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  • How detect length of a numpy array with only one element?

    - by mishaF
    I am reading in a file using numpy.genfromtxt which brings in columns of both strings and numeric values. One thing I need to do is detect the length of the input. This is all fine provided there are more than one value read into each array. But...if there is only one element in the resulting array, the logic fails. I can recreate an example here: import numpy as np a = np.array(2.3) len(a) returns an error saying: TypeError: len() of unsized object however, If a has 2 or more elements, len() behaves as one would expect. import numpy as np a = np.array([2.3,3.6]) len(a) returns 2 My concern here is, if I use some strange exception handling, I can't distinguish between a being empty and a having length = 1.

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  • Django & custom auth backend (web service) + no database. How to save stuff in session?

    - by Infinity
    I've been searching here and there, and based on this answer I've put together what you see below. It works, but I need to put some stuff in the user's session, right there inside authenticate. How would I store acme_token in the user's session, so that it will get cleared if they logged out? class AcmeUserBackend(object): # Create a User object if not already in the database? create_unknown_user = False def get_user(self, username): return AcmeUser(id=username) def authenticate(self, username=None, password=None): """ Check the username/password and return an AcmeUser. """ acme_token = ask_another_site_about_creds(username, password) if acme_token: return AcmeUser(id=username) return None ################## from django.contrib.auth.models import User class AcmeUser(User): objects = None # we cannot really use this w/o local DB def save(self): """saving to DB disabled""" pass def get_group_permissions(self): """If you don't make your own permissions module, the default also will use the DB. Throw it away""" return [] # likewise with the other permission defs def get_and_delete_messages(self): """Messages are stored in the DB. Darn!""" return []

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  • Best practice: How to persist simple data without a database in django?

    - by Infinity
    I'm building a website that doesn't require a database because a REST API "is the database". (Except you don't want to be putting site-specific things in there, since the API is used by mostly mobile clients) However there's a few things that normally would be put in a database, for example the "jobs" page. You have master list view, and the detail views for each job, and it should be easy to add new job entries. (not necessarily via a CMS, but that would be awesome) e.g. example.com/careers/ and example.com/careers/77/ I could just hardcode this stuff in templates, but that's no DRY- you have to update the master template and the detail template every time. What do you guys think? Maybe a YAML file? Or any better ideas? Thx

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  • rearranging a list of months

    - by MacUsers
    How can I list the numbers 01 to 12 (one for each of the 12 months) in such a way so that the current month always comes last where the oldest one is first. In other words, if the number is grater than the current month, it's from the previous year. e.g. 02 is Feb, 2011 (the current month right now), 03 is March, 2010 and 09 is Sep, 2010 but 01 is Jan, 2011. In this case, I'd like to have [09, 03, 01, 02]. This is what I'm doing to determine the year: for inFile in os.listdir('.'): if inFile.isdigit(): month = months[int(inFile)] if int(inFile) <= int(strftime("%m")): year = strftime("%Y") else: year = int(strftime("%Y"))-1 mnYear = month + ", " + str(year) I don't have a clue what to do next. What should I do here?

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  • jEdit+JythonInterpreter: how to import java class?

    - by JChao
    Hi, I'm running jEdit with the JythonInterprete and I have a .jar file called JavaTest.jar. JavaTest has a class called SampleJavaClass which has a method printerCount. From my .py file, I want to do: from javatest import SampleJavaClass class SampleClass(SampleJavaClass): def pymain(self): SampleJavaClass.printerCount(4) Java code: package javatest; public class SampleJavaClass { public static void printerCount(int i){ for(int j=0; j< i; j++){ System.out.println("hello world"); } } (etc...) In the JythonInterpreter, I have already tried clicking "Edit Jython Path" and adding the .jar file then running the interpreter again, but it still gives me ImportError: cannot import name SampleJavaClass

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  • Google App Engine: Update model definitons?

    - by Rosarch
    I recently updated one of my models by adding a db.ListProperty(): class DependencyArcTail(db.Model): courses = db.ListProperty(db.Key) ''' newly added ''' forwardLinks = db.ListProperty(db.Key) However, I can't seem to get this to be reflected in the SDK dashboard. I cleared the datastore and reloaded it. Then I ran the procedures that create the DependencyArcTail objects. However, forwardLinks still doesn't show up as an attribute in the SDK dashboard. What's happening?

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  • indexing for faster search of lists in a file??

    - by kaushik
    i have a file having around 1 lakh lists and have a another file with again a list of around an average of 50.. I want to compare 2nd item of list in second file with the 2nd element of 1st file and repeat this for each of the 50 lists in 2nd file and get the result of all the matching element. I have written the code for all this,but this is taking a lot of time as it need to check the whole the 1lakh list some 50 times..i want to improve the speed... please tell me how can i do this.... i cant not post my code as it is part of big code and will be difficult to infer anything from that... please tell what can be done to improve the speed?? thank u,

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  • Get Username from a Cookie

    - by craphunter
    Hi, I use the backend solution from django. I just want to get a username from the cookie or the session_key to get to know the user. How I can do it? from django.contrib.auth.models import User from django.contrib.sessions.models import Session def start(request, template_name="registration/my_account.html"): user_id = request.session.get('session_key') if user_id: name = request.user.username return render_to_response(template_name, locals()) else: return render_to_response('account/noauth.html') Only else is coming up. What am I doing wrong? Am I right then that authenticated means he is logged in? -- Okay this I got! Firstly, if you have some clarification to a question, update the question, don't post an answer or (even worse) another question, as you have done. Secondly, if the user is logged out, by definition he doesn't have a username. I mean the advantage of Cookies is to identify a user again. I just want to place his name on the webpage. Even if he is logged out. Or isnt't it possible?

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  • How to differentiate between method and function in a decorator?

    - by defnull
    I want to write a decorator that acts differently depending on whether it is applied to a function or to a method. def some_decorator(func): if the_magic_happens_here(func): # <---- Point of interest print 'Yay, found a method ^_^ (unbound jet)' else: print 'Meh, just an ordinary function :/' return func class MyClass(object): @some_decorator def method(self): pass @some_decorator def function(): pass I tried inspect.ismethod(), inspect.ismethoddescriptor() and inspect.isfunction() but no luck. The problem is that a method actually is neither a bound nor an unbound method but an ordinary function as long as it is accessed from within the class body. What I really want to do is to delay the actions of the decorator to the point the class is actually instantiated because I need the methods to be callable in their instance scope. For this, I want to mark methods with an attribute and later search for these attributes when the .__new__() method of MyClass is called. The classes for which this decorator should work are required to inherit from a class that is under my control. You can use that fact for your solution. In the case of a normal function the delay is not necessary and the decorator should take action immediately. That is why I wand to differentiate these two cases.

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  • text overlay for tray icon

    - by AnC
    I have a simple tray icon using PyGTK's gtk.StatusIcon: import pygtk pygtk.require('2.0') import gtk statusIcon = gtk.StatusIcon() statusIcon.set_from_stock(gtk.STOCK_EDIT) statusIcon.set_tooltip('Hello World') statusIcon.set_visible(True) gtk.main() How can I add a text label (one or two characters; basically, unread count) to the tooltip - without creating separate images for set_from_file?

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  • How to turn this simple 10 digit hex number back into 8 digits?

    - by Babil
    The algorithm to convert input 8 digit hex number into 10 digit are following: Given that the 8 digit number is: '12 34 56 78' x1 = 1 * 16^8 * 2^3 x2 = 2 * 16^7 * 2^2 x3 = 3 * 16^6 * 2^1 x4 = 4 * 16^4 * 2^4 x5 = 5 * 16^3 * 2^3 x6 = 6 * 16^2 * 2^2 x7 = 7 * 16^1 * 2^1 x8 = 8 * 16^0 * 2^0 Final 10 digit hex is: = x1 + x2 + x3 + x4 + x5 + x6 + x7 + x8 = '08 86 42 98 E8' The problem is - how to go back to 8 digit hex from a given 10 digit hex (for example: 08 86 42 98 E8 to 12 34 56 78) Some sample input and output are following: input output 11 11 11 11 08 42 10 84 21 22 22 33 33 10 84 21 8C 63 AB CD 12 34 52 D8 D0 88 64 45 78 96 32 21 4E 84 98 62 FF FF FF FF 7B DE F7 BD EF

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  • urllib open - how to control the number of retries

    - by user1641071
    how can i control the number of retries of the "opener.open"? for example, in the following code, it will send about 6 "GET" HTTP requests (i saw it in the Wireshark sniffer) before it goes to the " except urllib.error.URLError" success/no-success lines. password_mgr = urllib.request.HTTPPasswordMgrWithDefaultRealm() password_mgr.add_password(None,url, username, password) handler = urllib.request.HTTPBasicAuthHandler(password_mgr) opener = urllib.request.build_opener(handler) try: resp = opener.open(url,None,1) except urllib.error.URLError as e: print ("no success") else: print ("success!")

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  • Yet another list comprehension question

    - by relima
    I had this: if Setting["Language"] == "en": f.m_radioBox3.SetSelection(0) elif Setting["Language"] == "pt": f.m_radioBox3.SetSelection(1) elif Setting["Language"] == "fr": f.m_radioBox3.SetSelection(2) elif Setting["Language"] == "es": f.m_radioBox3.SetSelection(3) Then I did this: Linguas = ["en","pt","fr","es"] a = 0 for i in Linguas: if i == Setting["Language"]: f.m_radioBox3.SetSelection(a) a += 1 Is it possible to further simplify this and make it into a one-liner?

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  • List comprehension, map, and numpy.vectorize performance

    - by mcstrother
    I have a function foo(i) that takes an integer and takes a significant amount of time to execute. Will there be a significant performance difference between any of the following ways of initializing a: a = [foo(i) for i in xrange(100)] a = map(foo, range(100)) vfoo = numpy.vectorize(foo) a = vfoo(range(100)) (I don't care whether the output is a list or a numpy array.) Is there a better way?

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  • List filtering: list comprehension vs. lambda + filter

    - by Agos
    I happened to find myself having a basic filtering need: I have a list and I have to filter it by an attribute of the items. My code looked like this: list = [i for i in list if i.attribute == value] But then i thought, wouldn't it be better to write it like this? filter(lambda x: x.attribute == value, list) It's more readable, and if needed for performance the lambda could be taken out to gain something. Question is: are there any caveats in using the second way? Any performance difference? Am I missing the Pythonic Way™ entirely and should do it in yet another way (such as using itemgetter instead of the lambda)? Thanks in advance

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  • get the list and input from one function and run them in different function

    - by rookie
    i have a programm that generate the list and then i ask them to tell me what they want to do from the menu and this is where my problem start i was able to get the input form the user to different function but when i try to use the if else condition it doesn't check, below are my code def menu(x,l): print (x) if x == 1: return make_table(l) if x == 2: y= input("enter a row (as a number) or a column (as an uppercase letter") if y in [ "1",'2','3']: print("Minmum is:",minimum(y,l)) if x== 3: print ('bye') def main(): bad_filename = True l =[] while bad_filename == True: try: filename = input("Enter the filename: ") fp = open(filename, "r") for f_line in fp: f_str=f_line.strip() f_str=f_str.split(',') for unit_str in f_str: unit=float(unit_str) l.append(unit) bad_filename = False except IOError: print("Error: The file was not found: ", filename) #print(l) condition=True while condition==True: print('1- open\n','2- maximum') x=input("Enter the choice") menu(x,l) main() from the bottom function i can get list and i can get the user input and i can get the data and move it in second function but it wont work after that.thank you

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