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  • connection textfield and html table with database

    - by klox
    dear all..i have a textfield <tr> <td> <td><input type="text" id="mod"></td> </td> </tr> and a cell <tr> <td><div id="value">//i want data show here</div> </td> </tr> beside that, i've a table "settingdata" in database it consist of 2 field:itemdata and remark.. itemdata's value are "UD" and remark's value are "FM=87.5-108.0MHZ"... what must i do if i want after type "0103UD" at textfield inside <div id="value"></div> can show "FM=87.5-108.0mhz"...

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  • Joining two mysql_fetch_arrays

    - by John Harbert
    I am trying to piece two queries together. Below is the code Im using. However the table is splitting up the data. How can I remedy this? Or what better solutions are there? while($row = mysql_fetch_array($result)) { echo "<tr id='centered' >"; echo "<td class='leftalign'>" . $row['Quarter_Name'] . "</td>"; echo "<td>" . $row['Quarterly_yield'] . "</td>"; echo "<td>" . $row['Quarterly_yield'] . "</td>"; echo "<td>" . $row['Quarterly_yield'] . "</td>"; } while($row = mysql_fetch_array($result8)) { echo "<td>" . $row['Quarterly_yield'] . "</td>"; }

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  • Sphinx without using an auto_increment id

    - by squeeks
    I am current in planning on creating a big database (2+ million rows) with a variety of data from separate sources. I would like to avoid structuring the database around auto_increment ids to help prevent against sync issues with replication, and also because each item inserted will have a alphanumeric product code that is guaranteed to be unique - it seems to me more sense to use that instead. I am looking at a search engine to index this database with Sphinx looking rather appealing due to its design around indexing relational databases. However, looking at various tutorials and documentation seems to show database designs being dependent on an auto_increment field in one form or another and a rather bold statement in the documentation saying that document ids must be 32/64bit integers only or things break. Is there a way to have a database indexed by Sphinx without auto_increment fields as the id?

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  • adding count( ) column on each row

    - by Arsenal
    I'm not sure if this is even a good question or not. I have a complex query with lot's of unions that searches multiple tables for a certain keyword (user input). All tables in which there is searched are related to the table book. There is paging on the resultset using LIMIT, so there's always a maximum of 10 results that get withdrawn. I want an extra column in the resultset displaying the total amount of results found however. I do not want to do this using a seperate query. Is it possible to add a count() column to the resultset that counts every result found? the output would look like this: ID Title Author Count(...) 1 book_1 auth_1 23 2 book_2 auth_2 23 4 book_4 auth_.. 23 ... Thanks!

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  • Help optimizing a query with 16 subqueries

    - by Webnet
    I have indexes/primaries on all appropriate ID fields for each type. I'm wondering though how I could make this more efficient. It takes a while to load the page with only 15,000 rows and that'll quickly grow to 500k. The $whereSql variable simply has a few more parameters for the main ebay_archive_listing table. NOTE: This is all done in a single query because I have ASC/DESC sorting for each subquery value. NOTE: I've converted some of the sub queries to INNER JOIN's SELECT product_master.product_id, ( SELECT COUNT(listing_id) FROM ebay_archive_product_listing_assoc '.$listingCountJoin.' WHERE ebay_archive_product_listing_assoc.product_id = product_master.product_id) as listing_count, sku, type_id, ( SELECT AVG(ebay_archive_listing.current_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as average_bid_price, ( SELECT AVG(ebay_archive_listing.buy_it_now_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.buy_it_now_price > 0 ) as average_buyout_price, ( SELECT MIN(ebay_archive_listing.current_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as lowest_bid_price, ( SELECT MAX(ebay_archive_listing.current_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as highest_bid_price, ( SELECT MIN(ebay_archive_listing.buy_it_now_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as lowest_buyout_price, ( SELECT MAX(ebay_archive_listing.buy_it_now_price) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.current_price > 0 ) as highest_buyout_price, round((( SELECT COUNT(ebay_archive_listing.id) FROM ebay_archive_listing INNER JOIN ebay_archive_product_listing_assoc ON ( ebay_archive_product_listing_assoc.listing_id = ebay_archive_listing.id AND ebay_archive_product_listing_assoc.product_id = product_master.product_id ) WHERE '.$whereSql.' AND ebay_archive_listing.status_id = 2 ) / ( SELECT COUNT(listing_id) FROM ebay_archive_product_listing_assoc '.$listingCountJoin.' WHERE ebay_archive_product_listing_assoc.product_id = product_master.product_id ) * 100), 1) as sold_percent FROM product_master '.$joinSql.' WHERE product_master.product_id IN ( SELECT product_id FROM ebay_archive_product_listing_assoc INNER JOIN ebay_archive_listing ON ( ebay_archive_listing.id = ebay_archive_product_listing_assoc.listing_id AND '.$whereSql.' ) )

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  • Executing multiple update statements in PHP

    - by theband
    I have three update statements to be executed in PHP, i am getting the values of all these as return parameters. How to execute each statement independely and finally show the end user the result that it has been successfully updated. <?php public function name($parameter1,$parameter2.... $parametern) { $records=array(); $sql=""; $sql2=""; $sql3=""; $result=mysql_query($sql); //return $result; if(!$result){throw new Exception(mysql_error());} if(mysql_num_rows($result)==0){return $records;} while($row=mysql_fetch_assoc($result)){$records[]=$row;} return $records; } ?> Then how finally we can get the result in my row object.

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  • Update all but one result?

    - by Jack M.
    I'm trying to update a table to remove all but the first instance of a group. Basically, I have a table with vehicle data related to an insurance policy. Each policy should only have one power_unit. Everything else should be a towed unit. Unfortunately, a bug has been duplicating power units, and now I need to clean this up. There are ~10k records in the database, and ~4k of them have doubled up power units. The important bits of my table (call it test1 for now) are: +------------+---------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +------------+---------+------+-----+---------+----------------+ | id | int(10) | NO | PRI | NULL | auto_increment | | policy_id | int(10) | NO | | NULL | | | power_unit | int(1) | NO | | 0 | | +------------+---------+------+-----+---------+----------------+ And some sample data: +----+-----------+------------+ | id | policy_id | power_unit | +----+-----------+------------+ | 1 | 1 | 1 | | 2 | 1 | 1 | | 3 | 1 | 1 | | 4 | 2 | 1 | | 5 | 2 | 1 | | 6 | 2 | 1 | | 7 | 4 | 1 | | 8 | 4 | 1 | | 9 | 4 | 1 | | 10 | 5 | 1 | | 11 | 5 | 1 | | 12 | 6 | 1 | +----+-----------+------------+ Basically I'd like to end up where policy_id 1 has only one power_unit=1. Same for policy_id 2, 3, 4, etc. For policy_id 6, nothing should change (there is only one entry, and it is a power_unit already). I don't know if this is possible, but it was an intriguing problem for me, so I thought you guys might find it the same.

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  • Best way to update record X when Y is inserted

    - by Saif Bechan
    I have a huge table that is mainly used for backup and administrative purposes. The only records that matters is the last inserted record. On every hit to order by time inserted is just too slow. I want keep a separate table with the last inserted id. In PHP I now insert, get last inserted id, and update the other table. Is there a more efficient way to do this.

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  • Strange SQL problem selecting multiple values for same column

    - by Nubber
    Hello there, Been at this for a few hours now and I can't make any sense of it. I've used this way of selecting multiple values for same column a few times, but there is something weird with this one. SELECT * FROM employee as s INNER JOIN works AS w1 ON w1.name = s.name INNER JOIN employee AS w2 ON w2.name = s.name INNER JOIN employee AS w3 ON w3.name = s.name WHERE w2.city = 'Washington' Basically what I want to do is find all companies which have people in all the cities. The company name is under 'works'. The problem is however that if I have the WHERE w2.city='Washington' it will make ALL the cities match Washington when it should only touch w2 and leave w3 alone so I could match it with another value. Anyone know why its doing this? Or know a better way to do it. Thank you very much in advance.

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  • Where to store users visited pages?

    - by kofto4ka
    Hi there. I have a project, where I have posts for example. The task is next: I must show to user his last posts visit. This is my solution: every time user visits new (for him) topic, I create a new record in table visits. Table visits has next structure: id, user_id, post_id, last_visit. Now my tables visits has ~14,000,000 records and its still growing every day.. May be my solution isnt optimal and exists another way how to store users visits? Its important to save every visit as standalone record, because I also have feature to select and use users visits. And I cant purge this table, because data could be needed later month, year. How I could optimize this situation?

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  • mysql_fetch_assoc() expects parameter 1 to be resource, boolean given in

    - by user2533440
    I cannot figure out whats wrong with this code. Every time i try to run this file I get error mysql_fetch_assoc() expects parameter 1 to be resource <?php $q = "select * from tbfood"; $rs = mysql_query($q); while($msg = mysql_fetch_assoc($rs)){ echo "<p>".$msg["name"]."</p>"; echo "<p>".$msg["price"]."</p>"; if ($msg['idDruh'] == 1) { echo "string1"; } elseif ($msg['idDruh'] == 2) { echo "string2"; } elseif ($msg['idDruh'] == 3) { echo "string3"; } elseif ($msg['idDruh'] == 4) { echo "string4"; } elseif ($msg['idDruh'] == 5) { echo "string5"; } elseif ($msg['idDruh'] == 6) { echo "string6"; } elseif ($msg['idDruh'] == 7) { echo "string7"; } } ?>

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  • Operand should contain 1 column(s) about insert into & select

    - by user1038890
    "insert into NodeProfileSections (profile_no, tpl_section_no) select (np.profile_no, tps.tpl_section_no) from NodeProfile np, TemplateProfileSection tps, TemplateProfile tp where np.hostname = '%s' AND np.role = '%s' AND tp.tpl_profile_no = tps.tpl_profile_no AND tp.tpl_name = '%s' AND tp.role = '%s' AND tps.tpl_section_name = '%s';" %(hostname, role, template_name, role, section_name) error_message = 'Operand should contain 1 column(s)' How to solve this problem?

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  • Online Hotel Booking System, Simultaneous Booking?

    - by KiiroSora09
    I'm asked to create an online booking system with online payment and I'm wondering what to do in the case when 2 customers booked for the same room(s) at the same time. For Example: At the same time: Customer1 and Customer2 booked for a standard room which only has 1 room available. (The Room availability will display that there is still 1 room available). And then they hit the 'confirm' button at the same time.

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  • SELECT Data from multiple tables?

    - by Kyle R
    I have 3 tables, with 3 fields all the same. I basically want to select information from each table For example: userid = 1 I want to select data from all 3 tables, where userid = 1 I am currently using: SELECT r.*, p.*, l.* FROM random r LEFT JOIN pandom p ON r.userid = p.userid LEFT JOIN landom l ON l.userid = r.userid WHERE r.userid = '1' LIMIT 0, 30 But it doesn't seem to work.

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  • least value in count

    - by Nyfer
    i have a table employee(id,dept_id,salary,hire_date,job_id) . the following query i have to execute. Show all the employee who were hired on the day of the week on which least no of employee were hired. i have done the query, but am not able to get the least. please check if am correct. select id, WEEKDAY(hire_date)+1 as days,count(WEEKDAY(hire_date)+1) as count from test.employee group by days

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