Search Results

Search found 56516 results on 2261 pages for 'mysql create'.

Page 425/2261 | < Previous Page | 421 422 423 424 425 426 427 428 429 430 431 432  | Next Page >

  • Objective-C: How to create a method that will return a UInt8 array from an int

    - by Adam
    I need to create an Objective-C method that converts an int into a byte array. In this instance, I can't use NSArray as a return type, it must be an UInt8 array. I've written a simple method to do this, but it has errors during compile and tells me that I have incompatible return types. Here is the code snippet. Any ideas? - (UInt8[])ConvertToBytes:(int) i { UInt8 *retVal[4]; retVal[0] = i >> 24; retVal[1] = i >> 16; retVal[2] = i >> 8; retVal[3] = i >> 0; return retVal; }

    Read the article

  • PHP mysqli Insert not working, but not giving any errors.

    - by asdasdas
    As the title says Im trying to do a simple insert, but nothing actually is inserted into the table. I try to print out errors, but nothing is reported. My users table has many more fields than these 4, but they should all default. $query = 'INSERT INTO users (username, password, level, name) VALUES (?, ?, ?, ?)'; if($stmt = $db -> prepare($query)) { $stmt -> bind_param('ssis', $username, $password, $newlevel, $realname); $stmt -> execute(); $stmt -> close(); echo 'Any Errors: '.$db->error.PHP_EOL; } There are no errors given, but when I go to look at the table in phpmyadmin there is not a new row added. I know for sure that the types are correct (strings and integers). Is there something really wrong here or does it have something to do with the fact that I'm ignoring other columns. I have about 8 columns in the user table.

    Read the article

  • Android Create Layered drawable in XML

    - by Lyubomyr Dutko
    Hello, I would like to create a drawable in XML that should include: image drawable color drawable The color drawable provides white transparent color. So, as a result we would have image with some white transparent layer on top. I have tried to use LayerDrawable, but it fails to be created during application launch: <LayerDrawable xmlns:android="http://schemas.android.com/apk/res/android"> <BitmapDrawable android:src="@drawable/button_play" /> <ColorDrawable android:color="#80FFFFFF"/> </LayerDrawable> Could you please advice what is wrong here? Thanks.

    Read the article

  • how to create thumbnail system for MP4 files

    - by Pete Herbert Penito
    Hi everyone! I know I know, why am I using MP4 still?? It's because I have like 100 files already in this format and I need to upload to a website, I have the mp4 file embeded in the site already and the file played changes according to php. but what I really need is a way to dynamically create a thumbnail or take a snapshot of the video file to display on the page. I've read a couple things online but they all require the file type to be in FLV, what would be the best way to accomplish this? Thank you Guys!

    Read the article

  • Pagination links broken - php/jquery

    - by ClarkSKent
    Hey, I'm still trying to get my pagination links to load properly dynamically. But I can't seem to find a solution to this one problem. vote down star Hi everyone, I am still trying to figure out how to fix my pagination script to work properly. the problem I am having is when I click any of the pagination number links to go the next page, the new content does not load. literally nothing happens and when looking at the console in Firebug, nothing is sent or loaded. I have on the main page 3 links to filter the content and display it. When any of these links are clicked the results are loaded and displayed along with the associated pagination numbers for that specific content. I believe the problem is coming from the sql query in generate_pagination.php (seen below). When I hard code the sql category part it works, but is not dynamic at all. This is why I'm calling $ids=$_GET['ids']; and trying to put that into the category section but then the numbers don't display at all. If I echo out the $ids variable and click on a filter it does display the correct name/id, so I don't know why this doesn't work Here is the main page so you can see how I am including and starting the function(I'm new to php): <?php include_once('generate_pagination.php'); ?> <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.4.1/jquery.min.js"></script> <script type="text/javascript" src="jquery_pagination.js"></script> <div id="loading" ></div> <div id="content" data-page="1"></div> <ul id="pagination"> <?php //Pagination Numbers for($i=1; $i<=$pages; $i++) { echo '<li class="page_numbers" id="page'.$i.'">'.$i.'</li>'; } ?> </ul> <br /> <br /> <a href="#" class="category" id="marketing">Marketing</a> <a href="#" class="category" id="automotive">Automotive</a> <a href="#" class="category" id="sports">Sports</a> Here is the generate pagination where the problem seems to occur: <?php $ids=$_GET['ids']; include_once('config.php'); $per_page = 3; //Calculating no of pages $sql = "SELECT COUNT(*) FROM explore WHERE category='$ids'"; $result = mysql_query($sql); $count = mysql_fetch_row($result); $pages = ceil($count[0]/$per_page); ?> I thought I might as well post the jquery script if someone wants to see: $(document).ready(function(){ //Display Loading Image function Display_Load() { $("#loading").fadeIn(900,0); $("#loading").html("<img src='bigLoader.gif' />"); } //Hide Loading Image function Hide_Load() { $("#loading").fadeOut('slow'); }; //Default Starting Page Results $("#pagination li:first").css({'color' : '#FF0084'}).css({'border' : 'none'}); Display_Load(); $("#content").load("pagination_data.php?page=1", Hide_Load()); // Editing below. // Sort content Marketing $("a.category").click(function() { Display_Load(); var this_id = $(this).attr('id'); $.get("pagination.php", { category: this.id }, function(data){ //Load your results into the page var pageNum = $('#content').attr('data-page'); $("#pagination").load('generate_pagination.php?category=' + pageNum +'&ids='+ this_id ); $("#content").load("filter_marketing.php?page=" + pageNum +'&id='+ this_id, Hide_Load()); }); }); //Pagination Click $("#pagination li").click(function(){ Display_Load(); //CSS Styles $("#pagination li") .css({'border' : 'solid #dddddd 1px'}) .css({'color' : '#0063DC'}); $(this) .css({'color' : '#FF0084'}) .css({'border' : 'none'}); //Loading Data var pageNum = $(this).attr("id").replace("page",""); $("#content").load("pagination_data.php?page=" + pageNum, function(){ $(this).attr('data-page', pageNum); Hide_Load(); }); }); }); If any could assist me on solving this problem that would be great, thanks.

    Read the article

  • CodeIgniter Unable to Access Error Message Error

    - by 01010011
    Hi, I've created this registration form for registering new users to a website using CodeIgniter. My problem is, whenever I enter a username that already exists in my database, instead of giving me my error message which explains this to the user, it instead gives me this error message: Unable to access an error message corresponding to your field name Here are snippets of the code from my controller. Any assistance will be appreciated: function register() $this->load->library('form_validation'); $this->form_validation->set_rules('username', 'Username','trim|required|alpha_numeric|min_length[6]|xss_clean|strtolower|callback_username_not_exists); ... } function username_not_exists($username) { $this->form_validation->set_message('username','That %s already exists.'); if($this->User_model->check_exists_username($username)) { return false; } else { return true; }

    Read the article

  • Function for putting all database to an array

    - by jasmine
    I have written a function to print database to an array like this Array( ID=>1, PARENTID =>1, TITLE => LIPSUM, TEXT =>LIPSUM ) My function is: function dbToArray($db) { $allArrays =array(); $query = mysql_query("SELECT * FROM $db"); $dbRow = mysql_fetch_array($query); for ($i=0; $i<count($dbRow) ; $i++) { $allArrays[$i] = $dbRow; } $txt .='<pre>'; $txt .= print_r($allArrays); $txt .= '</pre>'; return $txt; } Anything wrong in my function. Any help is appreciated about my problem. Thanks in advance

    Read the article

  • jQuery / jqGrids / Submitting form data troubles...

    - by Kelso
    Ive been messing with jqgrids alot of the last couple days, and I have nearly everything the way I want it from the display, tabs with different grids, etc. Im wanting to make use of Modal for adding and editing elements on my grid. My problem that Im running into is this. I have my editurl:"editsu.php" set, if that file is renamed, on edit, i get a 404 in the modal.. great! However, with that file in place, nothing at all seems to happen. I even put a die("testing"); line at the top, so it sees the file, it just doesnt do anything with it. Below is the content. ........ the index page jQuery("#landings").jqGrid({ url:'server.php?tid=1', datatype: "json", colNames:['ID','Tower','Sector', 'Client', 'VLAN','IP','DLink','ULink','Service','Lines','Freq','Radio','Serial','Mac'], colModel:[ {name:'id', index:'id', width : 50, align: 'center', sortable:true,editable:true,editoptions:{size:10}}, {name:'tower', index:'tower', width : 85, align: 'center', sortable:true,editable:false,editoptions:{readonly:true,size:30}}, {name:'sector', index:'sector', width : 50, align: 'center',sortable:true,editable:true,editoptions:{readonly:true,size:20}}, {name:'customer',index:'customer', width : 175, align: 'left', editable:true,editoptions:{readonly:true,size:35}}, {name:'vlan', index:'vlan', width : 35, align: 'left',editable:true,editoptions:{size:10}}, {name:'suip', index:'suip', width : 65, align: 'left',editable:true,editoptions:{size:20}}, {name:'datadl',index:'datadl', width:55, editable: true,edittype:"select",editoptions:{value:"<? $qr = qquery("select * from datatypes"); while ($q = ffetch($qr)) {echo "$q[id]:$q[name];";}?>"}}, {name:'dataul', index:'dataul', width : 55, editable: true,edittype:"select",editoptions:{value:"<? $qr = qquery("select * from datatypes"); while ($q = ffetch($qr)) {echo "$q[id]:$q[name];";}?>"}}, {name:'servicetype', index:'servicetype', width : 85, editable: true,edittype:"select",editoptions:{value:"<? $qr = qquery("select * from servicetype"); while ($q = ffetch($qr)) {echo "$q[id]:$q[name];";}?>"}}, {name:'voicelines', index:'voicelines', width : 35, align: 'center',editable:true,editoptions:{size:30}}, {name:'freqname', index:'freqname', width : 35, editable: true,edittype:"select",editoptions:{value:"<? $qr = qquery("select * from freqband"); while ($q = ffetch($qr)) {echo "$q[id]:$q[name];";}?>"}}, {name:'radioname', index:'radioname', width : 120, editable: true,edittype:"select",editoptions:{value:"<? $qr = qquery("select * from radiotype"); while ($q = ffetch($qr)) {echo "$q[id]:$q[name];";}?>"}}, {name:'serial', index:'serial', width : 100, align: 'right',editable:true,editoptions:{size:20}}, {name:'mac', index:'mac', width : 120, align: 'right',editable:true,editoptions:{size:20}} ], rowNum:20, rowList:[30,50,70], pager: '#pagerl', sortname: 'sid', mtype: "GET", viewrecords: true, sortorder: "asc", altRows: true, caption:"Landings", editurl:"editsu.php", height:420 }); jQuery("#landings").jqGrid('navGrid','#pagerl',{edit:true,add:true,del:false,search:false},{height:400,reloadAfterSubmit:false},{height:400,reloadAfterSubmit:false},{reloadAfterSubmit:false},{}); now for the editsu.php file.. $operation = $_REQUEST['oper']; if ($operation == "edit") { qquery("UPDATE customers SET vlan = '".$_POST['vlan']."', datadl = '".$_POST['datadl']."', dataul = '".$_POST['dataul']."', servicetype = '".$_POST['servicetype']."', voicelines = '".$_POST['voicelines']."', freqname = '".$_POST['freqname']."', radioname = '".$_POST['radioname']."', serial = '".$_POST['serial']."', mac = '".$_POST['mac']."' WHERE id = '".$_POST['id']."'") or die(mysql_error()); } Im just having a hard time troubleshooting this to figure out where its getting hung up at. My next question after this would be to see if its possible to make it so when you click "add", that it auto inserts a row into the db with a couple variable predtermined and then bring up the modal window, but ill work on the first problem first. thanks!

    Read the article

  • executing perl code stored in a database?

    - by TheGNUGuy
    Hey everyone, Is it possible to save some perl code in a database then retrieve it using a select statement and then execute that perl code? I have tried using the eval() function but that doesn't seem to work. Here is what I'm trying right now and it doesn't seem to work: my $temp = $qryResults[0]; print $temp."\n"; eval{"$temp"}; the output is $con->Disconnect();exit; Thanks for the help!

    Read the article

  • Place Query Results into Array then Implode?

    - by jason
    Basically I pull an Id from table1, use that id to find a site id in table2, then need to use the site ids in an array, implode, and query table3 for site names. I cannot implode the array correctly first I got an error, then used a while loop. With the while loop the output simply says: Array $mysqli = mysqli_connect("server", "login", "pass", "db"); $sql = "SELECT MarketID FROM marketdates WHERE Date = '2010-04-04 00:00:00' AND VenueID = '2'"; $result = mysqli_query($mysqli, $sql) or die(mysqli_error($mysqli)); $dates_id = mysqli_fetch_assoc ( $result ); $comma_separated = implode(",", $dates_id); echo $comma_separated; //This Returns 79, which is correct. $sql = "SELECT SIteID FROM bookings WHERE BSH_ID = '1' AND MarketID = '$comma_separated'"; $result = mysqli_query($mysqli, $sql) or die(mysqli_error($mysqli)); // This is where my problems start $SIteID = array(); while ($newArray = mysqli_fetch_array($result, MYSQLI_ASSOC)) { $SIteID[] = $newArray[SIteID]; } $locationList = implode(",",$SIteID); ?> Basically what I need to do is correctly move the query results to an array that I can implode and use in a 3rd query to pull names from table3.

    Read the article

  • create manually parameter ReturnUrl

    - by user276640
    i have view like 'home/details/5', it can be access by anonymous user. but there is button, which can be pressed only by registered users. no problem, i can look into Request.IsAuthenticated , and if anonymous i show button login instead of secret button but the problem- when press login i can lose address and parameters of page. how can i create login button and pass a parameter ReturnUrl ? something like <%= Html.ActionLink("enter to buy", "LogOn", "Account", new { ReturnUrl = path to view with route value })%> i see only stupid solution <%= Html.ActionLink("enter to buy", "LogOn", "Account", new { ReturnUrl = "home/details/" + ViewContext.RouteData.Values["id"] })%> but i don't like to hard code names of controller

    Read the article

  • Create XML DocType element

    - by Moro
    Hi all, Please I am working with IBM message broker, and I want to know how to create (in java/esql) DOCTYPE element in a message as the following: <!DOCTYPE COMMAND PUBLIC "any//DTD any//EN" "xml/command.dtd"> <COMMAND> ...... <COMMAND> I tried: MbElement root = outMessage.getRootElement().getLastChild(); MbElement xmlDocType = root.createElementAsFirstChild(MbXMLNSC.DOCUMENT_TYPE); xmlDocType.setName("COMMAND PUBLIC"); xmlDocType.createElementAsLastChild(MbXMLNSC.Attribute, null, "any//DTD any//EN"); but no way :( it produces: <!DOCTYPE COMMAND PUBLIC []> <COMMAND> ...... <COMMAND> Thanks in advance,

    Read the article

  • how to evaluate query by DMBS?

    - by Kevinniceguy
    How do we evaluate the below database query by DBMS? the query is something like : SELECT SUM(price) FROM Room r, Hotel h WHERE r.hotelNo = h.hotelNo and hotelName = 'Paris Hilton' and roomNo NOT IN (SELECT roomNo FROM Booking b, Hotel h WHERE (dateFrom <= CURRENT_DATE AND dateTo = CURRENT_DATE) AND b.hotelNo = h.hotelNo AND hotelName = 'Paris Hilton');

    Read the article

  • Best practices to store CreditCard information into DataBase

    - by Garis Suero
    In my country the online payments are not an old thing, the first time i saw a web application taking payments directly to a local bank account was last year. So, Im a newbie coding web payment system. My question is, what are the best practices to store creditcard information into the database... I have many ideas: encrypting the creditcard, database security restriction, etc. What have you done?

    Read the article

  • PDO and SQL IN statements

    - by Sai
    Im using a sequel for search like this using PDOs $states = "'SC','SD'"; $sql = "select * from mytable where states in (:states)"; $params = array(':states'=>$states); and I use my function $result = $this->selectArrayAssoc($sql, $params); where my selectArrayAssoc function as following public function selectArrayAssoc($sql, $params = array()){ try{ $sth = $this->db->prepare($sql); $sth->execute($params); $result = $sth->setFetchMode(PDO::FETCH_ASSOC); return $sth->fetchAll(); }catch(PDOException $e){ print $e->getMessage(); //Log this to a file later when in production exit; } } it does not take the quoted variables, I think it is suppressing, in such cases how to deal with this.

    Read the article

  • Successful SQL Injection despite PHP Magic Quotes

    - by Crimson
    I have always read that Magic Quotes do not stop SQL Injections at all but I am not able to understand why not! As an example, let's say we have the following query: SELECT * FROM tablename WHERE email='$x'; Now, if the user input makes $x=' OR 1=1 --, the query would be: SELECT * FROM tablename WHERE email='\' OR 1=1 --'; The backslash will be added by Magic Quotes with no damage done whatsoever! Is there a way that I am not seeing where the user can bypass the Magic Quote insertions here?

    Read the article

  • Sql query problem

    - by LiveEn
    I have the below sql query that will update the the values from a form to the database $sql="update leads set category='$Category',type='$stype',contactName='$ContactName',email='$Email',phone='$Phone',altphone='$PhoneAlt',mobile='$Mobile',fax='$Fax',address='$Address',city='$City',country='$Country',DateEdited='$today',printed='$Printed',remarks='$Remarks' where id='$id'"; $result=mysql_query($sql) or die(mysql_error()); echo '<h1>Successfully Updated!!.</h1>'; when i submit I dont get any errors and the success message is displayed but the database isnt updated . When i echo the $sql, all the values are set properly. and when i ech the $result i get the value 1. can someone please tell me what am i doing wrong here??

    Read the article

  • Use SQL Result to Query second time and grab more results via php

    - by maxwell
    I am grabbing a list of school names from a database. When the user clicks on the school name, i want the code to fetch 2-3 other attributes related to the school name that the user has clicked on. My code for the single school name list: $query = mysql_query("Select schoolname, product, username, password from credentials c join products p on p.productid = c.productid join schools s on s.schoolid = c.schoolid join icons i on i.productid = p.productid order by s.schoolname"); echo '<ul>'; while($row = mysql_fetch_array($query)) { echo "<li> <a href='#'>" . $row['schoolname'] . "</a> </li>"; } echo ''; Current Output: School A School A School B School B School B School C School C Expected Output: School name displayed only once (distinct won't work because each school name has 2-3 product credentials School A School B School C Ability for User to click on a school. then the school names underneath will move down (toggle effect) and user can see product, username and password displayed for the school clicked (for example: user clicked on School A) School A productname1, username, password productname2, username, password School B School C

    Read the article

  • Should you do validation checks that go outside the possiblility of normal user activity?

    - by Scarface
    Hey guys I have been thinking about form security a lot lately. I have been told time and time again to check if form input is a number if you are expecting a number or escape it in case (unless you use proper mysqli formatting) to avoid injection. 1.After the safety checks are done, should I do additional logic checks? For example, if the user is sending a friend request to them-self for example even if my user interface will not show the form if the user is looking at their own page.

    Read the article

  • Using Active Objects and BLOBs

    - by Andrew L.
    I am in a group of people who are creating a Defect Tracking program as a project. We have been using Active Objects and have run into some issues. Currently maximum file size for the blob is approx. 2Mb but we want to be able to increase it up to 2Gb. We currently have been looking at many sites and have not been able to find out how to increase the size. We are currently storing the blob as an array of bytes. Our current error says, Packet for Query is too large? We don't know how to set the variable, and we don't know how to set it using AO. We are programming this in Java, too. We are wondering if anyone has a solution to this problem. Thanks for the Help.

    Read the article

  • Fulltext search on many tables

    - by Rob
    I have three tables, all of which have a column with a fulltext index. The user will enter search terms into a single text box, and then all three tables will be searched. This is better explained with an example: documents doc_id name FULLTEXT table2 id doc_id a_field FULLTEXT table3 id doc_id another_field FULLTEXT (I realise this looks stupid but that's because I've removed all the other fields and tables to simplify it). So basically I want to do a fulltext search on name, a_field and another_field, and then show the results as a list of documents, preferably with what caused that document to be found, e.g. if another_field matched, I would display what another_field is. I began working on a system whereby three fulltext search queries are performed and the results inserted into a table with a structure like: search_results table_name row_id score (This could later be made to cache results for a few days with e.g. a hash of the search terms). This idea has two problems. The first is that the same document can be in the search results up to three times with different scores. Instead of that, if the search term is matched in two tables, it should have one result, but a higher score. The second is that parsing the results is difficult. I want to display a list of documents, but I don't immediately know the doc_id without a join of some kind; however the table to join to is dependant on the table_name column, and I'm not sure how to accomplish that. Wanting to search multiple related tables like this must be a common thing, so I guess what I'm asking is am I approaching this in the right way? Can someone tell me the best way of doing it please.

    Read the article

  • Create javadoc with multiple src dirs

    - by Ed Marty
    I have a Util package with source files in three seperate directories, defined like so: src/com/domain/util src/Standard/com/domain/util src/Extended/com/domain/util The package is built with the first set of files and either one of the second or third set, to create a total of two different implementations of the same interface. Now, I want to generate javadoc based on those files. How can I specify that? What I really want to do is javadoc com.domain.util -sourcepath ./src;./src/Standard to build the javadoc for the standard util package, and javadoc com.domain.util -sourcepath ./src;./src/Extended to build the javadoc for the extended util package. This doesn't work. The only way I've found so far to actually make it work is to merge the directory structure of the common classes and the Standard classes into another location and run with that for the standard javadoc, then do the same for the Extended package. Is there another way?

    Read the article

  • Non Working Relationship

    - by Dominik K.
    Hello everyone, I got a problem with cake's model architecture. I got a Users-Model and a Metas-Model. Here are the model codes: Users: <?php class User extends AppModel { var $name = 'User'; var $validate = array( 'username' => array('notempty'), 'email' => array('email'), 'password' => array('notempty') ); var $displayField = 'username'; var $hasMany = array( 'Meta' => array( 'className' => 'Meta', 'foreignKey' => 'user_id' ) ); } ?> and the Metas Model: <?php class Meta extends AppModel { var $name = 'Meta'; //The Associations below have been created with all possible keys, those that are not needed can be removed var $belongsTo = array( 'User' => array( 'className' => 'User', 'foreignKey' => 'user_id', 'required' => true ) ); } ?> So now the question is why do I not get the Meta data into the User array? Should I get it in the Auth object? Or where can I work with the meta data? hope you can help me! Have a nice Day! Dom

    Read the article

  • How to get an hierarchical php structure from a db table, in php array, or JSON

    - by daniel
    Hi guys, can you please help me. How to get an hierarchical php structure from a db table, in php array, or JSON, but with the following format: [{ "attributes" : {"id" : "111"}, "data" : "Some node title", "children" : [ { "attributes" : { "id" : "555"}, "data" : "A sub node title here" } ], "state" : "open" }, { "attributes" : {"id" : "222"}, "data" : "Other main node", "children" : [ { "attributes" : { "id" : "666"}, "data" : "Another sub node" } ], "state" : "open" }] My SQL table contains the fields: ID, PARENT, ORDER, TITLE Can you please help me with this? I'm going crazy trying to get this. Many thanks in advance. Daniel

    Read the article

< Previous Page | 421 422 423 424 425 426 427 428 429 430 431 432  | Next Page >