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  • PAM authentication problem

    - by mdipierro
    I am using this module to authenticate using pam: http://code.google.com/p/web2py/source/browse/gluon/contrib/pam.py I can call authenticate('username','password') and it returns True/ False. It works for any 'username' but 'root'. My guess is that there is a security restriction in PAM that does not allow to check for the root password. I need to be able to check the root password. Is there anything I can change in the pam.conf or somewhere else to remove this restriction?

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  • I get a 400 Bad Request error while using django-piston

    - by Cheezo
    Hello, I am trying to use Piston to provide REST support to Django. I have implemented my handlers as per the documentation provided . The problem is that i can "read" and "delete" my resource but i cannot "create" or "update". Each time i hit the relevant api i get a 400 Bad request Error. I have extended the Resource class for csrf by using this commonly available code snippet: class CsrfExemptResource(Resource): """A Custom Resource that is csrf exempt""" def init(self, handler, authentication=None): super(CsrfExemptResource, self).init(handler, authentication) self.csrf_exempt = getattr(self.handler, 'csrf_exempt', True) My class (code snippet) looks like this: user_resource = CsrfExemptResource(User) class User(BaseHandler): allowed_methods = ('GET', 'POST', 'PUT', 'DELETE') @require_extended def create(self, request): email = request.GET['email'] password = request.GET['password'] phoneNumber = request.GET['phoneNumber'] firstName = request.GET['firstName'] lastName = request.GET['lastName'] self.createNewUser(self, email,password,phoneNumber,firstName,lastName) return rc.CREATED Please let me know how can i get the create method to work using the POST operation?

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  • Problem bounding name to a class in Django

    - by martinthenext
    Hello! I've got a view function that has to decide which form to use depending on some conditions. The two forms look like that: class OpenExtraForm(forms.ModelForm): class Meta: model = Extra def __init__(self, *args, **kwargs): super(OpenExtraForm, self).__init__(*args, **kwargs) self.fields['opening_challenge'].label = "lame translation" def clean_opening_challenge(self): challenge = self.cleaned_data['opening_challenge'] if challenge is None: raise forms.ValidationError('??????? ???, ??????????? ?????? ???. ???????????') return challenge class HiddenExtraForm(forms.ModelForm): class Meta: model = Extra exclude = ('opening_challenge') def __init__(self, *args, **kwargs): super(HiddenExtraForm, self).__init__(*args, **kwargs) The view code goes like that: @login_required def manage_extra(request, extra_id=None, hidden=False): if not_admin(request.user): raise Http404 if extra_id is None: # Adding a new extra extra = Extra() if hidden: FormClass = HiddenExtraForm else: FormClass = OpenExtraForm else: # Editing an extra extra = get_object_or_404(Extra, pk=extra_id) if extra.is_hidden(): FromClass = HiddenExtraForm else: FormClass = OpenExtraForm if request.POST: form = FormClass(request.POST, instance=extra) if form.is_valid(): form.save() return HttpResponseRedirect(reverse(view_extra, args=[extra.id])) else: form = FormClass(instance=extra) return render_to_response('form.html', { 'form' : form, }, context_instance=RequestContext(request) ) The problem is somehow if extra.is_hidden() returns True, the statement FromClass = HiddenExtraForm doesn't work. I mean, in all other conditions that are used in the code it works fine: the correct Form classes are intantiated and it all works. But if extra.is_hidden(), the debugger shows that the condition is passed and it goes to the next line and does nothing! As a result I get a UnboundLocalVar error which says FormClass hasn't been asssigned at all. Any ideas on what's happening?

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  • Pygame Sprite/Font rendering issues

    - by Grimless
    Hey guys. Here's my problem: I have a game class that maintains a HUD overlay that has a bunch of elements, including header and footer background sprites. Everything was working fine until I added a 1024x128 footer sprite. Now two of my text labels will not render, despite the fact that they DO exist in my Group and self.elements array. Is there something I'm missing? When I take out the footerHUDImage line, all of the labels render correctly and everything works fine. When I add the footerHUDImage, two of the labels (the first two) no longer render and the third only sometimes renders. HELP PLEASE! Here is the code: class AoWHUD (object): def __init__(self, screen, delegate, dataSource): self.delegate = delegate self.dataSource = dataSource self.elements = [] headerHudImage = KJRImage("HUDBackground.png") self.elements.append(headerHudImage) headerHudImage.userInteractionEnabled = True footerHUDImage = KJRImage("ControlsBackground.png") self.elements.append(footerHUDImage) footerHUDImage.rect.bottom = screen.get_rect().height footerHUDImage.userInteractionEnabled = True lumberMessage = "Lumber: " + str(self.dataSource.lumber) lumberLabel = KJRLabel(lumberMessage, size = 48, color = (240, 200, 10)) lumberLabel.rect.topleft = (_kSpacingMultiple * 0, 0) self.elements.append(lumberLabel) stoneMessage = "Stone: " + str(self.dataSource.stone) stoneLabel = KJRLabel(stoneMessage, size = 48, color = (240, 200, 10)) stoneLabel.rect.topleft = (_kSpacingMultiple * 1, 0) self.elements.append(stoneLabel) metalMessage = "Metal: " + str(self.dataSource.metal) metalLabel = KJRLabel(metalMessage, size = 48, color = (240, 200, 10)) metalLabel.rect.topleft = (_kSpacingMultiple * 2, 0) self.elements.append(metalLabel) foodMessage = "Food: " + str(len(self.dataSource.units)) + "/" + str(self.dataSource.food) foodLabel = KJRLabel(foodMessage, size = 48, color = (240, 200, 10)) foodLabel.rect.topleft = (_kSpacingMultiple * 3, 0) self.elements.append(foodLabel) self.selectionSprites = {32 : pygame.image.load("Selected32.png").convert_alpha(), 64 : pygame.image.load("Selected64.png")} self._sprites_ = pygame.sprite.Group() for e in self.elements: self._sprites_.add(e) print self.elements def draw(self, screen): if self.dataSource.resourcesChanged: lumberMessage = "Lumber: " + str(self.dataSource.lumber) stoneMessage = "Stone: " + str(self.dataSource.stone) metalMessage = "Metal: " + str(self.dataSource.metal) foodMessage = "Food: " + str(len(self.dataSource.units)) + "/" + str(self.dataSource.food) self.elements[2].setText(lumberMessage) self.elements[2].rect.topleft = (_kSpacingMultiple * 0, 0) self.elements[3].setText(stoneMessage) self.elements[3].rect.topleft = (_kSpacingMultiple * 1, 0) self.elements[4].setText(metalMessage) self.elements[4].rect.topleft = (_kSpacingMultiple * 2, 0) self.elements[5].setText(foodMessage) self.elements[5].rect.topleft = (_kSpacingMultiple * 3, 0) self.dataSource.resourcesChanged = False self._sprites_.draw(screen) if self.delegate.selectedUnit: theSelectionSprite = self.selectionSprites[self.delegate.selectedUnit.rect.width] screen.blit(theSelectionSprite, self.delegate.selectedUnit.rect)

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  • How to set up Atana Studio 3 Themes in Pydev

    - by willy1234x1
    I've installed the Aptana Studio 3 preview and noticed it has support for themes (such as a bespin style or Ruby envy) and I'd love to use the Bespin one in Pydev but so far I've had no luck getting it to work, anyone have a clue as to how to get it to work? Video showing the themes in action.

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  • How to call the __del__ method?

    - by Verrtex
    I am reading a code. There is a class in which __del__ method is defined. I figured out that this method is used to destroy an instance of the class. However, I cannot find a place where this method is used. The main reason for that is that I do not know how this method is used, probably not like that: obj1.del(). So, my questions is how to call the __del__ method? Thank you for any help.

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  • Editting ForeignKey from "child" table

    - by profuel
    I'm programming on py with django. I have models: class Product(mymodels.Base): title = models.CharField() price = models.ForeignKey(Price) promoPrice = models.ForeignKey(Price, related_name="promo_price") class Price(mymodels.Base): value = models.DecimalField(max_digits=10, decimal_places=3) taxValue = models.DecimalField("Tax Value", max_digits=10, decimal_places=3) valueWithTax = models.DecimalField("Value with Tax", max_digits=10, decimal_places=3) I want to see INPUTs for both prices when editing product, but cannot find any possibility to do that. inlines = [...] works only from Price to Product, which is stupid in this case. Thanx for adnvance.

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  • Numpy modify array in place?

    - by User
    I have the following code which is attempting to normalize the values of an m x n array (It will be used as input to a neural network, where m is the number of training examples and n is the number of features). However, when I inspect the array in the interpreter after the script runs, I see that the values are not normalized; that is, they still have the original values. I guess this is because the assignment to the array variable inside the function is only seen within the function. How can I do this normalization in place? Or do I have to return a new array from the normalize function? import numpy def normalize(array, imin = -1, imax = 1): """I = Imin + (Imax-Imin)*(D-Dmin)/(Dmax-Dmin)""" dmin = array.min() dmax = array.max() array = imin + (imax - imin)*(array - dmin)/(dmax - dmin) print array[0] def main(): array = numpy.loadtxt('test.csv', delimiter=',', skiprows=1) for column in array.T: normalize(column) return array if __name__ == "__main__": a = main()

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  • Get particular row as series from pandas dataframe

    - by Pratyush
    How do we get a particular filtered row as series? Example dataframe: >>> df = pd.DataFrame({'date': [20130101, 20130101, 20130102], 'location': ['a', 'a', 'c']}) >>> df date location 0 20130101 a 1 20130101 a 2 20130102 c I need to select the row where location is c as a series. I tried: row = df[df["location"] == "c"].head(1) # gives a dataframe row = df.ix[df["location"] == "c"] # also gives a dataframe with single row In either cases I can't the row as series.

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  • Euclidian Distances between points

    - by R S
    I have an array of points in numpy: points = rand(dim, n_points) And I want to: Calculate all the l2 norm (euclidian distance) between a certain point and all other points Calculate all pairwise distances. and preferably all numpy and no for's.

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  • How to reset Scrapy parameters? (always running under same parameters)

    - by Jean Ventura
    I've been running my Scrapy project with a couple of accounts (the project scrapes a especific site that requieres login credentials), but no matter the parameters I set, it always runs with the same ones (same credentials). I'm running under virtualenv. Is there a variable or setting I'm missing? Edit: It seems that this problem is Twisted related. Even when I run: scrapy crawl -a user='user' -a password='pass' -o items.json -t json SpiderName I still get an error saying: ERROR: twisted.internet.error.ReactorNotRestartable And all the information I get, is the last 'succesful' run of the spider.

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  • Counting amount of items in Pythons 'for'

    - by Markum
    Kind of hard to explain, but when I run something like this: fruits = ['apple', 'orange', 'banana', 'strawberry', 'kiwi'] for fruit in fruits: print fruit.capitalize() It gives me this, as expected: Apple Orange Banana Strawberry Kiwi How would I edit that code so that it would "count" the amount of times it's performing the for, and print this? 1 Apple 2 Orange 3 Banana 4 Strawberry 5 Kiwi

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  • Finding matching submatrics inside a matrix

    - by DaveO
    I have a 100x200 2D array expressed as a numpy array consisting of black (0) and white (255) cells. It is a bitmap file. I then have 2D shapes (it's easiest to think of them as letters) that are also 2D black and white cells. I know I can naively iterate through the matrix but this is going to be a 'hot' portion of my code so speed is an concern. Is there a fast way to perform this in numpy/scipy? I looked briefly at Scipy's correlate function. I am not interested in 'fuzzy matches', only exact matches. I also looked at some academic papers but they are above my head.

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  • SQLAlchemy returns tuple not dictionary

    - by Ivan
    Hi everyone, I've updated SQLAlchemy to 0.6 but it broke everything. I've noticed it returns tuple not a dictionary anymore. Here's a sample query: query = session.query(User.id, User.username, User.email).filter(and_(User.id == id, User.username == username)).limit(1) result = session.execute(query).fetchone() This piece of code used to return a dictionary in 0.5. My question is how can I return a dictionary?

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  • wxPython: Change a buttons text in a wx.FileDialog

    - by Sascha
    Hello I have a wx.FileDialog (with the wx.FD_OPEN flag) & I would like to know if I can (& how) I could change the button in the bottom right of the FileDialog from "Open" to "Create" or "Delete", etc. What I am doing is I have a button with the text "Delete Portfolio", when pressed it opens a FileDialog & allows the user to select a portfolio file(.db) to delete. So instead of the File Dialog's bottom right confirm button displaying "Open" I would like to be able to change the text to "Confirm" or "Delete" or whatever. Is this possible, its a rather superficial thing to do, but if the button says open when the user wants to select a file to delete, it can be a little confusing even if the title of the dialog says "please select a file to delete"

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  • Joining different models in Django

    - by Andrew Roberts
    Let's say I have this data model: class Workflow(models.Model): ... class Command(models.Model): workflow = models.ForeignKey(Workflow) ... class Job(models.Model): command = models.ForeignKey(Command) ... Suppose somewhere I want to loop through all the Workflow objects, and for each workflow I want to loop through its Commands, and for each Command I want to loop through each Job. Is there a way to structure this with a single query? That is, I'd like Workflow.objects.all() to join in its dependent models, so I get a collection that has dependent objects already cached, so workflows[0].command_set.get() doesn't produce an additional query. Is this possible?

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  • foreignkey problem

    - by realshadow
    Hey, Imagine you have this model: class Category(models.Model): node_id = models.IntegerField(primary_key = True) type_id = models.IntegerField(max_length = 20) parent_id = models.IntegerField(max_length = 20) sort_order = models.IntegerField(max_length = 20) name = models.CharField(max_length = 45) lft = models.IntegerField(max_length = 20) rgt = models.IntegerField(max_length = 20) depth = models.IntegerField(max_length = 20) added_on = models.DateTimeField(auto_now = True) updated_on = models.DateTimeField(auto_now = True) status = models.IntegerField(max_length = 20) node = models.ForeignKey(Category_info, verbose_name = 'Category_info', to_field = 'node_id' The important part is the foreignkey. When I try: Category.objects.filter(type_id = 15, parent_id = offset, status = 1) I get an error that get returned more than category, which is fine, because it is supposed to return more than one. But I want to filter the results trough another field, which would be type id (from the second Model) Here it is: class Category_info(models.Model): objtree_label_id = models.AutoField(primary_key = True) node_id = models.IntegerField(unique = True) language_id = models.IntegerField() label = models.CharField(max_length = 255) type_id = models.IntegerField() The type_id can be any number from 1 - 5. I am desparately trying to get only one result where the type_id would be number 1. Here is what I want in sql: SELECT c.*, ci.* FROM category c JOIN category_info ci ON (c.node_id = ci.node_id) WHERE c.type_id = 15 AND c.parent_id = 50 AND ci.type_id = 1 Any help is GREATLY appreciated. Regards

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  • Django and json request

    - by Hulk
    In a template i have the following code <script> var url="/mypjt/my_timer" $.post(url, paramarr, function callbackHandler(dict) { alert('got response back'); if (dict.flag == 2) { alert('1'); $.jGrowl("Data could not be saved"); } else if(dict.ret_status == 1) { alert('2'); $.jGrowl("Data saved successfully"); window.location = "/mypjt/display/" + dict.rid; } }, "json" ); </script> In views i have the following code, def my_timer(request): dict={} try: a= timer.objects.get(pk=1) dict({'flag':1}) return HttpResponse(simplejson.dumps(dict), mimetype='application/javascript') except: dict({'flag':1}) return HttpResponse(simplejson.dumps(dict), mimetype='application/javascript') My question is since we are making a json request and in the try block ,after setting the flag ,cant we return a page directly as return render_to_response('mypjt/display.html',context_instance=RequestContext(request,{'dict': dict})) instead of sending the response, because on success again in the html page we redirect the code Also if there is a exception then only can we return the json request. My only concern is that the interaction between client and server should be minimal. Thanks..

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  • How to replace empty string with zero in comma-separated string?

    - by dsaccount1
    "8,5,,1,4,7,,,,7,,1,9,3,6,,,8,6,3,9,,2,5,4,,,,,3,2,,,7,4,1,1,,4,,6,9,,5,,,,5,,,1,,6,3,,,6,5,,,,7,4,,1,7,6,,,,8,,5,,,7,1,,3,9," I'm doing a programming challenge where i need to parse this sequence into my sudoku script. Need to get the above sequence into 8,5,0,1,4,7,0,0,0,7,0,1,9,3,6,0,0,8......... I tried re but without success, help is appreciated, thanks.

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  • django: Changing auto_id of ModelForm based form class

    - by Meilo
    Every time I create an instance of the TestForm specified below, I have to overwrite the standard id format with auto_id=True. How can this be done once only in the form class instead? Any hints are very welcome. views.py from django.forms import ModelForm from models import Test class TestForm(ModelForm): class Meta: model = Test def test(request): form = TestForm(auto_id=True)

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