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  • MySql Alter Syntax error with mulitple FK

    - by acidzombie24
    If i do the first one i have no problem. When i do addition i get a syntax error. What is wrong with the syntax? The error says syntax error near [entire 2nd line] alter table `ban_Status` add FOREIGN KEY (`banned_user`) REFERENCES `user_data`(`id`) alter table `ban_Status` add FOREIGN KEY (`banned_user`) REFERENCES `user_data`(`id`), FOREIGN KEY (`banning_user`) REFERENCES `user_data`(`id`), FOREIGN KEY (`unban_user`) REFERENCES `user_data`(`id`)

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  • How to put comma in counted numbers?

    - by Ronnie Chester Lynwood
    hey huys im counting my table with this code: $county = mysql_query("SELECT COUNT(id) from table where type = 'application'"); $county = mysql_result($county, 0); $applications = ''.$county.''; this give me result like 1156563. but I want to see it like 1,156,563 with commas. how can i do this?

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  • Issue with SQL query for activity stream/feed

    - by blabus
    I'm building an application that allows users to recommend music to each other, and am having trouble building a query that would return a 'stream' of recommendations that involve both the user themselves, as well as any of the user's friends. This is my table structure: Recommendations ID Sender Recipient [other columns...] -- ------ --------- ------------------ r1 u1 u3 ... r2 u3 u2 ... r3 u4 u3 ... Users ID Email First Name Last Name [other columns...] --- ----- ---------- --------- ------------------ u1 ... ... ... ... u2 ... ... ... ... u3 ... ... ... ... u4 ... ... ... ... Relationships ID Sender Recipient Status [other columns...] --- ------ --------- -------- ------------------ rl1 u1 u2 accepted ... rl2 u3 u1 accepted ... rl3 u1 u4 accepted ... rl4 u3 u2 accepted ... So for user 'u4' (who is friends with 'u1'), I want to query for a 'stream' of recommendations relevant to u4. This stream would include all recommendations in which either the sender or recipient is u4, as well as all recommendations in which the sender or recipient is u1 (the friend). This is what I have for the query so far: SELECT * FROM recommendations WHERE recommendations.sender IN ( SELECT sender FROM relationships WHERE recipient='u4' AND status='accepted' UNION SELECT recipient FROM relationships WHERE sender='u4' AND status='accepted') OR recommendations.recipient IN ( SELECT sender FROM relationships WHERE recipient='u4' AND status='accepted' UNION SELECT recipient FROM relationships WHERE sender='u4' AND status='accepted') UNION SELECT * FROM recommendations WHERE recommendations.sender='u4' OR recommendations.recipient='u4' GROUP BY recommendations.id ORDER BY datecreated DESC Which seems to work, as far as I can see (I'm no SQL expert). It returns all of the records from the Recommendations table that would be 'relevant' to a given user. However, I'm now having trouble also getting data from the Users table as well. The Recommendations table has the sender's and recipient's ID (foreign keys), but I'd also like to get the first and last name of each as well. I think I require some sort of JOIN, but I'm lost on how to proceed, and was looking for help on that. (And also, if anyone sees any areas for improvement in my current query, I'm all ears.) Thanks!

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  • Can I lock tables in an IF statement in MySQL?

    - by MalcomTucker
    This is throwing a syntax error - --from body of a stored proc IF (name = in_name) SET out_id = temp; ELSE LOCK TABLE People WRITE; INSERT INTO People (Name) VALUES (in_name); UNLOCK TABLE; SELECT LAST_INSERT_ID() INTO out_id END IF do I have to lock any tables I need at the start of the SP?

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  • Fractional y-var in ggplot

    - by Misha
    How can I easily create a fractional y-value when using ggplot? t <- as.factor(test=sample(seq(0,100,10),1000,rep=T)) d <- as.factor(sample(c(0,1),1000,rep=T) p <- data.frame(t,d) My best shot was: ggplot(p,aes(x=t,y=prop.table(table(t,d),1)[,1])) + geom_point() However this doesnt work and I guess there is an easier way around this...

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  • mysql insert with auto-increment column

    - by czuroski
    Hello, I am trying to insert data into a mysql table from a csv file. I am using the infile sql command, but I am having trouble because the first column of the table is an id that is set as an auto increment field. what do I have to set my first column value to in order to get this to work, or can I do it at all? Thanks

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  • Nhibernate Common columns in base class

    - by sukh
    I want to design following scenario Base class (Id, Name, order, Value) 3 Derived classes derive1, derive2, derive3 inheriting properties from base There is no table for base class. And 1 table for each derived class. 3 tables have same columns. How can I create mapping file ignoring base class? Do I need to create 1 mapping file for each derived class? can I achieve this using only 1 mapping file?

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  • Autoincrement based on a set of other columns

    - by slack3r
    I have a table Course and every Course has many Resources. Course ========== course_id Resource ========== course_id number I want something like a seperate autoincrement for each course_id. Or, in other words, I want to auto-enumerate the resources for a given course. For example, the resource table could look something like: course_id | number ================== 1 | 1 1 | 2 2 | 1 1 | 3 1 | 4 2 | 2 2 | 3 and so on. I want to do this in SQL, using IBM DB2.

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  • [Zend Framework] How to format Zend_db Rowset output?

    - by rasouza
    I have a model which is referenced to a table registries extending Zend_Db and some methods which bascially uses fetchAll() all the time. What happens is: my table has a DATE field and I'd like it to output already formated when I call $row-reg_date. Is it possible by doing something in the model or do I have to manually format?

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  • How can I change column length using HQL query?

    - by gmugmu
    I tried session.createSQLQuery("ALTER TABLE People MODIFY address VARCHAR(1000);").executeUpdate(); but this throws org.hibernate.exception.SQLGrammarException: could not execute native bulk manipulation query After a lot of googling, the recommendation is to use HQL instead of SQL query to do bulk updates. Not sure how to use HQL to accomplish this. There seems to be no decent HQL documentation for updating column length in a table. Thanks so much for the help.

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  • What do you call the concept of dynamic data definition?

    - by DJTripleThreat
    Maybe this is simpler and more straightforward then what I'm thinking but I can't seem to find this concept on google anywhere. The concept is this: You have a table in a database and the table has a specified number of columns. However, it has been asked of me by previous clients that there also be a set of dynamic user defined columns that can be added on the fly. What is this concept called and is it considered a design pattern?

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  • Tree structured resource Authorization

    - by user323883
    I have portfolio table with portoflio_id and parent_portfolio_id and I have user table now some users may have access to all portfolios, or selective portfolios or depending on group, everything under a portfolio tree. can someone suggest a good schema or any existing framework

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  • How can you tell which columns are unused in ALL_TAB_COLS?

    - by thecoop
    When you query the ALL_TAB_COLS view on Oracle 9i, it lists columns marked as UNUSED as well as the 'active' table columns. There doesn't seem to be a field that explicitly says whether a column is UNUSED, or any view I can join to that lists the unused columns in a table. How can I easily find out which are the unused columns, so I can filter them out of ALL_TAB_COLS?

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  • jpa relationship-Google app engine

    - by megala
    I created two tables in google appengine datastore using JPA. Table1: *groupname pk *groupid *groupdesc *emailper Table2: *groupname *memberid *membername My constraint is if i enter data into table2 it check whether group already exists or not in table.If exists than only it store the data into table .How to solve this?

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  • Making a function for selecting from MySQL, how is mine?

    - by Doug
    This is my first time. I will appreciate any thoughts, tips, and what not. How can I improve this? Ultimately, I don't want so many selects in my script. function mysqlSelectCodes($table, $where, $order, $limit) { $sql = "SELECT * FROM $table WHERE $where ORDER BY $order LIMIT $limit" or die(mysql_error()); }

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  • MySQL Hibernate sort on 2 columns

    - by sammichy
    I have a table as follows Table item { ID - Primary Key content - String published_date - When the content was published create_date - When this database entry was created } Every hour (or specified time interval) I run a process to update this table with data from different sources (websites). I want to display the results according to the following rules. 1. The entries created each time the process runs should be grouped together. So the entries from the 2nd process run will always be after the entries from the first process run even if the published_date of an entry from the first run is after the published_date of an entry from the 2nd run. 2. Within the grouping by run, the entries by sorted by published_date 3. Another restriction is that I prefer that data from the same source not be grouped together. If I do the sort by create_date, published_date I will end up with data from source a, data from source b etc. I prefer that the data within each hour be mixed up for better presentation If I add a column to this table and store a counter which increments each time the process is run, it is possible to create a query to sort first by counter and then by published_dt. Is there a way to do it without adding a field? I'm using Hibernate over MySQL. e.g. Hour 1 (run 1) 4 rows collected from site a (rows 1-4) 3 rows collected from site b (rows 5-7) hour 2 (run 2) 2 row collected from site a (rows 8-9) 3 rows collected from site b (rows 10-12) ... After each run, new records are added to the database from each website. The create date is the time when the record was created in the database. The published date is part of the content and is read in from the external source. When the results are displayed I would like rows to be grouped together based on the hour they were published in. So rows 1-7 would be displayed before rows 8-12. Within each hourly grouping, I would like to sort the results by published date (timestamp). This is necessary so that the posts from all the sites collected in that hour are not grouped together but rather mixed in with each other.

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  • Oracle join issue

    - by acadia
    Hello, I have 3 tables and I am joining these 2 tables as follows: SELECT EMP.FNAME,EMP.LNAME,EMP.AGE,EMPD.TQ,EMPD.TA,CTY.CITY_NAME FROM EMPLOYEE EMP,EMPLOYEE_DETAIL EMPD, CITY CTY WHERE EMP.EMP_ID=EMPD.EMP_ID AND EMPD_CITY_ID=CTY.CITY_ID I want to display records even if City record is not in CITY table. For eg. if City_ID record for say 10 is not in City table but there is an employee detail record with City_id 10 it should display City_name as null instead of not displaying the record at all. Appreciate your help

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  • Excel: VLOOKUP that returns true or false?

    - by Svish
    In Excel we have the VLOOKUP function that looks for a value in a column in a table and then returns a value from a given column in that table if it finds something. If it doesn't, it produces an error. Is there a function that just returns true or false depending on if the value was found in a column or not?

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  • Nhibernate schema clasue

    - by Phil Whittaker
    How do I use the schema clause on a bag object in Nhibernate mapping? I have an table that I need to sepcify the schema for and the nhibernate documentation talks about table schema but I can't find any further details...

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  • SQL query joining rows with same value

    - by user1285737
    I need to write a query that creates a view that calculates the total cost of each sale, by considering quantity and price of each bought item. The view should return the debit and total cost. In the answer each debit-number should only occur once. Thanks in advance Table ITEM: ID NAME PRICE 118 Jeans 100 120 Towel 20 127 Shirt 55 Table DEBIT: DEBIT ITEM Quantity 100581 118 5 100581 120 1 100586 127 5

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