Search Results

Search found 111524 results on 4461 pages for 'user mode linux'.

Page 424/4461 | < Previous Page | 420 421 422 423 424 425 426 427 428 429 430 431  | Next Page >

  • Why does eth0 show an IP if I'm booting into runlevel 1?

    - by banjer
    I'm having some issues with networking on a new Linux server I'm building. The OS is SLES 11. When booting into runlevel 1, I see that eth0 is showing an IP. Physically, there is a network cable plugged into the card associated with eth1, and then there is a network cable plugged into a QLogic iSCSI card (eth4, not shown). I've been troubleshooting this for awhile, and it seems like eth0 is somehow getting assigned an IP, even though it isn't configured in Linux or even plugged into the network for that matter. Thoughts? ifconfig -a Here is the ifconfig output (Sorry, I need more rep before I can post images on SF...)

    Read the article

  • Perl missing while installing nginx on centos

    - by Ahoura Ghotbi
    I am trying to install nginx on my server, however it keeps returning "./configure: error: perl 5.6.1 or higher is required" eventhough I have perl v5.8.8!!!! I have already downloaded perl and trying to configure it using the following command : ./configure --with-http_stub_status_module --with-http_perl_module --with-http_flv_module --add-module=nginx_mod_h264_streaming here is the output : [root@fst nginx-0.8.55]# ./configure --with-http_stub_status_module --with-http_perl_module --with-http_flv_module --add-module=nginx_mod_h264_streaming checking for OS + Linux 2.6.18-308.el5 x86_64 checking for C compiler ... found + using GNU C compiler + gcc version: 4.1.2 20080704 (Red Hat 4.1.2-52) checking for gcc -pipe switch ... found checking for gcc builtin atomic operations ... found checking for C99 variadic macros ... found checking for gcc variadic macros ... found checking for unistd.h ... found checking for inttypes.h ... found checking for limits.h ... found checking for sys/filio.h ... not found checking for sys/param.h ... found checking for sys/mount.h ... found checking for sys/statvfs.h ... found checking for crypt.h ... found checking for Linux specific features checking for epoll ... found checking for sendfile() ... found checking for sendfile64() ... found checking for sys/prctl.h ... found checking for prctl(PR_SET_DUMPABLE) ... found checking for sched_setaffinity() ... found checking for crypt_r() ... found checking for sys/vfs.h ... found checking for nobody group ... found checking for poll() ... found checking for /dev/poll ... not found checking for kqueue ... not found checking for crypt() ... not found checking for crypt() in libcrypt ... found checking for F_READAHEAD ... not found checking for posix_fadvise() ... found checking for O_DIRECT ... found checking for F_NOCACHE ... not found checking for directio() ... not found checking for statfs() ... found checking for statvfs() ... found checking for dlopen() ... not found checking for dlopen() in libdl ... found checking for sched_yield() ... found checking for SO_SETFIB ... not found configuring additional modules adding module in nginx_mod_h264_streaming + ngx_http_h264_streaming_module was configured checking for PCRE library ... found checking for system md library ... not found checking for system md5 library ... not found checking for OpenSSL md5 crypto library ... found checking for zlib library ... found checking for perl + perl version: v5.8.8 built for x86_64-linux-thread-multi ./configure: error: perl 5.6.1 or higher is required

    Read the article

  • vim superuser mode

    - by Hulk
    After opening a file in vim,And if that file is created by root .How to change the current user to superuser mode without quitting or before saving. Thanks.

    Read the article

  • Create a Python User() class that both creates new users and modifies existing users

    - by ensnare
    I'm trying to figure out the best way to create a class that can modify and create new users all in one. This is what I'm thinking: class User(object): def __init__(self,user_id): if user_id == -1 self.new_user = True else: self.new_user = False #fetch all records from db about user_id self._populateUser() def commit(self): if self.new_user: #Do INSERTs else: #Do UPDATEs def delete(self): if self.new_user == False: return False #Delete user code here def _populate(self): #Query self.user_id from database and #set all instance variables, e.g. #self.name = row['name'] def getFullName(self): return self.name #Create a new user >>u = User() >>u.name = 'Jason Martinez' >>u.password = 'linebreak' >>u.commit() >>print u.getFullName() >>Jason Martinez #Update existing user >>u = User(43) >>u.name = 'New Name Here' >>u.commit() >>print u.getFullName() >>New Name Here Is this a logical and clean way to do this? Is there a better way? Thanks.

    Read the article

  • How do I connect to mysql from php ?

    - by roberto
    Hi guys. I'm working through examples from a book on php/mysql development. I'm working on a linux/apache environment. I've set up a database and a user. I attempt to connect with this line of code: $db_server = mysql_connect($db_hostname, $db_username, $db_password); I get this error: Warning: mysql_connect() [function.mysql-connect]: Access denied for user 'www-data'@'localhost' (using password: YES) in /var/www/hosts/dj/connect.php on line 3 unable to connect to database: Access denied for user 'www-data'@'localhost' (using password: YES) I can only guess what is happening here: I think www-data is a username for apache. Upon the database connection, the credentials being passed in to mysql are not those of my database user, but rather apache's own credentials. Is that what is happening here? How do I pass in the credentials I've defined for my user ?

    Read the article

  • GNU/Linux: Don't Call Them PC Viruses

    <b>The ERACC Web Log:</b> "The fact that malware are written primarily for PC systems is a given and is well reported in the news. The fact that malware are written primarily for Microsoft Windows based PC systems is often not reported."

    Read the article

  • Hiding some users in the user list of the OSX 10.6 login panel

    - by Lohoris
    Is there a way to show only some users in the login panel? I'm using OSX 10.6, and if I recall correctly I did something like that in a distant past but I really can't find out how. In the system preferences there seem to be nothing like that (neither in Accounts nor in Security, for instance), and Tinkertool does not do that. Google didn't help. edit: I hoped there was a graphical solution, such as while hiding them from the first screen, having also a button like "show all". I guess there isn't or somebody would have answered. Maybe I'll just change the usernames adding leading Z at the start of the usernames of the ones to "hide", so they'll appear lower in the list... :/

    Read the article

  • Linux Uninstalling errors

    - by Zack
    I want to uninstall back-track 5 so I deleted the partitions for back-track os. After deleting the partition that used to be for back-track becomes free space as in picture. But I can't delete that partition nor creating a new partition. I used G-Parted from hiren boot cd but it says there is no partition table, you need to create a partition table. But actually I have 5 partitions already. And I thought of restarting might fix it. But after showing post screen my laptop show grub error. I don't know what to do, and I tried to install back-track again to fix the problem but it also says that i do not have any partitions. I can only boot windows by passing through hiren boot cd. But most of the time My computer is not recognizing the external dvd drive, nor the internal so i have to restart again and again, hoping to catch the time computer recognize the dvd drive. Can I change the boot loader to correct the grub error? SOLVED : I have solved the grub error by writing MBR again by using EasyBCD But I still have the format error.

    Read the article

  • How to encrypt disk transparently without destroying data

    - by aseq
    On a Linux system, be it Debian, Redhat or any distro, I would like to encrypt the disk on the fly. That is, encrypt the disk transparently to the OS whilst it is running, reboots, shuts down etc. In addition it should not destroy data. I know there is (commercial) software for windows that does it. But I need a Linux solution. The solutions I know of do not support this as far as I can see (luks, truecrypt...). Maybe there is some hack or work around available?

    Read the article

  • Compiling ruby1.9.1 hangs and fills swap!

    - by nfm
    I'm compiling Ruby 1.9.1-p376 under Ubuntu 8.04 server LTS (64-bit), by doing the following: $ ./configure $ make $ sudo make install ./configure works without complaints. make hangs indefinitely until all my RAM and swap is gone. It get stuck after the following output: compiling ripper make[1]: Entering directory `/tmp/ruby1.9.1/ruby-1.9.1-p376/ext/ripper' gcc -I. -I../../.ext/include/x86_64-linux -I../.././include -I../.././ext/ripper -I../.. -I../../. -DRUBY_EXTCONF_H=\"extconf.h\" -fPIC -O2 -g -Wall -Wno-parentheses -o ripper.o -c ripper.c If I run the gcc command by hand, with the -v argument to get verbose output, it hangs after the following: Using built-in specs. Target: x86_64-linux-gnu Configured with: ../src/configure -v --enable-languages=c,c++,fortran,objc,obj-c++,treelang --prefix=/usr --enable-shared --with-system-zlib --libexecdir=/usr/lib --without-included-gettext --enable-threads=posix --enable-nls --with-gxx-include-dir=/usr/include/c++/4.2 --program-suffix=-4.2 --enable-clocale=gnu --enable-libstdcxx-debug --enable-objc-gc --enable-mpfr --enable-checking=release --build=x86_64-linux-gnu --host=x86_64-linux-gnu --target=x86_64-linux-gnu Thread model: posix gcc version 4.2.4 (Ubuntu 4.2.4-1ubuntu4) /usr/lib/gcc/x86_64-linux-gnu/4.2.4/cc1 -quiet -v -I. -I../../.ext/include/x86_64-linux -I../.././include -I../.././ext/ripper -I../.. -I../../. -DRUBY_EXTCONF_H="extconf.h" ripper.c -quiet -dumpbase ripper.c -mtune=generic -auxbase-strip ripper.o -g -O2 -Wall -Wno-parentheses -version -fPIC -fstack-protector -fstack-protector -o /tmp/ccRzHvYH.s ignoring nonexistent directory "/usr/local/include/x86_64-linux-gnu" ignoring nonexistent directory "/usr/lib/gcc/x86_64-linux-gnu/4.2.4/../../../../x86_64-linux-gnu/include" ignoring nonexistent directory "/usr/include/x86_64-linux-gnu" ignoring duplicate directory "../.././ext/ripper" ignoring duplicate directory "../../." #include "..." search starts here: #include <...> search starts here: . ../../.ext/include/x86_64-linux ../.././include ../.. /usr/local/include /usr/lib/gcc/x86_64-linux-gnu/4.2.4/include /usr/include End of search list. GNU C version 4.2.4 (Ubuntu 4.2.4-1ubuntu4) (x86_64-linux-gnu) compiled by GNU C version 4.2.4 (Ubuntu 4.2.4-1ubuntu4). GGC heuristics: --param ggc-min-expand=47 --param ggc-min-heapsize=32795 Compiler executable checksum: 6e11fa7ca85fc28646173a91f2be2ea3 I just compiled ruby on another computer for reference, and it took about 10 seconds to print the following output (after the above Compiler executable checksum line): COLLECT_GCC_OPTIONS='-v' '-I.' '-I../../.ext/include/i686-linux' '-I../.././include' '-I../.././ext/ripper' '-I../..' '-I../../.' '-DRUBY_EXTCONF_H="extconf.h"' '-D_FILE_OFFSET_BITS=64' '-fPIC' '-O2' '-g' '-Wall' '-Wno-parentheses' '-o' 'ripper.o' '-c' '-mtune=generic' '-march=i486' as -V -Qy -o ripper.o /tmp/cca4fa7R.s GNU assembler version 2.20 (i486-linux-gnu) using BFD version (GNU Binutils for Ubuntu) 2.20 COMPILER_PATH=/usr/lib/gcc/i486-linux-gnu/4.4.1/:/usr/lib/gcc/i486-linux-gnu/4.4.1/:/usr/lib/gcc/i486-linux-gnu/:/usr/lib/gcc/i486-linux-gnu/4.4.1/:/usr/lib/gcc/i486-linux-gnu/:/usr/lib/gcc/i486-linux-gnu/4.4.1/:/usr/lib/gcc/i486-linux-gnu/ LIBRARY_PATH=/usr/lib/gcc/i486-linux-gnu/4.4.1/:/usr/lib/gcc/i486-linux-gnu/4.4.1/:/usr/lib/gcc/i486-linux-gnu/4.4.1/../../../../lib/:/lib/../lib/:/usr/lib/../lib/:/usr/lib/gcc/i486-linux-gnu/4.4.1/../../../:/lib/:/usr/lib/ COLLECT_GCC_OPTIONS='-v' '-I.' '-I../../.ext/include/i686-linux' '-I../.././include' '-I../.././ext/ripper' '-I../..' '-I../../.' '-DRUBY_EXTCONF_H="extconf.h"' '-D_FILE_OFFSET_BITS=64' '-fPIC' '-O2' '-g' '-Wall' '-Wno-parentheses' '-o' 'ripper.o' '-c' '-mtune=generic' '-march=i486' I have absolutely no clue what could be going wrong here - any ideas where I should start?

    Read the article

  • Try the Linux desktop of the future

    <b>Tux Radar:</b> "For the tinkerers and testers, 2010 is shaping up to be a perfect year. Almost every desktop and application we can think of is going to have a major release, and while release dates and roadmaps always have to be taken with a pinch of salt, many of these projects have built technology and enhancements you can play with now."

    Read the article

  • USB Device first mounted as root, then by user

    - by Petr Marek
    When I connect my Kindle, it shows up as an usb0 media, which I can read but not write (owner = root). However, if I do sudo umount /media/usb0, usb0 gets unmounted and a Kindle media gets mounted properly (is writable etc.). What can cause such strange behavior? It's not only with Kindle, but with Flash drives etc. as well. My /etc/fstab: # /etc/fstab: static file system information. # # Use 'blkid' to print the universally unique identifier for a # device; this may be used with UUID= as a more robust way to name devices # that works even if disks are added and removed. See fstab(5). # # <file system> <mount point> <type> <options> <dump> <pass> proc /proc proc nodev,noexec,nosuid 0 0 # / was on /dev/sda2 during installation UUID=595815c2-d882-4ec8-a2cd-cce70471167c / ext4 errors=remount-ro 0 1 # /boot was on /dev/sda6 during installation #UUID=1340a336-66ca-4743-a6e4-41a307af2dda /boot ext4 defaults 0 3 # swap was on /dev/sda5 during installation UUID=afa49f1d-d505-4166-82a2-2f44548a48c6 none swap sw 0 0 UUID=deb86039-528a-45f3-b5f9-ce528740c94e /data_hdd ext4 defaults 0 2 My groups: petr@sova:~$ groups petr petr : petr adm cdrom sudo dip plugdev fuse lpadmin sambashare bumblebee

    Read the article

  • User directory in path in zsh: not working

    - by Yar
    I'm doing this in my .zshrc PATH="~/scripts:$PATH" and if I do echo $PATH it appears as the first thing in the path. Yet this directory isn't included in the executable path (nor for tab-completion). What am I doing wrong? ls ~/scripts shows the directory as expected. Edit: This works, though... I guess ~ doesn't work in the path? #PATH="~/scripts:$PATH" PATH="/Users/yar/scripts:$PATH"

    Read the article

  • How to evaluate a user against optimal performance?

    - by Alex K
    I have trouble coming up with a system of assigning a rating to player's performance. Well, technically there is is a trivial rating system, but I don't like it because it would mean assigning negative scores, which I think most players will be discouraged by. The problem is that I only know the ideal number of actions to get the desired result. The worst case is infinite number of actions, so there is no obvious scale. The trivial way I referred to above is to take score = (#optimal-moves - #players-moves), with ideal score being zero. However, psychologically people like big numbers. No one wants to win by getting a mark of 0. I wonder if there is a system that someone else has come up with before to solve this problem? Essentially I wish to score the players based on: How close they've come to the ideal solution. Different challenges will have different optimal number of actions, so the scoring system needs to take that into account, e.g. Challenge 1 - max 10 points, Challenge 2 - max 20 points. I don't mind giving the players negative scores if they've performed exceptionally badly, I just don't want all scores to be <=0

    Read the article

  • In-House Generated Certificates Supported for Signing E-Business Suite JAR Files

    - by Elke Phelps (Oracle Development)
    The E-Business Suite uses Java Archive (JAR) files to deliver certain types of E-Business Suite content desktop clients.  Previously we announced the support of securing JAR files with 3072-bit certificates signed by a third-party Certificate Authority (CA).  We now support securing JAR files with in-house generated certificates.  The new steps to use an in-house Certificate Authority for securing JAR files are provided in: Enhanced Signing of Oracle E-Business Suite JAR Files (Note 1207184.1) This enhancement is great news for those of you familiar with the warning that is triggered when using a self-signed certificate.  As a result of supporting self-signed certificates, the following warning can be avoided: Oracle E-Business Suite Release 12 Certified Platforms Linux x86 (Oracle Linux 4, 5) Linux x86 (RHEL 3, 4, 5) Linux x86 (SLES 9, 10) Linux x86-64 (Oracle Linux 4, 5) Linux x86-64 (RHEL 4, 5) Linux x86-64 (SLES 9, 10)  Oracle Solaris on SPARC (64-bit) (8, 9, 10) IBM AIX on Power Systems (64-bit) (5.3, 6.1) IBM Linux on System z** (RHEL 5, SLES 9, SLES 10) HP-UX Itanium (11.23, 11.31) HP-UX PA-RISC (64-bit) (11.11, 11.23, 11.31) Microsoft Windows Server (32-bit) (2003, 2008 for EBS 12.1 only) Oracle E-Business Suite Release 11i Certified Platforms Linux x86 (Oracle Enterprise Linux 4, 5) Linux x86 (RHEL 3, 4, 5) Linux x86 (SLES 8, 9, 10) Linux x86 (Asianux 1.0) Oracle Solaris on SPARC (64-bit) (8, 9, 10) IBM AIX on Power Systems (64-bit) (5.3, 6.1) HP-UX PA-RISC (64-bit) (11.11, 11.23, 11.31) HP Tru64 (5.1b) Microsoft Windows Server (32-bit) (2000, 2003) References Enhanced Signing of Oracle E-Business Suite JAR Files (Note 1207184.1) Related Articles Two New Options for Signing E-Business Suite JAR Files Now Available What Are the Minimum Desktop Requirements for EBS? Internet Explorer 9 Certified with Oracle E-Business Suite

    Read the article

  • Aser Aspire 3690 WIreless Not working, new Ubuntu user

    - by drew
    I don't know that much about Ubuntu, but I put it on an Acer Aspire 3690 Laptop (replaced Win Vista). Everything seems to work fine, but the wireless connection. It says "FIRMWARE MISSING". It detects that I have a wireless card, so I don't know what to do. I've already used the "ADDITIONAL DRIVERS" thing, and that didn't work. I've googled and have not found anything helpful. I don't really know what I'm doing, so can your directions please be kindergarden level? Thank you very much for any help you can provide. I really appreciate it.

    Read the article

  • Upload/Download images to FTP without bothering the user

    - by Dan B
    Hi, I know a lot of posts have been made in regards to FTP, but none have led me to what I need. I'm trying to upload a picture to a server (currently attempting FTP) but do it without notifying requiring the user to be involved. I want to be able to seamlessly upload/download the image when a certain user action occurs, but I don't want to use a third-party app like AndFTP. The idea is that a user will upload a picture, and then another user will be able to grab that picture based on which user put it up. No user will know where it's going or where it came from, nor will they navigate the FTP. Alternatively, does anyone have thoughts on a better way to do that? I thought of using the imgur api, but it can't be used commercially. It would, however, be perfect for my purposes. Is there a similar open-source alternative? Any help is greatly appreciated. Dan

    Read the article

< Previous Page | 420 421 422 423 424 425 426 427 428 429 430 431  | Next Page >