tables can be created? Thanks for the help!

    Read the article

  • How do I parse youtube xml for a specific entry?

    - by sharataka
    I am trying to return the duration of the video but am having trouble. #YOUTUBE FEED #download the file: file = urllib2.urlopen('http://gdata.youtube.com/feeds/api/videos/2s0vk2wEMtA') #convert to string: data = file.read() #close file because we dont need it anymore: file.close() #entire feed root = etree.fromstring(data) for entry in root: for item in entry: print item When I print item, I see as the last element: Element '{http://gdata.youtube.com/schemas/2007}duration' at 0x10c4fb7d0 But I don't know how to get the value from this. Any advice?

    Read the article

  • What is the proper way to check the previous value of a field before saving an object? (Using Django

    - by anonymous coward
    I have a Django Model with updated_by and an approved_by fields, both are ForeignKey fields to the built-in (auth) User models. I am aware that with updated_by, it's easy enough to simply over-ride the .save() method on the Model, and shove the request.user in that field before saving. However, for approved_by, this field should only ever be filled in when a related field (date_approved) is first filled in. I'm somewhat certain that I can check this logically, and fill in the field if the previous value was empty. What is the proper way to check the previous value of a field before saving an object? I do not anticipate that date_approved will ever be changed or updated, nor should there be any reason to ever update the approved_by entry. UPDATE: Regarding forms/validation, I should have mentioned that none of the fields in question are seen by or editable by users of the site. If I have misunderstood, I'm sorry, but I'm not sure how forms and validation apply to my question.

    Read the article

  • [Django] How do I filter the choices in a ModelForm that has a CharField with the choices attribute

    - by nubela
    I understand I am able to filter queryset of Foreignkey or Many2ManyFields, however, how do I do that for a simple CharField that is a Select Widget (Select Tag). For example: PRODUCT_STATUS = ( ("unapproved", "Unapproved"), ("approved", "Listed"), #("Backorder","Backorder"), #("oos","Out of Stock"), #("preorder","Preorder"), ("userdisabled", "User Disabled"), ("disapproved", "Disapproved by admin"), ) and the Field: o_status = models.CharField(max_length=100, choices=PRODUCT_STATUS, verbose_name="Product Status", default="approved") Suppose I wish to limit it to just "approved" and "userdisabled" instead showing the full array (which is what I want to show in the admin), how do I do it? Thanks!

    Read the article

  • Sqlalchemy: Many to Many relationship error

    - by 1001010101
    Dear everyone, I am following the Many to many relationship described on http://www.sqlalchemy.org/docs/mappers.html#many-to-many #This is actually a VIEW tb_mapping_uGroups_uProducts = Table( 'mapping_uGroups_uProducts', metadata, Column('upID', Integer, ForeignKey('uProductsInfo.upID')), Column('ugID', Integer, ForeignKey('uGroupsInfo.ugID')) ) tb_uProducts = Table( 'uProductsInfo', metadata, Column('upID', Integer, primary_key=True) ) mapper( UnifiedProduct, tb_uProducts) tb_uGroupsInfo = Table( 'uGroupsInfo', metadata, Column('ugID', Integer, primary_key=True) ) mapper( UnifiedGroup, tb_uGroupsInfo, properties={ 'unifiedProducts': relation(UnifiedProduct, secondary=tb_mapping_uGroups_uProducts, backref="unifiedGroups") }) where the relationship between uProduct and uGroup are N:M. When I run the following sess.query(UnifiedProduct).join(UnifiedGroup).distinct()[:10] I am getting the error: sqlalchemy.exc.ArgumentError: Can't find any foreign key relationships between 'uProductsInfo' and 'uGroupsInfo' What am I doing wrong?

    Read the article

  • Find all A^x in a given range

    - by Austin Henley
    I need to find all monomials in the form AX that when evaluated falls within a range from m to n. It is safe to say that the base A is greater than 1, the power X is greater than 2, and only integers need to be used. For example, in the range 50 to 100, the solutions would be: 2^6 3^4 4^3 My first attempt to solve this was to brute force all combinations of A and X that make "sense." However this becomes too slow when used for very large numbers in a big range since these solutions are used in part of much more intensive processing. Here is the code: def monoSearch(min, max): base = 2 power = 3 while 1: while base**power < max: if base**power > min: print "Found " + repr(base) + "^" + repr(power) + " = " + repr(base**power) power = power + 1 base = base + 1 power = 3 if base**power > max: break I could remove one base**power by saving the value in a temporary variable but I don't think that would make a drastic effect. I also wondered if using logarithms would be better or if there was a closed form expression for this. I am open to any optimizations or alternatives to finding the solutions.

    Read the article

  • filter queryset based on list, including None

    - by jujule
    Hi all I dont know if its a django bug or a feature but i have a strange ORM behaviour with MySQL. class Status(models.Model): name = models.CharField(max_length = 50) class Article(models.Model) status = models.ForeignKey(status, blank = True, null=True) filters = Q(status__in =[0, 1,2] ) | Q(status=None) items = Article.objects.filter(filters) this returns Article items but some have other status than requested [0,1,2,None] looking at the sql query : SELECT [..] FROM `app_article` LEFT OUTER JOIN `app_status` ON (`app_article`.`status_id` = `app_status`.`id`) WHERE (`app_article`.`status_id` IN (1, 2) OR `app_status`.`id` IS NULL) ORDER BY [...] the OR app_status.id IS NULL part seems to be the cause. if i change it to OR app_article.status_id IS NULL it works correctly. How to deal with this ? Thanx.

    Read the article

  • Extending appengine's db.Property with caching

    - by Noio
    I'm looking to implement a property class for appengine, very similar to the existing db.ReferenceProperty. I am implementing my own version because I want some other default return values. My question is, how do I make the property remember its returned value, so that the datastore query is only performed the first time the property is fetched? What I had is below, and it does not work. I read that the Property classes do not belong to the instances, but to the model definition, so I guess that the return value is not cached for each instance, but overwritten on the model every time. Where should I store this _resolved variable? class PageProperty(db.Property): data_type = Page def get_value_for_datastore(self, model_instance): page = super(PageProperty, self).get_value_for_datastore(model_instance) self._resolved = page return page.key().name() def make_value_from_datastore(self, value): if not hasattr(self, '_resolved'): self._resolved = Page.get_by_name(value) return self._resolved

    Read the article

  • How to get attributes from parent?

    - by bribon
    Hi all, Let's say we have these classes: class Foo(object): _bar = "" def __init__(self): self.bar = "hello" def getBar(self): return self._bar def setBar(self, bar): self._bar = bar def getAttributes(self): for attr in self.__dict__: print attr bar = property(getBar, setBar) class Child(Foo): def __init__(self): super(Child, self).__init__() self.a = "" self.b = "" if I do something like: child = Child() child.getAttributes() I get all the attributes from parent and child. How could I get the attributes only from the parent? Thanks in advance!

    Read the article

  • muti user dungeon help

    - by mudman
    ive created a single user dungeon which i would like to create into a multi user dungoen so at least two plays can play how would i do that what code do i need to add can anyone help? i would show coding but if i do then everyone would see it and all my work will be copied as i know other students do use this site to so plz understand my situation and yes this is a homework/assignment work.

    Read the article

  • UnicodeDecodeError from a GET-parameter in webapp2

    - by Aneon
    I'm getting a UnicodeDecodeError when recieving a GET-parameter from webapp2 that contains unicode characters, and then using it to do a NDB query. I get the same error message when manually running a unicode() on the parameter in the handler, so there either seems to be a problem in webapp2's URL routing or I've missed something. Preferably, all GET-parameters should be converted to unicode before getting passed into the handler so I don't need to do manual conversions in all of my handlers. I actually think it's worked before in an earlier version. The full error message read: UnicodeDecodeError: 'ascii' codec can't decode byte 0xc3 in position 1: ordinal not in range(128) The GET-parameter contains the following string: göteborg. It looks fine when I raise an Exception on it, but gives me an error when I (or NDB) use unicode() on it. EDIT: In NDB, it fails on the following code: File "C:\Program Files (x86)\Google\google_appengine\google\appengine\api\datastore_types.py", line 1562, in PackString pbvalue.set_stringvalue(unicode(value).encode('utf-8')) Thanks.

    Read the article

  • Returning all "positions" of a list

    - by Daymor
    I Have a list with "a" and "b" and the "b"'s are somewhat of a path and "a"'s are walls. Im writing a program to make a graph of all the possible moves. I got the code running to check the first "b" for possible moves, but i have NO Idea how im going to find all "b"'s , even less check them all without repeating. Major issue im having is getting the tuple coordinates of the "b"'s out of the list. Any pointers/tips?

    Read the article

  • Trouble getting QMainWindow to scroll

    - by random
    A minimal example: class MainWindow(QtGui.QMainWindow): def __init__(self, parent = None): QtGui.QMainWindow.__init__(self, parent) winWidth = 683 winHeight = 784 screen = QtGui.QDesktopWidget().availableGeometry() screenCenterX = (screen.width() - winWidth) / 2 screenCenterY = (screen.height() - winHeight) / 2 self.setGeometry(screenCenterX, screenCenterY, winWidth, winHeight) layout = QtGui.QVBoxLayout() layout.addWidget(FormA()) mainWidget = QtGui.QWidget() mainWidget.setLayout(layout) self.setCentralWidget(mainWidget) FormA is a QFrame with a VBoxLayout that can expand to an arbitrary number of entries. In the code posted above, if the entries in the forms can't fit in the window then the window itself grows. I'd prefer for the window to become scrollable. I've also tried the following... replacing mainWidget = QtGui.QWidget() mainWidget.setLayout(layout) self.setCentralWidget(mainWidget) with mainWidget = QtGui.QScrollArea() mainWidget.setLayout(layout) self.setCentralWidget(mainWidget) results in the forms and entries shrinking if they can't fit in the window. Replacing it with mainWidget = QtGui.QWidget() mainWidget.setLayout(layout) scrollWidget = QtGui.QScrollArea() scrollWidget.setWidget(mainWidget) self.setCentralWidget(scrollWidget) results in the mainwidget (composed of the forms) being scrunched in the top left corner of the window, leaving large blank areas on the right and bottom of it, and still isn't scrollable. I can't set a limit on the size of the window because I wish for it to be resizable. How can I make this window scrollable?

    Read the article

  • Creating readable html with django templates

    - by rileymat
    When using Django for html templating how do I create good html markup formatting. I am trying to make use of content blocks. But the content blocks show up at different levels of indentation in different templates. How do I get the content blocks to show indented like it would be if someone was to hand write the html. I am having the same problem with newlines; I can smash all the blocks together in the template. At that point the html looks better, but the templates are unmaintainable. I guess the question is how to you create pretty html markup with the django templating system?

    Read the article

  • Project Euler: problem 8

    - by Marijus
    n = # some ridiculously large number, omitted N = [int(i) for i in str(n)] maxProduct = 0 for i in range(0,len(N)-4): newProduct = 1 is_cons = 0 for j in range(i,i+4): if N[j] == N[j+1] - 1: is_cons += 1 if is_cons == 5: for j in range(i,i+5): newProduct *= N[j] if newProduct > maxProduct: maxProduct = newProduct print maxProduct I've been working on this problem for hours now and I can't get this to work. I've tried doing this algorithm on paper and it works just fine.. Could you give me hints what's wrong ?

    Read the article

  • indexing for faster search of lists in a file??

    - by kaushik
    i have a file having around 1 lakh lists and have a another file with again a list of around an average of 50.. I want to compare 2nd item of list in second file with the 2nd element of 1st file and repeat this for each of the 50 lists in 2nd file and get the result of all the matching element. I have written the code for all this,but this is taking a lot of time as it need to check the whole the 1lakh list some 50 times..i want to improve the speed... please tell me how can i do this.... i cant not post my code as it is part of big code and will be difficult to infer anything from that... please tell what can be done to improve the speed?? thank u,

    Read the article

  • nested list comprehension using intermediate result

    - by KentH
    I am trying to grok the output of a function which doesn't have the courtesy of setting a result code. I can tell it failed by the "error:" string which is mixed into the stderr stream, often in the middle of a different conversion status message. I have the following list comprehension which works, but scans for the "error:" string twice. Since it is only rescanning the actual error lines, it works fine, but it annoys me I can't figure out how to use a single scan. Here's the working code: errors = [e[e.find('error:'):] for e in err.splitlines() if 'error:' in e] The obvious (and wrong) way to simplify is to save the "find" result errors = [e[i:] for i in e.find('error:') if i != -1 for e in err.splitlines()] However, I get "UnboundLocalError: local variable 'e' referenced before assignment". Blindly reversing the 'for's in the comprehension also fails. How is this done? THanks. Kent

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 415 416 417 418 419 420 421 422 423 424 425 426  | Next Page >