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  • CSS Doozie: Replacing BG Image on SELECT dropdown

    - by ToiletOverflow
    I need to be able to change the background-image property of a SELECT drop-down using JavaScript/CSS. We have been able to accomplish this in Firefox, but it doesn't appear to be supported at all in IE. From what I've read, IE won't support this. But I'm wondering if there's anything else I could try. Does anyone here have any recommendations?

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  • Data validation in cell of datagridview control

    - by Yogi
    I am using datagridview control and in this grid user can edit the value of a fixed column. i want user only can write numaric values (e.g. 1, 2, 443 etc) I am not sure at which event of datagridview i have to write this code and what is the code to trap values

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  • Manipulating original elements with qTip

    - by pjotr
    I have a bunch of divs on my page and each of them has only the class attribute. In the divs there are some spans, which are set up to display a tooltip with the help of qTip. The tooltip should contain three items: Up: anchor, which should move the OuterDiv up (probably something like this: move up/down in jquery) Down: anchor, which should move the OuterDiv down Delete: anchor, which should remove the calling OuterDiv My code so far: <body> <div class="OuterDiv"> <div class="InnerDiv"> <span class="Position">Position 1</span> </div> </div> <div class="OuterDiv"> <div class="InnerDiv"> <span class="Position">Position 2</span> </div> </div> </body> And scripts: $(document).ready(function () { var qTipContent = '<a href="javascript:void(0)" onclick="">&uarr;</a>&nbsp;&nbsp;&nbsp;'; qTipContent = qTipContent + '<a href="javascript:void(0)" onclick="">&darr;</a>&nbsp;&nbsp;&nbsp;'; qTipContent = qTipContent + '<a href="javascript:void(0)" onclick="">X</a>'; $('.Position').each(function () { $(this).qtip({ content: qTipContent, hide: { fixed: true } }) }); }); How should the onclick function in the qTip content look like?

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  • z-index not working in IE

    - by praveenjayapal
    Hi friends, I have a button, while clicking the button i just produce a div containing some checkbox. If the user select the required checkbox, it will produce a iframe according to the value of the checkbox and the div will disappear. Its placed immediately below the button. Up to this its working fine. If the user again click the button, the droping div is comes behind the frame. Please help me to make it visible above the frame. I have used z-index, its working in firefox - but i cant made it in IE.. Please help me regarding this. Thankspraveen j

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  • Centering images php

    - by peak
    I'm trying to center an image in php. I'm currently using this line of code echo '<img src="newimage.jpg" width="110" height="120" class="centre">'; However, this seems to have no effect. I've also tried using something like this, img.center { display: block; margin-left: auto; margin-right: auto; } <img src="newimage.jpg" alt="Suni" class="center" /> but this merely gives me a syntax error, how do I go about fixing this? Thanks

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  • validation before ajax form submission

    - by ZX12R
    How do i introduce validation before remote_form_for submits? I have javascript function called validateForm(). I am able to call it before the AJAX request process. I tried to use return false and event.preventDefault. But there seems to be no effect. Here is what my code looks like <% remote_form_for :customer, :update =>"uxScreenLoaderDiv", :url => {:action => "login", :controller => "site"}, :html => {:id => "uxLoginForm"}, :onsubmit => "validateForm(event)" do |f| %> User name : <%= f.text_field "uxUserName", :class => "TextBox", :style => "width:100px;" %>&nbsp;* &nbsp;Password : <%= f.password_field "uxPassword", :class => "TextBox", :style => "width:100px;" %>&nbsp;* <%= f.submit "Go!", :class => "Button-Simple", :id => "uxSubmitButton" %> <% end %> the javascript function is simple as follows function validateForm(event){ return false; //event.preventDefault(); }

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  • input URL, output contents of "view page source", i.e. after javascript / etc, library or command-li

    - by Ryan Berckmans
    I need a scalable, automated, method of dumping the contents of "view page source" (DOM) to a file. Programs such as wget or curl will non-interactively retrieve a set of URLs, but do not execute javascript or any of that 'fancy stuff'. My ideal solution looks like any of the following (fantasy solutions): cat urls.txt | google-chrome --quiet --no-gui \ --output-sources-directory=~/urls-source (fantasy command line, no idea if flags like these exist) or cat urls.txt | python -c "import some-library; \ ... use some-library to process urls.txt ; output sources to ~/urls-source" As a secondary concern, I also need: dump all included javascript source to file (a la firebug) dump pdf/image of page to file (print to file)

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  • JavaScript text slideshow not working?

    - by I Build Websites
    I'm making a Javascript slideshow for my blog yet the array doesn't seem to be working. Can someone please say what I've been doing wrong <SCRIPT type="text/javascript"> var blog = new Array() blog[0]= "<h4>Sunday 17 of June 2012</h4><p title='Blog'>Donec tempus risus eget ligula viverra eget placerat odio tincidunt. Duis nisl sem, scelerisque faucibus congue vitae, accumsan at lectus. Cras vestibulum arcu ut lorem luctus eu pharetra tortor ultricies. Nam iaculis orci mauris. Etiam luctus, mauris sed adipiscing ullamcorper, augue enim volutpat sem, ut sagittis ipsum nibh ac nulla. Nam ultrices, quam eget sollicitudin porta, sapien mauris pulvinar augue, posuere hendrerit erat ligula ut magna. Maecenas laoreet nisi vitae magna consectetur a mollis purus tristique. Pellentesque elementum arcu non urna convallis eleifend. Aliquam eu lorem sed risus tempus tempor. Donec malesuada velit in odio vulputate iaculis. In tristique neque quis velit posuere adipiscing. Nullam dui neque, scelerisque non egestas feugiat, pellentesque vitae mauris.</p><hr>" and so the array continues till function display1() { document.getElementById(blogShow).innerHTML( blog[0]) } function display2() { document.getElementById(blogShow).innerHTML(blog[1]) } function display3() { document.getElementById(blogShow).innerHTML(blog[2]) } function display4() { document.getElementById(blogShow).innerHTML(blog[3]) } function display5() { document.getElementById(blogShow).innerHTML(blog[4]) } </SCRIPT> <div id="blogShow"> <SCRIPT type="text/javascript">display1()</SCRIPT> </div> <div id="blogNav"> <input type="button" onClick="display2()" value="1" class="button"> <input type="button" onClick="display3()" value="2" class="button"> <input type="button" onClick="display4()" value="3" class="button"> <input type="button" onClick="display5()" value="4" class="button"> </div> I know it's all inline and i will clean up after it works

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  • PHP Sessions Error

    - by Andrei Korchagin
    I'm new to PHP sessions and I've come across the following error: Warning: session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started at somefile:someline). As well as this one: Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent by (output started at somefile:someline). The session_start(); is the very first thing in all of my code. I'm not sure what the problem is. It gave me line numbers but all I do on those lines is start the session. Also - I have a portion of code whose POST action is another PHP page. How can I set a $_SESSION variable pertaining to this page within that action page?

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  • How to have multiple parts of a website in one page

    - by stas
    I want to make a website that will have multiple pages, but because of a unique navigation bar, I cannot simply link to a new file for each page. What is the best way to accomplish this. Some possibilities that I can think of are having all of them on one page, but using css and javascript to move the other pages offscreen, or using iframes and loading them with javascript. Could someone please direct me to some examples or tutorials?

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  • Javascript: why I cannot load my external js page in Drupal ?

    - by Patrick
    hi, when I add the tag script to load an external javascript file, my page is not longer displayed. There are not error in Firebug, there are not errors such as "File not found" or "Not enough permissions", the browser just displays a blank page for some reason. <?php print $head; ?> <?php print $styles; ?> <?php print $scripts; ?> <script type="text/JavaScript" src="main.js" /> If I remove the last line everything works perfectly. The previous php lines are the standard Drupal head lines. This is the content of my js file: $(document).ready( function() { alert("hello"); }); thanks

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  • Is it possible to hide the cursor in a webpage using CSS or Javascript?

    - by yeyeyerman
    I want to hide the cursor when showing a webpage that is meant to display information in a building hall. It doesn't have to be interactive at all. I tried with the cursor property and a transparent cursor image but I didn't make it work. Does anybody know if this can be done? I suppose this can be thought as a security threat for a user that can't know where he is clicking on, so I'm not very optimistic... Thank you!

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  • Detectig by how much user has scrolled

    - by Sean
    I have an image pop-up ability on my website (see this screenshot), in order to show users the full resolution picture when they click on a smaller version on the page. This is the current CSS that positions it: div#enlargedImgWrapper { position: absolute; top: 30px; left: 55px; z-index: 999; } The problem now is that if I click on an image further down the page, the window still appears in the top left corner of the page, where I can't see it until I scroll back up. I need it to appear relative to the window, whatever its current position relative to the document is. Note: I don't want to use position: fixed; as some images might be taller than the screen, so I want users to be able to scroll along the image as well. My idea was to use JS to change the top value: var scrollValue = ???; document.getElementById('enlargedImgWrapper').style.top = scrollValue+30 + 'px'; How can I detect by how much the user has scrolled down the page (var scrollValue)? Or is there a 'better' way to do this? Thanks!

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  • Adding new records in Access without wrecking the form

    - by Matt Parker
    I'm working on a simple Access 2003 application to keep track of things that need to be done for clients for some colleagues. Each colleague has a set of clients, and each client has a set of actions that need to be taken by a certain date. I've set up a form that consists of a combobox for client ID (indexed), a drop-down for the person who is handling that client's case, and a button for adding new clients (a standard Access-created Add Record button). The actions are listed in a subform below these three elements. The problem I've run into is that the first person I tested this on clicked the button to add a new record, then didn't fill it out and tried to select another client from the drop-down list. Access interprets this as an attempt to set the selected Client ID as the ID for the new record and rightfully throws an error for duplicate primary keys. I can think of a couple of ways around this problem, but I'd much rather hear your elegant solutions than kludge together some junk in a language I don't know. Let me know if you have any questions. Thank you.

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  • Jquery Content Cycle Next/Previous not working

    - by user340745
    I have a definition list with a lot of text inside of it. When a user comes to the page, I want the jQuery to hide two thirds of that content, add a next and previous button where appropriate, and fade the content in and out. The first third of the content is .issue-group-1, the second third is .issue-group-3, the third, .issue-group-3. I am trying to set it so that when the user hits the next button, the next button changes classes, and thus acts differently the next time the user clicks it (that is, it takes them to the third page instead of the second. Right now, the next/previous buttons are working on the first and second "pages" but the next button to the third page won't work. My code is probably too long and this is maybe not the best way to do it--I'm new to jquery. Any suggestions would be helpful. $(document).ready(function(){ $('.issue-group-2, .issue-group-3').hide(); $('a#next-button.page1').fadeIn(500); $('a#next-button.page1').click(function() { $(this).removeClass('page1').addClass('page2'); $('.issue-group-1').fadeOut(500, function() { $('.issue-group-2').fadeIn(500); }); $('a#previous-button').fadeIn(500); }); $('a#previous-button.page2').click(function() { $('#next-button.page2').removeClass('page2').addClass('page1'); $('.issue-group-2').fadeOut(500, function() { $('.issue-group-1').fadeIn(500); }); $('a#previous-button').fadeOut(500); }); $('a#next-button.page2').click(function() { $('a#previous-button').removeClass('page2').addClass('page3'); $('.issue-group-2').fadeOut(500, function() { $('.issue-group-3').fadeIn(500); }); $('a#next-button').fadeOut(500); }); $('a#previous-button.page3').click(function() { $(this).removeClass('page3').addClass('page2'); $('.issue-group-2').fadeOut(500, function() { $('.issue-group-2').fadeIn(500); }); $('a#next-button').fadeIn(500); }); });

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  • Text indent is not working in ie7

    - by saorabh
    I am working on a website and on the top navigation bar there is a search box, I applied the following css on the search submit button #submit{background:url("img/new-search-icon.png") no-repeat scroll -1px 0 #FFFFFF; border:0 none; cursor:pointer; display:block; height:21px; padding:0; position:absolute; right:0; text-indent:-9999px; top:0; width:20px; z-index:2;} My Problem is in IE7 the text indent is not working please help me if you want to see the demo you can view it by clicking here Click here. Please help me.

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  • Saving data that is in a table efficiently and also is easy to retrieve and echo back out

    - by Harry
    Information I currently have a table which image is below, Problem I have made this table using ul & li Here is the code http://jsfiddle.net/8j2qe/1/ Question What would be the best way of storing the data in the image and easily displaying it? Keeping in mind that each column can only have 1 entry. Thank you! And any questions will be answered ASAP! EDIT Sorry, I dont think I was clear enough in my initial question. What I am asking is, what is the best way to store and then display this type of data. I want to DISPLAY data from my database to show like it would in the image. Should I have a column in my database for each column on the table, then say either A,B,C or D depending on what column it is in but then how would I display it using PHP in my code provided? Im struggling to find a good way of explaining this, I am sorry.

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  • How can I create an http response from scratch?

    - by ispiro
    I have code that returns an http response, but it also includes the content of the page. How can I create a response from scratch so it won't include anything except what I put in it? My code now: GCheckout.AutoGen.NotificationAcknowledgment response = new GCheckout.AutoGen.NotificationAcknowledgment(); response.serialnumber = serialNumber; HttpContext.Current.Response.Clear(); HttpContext.Current.Response.BinaryWrite(GCheckout.Util.EncodeHelper.Serialize(response)); HttpContext.Current.Response.StatusCode = 200;

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  • Problem in displaying image in FireFox

    - by Param-Ganak
    Hello friends, I have a JSP page on which I have a div tag in which there is a a IMG tag. Using this IMG tag I want to show an image in it. Here the source path of an image is comes from database so I assigned a JSP variable using JSP scriplet. This JSP variable have the source path of an image. This path of image may be of different machine or of same machine i.e. images are stored on different machine or on same machine i.e. on local machine on different drive. The problem is that how to give path of image stored on different machine as well as on same machine. I have tried different ways like by giving ip address of that machine. Here is the path that of local machine where the image is stored img src= file:\localhost\D:\ScannedSheets\testproj/batch1/IMG001.jpg style="z-index:1; position:absolute; top:0; left:0; width:850; height:1099" With this syntax the image is visible in Internet Explorer but With the same syntax Its not visible in FireFox, Google Chrome etc. Please Guide me in friends. Also tell me that how to give path of the image stored on different machine which works In Internet Explorer, FireFox, Google chrome etc.

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  • CSS file in a Spring WAR returns a 404

    - by Rachel G.
    I have a J2EE application that I am building with Spring and Maven. It has the usual project structure. Here is a bit of the hierarchy. MyApplication src main webapp WEB-INF layout header.jsp styles main.css I want to include that CSS file in my JSP. I have the following tag in place. <c:url var="styleSheetUrl" value="/styles/main.css" /> <link rel="stylesheet" href="${styleSheetUrl}"> When I deploy the application, the CSS page isn't being located. When I view the page source, the href is /MyApplication/styles/main.css. Looking inside the WAR, there is a /styles/main.css. However, I get a 404 when I try to access the CSS file directly in the browser. I discovered that the reason for the issue was the Dispatcher Servlet mapping. The mapping looks as follows. <servlet-mapping> <servlet-name>Spring MVC Dispatcher Servlet</servlet-name> <url-pattern>/</url-pattern> </servlet-mapping> I imagine the Dispatcher Servlet doesn't know how to handle the CSS request. What is the best way to handle this issue? I would rather not have to change all of my request mappings.

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  • Detecting file upload size on the client side?

    - by DisgruntledGoat
    I'm using PHP for file uploads. In the PHP manual it shows an example using a MAX_FILE_SIZE hidden field, saying that it will detect on the client side (i.e. the browser) whether the file is too large or not. I've just tried the example in Firefox, Chrome and IE and it doesn't work. The file is always uploaded, even if it is way larger than the specified hidden field. Incidentally, if the file is larger than MAX_FILE_SIZE then calling move_uploaded_file doesn't work, so it seems the variable is having an effect server-side, but not client-side.

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