Search Results

Search found 21327 results on 854 pages for 'display resolution'.

Page 428/854 | < Previous Page | 424 425 426 427 428 429 430 431 432 433 434 435  | Next Page >

  • Java problem cant find image file

    - by user363035
    I am a student working on a homework project. I spent DAYS trying to get the following code to display an image on my new windows 7 laptop. I compiled it and ran it on my old xp pc and it worked! I really want to use my laptop. Any suggestions on how to get it to display the image? import java.awt.*; import java.applet.*; import java.awt.event.*; import java.awt.image.*; public class MoveIt extends Applet implements ActionListener { // set variables and componets private Image cup; Panel keypad = new Panel(); public int top = 15; public int left = 15; private Button keysArray[]; public void init() { cup = getImage(getDocumentBase(), "cup.gif"); Canvas myCanvas = new Canvas(); keysArray = new Button[5]; setLayout(new BorderLayout(5,5)); setBackground(Color.blue); // set up keypad layout keypad.setLayout(new BorderLayout(0,0)); keysArray[0] = new Button("Up"); keysArray[1] = new Button("Left"); keysArray[2] = new Button("Center"); keysArray[3] = new Button("Right"); keysArray[4] = new Button("Down"); // add buttons to the keypad panel keypad.add(keysArray[0], BorderLayout.NORTH); keysArray[0].addActionListener(this); keypad.add(keysArray[1], BorderLayout.EAST); keysArray[1].addActionListener(this); keypad.add(keysArray[2], BorderLayout.CENTER); keysArray[2].addActionListener(this); keypad.add(keysArray[3], BorderLayout.WEST); keysArray[3].addActionListener(this); keypad.add(keysArray[4], BorderLayout.SOUTH); keysArray[4].addActionListener(this); // add canvas and keypad to the BorderLayout add(myCanvas, BorderLayout.NORTH); add(keypad, BorderLayout.SOUTH); } public void paint(Graphics g) { g.drawImage( cup, left, top, this ); } public void actionPerformed(ActionEvent e) { // test for menu item clicks String arg = e.getActionCommand(); if (arg == "Up") top -=15; else if (arg == "Down") top +=15; else if (arg == "Left") left -=15; else if (arg == "Right") left +=15; else { top = 60; left =125; } repaint(); } }

    Read the article

  • jquery two ajax call asynchrounsly in asp.net not working...

    - by eswaran
    Hi all, I am developed an web application in asp.net. In this application I have used jquery ajax for some pages. In this application, when I make two ajax call asynchrounoulsy that would not do as I expceted. what is happening is even the second ajax call finishes i can see the result when the maximum time out ajax call finished. I mean i can see the both results in the same time, not one by one. for an example. I have 3 pages 1) main.aspx - for make two ajax request. 2) totalCount.aspx - to find the total count. (max it takes 7 seconds to return, as corresponding table contains 3 lak records) 3) rowCount.aspx - to find the row details. (max it takes 5 seconds to return result). due to this scene, I have planed to make asyn call in jquery ajax in asp.net. here is my code... function getResult() { getTotalCount(); getRows(); } // it takes max 7 seconds to complete // as it take 7 seconds it should display second.( I mean after the rows dispaying) // but displaying both at the same time after the max time consuming ajax call completed. function getTotalCount() { $.ajax({ type : "POST", async : true, url : "totalCount.aspx?data1=" + document.getElementById("data").value, success : function(responseText) { $("#totalCount").attr("value", responseText); } }) } // it takes max 5 seconds to complete. // after finished, this should display first.( i mean before total count displays) // but displaying both at the same time after the max time consuming ajax call completed. function getRows() { $.ajax({ type : "POST", url : "getrows.aspx?data1=" + document.getElementById("data").value, async : true, success : function(responseText) { $("#getRows").attr("value", responseText); } }); } I would like to know, If there is any possible to make asyn call in jquery ajax in asp.net. I searched in net, I got some points that says we cannot do this in asp.net ref link: http://www.mail-archive.com/[email protected]/msg55125.html if we can do this in asp.net How to do that? thanks r.eswaran.

    Read the article

  • how is this dropdown working ? on selection it displays another record.

    - by ida
    this website here: http://www.offpricecars.com/inventory2.html?F=C when you select a dropdown the record based on your selection is displayed. ive tried copying it to localhost and it wont work. ive also tryed reading its headers and cant seem to figure out how javascript is making the records display on selection. i do understand that its extension isnt really html and might be another but based on how its operating as a html file i cant seem to find anywhere on how its sending the string to show the records. thanks

    Read the article

  • Form resubmission issue-Django html

    - by Hulk
    There is a form ,which is submitted and then the page is redirected to another page.But if the user hits the refresh button again on the new page .the following message is displayed To display this page, Firefox must send information that will repeat any action (such as a search or order confirmation) that was performed earlier. And on press "OK" A duplicate entry is created how do i prevent this or how do i handle this I am using a django,application Thanks..

    Read the article

  • PIL's Image.show() brings up *two* different viewers

    - by DarenW
    When toying with images in the python shell, I use image.show(), where image is an instance of Image. Long ago nothing happened, but after defining a symlink to mirage named "xv", I was happy. The last few days, show() will bring up both ImageMagick's display and also Mirage. It's not clear where show() gets information on what to run. Documentation wasn't helpful. How to make it behave and bring up only what it thinks is xv?

    Read the article

  • how to limit the number of images to be displayed at a time in android imageswitcher control?

    - by Rupesh Chavan
    Hello Everyone, I have checked the working demo of ImageSwitcher and gallery. Actually i want to display 4 images at a time on screen and by default it displays number of images that it can fit in a screen say for ex. 6 images. Now i want to limit the number of images(to 4 images ) to be displayed on ImageSwitcher at the same time. Any help will be appreciated. Thank you, Rupesh

    Read the article

  • position of UITabbar

    - by user262325
    Hello everyone I try to place UITabbar on iPhone window using CGRectMake. But I found that the Y position is different from the display in Interface Builder. Is there anyone met the same problem? Using CGRectMake to locate the x,y position, is it possible cause the refusing from App stoe due to compatible reason? Thanks interdev

    Read the article

  • JQuery - code behind

    - by nisardotnet
    how would you use JQuery with asp.net Code-Behind what i mean by that: i have a div that displays the result based on some processing and this process done on code-behind and based on that result i have to display if the process went through sucessfully or not. how would i do and is that possible? can anybody show me some sample lines of code to understand? thanks.

    Read the article

  • How to center a Paypal button in IE8

    - by Barry
    On one of my pages, http://artistsatlaketahoe.com/abstract.html , the Paypal buttons appear centered beneath text in FireFox and Chrome, but not in IE8. I got the centering to work in FF and Chrome by adding the following within the Paypal code snippet relating the Add to Cart image: style="display: block; margin: 0 auto;" Unfortunately, it isn't working in IE8. Any suggestions? Thanks!!

    Read the article

  • hide javascript in php

    - by raja
    hi all i am working on a project, it need email validation when user enter his email address check for availiblity. i wrote the php code in javascript it works fine but my problem is when some see my page source it display all user email address in javascript code. i want hide this one. i wrote javascript code in seperate file but validation is not working. if any one hide how hide javascript code in php, guide me plzz. thanks

    Read the article

  • Getting Json data into a list view

    - by Rahul Varma
    Hi, I have been searching for a way to get the json data from a URl (for example: http://search.twitter.com/trends.json) and display it in a listview. Couldnt get a perfect example to get it done. Can anyone plz help me out by getting the solution and providing a good example of how to do it...

    Read the article

  • How do I apply a servlet filter when serving an HTML page directly?

    - by Philippe Beaudoin
    First off, I'm using Google AppEngine and Guice, but I suspect my problem is not related to these. When the user connect to my (GWT) webapp, the URL is a direct html page. For example, in development mode, it is: http://127.0.0.1:8888/Puzzlebazar.html?gwt.codesvr=127.0.0.1:9997. Now, I setup my web.xml in the following way: <?xml version="1.0" encoding="UTF-8"?> <web-app xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" version="2.5"> <display-name>PuzzleBazar</display-name> <!-- Default page to serve --> <welcome-file-list> <welcome-file>Puzzlebazar.html</welcome-file> </welcome-file-list> <filter> <filter-name>guiceFilter</filter-name> <filter-class>com.google.inject.servlet.GuiceFilter</filter-class> </filter> <filter-mapping> <filter-name>guiceFilter</filter-name> <url-pattern>/*</url-pattern> </filter-mapping> <!-- This Guice listener hijacks all further filters and servlets. Extra filters and servlets have to be configured in your ServletModule#configureServlets() by calling serve(String).with(Class<? extends HttpServlet>) and filter(String).through(Class<? extends Filter) --> <listener> <listener-class>com.puzzlebazar.server.guice.MyGuiceServletContextListener </listener-class> </listener> </web-app> Since I'm using Guice, I have to configure extra filters in my ServletModule, where I do this: filter("*.html").through( SecurityCookieFilter.class ); But my SecurityCookieFilter.doFilter is never called. I tried things like "*.html*" or <url-pattern>*</url-pattern> but to no avail. Any idea how I should do this?

    Read the article

  • How do I conditionally format a WPF TextBlock?

    - by Scott Ferguson
    I have a WPF TextBlock bound to a string. If that string is empty, I want the TextBlock to display a warning message in another colour. This is easy to do in code, I was wondering if there was a elegant WPF pure XAML solution for it? I have investigated Style Triggers, but the syntax doesn't come naturally to me. Thanks!

    Read the article

  • How can I detect device orientation going back and forth through tabs and views?

    - by JoshD
    My application goes back and forth between Portrait and Landscape. I have all of my content(labels, uiimageviews, uilabels) lined up to relocate for both orientations. However, the only change when the device is actually rotated. When I cycle between tabs after it has been rotated it just shows up autosized and not the way I have it setup when the user rotates it. How can I detect the orientation of the device and display the view to reflect the orientation when the taps different tabs?

    Read the article

  • iphone Odd Problem when using a custom cell

    - by Brodie4598
    Please note where I have the NSLOG. All it is displaying in the log is the first three items in the nameSection. After some testing, I discovered it is displaying how many keys there are because if I add a key to the plist, it will log a fourth item in log. nameSection should be an array of the strings that make up the key array in the plist file. the plist file has 3 dictionaries, each with several arrays of strings. The code picks the dictionary I am working with correctly, then should use the array names as sections in the table and the strings en each array as what to display in each cell. so if the dictionary i am working with has 3 arrays, NSLOG will display 3 strings from the first array: 2010-05-01 17:03:26.957 Checklists[63926:207] string0 2010-05-01 17:03:26.960 Checklists[63926:207] string1 2010-05-01 17:03:26.962 Checklists[63926:207] string2 then stop with: 2010-05-01 17:03:26.963 Checklists[63926:207] * Terminating app due to uncaught exception 'NSRangeException', reason: '* -[NSCFArray objectAtIndex:]: index (3) beyond bounds (3)' if i added an array to the dictionary, it log 4 items instead of 3. I hope this explanation makes sense... -(NSInteger)numberOfSectionsInTableView:(UITableView *)tableView{ return [keys count]; } -(NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger) section { NSString *key = [keys objectAtIndex:section]; NSArray *nameSection = [names objectForKey:key]; return [nameSection count]; } -(UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { NSUInteger section = [indexPath section]; NSString *key = [keys objectAtIndex: section]; NSArray *nameSection = [names objectForKey:key]; static NSString *SectionsTableIdentifier = @"SectionsTableIdentifier"; static NSString *ChecklistCellIdentifier = @"ChecklistCellIdentifier "; ChecklistCell *cell = (ChecklistCell *)[tableView dequeueReusableCellWithIdentifier: SectionsTableIdentifier]; if (cell == nil) { NSArray *nib = [[NSBundle mainBundle] loadNibNamed:@"ChecklistCell" owner:self options:nil]; for (id oneObject in nib) if ([oneObject isKindOfClass:[ChecklistCell class]]) cell = (ChecklistCell *)oneObject; } NSUInteger row = [indexPath row]; NSDictionary *rowData = [self.keys objectAtIndex:row]; NSString *tempString = [[NSString alloc]initWithFormat:@"%@",[nameSection objectAtIndex:row]]; NSLog(@"%@",tempString); cell.colorLabel.text = [tempArray objectAtIndex:0]; cell.nameLabel.text = [tempArray objectAtIndex:1]; return cell; return cell; } - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { UITableViewCell *cell = [tableView cellForRowAtIndexPath:indexPath]; if (cell.accessoryType == UITableViewCellAccessoryNone) { cell.accessoryType = UITableViewCellAccessoryCheckmark; } else if (cell.accessoryType == UITableViewCellAccessoryCheckmark) { cell.accessoryType = UITableViewCellAccessoryNone; } [tableView deselectRowAtIndexPath:indexPath animated:NO]; } -(NSString *)tableView:(UITableView *)tableView titleForHeaderInSection:(NSInteger)section{ NSString *key = [keys objectAtIndex:section]; return key; }

    Read the article

  • Working through exercises in "Cocoa Programming for Mac OS X" - I'm stumped

    - by Zigrivers
    I've been working through the exercises in a book recommended here on stackoverflow, however I've run into a problem and after three days of banging my head on the wall, I think I need some help. I'm working through the "Speakline" exercise where we add a TableView to the interface and the table will display the "voices" that you can choose for the text to speech aspect of the program. I am having two problems that I can't seem to get to the bottom of: I get the following error: * Illegal NSTableView data source (). Must implement numberOfRowsInTableView: and tableView:objectValueForTableColumn:row: The tableView that is supposed to display the voices comes up blank I have a feeling that both of these problems are related. I'm including my interface code here: #import <Cocoa/Cocoa.h> @interface AppController : NSObject <NSSpeechSynthesizerDelegate, NSTableViewDelegate> { IBOutlet NSTextField *textField; NSSpeechSynthesizer *speechSynth; IBOutlet NSButton *stopButton; IBOutlet NSButton *startButton; IBOutlet NSTableView *tableView; NSArray *voiceList; } - (IBAction)sayIt:(id)sender; - (IBAction)stopIt:(id)sender; @end And my implementation code here: #import "AppController.h" @implementation AppController - (id)init { [super init]; //Log to help me understand what is happening NSLog(@"init"); speechSynth = [[NSSpeechSynthesizer alloc] initWithVoice:nil]; [speechSynth setDelegate:self]; voiceList = [[NSSpeechSynthesizer availableVoices] retain]; return self; } - (IBAction)sayIt:(id)sender { NSString *string = [[textField stringValue] stringByTrimmingCharactersInSet:[NSCharacterSet whitespaceCharacterSet]]; //Is the string zero-length? if([string length] == 0) { NSLog(@"String from %@ is a string with a length of %d.", textField, [string length]); [speechSynth startSpeakingString:@"Please enter a phrase first."]; } [speechSynth startSpeakingString:string]; NSLog(@"Started to say: %@", string); [stopButton setEnabled:YES]; [startButton setEnabled:NO]; } - (IBAction)stopIt:(id)sender { NSLog(@"Stopping..."); [speechSynth stopSpeaking]; } - (void) speechSynthesizer:(NSSpeechSynthesizer *)sender didFinishSpeaking:(BOOL)complete { NSLog(@"Complete = %d", complete); [stopButton setEnabled:NO]; [startButton setEnabled:YES]; } - (NSInteger)numberOfRowsInTableView:(NSTableView *)aTableView { return [voiceList count]; } - (id)tableView: (NSTableView *)tv objecValueForTableColumn: (NSTableColumn *)tableColumn row:(NSInteger)row { NSString *v = [voiceList objectAtIndex:row]; NSLog(@"v = %@",v); NSDictionary *dict = [NSSpeechSynthesizer attributesForVoice:v]; return [dict objectForKey:NSVoiceName]; } /* - (BOOL)respondsToSelector:(SEL)aSelector { NSString *methodName = NSStringFromSelector(aSelector); NSLog(@"respondsToSelector: %@", methodName); return [super respondsToSelector:aSelector]; } */ @end Hopefully, you guys can see something obvious that I've missed. Thank you!

    Read the article

  • not able to get a processed list in jquery variable

    - by Pradyut Bhattacharya
    I have html list <ol id="newlist"> <li>Test <ol> <li>1</li> <li>2</li> <li>3</li> </ol> </li> <li>Another test <ol> <li>1</li> </ol> </li> <li>Cool Test <ol> <li>1</li> <li>2</li> </ol> </li> </ol> Now i have hidden the list using the css... #newlist li { display:none; list-style: none; } I want to display the list and the only the descendants which have greater than 1 descendants... the output should be... Test 1 2 3 Another test Cool Test 1 2 I have used jquery and able to get the output... the code i used... $("ol#newlist > li").show(); for (var i = 0; i < $("ol#newlist > li").length; i++) { if ($("ol#newlist > li:eq(" + i + ") ol > li").length > 1) $("ol#newlist > li:eq(" + i + ") ol > li").show(); } the sample page here Now i want all the list in a single variable like i can get the lis in a variable... var $li = $("ol#newlist > li"); but the code $li.add($("ol#newlist > li:eq(" + i + ") ol > li")); is not working... the sample page here Please help... Thanks Pradyut India

    Read the article

  • Is it possible to make an OS in python?

    - by None
    I was just wondering if it was possible to make an operating system in python. Nothing fancy. Maybe not even a "real" operating system with a kernel and all. Just a python program that is run when someone inserts the disc containing it that will make a fullscreen display on top of the installed os.

    Read the article

< Previous Page | 424 425 426 427 428 429 430 431 432 433 434 435  | Next Page >