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  • What would be the Better db design for the old db structure?

    - by yawok
    i've a old database where i store the data of the holidays and dates in which they are celebrated.. id country hdate description link 1 Afghanistan 2008-01-19 Ashura ashura 2 Albania 2008-01-01 New Year Day new-year the flaws in the above structure is that, i repeat the data other than date for every festival and every year and every country.. For example, I store a new date for 2009 for ashura and afghanistan .. I tried to limit the redundancy and split the tables as countries (id,name) holidays (id, holiday, celebrated_by, link) // celebrated_by will store the id's of countries separated by ',' holiday_dates (holiday_id, date, year) // date will the full date and year will be as 2008 or 2009 Now i have some problems with the structure too.. consider that i store the holiday like Independence day , its common for more countries but will have different dates. so how to handle this and and the link will have to be different too.. And i need to list the countries which celebrates the same holiday and also when i describe about a single holiday i need to list all the other holidays that country would be celebrating.. And the most of all , i already have huge amount of data in the old tables and i need to split it to the new one once the new design is finalized... Any ideas?

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  • How to first get different related values from diferent SQL tables (PHP)

    - by Ole Jak
    I am triig to fill options list. I have 2 tables USERS and STREAMS I vant to get all streams and get names of users assigned to that streams. Users consists of username and id Streams consists of id, userID, streamID I try such code: <?php global $connection; $query = "SELECT * FROM streams "; $streams_set = mysql_query($query, $connection); confirm_query($streams_set); $streams_count = mysql_num_rows($streams_set); while ($row = mysql_fetch_array($streams_set)){ $userid = $row['userID']; global $connection; $query2 = "SELECT email, username "; $query2 .= "FROM users "; $query2 .= "WHERE id = '{$userid}' "; $qs = mysql_query($query2, $connection); confirm_query($qs); $found_user = mysql_fetch_array($qs); echo ' <option value="'.$row['streamID'].'">'.$row['userID'].$found_user.'</option> '; } ?> But it does not return USER names from DB=( So what shall I do to this code to see usernames as "options" text?

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  • searching array of words faster

    - by Martijn
    hi eveybody i want to look how much an array comes in a database. Its pretty slow and i want to know if there's a way of searching like multiple words or an whole array without a for loop.. i'm struggeling for a while now. here's my code $dateBegin = "2010-12-07 15:54:24.0"; $dateEnd = "2010-12-30 18:19:52.0"; $textPerson = " text text text text text text text text text text text text text text "; $textPersonExplode = explode(" ", $textPerson ); $db = dbConnect(); for ( $counter = 0;$counter <= sizeof($textPersonExplode)-1 ; $counter++) { $query = "SELECT count(word) FROM `news_google_split` WHERE `word` LIKE '$textPersonExplode[$counter]' AND `date` >= '$dateBegin' AND `date` <= '$dateEnd'"; $result = mysql_query($query) or die(mysql_error()); while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { $word[] = $textPersonExplode[$counter]; $count[] = $row[0]; } if (!$result) { die('Invalid query: ' . mysql_error()); } } thanks for the help.

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  • INSERT ... ON DUPLICATE KEY UPDATE with WHERE?

    - by Raven
    Hi! I'm doing a INSERT ... ON DUPLICATE KEY UPDATE but I need the update part to be conditional, only doing the update if some extra condition has changed. However, WHERE is not allowed on this UPDATE. Is there any workaround for this? I can't do combinations of INSERT/UPDATE/SELECT since this needs to work over a replication.

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  • Creating a multi-row "table" as part of a SELECT

    - by Chad Birch
    I'm not really sure how to describe my question (thus the awful title), but it's related to this recent question. The problem would be easily solved if there was some way for me to create a "table" with 4 rows as part of my SELECT (to use with NOT IN or MINUS). What I mean is, I can do this: SELECT 1, 2, 3, 4; And will receive one row from the database: | 1 | 2 | 3 | 4 | But is there any way to receive the following (without using UNION, I don't really want a query that's potentially thousands of lines long with a long list)? | 1 | | 2 | | 3 | | 4 |

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  • How can I select the required records?

    - by simple
    Tables: Product: [id, name, brand_id, is_published] Brand: [id, name, is_published] Awards: [id, name] ProductAwards [product_id, award_id] How do I select the list of PUBLISHED brands along with the number of AWARDS of brand's products that are Published. I am cool with all the part except issuing the "is_published" restriction when counting Awards. I hope this is clear; can anyone just suggest where to dig?

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  • Help with sql query

    - by user225269
    I have two tables: subject and student. I'm trying to count the number of subjects enrolled by each student. How do I do that?I'm trying the code below but it doesn't give the answer I need. Please help. SELECT COUNT( subject.SUBJECT ) , student.IDNO, student.FIRSTNAME, subject.SUBJECT FROM student, subject GROUP BY subject.SUBJECT LIMIT 0 , 30

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  • Array values changing unexpectedly

    - by Lizard
    I am using cakephp 1.2 and I have an array that appears to have a value change even though that variable is not being manipulated. Below is the code to that is causing me trouble. PLEASE NOTE - UPDATE Changing the variable name makes no difference to the outcome, The values get changed somewhere between the two print_r calls, and I can't see why the $this-find would do this . echo "Start of findCountByString()"; print_r($myArr); $test = $this->find('count', array( 'conditions' => $conditions, 'joins' => array('LEFT JOIN `articles_entities` AS ArticleEntity ON `ArticleEntity`.`article_id` = `Article`.`id`'), 'group' => 'Article.id' )); echo "End of findCountByString()"; print_r($myArr); I am getting the following output: Start of findCountByString() Array ( [0] => 4bdb1d96-c680-4c2c-aae7-104c39d70629 [1] => 4bdb1d6a-9e38-479d-9ad4-105c39d70629 [2] => 4bdb1b55-35f0-4d22-ab38-104e39d70629 [3] => 4bdb25f4-34d4-46ea-bcb6-104f39d70629 ) End of findCountByString() Array ( [0] => 4bdb1d96-c680-4c2c-aae7-104c39d70629 [1] => 4bdb1d6a-9e38-479d-9ad4-105c39d70629 [2] => 4bdb1b55-35f0-4d22-ab38-104e39d70629 [3] => '4bdb25f4-34d4-46ea-bcb6-104f39d70629' # This is now in inverted commas ) The the value in my array have changed, and I don't know why? Any suggestions?

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  • reterview data from two tables using inner join in cakephp

    - by user3593884
    I two tables from database one as user(id,first_name,last_name) and the second table location(id,country). I need to perform inner join with this two tables and the list should display first_name,last_name,country with condition user.id=location.id I have written sql queries in cakephp $this->set('users',$this->User->find('list', array( 'fields' => array('User.id', 'User.first_name','location.country'), array('joins' => array(array('table' => 'location', 'alias' => 'location', 'type' => 'INNER', 'conditions' => array('User.id = location.id'))))))); i get error -Unknown column 'location.country' in 'field list' Please help!

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  • How could I compare these database values in PHP?

    - by Dan
    So a user selects from a drop down list a value. I take this value, put it into a variable, then select from the database the ID value of that table A holding the selected value also. So now I'm trying to use that ID value to get to a many-to-many relationship table that has the selected value from table A to a different table B. The many-to-many relationship table has both IDs. How can I compare this using PHP? So it would be like: $A = $_POST['a']; $sql = "SELECT a, aID from TABLEA WHERE a = $A"; What do I do then to compare the aID with the many-to-many relationships table, then get the other ID in that table and then take that ID to get values from table B?

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  • I'm making a resume...what would you consider as intermediate python programming skills?

    - by user285884
    I've made a couple of scripts. One is a stock screener that can search through every stock. Another creates a heatmap that tells you what's performed well and badly over the past day. They aren't really that useful, just did them to work on my programming skills. I was able to throw some SQL in my scripts too. Would you call that intermediate? Thanks? How do you guys list your programming skills on your resume? Maybe there's a better way of putting it on my resume than "intermediate" or "beginner."

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  • PHP mysql_fetch does not return values

    - by Petr
    Hi, Being quite new with PHP, I cannot find any solution why this does not work. The query is OK and the resource is returned. But I dunno why fetch_assoc does not print values. Thanks $query=sprintf("SELECT ID,NAME FROM USERS WHERE PASS='%s' AND NAME='%s'",mysql_real_escape_string($p),mysql_real_escape_string($n)); $result=mysql_query($query); if ($result) { while ($row = mysql_fetch_assoc($result)) { echo $row['ID']; echo $row['NAME']; } } }

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  • custom function is not getting called

    - by nectar
    here my code - $child1 = create_childid()."01"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child1', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); echo $newid; update_level(); $child2 = create_childid()."02"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child2', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); update_level(); $child3 = create_childid()."03"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child3', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); update_level(); $child4 = create_childid()."04"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child4', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); update_level(); $child5 = create_childid()."05"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child5', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); update_level(); ERROR : update_level(); is executing only once why??

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  • Incorrect usage of UPDATE and ORDER BY

    - by nico55555
    I have written some code to update certain rows of a table with a decreasing sequence of numbers. To select the correct rows I have to JOIN two tables. The last row in the table needs to have a value of 0, the second last -1 and so on. To achieve this I use ORDER BY DESC. Unfortunately my code brings up the following error: Incorrect usage of UPDATE and ORDER BY My reading suggests that I can't use UPDATE, JOIN and ORDER BY together. I've read that maybe subqueries might help? I don't really have any idea how to change my code to do this. Perhaps someone could post a modified version that will work? while($row = mysql_fetch_array( $result )) { $products_id = $row['products_id']; $products_stock_attributes = $row['products_stock_attributes']; mysql_query("SET @i = 0"); $result2 = mysql_query("UPDATE orders_products op, orders ord SET op.stock_when_purchased = (@i:=(@i - op.products_quantity)) WHERE op.orders_id = ord.orders_id AND op.products_id = '$products_id' AND op.products_stock_attributes = '$products_stock_attributes' AND op.stock_when_purchased < 0 AND ord.orders_status = 2 ORDER BY orders_products_id DESC") or die(mysql_error()); }

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  • 2 table SQL Query weird results

    - by javArc
    Ok this is driving me nuts, I need to write an SQL query that will grab product information from 2 tables. The first table 'products' contains the productId, productname, quantityperunit and unitprice. Now I can search by productname and categoryname individually, but when I try to combine the 2 I get crazy results, Here's the query: "SELECT DISTINCT productId, productname, quantityperunit, unitprice FROM products pr, categories ca WHERE pr.categoryID = ca.categoryID AND ProductName LIKE '%" + searchTerm + "%' OR CategoryName LIKE '%" + searchTerm + "%' excuse the java style in there, here it is formatted better: SELECT DISTINCT productId, productname, quantityperunit, unitprice FROM products pr, categories ca WHERE pr.categoryID = ca.categoryID AND ProductName LIKE 'Tofu' OR CategoryName LIKE 'Tofu' any help would be appreciated.

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  • Convert tax like IRS function to SQL

    - by CrashRoX
    Trying to convert this tax-like IRS function http://stackoverflow.com/questions/1817920/calculating-revenue-share-at-different-tiers to SQL. The assumption is the table would be one column (price) and the tiers will be added dynamically. My first attempt has some case statements that didn't work out well. I have since scrapped it :) Thanks for the help!

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  • how can I check data has been inserted successfully

    - by Piyush
    I have two insert statements.Second one will be executed only after successful execution of First one.What I wd like to do is- $sqlone="Insert into ....."; $sqltwo="Insert into....."; If(mysql_query($sqlone)) { If(mysql_query($sqltwo)) { show message Data inserted in both tables. } }

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  • Need help with a sub query/group/order (get latest comment for each ordered topic)

    - by Scarface
    Hey guys I have a query that currently finds the latest comment for each of a user's topics and then orders topics by that comment's timestamp. What I want to do is expand on this query's use and print the latest comment for each topic. The problem with this query is that while it orders the topics correctly, it prints seemingly random comments for each topic. I am trying to implement a sub query but I am not quite sure how to approach it. I was thinking that I just had to somehow use this query to get the comments. If anyone has any ideas I would really appreciate it. Here is what I think I need to add SELECT * FROM comments where topic_id='$topic_id' ORDER BY timestamp DESC LIMIT 1 Here is the query I need to modify SELECT topic.topic_title, topic.content_type, topic.subject_id, topic.creator, topic.description, topic.topic_id,comments.message,comments.user FROM comments JOIN topic ON topic.topic_id = comments.topic_id WHERE topic.creator = '$user' AND comments.timestamp > $week GROUP BY topic_id ORDER BY MAX(comments.timestamp) DESC

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