Double linking array in Python
- by cdecker
Since I'm pretty new this question'll certainly sound stupid but I have no idea about how to approach this.
I'm trying take a list of nodes and for each of the nodes I want to create an array of predecessors and successors in the ordered array of all nodes.
Currently my code looks like this:
nodes = self.peers.keys()
nodes.sort()
peers = {}
numPeers = len(nodes)
for i in nodes:
peers[i] = [self.coordinator]
for i in range(0,len(nodes)):
peers[nodes[i%numPeers]].append(nodes[(i+1)%numPeers])
peers[nodes[(i+1)%numPeers]].append(nodes[i%numPeers])
# peers[nodes[i%numPeers]].append(nodes[(i+4)%numPeers])
# peers[nodes[(i+4)%numPeers]].append(nodes[i%numPeers])
The last two lines should later be used to create a skip graph, but that's not really important. The problem is that it doesn't really work reliably, sometimes a predecessor or a successor is skipped, and instead the next one is used, and so forth. Is this correct at all or is there a better way to do this? Basically I need to get the array indices with certain offsets from each other.
Any ideas?
