Search Results

Search found 12055 results on 483 pages for 'password complexity'.

Page 444/483 | < Previous Page | 440 441 442 443 444 445 446 447 448 449 450 451  | Next Page >

  • php import larg table to phpmyadmin database

    - by safaali
    hi, I am so worry :( I dropped one of the tables from the database accidentally. fortunately, I have back-up. (I have used the "Auto backup for mysql") The back-up of the table is stored as .txt file (56 Megabytes) on my PC. I tried to import it by PhpMyAdmin and the import failed because the file is too large to import. then I uploaded the file to /home/tablebk directory. I have some experiences in php. I know that I would import it with this code, but i don't know the sql statment for this import. what is have to put as $line variable? please help me :( :( <?php $dbhost = 'localhost'; $dbuser = 'mysite'; $dbpw = 'password'; $dbname = 'databasename'; $file = @fopen('country.txt', 'r'); if ($file) { while (!feof($file)) { $line = trim(fgets($file)); $flag = mysql_query($line); if (isset($flag)) { echo 'Insert Successfully<br />'; } else { echo mysql_error() . '<br/>'; } flush(); } fclose($file); } echo '<br />End of File'; ?>

    Read the article

  • Mechanize form submit not going to the correct response page, no errors as to why. Something I'm doing?

    - by Zack Shapiro
    I threw this all in one controller for testing purposes. My code fills out the form correctly for adding a new address to your Amazon account. There are two buttons that submit this form, one takes you to add a new address which is what I don't want, and the other is just a Save & Continue input/image. When I submit the form via that button, as I do below, the form is still on the page, filled out as I have with my code. Inspecting the page titles, they're the same. There are no discernible errors that Mechanize or Amazon spit back. Any ideas? class AmazonCrawler def initialize @agent = Mechanize.new do |agent| agent.user_agent_alias = 'Mac Safari' agent.follow_meta_refresh = true agent.redirect_ok = true end end def login # login_url = "https://www.amazon.com/ap/signin?_encoding=UTF8&openid.assoc_handle=usflex&openid.claimed_id=http%3A%2F%2Fspecs.openid.net%2Fauth%2F2.0%2Fidentifier_select&openid.identity=http%3A%2F%2Fspecs.openid.net%2Fauth%2F2.0%2Fidentifier_select&openid.mode=checkid_setup&openid.ns=http%3A%2F%2Fspecs.openid.net%2Fauth%2F2.0&openid.ns.pape=http%3A%2F%2Fspecs.openid.net%2Fextensions%2Fpape%2F1.0&openid.pape.max_auth_age=0&openid.return_to=https%3A%2F%2Fwww.amazon.com%2Fgp%2Fcss%2Fhomepage.html%3Fie%3DUTF8%26ref_%3Dgno_yam_ya" login_url = "https://www.amazon.com/gp/css/account/address/view.html?ie=UTF8&ref_=ya_add_address&viewID=newAddress" @agent.get(login_url) form = @agent.page.forms.first form.email = "[email protected]" form.radiobuttons.first.value = "0" form.radiobuttons.last.check form.password = "my_password" dashboard = @agent.submit(form) end end class UsersController < ApplicationController def index response = AmazonCrawler.new.login form = response.forms[1] # fill out form form.enterAddressFullName == "Your Name" form.enterAddressAddressLine1 = "123 Main Street" form.enterAddressAddressLine2 = "Apartment 34" form.enterAddressCity = "San Francisco" form.enterAddressStateOrRegion = "CA" form.enterAddressPostalCode = "94101" form.enterAddressPhoneNumber = "415-555-1212" form.AddressType = "RES" new_response = form.submit( form.button_with(value: /Save.*Continue/) ) end end

    Read the article

  • Cannot Resize DIV to anything smaller than maximum width

    - by MxmastaMills
    Quick CSS Question. I cannot seem to figure out a very simple CSS/HTML problem. Here's a JSFiddle. http://jsfiddle.net/BmM6t/ Basically, these two divs are not resizing to anything less than 100% width: <div id="main_pic" class="main_div"> THIS IS WHERE THE MAIN PIC WILL GO. </div> <div id="signin" class="main_div"> SIGN IN TO THE SITE! <form> <label for="name">EMAIL/USERNAME:</label> <input type="text" name="name" id="name"> <label for="email">PASSWORD:</label> <input type="text" name="email" id="email"> <br /> <input type="submit" value="Let's Play!"> </form> </div> You'll see that the two divs with class main_div actually take up the entire width of the screen for some reason (you can see that if you inspect the element) even though their widths are clearly written. When you try to change the width of one of the main_div's it changes the width but if you inspect the element, it just changes the width of the object and adds padding around it to make sure it still takes up the entire width of the screen. I'm sure it's some little error I've made but I can't find it. Thanks for the help!

    Read the article

  • update record only works when there is no auto_increment

    - by every_answer_gets_a_point
    i am accessing a mysql table through an odbc connection in excel here is how i am updating the table: With rs .AddNew ' create a new record ' add values to each field in the record .Fields("datapath") = dpath .Fields("analysistime") = atime .Fields("reporttime") = rtime .Fields("lastcalib") = lcalib .Fields("analystname") = aname .Fields("reportname") = rname .Fields("batchstate") = "bstate" .Fields("instrument") = "NA" .Update ' stores the new record End With when the schema of the table is this, updating it works: create table batchinfo(datapath text,analysistime text,reporttime text,lastcalib text,analystname text, reportname text, batchstate text, instrument text); but when i have auto_increment in there it does not work: CREATE TABLE batchinfo ( rowid int(11) NOT NULL AUTO_INCREMENT, datapath text, analysistime text, reporttime text, lastcalib text, analystname text, reportname text, batchstate text, instrument text, PRIMARY KEY (rowid) ) ENGINE=InnoDB AUTO_INCREMENT=67 DEFAULT CHARSET=latin1 has anyone experienced a problem like this where updating does not work when there is an auto_increment field involved? connection string: Private Sub ConnectDB() Set oConn = New ADODB.Connection oConn.Open "DRIVER={MySQL ODBC 5.1 Driver};" & _ "SERVER=localhost;" & _ "DATABASE=employees;" & _ "USER=root;" & _ "PASSWORD=pas;" & _ "Option=3" End Sub also here's the rs.open: rs.Open "batchinfo", oConn, adOpenKeyset, adLockOptimistic, adCmdTable

    Read the article

  • How would I construct a terminal command to download a folder with wget from a Media Temple (gs) ser

    - by racl101
    I'm trying to download a folder using wget on the Terminal (I'm usin a Mac if that matters) because my ftp client sucks and keeps timing out. It doesn't stay connected for long. So I was wondering if I could use wget to connect via ftp protocol to the server to download the directory in question. I have searched around in the internet for this and have attempted to write the command but it keeps failing. So assuming the following: ftp username is: [email protected] ftp host is: ftp.s12345.gridserver.com ftp password is: somepassword I have tried to write the command in the following ways: wget -r ftp://[email protected]:[email protected]/path/to/desired/folder/ wget -r ftp://serveradmin:[email protected]/path/to/desired/folder/ When I try the first way I get this error: Bad port number. When I try the second way I get a little further but I get this error: Resolving s12345.gridserver.com... 71.46.226.79 Connecting to s12345.gridserver.com|71.46.226.79|:21... connected. Logging in as serveradmin ... Login incorrect. What could I be doing wrong?

    Read the article

  • Developers: How does BitLocker affect performance?

    - by Chris
    I'm an ASP.NET / C# developer. I use VS2010 all the time. I am thinking of enabling BitLocker on my laptop to protect the contents, but I am concerned about performance degradation. Developers who use IDEs like Visual Studio are working on lots and lots of files at once. More than the usual office worker, I would think. So I was curious if there are other developers out there who develop with BitLocker enabled. How has the performance been? Is it noticeable? If so, is it bad? My laptop is a 2.53GHz Core 2 Duo with 4GB RAM and an Intel X25-M G2 SSD. It's pretty snappy but I want it to stay that way. If I hear some bad stories about BitLocker, I'll keep doing what I am doing now, which is keeping stuff RAR'ed with a password when I am not actively working on it, and then SDeleting it when I am done (but it's such a pain).

    Read the article

  • encrypting passwords in a python conf file on a windows platform

    - by Richard
    Hello all. I have a script running on a remote machine. db info is stored in a configuration file. I want to be able to encrypt the password in the conf text so that no one can just read the file and gain access to the database. This is my current set up: My conf file sensitive info is encoded with base64 module. The main script then decodes the info. I have compiled the script using py2exe to make it a bit harder to see the code. My question is: Is there a better way of doing this? I know that base64 is not a very safe way of encrypting. Is there a way to encode using a key? I also know that py2exe can be reversed engineered very easily and the key could be found. Any other thoughts? I am also running this script on a windows machine, so any modules that are suggested should be able to run in a windows environment with ease. I know there are several other posts on this topic but I have not found one with a windows solution, or at least one that is will explained.

    Read the article

  • SQL Server Connection Timeout C#

    - by Termin8tor
    First off I'd like to let everyone know I have searched my particular problem and can't seem to find what's causing my problem. I have an SQL Server 2008 instance running on a network machine and a client I have written connecting to it. To connect I have a small segment of code that establishes a connection to an sql server 2008 instance and returns a DataTable populated with the results of whatever query I run against the server, all pretty standard stuff really. Anyway the issue is, whenever I open my program and call this method, upon the first call to my method, regardless as to what I've set my Connection Timeout value as in the connection string, it takes about 15 seconds and then times out. Bizarrely though the second or third call I make to the method will work without a problem. I have opened up the ports for SQL Server on the server machine as outlined in this article: How to Open firewall ports for SQL Server and verified that it is correctly configured. Can anyone see a particular problem in my code? string _connectionString = "Server=" + @Properties.Settings.Default.sqlServer + "; Initial Catalog=" + @Properties.Settings.Default.sqlInitialCatalog + ";User Id=" + @Properties.Settings.Default.sqlUsername + ";Password=" + @Properties.Settings.Default.sqlPassword + "; Connection Timeout=1"; private DataTable ExecuteSqlStatement(string command) { using (SqlConnection conn = new SqlConnection(_connectionString)) { try { conn.Open(); using (SqlDataAdapter adaptor = new SqlDataAdapter(command, conn)) { DataTable table = new DataTable(); adaptor.Fill(table); return table; } } catch (SqlException e) { throw e; } } } The SqlException that is caught at my catch is : "Timeout expired. The timeout period elapsed prior to completion of the operation or the server is not responding." This occurs at the conn.Open(); line in the code snippet I have included. If anyone has any ideas that'd be great!

    Read the article

  • How do I ignore an "invalid" SSL certificate in Objective-C?

    - by ipwnstuff
    Currently I have: NSArray* array = [NSArray arrayWithObjects:@"auth.login",@"username",@"password", nil]; NSData* packed_array = [array messagePack]; NSURL* url = [NSURL URLWithString:@"https://192.168.1.149:3790/api/1.0"]; NSMutableURLRequest* request = [NSMutableURLRequest requestWithURL:url]; [request setHTTPMethod:@"POST"]; [request setValue:@"RPC Server" forHTTPHeaderField:@"Host"]; [request setValue:@"binary/message-pack" forHTTPHeaderField:@"Content-Type"]; [request setValue:[NSString stringWithFormat:@"%d",[packed_array length]] forHTTPHeaderField:@"Content-Length"]; [request setHTTPBody:packed_array]; NSURLResponse *response; NSError *error; responseData = [NSMutableData dataWithData:[NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error]]; NSLog(@"response data: %@",[responseData messagePackParse]); NSLog(@"error: %@",error); - (BOOL)connection:(NSURLConnection *)connection canAuthenticateAgainstProtectionSpace:(NSURLProtectionSpace *)protectionSpace { NSLog(@"called canAuthenticateAgainstProtectionSpace"); return [protectionSpace.authenticationMethod isEqualToString:NSURLAuthenticationMethodServerTrust]; } - (void)connection:(NSURLConnection *)connection didReceiveAuthenticationChallenge:(NSURLAuthenticationChallenge *)challenge { NSLog(@"called didReceiveAuthenticationChallenge"); [challenge.sender useCredential:[NSURLCredential credentialForTrust:challenge.protectionSpace.serverTrust] forAuthenticationChallenge:challenge]; } Which returns "Error Domain=NSURLErrorDomain Code=-1202 "The certificate for this server is invalid"…" How should I be implementing the answer from this question?

    Read the article

  • Preserving the order of annotations

    - by Ragunath Jawahar
    When obtaining the list of fields using getFields() and getDeclaredFields(), the order of the fields in a Java class is undefined. I need this order in my validation library. Since the order is not preserved (though some claim that the order is preserved in JDK 6 and above but is not guaranteed across VMs). I cannot speculate on this because the order of annotations across fields is absolutely essential for the library. One way to get around this is to have an order or an index attribute in my Annotation. What worries me is that the code could become a bit cumbersome for maintaining in the following case. If the use wants to insert a new annotated field then, he might have to renumber all the other annotations in the class. I could have the order or index as a floating point number - float or double but , it wouldn't look good to have order such as 1, 1.5, 2, etc., What would be an elegant solution for this problem? Here is a example code so that you can get an idea about the problem: @Required @TextRule (minLength = 6, message = "You need at least 6 characters.") private EditText usernameEditText; @Password private EditText passwordEditText; @ConfirmPassword private EditText confirmPasswordEditText; @Email private EditText emailEditText;

    Read the article

  • PHP shell_exec() - Run directly, or perform a cron (bash/php) and include MySQL layer?

    - by Jimbo
    Sorry if the title is vague - I wasn't quite sure how to word it! What I'm Doing I'm running a Linux command to output data into a variable, parse the data, and output it as an array. Array values will be displayed on a page using PHP, and this PHP page output is requested via AJAX every 10 seconds so, in effect, the data will be retrieved and displayed/updated every 10 seconds. There could be as many as 10,000 characters being parsed on every request, although this is usually much lower. Alternative Idea I want to know if there is a better* alternative method of retrieving this data every 10 seconds, as multiple users (<10) will be having this command executed automatically for them. A cronjob running on the server could execute either bash or php (which is faster?) to grab the data and store it in a MySQL database. Then, any AJAX calls to the PHP output would return values in the MySQL database rather than making a direct call to execute server code every 10 seconds. Why? I know there are security concerns with running execs directly from PHP, and (I hope this isn't micro-optimisation) I'm worried about CPU usage on the server. The server is running a sempron processor. Yes, they do still exist. Having this only execute when the user is on the page (idea #1) means that the server isn't running code that doesn't need to be run. However, is this slow and insecure? Just in case the type of linux command may be of assistance in determining it's efficiency: shell_exec("transmission-remote $host:$port --auth $username:$password -l"); I'm hoping that there are differences in efficiency and level of security with the two methods I have outlined above, and that this isn't just micro-micro-optimisation. If there are alternative methods that are better*, I'd love to learn about these! :)

    Read the article

  • Entity Framework - Store parent reference on child relationship (one -> many)

    - by contactmatt
    I have a setup like this: [Table("tablename...")] public class Branch { public Branch() { Users = new List<User>(); } [Key] public int Id { get; set; } public string Name { get; set; } public List<User> Users { get; set; } } [Table("tablename...")] public class User { [Key] public int Id {get; set; } public string Username { get; set; } public string Password { get; set; } [ForeignKey("ParentBranch")] public int? ParentBranchId { get; set; } // Is this possible? public Branch ParentBranch { get; set; } // ??? } Is it possible for the User to know what parent branch it belongs to? The code above is not working. Entity Framework version 5.0 .NET 4.0 c#

    Read the article

  • The type or namespace name 'WebControls' could not be found (are you missing a using directive or an assembly reference?)

    - by user1467175
    I encountered this error: The type or namespace name 'WebControls' could not be found (are you missing a using directive or an assembly reference?) Source Error: Line 28: Login Login1 = (WebControls.Login)LoginView1.FindControl("Login1"); // here the error code Line 29: TextBox UserName = (TextBox)Login1.FindControl("UserName"); Line 30: TextBox FailureText = (TextBox)Login1.FindControl("FailureText"); I did some research and the solution was to add this into the source code: System.Web.UI.WebControls.Login but I have no idea where this code can be add into. At first I tried putting it as a namespace, but it was wrong. Anyone can tell me where should I place this code at?? EDIT protected void Login1_LoginError(object sender, System.EventArgs e) { //Login Login1 = (WebControls.Login).LoginView1.FindControl("Login1"); Login Login1 = (System.Web.UI.WebControls.Login)LoginView1.FindControl("Login1"); TextBox UserName = (TextBox)Login1.FindControl("UserName"); TextBox FailureText = (TextBox)Login1.FindControl("FailureText"); //There was a problem logging in the user //See if this user exists in the database MembershipUser userInfo = Membership.GetUser(UserName.Text); if (userInfo == null) { //The user entered an invalid username... FailureText.Text = "There is no user in the database with the username " + UserName.Text; } else { //See if the user is locked out or not approved if (!userInfo.IsApproved) { FailureText.Text = "When you created your account you were sent an email with steps to verify your account. You must follow these steps before you can log into the site."; } else if (userInfo.IsLockedOut) { FailureText.Text = "Your account has been locked out because of a maximum number of incorrect login attempts. You will NOT be able to login until you contact a site administrator and have your account unlocked."; } else { //The password was incorrect (don't show anything, the Login control already describes the problem) FailureText.Text = string.Empty; } } }

    Read the article

  • Symfony deploying issue

    - by medhad
    I have some problem while configuring symfony project on the production server. When I run the command doctrine --build --all --and-load it gives me error in the production environment: doctrine Dropping "doctrine" database PHP Notice: Undefined index: dbname in /var/www/sf_project/lib/vendor/symfony/lib/plugins/sfDoctrinePlugin/lib/vendor/doctrine/Doctrine/Connection.php on line 1472 Notice: Undefined index: dbname in /var/www/sf_project/lib/vendor/symfony/lib/plugins/sfDoctrinePlugin/lib/vendor/doctrine/Doctrine/Connection.php on line 1472 doctrine SQLSTATE[42000]: Syntax error or access violation: 1064 You have an erro...e right syntax to use near '' at line 1. Failing Query: "DROP DATABASE " doctrine Creating "dev" environment "doctrine" database PHP Notice: Undefined index: dbname in /var/www/sf_project/lib/vendor/symfony/lib/plugins/sfDoctrinePlugin/lib/vendor/doctrine/Doctrine/Connection.php on line 1439 However after the error it creates the table successfully. But if I run the command second times it fails partially while crating the tables. I have changed my database.yml configuration properly for the production environment. here it is: all: doctrine: class: sfDoctrineDatabase param: dsn: mysql:host=localhost;dbname=sf_project port: 3306 username: root password: mainserver Its working right in the local environment though. Can some one shed some light on it ?

    Read the article

  • Exception thrown when creating database

    - by Bob
    For some reason, I can't get embedded firebird sql to work on Windows using C#/.NET. Here's my code: string BuildConnectionString() { FbConnectionStringBuilder builder = new FbConnectionStringBuilder(); builder.DataSource = "localhost"; builder.UserID = "SYSDBA"; builder.Password = "masterkey"; builder.Database = "database.fdb"; builder.ServerType = FbServerType.Embedded; return builder.ConnectionString; } private void OnConnectClicked(object sender, EventArgs e) { string cString = BuildConnectionString(); FbConnection.CreateDatabase( cString ); FbConnection connection = new FbConnection( cString ); connection.Open(); //CreateTable(); //FillListView(); connection.Close(); } When I call FbConnection.CreateDatabase, I get the following exception: An attempt was made to load a program with an incorrect format. (Exception from HRESULT: 0x8007000B) I'm very new to SQL and Firebird in general, so I'm not sure how to resolve this issue. Anyone?

    Read the article

  • Assistance with CC Processing script

    - by JM4
    I am currently implementing a credit card processing script, most as provided by the merchant gateway. The code calls functions within a class and returns a string based on the response. The end php code I am using (details removed of course) with example information is: <?php $gw = new gwapi; $gw->setLogin("username", "password"); $gw->setBilling("John","Smith","Acme, Inc.","888","Suite 200", "Beverly Hills", "CA","77777","US","555-555-5555","555-555-5556","[email protected]", "www.example.com"); // "CA","90210","US","[email protected]"); $gw->setOrder("1234","Big Order",1, 2, "PO1234","65.192.14.10"); $r = $gw->doSale("1.00","4111111111111111","1010"); print $gw->responses['responsetext']; ?> where setlogin allows me to login, setbilling takes the sample consumer information, set order takes the order id and description, dosale takes the amount charged, cc number and exp date. when all the variables are sent validated then sent off for processing, a string is returned in the following format: response=1&responsetext=SUCCESS&authcode=123456&transactionid=23456&avsresponse=M&orderid=&type=sale&response_code=100 where: response = transaction approved or declined response text = textual response authcode = transaction authorization code transactionid = payment gateway tran id avsresponse = avs response code orderid = original order id passed in tran request response_code = numeric mapping of processor response I am trying to solve for the following: How do I take the data which is passed back and display it appropriately on the page - If the transaction failed or AVS code doesnt match my liking or something is wrong, an error is displayed to the consumer; if the transaction processed, they are taken to a completion page and the transaction id is sent in SESSION as output to the consumer If the response_code value matches a table of values, certain actions are taken, i.e. if code =100, take to success page, if code = 300 print specific error on original page to customer, etc.

    Read the article

  • How important is it that models be consistent across project components?

    - by RonLugge
    I have a project with two components, a server-side component and a client-side component. For various reasons, the client-side device doesn't carry a fully copy of the database around. How important is it that my models have a 1:1 correlation between the two sides? And, to extend the question to my bigger concern, are there any time-bombs I'm going to run into down the line if they don't? I'm not talking about having different information on each side, but rather the way the information is encapsulated will vary. (Obviously, storage mechanisms will also vary) The server side will store each user, each review, each 'item' with seperate tables, and create links between them to gather data as necessary. The client side shouldn't have a complete user database, however, so rather than link against the user for gathering things like 'name', I'd store that on the review. In other words... --- Server Side --- Item: +id //Store stuff about the item User: +id +Name -Password Review: +id +itemId +rating +text +userId --- Device Side --- Item: +id +AverageRating Review: +id +rating +text +userId +name User: +id +Name //Stuff The basic idea is that certain 'critical' information gets moved one level 'up'. A user gets the list of 'items' relevant to their query, with certain review-orientation moved up (i. e. average rating). If they want more info, they query the detail view for the item, and the actual reviews get queried and added to the dataset (and displayed). If they query the actual review, the review gets queried and they pick up some additional user info along the way (maybe; I'm not sure if the user would have any use for any of the additional user information). My basic concern is that I don't wan't to glut the user's bandwidth or local storage with a huge variety of information that they just don't need, even if proper database normalizations suggests that information REALLY should be stored at a 'lower' level. I've phrased this as a fairly low-level conceptual issue because that's the level I'm trying to think / worry over, but if it matters I'm creating a PHP / MySQL server that provides data for a iOS / CoreData client.

    Read the article

  • PHP Fix Warning: Cannot modify header information - headers already sent...

    - by Storm Kiernan
    Warning: Cannot modify header information - headers already sent by (output started at /home/blocexco/public_html/homepage.php:73) in /home/blocexco/public_html/classes/mysql/mysql.security.php on line 99 This error is repeated a second time for mysql.security.php on line 100. homepage:73 <div class="login"> <?php require_once 'login.php'; ?> </div> mysql.security.php: 99-100 setcookie('username', "", time() - (60 * 60 * 24 * 365)); setcookie('password', "", time() - (60 * 60 * 24 * 365)); I know this isn't a "BOM" issue as I've read about. There is output before and after my calls to header() and setcookie() functions - this is necessary since the homepage includes a php file which then injects the right login or logout form. I've heard about using ob_start() at the beginning of content, but that's not a very specific instruction...I tried placing it at the beginning of homepage.php (just before the html tag) and that didn't fix anything. I'm new to PHP (a few days in, and new to web-app dev in general). To be honest, it blows my mind that I can't just change which page I am on, via php without bending over backwards...

    Read the article

  • Sessions not sticking linux server

    - by Jacob Windsor
    I have just moved the dev site over to my linux server for production but the sessions don't seem to be sticking for very long. I am guessing it is the server settings and not the php because it does the same thing with the plesk panel. Whenever a script is executed the sessions seems to get unset. I see nothing in the error log so not sure what it is. It all worked fine on wamp. Anyway I uploaded the php.ini file which was in the wamp server as it had all the settings i needed and all was working on localhost. Not sure what the problem is and this is the final thing that I have to sort out before going into production. And just too add the sessions are being started as they last for a little bit just don't stick around long. Here is the relevent part of my login script just in case there is something wrong with the code: // if login is ok then we add a cookie if($flag == 0) { $pass = htmlspecialchars(mysql_real_escape_string($_POST['pass'])); $username = htmlspecialchars(mysql_real_escape_string($_POST['username'])); $_SESSION['username']=$username; $_SESSION['password']=$pass;

    Read the article

  • Apache's AuthDigestDomain and Rails Distributed Asset Hosts

    - by Jared
    I've got a server I'm in the process of setting up and I'm running into an Apache configuration problem that I can not get around. I've got Apache 2.2 and Passenger serving a Rails app with distributed asset hosting. This is the feature of Rails that lets you serve your static assets from assets0.example.com, assets1, assets2, and so on. The site needs to be passworded until launch. I've set up HTTP authentication on the site using Apache's mod_auth_digest. In my configuration I'm attempting to use the AuthDigestDomain directive to allow access to each of the asset URLs. The problem is, it doesn't seem to be working. I get the initial prompt for the password when I load the page, but then the first time it loads an asset from one of the asset URLs, I get prompted a 2nd, 3rd, or 4th time. In some browsers, I get prompted for every single resource on the page. I'm hoping that this is only a problem of how I'm specifying my directives and not a limitation of authorization in Apache itself. See the edited auth section below: <Location /> AuthType Digest AuthName "Restricted Site" AuthUserFile /etc/httpd/passwd/passwords AuthGroupFile /dev/null AuthDigestDomain / http://assets0.example.com/ http://assets1.example.com/ http://assets2.example.com/ http://assets3.example.com/ require valid-user order deny,allow allow from all </Location>

    Read the article

  • login/logout problem in PHP

    - by user356170
    i have a question. I have a website in which i am giving security like login id and password( as usual). No what i want is that, 1) I don't want to allow a single user to login in different machine at the same time. 2) For this i am using a column in database which is keeping the current status of user(i.e. loging/logout). I am allowing user to login only when has session has not closed and status is login. 3) So my problem is that when i am logging out manually. it is closing the session as well as updating the database with status "logout". 4) but when i am closing the window from Cross buttonat top right corner. it is closing the ssion but table data is still "login". so later on i can't be able to login into the same user. 5) So how could i solve this problem. Please help me!

    Read the article

  • Write transparent HTTP Proxy script in PHP

    - by Leo Izen
    Is there an easy forwarding/transparent php proxy script that I can host on my web server? These are my conditions: I'm using free web hosting, so I have pretty much no control over my machine. Otherwise I could use Perl's HTTP::Proxy module. This means no root password. It does run php though. I already have a server running on port 80. What I mean is I would like to put a php script as index.php on my server that will forward all requests. I don't want a script like PHProxy or Glype where I go to the site, then enter a URL. I want a server so I can enter proxy.example.com:80 in Firefox's or IE's or whatever's proxy settings and it will forward all requests to the server. Preferably (though not fatal if not possible) I would like for it to pass on the USER_AGENT environmental variable (That's the browser) instead of setting itself to be the USER_AGENT I can't start a new Daemon. My server won't allow it. Is there a script that will do this? If so, which?

    Read the article

  • Make an NSString accessible in the whole class

    - by OhhMee
    Hello, I want to know how can I make an NSString accessible in the whole class. Say I have these codes: - (void) init { NSArray *elements = [xpathParser search:@"//foo"]; TFHppleElement *element = [elements objectAtIndex:0]; NSString *data = [element content]; NSArray *elements1 = [xpathParser search:@"//foo2"]; TFHppleElement *element2 = [elements1 objectAtIndex:0]; NSString *data2 = [element2 content]; } And I want to use data & data2 in the whole class, how can I do that? I want to show results here: - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *CellIdentifier = @"Cell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier] autorelease]; } // Configure the cell. switch (indexPath.row) { case 0 : cell.textLabel.text = (@"%@", data); break; case 1: cell.textLabel.text = (@"%@", data2); break; } // Email & Password Section return cell; }

    Read the article

  • Most effecient way to create a "slider" timeline in HTML, CSS, and JavaScript?

    - by ZapChance
    Alright, so here's my dilemma. I've got these two "slides" lined up, one ready to be passed into view. I have it working and all, but I can scroll over to the right to see the second slide! How could I have it you can only view the one slide? JavaScript used: function validate(form) { var user = form.username.value; var pass = form.password.value; if(user === "test") { if(pass === "pass") { var hideoptions = {"direction" : "left", "mode" : "hide"}; var showoptions = {"direction" : "left", "mode" : "show"}; /*$("#loginView").toggle("slide", hideoptions, 1000, function() { $("#loginView").css("margin-left", "100%"); }); $("#mainView").toggle("slide", showoptions, 1000, function() { $("#mainView").css("margin-left", 0); });*/ $("#loginView").animate({ marginLeft: "-100%" }, 1000); $("#mainView").animate({ marginLeft: "0" }, 1000); } else { alert("nope"); } } else { alert("nope 2"); } } As you can see here @ http://jsfiddle.net/D7Va3/1/ (JSFiddle), once you enter "test" and "pass", then click enter, the tiles slide. But. If you reload, you can see that you can scroll to the right of the screen and view the second slide prematurely, which is just not going to work for me. I still need to achieve the same seamless transition, but you must only be able to view one slide at a time. Also, I plan to expand with more slides, so if you're feeling lucky today, I'd really love to see an example of how I could support multiple frames. I'm very new to JavaScript (yet I know syntax rules, and general coding knowledge from other languages), so the better you explain, the more knowledgeable I can be, and I'd be very grateful for that. Thanks in advance!

    Read the article

  • TV Guide script - getting current date programmes to show

    - by whitstone86
    This is part of my TV guide script: //Connect to the database mysql_connect("localhost","root","PASSWORD"); //Select DB mysql_select_db("mytvguide"); //Select only results for today and future $result = mysql_query("SELECT programme, channel, episode, airdate, expiration, setreminder FROM mediumonair where airdate >= now()"); The episodes show up, so there are no issues there. However, it's getting the database to find data that's the issue. If I add a record for a programme that airs today this should show: Medium showing on TV4 8:30pm "Episode" Set Reminder Medium showing on TV4 May 18th - 6:25pm "Episode 2" Set Reminder Medium showing on TV4 May 18th - 10:25pm "Episode 3" Set Reminder Medium showing on TV4 May 19th - 7:30pm "Episode 3" Set Reminder Medium showing on TV4 May 20th - 1:25am "Episode 3" Set Reminder Medium showing on TV4 May 20th - 6:25pm "Episode 4" Set Reminder but this shows instead: Medium showing on TV4 May 18th - 6:25pm "Episode 2" Set Reminder Medium showing on TV4 May 18th - 10:25pm "Episode 3" Set Reminder Medium showing on TV4 May 19th - 7:30pm "Episode 3" Set Reminder Medium showing on TV4 May 20th - 1:25am "Episode 3" Set Reminder Medium showing on TV4 May 20th - 6:25pm "Episode 4" Set Reminder I almost have the SQL working; just not sure what the right code is here, to avoid the second mistake showing - as the record (which indicates a show currently airing) does not seem to work at present. Please can anyone help me with this? Thanks

    Read the article

< Previous Page | 440 441 442 443 444 445 446 447 448 449 450 451  | Next Page >