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  • mailing system DB structure, need help

    - by Anna
    i have a system there user(sender) can write a note to friends(receivers), number of receivers=0. Text of the message is saved in DB and visible to sender and all receivers then they login to system. Sender can add more receivers at any time. More over any of receivers can edit the message and even remove it from DB. For this system i created 3 tables, shortly: users(userID, username, password) messages(messageID, text) list(id, senderID, receiverID, messageID) in table "list" each row corresponds to pair sender-receiver, like sender_x_ID -- receiver_1_ID -- message_1_ID sender_x_ID -- receiver_2_ID -- message_1_ID sender_x_ID -- receiver_3_ID -- message_1_ID Now the problem is: 1. if user deletes the message from table "messages" how to automatically delete all rows from table "list" which correspond to deleted message. Do i have to include some foreign keys? More important: 2. if sender has let say 3 receivers for his message1 (username1, username2 and username3) and at certain moment decides to add username4 and username5 and at the same time exclude username1 from the list of receivers. PHP code will get the new list of receivers (username2, username3, username4, username5) That means insert to table "list" sender_x_ID -- receiver_4_ID -- message_1_ID sender_x_ID -- receiver_5_ID -- message_1_ID and also delete from table "list" the row corresponding to user1 (which is not in the list or receivers any more) sender_x_ID -- receiver_1_ID -- message_1_ID which sql query to send from PHP to make it in an easy and intelligent way? Please help! Examples of sql queries would be perfect!

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  • Most effecient way to create a "slider" timeline in HTML, CSS, and JavaScript?

    - by ZapChance
    Alright, so here's my dilemma. I've got these two "slides" lined up, one ready to be passed into view. I have it working and all, but I can scroll over to the right to see the second slide! How could I have it you can only view the one slide? JavaScript used: function validate(form) { var user = form.username.value; var pass = form.password.value; if(user === "test") { if(pass === "pass") { var hideoptions = {"direction" : "left", "mode" : "hide"}; var showoptions = {"direction" : "left", "mode" : "show"}; /*$("#loginView").toggle("slide", hideoptions, 1000, function() { $("#loginView").css("margin-left", "100%"); }); $("#mainView").toggle("slide", showoptions, 1000, function() { $("#mainView").css("margin-left", 0); });*/ $("#loginView").animate({ marginLeft: "-100%" }, 1000); $("#mainView").animate({ marginLeft: "0" }, 1000); } else { alert("nope"); } } else { alert("nope 2"); } } As you can see here @ http://jsfiddle.net/D7Va3/1/ (JSFiddle), once you enter "test" and "pass", then click enter, the tiles slide. But. If you reload, you can see that you can scroll to the right of the screen and view the second slide prematurely, which is just not going to work for me. I still need to achieve the same seamless transition, but you must only be able to view one slide at a time. Also, I plan to expand with more slides, so if you're feeling lucky today, I'd really love to see an example of how I could support multiple frames. I'm very new to JavaScript (yet I know syntax rules, and general coding knowledge from other languages), so the better you explain, the more knowledgeable I can be, and I'd be very grateful for that. Thanks in advance!

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  • How to strengthen Mysql database server Security?

    - by i need help
    If we were to use server1 for all files (file server), server2 for mysql database (database server). In order for websites in server1 to access to the database in server2, isn't it needed to connect to to ip address of second (mysql server) ? In this case, is remote mysql connection. However, I seen from some people comment on the security issue. remote access to MySQL is not very secure. When your remote computer first connects to your MySQL database, the password is encrypted before being transmitted over the Internet. But after that, all data is passed as unencrypted "plain text". If someone was able to view your connection data (such as a "hacker" capturing data from an unencrypted WiFi connection you're using), that person would be able to view part or all of your database. So I just wondering ways to secure it? Allow remote mysql access from server1 by allowing the static ip adress allow remote access from server 1 by setting port allowed to connect to 3306 change 3306 to other port? Any advice?

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  • problems getting HTTPRiot working

    - by bwizzy
    I've got an iphone app where I'm trying to use HTTPRiot to make some API calls to a web app. Problem is I can't see that none of the HTTPRiot delegate methods are being called. I've got a log in all the delegate methods, and I'm also looking at the webserver log. I see that the URL is being hit. //API.h #import <Foundation/Foundation.h> #include <HTTPRiot/HTTPRiot.h> @interface API : HRRestModel { } +(void)runTest; @end //API.m #import "API.h" @implementation API + (void)initialize { NSLog(@"api initialize"); [self setDelegate:self]; [self setBaseURL:[NSURL URLWithString:@"http://localhost:3000/api"]]; [self setBasicAuthWithUsername:@"demo" password:@"123456"]; NSDictionary *params = [NSDictionary dictionaryWithObject:@"1234567" forKey:@"api_key"]; [self setDefaultParams:params]; }//end initialize +(void)runTest { NSLog(@"api run test"); // Would send a request to http://localhost:1234/api/people/1?api_key=1234567 [self getPath:@"/save_diet" withOptions:nil object:nil]; } +(void)restConnection:(NSURLConnection *)connection didReturnResource:(id)resource object:(id)object { NSLog(@"didReturnResource"); } +(void)restConnection:(NSURLConnection *)connection didReceiveResponse:(NSHTTPURLResponse *)response object:(id)object { NSLog(@"didReceiveResponse"); } +(void)restConnection:(NSURLConnection *)connection didReceiveParseError:(NSError *)error responseBody:(NSString *)body object:(id)object { NSLog(@"didReceiveParseError"); } +(void)restConnection:(NSURLConnection *)connection didReceiveError:(NSError *)error response:(NSHTTPURLResponse *)response object:(id)object { NSLog(@"didReceiveError"); } +(void)restConnection:(NSURLConnection *)connection didFailWithError:(NSError *)error object:(id)object { NSLog(@"didFailWithError"); } @end //test code [API runTest]; //log output

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  • How to **delete-protect** a file or folder on Windows Server 2003 and onwards using C#/Vb.Net?

    - by Steve Johnson
    Hi all, Is it possible to delete-protect a file/folder using Registry or using a custom written Windows Service in C#? Using Folder Permissions it is possible, but i am looking for a solution that even restricts the admin from deleting specific folders. The requirement is that the administrator must not be easily track the nature of protection and/or may not be able to avert it easily. Obviously all administrators will be able to revert the procedure if the technique is clearly understood. Like folder Permissions/OwnerShip Settings can easily be reset by an administrator. SO that is not an option. Folder protection software can easily be uninstalled and show clear indication that a particular folder is protected by some special kind of software. SO that too is not an option. Most antivirus programs protect folders and files in Program Dir. Windows itself doesnt allow certain files such as registry files in c:\windows\system32\config to not even copied. Such a protection is desired for folders which allowse to read and write to files but not allow deletion. Similar functionality is desired. The protection has to seemless and invisible. I do not want to use any protection features like FolderLock and Invisible secrets/PC Security and Desktop password etc. Moreover, the solution has to be something other than folder encryption. The solution has to be OS-native so ** that it may implemented ** pro grammatically using C#/VB.Net. Please help. Thanks

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  • Prompting for authentication from a wxPython program and passing it along to IIS?

    - by MetaHyperBolic
    I have a client (written in Python, with a wxPython front end in dead-simple wizard style) which communicates a website running IIS. A python script receives requests and does the usual client-server dance. I would have written this as a browser application, but for the requirement that certain things happen on the local PC that the web can't help with (file manipulation, interfacing with certain USB hardware, etc.) Right now, I am simply using the logon credentials, compounded as a string from os.environ['USERDOMAIN'] and os.environ['USERNAME'], to pass along to the server, which connects to Active Directory and enumerates the members of the group, looking for those logon credentials. It's an ugly hack, but it works. Obviously, I could make people log out of the generic helper accounts and log back into Windows using specific accounts. However, I wondered how feasible it would be to provide some kind of logon prompt wherein the user can type in a name and password, then some kind of authorization token could be passed on to IIS. This seems like something I would not want to do myself, given that amateurs almost always make huge security mistakes. Now you can see why I am wishing this was purely web-based. What's a good way to handle this?

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  • How do I import facebook friends from another website

    - by Jim Zimmerman
    I am looking for a way to connect to facebook by allowing the user to enter in their username and password and have our app connect to their account and get their contacts so that they can invite them to join their group on our site. I have written a facebook app before, but this is not an app as much as it is a connector so that they can invite all their friends or just some to the site we are working on. I have seen several other sites do this and also connect to Yahoo, Gmail and Hotmail contacts. I dont think they are using Facebook Connect to do this since it is so new, but they may be. Any solution in any language is fine as I can port whatever example to use C#. I cannot find anything specifically on Google or Facebook to address this specific problem. Any help is appreciated. I saw a first answer get removed that had suggested i might need to scrape the friends page. The more I look around, this might be what i need to do. Any other way i think will require the person to add it as an app. I am wondering how a answer can get removed, maybe that user deleted it.

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  • How do I ignore an "invalid" SSL certificate in Objective-C?

    - by ipwnstuff
    Currently I have: NSArray* array = [NSArray arrayWithObjects:@"auth.login",@"username",@"password", nil]; NSData* packed_array = [array messagePack]; NSURL* url = [NSURL URLWithString:@"https://192.168.1.149:3790/api/1.0"]; NSMutableURLRequest* request = [NSMutableURLRequest requestWithURL:url]; [request setHTTPMethod:@"POST"]; [request setValue:@"RPC Server" forHTTPHeaderField:@"Host"]; [request setValue:@"binary/message-pack" forHTTPHeaderField:@"Content-Type"]; [request setValue:[NSString stringWithFormat:@"%d",[packed_array length]] forHTTPHeaderField:@"Content-Length"]; [request setHTTPBody:packed_array]; NSURLResponse *response; NSError *error; responseData = [NSMutableData dataWithData:[NSURLConnection sendSynchronousRequest:request returningResponse:&response error:&error]]; NSLog(@"response data: %@",[responseData messagePackParse]); NSLog(@"error: %@",error); - (BOOL)connection:(NSURLConnection *)connection canAuthenticateAgainstProtectionSpace:(NSURLProtectionSpace *)protectionSpace { NSLog(@"called canAuthenticateAgainstProtectionSpace"); return [protectionSpace.authenticationMethod isEqualToString:NSURLAuthenticationMethodServerTrust]; } - (void)connection:(NSURLConnection *)connection didReceiveAuthenticationChallenge:(NSURLAuthenticationChallenge *)challenge { NSLog(@"called didReceiveAuthenticationChallenge"); [challenge.sender useCredential:[NSURLCredential credentialForTrust:challenge.protectionSpace.serverTrust] forAuthenticationChallenge:challenge]; } Which returns "Error Domain=NSURLErrorDomain Code=-1202 "The certificate for this server is invalid"…" How should I be implementing the answer from this question?

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  • How can I filter then modify e-mails using IMAP?

    - by swolff1978
    I have asked this question in a different post here on SO: How can a read receipt be suppressed? I have been doing some research of my own to try and solve this problem and accessing the e-mail account via IMAP seems like it is going to be a good solution. I have successfully been able to access my own Inbox and mark messages as read with no issue. I have been asked to preform the same task on an Inbox that contains over 23,000 emails. I would like to run the test on a small amount of e-mails from that inbox before letting the whole 23,000 get it. Here is the code I have been running via telnet: . LOGIN [email protected] password . SELECT Inbox . STORE 1:* flags \Seen 'this line marks all the e-mails as read So my question is how can i execute that store command on a specific group of e-mails... say emails that are going to / coming from a specific account? Is there a way to like concatenate the commands? like a FETCH then the STORE? Or is there a better way to go about getting a collection of e-mails based on certain criteria and then modifying ONLY those e-mails that can be accomplished through IMAP?

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  • PHP & form validation

    - by user887515
    I have a form that I'm submitting via ajax, and I want to return a message of the list of fields that were empty. I've got that all done and dusted, but it just seems really long winded on the PHP side of things. How can I do the below in a less convoluted way? <?php if(empty($_POST["emailaddress"])){ $error = 'true'; $validation_msg = 'Country missing.'; if(empty($error_msg)){ $error_msg .= $validation_msg; } else{ $error_msg .= '\n' . $validation_msg; } } if(empty($_POST["password"])){ $error = 'true'; $validation_msg = 'Country missing.'; if(empty($error_msg)){ $error_msg .= $validation_msg; } else{ $error_msg .= '\n' . $validation_msg; } } if(empty($_POST["firstname"])){ $error = 'true'; $validation_msg = 'First name missing.'; if(empty($error_msg)){ $error_msg .= $validation_msg; } else{ $error_msg .= '\n' . $validation_msg; } } if(empty($_POST["lastname"])){ $error = 'true'; $validation_msg = 'Last name missing.'; if(empty($error_msg)){ $error_msg .= $validation_msg; } else{ $error_msg .= '\n' . $validation_msg; } } if($error){ header('HTTP/1.1 500 Internal Server Error'); header('Content-Type: application/json'); die($error_msg); } ?>

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  • How to specify hash algorithm when updating LDAP via Java?

    - by JuanZe
    Is there a way to specify the hash algorithm (MD5, SHA1, etc.) to use for storing the passwords when you update an Open LDAP directory using Java APIs with code like this: private void resetPassword(String principal, String newPassword) throws NamingException { InitialDirContext ctxAdmin = null; Hashtable<String, String> ctxData = new Hashtable<String, String>(); ctxData.put(Context.INITIAL_CONTEXT_FACTORY, "com.sun.jndi.ldap.LdapCtxFactory"); ctxData.put(Context.PROVIDER_URL, "ldap://myserver:389"); ctxData.put(Context.SECURITY_AUTHENTICATION, "simple"); ctxData.put(Context.SECURITY_PRINCIPAL, "admin_dn"); ctxData.put(Context.SECURITY_CREDENTIALS, "admin_passwd"); InitialDirContext ctxAdmin = new InitialDirContext(ctxData); if (newPassword == null || newPassword.equals("")) { String msg = "Password can't be null"; throw new NamingException(msg); } else { if (principal == null || principal.equals("")) { String msg = "Principal can't be null"; throw new NamingException(msg); } else { if (ctxAdmin == null) { String errCtx = "Can't get LDAP context"; throw new NamingException(errCtx); } } } BasicAttribute attr = new BasicAttribute("userpassword", newPassword); ModificationItem modItem = new ModificationItem(DirContext.REPLACE_ATTRIBUTE, attr); ModificationItem[] items = new ModificationItem[1]; items[0] = modItem; ctxAdmin.modifyAttributes("cn=" + principal + ",ou=Users,dc=com", items); }

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  • validation before ajax form submission

    - by ZX12R
    How do i introduce validation before remote_form_for submits? I have javascript function called validateForm(). I am able to call it before the AJAX request process. I tried to use return false and event.preventDefault. But there seems to be no effect. Here is what my code looks like <% remote_form_for :customer, :update =>"uxScreenLoaderDiv", :url => {:action => "login", :controller => "site"}, :html => {:id => "uxLoginForm"}, :onsubmit => "validateForm(event)" do |f| %> User name : <%= f.text_field "uxUserName", :class => "TextBox", :style => "width:100px;" %>&nbsp;* &nbsp;Password : <%= f.password_field "uxPassword", :class => "TextBox", :style => "width:100px;" %>&nbsp;* <%= f.submit "Go!", :class => "Button-Simple", :id => "uxSubmitButton" %> <% end %> the javascript function is simple as follows function validateForm(event){ return false; //event.preventDefault(); }

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  • [RPM Building] How to take user input during install

    - by Sam
    So when I create a debian package, I am able to write a post-installation shell script that runs just fine. Currently mine is configured to do echo "Please enter your MySQL Database user (default root)" read MYSQL_USER echo "Please enter the MySQL Database user password (default root)" read -s MYSQL_PASS DBEXIST=0 CMD="create database lportal;use lportal;" (mysql -u$MYSQL_USER -p$MYSQL_PASS -e "$CMD") || ((DBEXIST++)) if [ $DBEXIST -ne 0 ]; then echo "Setup finished, but MySQL already has an lportal table. This could be from a previous installation of Liferay. If you want a fresh installation of this bundle, please remove the lportal table and reinstall this package." fi This works fine for Ubuntu. However, I can't seem to get user input to work with RPMs for Fedora. Is there a good way to take user input? From what I understand, RPMs were designed not to allow interactive installs. However I can't see a better way to do this.. Is there possibly a way to automatically find local MySQL settings without asking the user? Otherwise, what's the best way to ask for user input?

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  • Jython & Mysql - what is the current practice for connection?

    - by Sector7B
    Just trying jython for the first time, because something came up at work that would fit for this perfect for it. I assume jython can make mysql jdbc connection using the mysql jdbc driver. After googling and reading, however I am having problems and it seems jython specific and probably simple. so i do jython: Jython 2.5.1 (Release_2_5_1:6813, Sep 26 2009, 13:47:54) [Java HotSpot(TM) 64-Bit Server VM (Apple Inc.)] on java1.6.0_17 Type "help", "copyright", "credits" or "license" for more information. >>> import sys >>> print sys.path ['', '/JYTHONPATH/mysql-connector-java-5.1.10-bin.jar', '/WorkArea/Apps/jython/jython2.5.1/Lib', '__classpath__', '__pyclasspath__/', '/WorkArea/Apps/jython/jython2.5.1/Lib/site-packages'] >>> code i'm running from java.lang import * from java.sql import * driverName="com.mysql.jdbc.Driver" Class.forName(driverName) url = "jdbc:mysql://localhost/test?user=jgreenaw&password=" con = DriverManager.getConnection(url) stmt = con.createStatement() output riux:Desktop$ jython pymysql.py Traceback (most recent call last): File "pymysql.py", line 7, in <module> Class.forName(driverName) at java.net.URLClassLoader$1.run(URLClassLoader.java:200) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:188) at java.lang.ClassLoader.loadClass(ClassLoader.java:315) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:330) at java.lang.ClassLoader.loadClass(ClassLoader.java:250) at java.lang.ClassLoader.loadClassInternal(ClassLoader.java:398) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Class.java:169) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) java.lang.ClassNotFoundException: java.lang.ClassNotFoundException: com.mysql.jdbc.Driver any advice? thanks

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  • Extra NotifyIcon shown in system tray

    - by Kettch19
    I'm having an issue with an app where my NotifyIcon displays an extra icon. The steps to reproduce it are easy, but the problem is that the extra icon shows up after any of the actual codebehind we've added fires. Put simply, clicking a button triggers execution of method FooBar() which runs all the way through fine but its primary duty is to fire a backgroundworker to log into another of our apps. It only appears if this particular button is clicked. Strangely enough, we have a WndProc method override and if I step through until the extra NotifyIcon appears, it always appears during this method so something else beyond the codebehind must be triggering the behavior. Our WndProc method is currently (although I don't think it's caused by the WndProc): Protected Overrides Sub WndProc(ByRef m As System.Windows.Forms.Message) 'Check for WM_COPYDATA message from other app or drag/drop action and handle message If m.Msg = NativeMethods.WM_COPYDATA Then ' get the standard message structure from lparam Dim CD As NativeMethods.COPYDATASTRUCT = m.GetLParam(GetType(NativeMethods.COPYDATASTRUCT)) 'setup byte array Dim B(CD.cbData) As Byte 'copy data from memory into array Runtime.InteropServices.Marshal.Copy(New IntPtr(CD.lpData), B, 0, CD.cbData) 'Get message as string and process ProcessWMCopyData(System.Text.Encoding.Default.GetString(B)) 'empty array Erase B 'set message result to 'true', meaning message handled m.Result = New IntPtr(1) End If 'pass on result and all messages not handled by this app MyBase.WndProc(m) End Sub The only place in the code where the NotifyIcon in question is manipulated at all is in the following event handler (again, don't think this is the culprit, but just for more info): Private Sub TrayIcon_MouseDoubleClick(ByVal sender As System.Object, ByVal e As System.Windows.Forms.MouseEventArgs) Handles TrayIcon.MouseDoubleClick If Me.Visible Then Me.Hide() Else PositionBottomRight() Me.Show() End If End Sub The backgroundworker's DoWork is as follows (just a class call to log in to our other app, but again just for info): Private Sub LoginBackgroundWorker_DoWork(ByVal sender As Object, ByVal e As System.ComponentModel.DoWorkEventArgs) Handles LoginBackgroundWorker.DoWork Settings.IsLoggedIn = _wdService.LogOn(Settings.UserName, Settings.Password) End Sub Does anyone else have ideas on what might be causing this or how to possibly further debug this? I've been banging my head on this without seeing a pattern so another set of eyes would be extremely appreciated. :) I've posted this on MSDN winforms forums as well and have had no luck there so far either.

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  • MySQLDB query not returning all rows

    - by RBK
    I am trying to do a simple fetch using MySQLDB in Python. I have 2 tables(Accounts & Products). I have to look up Accounts table, get acc_id from it & query the Products table using it. The Products tables has more than 10 rows. But when I run this code it randomly returns between 0 & 6 rows each time I run it. Here's the code snippet: # Set up connection con = mdb.connect('db.xxxxx.com', 'user', 'password', 'mydb') # Create cursor cur = con.cursor() # Execute query cur.execute("SELECT acc_id FROM Accounts WHERE ext_acc = '%s'" % account_num ) # account_num is alpha-numberic and is got from preceding part of the program # A tuple is returned, so get the 0th item from it acc_id = cur.fetchone()[0] print "account_id = ", acc_id # Close the cursor - I was not sure if I can reuse it cur.close() # Reopen the cursor cur = con.cursor() # Second query cur.execute("SELECT * FROM Products WHERE account_id = %d" % acc_id) keys = cur.fetchall() print cur.rowcount # This prints incorrect row count for key in keys: # Does not print all rows. Tried to directly print keys instead of iterating - same result :( print key # Closing the cursor & connection cur.close() con.close() The weird part is, I tried to step through the code using a debugger(PyDev on Eclipse) and it correctly gets all rows(both the value stored in the variable 'keys' as well as console output are correct). I am sure my DB has correct data since I ran the same SQL on MySQL console & got the correct result. Just to be sure I was not improperly closing the connection, I tried using with con instead of manually closing the connection and it's the same result. I did RTFM but I couldn't find much in it to help me with this issue. Where am I going wrong? Thank you. EDIT: I noticed another weird thing now. In the line cur.execute("SELECT * FROM Products WHERE account_id = %d" % acc_id), I hard-coded the acc_id value, i.e made it cur.execute("SELECT * FROM Products WHERE account_id = %d" % 322) and it returns all rows

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  • Preserving the order of annotations

    - by Ragunath Jawahar
    When obtaining the list of fields using getFields() and getDeclaredFields(), the order of the fields in a Java class is undefined. I need this order in my validation library. Since the order is not preserved (though some claim that the order is preserved in JDK 6 and above but is not guaranteed across VMs). I cannot speculate on this because the order of annotations across fields is absolutely essential for the library. One way to get around this is to have an order or an index attribute in my Annotation. What worries me is that the code could become a bit cumbersome for maintaining in the following case. If the use wants to insert a new annotated field then, he might have to renumber all the other annotations in the class. I could have the order or index as a floating point number - float or double but , it wouldn't look good to have order such as 1, 1.5, 2, etc., What would be an elegant solution for this problem? Here is a example code so that you can get an idea about the problem: @Required @TextRule (minLength = 6, message = "You need at least 6 characters.") private EditText usernameEditText; @Password private EditText passwordEditText; @ConfirmPassword private EditText confirmPasswordEditText; @Email private EditText emailEditText;

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  • Is this the best way to make an API request using PHP CURL?

    - by Abs
    Hello all, I have a site that has a simple API which can be used via http. I wish to make use of the API and submit data about 1000-1500 times at one time. Here is their API: http://api.jum.name/ I have constructed the URL to make a submission but now I am wondering what is the best way to make these 1000-1500 API GET requests? Here is the PHP CURL implementation I was thinking of: $add = 'http://www.mysite.com/3rdparty/API/api.php?fn=post&username=test&password=tester&url=http://google.com&category=21&title=story a&content=content text&tags=Season,news'; curl_setopt ($ch, CURLOPT_URL, "$add"); curl_setopt ($ch, CURLOPT_POST, 0); curl_setopt ($ch, CURLOPT_COOKIEFILE, 'files/cookie.txt'); curl_setopt ($ch, CURLOPT_FOLLOWLOCATION, 0); curl_setopt ($ch, CURLOPT_RETURNTRANSFER, TRUE); $postdata = curl_exec ($ch); Shall I close the CURL connection every time I make a submission? Can I re-write the above in a better way that will make these 1000-1500 submissions quicker? Thanks all

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  • PHP Fix Warning: Cannot modify header information - headers already sent...

    - by Storm Kiernan
    Warning: Cannot modify header information - headers already sent by (output started at /home/blocexco/public_html/homepage.php:73) in /home/blocexco/public_html/classes/mysql/mysql.security.php on line 99 This error is repeated a second time for mysql.security.php on line 100. homepage:73 <div class="login"> <?php require_once 'login.php'; ?> </div> mysql.security.php: 99-100 setcookie('username', "", time() - (60 * 60 * 24 * 365)); setcookie('password', "", time() - (60 * 60 * 24 * 365)); I know this isn't a "BOM" issue as I've read about. There is output before and after my calls to header() and setcookie() functions - this is necessary since the homepage includes a php file which then injects the right login or logout form. I've heard about using ob_start() at the beginning of content, but that's not a very specific instruction...I tried placing it at the beginning of homepage.php (just before the html tag) and that didn't fix anything. I'm new to PHP (a few days in, and new to web-app dev in general). To be honest, it blows my mind that I can't just change which page I am on, via php without bending over backwards...

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  • Symfony form values missing

    - by Cav
    Hi, I was writing a simple login form, everything works fine (validation etc.) but I can't get the values, there's my code: public function executeIndex(sfWebRequest $request) { $this->getUser()->clearCredentials(); $this->getUser()->setAuthenticated(false); $this->form = new LoginForm(); if ($request->isMethod('post') && $request->hasParameter('login')) { $this->form->bind($request->getParameter('login')); if ($this->form->isValid()) { $this->getUser()->setAuthenticated(true); $this->getUser()->addCredential('user'); $this->login = $this->form->getValue('login'); } } } $this-login is NULL. Now I checked almost everything, the form is valid, isBound() is true, count() returns 3, I can see the values in my request: parameterHolder: action: index login: { login: foo, password: foo, _csrf_token: 53ebddee1883d7e3d6575d6fb1707a15 } module: login BUT getValues() returns NULL, getValue('login') etc. returns NULL as well. How can it be? And no, I don't want to use sfGuard-Plugins ;)

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  • How to secure connection strings in VS?

    - by salvationishere
    I see several others have posted this question, however, none of the solutions I've tried have fixed this yet. I have a 32-bit XP running VS 2008 and I am trying to encrypt my connection string in my web.config file. But I am getting the error: The configuration section '...' was not found. Failed! The command I give it: C:\Program Files\Microsoft Visual Studio 9.0\VCAspnet_regiis.exe -pe "system.we b/AdventureWorksConnectionString2" -app "/Documents and Settings/Admin/My Docume nts/Visual Studio 2008/Projects/AddFileToSQL2" Also, how does -app map virtual directory? In other words the path above is the directory right below c:. Is this the correct path to use? And AddFileToSQL2 is the name of my project, although it is part of the AddFileToSQL solution. I have this folder web shared with all of the permissions. And the relevant part of my web.config file: <add name="AdventureWorksConnectionString2" connectionString="Data Source=SIDEKICK;Initial Catalog=AdventureWorks;Persist Security Info=true; User ID=AdventureWorks;Password=sqlMagic" providerName="System.Data.SqlClient" />

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  • encrypting passwords in a python conf file on a windows platform

    - by Richard
    Hello all. I have a script running on a remote machine. db info is stored in a configuration file. I want to be able to encrypt the password in the conf text so that no one can just read the file and gain access to the database. This is my current set up: My conf file sensitive info is encoded with base64 module. The main script then decodes the info. I have compiled the script using py2exe to make it a bit harder to see the code. My question is: Is there a better way of doing this? I know that base64 is not a very safe way of encrypting. Is there a way to encode using a key? I also know that py2exe can be reversed engineered very easily and the key could be found. Any other thoughts? I am also running this script on a windows machine, so any modules that are suggested should be able to run in a windows environment with ease. I know there are several other posts on this topic but I have not found one with a windows solution, or at least one that is will explained.

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  • SQL Server Connection Timeout C#

    - by Termin8tor
    First off I'd like to let everyone know I have searched my particular problem and can't seem to find what's causing my problem. I have an SQL Server 2008 instance running on a network machine and a client I have written connecting to it. To connect I have a small segment of code that establishes a connection to an sql server 2008 instance and returns a DataTable populated with the results of whatever query I run against the server, all pretty standard stuff really. Anyway the issue is, whenever I open my program and call this method, upon the first call to my method, regardless as to what I've set my Connection Timeout value as in the connection string, it takes about 15 seconds and then times out. Bizarrely though the second or third call I make to the method will work without a problem. I have opened up the ports for SQL Server on the server machine as outlined in this article: How to Open firewall ports for SQL Server and verified that it is correctly configured. Can anyone see a particular problem in my code? string _connectionString = "Server=" + @Properties.Settings.Default.sqlServer + "; Initial Catalog=" + @Properties.Settings.Default.sqlInitialCatalog + ";User Id=" + @Properties.Settings.Default.sqlUsername + ";Password=" + @Properties.Settings.Default.sqlPassword + "; Connection Timeout=1"; private DataTable ExecuteSqlStatement(string command) { using (SqlConnection conn = new SqlConnection(_connectionString)) { try { conn.Open(); using (SqlDataAdapter adaptor = new SqlDataAdapter(command, conn)) { DataTable table = new DataTable(); adaptor.Fill(table); return table; } } catch (SqlException e) { throw e; } } } The SqlException that is caught at my catch is : "Timeout expired. The timeout period elapsed prior to completion of the operation or the server is not responding." This occurs at the conn.Open(); line in the code snippet I have included. If anyone has any ideas that'd be great!

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  • understanding the ORM models in MVC

    - by fayer
    i cant fully understand the ORM models in MVC. so i am using symfony with doctrine. the doctrine models are created. does this mean that i don't have to create any models? are the doctrine models the only models i need? where should i put the code that uses the doctrine models: eg. $phoneIds = array(); $phone1 = new Phonenumber(); $phone1['phonenumber'] = '555 202 7890'; $phone1->save(); $phoneIds[] = $phone1['id']; $phone2 = new Phonenumber(); $phone2['phonenumber'] = '555 100 7890'; $phone2->save(); $phoneIds[] = $phone2['id']; $user = new User(); $user['username'] = 'jwage'; $user['password'] = 'changeme'; $user->save(); $user->link('Phonenumbers', $phoneIds); should this code be in the controller or in another model? and where should i validate these fields (check if it exists in database, that email is email etc)? could someone please shed a light on this. thanks.

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  • The type or namespace name 'WebControls' could not be found (are you missing a using directive or an assembly reference?)

    - by user1467175
    I encountered this error: The type or namespace name 'WebControls' could not be found (are you missing a using directive or an assembly reference?) Source Error: Line 28: Login Login1 = (WebControls.Login)LoginView1.FindControl("Login1"); // here the error code Line 29: TextBox UserName = (TextBox)Login1.FindControl("UserName"); Line 30: TextBox FailureText = (TextBox)Login1.FindControl("FailureText"); I did some research and the solution was to add this into the source code: System.Web.UI.WebControls.Login but I have no idea where this code can be add into. At first I tried putting it as a namespace, but it was wrong. Anyone can tell me where should I place this code at?? EDIT protected void Login1_LoginError(object sender, System.EventArgs e) { //Login Login1 = (WebControls.Login).LoginView1.FindControl("Login1"); Login Login1 = (System.Web.UI.WebControls.Login)LoginView1.FindControl("Login1"); TextBox UserName = (TextBox)Login1.FindControl("UserName"); TextBox FailureText = (TextBox)Login1.FindControl("FailureText"); //There was a problem logging in the user //See if this user exists in the database MembershipUser userInfo = Membership.GetUser(UserName.Text); if (userInfo == null) { //The user entered an invalid username... FailureText.Text = "There is no user in the database with the username " + UserName.Text; } else { //See if the user is locked out or not approved if (!userInfo.IsApproved) { FailureText.Text = "When you created your account you were sent an email with steps to verify your account. You must follow these steps before you can log into the site."; } else if (userInfo.IsLockedOut) { FailureText.Text = "Your account has been locked out because of a maximum number of incorrect login attempts. You will NOT be able to login until you contact a site administrator and have your account unlocked."; } else { //The password was incorrect (don't show anything, the Login control already describes the problem) FailureText.Text = string.Empty; } } }

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